The angle at which it should be banked for a traffic speed of 100 km/h is
14.57°.
How do find the angle of Banking of road?Banking of roads is the practice of raising the outer borders of curving roads over the inner edge in order to give vehicles the necessary centripetal force to make a turn safely.Skidding can be prevented by banking.The banking of roadways aids in preventing toppling or overturning.To find the angle of banking following formula can be used,
[tex]tan \alpha = v^{2} /rg[/tex]
Given v = 100km/h or
= 100 x 1000 / 3600
= 27.7 m/s
Hence,
[tex]tan \alpha = (27.7)^{2} / 300 * 9.81[/tex]
[tex]tan\alpha = 0.26[/tex]
[tex]\alpha = tan^{-1} 0.26[/tex]
[tex]\alpha = 14.57[/tex]°
Hence, the angle of banking of the road will be 14.57°
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What is the monthly (30 days) energy cost (in
$) of leaving a 40-W bulb on continuously if
electricity costs 21¢ per kWh? Round final
answer to the nearest cent.
Explanation:
Power= 40 W
cost=21¢/kWh
t=1 month=30 days = 720h
Energy= power*time
E= 40W* 720h = 28800kWh
Cost= Energy*rate
cost= 28800kWh*21¢/kWh
cost=604800¢
Compute the speed of sound waves in air at room temperature (T=200C) and find the range of wavelengths in air to which the human ear (which can hear frequencies in the range of 20 – 20,000Hz) is sensitive. The mean molar mass of air (a mixture of principally nitrogen and oxygen) is 28.8 x 10-3kg/mol and the ratio of heat capacity is ϒ = 1.40.
The speed of sound waves in air at room temperature T=20° is 344.035 m/s.
The range of wavelength in air to which the human ear (which can hear frequencies in the range of 20 – 20,000Hz) is sensitive is 17.20 m to 0.0172 m.
What is wavelength?The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.
Wavelength λ = c/f
where c is the speed of sound wave.
Given the room temperature T = 20 +273 = 293K
The velocity of sound wave is given by
v = √(γRT/m)
where γ =1.4 , m = 28.8×10⁻³ kg/mol R = 8.31 J/K.mol
Substituting the values, we get
v = 344.035 m/s
Thus, the speed of sound wave is 344.035 m/s
The human ear can hear frequencies in the range of 20 – 20,000Hz.
The wavelength corresponding to 20Hz is
λ = c/f
λ = 344.035 /20
λ = 17.20 m
The wavelength corresponding to 20,000Hz is
λ = 344.035 /20000
λ = 0.0172 m
Thus, the range of wavelength is 17.20 m to 0.0172 m sensitive to human ear.
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A mass of (200 of hot water at (75, 0 degrees * C) is mixed with cold water of mass M at (5, 0 degrees * C) The final temperature of the mixture is (25, 0 degrees * C) What is the mass of the cold water (M)
Q in = Q out
mcΔt in = mcΔt out (c = equal)
mΔt in = mΔt out
200 x (75-25) = M x (25-5)
M = 500 g
∆T for hot water
75-2550°C∆T for cold water
25-520°CBoth are equal according law of conservation of energy
[tex]\\ \rm\Rrightarrow m_1c\delta T_0=m_2c\delta [/tex]
[tex]\\ \rm\Rrightarrow 200(50)=m_2(20)[/tex]
[tex]\\ \rm\Rrightarrow 10000=m_2(20)[/tex]
[tex]\\ \rm\Rrightarrow m_2=500g=0.5kg[/tex]
The position of particle as a function of particle of time is given by: r(t)=3tî–4t^2j+2k. Where î & j are unit vector along the x-axis and y-axis respectively. Find the unit vector along r(t)
The unit vector along r(t) will be 3t–4t^2+2
A vector is a quantity with direction and magnitude that is especially useful for locating one location in space in relation to another. A quantity or phenomena with independent qualities for both size and direction is called a vector. The word can also refer to a quantity's mathematical or geometrical representation. Velocity, momentum, force, electromagnetic fields weight are a few examples of vectors in nature.
Given the the position of particle as a function of particle of time is given by: r(t)=3tî–4t^2j+2k. Where î & j are unit vector along the x-axis and y-axis respectively.
