A marine biologist wants to estimate the average weight of a population of dolphins living in a certain region of the ocean. The biologist will collect a random sample of dolphins and use the sample weights to create the estimate Which of the following is an appropriate method for the biologist to use for inference to the population?
A A one-sample t-interval for a population mean
B A one-sample t-interval for a sample mean
C A one-sample 2-interval for a population proportion
D A matched-pairs t-interval for a mean difference
E A two-sample t-interval for a difference between means

Answer:

D

Step-by-step explanation:

x + 2/5 = 1/3

x = 1/3 - 2/5

x = -1/15

Answer:

-1/15

Step-by-step explanation:

Answer:

18

Step-by-step explanation:

=(

48

1

)(

3

8

)

=

(48)(3)

(1)(8)

=

144

8

=18

well just look at the tens digit and see if it is bigger or smaller than 5, in this case 8>5

so the answer is 6,615,000, it is 000 because 9+1 became a 10

Answer:

56 and 1/4 square yds

Step-by-step explanation:

Answer:

The value of test statistic

   |Z| = |-2.2883| = 2.2883

Step-by-step explanation:

Step(i):-

Given that the mean of the Population = 57.7miles/gallon

The standard deviation of the Population = 1.9

The mean of sample x⁻ = 57.4

Given that the sample size 'n' =210

level of significance = 0.1

Step(ii):-

Test statistic

        [tex]Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }[/tex]

       [tex]Z = \frac{57.4-57.7}{\frac{1.9}{\sqrt{210} } }[/tex]

      Z = -2.2883

  |Z| = |-2.2883| = 2.2883

Final answer:-

The value of test statistic

   |Z|  = 2.2883

Answer:

They made 2 batches

Step-by-step explanation:

If the factory used ⅔, and 1 batch is ⅓, the factory made 1 batch for each 3rd they used. ⅔, 2 batches

Answer:

Step-by-step explanation:

[tex]y=mx+b\\ \\ m=\frac{-7-8}{8-\ -2}=\frac{-15}{10}=\ -\frac{3}{2}\\ \\ y=\ -\frac{3x}{2}+b,\ (-2,8)\\ \\ 8=\ -\frac{3(-2)}{2}+b\\ \\ 8=3+b,\ b=5\\ \\ y=\frac{10-3x}{2}[/tex]

Answer:   y  = - 3/2x + 5

Step-by-step explanation:

To write the equation in slope intercept form, you will have to find the slope and the y-intercept.

(-2,8) (8,-7)  

To find the slope using these points, you will find the difference in the y coordinates and divide it by the difference in the x coordinates.

-7 - 8 = - 15

8 - (-2) = 10

   Slope:   -15/10   =  -3/2  

The slope is  -3/2

Now using the formula y=mx+b  , use one of the given points and the slope to solve for b , which is the y-intercept.

     8  = -3/2(-2) + b

    8 = 3 + b

   -3     -3

    b = 5

Answer:

59

Step-by-step explanation:

Find the diagram attached

From the diagram, we can see that both given angles are vertically opposite angles, hence they are equal

3x - 33 = 2x+26

3x-2x = 26 + 33

x = 59

Hence the value of x is 59

Answer:

y=-4x+3

Step-by-step explanation:

it does not show the equations that are following

but the main thing you need to know is that when two lines are parallel they have the same slope

and do you mean 2x+8y=18 not x?

edit:

answer choices: y=-4x+3, y=8x-2, y=4x+7, y=-8x+9

2y+8x=18

first change that equation to slope intercept form to find the slope

2y = -8x+18 -> y = -4x+9

slope is -4

so the answer is y=-4x+3 because it also has a slope of -4

Answer:

Step-by-step explanation:

[tex]\frac{n^2}{11}+6[/tex]

Step-by-step explanation:

[tex]305x + 30 - 80 \\ 305x - 50 \\ 305x = 50 \\ x = \frac{305}{50} \\ x = \frac{61}{10} [/tex]

Answer:

EF=2 cm

Step-by-step explanation:

Answer:

EF = 2 cm

Step-by-step explanation:

HK = HG + GK

10 = 4 + GK

GK = 10 - 4

GK = 6 cm

or

KG = 6cm

[tex] \triangle EGH \cong\triangle KGF... (given) [/tex]

[tex]\because EG\cong KG.. (cpct) [/tex]

[tex]\therefore EG = 6 cm [/tex]

[tex]\because FG\cong HG.. (cpct) [/tex]

[tex]\therefore FG = 4 cm [/tex]

EF = EG - FG (E-F-G)

EF = 6 - 4

EF = 2 cm

Answer:

y = -x

Step-by-step explanation:

Let the equation representing the table attached is,

y = mx + b

Here, m = Slope of the line

b = y-intercept

Since, slope of a line passing through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,

m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

From the table attached,

Slope of the line passing through (23, -23) and (33, -33),

m = [tex]\frac{-33+23}{33-23}[/tex]

m = -1

Equation of the line will be,

y = -x + b

Since, this line passes through another point (43, -43),

-43 = -43 + b

b = 0

Therefore, equation of the line representing the table will be,

y = -x  

Answer:

36-e

Step-by-step explanation:

-

Answer: 181.46 cm.

