A 17.11 gram sample of an organic compound containing only C, H, and O is analyzed by combustion analysis and 21.71 g CO2 and 5.926 g H2O are produced. In a separate experiment, the molar mass is found to be 104.1 g/mol. Determine the empirical formula and the molecular formula of the organic compound. Enter the elements in the order C, H, O empirical formula

Answers

Answer 1

Answer:  The empirical formula and the molecular formula of the organic compound is [tex]CHO[/tex] and [tex]C_4H_4O_4[/tex] respectively.

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

[tex]C_xH_yO_z+O_2\rightarrow CO_2+H_2O[/tex]

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of [tex]CO_2[/tex] = 21.71 g

Mass of [tex]H_2O[/tex]= 5.926 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 21.71 g of carbon dioxide, =[tex]\frac{12}{44}\times 21.71=5.921g[/tex] of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 5.926 g of water, =[tex]\frac{2}{18}\times 5.926=0.658g[/tex] of hydrogen will be contained.

Mass of oxygen in the compound = (17.11) - (5.921+0.658) = 10.53  g

Mass of C = 5.921 g

Mass of H = 0.658 g

Mass of O = 10.53 g

Step 1 : convert given masses into moles.

Moles of C =[tex] \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.921g}{12g/mole}=0.493moles[/tex]

Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.658g}{1g/mole}=0.658moles[/tex]

Mass of O=[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{10.53g}{16g/mole}=0.658moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =[tex]\frac{0.493}{0.493}=1[/tex]

For H =[tex]\frac{0.658}{0.493}=1[/tex]

For O=[tex]\frac{0.658}{0.493}=1[/tex]

The ratio of C : H: O =  1: 1: 1

Hence the empirical formula is [tex]CHO[/tex].

empirical mass of CHO = 12(1) + 1(1) + 1 (16) = 29

Molecular mass = 104.1 g/mol

[tex]n=\frac{\text {Molecular mass}}{\text {Equivalent mass}}=\frac{104.1}{29}=4[/tex]

Thus molecular formula = [tex]n\times {\text {Empirical formula}}=4\times CHO=C_4H_4O_4[/tex]


Related Questions

Which of the following reactions is balanced?
Question 13 options:

A)

Sn2+ + Fe3+ → Sn4+ + Fe2+

B)

Sn2+ + 2Fe3+ → Sn4+ + Fe2+

C)

Sn2+ + 2Fe3+ → Sn4+ + 2Fe2+

D)

2Sn2+ + Fe3+ → 2Sn4+ + Fe2+

Answers

The answer is A
Hope this helps.

The balanced chemical equation among the given reactions is:

Sn²⁺ + 2Fe³⁺  →  Sn⁴⁺ + 2Fe²⁺

Therefore, option (C) is correct.

What is the balanced chemical equation?

A chemical equation of a reaction can be defined as the representation of a reaction in terms of chemical symbols of the substances used in the given reaction. The number of atoms of substances on the balanced equation is equal on either side of the equation.

According to the law of conservation of mass, while balancing a chemical equation, the total mass (reactant side) should be equal to the total mass (product side) in a chemical equation.

In the given equation, the positive charge on reactant side should be equal to the positive charge on product side.

[tex]Sn^{2+ }+ 2Fe^{3+} \longrightarrow Sn^{4+} + 2Fe^{2+}[/tex]

The two electrons lost by the Sn²⁺ ions get converted into Sn⁴⁺ ions. These two electrons are accepted by two ions of Fe³⁺ and converted into Fe²⁺ ions.

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how atom split go boom boom? :)

Answers

Answer:

To split an atom a neutron, traveling at an accurate speed must be shot at the nucleus.

Explanation:

100 POINTS!!!!!!!
The following diagram shows the branching tree for four kingdoms and some of their shared derived characteristics.

A slanting line is shown. There are four lines drawn vertically on this line at equal intervals. There is a black circle between each pair of these vertical lines. Protists, Plants, Fungi, Animals are written on top of each vertical line in order from left to right. Common Cell is written on the left most end of the sloping line. The second black circle has Mostly Multicellular written on it. The first black circle has X written on it.

What shared characteristic can be written at point X? Use complete sentences to explain your answer.