We have to find the unit vector along r(t)
To find the unit vector along r(t) we have to put the value of (i,j,k) = (1,1,1) in r(t)
So,
r(t) = 3tî–4t^2j+2k
r(t) = 3t(1)–4t^2(1)+2(1)
r(t) = 3t–4t^2+2
Therefore the unit vector along r(t) will be 3t–4t^2+2
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What does Charles Darwin’s theory of natural selection state about traits?
A.
Traits that increase the survival rate of a population are rarely passed on to future generations since they can affect reproduction.
B.
Traits that prevent people from reproducing are passed on to future generations to ensure their survival.
C.
Traits that make it more likely for a species to survive or reproduce become less common in a population over time.
D.
Traits that provide a survival or reproductive advantage are more likely to be passed on to future generations.
Charles Darwin's theory of natural selection states that features that offer survival or reproductive advantage are more likely to be handed down to subsequent generations.
What are traits?A trait is a distinctive pattern of behavior or conscious motivation that may be evaluated by peers or oneself.
Traits that provide a survival or reproductive advantage are more likely to be passed on to future generations is Charles Darwin’s theory of natural selection state traits.
Hence option D is correct.
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Answer: option d
Explanation:
the 3kg object in figure is released from rest at height of on a curved frictionless ramp. at the foot of the ramp is a spring of force constant 400N/m. the object slides down the ramp and into the spring,compressing it a distance x before coming momentarily to rest.
a) find x
b) describe the motion of the object (if any) after the block momentarily comes to rest?
(a) The compression of the spring is 7.4 cm.
(b) When the object comes to rest its potential energy from the given height will be converted into elastic potential energy of the spring.
Compression of the spring [ x ]
The compression of the spring is calculated by applying Hooke's law as follows;
F = kx
x = F/k
x = (mg)/k
x = (3 x 9.8)/400
x = 0.074 m
x = 7.4 cm
When the object comes to rest its potential energy from the given height will be converted into elastic potential energy of the spring.
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Question 3 of 10
The Moon has much less gravitational force than Earth. What would happen
if you went to the Moon?
OA. Your mass would decrease.
O
B. Your weight would increase.
O
C. Your mass would increase.
O
D. Your weight would decrease.
SUBMIT
Answer:
D
Explanation:
Mass is the amount of matter your body has ....does not change on the Moon.
there is less gravity .....so your WEIGHT would decrease
use ideas of electromagnetic induction to explain how the input voltage is transformed into an output voltage
With the help of a transformer input voltage is transformed into an output voltage
What is induced voltage?Electromagnetic induction is what causes the induced voltage. Electromagnetic induction is the process of generating emf (induced voltage) by subjecting a conductor to a magnetic field.
In this case, a magnet is pushed in and out of a wire coil attached to a high-resistance voltmeter.
Typically, a transformer's primary winding is attached to the input voltage source and changes electrical power into a magnetic field.
The secondary winding's role is to turn this alternating magnetic field into electricity, generating the necessary output voltage.
Hence with the help of a transformer input voltage is transformed into an output voltage.
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A 17-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 31 N. Starting from rest, the sled attains a speed of 2.3 m/s in 9.2 m. Find the coefficient of kinetic friction between the runners of the sled and the snow.
What is the number and units?
The sled accelerates with magnitude [tex]a[/tex] such that
[tex]\left(2.3\dfrac{\rm m}{\rm s}\right)^2 = 2a(9.2\,\mathrm m) \implies a = 0.2875\dfrac{\rm m}{\mathrm s^2}[/tex]
By Newton's second law, the net force in the plane of motion (parallel to the ground) is
[tex]31\,\mathrm N - F_{\rm friction} = (17 \,\mathrm{kg}) \left(0.2875 \dfrac{\rm m}{\mathrm s^2}\right)[/tex]
so that the force of friction exerts a magnitude of
[tex]F_{\rm friction} = 26.1125 \,\mathrm N[/tex]
Perpendicular to the ground, the sled is in equilibrium, so Newton's second law says
[tex]F_{\rm normal} - (17\,\mathrm{kg})g = 0 \implies F_{\rm normal} = 166.6 \,\mathrm N[/tex]
The magnitude of friction is proportional to the magnitude of the normal force by a factor of [tex]\mu_k[/tex], the coefficient of kinetic friction. It follows that
[tex]F_{\rm friction} = \mu_k F_{\rm normal} \implies \mu_k = \dfrac{26.1125\,\rm N}{166.6\,\rm N} \approx \boxed{0.16}[/tex]
(and the coefficient is dimensionless).
