The force exerted on the pumpkin by the wall is 600 N
From the question given above, the following data were obtained:
Mass (m) = 2 Kg
Initial velocity (u) = 15 m/s
Final velocity (v) = 0 m/s
Time (t) = 0.05 s
Force (F) =?The force exerted on the pumpkin by the wall can be obtained as follow:
[tex]f = \frac{m(v + u)}{t} \\ \\ f = \frac{2(0 + 15)}{0.05} \\ \\ f = \frac{2 \times 15}{0.05} \\ \\ f = \frac{30}{0.05} \\ \\ [/tex]
F = 600 NTherefore, the force exerted on the pumpkin by the wall is 600 N
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One factor that could account for a drop in the water table is:
A. more wind.
B. less porous soil.
C. more clouds.
D. less rain and snow.
Answer:
D. Less rain and snow.
Explanation:
A factor that can be a account for a drop in the water table is, less rain and snow. to topography, water tables is influenced by lot of factors, including the geology, weather, ground cover.
According to Washington, is a strong central government important?
Answer:
According to Washington, the most important factor in sustaining the independence of the United States was protecting the unity of the states. ... Members of the Democratic-Republican Party believed that a strong federal government would not respect the rights of the states and the people.
Explanation:
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Suppose that an object of mass 11.4 g is hung from a vertical spring that is stretched 10 cm as a result. What is the spring constant of this spring, in N/m
i am giving brainly to however answers first
A student made the table to showing how different objects transform electrical energy. Which statement best explains why the table is incorrect?
Item Transformed Energy
Radio Electrical → Sound
Lamp Electrical → Light
Doorbell Electrical → Motion
Iron Electrical → Heat
The doorbell transforms electrical energy into sound.
The iron transforms electrical energy into light.
The lamp transforms electrical energy into sound.
The radio transforms electrical energy into heat.
Answer:
The doorbell transforms electrical energy into sound.
Explanation:
The doorbell MAY turn electrical energy into motion of a striker which then impacts a resonator creating sound. However all door bells do not have solenoids. Some are electronic playing recordings when activated.
All doorbells do produce sound, though.
when 15 newtons of force is applied to the 0.50 kg book, the friction keeps the book from sliding down the wall
The minimum force to keep the book from sliding is 15 N.
The minimum coefficient of friction to keep the book from sliding is 0.33.
The given parameters;
applied force, F = 15 Nmass of the book, m = 0.5 kgThe normal force on the book is calculated as;
[tex]F_n = mg\\\\F_n = 0.5 \times 9.8\\\\F_n = 4.9 \ N[/tex]
The minimum force to keep the book from sliding is calculated as;
[tex]F - F_s = 0\\\\F_s = F\\\\F_s = 15 \ N[/tex]
The minimum coefficient of friction to keep the book from sliding is calculated as;
[tex]\mu_s F = F_n\\\\\mu_s = \frac{F_n}{F} \\\\\mu_s = \frac{4.9}{15} \\\\\mu_s = 0.33[/tex]
"Your question is not complete, it seems to be missing the following information";
When a force of 15 newtons is applied to the 0.50 kg book, the friction keeps the book from sliding down the wall. What is the minimum force and minimum coefficient of friction to keep the book from sliding?
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answers please
5 pointss
Answer:
1.a shadow is caused by an object blocking light so that it does not reach a surface. The area in shadow appears black because there is no light falling on it----it appears dark. In fact most shadows are not totally black because light usually bounces around the obstruction off other objects.
2.Shadow gives us the shape about the object and we can know the nature of that image by it's shadow. ... As shadow is complete with the all features of objects like it's shape, size and everything; This helps to know whether the shape of the object. Hence, Shadow tells us about the shape of the object.
3.The bird or an airplane flying high in the sky do not cast their shadow on the ground because they are at very high altitude due to which the ground which acts as screen for the shadow is far away and in absence of the screen the shadow cannot be formed.
Explanation:
BY Roses_are_Rosie
Sarah and Tom are riding on a merry-go-round revolving at a constant rate. Sarah is sitting on the edge and Tom is half-way in from the edge. What is the relationship between their centripetal accelerations
The centripetal acceleration of Tom sitting half-way from the edge of the merry-go-round is double of the centripetal acceleration of Sarah sitting at the edge of the merry-go-round.