Answers

Answer:

The answer could be "Autotrophs that photosynthesis".

Explanation:

At point X, the common characteristic can be written. The common character between protists and plants is autotrophs that photosynthesize which is the characteristic of plant-like protists. Plant-like protists are autotrophs, use carbon dioxide and water to produce glucose by the process of photosynthesis.

which of the following are the correct formulas for potassium oxide and calcium oxide respectively

Answers

Explanation:

potassium oxide is K2O

calcium oxide is CaO

calcium oxide is used to make glass

potassium oxide is used in fertilizer

Identify an alkene and carboxylic acid using primary observations

Answers

If the unknown substance decolorize bromine water, it is an alkene. If it does not, litmus paper is used to test it. If the paper turns red, then the substance may be a carboxylic acid, and the reaction with sodium carbonate serves as additional confirmation. It is not a carboxylic acid if it does not react with sodium carbonate. A substance is not an alkene or a carboxylic acid if it does not decolorize bromine water and is not acidic.

What is the flowchart for identification of an alkene and carboxylic acid?

The following flowchart can be used to recognize an alkene and a carboxylic acid:

1. Start with the hypothetical unknown substance.

2. Use bromine water to test the substance.

a. An alkene is a substance that discolors bromine water.

b. Move on to the following stage if the compound does not lighten bromine water.

3. Use universal indicator paper or litmus paper to test the chemical.

a. The substance might be a carboxylic acid if it is acidic and causes the paper to turn red.

b. Go to the following step if the chemical is not acidic.

4. Use sodium carbonate to evaluate the substance.

a. A substance is a carboxylic acid if it reacts with sodium carbonate to release carbon dioxide gas.

b. The chemical is not a compound if it does not react with sodium carbonate.

Therefore, if the unknown substance decolorize bromine water, it is an alkene. If it does not, litmus paper is used to test it. If the paper turns red, then the substance may be a carboxylic acid, and the reaction with sodium carbonate serves as additional confirmation.

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Your question is incomplete, most probably the complete question is:

TASK 2 - Pass 2B.P4 Identify an alkene and carboxylic acid using primary observations. To achieve 2B.P4, learners should follow guidance to identify an alkene and a carboxylic acid (for example, ethanoic acid) from primary observations. Learners will be expected to identify an alkene in the way described in 1B.4. For ethanoic acid this is by its pH and its reaction with sodium carbonate. The guidance given to the learners could be in the form of a flowchart.​

h20 (s) -> h20 (g)
endothermic or exothermic

Answers

Answer:

Endothermic.

Explanation:

Hello there!

In this case, it is necessary to keep in mind that exothermic processes are characterized by the release of energy and the endothermic processes by the absorption of heat. In such a way, every process from solid to liquid or gas is endothermic as they require energy to separate the molecules and therefore turn out in the phase change. On the other hand, every process from gas to liquid or solid is exothermic as heat is released to rejoin the molecules and produce the phase change.

Therefore, since solid water molecules tend to be well-arranged, it is necessary to add heat to the system to produce the phase change until gas; in such a way, this process is endothermic as energy must be absorbed by the ice.

Best regards!

If I have 150g of NaNO3, how many moles are there?
a) 1.76 mol NaNO3
b) 12750 mol NaNO3
c) 17.6 g NaNO3
d) 0.56 mol NaNO

Answers

Answer:

[tex]\boxed {\boxed {\sf A.\ 1.76 \ mol \ NaNO_3}}[/tex]

Explanation:

To covert from grams to moles, the molar mass is used. This is the mass of 1 mole of a substance. These are located on the Periodic Table. They are the equivalent to the atomic masses, but have different units: grams per mole.

We are given the compound: NaNO₃

Look up the values for each individual element (sodium, nitrogen, and oxygen)

Na:  22.989769 g/mol N: 14.007 g/mol O: 15.999 g/mol

Now find the molar mass of the entire compound. Notice that oxygen has a subscript of 3 in the formula, so there are 3 atoms of oxygen per molecule. We must multiply its molar mass by 3 before adding the others.

O₃: 15.999*3=47.997 g/mol NaNO₃: 22.989769+14.007+47.997=84.993769 g/mol

Use this value as a ratio.

