Answer:
x=3, Adding and dividing. (Im not too sure how to answer that question, Are there some options that you learned in class?)
Step-by-step explanation:
4x-5=7
+5 +5
4x=12
/4 /4
x=3
help me find the fraction please
Answer: 9/64
Step-by-step explanation:
First, we find the probability of blue in one spin.
One spin: 3/8
Next, we also know that the second spin will also have a probability of 3/8.
To combine these probabilities in both spins, we multiply. This will combine the two independent events. It can be similar to Permutation.
Probability of both spins: 3/8 x 3/8
=9/64
9/64 is the combined probability of both spins.
Consider the following. sin u = 3/5 π/2 (a) Determine the quadrant in which u/2 lies. O Quadrant 1 O Quadrant II O Quadrant III O Quadrant IV (b) Find the exact values of sin(u/2), cos(u/2), and tan(u/2 sin(u/2) cos(u/2) = tan(u/2) =
(a) The quadrant in which u/2 lies is either Quadrant I or Quadrant II.
(b) The exact values of sin(u/2), cos(u/2), and tan(u/2) are:
sin(u/2) = √10/5
cos(u/2) = 3√10/10
tan(u/2) = 2/3
(a) To determine the quadrant in which u/2 lies, we need to look at the value of sin u. Since sin u is positive (3/5 is positive and π/2 is in Quadrant I), we know that u is in either Quadrant I or Quadrant II.
To find u/2, we divide u by 2, which means u/2 will be in either Quadrant I or Quadrant II as well. Therefore, the answer is either Quadrant I or Quadrant II.
(b) We can use the half-angle formulas to find the values of sin(u/2), cos(u/2), and tan(u/2):
sin(u/2) = ±√[(1 - cos u)/2]
cos(u/2) = ±√[(1 + cos u)/2]
tan(u/2) = sin(u/2)/cos(u/2)
Since sin u = 3/5, we can find cos u using the identity sin^2 u + cos^2 u = 1:
cos u = ±√[(1 - sin^2 u)] = ±√[(1 - 9/25)] = ±4/5
Since u/2 is in either Quadrant I or Quadrant II, we know that sin(u/2) and cos(u/2) are positive. Therefore, we can choose the positive square roots for sin(u/2) and cos(u/2):
sin(u/2) = √[(1 - cos u)/2] = √[(1 - 4/5)/2] = √[1/10] = √10/10 = √10/5
cos(u/2) = √[(1 + cos u)/2] = √[(1 + 4/5)/2] = √[9/10] = 3/√10 = 3√10/10
Finally, we can use these values to find tan(u/2):
tan(u/2) = sin(u/2)/cos(u/2) = (√10/5)/(3√10/10) = 2/3
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I need this problem solved.
The relation has been plotted on the graph where the first quadrant has (1, 2) and (2, 4), while the second quadrant contains (-1, 3) and (-2, 4).
What is a graph?In mathematics, a graph is a visual representation or diagram that shows facts or values in an ordered way.
The relationships between two or more items are frequently represented by the points on a graph.
You can compare various data sets using bar graphs.
In a line graph, the data is represented by tiny dots, and the line that connects them indicates what happens to the data.
So, we have the coordinates:
(-1, 3); (-2, 4); (1, 2); (2, 4)
Now, plot it on the graph as follows:
(Refer to the graph attached below.)
(-1, 3) and (-2, 4) are in the 2nd quadrant, and (1, 2) and (2, 4) are in the 1st quadrant.
Therefore, the relation has been plotted on the graph where the first quadrant has (1, 2) and (2, 4), while the second quadrant contains (-1, 3) and (-2, 4).
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Correct question:
Express the relation (-1, 3); (-2, 4); (1, 2); (2, 4) on the graph.
Carla, the baker, worked for 5 hours to make cookies..
She ended with 380 cookies altogether. Write an
equation to express how many cookies Carla made
each hour.
Answer:
5x=380
x = 76
Carla made 76 cookies each hours
Step-by-step explanation:
Just make an equation, so the total number of cookies is 380 and she works for 5 hours, so it is just 380/5.
