11 When you stand on scales you see your mass in kg. Explain whether
it is your mass or your weight that makes the scales work.

It takes source B 40 s to complete two half lives.

The half-life of a chemical is the amount of time it takes for half of the atoms in a sample to decay. This concept is widely used to describe how quickly a substance decays radioactively in nuclear physics and radiochemistry. Each radioactive substance has a unique half-life due to the properties of each atomic nucleus.

Looking at the graph, we can see that the half life of the source B is 20s .

Hence the time taken to complete two half lives = 2(20 s) =  40 s.

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The machine changes how work is done, by making the process easier and increasing output with less effort.

Any device that uses energy to carry out a task is a machine. Machines can be simple, like a lever or pulley, or complex, like a computer or a car engine. The purpose of a machine is to make work easier, faster, or more efficient than it would be without the machine. Different types of energy, including human power, electricity, and fuel, can be used to power machines.

Bicycle: A bicycle is a human-powered machine that allows people to move faster and with less effort than walking or running. A person can travel farther distances faster and with less physical effort by turning the wheels and shifting gears with their pedaling motion.

Ax blade: An ax blade is a cutting tool used for chopping wood. It facilitates the process of splitting wood by utilizing a sharp metal blade to cut through the wood fibers, rather than depending exclusively on physical power to break the wood apart.

Car jack: A car jack is a mechanical device used to lift a car off the ground. A person can raise the car to access the underside for repairs or maintenance by pulling a lever and applying hydraulic pressure. Compared to attempting to lift the car manually, this makes maintenance and repairs easier and safer.

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Answer:

F = 5.2324 x 10⁻⁸ N

Explanation:

F = G(m₁ · m₂) / r²

where F is the gravitational force, G is the gravitational constant (6.674 x 10⁻¹¹ N·m²/kg²), m1 and m2 are the masses of the two objects, and r is the distance between them.

Plugging in the given values m1 = m2 = 70.0 kg, r = 2.5 m:

F = (6.674 x 10⁻¹¹)(70.0 kg)² / (2.50 m)²

F = 5.2324 x 10⁻⁸ N

Therefore, the gravitational force between the two 70.0 kg masses separated by 2.50 m is approximately 5.2324 x 10⁻⁸ N.

The current would decrease if one light bulb is removed from the circuit. Option B is correct.

If one light bulb is removed from a simple circuit with two identical light bulbs that are in series with one another, the total resistance in the circuit would increase. This is because the resistance of the circuit is proportional to the number of resistors in the circuit, and removing one bulb reduces the number of resistors in the circuit.

The total current in the circuit would decrease because the resistance has increased. This is because the current flowing through a circuit is inversely proportional to the resistance of the circuit according to Ohm's law. Option B is correct.

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(a) The S-P difference (sec) is 40 sec.

(b) The amplitude (mm) is 10 mm

(c) The distance (km) is 380 km

(d) The magnitude (M) is 4.5

The S-P wave difference (sec) is a measure used in seismology to determine the distance between a seismic station and an earthquake source.

From the graph, the S-P difference, that is between S and P = 40 s - 0 s

= 40 s

The distance (km) corresponding to 40 sec is 380 km.

The amplitude of the wave is the maximum displacement of the wave and it is equal to 10 mm.

The corresponding magnitude of the wave is 4.5.

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Due to its high density, the mercury barometer is the greatest option for precisely measuring minor changes in pressure. The correct option is A.

A barometer is an instrument used to measure atmospheric pressure. It typically consists of a long glass tube filled with a liquid, usually mercury, and inverted in a container of the same liquid.

The preferred barometer to measure small pressures accurately would be the mercury barometer (option A), because it has a higher density compared to the other options and hence it can detect smaller changes in pressure.

To see why the other options are not as good for measuring small pressures accurately, we can compare their densities:

Oil-water barometer: The density of oil is lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.

Water barometer: The density of water is much lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.

Oil barometer: The density of oil is lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.

Therefore, option A, the mercury barometer, is the best choice for measuring small changes in pressure accurately due to its high density.

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Answer:

The physical quantities are the quantities that are the base quantities of the measurement. They are known as the fundamental quantities. The units of those units are known as the fundamental units. The derived physical quantities are dependent on the fundamental quantities.

a) The power of the electric golf cart is approximately 1.674 horsepower.

b) The force exerted by the electric golf cart is approximately 2182.5 Newtons.

(a) To convert 1.25 kW to horsepower, we can use the conversion factor:

1 horsepower = 0.746 kW

So, 1.25 kW = (1.25/0.746) horsepower = 1.674 horsepower (approximately)

Therefore, the power of the electric golf cart is approximately 1.674 horsepower.

(b) To calculate the force exerted by the cart, we can use the following formula:

force = power / velocity

where power is in watts, velocity is in meters per second, and force is in Newtons.

