20000 students took a standardized math test. The scores on the test are normally distributed, with a mean score of 85 and a standard deviation of 5. About how many students scored between 90 and 95?

Answers

Answer 1

Answer: 2718

Step-by-step explanation:

Given: Mean score = 85

Standard deviation = 5

Let x be the score of a random student that follows normal distribution.

Then, the probability that a student scored between 90 and 95 will be

[tex]P(90< x < 95)\\\\=P(\dfrac{90-85}{5}<\dfrac{x-\mu}{\sigma}<\dfrac{95-85}{5})\\\\= P(1< z< 2)\ \ \ \ \ [z=\dfrac{x-\mu}{\sigma}]\\\\=P(z<2)-P(z<1)\\\\=0.9772-0.8413\\\\=0.1359[/tex]

The number of students scored between 90 and 95 = 0.1359 x (Total students)

= 0.1359 (20000)

= 2718

Hence, The number of students scored between 90 and 95 = 2718


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rows of
grapes
each hour he worked. After completing 140 rows of grapes, how many
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Answers

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Answers

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Answers

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