Step-by-step explanation: The real answer is 181.462086 cm but we can round that to 2 decimal places.

The answer is,

[tex]y = 1.6[/tex]

Answer:

Y = 1.6

Step-by-step explanation:

Y = 2 - 0.4

Y = 1.6

radius of ½ circle = d : 2

= 6in : 2 = 3in

Total area = Rectangle area + ½Circle area + Triangle area

= (l×w) + ½(π×r²) + (½×b×h)

= (10×6) + ½(π×3²) + (½ × (14-10) × 6)

= 60 + 14.14 + 12 = 86.14in

See the bold one in line 2 of total area, thats the formula of all shape.

Answer:

well it is a right trianlg that means that the first side is 90 degrees

and the other two sides are 45 because they look the same angles so 180 minus 90 = 90 divide that by 2 to get 45

Step-by-step explanation:

Replace x with 1 nd solve, then replace x with 3 and solve:

x^3 - 2x^2 +3x

When x = 1:  1^3 -2(1)^2 +3(1) = 3 -3 +3 = 3

When x = 3: 3^3 -2(3)^2 + 3(3) = 27 -18 +9 = 18

The difference between the two solutions is 18-3 = 15

The difference between the two x values = 3-1 = 2

The rate of change is 15/2  or 7.5 as a decimal.

Answer:

[tex]4T1 - T3 - T2= 45[/tex]

[tex]4T2- T1 - T4 = 75[/tex]

[tex]4T3- T1 - T4 = 75[/tex]

[tex]4T4 - T2 - T3= 105[/tex]

Step-by-step explanation:

Given

[tex]\begin{array}{cccc}{ } & {30} & {30} & { } & {15} & {T1} &{T2} & {45} & {15} & {T3} & {T4} & {45} & {} & {60} & {60} & {} \ \end{array}[/tex]

Required

Set up 4 linear equations to solve for T1,T2,T3, andT4

From the question, we understand that each temperature is the average of the 4 surrounding temperatures.

So, we have:

For T1, the surrounding temperatures are: 30, 15, T3 and T2.

The average is:

[tex]T1 = \frac{1}{4}(30 + 15 + T3 + T2)[/tex]

[tex]T1 = \frac{1}{4}(45 + T3 + T2)[/tex]

Multiply through by 4

[tex]4T1 = 45 + T3 + T2[/tex]

Equate variables to constant

[tex]4T1 - T3 - T2= 45[/tex]

For T2, the surrounding temperatures are: T1, T4, 45 and 30.

The average is:

[tex]T2 = \frac{1}{4}(T1 + T4 + 45 + 30)[/tex]

[tex]T2 = \frac{1}{4}(T1 + T4 + 75)[/tex]

Multiply through by 4

[tex]4T2 = T1 + T4 + 75[/tex]

Equate variables to constant

[tex]4T2- T1 - T4 = 75[/tex]

For T3, the surrounding temperatures are: 60, 15, T1 and T4

The average is:

[tex]T3 = \frac{1}{4}(60 + 15 + T1 + T4)[/tex]

[tex]T3 = \frac{1}{4}(75 + T1 + T4)[/tex]

Multiply through by 4

[tex]4T3 = 75 + T1 + T4[/tex]

Equate variables to constant

[tex]4T3- T1 - T4 = 75[/tex]

For T4, the surrounding temperatures are: 60, 45, T2 and T3

The average is:

[tex]T4 = \frac{1}{4}(60 + 45 + T2 + T3)[/tex]

[tex]T4 = \frac{1}{4}(105 + T2 + T3)[/tex]

Multiply through by 4

[tex]4T4 = 105 + T2 + T3[/tex]

Equate variables to constant

[tex]4T4 - T2 - T3= 105[/tex]

So, the equations are:

[tex]4T1 - T3 - T2= 45[/tex]

[tex]4T2- T1 - T4 = 75[/tex]

[tex]4T3- T1 - T4 = 75[/tex]

[tex]4T4 - T2 - T3= 105[/tex]

Answer:

Step-by-step explanation:

you can use desmos to see the graph

but 4 is the y intercept, so that means you can start from the point (0, 4). then, to draw the rest of the line,  you would go up 3 and right 1 because the slope is 3 or 3/1

Answer:

you could do 3 tens and 1 ones or 2 tens and 11 ones

Step-by-step explanation:

hope this helps!

Answer:

No

Step-by-step explanation:

if u subsitute x for 4, 4+5 would equal positive 9.

Answer:

last option.

linear pair

.............

Answer: Mika rides his bike for 6 miles to his friend's house and back. The extra information is when the problem says "He leaves his house at 4 p.m." since we are talking about distance, not time.

Step-by-step explanation:

Answer:

375 m

Step-by-step explanation:

[tex] \frac{3}{4} \times 1000 = 750[/tex]

From halfway

[tex] \frac{750}{2} = 375[/tex]

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