Select the correct answer.
consider this equation.
cos(ф) = [tex]\frac{8}{9}[/tex]
if ф is an angle in quadrant iv, what is the value of tan(ф)?
The value of tan(ф) when cos(ф) = 8/9 in quadrant IV is - √17/8
To solve for the value of tan(ф), we need to use the trigonometric identity: tan(ф) = sin(ф)/cos(ф).
Since ф is in quadrant IV, we know that the cosine value is positive (due to cosine being positive in the adjacent side of quadrant IV) and the sine value is negative (due to sine being negative in the opposite side of quadrant IV).
We are given the value of the cosine, which is cos(ф) = 8/9. To find the sine, we can use the Pythagorean identity: sin²(ф) + cos²(ф) = 1.
Plugging in the given value of the cosine, we get: sin²(ф) + (8/9)² = 1. Solving for sin(ф), we get sin(ф) = - √(1 - (64/81)) = - √(17/81) = - √17/9.
Now that we have the values of sin(ф) and cos(ф), we can substitute them into the tan(ф) equation: tan(ф) = sin(ф)/cos(ф) = (- √17/9)/(8/9) = - √17/8.
Therefore, the value of tan(ф) when cos(ф) = 8/9 in quadrant IV is - √17/8.
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helpppp pleaseee!!!!
Answer:
Step-by-step explanation:
If c(t) = 53.2te^{- 0.26} measures the concentration, in ng/ml of a drug in a person's system thours after the drug is administered. a) What is the peak concentration of the drug? b) When does the drug reach peak concentration?
(a) To find the peak concentration of the drug, we need to find the maximum value of c(t). Since c(t) is an exponential function, its maximum value occurs at its maximum point, which is where its derivative is equal to zero. We can find this point by taking the derivative of c(t) and setting it equal to zero:c'(t) = 53.2e^{-0.26} - 13.832te^{-0.26} = 0Solving for t, we get t = 3.870 hours. Therefore, the peak concentration of the drug is c(3.870) = 109.2 ng/ml.(b) To find when the drug reaches peak concentration, we have already found that it occurs at t = 3.870 hours. Therefore, the drug reaches peak concentration 3.870 hours after it is administered.
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The peak concentration of the drug is approximately 42.83 ng/ml, and it occurs around 3.85 hours after the drug is administered.
To find the peak concentration of the drug and when it reaches that peak, we'll need to consider the given function c(t) = 53.2te^(-0.26t), where t is the time in hours.
a) To find the peak concentration, we need to determine the maximum value of c(t). We can do this by taking the first derivative of c(t) with respect to t and setting it equal to 0.
c'(t) = 53.2(-0.26)e^(-0.26t) + 53.2e^(-0.26t) = 0
Now, solve for t:
t ≈ 3.85 hours
b) Plug the value of t back into the c(t) function to find the peak concentration:
c(3.85) = 53.2(3.85)e^(-0.26(3.85)) ≈ 42.83 ng/ml
So, the peak concentration of the drug is approximately 42.83 ng/ml, and it occurs around 3.85 hours after the drug is administered.
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Melanie is making a piece of jewelry that is in the shape of a right triangle. The two shorter sides of the piece of jewelry are 4 mm and 3 mm. Find the perimeter of the piece of jewelry.
Therefore , the solution of the given problem of triangle comes out to be the jewellery's circumference is 12 mm.
What precisely is a triangle?If a polygon contains at least one more segment, it is a hexagon. It is a simple rectangle in shape. Anything like this can only be distinguished from a standard triangle form by edges A and B. Even if the edges are perfectly collinear, Euclidean geometry only creates a portion of the cube. A triangle is made up of a quadrilateral and three angles.
Here,
The lengths of all three sides must be added up in order to determine the jewellery's perimeter.
=> c²= a² + b²
where a and b are the lengths of the other two sides, and c is the length of the hypotenuse.
=> A = 3mm, and B = 4mm.
Therefore, we can determine the length of the hypotenuse using the Pythagorean theorem:
=> c² = a²+ b²
=> c² = 3² + 4²
=> c² = 9 + 16
=> c² = 25
=> c = √25)
=> c = 5 mm
As a result, the hypotenuse is 5 mm long.
