A cell phone leans against a wall. The bottom of the phone is 4 inches from the base of the wall, and the top of the phone makes an angle of 52 degrees with the wall. Find the length, x, of the phone so you can buy a new case. Round to the nearest hundreths place
The length of the phone is approximately 6.08 inches, so you can buy a case that fits this size.
To find the length, x, of the phone, we can use trigonometry. We know that the bottom of the phone is 4 inches from the base of the wall, so we can use the tangent function to find the length of the phone.
tangent(52 degrees) = opposite/adjacent
The opposite side is x (the length of the phone) and the adjacent side is 4 inches.
So,
tangent(52 degrees) = x/4
Multiplying both sides by 4, we get:
4 * tangent(52 degrees) = x
Using a calculator, we find that:
x ≈ 6.08 inches
Therefore, the length of the phone is approximately 6.08 inches, so you can buy a case that fits this size.
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Use the summation formulas to rewrite the expression without the summation notation.
∑ 8i+7/n^2
The expression without the summation notation for ∑ 8i+7/n²2 using the summation formulas is (4n + 3)/2n.
To rewrite the expression without the summation notation, we need to use the summation formulas. We can start by expanding the given summation:
∑ 8i+7/n²2 = 8(1)/n²2 + 8(2)/n²2 + 8(3)/n²2 + ... + 8(n)/n²2 + 7/n²2
Next, we can simplify each term by factoring out 8/n²2:
= (8/n²2)(1 + 2 + 3 + ... + n) + 7/n²2
Using the formula for the sum of the first n positive integers, we have:
= (8/n²2)(n(n+1)/2) + 7/n²2
= (4n² + 4n)/2n² + 7/n²2
= (4n + 3)/2n
Therefore, the expression is (4n + 3)/2n.
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What’s the answer I need help pls?
Answer:
(E). y = 2cos(3x)
Step-by-step explanation:
First, amplitude of cos(x) is 1 , then 2cos(x) has amplitude 2
Second, period of cos(x) is 2[tex]\pi[/tex] , then 3 × [tex]\frac{2\pi }{3}[/tex] = 2[tex]\pi[/tex]
So, the answer is y = 2cos(3x)
A car mechanic has a tin containing 5 litres of engine oil.
Each week they use 450 millilitres of this oil for their vehicles.
The car mechanic says
After 9 weeks I will have used over 80% of the oil in this tin.
Are they correct?
Show how you decide.
The car mechanic is correct in saying that they will have used over 80% of the oil in the tin after 9 weeks.
To determine if the car mechanic is correct, we first need to calculate how much oil they will use in 9 weeks.
450 millilitres of oil are used each week, so after 9 weeks, they will have used:
450 x 9 = 4050 millilitres
Next, we need to convert this to litres, since the oil tin is measured in litres.
There are 1000 millilitres in 1 litre, so:
4050 ÷ 1000 = 4.05 litres
Therefore, after 9 weeks, the car mechanic will have used 4.05 litres of oil.
Now we need to determine if this is over 80% of the total oil in the tin.
The tin contains 5 litres of oil, so we need to find 80% of 5:
5 x 0.8 = 4
So if the car mechanic has used more than 4 litres of oil in 9 weeks, they have used over 80% of the oil in the tin.
We know from earlier that they will have used 4.05 litres, which is slightly over 80%. Therefore, the car mechanic is correct in saying that they will have used over 80% of the oil in the tin after 9 weeks.
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PLS HELP!!
Mandy's Candies is most famous for their homemade fudge and homemade toffee. They make an average of 155 pounds of fudge and toffee combined each month. They sell a pound of fudge for $8.40 and a pound of toffee for $7.28. Mandy's averages $1,212.40 each month in fudge and toffee sales. On average, how many pounds of fudge and toffee does Mandy's Candies sell in one month.
Answer:
75 pounds of fudge & 80 pounds of toffee per month.
Step-by-step explanation:
Let qty of fudge be x pounds & qty of toffee be y pounds per month
They make an average of 155 pounds of fudge and toffee combined each month
x+y=155 (1)
They sell a pound of fudge for $8.40 and a pound of toffee for $7.28. Mandy's averages $1,212.40 each month in fudge and toffee sales.