Let the constant rate of their motion, = v
Let the radius of the merry-go-round = R
The centripetal acceleration of Sarah sitting at the edge of the merry-go-round is calculated as;
[tex]a_c_1 = \frac{V^2}{R}[/tex]
The centripetal acceleration of Tom sitting half-way from the edge of the merry-go-round is calculated as;
[tex]a_c_2 = \frac{V^2}{\frac{1}{2} \times R } \\\\a_c_2 = \frac{2V^2}{R} \\\\a_c_2 = 2(\frac{V^2}{R} )\\\\a_c_2 = a_c_1[/tex]
Thus, the centripetal acceleration of Tom sitting half-way from the edge of the merry-go-round is double of the centripetal acceleration of Sarah sitting at the edge of the merry-go-round.
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An arrow is shot straight up in the air from the ground with an initial velocity of 54.0 m/s. If on striking the ground it
embeds itself 15.0 cm into the ground, what is the acceleration required to stop the arrow when it hits the ground?
hindi ko po alam yan sorry po
What power (in horsepower) is developed by a grinding machine whose wheel has a radius of 8.89 in and runs at 7.42 rev/s, when the tool to be sharpened is held against the wheel with a force of 47.3 lb
Answer:
P = W / t definition of power
P = F s / t = F v t / t = F v power expended
v = 2 pi R f f = frequency = rev / sec (S = 2 pi R n = 2 pi R f t)
and v = S / t
P = F 2 pi R f = 47.3 lb * 6.28 * .741 ft * 7.42 / sec = 1630 ft-lb/sec
(1630 ft-lb/sec) / (550 ft-lb/sec / HP) = 2.96 HP
3) A 60. kg person is in an elevator. The elevator starts from rest and then accelerates upwards at 2.0 m/s^2 for 4.0 seconds. Calculate the work done by the normal force on the person. *
Answer is 1.1 x 10^4 J
Answer:
WD = 11328 J → 1.1 × 10⁴ (to 2 sig figs)
Explanation:
WD = work done (J)
F = force (N), i.e. the normal force on the person
W = weight (N)
s = displacement (m)
m = mass (kg) = 60
a = acceleration (m/s²) = 2
g = gravity (m/s²) = 9.8
t = time (s) = 4
u = initial velocity (m/s) = 0
The formulas or equations that are relevant ate:
WD = F × s
F = m × a
W = m × g → note: this is simply a variation of the formula F = ma
s = ut + ¹/₂.at²
We want to find WD, so we need to know the force and the displacement (or distance);
Firstly, we want to find the normal force on the person in the elevator;
The downwards force the person produces on the elevator is the weight of the person, which is:
W = 60 × g
W = 60 × 9.8
W = 588
We are told the elevator is accelerating upward, so we can construct an equation to find F with the formula F = ma:
F - W = 60 × 2
F - 588 = 120
F = 708
Note: illustrations may be helpful to understand this, as has been shown in the picture
We also need displacement, which we use the formula s = ut + ¹/₂at²:
s = 0(4) + ¹/₂(2)(4)²
s = 16 m
Now we have F and s, we can calculate WD:
WD = 708 × 16
WD = 11328 J → This can be rounded to 1.1 × 10⁴ to 2 significant figures
A plane traveling 3.1 m/s east encounters wind traveling 4.7 m/s north. The wind current is 18 m wide. Determine the time to cross the wind current.
explain why oxygen-16 and 16/8o are not considered isotopes
Answer:
Each oxygen isotope has 8 protons but a different amount of neutrons. The mass of an isotope is represented by its isotope number. As a result, oxygen 16 has eight protons and eight neutrons, oxygen 17 has eight protons and nine neutrons, and oxygen 18 has eight protons and ten neutrons.
Explanation:
Hello, I want to ask. . anyone knows the answer.
Answer:
1 tablet
Explanation:
The closest rounding of 1.04 that is in the answers is 1.
Make a rule: If you know the width, length, and mass of a boat, how can you calculate how deep it will sink in water
Answer:
U would need to know the depth of the water
Explanation:
help this is urgent ;-;
how does spatial pattern of heights illustrate the relationship between temperature density and the rate of vertical pressure change
The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.
Generally, the relationship between temperature, density and rate of vertical pressure is given as;
[tex]\rho = \frac{PM}{RT}[/tex]
[tex]\frac{dP}{dz} = -\rho g\\\\[/tex]
where;
ρ is densityT is temperaturedP is rate of change of vertical pressureThus, from the formula above, we can conclude the following relationship between temperature, density and the rate of vertical pressure change in spatial pattern of heights.
The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.
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Explain one way the pattern of the moon would be affected if the moon took longer time to orbit the earth
Each day the Moon's appearance changes depending on where it is in its earth orbit. The pattern of day and night is followed only due to the rotation of the earth.
