Answer:
Decay Problem.Decay rate, r = 0.014Initial Amount =120,000[tex]P(t)=120000(0.986)^t[/tex]P(10)=104,220Step-by-step explanation:
The exponential function for growth/decay is given as:
[tex]P(t)=P_0(1 \pm r)^t, where:\\P_0$ is the Initial Population\\r is the growth/decay rate\\t is time[/tex]
In this problem:
The city's initial population is 120,000 and it decreases by 1.4% per year.
Since the population decreases, it is a Decay Problem.Decay rate, r=1.4% =0.014Initial Amount =120,000Therefore, the function is:
[tex]P(t)=120000(1 - 0.014)^t\\P(t)=120000(0.986)^t[/tex]
When t=10 years
[tex]P(10)=120000(0.986)^10\\=104219.8\\\approx 104220 $ (to the nearest whole number)[/tex]
NOT SURE NEED HELP PLEASE
Answer:
bh
6, 17
102
51
Step-by-step explanation:
Answer:
1/2 (bh)
1/2(17)(6)
51
three friends went to a restraunt and ordered two orders of wings and three soft drinks. their bill totaled $22.50. later that day, five friends went to the same restraunt and ordered three orders of wings and a soft drink each. their bill totaled $34.50. write and solve a system of equations to determine the price of one order of wings.
Answer:
$9
Step-by-step explanation:
Let the price of one order of wings be w.
Let the price for one order of soft drinks be s.
Three friends went to a restaurant and ordered two orders of wings and three soft drinks. Their bill totaled $22.50. This means that:
2w + 3s = 22.50 _____________(1)
Five friends went to the same restaurant and ordered three orders of wings and a soft drink each. Their bill totaled $34.50. This means that:
3w + 5s = 34.50 ______________(2)
We have a system of quadratic equations:
2w + 3s = 22.50 _____________(1)
3w + 5s = 34.50 ______________(2)
Multiply (1) by 5 and (2) by 3:
10w + 15s = 112.50 _______(3)
9w + 15s = 103.50 _______(4)
Subtract (4) from (3):
w = $9
Therefore, the price of one order of wings is $9.
A soup can has a diameter of 8 centimeters and a height of 15 centimeters how much soup does the can hold?
Answer:
V = 240 pi
Step-by-step explanation:
We want the volume of a cylinder
V = pi r^2 h
We have the diameter and want the radius
r = d/2 = 8/2 = 4
V = pi ( 4)^2 * 15
V = pi * 16* 15
V = 240 pi
Let pi = 3.14
V =753.6 cm^3
Let pi be the pi button
V =753.9822369 cm^3
Answer:
240 pi
Step-by-step explanation:
found the answer online so now work (don't delete my answer)
5 inches is blank times big as 1 inch
Answer:
5 inches is 5 times as big as 1 inch
A physicist examines 25 water samples for nitrate concentration. The mean nitrate concentration for the sample data is 0.165 cc/cubic meter with a standard deviation of 0.0783. Determine the 80% confidence interval for the population mean nitrate concentration. Assume the population is approximately normal. Step 1 of 2 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Answer:
The 80% confidence interval for the the population mean nitrate concentration is (0.144, 0.186).
Critical value t=1.318
Step-by-step explanation:
We have to calculate a 80% confidence interval for the mean.
The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.
The sample mean is M=0.165.
The sample size is N=25.
When σ is not known, s divided by the square root of N is used as an estimate of σM:
[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{0.078}{\sqrt{25}}=\dfrac{0.078}{5}=0.016[/tex]
The degrees of freedom for this sample size are:
[tex]df=n-1=25-1=24[/tex]
The t-value for a 80% confidence interval and 24 degrees of freedom is t=1.318.
The margin of error (MOE) can be calculated as:
[tex]MOE=t\cdot s_M=1.318 \cdot 0.016=0.021[/tex]
Then, the lower and upper bounds of the confidence interval are:
[tex]LL=M-t \cdot s_M = 0.165-0.021=0.144\\\\UL=M+t \cdot s_M = 0.165+0.021=0.186[/tex]
The 80% confidence interval for the population mean nitrate concentration is (0.144, 0.186).
A car company claims that its cars achieve an average gas mileage of at least 26 miles per gallon. A random sample of eight cars form this company have an average gas mileage of 25.5 miles per gallon and a standard deviation of 1 mile per gallon. At α=0.06, can the company’s claim be supported, assuming this is a normally distributed data set?