So the cost of monthly fudge&toffee is 8.40*x+7.28*y=1,212.40
8.40x+7.28y=1212.40 ;(2)
multiply eq (1) by 8.40 & then subtract 2 from 1
8.40x+8.40y=155*8.40
8.40x+8.40y=1,302 (1')
8.40x+7.28y=1212.40 ;(2)
-----------------------
(8.40-7.28)y=1,302-1,212.40
1.12y=89.60
y=89.60/1.12=80 pounds of toffee
In order to solve for x, take the value for y and substitute it back into either one of the original equations.
x+80=155
x=155-80=75 pounds
So they make 75 pounds of fudge & 80 pounds of toffee per month.
Resolver la siguiente in ecuación |2x-3|< 3+x-x^2
Answer:
Step-by-step explanation:
To solve the equation, we'll need to consider two cases:
Case 1: 2x - 3 is positive or zero
If 2x - 3 is positive or zero, then |2x - 3| = 2x - 3, and the inequality becomes:
2x - 3 < 3 + x - x^2
Rearranging and simplifying:
x^2 - x - 6 < 0
Factoring:
(x - 3)(x + 2) < 0
The solutions to this inequality are:
-2 < x < 3
However, we still need to check that 2x - 3 is indeed positive or zero for this range of x. We can see that this is true for x in the range (-2, 3), so this is a valid solution.
Case 2: 2x - 3 is negative
If 2x - 3 is negative, then |2x - 3| = -(2x - 3), and the inequality becomes:
-(2x - 3) < 3 + x - x^2
Rearranging and simplifying:
x^2 - 3x - 6 < 0
Factoring:
(x - 3)(x + 2) > 0
The solutions to this inequality are:
x < -2 or x > 3
However, we still need to check that 2x - 3 is indeed negative for this range of x. We can see that this is true for x < -2, so this is a valid solution.
Putting these two cases together, we get the solution:
x < -2 or -2 < x < 3
I hope this helps! Let me know if you have any questions.
For how many different integers $k$ are there rational solutions to the quadratic equation
[tex]\[x^2 + kx + 4k = 0?\][/tex]
For k = 0 and k = 16, there are rational solutions to the quadratic equation [tex]x^{2} + kx + 4k = 0[/tex]
We are given a quadratic equation [tex]x^{2} + kx + 4k = 0[/tex]
An algebraic equation in x with a degree of 2 is known as a quadratic equation. It is written in the format [tex]a[/tex][tex]x^{2}[/tex] [tex]+ bx + c[/tex] = 0. To find out whether there exists two solutions, one solution, or no solution for a quadratic equation, we use the discriminant of the quadratic equation.
We will find the solutions to this quadratic equation with the help of discriminant formula
As we know from the equation that b = k, a = 1, and c = 4k.
[tex]b^2 - 4ac = 0[/tex]
[tex]k^2 - 4(4k) = 0[/tex]
[tex]k^2 - 16k = 0[/tex]
k (k-16) = 0
k = 0 or k - 16 = 0
k = 0 or k = 16
So, for k = 0 or k = 16 the equation [tex]x^{2} + kx + 4k = 0[/tex] has only one solution.
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The graph of a linear function y=mx + 2 goes through the point (4,0). Which of the following must be true?
A
m is negative.
B
m = 0
C
m is positive
D
Cannot be determined.
The slope of the line is negative, the correct answer is (A) m is negative.
Which of the given statement must be true?The formula for equation of line is expressed as;
y = mx + b
Where m is slope and b is y-intercept.
Given that; that the graph of a linear function y = mx + 2 is a straight line with slope m and y-intercept (0,2).
Also, the line passes through the point (4,0), we can use this point to find the value of the slope m.
0 = m(4) + 2
Solve for m
0 = 4m + 2
4m = -2
m = -2/4
m = -1/2
Hence, the slope m is negative.
Option A is the correct answer.
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The probability that Max will have to stop for a passing train on his route to work is 0. 5. The probability that there will be construction on Max's route to work ,begin emphasis,and,end emphasis, that he will have to stop for a train is 0. 4. What is the probability that there was construction if Max had to stop for a passing train on his route to work?
The problem is asking for the probability of construction given that Max had to stop for a passing train on his route to work. This can be solved using Bayes' theorem, which states that the probability of A given B is equal to the probability of B given A multiplied by the probability of A, divided by the probability of B.
In this case, let A be the event that there is construction on Max's route, and let B be the event that Max has to stop for a passing train. We are looking for the probability of A given B.