We total the lengths of all three sides to determine the jewellery's perimeter:
=> perimeter = 4mm, 3mm, and 5mm.
=> 12 mm is the diameter.
Therefore, the jewellery's circumference is 12 mm.
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The alverado's have a monthly income of $6,000.
3. how much more do they spend on taxes than on clothing?
pls help fast! my teacher is gonna get mad!
The Alverados spend $1,200 more on taxes than on clothing.
How we get the tax spend on clothing?To determine how much more the Alverados spend on taxes than on clothing, we need to know how much they spend on each.
If we assume that the Alverados spend 25% of their income on taxes, that would be:
0.25 x $6,000 = $1,500
If we assume that the Alverados spend 5% of their income on clothing, that would be:
0.05 x $6,000 = $300
To find how much more they spend on taxes than on clothing, we can subtract the amount spent on clothing from the amount spent on taxes:
$1,500 - $300 = $1,200
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The school swim team swam a combined distance of 346. 725 meters during swim practice. Using number names, how would you say 346. 725? (6. NBT. 3_a. ) *
The number name of 346. 725 is three hundred forty-six point seven two five.
A number name refers to the name that is used to describe the number in words. This is helpful in communicating it orally.
To convert the given number to word form, we do as follows:
1. We check the digits of the number before decimals
In this case, the number of digits in the question is 3
2. The highest place value is then checked.
It comes out to be hundreds
3. We name it accordingly and add a suffix to the face value
This is 3 and the name comes out to be Three hundred
4. We continue it till we encounter the decimal
We get the number as Three hundred forty-six
5. Then we mention the word decimal or point
The result is Three hundred forty-six point
6. The number after the decimal is written as it is
Hence, the name comes out to be Three hundred forty-six point seven two five.
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In A shown below radius AB is perpendicular to chord XY at point C If XY=30cm and AC=8m what is the measure of XC
pls help
Therefore, the measure of line segment XC is 3.75 cm.
What is perpendicular?In geometry, two lines or planes are said to be perpendicular if they intersect each other at a right angle (90 degrees). The term "perpendicular" is also commonly used to describe the relationship between a line and a surface, where the line is at a right angle to the surface at the point of intersection. In general, the concept of perpendicularity is fundamental to many mathematical and scientific fields, such as trigonometry, physics, and engineering. It is also a commonly used term in everyday language to describe objects or structures that intersect at right angles, such as the corners of a square or the legs of a chair.
Here,
In the given diagram, let O be the center of the circle and let XC = a.
Since AB is perpendicular to XY at C, we have AC = BC = 8 m (using Pythagoras theorem). Also, since AB is a radius of the circle, we have AB = r, where r is the radius of the circle.
By the power of a point theorem, we have:
AC × XC = BC × XY
Substituting the given values, we get:
8 m × a = 8 m × 30 cm
Simplifying and converting units, we get:
a = 3.75 cm
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A small printing company launched an online ordering system to expand its business. The equation с. 400-(1. 03)" represents the number of customers c it has in terms of the number of months m since it launched the ordering system. 1. By what factor does the number of customers grow in one year? Write your answer as an expression and a numerical value.
2. If y is the time in years write an equation for the numbers of costumers c as a function of the numbers of years y after the introduction of the ordering system.
1. The growth factor for the number of customers over a year is approximately 1.4266.
2. the growth factor in customers over a decade period is approximately 5.927.
Factors that affect how many consumers there are in a year are
c(12)/c(0) = (400 x (1.03)¹²) / (400 x (1.03)⁰)
= (1.03)¹²
= 1.4266....
Therefore, the growth factor for the number of customers over a year is approximately 1.4266.
2. To write an equation for the number of customers c as a function of the number of years y, we can substitute m = 12y into the original equation
[tex]c(y) = 400 x (1.03)^{12y}[/tex]
one decade = 10 years
= 120 months
We must calculate the value of the equation at m=120 and divide it by the equation's value at m=0.
c(120) / c(0) = [400 x (1.03)¹²⁰] / [400 x (1.03)⁰]
= (1.03)¹²⁰
= 5.927...
Therefore, the growth factor in customers over a ten-year period is approximately 5.927.
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Given Question is incomplete, complete question is given below:
A small printing company launched an online ordering system to expand its business. The equation [tex]c=400(1. 03)^m[/tex] represents the number of customers c it has in terms of the number of months m since it launched the ordering system.
1. By what factor does the number of customers grow in one year? Write your answer as an expression and a numerical value
2. If y is time in years, write an equation for the number of customers c as a function of the number of years y after the introduction of the ordering system. If this model continues to apply for a decade, by what factor will the number of customers grow in one decade?
What is an equation of the line that passes through the points ( 8 , 6 ) and ( − 3 , 6 )
The equation of line passing through the points (8, 6) and (-3, 6) is y = 6. Since the y-coordinate is the same for both points, the line is a horizontal line at y = 6.
To find the equation of the line passing through the points (8, 6) and (-3, 6), we can use the slope-intercept form of a linear equation:
y = mx + b
where m is the slope of the line and b is the y-intercept.
First, we need to find the slope, which is given by
m = (y2 - y1) / (x2 - x1)
where (x1, y1) = (8, 6) and (x2, y2) = (-3, 6)
m = (6 - 6) / (-3 - 8)
m = 0 / -11
m = 0
Since the slope is zero, the line is a horizontal line. We can see from the given points that the line passes through y = 6. Therefore, the equation of the line is
y = 6
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Consider the following function f(x)=x^2+5
part a write a function in vertex form that shifts f(x) right 3 units
part b write a function in vertex form that shifts f(x) left 10 unites
Part a: f(x) = (x-3)^2 + 5
Part b: f(x) = (x+10)^2 + 5
Part a: To shift the function f(x) = x^2 + 5 right 3 units, we need to subtract 3 from the x-coordinate of the vertex. The vertex form of a quadratic function is given by f(x) = a(x-h)^2 + k, where (h,k) is the vertex. Thus, the function in vertex form that shifts f(x) right 3 units is:
f(x) = (x-3)^2 + 5
Part b: To shift the function f(x) = x^2 + 5 left 10 units, we need to add 10 to the x-coordinate of the vertex. Using the same vertex form as before, the function in vertex form that shifts f(x) left 10 units is:
f(x) = (x+10)^2 + 5
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Please answer now! Please show the Example
Mr. Bilo received 8 P50-bills, 5 P100-bills, and 5 P20-bills.
How many P50, P100, and P20 bills did Mr. Pilo get?The number of P50, P100, and P20 bills Mr. Pilo got is calculated as follows;
Amount from P50-bills: 2/5 x P1,000 = P400
Amount from P100-bills: 1/2 x P1,000 = P500
The total amount he received from the P50-bills and P100-bills = P400 + P500
The total amount he received from the P50-bills and P100-bills = P900. The amount left to be changed into P20-bills = P1,000 - P900
The amount left to be changed into P20-bills = P100.
The number of bills will then be:
Number of P50-bills: P400 ÷ P50 = 8
Number of P100-bills: P500 ÷ P100 = 5
Number of P20-bills: P100 ÷ P20 = 5
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Complete question:
Mr Bilo has a P1,000-bill and asked someone to exchange in to 2/5 P50-bill and 1/2 P100-bill and the rest into 20-bill. How many P50,P100 and P20 bills did he get.
How can I figure this out?
Answer:
Blue = 4
Red = 24
Green = 4
All = 32
Step-by-step explanation:
Area of a triangle: 1/2 * base * height, so for both blue and green:
1/2 * 2 * 4
1 * 4
4
Area of an object with 4 sides: length * width, so for red:
6 * 4
24
Area of everything: blue + red + green, so for all:
4 + 4 + 24
8 + 24
32
I NEED HELP ON THIS ASAP!! IT'S DUE TODAY!!
The transformations performed on f(x) to create g(x) is a reflection over the y-axis and a translation 4 units up.
An equation for g(x) in terms of f(x) is g(x) = f(-x) + 4.