What is the rotation of the Earth?The phrases revolution and rotation describe the various movements of the earth. Rotation is the tendency of the planet on its axis.
The movement of the earth around the sun is a definite path or orbit known as revolution. The earth's axis, a fictional line, makes a 6612° angle with its orbital plane.
The rotation of the earth on its axis does not cause night and day. The occurrence of night and day is caused by the rotation of the earth.
The lunar cycle begins when the Sun, Moon, and Earth are aligned (the Moon is between the Earth and the Sun, and the hemisphere of the Moon faces away from the Earth.
As a result, if the moon took longer to orbit the Earth, the pattern would be disrupted.
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You wear lead to protect you from ____.
1. microwaves
2. gamma rays
3.x_rays
4. infrared
how long in seconds would it take a rock to fall 450 feet and what would be the final velocity of the rock in miles per hour when it hit the ground
Answer:
S = Vy t + 1/2 g t^2 = 1/2 g t^2 vertical speed with zero initial speed
t = (2 S / g)^1/2 with g = 32 ft/sec^2
t = (900 / 32)^1/2 = 5.30 sec time to reach ground
V = a t = 32 ft/s^2 * 5.30 s = 170 ft/sec
170 ft/sec / (88 ft/sec / 60 mph) = 116 mph since 88 ft/sec = 60 mph
Plane-polarized light is incident on a single polarizing disk with the direction of E0 parallel to the direction of the transmission axis. Through what angle should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of 1.22
Malus's law allows us to find the result for which is the angle of the polarizer for a reduction of the intensity is:
θ = 34.9º
Malus's law establishes a mathematical relationship for the light transmitted by a polarizer is:
I = I₀ cos² θ
where I and I₀ are the transmitted and incident intensities, respectively, θ is the angle between the two polarizers.
They indicate that the incident light is polarized, so we do not need the first polarized to create the polarized light, ask what the polarized angle should be for the intensity to be reduced by a factor.
[tex]\frac{I_o}{I } = 1.22 \\\frac{I}{Io} = 0.81967[/tex]
Let's use Malus's law
i / Io = cos² θ
cos θ = [tex]\sqrt{\frac{I}{I_o} }[/tex]
θ = cos⁻¹1 0.81967
θ = 34.9º
In conclusion, using Malus's law we can find the angle of the polarized for a reduction of the intensity is:
θ = 34.9º
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A 100-g block slides back and forth on a frictionless surface between two springs, as shown in Fig. 7.18. The left-hand spring has k = 110 N/m and its maximum compression is 21 cm.The right-hand spring has
k = 240 N/m. Find (a) the maximum compression of the right-hand spring and (b) the speed of the block as it moves between the springs.
(a) Energy is conserved at every point in the block's motion, so the potential energy P stored in the first spring at its maximum compression is the same as is stored in the second spring.
The total work performed on the block by the first spring is
W = -1/2 (110 N/m) (0.21 m²) = -2.4255 J
The work performed by the second spring is the same, so
W = -1/2 (240 N/m) x²
Solve for x :
x² = -2W/(240 N/m) = 0.0202125 m²
x ≈ 0.14 m = 14 cm
(b) By the work-energy theorem, the total work performed by either spring on the block as the spring is compressed is equal to the change in the block's kinetic energy. The restoring force of the spring is the only force involved. At maximum compression, the block has zero velocity, while its kinetic energy and hence speed is maximum just as it comes into contact with either spring.
W = 0 - K
W = -1/2 (0.10 kg) v²
v² = -2W/(0.10 kg) = 48.51 m²/s²
v ≈ 7.0 m/s
Please help
Which statement is true in this situation?
Answer:
b
Explanation:
because the of F frick is the same of the size of F app
A jet needs to reach a "lift-off' speed of 120 m/s before it can leave the ground. How quickly must
the jet accelerate if the run way has a length of 322 m?
The jet must accelerate in 5.37 s if it must reach the lift-off speed
From the question given above, the following data were:
Initial velocity (u) = 0 m/s
Final velocity (v) = 120 m/s
Distance (s) = 322 m
Time (t) =?The time needed for the jet to accerate can be obtained as follow:
[tex]s = \frac{(v + u)t}{2} \\ \\ 322 = \frac{(120 + 0)t}{2} \\ \\ 322 = \frac{120t}{2} \\ \\ cross \: multiply \\ \\ 120t = 322 \times 2 \\ \\ 120t = 644 \\ \\ divide \: both \: side \: by \: 120 \\ \\ t = \frac{644}{120} \\ \\ [/tex]
t = 5.37Thus, the jet must accelerate in 5.37 s in order to reach the lift-off speed
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As the jet leaves the ground, it accelerates at a rate of 22.4 ms-2.
