The speed the golf must have initially to reach the hole is 31.32`1 m/s.
What is projectile?When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion.
A golfer wishes to chip a shot into the hole 50m away on flat level ground. if the ball flies to a maximum height of 25m.
The angle with which the ball flies,
tan θ = 25 m/ (50m/2)
tan θ =1
θ =45°
If u is the initial speed, the maximum height of the ball is
H = u² sin²θ / 2g
Put the values, we get
25 = u² sin²45 / (2x9.81)
u = 31.321 m/s
Thus, the initial speed is 31.321 m/s
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ubes have sides of equal lengths. What is the fastest way to measure the volume of a cube-shaped table?
measure the length, width, and height of the table, then multiply those numbers
measure one side with a ruler, and multiply that number by itself three times
measure one side with a ruler, and multiply that number by itself and then by
measure the length, width, and height of the table, then multiply those numbers by
The quickest technique to calculate the volume of a cube-shaped table is to use a ruler to measure one side, then multiply that figure by three. Option B is correct.
How do you calculate the volume of a cube?Assume the side length of the cube under consideration is L units. The volume of the cube is then equal to L³ cubic units.
The volume of a cube is;
V = L³
Ubes have equal-length sides. The quickest technique to calculate the volume of a cube-shaped table is to use a ruler to measure one side, then multiply that figure by three.
Hence option B is correct.
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A bus start from rest. If the acceleration of bus is 0.5 m/s square. what will be its velocity at the end of 2 minutes?what will be the distance cover?
Answer:
3586
Explanation:
by using formula s=it+0.5at^2
Answer:
[tex]\fbox {Velocity = 60 m/s, Distance = 3600 m}[/tex]
Explanation:
Part (i) : Velocity at end of 2 minutes
Equation used ⇒ [tex]\boxed {v = u + at}[/tex]
⇒ t = 2 minutes = 2 x 60 = 120 seconds
⇒ v = 0 + (0.5)(120)
⇒ v = 60 m/s
Part (ii) : Distance covered
Equation used ⇒ [tex]\boxed {S = \frac{v^{2}-u^{2}}{2a}}[/tex]
⇒ S = (60)² - (0)² / 2(0.5)
⇒ S = 3600 m
Explain why it is more difficult to balance a nail on its tip than on its base.
note:please dont answer according to presuure concepts,answer according to equilibrium concepts.thanks.
It is much easier to balance a thing that has a large base of support and a low center of gravity. The object won't topple over as a result of little center of gravity wobble because of the wide base and low center of gravity. Therefore, balancing a nail on its base as opposed to its tip would be simpler.
c) Use the table to explain how the masses of Objects 1 and 2 relate to the gravitational force
between them. Be sure to:
Describe the scenario.
DExplain the table headings to introduce the data in the table.
Use the data to show a trend.
Summarize the information from the table in a sentence, showing the relationship between
the masses of objects and the gravitational force between the objects.
Use the table to explain how the masses of Objects 1 and 2 relate to the gravitational force between them the power of the gravitational pressure among gadgets relies upon on factors, mass and distance. the pressure of gravity the loads exert on every other.
How do the loads of items 1 and a couple of relate to the gravitational pressure among them?Gravitational pressure -an appealing pressure that exists among all items with mass; an item with mass draws every other item with mass; the value of the pressure is immediately proportional to the loads of the 2 items and inversely proportional to the rectangular of the gap among the 2 items.
Since the gravitational pressure is immediately proportional to the mass of each interacting items, greater large items will entice every different with a more gravitational pressure. So because the mass of both item increases, the pressure of gravitational appeal among them additionally increases.
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Hi,i need this hurry and correctly please!!!,fake answers i report you.Thanks.
Step-by-step explanation:
Step 1: Formula
10.0 = Meters
800 = Newtons
4.0 = Centre of Gravity
Explanation in words (Short Form)
- We know all the formulas and that we are calculating the least force being applied. We know that balancing the pole at (A) with the weight of the gravity will equal more force at B times 10. So the answer will be 320 N because the B force will equal 3200. If we divide 3200 by 10. The answer will result as 320. So the final answer for this question is 320N
Answer:
Balancing the pole at A with the weight acting at the centre of gravity = 800(4) Force at B multiplied by 10 = 3200 divided by 10 equals 320N
= 320N
Hope this helps.
Which vector shows the velocity of the yo-yo at this moment?