Any Acellus folk figure out the answer to this one??? I CANNOT for the life of me.
What is the angular velocity of the minute hand of a clock?
[?] rad/s
Hint: It travels clockwise and takes 60 minutes to make one revolution.
(not 1.25, 1.7, 1800, 30, 60, 0.1047)
Answer:
-0.10472[tex]\frac{rad}{s}[/tex]
Explanation:
Remember that any clockwise rotation is considered negative, and any counterclockwise rotation is considered positive.
The formula for period is:
[tex]T = \dfrac{2\pi}{\omega}[/tex]
Solve for [tex]\omega\\[/tex] and you get:
[tex]\omega=\dfrac{2\pi}{T}[/tex]
The period is 60 seconds so make that division and you're left with -0.10472[tex]\frac{rad}{s}[/tex] or -0.10[tex]\frac{rad}{s}[/tex] if significant figures apply (negative because the rotation is clockwise).
What is the magnitude of the gravitational force of attraction to Jupiter exerts on IO
The gravity force between Jupiter and Io will be 6.343 × 10²² N.
What is Newton's law of gravitation?
Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Given data;
Mass of Jupiter,[tex]\rm m_j = 1.9 \times 10^{27} \ kg[/tex]
Mass of moon of Jupiter,[tex]\rm m_{i_0}= 8.9 \times 10^{22} \ kg[/tex]]
The gravitational constant is,[tex]\rm G = 6.67 \times 10^{-11 } \ m^3 kg^{-1} s^{-2}[/tex]
Distance between Jupiter and Io, R = 421,700 km = 4,217,00,000 m
The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
The gravitational force is found as;
[tex]\rm F = G \frac{ m_J m_{I_0}}{R^2} \\\\\ F = (6.67\times 10^{-11}) \frac{( (1.9\times 10^{27})\times (8.9\times 10^{22} )} { (421700000)^2}\\\\ F_g = 6.343 \times 10^{22} \ N[/tex]
Hence, the gravity force between Jupiter and Io will be 6.343 × 10²² N.
The complete question is
"Jupiter has a mass of 1.9 × 1027 kg, and its moon Io has a mass of 8.9 × 1022 kg. Their centers are separated by a distance of 421,700 km what is the force of gravity acting on Io? "
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Charlene has just begun to be able to form a mental representation of an object that is not visibly
present According to Piaget, that means that she has made the transition from the
stage
to the
stage
According to Piaget, that means that she has made the transition from the sensorimotor to preoperational stage
What is the sensorimotor stage?The first of Piaget's four stages of cognitive development is the sensorimotor stage.
A child's understanding that the outside world exists apart from them is what distinguishes it.
Within Piaget's stages of development, the kid will advance to the following stage after they have completely grasped this.
"Charlene has just begun to be able to form a mental representation of an object that is not visibly present.
According to Piaget, that means that she has made the transition from the sensorimotor to preoperational stage
Only recently has Charlene been able to create a mental image of something that is not physically present.
That indicates that she has moved from the sensorimotor to the preoperational level, in accordance with Piaget.
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Becky races Tom down the street .Becky , initially at a stop,takes 5.5 s to reach 30 m/s . What accelerated?
Becky's acceleration is 5.45 [tex]ms^2[/tex].
Acceleration = [tex]\frac{v-u}{t}[/tex]
where v= final velocity , u= initial velocity , t= time taken
according to the question :
initial veocity = 0 (it is at stop initially)
final velocity = 30m/s
time taken = 5.5 s
according to the formula acceleration = [tex]\frac{30-0}{5.5}[/tex]=[tex]5.45[/tex]
Hence Becky's acceleration is 5.45 [tex]ms^2[/tex].
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What is the current in a circuit that is powered by a 6.0 V battery and
connected in series by a 2.0 Ω resistor and a 12.0 Ω resistor?