Using Bayes' theorem, we have:
P(A|B) = P(B|A) * P(A) / P(B)
We know that P(B) = 0.5, the probability that Max has to stop for a passing train. We also know that P(B|A) = 0.4, the probability that there is construction and Max has to stop for a passing train.
To find P(A), the probability of construction on Max's route, we need to use the complement of the event A, which is the probability that there is no construction:
P(not A) = 1 - P(A) = 1 - 0.4 = 0.6
Finally, we can plug in the values and solve for P(A|B):
P(A|B) = 0.4 * 0.4 / 0.5 = 0.32
Therefore, the probability that there was construction if Max had to stop for a passing train on his route to work is 0.32 or 32%.
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Reese is installing an in-ground rectangular pool in her backyard. her pool will be 30 feet long, 14 feet wide, and have an average depth of 8 feet. she is installing two pipes to bring water to fill the pool; these pipes will also be used to drain the pool at the end of each season. one pipe can fill and drain the pool at a rate that is 1 more than 2 times faster than the other pipe. if both pipes are open and working properly, it will take 3.5 hours to fill the pool.
The faster pipe can fill and drain the pool at a rate of 640.34 cubic feet per hour.
Reese is installing a rectangular pool in her backyard that is 30 feet long, 14 feet wide, and has an average depth of 8 feet. To fill and drain the pool, she is using two pipes. Let's call the slower pipe's rate of filling and draining the pool "r" (in units of volume per hour). Then, according to the problem, the faster pipe's rate is 2r+1 (since it is "1 more than 2 times faster" than the slower pipe).
If both pipes are open and working properly, we know it will take 3.5 hours to fill the pool. That means the total volume of the pool is:
V = length x width x depth
V = 30 ft x 14 ft x 8 ft
V = 3,360 cubic feet
We also know that when both pipes are open, they can fill the pool in 3.5 hours. That means the combined rate of filling the pool is:
V / t = (r + 2r+1)
3360 / 3.5 = 3r+1
960 = 3r+1
959 = 3r
r = 319.67 cubic feet per hour
So the slower pipe can fill and drain the pool at a rate of 319.67 cubic feet per hour. To find the rate of the faster pipe, we just need to substitute this value into our equation for the faster pipe's rate:
2r+1 = 2(319.67) + 1
2r+1 = 640.34
Therefore, the faster pipe can fill and drain the pool at a rate of 640.34 cubic feet per hour.
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Anne's Road Paving Company mixed 16 1/4 tons of cement. They used 6 3/4 tons of the cement to pave a street downtown. How much cement did they have left?
Answer is 9.5 tons of cement
Anne's Road Paving Company initially mixed 16 1/4 tons of cement. They used 6 3/4 tons for paving a street downtown. To find the remaining amount of cement, subtract the used amount from the initial amount:
16 1/4 - 6 3/4 = 15 1/4 - 5 3/4 = 9 1/2 tons.
So, they had 9 1/2 tons of cement left.
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Please i cant find the answer to this
Answer:
9
Step-by-step explanation:
First, let's move the variables to one side and the numbers to the other side:
[tex]\frac{2}{3}b+5=20-b\\[/tex]
subtract 5 from both sides:
[tex]\frac{2}{3}b=15-b\\[/tex]
add b to both sides:
[tex]\\1\frac{2}{3}b=15\\[/tex]
divide both sides by [tex]1\frac{2}{3}[/tex]:
[tex]b=9[/tex]
Hope this helps :)
Si se tiene un recipiente en forma de prisma triangular como el de la figura B, lleno de un líquido que se vierte en otro recipiente cilindro como el de la figura A Después de esa acción, ¿Qué volumen le falta al cilindro para estar completamente lleno?
The number of cones that can be filled with the ice cream from the container is 10.
Let's start with the container. We are given that it is a right circular cylinder with a diameter of 12 cm and a height of 15 cm. To find the volume of this cylinder, we use the formula:
Volume of cylinder = πr²h
where r is the radius of the cylinder (which is half of the diameter), and h is the height. Substituting the given values, we get:
Volume of cylinder = π(6 cm)²(15 cm) = 540π cubic cm
So the container has a volume of 540π cubic cm.