Answer:
[tex]t=\frac{25.5-26}{\frac{1}{\sqrt{8}}}=-1.414[/tex]
The degrees of freedom are given by:
[tex]df=n-1=8-1=7[/tex]
The p value for this case is given by:
[tex]p_v =P(t_{(7)}<-1.414)=0.100[/tex]
Since the p value is higher than the significance level of 0.06 we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 25.5 and then the claim makes sense
Step-by-step explanation:
Information given
[tex]\bar X=25.5[/tex] represent the sample mean
[tex]s=1[/tex] represent the sample standard deviation
[tex]n=8[/tex] sample size
[tex]\mu_o =26[/tex] represent the value to verify
[tex]\alpha=0.06[/tex] represent the significance level
t would represent the statistic (variable of interest)
[tex]p_v[/tex] represent the p value
Hypothesis to est
We want to test if the true mean is at least 26 mpg, the system of hypothesis would be:
Null hypothesis:[tex]\mu \geq 25.5[/tex]
Alternative hypothesis:[tex]\mu < 25.5[/tex]
The statistic for this case is given by;
[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)
Replacing the info given we got:
[tex]t=\frac{25.5-26}{\frac{1}{\sqrt{8}}}=-1.414[/tex]
The degrees of freedom are given by:
[tex]df=n-1=8-1=7[/tex]
The p value for this case is given by:
[tex]p_v =P(t_{(7)}<-1.414)=0.100[/tex]
Since the p value is higher than the significance level of 0.06 we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 25.5 and then the claim makes sense
Create an explicit formula for the following sequence 1/3,-1,3,-9
Answer:
multiply by -3
Step-by-step explanation:
1/3 gives -3/3=-1
-1*-3=3
3*-3=-9
it defines the function f so that f(x)=-3x
the revenue function for a school group selling n bookmarks is given by R(n) =2n and the total cost function is given by C(n)=144+0.08n. determine the number of books
Correction
The revenue function for a school group selling n bookmarks is given by R(n) =2n and the total cost function is given by C(n)=144+0.08n. Determine the number of bookmarks sold at which they break-even.
Answer:
75 bookmarks
Step-by-step explanation:
The break-even point is the point at which revenue earned is equal to the cost of production.
Given the cost and revenue functions respectively:
R(n) =2nC(n)=144+0.08nCost=Revenue
C(n)=R(n)
144+0.08n=2n
144=2n-0.08n
144=1.92n
Divide both sides by 1.92
n=75
When 75 bookmarks are sold, the school group will break even.
76,80,88,95,100,101,? Which number comes next in this sequence?
Answer:
112
Step-by-step explanation:
Difference between each 4,8,7,5,1
Add numbers next to each other in pairs = 12
So 12-1= 11 and
101+11=112
A designer makes a model of a patio using 1/2 inch square tiles each 1/2 inch square tiles = 4 square feet what area is represented by the 8 x 6 model
Answer:
[tex]192ft^2[/tex]
Step-by-step explanation:
The model of a patio was made by
using 1/2 inch square title=4 square feet.
area represented by the 8 *6 model can be calculated as follows;
FIRSTLY, the number of tiles in the 8 *6 model can be calculated by multiplying it i.e
8 *6 model =[tex]48 tiles[/tex]
Hence there are 48 tiles in 8 *6 model
It was given that 1/2 inch square title=4
square feet.
So to calculate the total Area occupied by the 48 tiles
[tex]Area=1/2×48[/tex]
[tex]Area=24inches^2[/tex]
If [tex]1/2inches^2=4ft^2[/tex] ( from the question)
Let X represent [tex]24inches^2[/tex]
Then, [tex]24inches^2=Xft^2[/tex]
Cross multiply
[tex]4×24=X×1/2
X=4×24×2
X=[tex]192ft^2[/tex]
[tex]24inches^2=[tex]192ft^2[/tex]
Therefore, the area represented by the 8 *6 model is [tex]192ft^2[/tex]
John has grades of 82 and 98 on his first two history tests. What must he score on his third test so that his average is at least 88?
John's average on all three tests, assuming a score of S on the third test, would be
(82 + 98 + S)/3
He wants the average to be at least 88, so solve the inequality:
(82 + 98 + S)/3 ≥ 88
82 + 98 + S ≥ 264
180 + S ≥ 264
S ≥ 84
So John needs to obtain a grade of at least 84 on the third test to get the average he wants.
The score on his third test is 84 so that his average is at least 88 given first two grades 82 and 98. This can be obtained by using the formula to find average.
What is the formula to find average?Average of observations is the ratio of sum of observations to total number of observations.
How do we find the third grade using average formula?
Grade of first test=82
Grade of second test = 98
let grade of third test be x
Average of the grades = [tex]\frac{82+98+x}{3}[/tex] ≥ 88
[tex]\frac{180+x}{3}[/tex] ≥ 88 ⇒ x ≥ 246-180 ⇒ x ≥ 84
Hence we can say that the score on his third test is 84 so that his average is at least 88 given first two grades 82 and 98.
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Confidence Intervals for Curved Gaussian Family Bookmark this page (a) 1 point possible (graded) Let X1,…,Xn be i.i.d. random variables with distribution N(θ,θ) , for some unknown parameter θ>0 . True or False: The sample average X¯¯¯¯n follows a normal distribution for any integer n≥1 .
a. true
b. false
Answer:
True
True
Step-by-step explanation:
The unknown parameters are treated as variable and data serve as coefficients. The random variables are value whose outcome depends on some random event. The θ can exist when n ≥ 0. A sample mean is a sequence which has normal distribution and n ≥ 1. The sample average of X-n follows normal distribution for all integer and n is greater or equal to 1.
The given statement is True
Random variable:The unknown parameters should be considered variable and data represent the coefficients. The random variables refers to the value where outcome based on some random event. The θ could exist at the time when n ≥ 0. A sample mean represent the sequence that contains normal distribution and n ≥ 1.
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x + 10 + 9x=14x-58 can anyone answer this?
The answer to your problem is: X=17
Answer:
17
Step-by-step explanation:
x + 10 + 9x=14x-58
x + 9x + 10 =14x-58
10x + 10 =14x-58
By grouping like terms by moving 14x to the left and 10 to the right of the equation; we have:
10x - 14x =-58-10
-4x=-68
x=-68/-4=17{ dividing both sides by -4}
Question 1 Muit Choice Worth 1 points)
(08.01 LC)
The school principal wants to know whether the students in the entire school prefer football or basketball. The principal draws a random sample from the following groups:
• All school teachers
. All girls in each grade
. All students in each grade
• All students on the basketball team
Which of the following groups best represents the population she should take a random sample from to get the best results for her survey?
All school teachers
All girls in each grade
All students in each grade
All students on the basketball team
Answer:
I think its C. All students in each grade
Step-by-step explanation:
because it should be the students choice.
ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. I say no guessing because people usually guess on my questions. CHECK ALL THAT APPLY
Answer:
A. it would be shifted up
Step-by-step explanation:
Y=MX+B
B is the Y-intercept.
Answer:
a. it would be shifted up
Step-by-step explanation:
the difference between the original and the new function is that the b value is changed from -6 to +8, meaning the y-intercept value has increased. this would shift the graph up by 14.
From an urn containing 3 white and 2 black balls, two balls are drawn one after the other without replacement. What is the probability that the first ball drawn is white and the second black?
Answer:
There is a 3/5 chance of the first ball being white, and a 3/10 chance the second one is black.
Step-by-step explanation:
There are 5 balls, of which 3 are white, so you have a 3/5 chance of the first one being white. Then you have 2 white and 2 black balls. There is a 2/4 chance of picking a black ball. Multiply 3/5 and 2/4 to get 6/20, or 3/10 for choosing a white ball then a black ball.
What is the answer to x>-8
Answer:
Sorry, I cant understand rewrite it again.
the number of ants per acre in the forest is normally distributed with mean 42000 and standard deviation 12275. let x = number of ants in a randomly selected acre of the forest. Round all answers to 4 decimal places where possible. Find the probability that a randomly selectd acre has between 32647 and 43559 ants.
Answer:
0.3182 = 32.81% probability that a randomly selected acre has between 32647 and 43559 ants.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 42000, \sigma = 12275[/tex]
Find the probability that a randomly selectd acre has between 32647 and 43559 ants.
This is the pvalue of Z when X = 43559 subtracted by the pvalue of Z when X = 32647. So
X = 43559:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{43559 - 42000}{12275}[/tex]
[tex]Z = 0.13[/tex]
[tex]Z = 0.13[/tex] has a pvalue of 0.5517.
X = 32647:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{32647 - 42000}{12275}[/tex]
[tex]Z = -0.76[/tex]
[tex]Z = -0.76[/tex] has a pvalue of 0.2236
0.5517 - 0.2236 = 0.3281
0.3182 = 32.81% probability that a randomly selected acre has between 32647 and 43559 ants.
A statistician calculates that 9% of Americans are vegetarians. If the statistician is correct, what is the probability that the proportion of vegetarians in a sample of 471 Americans would be greater than 8%
Answer:
The probability that the proportion of vegetarians in a sample of 471 Americans would be greater than 8% is P=0.776.
Step-by-step explanation:
We have to calculate a probability that a sample of n=471 has a proportion greater than 8%, given that the population proportion is 9%.
First, we have to calculate the parameters of the sampling distribution of the proportions:
[tex]\hat{p}=p=0.09\\\\\\\sigma_{\hat{p}}=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.09\cdot 0.91}{471}}=0.0132[/tex]
Now, we can calculate the probability using the z-score:
[tex]z=\dfrac{p-\hat{p}}{\sigma_{\hat{p}}}=\dfrac{0.08-0.09}{0.0132}=\dfrac{-0.01}{0.0132}=-0.7576[/tex]
Then, the probability is:
[tex]P(p>0.08)=P(z>-0.7576)=0.776[/tex]
if f(x) =2x^2+5 (x-2) completel the following statement f(3)=
Answer:
41
Step-by-step explanation:
f(3) = 2(3)^2 +5(x-2)
= 2(18)+ 5
= 41
what is the range of the exponential function shown below? f(x)=9*2^x
Answer:
(0, ∞)
Step-by-step explanation:
An exponential function has a horizontal asymptote at y=0. Its vertical extent is toward infinity.
The range is ...
0 < f(x) < ∞
Let x represent the number. Use the given conditions to write an equation. Solve the equation and find the number.
The product of 8 and a number is 96. Find the number.
Write an equation for the given conditions.
Answer:
12
Step-by-step explanation:
8x=96
x=96/8
x=12
Answer:
12
Step-by-step explanation:
8x=96
96/8
x=12
so the the product of 8and 12=96
Write the coordinates of the vertices of a triangle A'B'C' that results from a translation of triangle ABC two units to the right and four units down .
Answer:
A'(4,-6) , B'(0,1), C'(-2,-2)
Step-by-step explanation:
From the given graph the coordinates of ΔABC area A (2,-2), B(-2,5) and C(-4,2)
If a translation is applied on ΔABC two units to the right and four units down to create ΔA'B'C'.
Then to find the coordinates of ΔA'B'C' will be we need to apply the translation rule
[tex](x,y)\rightarrow(x+2,y-4)[/tex]
Now, [tex]A(2,-2)\rightarrow A'(2+2,-2-4)=A'(4,-6)[/tex]
[tex]B(-2,5)\rightarrow B'(-2+2,5-4)=B'(0,1)[/tex]
and [tex]C(-4,2)\rightarrow C'(-4+2,2-4)=C'(-2,-2)[/tex]
A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n = 1083 and x=550 who said “yes “ Use a 99% confidence level
A. Find the best point estimate of the population p.
Step-by-step explanation:
p = x / n
p = 550 / 1083
p = 0.5078
What value of x is in the solution set of 2x – 3 > 11 – 5x?
Given:
2x -3 > 11 -5x
Simplify both sides:
2x - 3 > -5x + 11
Add 5x to both sides:
2x - 3 +5x > -5x + 11 +5
7x - 3 > 11
Add 3 to both sides:
7x - 3 +3 > 11 + 3
7x > 14
Divided 7 to both sides:
[tex]\frac{7x}{7}[/tex] > [tex]\frac{14}{7}[/tex]
x > 2
Answer:
Any number greater than 2 would be the answer. In Edg, choose 4! Choosing 2 would be incorrect in their system.
Step-by-step explanation:
If 3^2+1 =3^x+5. What is the value of x?
Answer:
[tex]x=1.464974[/tex]
Step-by-step explanation:
[tex]3^2+1 =3^x+5[/tex]
[tex]9+1 =3^x+5[/tex]
[tex]10 =3^x+5[/tex]
[tex]10-5 =3^x[/tex]
[tex]5=3^x[/tex]
[tex]log(3x)=log(5)[/tex]
[tex]x \times (log(3))=log(5)[/tex]
[tex]x=\frac{log(5)}{log(3)}[/tex]
[tex]x=1.464974[/tex]
Answer: 1.46497352 or 1.5
Step-by-step explanation:
Complete 3^2 to get 9, then add 1 to get 10
Then subtract 5 from both sides to get [tex]5=3^x[/tex]
Youre gonna have to apply a log rule here to get:
[tex]log_{3}5=x[/tex]
You get 1.46497352 or approximately 1.5
Parallelogram L M N O is shown. Angle M is (3 x minus 55) degrees, angle N is (5 y) degrees, and angle O is (2 x) degrees. In parallelogram LMNO, what are the values of x and y?
Answer:
x=55,y=14
Step-by-step explanation:
<M = <{opposite angles of a parallelogram are congruent and equal}
Hence 3x-55 = 2x=>3x-2x= 55 =>x=55
Simarly;
M+N=180°{ sum of angles in a parallelogram is 180°}
N= 180°-M=>N=180-(3x-55)=180-(3x55-55)= 180- 110=70°
N=70°=>5y=70=>y=70/5=14
therefore x=55,y=14
Answer:
55 and 14
Step-by-step explanation:
i just took the test
A report about how American college students manage their finances includes data from a survey of college students. Each person in a representative sample of 793 college students was asked if they had one or more credit cards and if so, whether they paid their balance in full each month. There were 500 who paid in full each month. For this sample of 500 students, the sample mean credit card balance was reported to be $825. The sample standard deviation of the credit card balances for these 500 students was not reported, but for purposes of this exercise, suppose that it was $200. Is there convincing evidence that college students who pay their credit card balance in full each month have a mean balance that is lower than $905, the value reported for all college students with credit cards
Answer:
Yes. There is enough evidence to support the claim that college students who pay their credit card balance in full each month have a mean balance that is lower than $905.
Step-by-step explanation:
We want to test the claim that college students who pay their credit card balance in full each month have a mean balance that is lower than $905.
To perform this test we have a sample of 500 students which have paid their balance in full each month. The sample mean is $825 and the estimated sample deviation is considered $200.
Then, the null and alternative hypothesis are:
[tex]H_0: \mu=905\\\\H_a:\mu< 905[/tex]
The significance level is 0.05.
The sample has a size n=500.
The sample mean is M=825.
The estimated standard error of the mean is computed using the formula:
[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{200}{\sqrt{500}}=8.94[/tex]
Then, we can calculate the t-statistic as:
[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{825-905}{8.94}=\dfrac{-80}{8.94}=-8.94[/tex]
The degrees of freedom for this sample size are:
[tex]df=n-1=500-1=499[/tex]
This test is a left-tailed test, with 499 degrees of freedom and t=-8.94, so the P-value for this test is calculated as (using a t-table):
[tex]\text{P-value}=P(t<-8.94)=0[/tex]
As the P-value (0) is smaller than the significance level (0.05), the effect is significant.
The null hypothesis is rejected.
There is enough evidence to support the claim that college students who pay their credit card balance in full each month have a mean balance that is lower than $905.
Triangle ABC has been dilated about point A by a scale factor of One-third.
Triangle A B C. Side A C has a length of 39, side A B is 30, side C B is 48. Triangle A prime B prime C prime.
What are the lengths, in units, of the three sides of Triangle A prime B prime C prime?
Answer:
10,16,13
Step-by-step explanation:
got that right
The lengths of the sides of the triangle after the dilation is 13 , 10 and 16 respectively
What is Dilation?Resizing an item uses a transition called Dilation. Dilation is used to enlarge or contract the items. The result of this transformation is an image with the same shape as the original. However, there is a variation in the shape's size. Dilation transformations ensure that the shape will stay the same and that corresponding angles will be congruent
Given data ,
Let the triangle be represented as ABC
Now , the dilated triangle is represented as A'B'C'
The dilation scale factor is d = 1/3
The measure of side AC = 39
The measure of side AB = 30
The measure of side BC = 48
Now , after the dilation of 1/3 , we get
The measure of side A'C' = 39 ( 1/3 ) = 13
The measure of side A'B' = 30 ( 1/3 ) = 10
The measure of side B'C' = 48 ( 1/3 ) = 16
Hence , the dilation triangle is having lengths 13 , 10 and 16
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Please answer this correctly
Answer:
Area of the figure = 169.5 yards²
Step-by-step explanation:
Area of Rectangle = Length × Width
Area of triangle = 1/2(base × height)
We'll divide the whole figure into parts so that we can find the area more easily!
Rectangle 1 (uppermost):
10 × 4 = 40 yards²
Square 1 (right below the rectangle 1):
7 × 7 = 49 yards²
Rectangle 2 (with square 1):
7 × 3 = 21 yards²
Triangle 1 (Below rectangle 2):
1/2(17 × 7) = 119/2 = 59.5 yards²
Now adding up all to get the area of the whole figure:
Area of the figure = 40 + 49 + 21 + 59.5
Area of the figure = 169.5 yards²