A. 0.50 A
B. 3.0 A
C. 84.0 A
D. 0.43 A
Answer:
D. 0.43 A
Explanation:
First you will find the total resistance which is
R=R¹+R²
R=2+12
R= 14 ohms
I = V/R
I = CURRENT
V= VOLTAGE
R = RESISTANCE
I= 6/14
I =0.43 A
3. Planet 1 has mass M₁ and radius R₁. Planet 2 has mass M₂ and radius
R₂. The two planets are a distance of L apart, measured from surface to
surface. An object is launched with some initial speed from the surface of
Planet 1 directly towards Planet 2. For this problem, assume that Planets
1 and 2 are stationary. (20 points)
(a) At what initial speed must the object be launched so that it reaches
the surface of Planet 2 with zero speed?
(b) Derive an inequality between M₁ and M₂ that represents when (a)
can occur.
(c) Show that, using your result in (b), if R₁ = R₂, then M₁ must be
greater than M₂.
(a) The initial speed must the object be launched so that it reaches
the surface of Planet 2 with zero speed is √[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}]
(b) An inequality between M₁ and M₂ that represents when (a)
can occur is { M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0
(c) if R₁ = R₂, then M₁ must be greater than M₂ is proved.
What is gravity?The force of attraction felt by a person which is directed at the center of a planet or Earth is called as the gravity.
The force of attraction is directly proportional to the product of masses of the object and inversely proportional to the square of distance between them.
F = GMm/R²
Given, Planet 1 has mass M₁ and radius R₁. Planet 2 has mass M₂ and radius R₂. The two planets are a distance of L apart, measured from surface to surface. An object is launched with some initial speed from the surface of Planet 1 directly towards Planet 2. For this problem, assume that Planets1 and 2 are stationary.
If v is the launch velocity, then initial total energy will be
T.E = 1/2 mv² + ( -GM₁m/ R₁ - G M₂m/(R₂ + L)
The final total energy will be
T.E =0 + ( -GM₁m/ (R₁ +L) - G M₂m/ R₂)
From energy conservation principle, we get
1/2 mv² + ( -GM₁m/ R₁ - G M₂m/(R₂ + L) = ( -GM₁m/ (R₁ +L) - G M₂m/ R₂)
v = √[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}]
(b) an inequality between M₁ and M₂ so that object reaches the surface of Planet 2 with zero speed is
[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}] =0
{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0
Thus, this is an inequality between M₁ and M₂.
(c) If R₁ = R₂, then
{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0
M₁(R+L) + M₂R - M₁R -M₂(R+L) / R (R+L) ≥ 0
M₁(R+L) + M₂R - M₁R -M₂(R+L) ≥ 0
M₁L - M₂L ≥ 0
M₁ ≥ M₂
M₁ must be greater than M₂.
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Gravity will have a greater effect on an object with?
As the pressure on a sample of gas increases, the volume of the sample
Decrease
Stays the same
Increase
Answer:
decreases
Explanation:
because all the particles are wanting to say together and hit each other in a small area
_____ is a force which is applied to an object by another object or a person. __________ is a force that always opposes the motion of an object and is frequently ignored. a. Tensional force, friction c. Applied force, air resistance b. Friction, applied force d. None of the above. Please select the best answer from the choices provided A B C D
Answer:
Fritional force
Explanation:
Fritional force is a force that always opposes the motion of an object and is frequently ignored
C
Explanation:
Applied force, air resistance
a 2.50 cm tall object is 36.0 cm from a concave mirror with f=12.0 cm. find the image height.
The height of the image is -6 cm.
The reflecting surface of a concave mirror is curled inward and away from the light source. Light is reflected inward to a single focus point via concave mirrors. Concave mirrors, in contrast to convex mirrors, produce a variety of images depending on the object's to the mirror.
Given that, an object placed 36 cm from a concave mirror having the focal length of 12 cm and height of image is 2.50 cm
We have to find height of the Image
Using Mirror Formula:
1/f = 1/v + 1/u
Where,
f = focal length
v = Image distance from the mirror
u = object distance from the mirror (concave)
Substitute the known values in the above formula to find the value of 'v' i.e. from the mirror.
1/(-12) = 1/v + 1/(-36)
1/(-12) = 1/v - (1/36)
1/v = -0.055
v = -18 cm
Therefore, Image distance the from the concave mirror is -18 cm.
Now,
m = -v/u = hi/h
Substitute the values,
-(-18)/(-36) = hi/12
-0.5 = hi/12
-6 = hi
Therefore, the height of the image is -6 cm.