[tex]\frac {84.993769 \ g \ NaNO_3}{1 \ mol \ NaNO_3}[/tex]

Multiply by the given number of grams: 150

[tex]150 \ g \ NaNO_3*\frac {84.993769 \ g \ NaNO_3}{1 \ mol \ NaNO_3}[/tex]

Flip the ratio so the grams of sodium nitrate cancel.

[tex]150 \ g \ NaNO_3*\frac {1 \ mol \ NaNO_3}{84.993769 \ g \ NaNO_3}[/tex]

[tex]150 *\frac {1 \ mol \ NaNO_3}{84.993769}[/tex]

[tex]\frac {150}{84.993769} \ \ mol \ NaNO_3[/tex]

[tex]1.7648352551 \ mol \ NaNO_3[/tex]

If we round to the nearest hundredth, the 4 in the thousandth place tells us to leave the 6.

[tex]1.76 \ mol \ NaNO_3[/tex]

150 grams of sodium nitrate is approximately 1.76 moles of sodium nitrate. Therefore, choice A is correct.

This is a freebie for anyone for one get the crown

Answers

Answer:

hhh

Explanation:

Can somebody please help me!!!

Answers

Answer:

force are called roll

Explanation:

force your answer give me five Points

Answer:

friction

Explanation:

The other terms honestly just don't make any sense in this context. Round objects experience less friction, since they have less of their surface touching the ground at a time. Imagine a bowling bowl: only a small part of the ball is ever touching the ground at one instant. Now imagine a waffle: almost all of the surface is touching the ground.

How many moles are in 30.68 grams of potassium nitrate? Molar mass of potassium nitrate is 101.11 g/mol.
A. 1.36 moles
B. 1.02 x 10^-22 moles
C. 3,102.05 moles
D. 0.303 moles

Answers

The answer should be B

the moisturizer you see on the mirror in your bathroom after a hot shower is called?​

Answers

Answer:

Soap that was thrown out

What is the volume of 3.00 × 10 20atoms in an aluminum block? The density of aluminum is 2.70 g/cm 3 .

Answers

Answer:

[tex]V=4.98x10^{-3}cm^3[/tex]

Explanation:

Hello there!

In this case, according to the given atoms of aluminum, it is possible for us to calculate the mass via the Avogadro's number and its atomic mass of 27.0 g/mol:

[tex]m_{Al}=3.00x10^{20}atoms Al*\frac{1molAl}{6.022x10^{23}atomsAl} *\frac{27.0gAl}{1mol}=0.0135gAl[/tex]

Noe, given the density of the Al, we can calculate the volume as shown below:

[tex]d=m/V\\\\V=m/d\\\\V=0.0135g/(2.70g/cm^3)\\\\V=4.98x10^{-3}cm^3[/tex]

Best regards!

What is the pH of a 0.00530 M solution of HCI?

Answers

Answer:

2.28

Explanation:

HCl(l) ===> H+ + cl-

HCl is a very strong acid. Almost all of it will decompose to the right. That means the concentration of H+ is 0.00530

pH = - log [H+]

pH = - log[0.00530]

pH = - - 2.2757

pH = 2.2757

Rounded this 2.28

What is the pressure, in mmHg, of a 4.00 g sample of O2 gas, which has a temperature of 37.0 °C, and a volume of 4400 mL?

Answers

Answer:

549.48 mmHg

Explanation:

We'll begin by calculating the number of mole of oxygen in 4 g. This can be obtained as follow:

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ = 4 g

Mole of O₂ =?

Mole = mass /molar mass

Mole of O₂ = 4/32

Mole of O₂ = 0.125 mole

Next, we shall convert 37.0 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T (°C) = 37.0 °C

T(K) = 37.0 °C + 273

T(K) = 310 K

Next, we shall convert 4400 mL to L.

1000 mL = 1 L

Therefore,

4400 mL = 4400 mL × 1 L / 1000 mL

4400 mL = 4.4 L

Next, we shall determine the pressure. This can be obtained as follow:

Number of mole (n) = 0.125 mole

Temperature (T) = 310 K

Volume (V) = 4.4 L

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =?