What is a reflection over the y-axis?In Mathematics and Geometry, a reflection over or across the y-axis or line x = 0 is represented and modeled by this transformation rule (x, y) → (-x, y).
By applying a reflection over the y-axis to coordinate A of the image ABCD, we have the following:
(x, y) → (-x, y)
Coordinate = (-1, 1/10) → Coordinate A' = (-(-1), 1/10) = (1, 1/10).
Furthermore, the transformation rule for the translation of a point by k units up is given by;
(x, y + k) → (x', y')
(1, 1/10 + k) → E(1, 4 1/10)
1/10 + k = 4 1/10
k = 4 1/10 - 1/10
k = 4.
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Helppp translation and reflection
The images of points B and C are B'(x, y) = (- 2, 6) and C'(x, y) = (- 1, 7), respectively.
How to compute the image of a point by translation
In this problem we find must determine the image of two points by translation, whose formula is introduced below:
T(x, y) = P'(x, y) - P(x, y)
Where:
P(x, y) - Original point.P'(x, y) - Resulting point.T(x, y) - Translation vector.First, determine the translation vector:
T(x, y) = (1, 4) - (0, 0)
T(x, y) = (1, 4)
Second, determine the images of points B and C:
B'(x, y) = (- 3, 2) + (1, 4)
B'(x, y) = (- 2, 6)
C'(x, y) = (- 2, 3) + (1, 4)
C'(x, y) = (- 1, 7)
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A water sample shows 0.063 grams of some trace element for every cubic centimeter of water. Tariq uses a container in the shape of a right cylinder with a radius of 7.6 cm and a height of 17 cm to collect a second sample, filling the container all the way. Assuming the sample contains the same proportion of the trace element, approximately how much trace element has Tariq collected? Round your answer to the nearest tenth.
Therefore, Tariq has collected 201.09 g trace element.
We are given that Tariq uses a container that is in the shape of a cylinder. The radius of the cylinder is 7.6 cm and the height of the cylinder is 17 cm.
Firstly, we will find the volume of the cylinder by applying the formula
The volume of the cylinder = [tex]\pi r^{2} h[/tex]
As we know the values of r and h, we will substitute these values in the given formula
The volume of cylinder = 3.14 * 17.6 * 7.6 *7.6
The volume of cylinder = 55.264 * 57.76
Volume = 3192.04 [tex]cm^{3}[/tex]
We are given that the water sample shows 0.063 grams of some trace element for every cubic centimeter of water. Therefore, we will multiply the volume of the cylinder by 0.063 to calculate the number of trace elements collected.
= 3192.04 * 0.063
= 201.09
Therefore, a total of 201.09 g of trace elements was collected by Tariq.
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you are planning a trip to australia. your hotel will cost you a$110 per night for seven nights. you expect to spend another a$3,400 for meals, tours, souvenirs, and so forth. how much will this trip cost you in u.s. dollars if $1
The total cost of the trip in U.S. dollars as per given rates and conversion is equal to approximately USD 3,232.58.
Total cost of the trip in U.S. dollars,
Convert the Australian dollars to U.S. dollars.
Using the exchange rate of 0.7752 USD per 1 AUD.
The cost of the hotel is,
7 nights × A$110/night = A$770
To convert this to U.S. dollars, multiply by the exchange rate,
A$770 × 0.7752 USD/AUD
= USD 596.904
Expected cost of meals, tours, souvenirs, etc. is,
A$3,400
Convert this to U.S. dollars, we again multiply by the exchange rate,
A$3,400 × 0.7752 USD/AUD
= USD 2,635.68
Total cost of the trip in U.S. dollars is the sum of these two amounts is,
USD 596.904 + USD 2,635.68 = USD 3,232.584
Rounding to two decimal places = approximately USD 3,232.58.
Therefore, the cost of the trip in the U.S. dollars is equal to approximately USD 3,232.58.
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The above question is incomplete, the complete question is:
You are planning a trip to Australia. your hotel will cost you a$110 per night for seven nights. you expect to spend another a$3,400 for meals, tours, souvenirs, and so forth. How much will this trip cost her in U.S. dollars if the USD equivalent is .7752?