Now, let's move on to the cones. We are given that the cones have a height of 12 cm and a diameter of 6 cm. The cones have a hemispherical shape on the top, so we can consider them as a combination of a cone and a hemisphere. The formula for the volume of a cone is:
Volume of cone = (1/3)πr²h
where r is the radius of the base of the cone, and h is the height. Substituting the given values, we get:
Volume of cone = (1/3)π(3 cm)²(12 cm) = 36π cubic cm
The formula for the volume of a hemisphere is:
Volume of hemisphere = (2/3)πr³
where r is the radius of the hemisphere. Substituting the given values (the radius is half the diameter of the cone, which is 3 cm), we get:
Volume of hemisphere = (2/3)π(3 cm)³ = 18π cubic cm
So the total volume of each cone is:
Volume of cone + hemisphere = 36π + 18π = 54π cubic cm
To find out how many cones can be filled with the ice cream from the container, we divide the volume of the container by the volume of each cone:
Number of cones = Volume of container / Volume of each cone Number of cones
=> (540π cubic cm) / (54π cubic cm) Number of cones = 10
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Complete Question:
A container shaped like a right circular cylinder having diameter 12 cm and height 15 cm is full of ice cream. The ice cream is to be filled into cones of height 12 cm and diameter 6 cm, having a hemispherical shape on the top. Find the number of such cones which can be filled with ice cream.
Which is the simplest formula for working out probability
The simplest formula for working out probability is the following:
Probability (P) = Number of favorable outcomes (F) / Total number of possible outcomes (T)
In this formula, the probability of an event occurring is calculated by dividing the number of favorable outcomes by the total number of possible outcomes. Probability is a measure of the likelihood or chance of an event occurring. It is represented as a value between 0 and 1, where 0 indicates an impossible event and 1 indicates a certain event.
To calculate the probability, you need to determine the number of favorable outcomes, which are the desired outcomes or the outcomes you are interested in. Then, you divide that by the total number of possible outcomes, which is the number of equally likely outcomes in the given situation.
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11. The function f(t) = 40 sin (π/45 t) +48 models the height in feet of one car od a Ferris wheel called the Colossus, where t is the time in seconds. Each of the functions below models the motion of a different Ferris wheel. Which Ferris wheel has the same diameter as The Colossus?
a. g(t) = 40 cos (π/45 t) +50
b. h(t) = 39 cos (π/60 t) + 49
c. j(t) = 39 sin (π/45 t) + 48
d. k(t) = 39 sin (π/45 t) + 49
Ferris wheel has the same diameter as The Colossus is g(t) = 40 cos (π/45 t) +50. So, correct option is A.
To determine which of the given functions represents a Ferris wheel with the same diameter as The Colossus, we need to use the fact that the diameter of a Ferris wheel is equal to the amplitude of the sinusoidal function that models its height.
The amplitude of the function f(t) = 40 sin (π/45 t) +48 is 40, so the diameter of The Colossus is 40 feet. We need to find the function that also has an amplitude of 40.
Looking at the given answer choices, we see that function g(t) has an amplitude of 40 cos (π/45 t) +50, which is equal to 40. This means that the Ferris wheel represented by function g(t) has a diameter of 40 feet, the same as The Colossus.
Functions h(t), j(t), and k(t) all have amplitudes that are less than 40, so they represent Ferris wheels with smaller diameters than The Colossus.
Therefore, the answer is A.
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What is the solution of |x – 6| ≥ 1? 5 < x < 7 x ≤ –7 or x ≥ –5 x ≤ 5 or x ≥ 7 –7 < x < –5
Answer:
(c) x ≤ 5 or x ≥ 7
Step-by-step explanation:
You want the solution to |x -6| ≥ 1.
UnfoldThe absolute value relation represents two relations, one for the domain x < 6, and one for the domain x ≥ 6.
x < 6In this domain, the inequality becomes ...
-1 ≥ x -6
5 ≥ x . . . . . . add 6
x ≤ 5 . . . . . . . put x on the left
x ≥ 6In this domain, the inequality is ...
x -6 ≥ 1
x ≥ 7
The disjoint solution sets are x ≤ 5 or x ≥ 7.
__
Additional comment
For |x -a| ≤ b, we can "unfold" this to the compound inequality ...
-b ≤ (x -a) ≤ b
copying the inequality symbol to the left side, and writing the opposite of the constant there.
We can do the same thing with the inequality ...
|x -a| ≥ b
but it doesn't really make sense as a compound inequality.
Instead, we have to write it as ...
-b ≥ (x -a) or (x -a) ≥ b
in recognition of the fact that the solution spaces are disjoint.
Luke has scored a goal in 15 of his 26 soccer games this season and has a hit in 12 of his 16 baseball games this season. Based on the results in his season so far, Luke wants to figure out the probability that he will score a goal in his next soccer game and get a hit in his next baseball game. Enter the probability as a fraction in reduced form
The probability of Luke scoring a goal in his next soccer game and getting a hit in his next baseball game is 45/104 in reduced form.
The probability of Luke scoring a goal in his next soccer game is the ratio of the number of games he scored a goal to the total number of soccer games he played so far. Thus, the probability of scoring a goal in his next game is 15/26.Similarly, the probability of Luke getting a hit in his next baseball game is the ratio of the number of games he had a hit to the total number of baseball games he played so far.
Thus, the probability of getting a hit in his next game is 12/16.Since the events are independent, we can use the product rule to find the probability of both events happening together. Thus, the probability of scoring a goal in his next soccer game and getting a hit in his next baseball game is (15/26) x (12/16) = 45/104 in reduced form.
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Jessica records the number of winners at the dunk-a-teacher booth at the town fair as shown in the table. if there are 750 contestants on monday, how many should jessica expect to dunk a teacher? enter your answer in the box.
If there are 750 contestants on Monday, Jessica should expect around 75 of them to dunk a teacher.
Based on the table provided, we can see that the percentage of winners at the dunk-a-teacher booth varies from day to day.
On Monday, 10% of contestants were able to dunk a teacher.
Therefore, if there are 750 contestants on Monday, Jessica should expect around 75 of them to dunk a teacher.
This is calculated by multiplying 750 by 0.10, which gives us 75. It's important to note that this is just an estimation, as the actual number of winners may be slightly higher or lower than 75.
However, this gives Jessica a rough idea of what to expect at the booth on Monday.
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Mrs. mueller writes an inequality on the board. the table shows the responses of four students for possible values of x.
x>6
student
jacob
kendra
luke
maya
response
6
8
10
12
which student has a correct response to mrs. mueller's inequality?
o jacob
o kendra
o luke
o maya
The inequality given by Mrs. Mueller is x>6, which means that x is greater than 6. To check which student has given the correct response, we need to check if their values of x satisfy the given inequality.
Looking at the table, we see that all four students have given values of x that are greater than 6. However, we need to choose the student who has given the correct response to the inequality.
Jacob has given the response 8, which satisfies the inequality x>6. Kendra has given the response 10, which also satisfies the inequality. Luke has given the response 12, which is also greater than 6 and satisfies the inequality. Maya has given the response 10, which is the same as Kendra's response and also satisfies the inequality.
Therefore, we can say that all four students have given correct responses to Mrs. Mueller's inequality.
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Question #6
Samantha is fishing at the pier, holding her rod with two hands. At the same time she also
has her gun equipped, so she is able to defend herself when robbers approach her. What is
Samantha doing wrong?
Your answer is 150 characters short!
Enter your answer here.
Samantha is doing two things wrong: she is breaking the law and it is unsafe to handle a firearm while fishing.
Samantha is breaking the law by possessing a firearm while fishing at the pier. Most fishing piers are considered public places and carrying a firearm in public places is usually prohibited unless the person has a valid permit or is a law enforcement officer. It could cause panic among other people around her. It is important to follow local laws and regulations regarding firearms and to prioritize safety when in public spaces.
Additionally, it is unsafe and irresponsible to handle a firearm while fishing as it can cause accidents or injuries to oneself or others. She should not hold her fishing rod with both hands if she needs to be prepared to use her gun for self-defense. It would be difficult to access and use the gun effectively while holding the rod with both hands.
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The image shows three sets of stuffed bears. Each set represents a term of the sequence (1, 4, 7,. . . ). An arrangement of stuffed toy bears in groups of 1, 4, and 7
What is the next term in the sequence?
Describe the domain of the sequence. Describe the range of the sequence
The next term in the sequence of the series which have groups of 1, 4, and 7 is 10.
The fundamental concepts in mathematics are series and sequence. A series is the total of all components, but a sequence is an ordered group of items in which repeats of any kind are permitted. One of the typical examples of a series or a sequence is a mathematical progression.
We have the series as 1, 4, 7, ....
First term = a = 1
Common difference = d = 3
Using the formula for the Term is
T = a + (n-1)d
T = 1 + (n-1)3
= 1 + 3n - 3
T = 3n - 2
To find the next term in the series we need to find the 4th term so
T₄ = 3(4) - 2
= 12 - 2
T₄ = 10.
The domain of the sequence T = 3n - 2 is all Real numbers n ∈ Real numbers.
The range is given as
R ∈ (-∞, ∞).
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Answer:
1, 4, and 7 is 10
Step-by-step explanation:
The pattern sequence follows the add 3 rule so, the next term in the sequence will be 10.
The index of the terms of represents the domain of a function, which is { 1, 2, 3, . . .}.
The range includes the terms of the sequence {1, 4, 7, . . .}.
The president of the student council wants to survey the student population about parking. She decides to use a
random number table to take a random sample of 100 of the 1,020 students at the school. What is the smallest number
of digits that should be used to label the population?
The smallest number of digits that should be used to label the population is 4, since there are 1,020 students in the school.
To determine the smallest number of digits needed to label the population, we will follow these steps:
1. Determine the total number of students in the population.
2. Identify the number of digits needed to represent the largest student number.
3. Apply this number of digits to all student labels.
Let's apply these steps to your question:
1. The total number of students is 1,020.
2. The largest student number is 1,020, which requires 4 digits (since it has four numbers: 1, 0, 2, and 0).
3. To label the entire student population consistently, use 4 digits for all student labels.
So, the smallest number of digits that should be used to label the population is 4.
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The Huns migrated to the West in groups. There were three sections of the migration: the front, the middle, and the back. There were 3 groups of 5 people leading in the front and the same amount of groups and people at the back of the migration. In the middle of the pack, we have 9 groups of 9 people each. Write an expression and solve for the total number of Huns that migrated to the West. Use exponents in your expression.
The total number of Huns that migrated to the West is 111.
How to calculate the total number of Huns?To find the total number of Huns that migrated to the West, we can use the expression:
Total number of Huns = Number of groups x Number of people per group
For the front and back sections, there were 3 groups of 5 people each, so the total number of Huns in each section is:
3 x 5 = 15
For the middle section, there were 9 groups of 9 people each, so the total number of Huns in the middle section is:
9 x 9 = 81
To find the total number of Huns that migrated to the West, we add up the number of Huns in each section:
15 + 81 + 15 = 111
Therefore, the total number of Huns that migrated to the West is 111.
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Use even and odd functions to evaluate the following integral. ſ(cosa + 3x4) dx -T
The integral of ſ(cosa + 3x^4) dx simplifies to ∫cos(x) dx, which can be evaluated as sin(x) + C, where C is the constant of integration.To evaluate the integral of ſ(cosa + 3x^4) dx using even and odd functions, we can decompose the integrand into even and odd parts.
Let's first identify the even and odd parts of the integrand. The function cos(x) is an even function because it is symmetric with respect to the y-axis, i.e., cos(-x) = cos(x). On the other hand, the function 3x^4 is an odd function because it is symmetric with respect to the origin, i.e., (-x)^4 = x^4.
We can rewrite the integrand as a sum of even and odd functions:
cos(x) + 3x^4 = (1/2) * (cos(x) + cos(-x)) + (1/2) * (3x^4 - 3(-x)^4)
Now, we can use the properties of even and odd functions to simplify the integral. The integral of an even function over a symmetric interval is equal to twice the integral of the function over half of the interval. Similarly, the integral of an odd function over a symmetric interval is equal to zero.
So, the integral of (1/2) * (cos(x) + cos(-x)) dx is equal to (1/2) * 2 * ∫cos(x) dx, since cos(x) is an even function.
And the integral of (1/2) * (3x^4 - 3(-x)^4) dx is equal to (1/2) * 0, since 3x^4 - 3(-x)^4 is an odd function and the interval of integration is symmetric.
Therefore, the integral of ſ(cosa + 3x^4) dx simplifies to ∫cos(x) dx, which can be evaluated as sin(x) + C, where C is the constant of integration.
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Qn in attachment . ..
The variance of first n even natural numbers is n²-1/12. So, the correct option is (a) .
The first n even natural numbers can be represented as 2, 4, 6, ..., 2n. The mean or expected value of this sequence is given by:
mean = (2 + 4 + 6 + ... + 2n) / n
= 2(1 + 2 + 3 + ... + n) / n
= 2n(n+1)/2n
= n+1
The variance of a sequence is the average of the squared differences from the mean, so we need to calculate:
Var = [(2- (n+1))² + (4- (n+1))² + (6- (n+1))² + ... + (2n- (n+1))²] / n
Simplifying the expression inside the brackets and using the formula for the sum of the first n integers, we get:
Var = [4(1² + 2² + 3² + ... + n²) - 4(n+1)(1 + 2 + 3 + ... + n) + n(n+1)²] / n
Substituting the formula for the sum of the first n squares and the sum of the first n integers, we get:
Var = [4n(n+1)(2n+1)/6 - 4(n+1)n(n+1)/2 + n(n+1)²] / n
Simplifying and factoring out (n+1), we get:
Var = (n+1)(n² - 1) / 3
Thus, the correct option is (a) n²-1/12.