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Question 12 of 25
Two identical satellites circle the Earth in orbits. The distance between the
Earth and satellite B is twice the distance between the Earth and satellite A.
What is the relationship between the gravitational force acting on satellite A
(FA) and the force on B (FB)?
Earth
OA. FB = FA
OB. Cannot be determined
OC. FB< FA
OD. Fa> FA
Satellite A
Satellite B
Answer:
F = G M m / R^2 gravitational force on satellite of mass m
Fma / Fmb = (ma / Ra^2) \ (mb / Rb^2) = (ma / mb) * (Rb / Ra)^2
Fma / Fmb = 1 * 4 = 4
The force on A is 4 times the force on B
You drive 8.50 km in a straight line in a direction 30° East of North.
(a) Find the distances you would have to drive straight East and then straight North to arrive at the same point. (This is equivalent to finding the components of the displacement along the East and North directions.)
km East
km North
(b) Show that you still arrive at the same point if the East and North legs are reversed in order.
(a.1) The component of displacement along the East is 7.36 km.
(a.2) The component of displacement along the North is 4.25 km.
(b) When the East and North legs are reversed in order, you will still travel 8.5 km.
Component of displacement along the East
dx = d cosθ
dx = 8.5 km x cos(30)
dx = 7.36 km
Component of displacement along the Northdy = d sinθ
dy = 8.5 km x sin(30)
dy = 4.25 km
When East and North legs are reversed;dx = 4.25 km
dy = 7.36 km
Resultant displacement;
R = √(dx² + dy²)
R = √(4.25² + 7.36²)
R = 8.5 km
Thus, when the East and North legs are reversed in order, you will still travel 8.5 km.
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In the following word completion task: carrot, peas, corn, b_____, most people would answer “beans” (instead of “beetle” for example) even though there were no instructions on how to do this task. The psychological reason we made the assumption that the blank word was related to the previous words is due to
Answer:
Explanation:
Wow, I said 'beets'..... I must be weird.
During a diversity management session, a manager suggests that stereotypes are a necessary part of working with others. “I have to make assumptions about what’s in the other person’s head, and stereotypes help me do that,” she explains. “It’s better to rely on stereotypes than to enter a working relationship with someone from another culture without any idea of what they believe in!” Discuss the merits of and problems with the manager’s statement.
The merits of and problems with the manager’s statement are explained below.
What is stereo typing in organizations?Extension of the social identity of the individual in groups such as working in company or studying in college is called as the stereotyping in organizations.
Merits of Stereotypes in organizations:
It relies on categorical thinkingHelps understand outside world easily'unique characteristics are difficult to recall every time.groups are identified easilyhelps filling the gaps while talking of some new culture.helps enhancing self perception and social identity.Demerits of Stereotypes:
difficulty in understanding behavior of other individual in organizations.an individual may be sometimes under or over estimated.discourages social group while entering a profession.discriminatory behavior.not helps in describing with their talent.Thus, the merits and demerits of stereotypes in organizations are explained above.
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If the velocity of an object doubles and it’s mass triples, the objects momentum increases by how much? A)1.5 times B)2 times C)3 times D)6 times
Answer:
(D)6 times
Explanation:
Hello !
Because when we see the equation of momentum P=mv, where p=momentum
m=mass of the object&
v=velocity of the object
And, p is directly propositional to both mass and velocity.
Thus, p=mv
p=3m.2v....giving on the valuesp=6(mv)Therefore, we can conclude by when the mass is tripled and the velocity is doubled the momentum is increased by 6 units.
A spoon inserted in a half-filled cup of water appears crooked because as light travels into a substance with a lower index of refraction, it... Select one: a. does not bend. b. bends away from the normal. c. bends toward the normal. d. is reflected.
Explanation:
The light is bent away from the normal
what is the radius of the 5th orbital in hydrogen?