You can find the area of a trapezoid by decomposing it into a rectangle and one or more triangles you can find the area of a kite by decomposing it into triangles
The statement on finding the areas of a trapezoid and a kite are True.
How to find area by decomposing shapes ?To determine the area of a trapezoid, it can be broken down into separate geometrical shapes. One possible breakdown would include a rectangle with two adjacent right triangles or an isosceles triangle with one right triangle configuration. By calculating each smaller compartment's size and summing them together, one can obtain the total area for the trapezoid.
Similarly, in order to find the surface area of a kite shape, drawing a diagonal creates two adjoining triangles that are easily computed individually then summed.
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Options for this question :
True
False
(5, -8) reflected across the y axis and then reflected across the x axis
Sorry for bad handwriting
if i was helpful Brainliests my answer ^_^
Help with problem in photo
Check the picture below.
Answer:
250 degrees
Step-by-step explanation:
For any circle tangent to line FG at point F, as shown in the diagram, and for any point E on the circle, the relationship between the measure of angle GFE and the arclength of FE is given by [tex]m~\text{arc}~FE=2m \angle GFE[/tex].
So, the measure of the arc FE is 110 degrees. Since a circle is fully 360degrees, the missing arc represented by the question mark is given by the following equation:
? + 110 = 360
Solving for the ?
? = 250 degrees
Select the correct answer from each drop-down menu. hemoglobin level age less than 25 years 25–35 years above 35 years total less than 9 21 32 76 129 between 9 and 11 49 52 46 147 above 11 69 44 40 153 total 139 128 162 429 based on the data in the two-way table, the probability of being 25-35 years and having a hemoglobin level above 11 is . the probability of having a hemoglobin level above 11 is . being 25-35 years and having a hemoglobin level above 11 dependent on each other.
The probability of being 25-35 years and having a hemoglobin level above 11 is 0.102. The probability of having a hemoglobin level above 11 is 0.356. Being 25-35 years and having a hemoglobin level above 11 are dependent on each other.
From the two-way table, the total number of individuals who have a hemoglobin level above 11 is 153+44+40=237. The probability of having a hemoglobin level above 11 is the total number of individuals with hemoglobin level above 11 divided by the total number of individuals, which is 237/429=0.356.
The number of individuals who are between 25-35 years and have a hemoglobin level above 11 is 44. The probability of being 25-35 years and having a hemoglobin level above 11 is the number of individuals who are between 25-35 years and have a hemoglobin level above 11 divided by the total number of individuals, which is 44/429=0.102.
Being 25-35 years and having a hemoglobin level above 11 are dependent on each other because the probability of having a hemoglobin level above 11 changes based on the age group.
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consider h(x)= 11x² - 6x calculate H (x) Fx 6.Xr1 유 11 6 3 (22.-6) 3 6 In(3) 11 A) 2 +1 (221 - 6)31 B) - (11r? - br)3*** In(3) 2 (3***") - 6 In(3) (221 - 63#* - (1142 – 63)3 (3***")" 2 +1 4 (221 - 63 - (1122 – 6x)3 In(3) i 1 D)
The answer is B) - (11x² - 6x)ln(3) + 2ln(3) - 6ln(x) + C, where C is the constant of integration.
To solve this problem, we are given a function h(x) and asked to find its antiderivative or indefinite integral, which is denoted by H(x) and is defined as the function whose derivative is h(x). We are also given a specific value of H(x) at x = 6 and asked to use it to find the constant of integration, denoted by C.
The given function is h(x) = 22x - 3x² - 6/x, and we want to find H(x), which is the antiderivative of h(x). Using the power rule of integration, we can integrate each term of h(x) separately:
∫ (22x - 3x² - 6/x) dx = ∫ 22x dx - ∫ 3x² dx - ∫ 6/x dx= 11x² - x³ - 6ln|x| + Cwhere C is the constant of integration. Note that we need to include an absolute value sign around x in the natural logarithm term because the function is not defined for x = 0.
Next, we are given that H(6) = 31, which means that when x = 6, the value of H(x) is 31. Substituting x = 6 and H(x) = 31 into the above equation, we get:
31 = 11(6)² - (6)³ - 6ln|6| + CSimplifying, we get:
31 = 132 - 216 - 6ln(6) + CC = 221/3 - 6ln(6)Therefore, the antiderivative of h(x) is:
H(x) = 11x² - x³ - 6ln|x| + 221/3 - 6ln(6)We can simplify the expression by using the identity ln|a/b| = ln|a| - ln|b|:
H(x) = 11x² - x³ - 6ln(3) - 6ln(x) + 2ln(3) + Cwhere C is the constant of integration. Thus, the final answer is:
B) - (11x² - 6x)ln(3) + 2ln(3) - 6ln(x) + C, where C is the constant of integration.To learn more about integration, here
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A rectangular prism shaped fish tank is 2014 inches wide, 1012 inches long, and 1812 inches tall.
What is the volume of the fish tank in cubic inches?
Responses
49 1/4
212 5/8
3600 1/16
3933 9/16
The volume of the fish tank is approximately 3,693,142,608 cubic inches
How to solveTo find the volume of the rectangular prism-shaped fish tank, we need to multiply its width, length, and height.
Given the dimensions are 2014 inches wide, 1012 inches long, and 1812 inches tall, the calculation is as follows:
Volume = Width × Length × Height
Volume = 2014 in × 1012 in × 1812 in
Upon calculating the product, we get:
Volume ≈ 3,693,142,608 cubic inches
The volume of the fish tank is approximately 3,693,142,608 cubic inches
N.B: None of the answer choices has the correct answer.
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The radius of the large circle is 3 inches and AB is its diameter. Also, AC is tangent to the large circle at point A. If arc CD = 160 and arc CE = 100, find the area of triangle ABC.
The area of triangle ABC is 13.95 square inches.
We can start by finding the length of AB, which is equal to the diameter of the circle. Since the radius is 3 inches, the diameter is 2 times the radius, or 6 inches.
Next, we can use the fact that AC is tangent to the circle to conclude that angle CAB is a right angle. Therefore, triangle ABC is a right triangle.
Let's use the information about the arcs CD and CE to find the measure of angle BAC. The measure of an inscribed angle is half the measure of the arc that it intercepts, so angle CAD is 80 degrees and angle CAE is 50 degrees. Since angles CAD and CAE are opposite each other and AC is a tangent, we have angle BAC is 180 - 80 - 50 = 50 degrees.
Now we know that triangle ABC is a right triangle with a 90-degree angle at B and a 50-degree angle at A. To find the area of the triangle, we need to know the length of BC.
Using trigonometry, we can find that BC = AB * sin(50) ≈ 4.65 inches.
Therefore, the area of triangle ABC is (1/2) * AB * BC = (1/2) * 6 * 4.65 = 13.95 square inches. Rounded to the nearest hundredth, the area of triangle ABC is 13.95 square inches.
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Andre is playing greatest product. he says the greatest product it’s possible to make in the game is 987x65 do you agree or disagree with andre
Andre's claim that the greatest product possible in the game is 987x65 is incorrect.
Why is Andre's claim incorrect?
While 987x65 is a large product, it is not the greatest possible product in the game. In fact, a larger product can be obtained by multiplying the two largest numbers available in the game. Without knowing the specific rules of the game, it is impossible to determine the exact greatest product, but it is certain that 987x65 is not it.
To elaborate, the game likely has certain constraints or rules that limit the numbers that can be multiplied. It may be possible to combine multiple numbers to create a larger product, or to find a different pair of numbers that yield a larger product. Therefore, without knowing the specifics of the game's rules, it is impossible to determine the greatest possible product.
The actual greatest product possible in the game will depend on the specific rules and constraints that are in place. It may be possible to combine multiple numbers to create an even larger product, or to find a different pair of numbers that yield a larger product. Without knowing the specifics of the game's rules, it is impossible to determine the greatest possible product.
In mathematics, the concept of maximum or greatest products is important and is studied in various areas such as algebra, number theory, and calculus. In real-world applications, maximum products play a critical role in determining profits, yields, and returns on investments in economics and finance. In engineering, the concept of maximum product is used in optimization problems, where the goal is to maximize or minimize a certain function or output.
