Answer: Physical Weathering physically breaks the rock, while Chemical Weathering chemically changes the rock causing it to break.
Explanation: Physical Weathering happens naturally causing the rock to break. An example is roots growing into the concrete causing it to crack. Chemical Weathering on the other hand chemically changes the rock by a chemical reaction. An example is acid rain. Gas or other pollution mixing in with water causing acid rain.
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Subtract to find the temperature changes
for the water and the metal.
AT (water) =
AT (metal) =
Answer:
Explanation:
The temperature changes for the water and the metal is
ΔT (water) = 4.7°C
ΔT (metal) = - 72.9°C
Specific HeatThe quantity or amount of heat per unit mass required to raise the temperature of a body by one degree Celsius is known as specific heat. The unit of specific heat are joules or calories per gram per degree Celsius. Specific heat is an intensive property.
Calculate the temperature changesRelationship between temperature and heat is expressed as:
Q = mcΔT
where,
Q is heat energy in Joules (J)
m is mass (in grams)
c is specific heat in J/g°C
ΔT is change in temperature
Now calculate the temperature changes for the water
ΔT (water) = T(final) - T(initial)
= 27.1 - 22.4
= 4.7°C
Now calculate the temperature changes for the metal
ΔT(metal) = T(final) - T(initial)
= 27.1 - 100
= -72.9°C
Thus, from the above calculation we can see that the temperature changes for the water and the metal is
ΔT (water) = 4.7°C
ΔT (metal) = - 72.9°C
Learn more about the specific heat here: https://brainly.com/question/21406849
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Balance the combustion reaction between propane and oxygen.
C ₃ H ₈+ O ₂→ CO ₂ + H ₂ O
Answer:
The answer is C3H8 + 5O2 → 3CO2 + 4H2O .
Answer:
[tex]\huge \boxed{\mathrm{C_3 H_8 +5O_2 \Rightarrow 3CO_2 +4 H_2 O}}[/tex]
[tex]\rule[225]{225}{2}[/tex]
Explanation:
[tex]\sf C_3 H_8 +O_2 \Rightarrow CO_2 + H_2 O[/tex]
Balancing Carbon atoms on the right side,
[tex]\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 + H_2 O[/tex]
Balancing Hydrogen atoms on the right side,
[tex]\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 +4 H_2 O[/tex]
Balancing Oxygen atoms on the left side,
[tex]\sf C_3 H_8 +5O_2 \Rightarrow 3CO_2 +4 H_2 O[/tex]
[tex]\rule[225]{225}{2}[/tex]