PV = nRT

P × 4.4 = 0.125 × 0.0821 × 310

Divide both side by 4.4

P = (0.125 × 0.0821 × 310) / 4.4

P = 0.723 atm

Finally, we shall convert 0.723 atm to mmHg.

1 atm = 760 mmHg

Therefore,

0.723 atm = 0.723 atm × 760 mmHg / 1 atm

0.723 atm = 549.48 mmHg

Thus, the pressure is 549.48 mmHg

can boron bond with lithium

Answers

Answer:

No, they are not able to bond.

Explanation:

Hello there!

In this case, regarding chemical bonds, it is necessary to remember that these come up when a metal is bonded with a nonmetal, or, when two nonmetals get bonded; however, even there exist a type of denominated metallic, it is not eligible for boron and lithium because they tend to stable as cations (positive) and therefore, equal charges are not eligible for bonding, thus, boron and lithium would not be able to bond.

Best regards!

The state of matter in which a material has definite shape and definite
volume is the

Answers

Answer:

It's a solid.

Explanation:

Solids never change their shape as opposed to gases and liquids. This is because their molecules are tightly packed together. Since all solids have a definite shape, it's volume will also be definite.

Hydrogen, deuterium, and singly ionized helium are all examples of one-electronatoms. The deuterium nucleus has the same charge as the hydrogen nucleus, and almost exactlytwice the mass. The helium nucleus has twice the charge of the hydrogen nucleus, and almostexactly four times the mass. Make a prediction of the ratios of the ground state energies of theseatoms, considering that current spectroscopy accuracy is extremely good (on the order of107).

Answers

Answer:

0.99986

Explanation:

attached below is the detailed solution to the given problem

Express the ratios of the ground state energies of these atoms

ground state energies ( Ed , Ehe )

= Ed / Ehe = -13.5963 / -13.59815

                 = 0.99986

What volume in milliliters of 0.100 M HCIO3 is required to neutralize
40.0 mL of 0.165 M KOH?

Answers

Answer:

66.0 mL HClO3

Explanation:

M1V1 = M2V2

M1 = 0.100 M HClO3

V1 = ?

M2 = 0.165 M KOH

V2 = 40.0 mL KOH

Solve for V1 --> V1 = M2V2/M1

V1 = (0.165 M)(40.0 mL) / (0.100 M) = 66.0 mL HClO3

Identify the following for an atom with 8 protons, 8 electrons, and 7 neutrons.
a. Atomic number:
b. Mass number:
c. Nuclear Notation:
d. Hyphen Notation:

please help

Answers

Answer:

i thinks its a. but iam not sure


A roller coaster is travelling without friction as
shown in the diagram. If the speed of the roller
coaster at A is 3.0 m/s, what is the speed at B?

Answers

Answer:

Thus, the speed at B = 13 m/s

Explanation:

From the attached image:

Using the conservation of energy;

Iinital M.E = Final M.E

where;

M.E = mechanical energy

[tex]\dfrac{1}{2} \times m \times v_A^2+ mgh_A = \dfrac{1}{2} \times m \times v_B^2+ mgh_B[/tex]

[tex]\dfrac{1}{2} \times m \times 3^2+m \times 9.8 \times 15 = \dfrac{1}{2} \times m \times v_B^2+ m\times 9.8 \times 7 \\ \\ \dfrac{1}{2} \times 3^2 + 9.8 \times 15 = \dfrac{1}{2} \times v^2 + 9.8 \times 7 \\ \\ \implies 151.5 = 0.5 v^2 + 68.6 \\ \\ 0.5v^2 = 151.5 - 68.6 \\ \\ 0.5 v^2 = 82.9 \\ \\ v^2 = \dfrac{82.9}{0.5} \\ \\ v^2 = 165.8 \\ \\ v = \sqrt{165.8} \\ \\ v = 12.9 \ m/s\\ \\ \mathbf{v \simeq 13 \ m/s}[/tex]

Why do gas molecules move at different speeds at a given temperature?

Answers

Answer:

Gas molecules move at different speed at a given temputure bc as temp increases they move faster

Explanation:

they move faster bc they gain kinetetic energy

Given [OH-] 6.98 times 10^-2 what is the ph and [H+]

Answers

Answer:

[H+]=1.43*10^-13

pH=12.84

Explanation:

Take the -log of the [OH-] to get the pOH:

pOH= -log(6.98*10^-2)=1.15

pH=14-pOH

pH=14-1.15

pH=12.843

[H+]=10^(-pH)

[H+]=10^(-12.843)

[H+]-1.43*10^-13

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What is the net ionic equation for the reaction between Na2SO4 and CaCl2?
A. 2Na+(aq) + 2Cl-(aq) 2NaCl(aq)
B. Na2SO4(aq) + CaCl2(aq) CaSO4(s) + 2NaCl(aq)
C. SO42-(aq) + Ca2+(aq) CaSO4(s)
D. 2Na+(aq) + SO42-(aq) + Ca2+(aq) + 2Cl-(aq) CaSO4(s) + 2Na+ + 2Cl-(aq)

Answers

The net ionic equation for the reaction between Na₂SO₄ and CaCl₂ is:

SO₄²¯(aq) + Ca²⁺(aq) —> CaSO₄(s)

(Option C)

Dissociation equation

In solution, Na₂SO₄ and CaCl₂ will dissociate as follow

Na₂SO₄(aq) —> 2Na⁺(aq) + SO₄²¯(aq)

CaCl₂(aq) —> Ca²⁺(aq) + 2Cl¯(aq)

How to write the net ionic equation

Na₂SO₄(aq) + CaCl₂(aq) —>

2Na⁺(aq) + SO₄²¯(aq) + Ca²⁺(aq) + 2Cl¯(aq) —> CaSO₄(s) + 2Na⁺(aq) + 2Cl¯(aq)

Cancel out the spectator ions (i.e Na⁺ + Cl¯) to obtain the net ionic equation

SO₄²¯(aq) + Ca²⁺(aq) —> CaSO₄(s)

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A scuba tank has a volume of 10.3 L and a pressure of 19,300 kPa. If the gas is transferred to a 50.0 L container, what is it's new pressure?

Answers

Hi there!

Here's a screenshot of the problem being solved.

When is energy released during a chemical reaction?
A. when chemical bonds break and form
B. when chemical bonds form
C. when chemical bonds break

“Don’t click links if answers have one!”

Answers

C. When chemical break and form

HI(aq)+NaOH(aq)→
what the final balanced chemical equation with the phases included

Answers

Answer:

[tex]HI(aq)+NaOH(aq)\rightarrow NaI(aq)+H_2O(l)[/tex]

Explanation:

Hello there!

In this case, for this neutralization reaction, it is possible to realize that one the neutralization products is water (pH=7) and the other one is the salt coming up from the cation of the NaOH and the anion of the HI:

[tex]HI(aq)+NaOH(aq)\rightarrow NaI+H_2O[/tex]

Moreover, since the solubility of NaI is large in water, we infer it remains aqueous whereas the water is maintained as liquid:

[tex]HI(aq)+NaOH(aq)\rightarrow NaI(aq)+H_2O(l)[/tex]

Which is also balanced as the number of atoms of all the elements is the same at both sides.

Best regards!

What is standard pressure in atmospheres?

a.10
b.1
c.5
d.2

Answers

The answer is d. 2 hope this helps

How many moles of methane gas are present in 425 L of the gas? Round answer to 3 significant figures.

Answers

Answer:

No. of moles of methane = 18.9 mol

Explanation:

No. of moles = Volume of gas / Volume of gas (at STP)

Volume of gas at STP (Standard Temperature and Pressure) = 22.4L

N = 425 / 22.4

N = 18.973

∴No. of moles of methane = 18.9 mol

Which of these are found in eukaryotic cells?
1. nucleoid
2. vacuole
3. mitochondria
4. Golgi apparatus
O A. 1, 3, 4
O B. 1, 2,4
O C. 2, 3, 4
O D. 1, 2, 3

Answers

Answer:

C

Explanation:

nucleoid is prokaryotic

Answer:

mitochondria is found in eukaryotic cells.

How many moles of carbon dioxide gas occupy a volume of
81.3 L at 204 kPa and a temperature of 95.0 °C?
mol CO2

Answers

Answer:

5.42

Explanation:

I used a calculator

Answer: 5.42 mol CO2

Explanation: Uses idea gas law

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