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Find the value of a2+bc√−d, when
a = –3, b = 2, c = 100, and d = –2
To find the value of a² + bc√(-d) when a = -3, b = 2, c = 100, and d = -2, follow these steps:
Step 1: Substitute the values into the expression.
a² + bc√(-d) = (-3)² + (2)(100)√(-(-2))
Step 2: Simplify the expression.
(-3)² + (2)(100)√(2) = 9 + 200√2
So, the value of a² + bc√(-d) when
a = -3,
b = 2,
c = 100,
d = -2 is 9 + 200√2.
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Zachary brought $38. 25 to the state fair. He bought a burger, a souvenir, and a pass. The burger was 1 6 as much as the souvenir, and the souvenir cost 3 4 the cost of the pass. Zachary had $4. 50 left over after buying these items
It is not possible for Zachary to buy a burger, a souvenir, and a pass with the given prices and have $4.50 left over.
What was the total cost of the burger, souvenir, and pass that Zachary bought at the state fair, if he had $4.50 left over and the burger was 1/6 as much as the souvenir, while the souvenir cost 3/4 the cost of the pass?Let's represent the cost of the souvenir as x.
Then, according to the problem:
The cost of the burger is 1/6 of the cost of the souvenir, which is (1/6)x.
The cost of the pass is 4/3 times the cost of the souvenir, which is (4/3)x.
The total cost of the burger, souvenir, and pass is equal to the amount Zachary brought to the state fair, which is $38.25.
Zachary had $4.50 left over after buying these items, so the cost of the burger, souvenir, and pass must be $33.75.
Putting all this information together, we can write an equation:
(1/6)x + x + (4/3)x = 33.75
Simplifying the left side of the equation:
(7/6)x = 33.75
Multiplying both sides by 6/7:
x = 30
Therefore, the cost of the souvenir is $30, the cost of the burger is (1/6) * 30 = $5, and the cost of the pass is (4/3) * 30 = $40.
To check that these values are correct, we can add them up:
30 + 5 + 40 = 75
And we can subtract the total cost from the amount Zachary brought:
38.25 - 75 = -36.75
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There are four spaces each so you can put either parentasis or brakets
In the given function the domain is [-1, ∞]
Range is [-3, ∞]
The interval when function is positive [0, ∞]
The domain of a function is the set of values that we are allowed to plug into our function.
This set is the x values in a function such as f(x).
The range of a function is the set of values that the function assumes
In the given function the domain is [-1, ∞]
Range is [-3, ∞]
The interval when function is positive [0, ∞]
The interval when function is negative [-∞, -1]
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Please asap!!! will give 100 brainlest!!! (there's more than one answer)
select all the correct measures of center and variation for the following data set.
10, 20, 31, 17, 18, 5, 22, 25, 14, 43
a. first quartile = 12
b. iqr = 11
c. median = 19
d. third quartile = 25
e. mad = 7
First quartile is 14, IQR is 14, median is 19, third quartile is 28 and MAD is 7.
a. First quartile = 12 and d. Third quartile = 25 are not necessarily correct measures of quartiles for this dataset. To calculate the quartiles, we need to first order the data set and then find the value(s) that divide it into four equal parts. In this case, the sorted dataset is:
5, 10, 14, 17, 18, 20, 22, 25, 31, 43
The first quartile is the median of the lower half of the data: (5, 10, 14, 17, 18) and is 14.
b. IQR = 11 is not correct. The IQR (Interquartile Range) is the difference between the third quartile and the first quartile, which is 28-14=14 for this dataset.
c. Median = 19 is a correct measure of center.
d. The third quartile is the median of the upper half of the data: (22, 25, 31, 43) and is 28.
e. MAD = 7 is a correct measure of variation.
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A bag of sweets contains only gobstoppers and sherbert lemons.
There are 3 gobstoppers for every 4 sherbert lemons.
There are 56 sweets in the bag. How many gobstoppers are there?