The vector which shows the velocity of the yo-yo at this moment is A and is denoted as option A.
What is Velocity?This is referred to the rate of change of distance with time and the unit is metre per seconds.
A shows the direction of motion is same as the direction of velocity and is the tangent at that particular point hence why it was chosen as the most appropriate choice.
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3. A body accelerates constantly at 4m/s² from rest for a distance of 60m. a) How long did it take to reach a distance of 60m? [2] b) Calculate the velocity reached.
Answer:
will you mark brainliest.
What allows the electromagnet in a motor to rotate consistently in one
direction, transforming electrical energy into mechanical energy?
Hi!
Inside an electric motor, permanent magnets are set onto a ring surrounding a coil of wire. The communicater mother is what makes it spin
what determines the velocity of an object
a body starts moving from rest and attends the acceleration of 0.5m/s². calculate the velocity at the end of 3 minutes also find the distance travelled by it during that time
Answer:
See below
Explanation:
3 minutes = 180 seconds
v f = at = .5 m/s^2 * 180 s = 90 m/s
Distance = 1/2 a t^2 = .5 * .5 * 180^2 = 8100 m
Different between
atmospheric presure and liquid
pressure
Explanation:
An atmosphere (atm) is a unit of measurement equal to the average air pressure at sea level but liquid pressure is exerted on the surface of an object in a liquid.
And they also differ in formulas. We can calculate atmospheric pressure in two ways. First we can get the atmospheric pressure by an instrument called barometer. And the second one is by usin this formula, atmospheric pressure = density of mercury x acceleration due to gravity x height of column of mercury. But this equation will only work if the atmospheric pressure is being measured by mercury.
But the formula for liquid pressure is defferent and the instrument used to measure the liquid pressure is also defferent.
The instrument used to measure the liquid pressure is pressure gauge. And the formula for the liquid pressure is density x height x gravity. Please give me a like and thank me.
please.
The speed of light is a constant and approximately equal to 300,000,000 meters per second.
Green lasers emit light at a wavelength of 532 nm. However, the material that is used to make most green lasers does not emit light at 532 nm. Instead, it emits light at a different wavelength, and the laser then uses a “frequency doubler.” This doubles the frequency of the emitted light, and the resultant light is the green 532 nm that we observe.
1 meter is equal to 1,000,000,000 nanometers.
What is the output light frequency of the material used before doubling?
The material used before doubling will produce light at a frequency of 0.056 Hz.
What is the frequency?The number of times a wave occurs repeatedly in a second is known as frequency.
The formula provides the frequency as,
[tex]\rm v = \lambda \times f \\\\\ \rm f = \frac{v}{\lambda} \\\\ \rm f = \frac{3 \times 10^8}{532 \times 10^-9} \\\\ \rm f = 3 \times 10^{12} \\\\ f= 0.056 \ Hz[/tex]
Therefore, the material used before doubling will have an output light frequency of 0.056 Hz.
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A car initially traveling at 15.0 m/s accelerates at a constant rate of 4.50 m/s2 over a distance of 45.0 m. how long does it take the car to cover this distance? (4 points)
A car initially traveling at 15.0 m/s accelerates at a constant rate of 4.50 m/s2 over a distance of 45.0 m, the time taken to cover this distance is mathematically given as
t = 2.24 s
What is the time taken to cover this distance?Generally, the equation for Kinematic relation is mathematically given as
S = ut + (1/2)at^2
Therefore
45 = 15t + 2.25 t^2
2.25 t^2 + 15 t -45 = 0
t = 2.24 s
In conclusion, the time is taken to cover this distance
t = 2.24 s
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Deena made a chart to summarize features of a velocity vs. time graph for objects with constant acceleration and objects with constant velocity.
The statement which best describes Deena's error is: B. Include the area of the rectangle under the line to find displacement for constant acceleration.
What is a velocity vs. time graph?A velocity vs. time graph can be defined as a type of graph that is used to graphically represent the rate of change of velocity of an object with respect to time.
Based on the information provided in the table shown (see attachment), the statement which best describes Deena's error is her not including of the area of the rectangle under the line, so as to enable her find displacement for constant acceleration.
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Complete Question:
Deena made a chart to summarize features of a velocity vs. time graph for objects with constant acceleration and objects with constant velocity.
Which best describes Deena's error?
A. The line for constant velocity is not horizontal; it is diagonal and slopes downward.
B. Include the area of the rectangle under the line to find displacement for constant acceleration.
C. Find acceleration by finding the area of the rectangle above the line.
D. Find velocity by calculating the slope of the line.
A girl at a state fair swings a ball in a vertical circle at the end of a string, the force of the string at the bottom is: A-Less than the weight of the ball B-greater than the weight of the ball C-equal to the weight of the ball D-Zero
which choice is correct and why? thx
The force of the string at the bottom is greater than the weight of the ball. The correct option is B.
What is Net force?When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.
A girl at a state fair swings a ball in a vertical circle at the end of a string.
When the ball is at the bottom, the force acting will be
The tension in the string , T = mass x centripetal acceleration + Force of gravity
So, T = m x ac + mg
The tension in the cable at the bottom will have centripetal force and weight forces acting on it.
Thus, the force of the string at the bottom is greater than the weight of the ball.
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Two particles having charges q,=0.700nc and q=9.00nc are separated by a distance of 1.40m. at what point along the line connecting the two charges is the total electric field due to the two charges equal to zero?
The point along the line connecting the two charges is the total electric field due to the two charges equal to zero will be 0.3056.
What is electric field strength?
The electric field strength is defined as the ratio of electric force and charge. The field's direction is determined by the direction of the force acting on the positive charge.
The megnitude of the electric field for charge 1 is;
[tex]\rm E_1 = (9 \times 10^9 )\times \frac{0.700 \times 10^{-9}}{x^2}[/tex]
The megnitude of the electric field for charge 1 is;
[tex]\rm E_2 = 9.0 \times 10^9 \times \frac{9.00 \times 10^{-9}}{(1.80-x)^2}[/tex]
The net electric field at point p is;
[tex]\rm \frac{0.700}{x^2} = \frac{9.00}{(1.40-x)^2} \\\\( \frac{1.40-x}{x} )^2 = \frac{9.00}{0.700} \\\\\ \frac{1.40-x}{x}=3.58 \\\\ \frac{140}{x} -1=3.58\\\\\ \frac{140}{x}=3.58+1\\\\ x=0.3056 \ m[/tex]
Hence, the point along the line connecting the two charges is the total electric field due to the two charges equal to zero will be 0.3056.
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Particles q1, 92, and q3 are in a straight line.
Particles q1 = -5.00 x 10-6 C,q2 = -5.00 x 10-6 C,
and q3 = -5.00 x 10-6 C. Particles q₁ and q2 are
separated by 0.500 m. Particles q2 and q3 are
separated by 0.500 m. What is net force on 93?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
-5.00 x 10-6 C
91
0.500 m-
-5.00 x 10-6 C
92
-5.00 x 10-6 C
93
0.500 m-
The answer to the question is 1.125 Newton
Formula for electrostatic force is F = ( K q1 q2 )/ r²
where q1 and q2 represent the charges and r represents the distance between them and the value of K is 9 × 10⁹.
Total net force on q3 will be the summation of electrostatic force between q1 and q3 and electrostatic force between q2 and q3, as all the three charges are of same sign and lie in the same line.
Electrostatic force between q1 and q3
r will be 0.500 + 0.500 = 1 m
F = ( K q1 q3 )/ r²
F = ( (9 × 10⁹ ) x (5.00 x 10⁻⁶) x (5.00 x 10⁻⁶) )/ 1²
F₁₃ = 2.25 × 10⁻¹ N
Electrostatic force between q2 and q3
r will be 0.500 m
F = ( K q1 q3 )/ r²
F = ( (9 × 10⁹ ) x (5.00 x 10⁻⁶) x (5.00 x 10⁻⁶) )/ 0.5²
F = (225 × 10⁻³) / (25 × 10⁻²)
F₂₃ = 9 × 10⁻¹ N
Total force on q3 will be F₁₃ + F₂₃
Total force on q3 = ( 2.25 × 10⁻¹ ) + (9 × 10⁻¹ ) N
Total force on q3 = ( 2.25 × 10⁻¹ ) + (9 × 10⁻¹ ) N
Total force on q3 = ( 11.25 × 10⁻¹ ) N
Total force on q3 = 1.125 N
Thus after solving we got the net force on q3 as 1.125 Newton
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A metal block has a density of 5000 kg per cubic meter and a mass of 15,000 kg. What is its volume?
Taking into account the definition of density, the volume of the metal block is 3 m³.
What is densityDensity is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.
In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.
Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:
[tex]density=\frac{mass}{volume}[/tex]
From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.
Volume of the metal blockIn this case, you know that:
Density= 5000 [tex]\frac{kg}{m^{3} }[/tex]Mass= 15000 kgVolume= ?Replacing in the definition of density:
[tex]5000 \frac{kg}{m^{3} } =\frac{15000 kg}{volume}[/tex]
Solving:
volume×5000 [tex]\frac{kg}{m^{3} }[/tex]= 15000 kg
volume= [tex]\frac{15000 kg}{5000 \frac{kg}{m^{3} }}[/tex]
volume= 3 m³
In summary, the volume of the metal block is 3 m³.
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Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. How long will the ball be in the air before it lands? Round your answer to the nearest tenth.
s
How far will the football travel before it lands? Round your answer to the nearest tenth.
m
Answer:
See below
Explanation:
vertical velocity=13.9 sin 25
When it hits the ground y = 0
0 = vo t - 1/2 a t^2
0 = 13.9 sin 25 t - 1/2 (9.81)t^2
0 = 13.9 sin 25 - 1/2 (9.81) t shows t = 1.1976 ~ 1.2 sec
horizontal speed x time = distance
13.9 cos 25 x 1.1976 =15 .1 meters
compared to other spiral galaxies, the milky way is ____.
The Milky Way, a member of the "Local Group," is different than other galaxies in the universe. First, it is brighter than most galaxies that we have been able to see. Second, the Milky Way is a barred spiral galaxy; unlike typical spiral galaxies, barred spiral galaxies have flat discs in their centers.
Answer:
The Milky Way Galaxy, is a spiral galaxy, meaning that there are multiple arms spiraling in toward the middle of the galaxy. Are there any other galaxies in the universe shaped like the Milky Way Galaxy?
Please help me do that.
Answer:
a) 22.2 N
Explanation:
To find load effort. Identify load, efficiency and velocity ratio (VR)
Here given:
Load = 100 NEfficiency = 75%VR (number of pulleys) = 6Effort :
[tex]\rightarrow \sf \dfrac{MA}{VR} = \dfrac{Load \ \div \ efficiency }{VR} = \dfrac{100 \div 75 \% }{6} = 22.22 \ N[/tex]
Identify each statement that describes a benefit of the scientific method. (Select all choices that apply)
Group of answer choices
a) It provides an answer to questions immediately.
b) It gives scientists a standardized way to approach a problem.
C) It gives scientists a common vocabulary for sharing information.
D) It reduces bias and judgment from personal experiences.
The statements that describe a benefit of the scientific method are as follows:
It gives scientists a standardized way to approach a problem. It reduces bias and judgment from personal experiences. It gives scientists a common vocabulary for sharing information.Thus, the correct options are B, C, and D.
What is the Scientific method?The scientific method may be defined as a strategy of research in which a problem is recognized, relevant data is collected, a conjecture is composed of this data, and the assumption is empirically tested to determine the outcome of particular research.
The scientific method never explains or provides an answer to any question immediately because it consists of a scripted format with certain parameters.
The scientific method uses the identical vocabulary for sharing information with one another in particular terminology.
Therefore, it is well described above.
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The James Webb Space Telescope (JWST) will allow us to look back in time and observe the early universe. You are a scientist trying to observe an object that emitted its light a long time ago.
(a) Explain why the light you receive from the object is red-shifted.
The object has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 microme- tres (mid-infrared light).
(b) What is the wavelength of the light emitted by the object?
(c) What type of radiation was originally emitted by the object?
i will mark you as brainiest please help me sooner
#a
This is because red color has higher wavelength and it can clear universe and our atmosphere better,
This has the same reason as how we can see only red color during sunset.
#b
[tex]\boxed{\sf z=\dfrac{ \lambda-\lambda_o}{\lambda_o}}[/tex]
lambda_o be x
Put values
[tex]\\ \rm\Rrightarrow 7.6=\dfrac{2\times10^{-6}-x}{x}[/tex]
[tex]\\ \rm\Rrightarrow 7.6=\dfrac{2\times 10^{-6}}{x}-1[/tex]
[tex]\\ \rm\Rrightarrow 8.6=\dfrac{2\times 10^{-6}}{x}[/tex]
[tex]\\ \rm\Rrightarrow x=0.23\times 10^{-6}m[/tex]
[tex]\\ \rm\Rrightarrow x=0.23\mu m[/tex]
What is the degree measure of angle bac? round to the nearest whole degree. 19° 20° 70° 71°
The degree measure of angle ∠ bac will be 70°. Option C is correct.
What exactly is an angle?The angle is the distance between the intersecting lines or surfaces. In addition, the angle is expressed in degrees. The angle is 360 degrees for a full revolution.
Given expression;
[tex]\rm cos^{-1}(\frac{3.4}{10})=x \\\\ x = cos^{-1}(0.34) \\\\ x = 70.12^0[/tex]
The degree measure of angle ∠bac will be 70°.
Hence option C is correct.
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Answer:
70 Degrees
Explanation:
Geometry B E2020!! :3
which of the following is not a lever?
a. winch
b. scissors
c. can openers
d. tweezers
Answer:
a?
Explanation:yes it is a
A tennis ball moving with velocity v₁ hits a stationary tennis ball. The collision is inelastic and the two balls start travelling
together, as shown in the picture. What is the velocity of the two tennis balls moving
together?
A. 2v1
B. 1/2v1
C. 1/3v1
D. V1
Answer:
B.1/2v1 that's the answer
A violin sounds a note of F sharp, with a pitch of 370 Hz. What are the frequencies of the next three harmonics produced with this note?
Answer:
Answer 740 H z, 1110 H z, 1480 H z
Explanation:
The F sharp note (370 Hz) makes the next three harmonics with frequencies of 740 Hz, 1110 Hz, and 1480 Hz, respectively.
It is necessary to have an understanding of the relationship between harmonics and the fundamental frequency in order to calculate the frequencies of the following three harmonics produced by the note F sharp, which has a pitch of 370 Hz.
The fundamental frequency, denoted by f1, is the first harmonic and corresponds to the frequency of the note (F sharp in this example) when it was initially played. Its pitch is 370 hertz.
The fundamental frequency (f1) is multiplied by two to get the second harmonic frequency (f₂), which is written as f₂ = 2 × f1.
The frequency of the third harmonic (f₃) is equal to three times the frequency of the fundamental tone, or f₃ = 3 × f₁.
The frequency of the fourth harmonic, denoted by f₄, is equal to four times the frequency of the fundamental tone. f₄ = 4 × f₁
If we know that the fundamental frequency, or f₁, is 370 hertz, then we can figure out the frequencies of the following three harmonics, which are as follows:
f₂ = 2 × 370 Hz, which equals 740 Hz
f₃ = 3 times 370 Hz, which equals 1110 Hz; f₄ = 4 times 370 Hz, which equals 1480 Hz
Following the frequency of the F sharp note (370 Hz), the next three harmonics produced have frequencies of 740 Hz, 1110 Hz, and 1480 Hz respectively.
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You launch a model rocket that has a mass of 1.5 kg.At a height of 300m,it is traveling at 125 m/s.what is the kinetic energy at this point
Answer:
zero
Explanation:
Because if the object is not in motion then it only posseses potential energy not kinetic energy
Two marbles, one twice as heavy as the other, are dropped to the ground from the roof of a building. Just before hitting the ground, the heavier marble has 1. as much kinetic energy as the lighter one. 2. twice as much kinetic energy as the lighter one. 3. half as much kinetic energy as the lighter one. 4. four times as much kinetic energy as the lighter one. 5. impossible to determine
Given that one marble is twice as heavy as the other, the correct statement is: the heavier marble has twice as much kinetic energy as the lighter one
How to determine the energy of the lighter marbleMass = mAcceleration due to gravity = gHeight = hKinetic energy of light marble (KE₁) =?KE = PE = mgh
KE₁ = mgh
How to determine the energy of the heavier marbleMass = 2mAcceleration due to gravity = gHeight = hKinetic energy of heavier marble (KE₂) =?KE = PE = mgh
KE₂ = 2mgh
How to campare both kinetic energies Kinetic energy of light marble (KE₁) = mghKinetic energy of heavier marble (KE₂) = 2mghComparison (KE₂ / KE₁) =?KE₂ / KE₁ = 2mgh / mgh
KE₂ / KE₁ = 2
Cross multiply
KE₂ = 2 × KE₁ =
KE₂ = 2KE₁
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The force of gravity between two objects is greatest when the objects have?
The force of gravity increases as the product of their individual masses' increases
Hope it helps!