We have the following information from the question;
Final velocity = 120 m/s
Initial velocity = 0 m/s
Distance covered = 322 m
Acceleration = ?
Using the equation;
v^2 = u^2 + 2as
v = final velocity
u = initial velocity
a = acceleration
s = distance
(120)^2 = 0^2 + (2 × a × 322)
14400 = 644a
a = 14400/644
a = 22.4 ms-2
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A ball is Thrown straight up with a speed of 30 M/S, and air resistance is negligible what is its velocity after 4.2s
Answer:
11.2 m/s
Explanation:
We need to first figure out how long it took to reach the ball's max height:
Vf = 0
Vi = 30 m/s
a = -9.81 m/s^2
t = ?
---------------
Vf = Vi + at
0 = 30 + (-9.81)t ---> -30 = -9.81t ---> 3.058 = t
t = 3.058 s
---------------
We can now solve the problem by subtracting the given time (4.2s) by the max height time (3.058s) and plugging that into a kinematic equation for Vf:
Vi = 0
a = 9.81 m/s^2
t = (4.2s - 3.058s) = 1.142 s
Vf = ?
---------------
Vf = Vi + at
Vf = 0 + (9.81)*(1.142) ---> Vf = 11.203
---------------
The velocity of the ball after 4.2s is 11.2 m/s
A 1500-kg car accelerates from 0 to 25 m/s in 7.0 s. What is the average power delivered by the engine (1 hp
A strechy material with a spring constant of 42 N/m is stretched 3.6 cm from its equilibrium length. What is the magnitude of the resulting spring force
The force acting on a stretchy material is the product of of the spring constant and the displacement by stretching of the material. Thus, resultant force of the material with a spring constant o 42 N/m with a displacement of 3.6 cm is 1.51 N downwards.
What is force?Force is an external agent acting on a body to change it form the state of rest or motion. There are various kinds of forces such as gravitational force, nuclear force, magnetic force, frictional force etc.
A stretching material such as a string will experience an elastic nature. The force F acting on the spring is directly proportional to the its displacement X. The proportionality constant is called spring constant.
Hence we can write it as ,
F = -kx
Here, the spring constant is given 42 N/m and displacement is 3.6 cm or 0.036 m. Now the force is calculated as follows:
Force = -0.036 m × 42 N/m
=- 1.51 N
The negative sign indicates the direction is downwards.
Thus, the force acting on the material is 1.51 N.
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A 25kg cannon ball is shot out of a 1600 kg cannon that is initially at rest . When fired the velocity of the cannon ball is 200m/s. What is the recoil velocity of the cannon?
The correct answer is the recoil velocity of the cannon is equal to 90m/s.
The recoil velocity of the cannon is equal to 3.125m/s.
What is law of conservation of linear momentum?According to this law, the sum of the momentum before and after the collision must be equal.
m₁ u₁ + m₂u₂ = m₁v₁ + m₂ v₂
where m₁ and m₂ is the mass of the collided bodies, u₁ and u₂ are initial speed while v₁ & v₂ is final speed.
Conservation of momentum is a characteristic held by an object where the total amount of momentum never changes.
Given the mass of the cannonball, m₁ = 25 Kg
The velocity of the cannonball, v₁ = 200 m/s
The mass of the cannon, m₂ = 1600 Kg
Assume that v₂ is the recoil velocity of the cannon.
From the law of conservation of momentum: P(initial) = P (final)
m₁ v₁ = m₂ v₂
25 × 200 = 1600 × v₂
v₂ = 3.125 m/s
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The gravitational force between two objects is represented by the variable F.
If the masses are both doubled and the distance is halved, what is the new gravitational force?
Explanation:
Fgravity = G*(mass1*mass2)/D²
G is the gravitational constant, which has the same value throughout our universe.
D is the distance between both objects.
now, we change these numbers
Fgravitynew = G*(2*mass1*2*mass2)/(1/2 * D)² =
= G*(4*mass1*mass2)/(D²/4) =
= 4* (G*(mass1*mass2)/D²) *4 =
= 16* (G*(mass1*mass2)/D²) = 16*Fgravity
so, the new gravitational force will be 16×F.
demonstrate how souni wave works
Answer:
Explanation:
Sound waves exist as variations of pressure in a medium such as air. They are created by the vibration of an object, which causes the air surrounding it to vibrate. The vibrating air then causes the human eardrum to vibrate, which the brain interprets as sound.
sjkdvsndjkvnisdvnuisbvibsdv.
Answer:
hello!
Explanation:
