It's not A. Please help.
Answer:
It represents double composition
‼️ IN DESPERATE NEED OF HELP ‼️ i have a time limit of 20 minutes and i’m so lost, please help with a step-by-step explanation
The blue color of the sky results from the scattering of sunlight by air molecules. If the blue light of the sky
has a frequency of about 7.5 x 10“ Hz, what is the wavelength of this radiation (in m)?
0.00004
Explanation:
velocity of electromagnetic waves = 3.0×10^8.
Wavelength=velocity/frequency
(3.0×10^8) (7.5×10^12)
Please help.
Which has the greatest net force?
A 30-kg box falling from a window, with air resistance
A 2,000-kg car with a constant velocity of 35 m/s
A 30-kg box falling on the Moon
A 2-kg soccer ball accelerating at 22 m/s2
In the simulation, start with m1 = 200 kg and m, = 400 kg with their centers 8 meters apart. If you want to increase in the gravitational force between the two masses by the greatest amount, should you double the mass of m, or should you halve the distance sentences, explain which option would create the greater increase in the gravitational force and why. (2 points)
To double the gravitational force between the two blocks, double the mass of the blocks and keep the distance between constant.
The given parameters;
mass of the first block, m₁ = 200 kgmass of the second block, = 400 kgcenter mass of the blocks, r = 8 mThe gravitational force between the two mass is calculated by applying Newton's law of universal gravitation as follows;
[tex]F = \frac{Gm_1 m_2}{r^2}[/tex]
The magnitude of the gravitational force increases with increase in the mass of the blocks and decreases with increase in the distance between the blocks.
To double the gravitational force between the blocks, double the mass of the blocks;
[tex]F = \frac{G(2m_1)(2m_2)}{r^2} \\\\F = 2 \times \frac{Gm_1 m_2}{r^2}[/tex]
Thus, to double the gravitational force between the two blocks, double the mass of the blocks and keep the distance between constant.
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A soccer ball is kicked from ground level at a velocity of 40 m/s at an angle of 30o
above
the horizontal. Find:
a. Hang Time (total time the ball is in the air)
b. The ball’s maximum height
c. The ball’s Range
Answer:
b the balls maximum height
guys are our body made out of 70 percet water?
Answer:
I'm pretty Sure. Yea look.
Explanation:
Up to 60% of the human adult body is water. According to H.H. Mitchell, Journal of Biological Chemistry 158, the brain and heart are composed of 73% water, and the lungs are about 83% water. The skin contains 64% water, muscles and kidneys are 79%, and even the bones are watery: 31%.
please help ! Which of the following objects has the greatest momentum?
Answer:
maybe the third one....
A race car travels on a straight racetrack with
a forward velocity of 44 m/s and slows at a
constant rate to a velocity of 22 m/s over 11 s.
How far does it move during this time?
Answer:968 m/s
Explanation:
If a race car travels on a straight racetrack with a forward velocity of 44 m/s and slows at a constant rate to a velocity of 22 m/s over 11 s, then the distance traveled by the race car would be 343 m.
What are the three equations of motion?There are three equations of motion given by Newton
The first equation is given as follows
v = u + at
the second equation is given as follows
S = ut + 1/2×a×t²
the third equation is given as follows
v² - u² = 2×a×s
As given in the problem Question a race car travels on a straight racetrack with a forward velocity of 44 m/s and slows at a constant rate to a velocity of 22 m/s over 11 s,
initial velocity = 22 m/s
final velocity = 44 m/s
time = 11 s
By using the first equation of motion,
v = u + at
44 = 22 + 11a
11a = 22
a = 2 m/s²
By using the second equation of motion,
S = ut + 1/2*a*t²
u= 22m/s , a= 2m/s² and t = 11seconds
S = 22*11 + 0.5*2*11²
S = 222+121
S= 343 m
Thus, the distance covered by the race car would be 343 m.
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When does the air parcel stop losing energy?
Answer:
If there is no cloud (liquid water) in the parcel
Explanation:
Answer:
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What are the two factors that affect the force of gravity?
Answer:
there u go if u feel answer is good plzz mark me brainlest
Explanation:
When dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.
Answer:
The factors that affect the force of gravity are :
i) Mass
ii) Acceleration
. What is the kinetic energy of a 10 kg car that is moving 4 m/s?
Answer:
80 joule
Explanation:
The formula of kinetic energy is 1/2 mv2.
Material
Density (g/cm)
water
1.0
aluminum
2.7
iron
7.9
silver
10.5
gold
19.3
Use the chart above to find the identity of the unknown sample
Answer:Gold is metallic, with a yellow color when in a mass, but when excellently separated it may be black, ruby, or purple. Your density numbers have no units, so they are unusable.
If the numbers you give match to the densities of the given metal in g/ml or kg/L, it should be gold.
Density = mass/volume, so:
96.5g/5ml = 19.3 g/ml. So the answer is 19.3 gold.
Explanation:
could earth-like beings inhabit any other planets in our solar system? how? and why?
Your question says 'in our solar system.' It might or might not be possible. It actually depends on whether the temperature of the planet, the atmosphere, availability of water & food & the things found there suit the needs of the organisms. As of now, no planet in our solar system or in the universe support the inhabitants of earth-like beings. But who knows? It's not entirely impossible either. Scientists say there were remains of water found in Mars which might prove the existence of extraterrestrials. Still, it has not been proved.
_________
RainbowSalt2222 ☔
It measures only small earthquakes.
It collects data using a seismograph.
It shows only the strength of seismic waves that were produced.
It determines the amount of damage caused by an earthquake.
Answer:
It measures only small earthquakes.
It collects data using a seismograph.
Explanation:
hope this helps
Answer: b. It uses data collected by a seismograph.
Explanation:
A 65 kg passenger in a car travels at a speed of 8.0 m/s. If the passenger is stopped by an airbag in 0.75 s, how much force is required?
F=ma,a,=v/t ,=65(8/0.75)=693.33
displacement is simply change in position. What is the largest displacement you have experienced in a singale day
Well that happens to me all the time.
Suppose that the system were placed in an elevator that accelerates downward at 2 m/s2. What would the scale read?.
The reading on the scale when the system is placed on elevator accelerating downward is 7.8m (N).
The given parameter
downward acceleration, a = 2 m/s²The reading on the scale is determined by applying Newton's second law of motion;
R = mg - ma
R = m(g - a)
R = m(9.8 - 2)
R = 7.8 m. (N)
where;
m is the mass of the systemThus, the reading on the scale when the system is placed on elevator accelerating downward is 7.8m (N).
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What is the relationship between kinetic energy and changing states of matter?
Answer:
The kinetic molecular theory of matter states that: Matter is made up of particles that are constantly moving. All particles have energy, but the energy varies depending on the temperature the sample of matter is in. This in turn determines whether the substance exists in the solid, liquid, or gaseous state.
A 76-kg water skier is being pulled by a nylon (Young's modulus 3.7 x 109 N/m2) tow rope that is attached to a boat. The unstretched length of the rope is 19 m and its cross-section area is 1.6 x 10-5 m2. As the skier moves, a resistive force (due to the water) of magnitude 140 N acts on her; this force is directed opposite to her motion. What is the change in length of the rope when the skier has an acceleration whose magnitude is 0.61 m/s2?
Newton's second law and the definition of Young's modulus allows us to find the change in length in the chord is:
Length change is: ΔL = 5.98cm
Given parameters
Mass of the water skier m = 76 kg Young's modulus of chord Y = 3.7 10⁹ N / m² Chord length Lo = 19 m. The area of the curda is a = 1.6 10-5 m² Friction force with water fr = 140 N. Acceleration a = 0.61 m / s²To find
The change in length of the chord.
Newton's second law says that the net force on a body is directly proportional to its mass and acceleration.
∑ F = m a
where bold letters indicate vectors, F is force, m is mass, and acceleration.
A free-body diagram is a diagram of the forces without the details of the bodies, see attached.
T-fr = m a
T = ma + fr
Let's calculate.
T = 76 0.61 + 140
T = 186.36 N
Yung's modulus is defined by the relationship between stress and strain.
[tex]Y = \frac{\frac{F}{A} }{\frac{\Delta L}{L_o} }[/tex]
[tex]\Delta L = \frac{F}{A} \ \frac{L_o}{Y}[/tex]
Let's calculate.
ΔL = [tex]\frac{186.36}{1.6 \ 10^{-5}} \ \frac{19}{3.7 \ 10^9}[/tex]
ΔL = 5.98 10⁻² m = 5.98 cm
In conclusion using Newton's second law and Young's modulus definition we can find the change in length in the chord is:
Length change is: ΔL = 5.98cm
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A steel ball is at one end of a box that is moving forward as shown. The box suddenly stops. According to Newton's first law, what happens to the steel ball just after the box stops
According to Newton's first law, the steel ball will be reluctant to stop and want to continue in the motion. What will happen is that, the steel ball will either take a parabolic motion forward or move with a great speed to hit the front end of the box
According to Newton's first law, an object which is at rest will continue to remain at rest or in motion in a straight line will continue to move in a straight line except an external force act on it.
That means if a body is at rest, the body will be reluctant to start moving. And when a body is in a motion, it will be reluctant to stop. This is known as inertia
A steel ball that is at one end of a box that is moving forward is already experiencing motion in a straight line. If the box suddenly stops, According to Newton's first law, the steel ball will be reluctant to stop and want to continue in the motion. What will happen is that, the steel ball will either take a parabolic motion forward or move with a great speed to hit the front end of the box just after the box stops.
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In the apparatus shown above, one end of a string of length L is attached to a block of mass M and the other end is connected to the axle of a motor that rotates, causing the block to move in a circle of radius R at a constant speed vT such that the string makes an angle θ with the vertical. A student wants to use the apparatus to make measurements and create a graph that can be used to estimate the acceleration g due to gravity at the surface of Earth. The student can adjust the motor to achieve different tangential speeds of the block
Newton's second law allows finding the result for the type of graph to find the gravity acceleration is:
The student must make a graph of the tangential velocity versus the tangent of the angle and of the slope to find the value of gravity.g = [tex]\frac{slope}{\sqrt{L} }[/tex]
Oscillatory motion is a simple harmonic motion where the restoring force is proportional to the displacement.
Newton's second law gives a relationship between the net force, the mass and the acceleration of a body, in the attached we can see a free body diagram of the system, let's apply Newton's second law.
[tex]t_y - W =0 \\T_x = m a[/tex]
Since the movement is circular, the acceleration is centripetal.
[tex]a = \frac{v^2}{r}[/tex]
Let's substitute.
[tex]t_x = m \frac{v^2}{r}[/tex]
Let's use trigonometry to find the radius of the circle and the stress component.
sin θ = [tex]\frac{r}{L}[/tex]
r = L sin θ
sin θ = [tex]\frac{T_x}{T}[/tex]
cos θ = [tex]\frac{T_y}{T}[/tex]
Tₓ = T sin θ
[tex]T_y[/tex] = T cos θ
Let's substitute.
T sin θ = [tex]\frac{m v^2 }{L sin \theta }[/tex]
T sin² θ = [tex]\frac{m}{L} \ v^2[/tex]
From the other equation.
[tex]T_y= W \\T cos \theta = m g[/tex]
Let's write our system of equations.
T sin² θ = [tex]\frac{m}{L} \ v^2[/tex]
T cos θ = m g
We solve the system by squaring the second equation and dividing.
tan² θ = [tex]\frac{1}{g^2 L } \ v^2[/tex]
L g² tan² θ = v²
v = g [tex]\sqrt{L}[/tex] tan θ
Consequently, if the student makes a graph of the velocity versus the tangent of the angle, he obtains a straight line and the slope is:
slope = g [tex]\sqrt{L}[/tex]
From this expression you can calculate the acceleration of gravity.
[tex]g= \frac{slope}{\sqrt{L} }[/tex]
In conclusion using Newton's second law we can find the result for the type of graph to find the gravity acceleration is:
The student must make a graph of the tangential velocity versus the tangent of the angle and of the slope to find the value of gravity.[tex]g = \frac{slope}{\sqrt{L} }[/tex]
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What is the smallest possible wavelength of light?
Explanation:
Blue or violet light has the shortest wavelength. White light is a combination of all colors in the color spectrum.
A ball was positioned in the middle of a smooth ramp and allowed to roll
downward. How does the total mechanical energy of the ball before it is
released compare to its total mechanical energy at the bottom of the ramp?
Assume there is no friction.
Answer:
These are all the forces acting on the ball: friction, gravity, and a normal force.
Explanation:
At the middle of the ramp their will be potential energy associated with the ball and the total mechanical energy will be equal to its potential energy . At the bottom of the ramp their will be kinetic energy associated with the ball and total mechanical energy will be equal to its kinetic energy .
What is mechanical energy ?Mechanical energy is the energy that is possessed by an object due to its motion or due to its position.
Total mechanical energy = potential energy + kinetic energy
When ball is positioned in the middle of the ramp , the ball is at rest , which implies that total mechanical energy is equal to potential energy possessed by the ball and their is no kinetic energy at that instant of time , after that it came under the action of forces due to which it rolls down and its potential energy starts converting into kinetic energy and the total mechanical energy will be the sum of potential as well as kinetic energy and when it reaches at the bottom of the ramp the total mechanical energy will be kinetic energy of the ball.
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when partners representing multiple jurisdictions and agencies
Answer:
When partners representing multiple jurisdictions or agencies work together to establish the incident objectives, Unified Command is being used.
Explanation:
If the absolute temperature of a gas is doubled and the pressure of the gas is doubled, how will the volume change
Answer: the volume quadruples
Explanation:
Which of the following is a vector quantity?
Answer:
D
Explanation:
A vector quantity is an object with both magnitude and direction, like velocity.
:))
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Many fitness apps have features that allow you to share results on social media. Are there benefits to this kind of sharing?
A.
No, workouts are about achieving your personal best.
B.
No, people often compare themselves to others on social media.
C.
Yes, sharing provides accountability, making exercise more likely to stick.
D.
Yes, all aspects of daily life should be shared on social media when possible.
PLEASE NO LINKS
Answer:
I think the correct answer is A
The density of aluminum is 2700 kg/m3. If transverse waves propagate at 34 m/s in a 4.6-mm diameter aluminum wire, what is the tension on the wire
Answer:
52N
Explanation:
v=SQRT(T/μ), μ=pA, A=πr^2
v=SQRT(T/pπr^2)
v^2=T/pπr^2
v^2*pπr^2=T
34^2*2700*π*0.0023^2=T
T=52N
The tension on the aluminum wire at the given density is 52.02 N.
Tension in the wire
The tension in the wire is calculated using the following formulas;
[tex]v = \sqrt{\frac{T}{\mu} }[/tex]
where;
v is speed of the sound waveT is the tension in the wireμ is mass per unit lengthArea of the aluminum wireA = πd²/4
A = π x (4.6 x 10⁻³)²/4
A = 1.66 x 10⁻⁵ m²
Mass per unit length of the wireμ = ρA
μ = 2700 kg/m³ x 1.66 x 10⁻⁵ m²
μ = 0.045 kg/m
Tension on the wire[tex]34 = \sqrt{\frac{T}{0.045} } \\\\34^2 = \frac{T}{0.045}\\\\T = (34^2)(0.045)\\\\T = 52.02 \ N[/tex]
Thus, the tension on the aluminum wire at the given density is 52.02 N.
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Why does a sealed bag of chips expand when you take it to a higher altitude?
Answer:
As the atmospheric pressure decreases with increase in altitude, when a sealed bag of chips is taken to higher altitude then the pressure of the gases inside the bag become greater than the outer atmospheric pressure and apply pressure on the side covering of the chips bag due to which the chips bag expand.
Which gas is least likely to obey the ideal gas laws at very high pressures and very low temperatures?
Answer:
Xe
Explanation:
At low temperatures or high pressures, real gases deviate significantly from ideal gas behavior. It is also good to know that ideal gas law assumes that the gas molecules have negligible/no size.
Keeping that in mind, Xe is the largest of the bunch, and therefore is expected to have the greatest deviation of the ideal gas when under high pressure or low temperature.
Hope this helped