Answer: 1.32 x 10^-9 m
Explanation:
The formula for the radius of nth orbital is:
[tex]r_{n}=\frac{n^{2}}{Z} \times 0.528 \text { Angstorms }[/tex]
For hydrogen, Z= 1, so we have:
[tex]$$\begin{aligned}r_{n} &=5^{2} \times 0.528 \text { Angstorm } \\&=13.2 \text { Angstorms } \\&=13.2 \times 10^{-10} \mathrm{~m} \\&=1.32 \times 10^{-9} \mathrm{~m}\end{aligned}$$[/tex]
Answer: 1.32*10^-9
Explanation: I had the same question and here's what I got:
rn = n2(r1)
n = 5
r = 5.29*10^-11
rn = n^2(r1)
= 5^2(5.29*10^-11)
r = 1.32*10^-9
What method could I use to test this hypothesis? If the mass and the volume of and object are known, then its density can be calculated dividing the object's mass by its volume.
Answer:
The scientific method
Explanation:
28. An electron with a speed of 4.0 x 10° m/s enters a uniform magnetic field of magnitude 0.040 T at an angle of 35 degrees to the magnetic field lines. The electron will follow a helical path. a) Determine the radius of the helical path. b) How far forward will the electron have moved after completing one circle?
Answer:
r= 1.09×10^-4
Explanation:
Given
V=speed=4.0×10^5 m/s
B= magnetic field= 0.040 T
©=angle= 35°
m= mass of electron= 9.11×10^-31
q= charge of electron= 1.60×10^-19
solution
qv×B= mv²/r
qvBsin©=mv²/r
qBsin©=mv/r
r=mv/qBsin©
r=9.11×10^-31× 4.0×10^5/1.064×10^-19×0.04T(sin35°)
r= 1.09×10^-4 m
a) r = 1.09 * [tex]10^{-4}[/tex] m
b) Distance travelled : 6.845 * [tex]10^{-4}[/tex] m
What is an electron ?
An electron is a stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.
given
charge of electron : 1.6 * [tex]10^{-19}[/tex] C
mass of electron = 9.11 * [tex]10^{-31}[/tex] kg
v = 4.0 x 10 m/s
B = 0.040 T
theta = 35 degrees
since ,
force in magnetic field on electron = centripetal force
a) q(v*B) = m [tex]v^{2}[/tex] / r
q v B sin(theta) = m [tex]v^{2}[/tex] / r
r =m v /q B sin(theta)
r = 9.11 * [tex]10^{-31}[/tex] * 4.0 x [tex]10^{5}[/tex]/ 1.6 * [tex]10^{-19}[/tex] sin (35)
r = 1.09 * [tex]10^{-4}[/tex] m
b) far forward will the electron have moved after completing one circle will be equal to circumference of the circle = 2πr
= 2 * 3.14 * 1.09 * [tex]10^{-4}[/tex] m = 6.845 * [tex]10^{-4}[/tex] m
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A pendulum bob executing simple harmonic motion has 2cm and 12Hz as amplitude and frequency respectively. Calculate the period of the motion
Answer:
Explanation:
The amplitude is extraneous information for this question.
Period (T) is simply a measure of time (how long it takes to complete a full cycle).
The frequency (f), is the reciprocal (how many cycles it can complete per unit of time).
The frequency reported is 12Hz. Hz is a unit meaning "cycles per second"
Thus 12cycles = 1second.
To find the number of seconds per cycle, simply create the other unit fraction and simplify:
[tex]T=\frac{1second}{12cycles}\\T=0.8\bar{3}\frac{seconds}{cycle}\\[/tex]
[tex]T=0.83seconds[/tex]
Identify the law, write the equation and calculate the answer to the problem below.
An incident light ray strikes water at an angle of 45 degrees. The index of refraction of air is 1.0003, and the index of refraction of water is 1.33. What is the angle of refraction rounded to the nearest whole number?
Find refractive index first
[tex]\\ \rm\Rrightarrow \mu=\dfrac{c}{v}[/tex]
[tex]\\ \rm\Rrightarrow \mu=\dfrac{1.0003}{1.33}[/tex]
[tex]\\ \rm\Rrightarrow \mu =0.75[/tex]
Now
[tex]\\ \rm\Rrightarrow \dfrac{sini}{sinr}=\mu[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{sin45}{sinr}=0.75[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{sin45}{0.75}=sinr[/tex]
[tex]\\ \rm\Rrightarrow sinr=0.94[/tex]
[tex]\\ \rm\Rrightarrow r=sin^{-1}(0.94)[/tex]
[tex]\\ \rm\Rrightarrow r=70^{\circ}[/tex]