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Prove the following 2 trig identities. Show all steps!
Answer:
a) multiply by cos²/cos², move sin/cos inside parentheses, simplify
d) multiply by (cot+cos); use cot=cos·csc, csc²-1=cot² in the denominator
Step-by-step explanation:
You want to prove the identities ...
sin²(x)(cot(x) +1)² = cos²(x)(tan(x) +1)²cos(x)cot(x)/(cot(x)-cos(x) = (cot(x)+cos(x)/(cos(x)cot(x))IdentitiesUsually, we want to prove a trig identity by providing the steps that transforms one side of the identity to the expression on the other side. Here, each of these identity expressions can be simplified, so it is actually much easier to simplify both expressions to one that is common.
a) sin²(x)(cot(x) +1)² = cos²(x)(tan(x) +1)²We are going to use s=sin(x), c=cos(x), (s/c) = tan(x), and (c/s) = cot(x) to reduce the amount of writing we have to do.
[tex]s^2\left(\dfrac{c}{s}+1\right)^2=c^2\left(\dfrac{s}{c}+1\right)^2\qquad\text{given}\\\\\\\dfrac{s^2(c+s)^2}{s^2}=\dfrac{c^2(s+c)^2}{c^2}\qquad\text{use common denominator}\\\\\\(c+s)^2=(c+s)^2\qquad\text{cancel common factors; Q.E.D.}[/tex]
d) cos(x)cot(x)/(cot(x)-cos(x) = (cot(x)+cos(x)/(cos(x)cot(x))Using the same substitutions as above, we have ...
[tex]\dfrac{c(c/s)}{(c/s)-c}=\dfrac{(c/s)+c}{c(c/s)}\qquad\text{given}\\\\\\\dfrac{c^2}{c(1-s)}=\dfrac{c(1+s)}{c^2}\qquad\text{multiply num, den by s}\\\\\\\dfrac{c(1+s)}{(1-s)(1+s)}=\dfrac{c(1+s)}{c^2}\\\\\\\dfrac{c(1+s)}{1-s^2}=\dfrac{c(1+s)}{c^2}\\\\\\\dfrac{c(1+s)}{c^2}=\dfrac{c(1+s)}{c^2}\qquad\text{Q.E.D.}[/tex]
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Additional comment
The key transformation in (d) is multiplying numerator and denominator by (1+sin(x)). You can probably prove the identity just by doing that on the left side, then rearranging the result to make it look like the right side.
For (a), the key transformation seems to be multiplying by cos²(x)/cos²(x) and rearranging.
Sometimes it seems to take several tries before the simplest method of getting from here to there becomes apparent. The transformations described in the top "Answer" section may be simpler than those shown in the "Step-by-step" section.
What is the probability of drawing a diamond or a spade card from a standard deck of cards and rolling a 2 on a six-sided die?
10. 7%
25%
8. 3%
04. 2%
The probability of drawing a diamond or a spade card from a standard deck of cards and rolling a 2 on a six-sided die is 8.33%
To calculate the probability of drawing a diamond or a spade card from a standard deck of cards, we need to find the total number of diamond and spade cards in the deck. There are 13 cards in each suit, so there are 26 diamond and spade cards in total. The deck has 52 cards in total, so the probability of drawing a diamond or a spade card is:
P(diamond or spade) = 26/52 = 1/2 = 50%
To calculate the probability of rolling a 2 on a six-sided die, we need to find the total number of possible outcomes, which is 6 (since there are 6 sides on the die), and the number of favorable outcomes, which is 1 (since there is only one face with a 2 on it). Therefore, the probability of rolling a 2 on a six-sided die is:
P(rolling a 2) = 1/6 = 16.67%
To find the probability of both events happening together (drawing a diamond or a spade card and rolling a 2 on a six-sided die), we multiply the probabilities of each event:
P(diamond or spade AND rolling a 2) = P(diamond or spade) * P(rolling a 2)
= 50% * 16.67%
= 8.33%
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