First, we need to convert the power of the cart from 1.25 kW to watts:

1 kW = 1000 watts

So, 1.25 kW = 1250 watts

Now, we need to convert the distance traveled by the cart from meters to kilometers, and the time taken from seconds to hours:

200 m = 0.2 km

35.0% = 0.35 hours

Using the formula, we can calculate the force exerted by the cart as:

force = power / velocity

force = 1250 / (0.2/0.35)

force = 1250 / 0.5714

force = 2182.5 N (approximately)

Therefore, the force exerted by the electric golf cart is approximately 2182.5 Newtons.

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The acceleration of the racing camel is 1.38 m/s².

From Newton's second law, force is expressed as;

F = m × a

Where is mass of object and a is the acceleration

Given that:

To determine the acceleration of the camel, pug the given values into the abovr formula and solve for a.

F = m × a

897N = 650 kg × a

Note that: Newton N is the same as kg·m/s²

Hence;

897kg·m/s² = 650 kg × a

Divide both sides by 650 kg

a = (897kg·m/s²) / (650 kg)

a = 1.38 m/s²

Therefore, the acceleration is 1.38 meters per second sqaure.

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Answer:

Approximately [tex]5.94\; {\rm N}[/tex].

Explanation:

The gravitational force between two objects of uniform mass is:

[tex]\displaystyle F = \frac{k\, M\, m}{r^{2}}[/tex],

Where:

Rearrange this equation to find [tex]r[/tex]:

[tex]\begin{aligned} r &= \sqrt{\frac{k\, M\, m}{F}} \\ &= \sqrt{\frac{(6.67 \times 10^{-11})\, (75.0)\, (60.0)}{8.50 \times 10^{-9}}}\; {\rm kg} \\ &\approx 5.94\; {\rm kg}\end{aligned}[/tex].

Answer: 3.99•10⁴ J

Explanation:

The Heat Formula is: Q = m • C • ΔT

Your given C, m, T₀, and T

C = 0.385 J/g•K

m = 1.55 kg or 1,550 g

T₀ = 33.0 °C

T = 99.9 °C

(ΔT = T - T₀)

Your only remaining variable is Q, heat, so you can now plug in your values to solve.

Q = (1550)(0.385)(99.9 - 33.0)

(ΔT(°C) = ΔT(K) because the conversion is linear)

Q = 39,922.575 J

or

3.99•10⁴ J

Answer:

A screw gauge, also known as a micrometer screw gauge, is a precision measuring instrument used to measure small distances with high accuracy. It consists of a calibrated screw and a calibrated thimble with a spindle and an anvil face. The spindle is attached to the screw, and the anvil face is fixed to the body of the instrument.

To use a screw gauge, the object being measured is placed between the spindle and the anvil face, and the screw is turned until the spindle makes contact with the object. The thimble is then turned, which moves the spindle and the screw, until the spindle is firmly in contact with the object. The reading on the scale of the thimble is then taken, which gives the distance between the spindle and the anvil face, with a high degree of precision.

Screw gauges are commonly used in a variety of fields, including engineering, machining, and scientific research, where accurate measurements are required.

Screw gauge measures diameter with high accuracy using a screw and nut mechanism. It has a pitch and graduated thimble.

A screw check is an estimating instrument used to gauge the width of items, particularly wires and chambers, with high exactness. It deals with the rule of a screw and nut component.The screw measure comprises of a U-molded outline with a screw toward one side and a thimble at the other.

The screw has a pitch, which is the distance gone by the screw in one complete turn. The pitch is as a rule of the request for 0.5 mm. The thimble is graduated into 50 or 100 equivalent parts. The roundabout scale on the thimble must be changed to such an extent that the zero of the scale matches with the zero of the pitch scale.

To utilize the screw check, the item whose width is to be estimated is set between the iron block and the shaft. The screw is turned until the shaft simply contacts the item. The pitch scale perusing is noted.

The thimble is then turned until the zero of the thimble scale concurs with the middle line of the pitch scale. The thimble scale perusing is then noted. The breadth of the item is then determined by adding the pitch scale perusing and the thimble scale perusing.

Along these lines, a screw check can gauge widths to an exactness of 0.01 mm or better. It is broadly utilized in designing, fabricating, and logical applications.

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The heel of shoe D applies the greatest force to the carpet because it has the largest surface area in contact with it, and thus the largest force is distributed over that larger area.

Answer:

The answer is 13.5g/cm³

Explanation:

m1=20g

m3=70g

m2=695g

v=20cm³

m2-m1/m3-m1

R.d=695-20/70-20

R.d=675/50

R.d=13.5

R.d=density of liquid/density of water

density of liquid =R.d×density of water

D=13.5×1

D=13.5g/cm³

The correct answer is using ultrasonic waves to create images of objects found inside other objects.

Infrasonic Wave: An infrasonic wave is a longitudinal elastic wave whose frequency is lower than that of sound, or 20Hz. For instance: It typically occurs during an earthquake. Ultrasonic Wave: An ultrasonic wave is a longitudinal wave with a frequency greater than the threshold of human hearing, or 20 kHz.

The audible range of frequencies below 20 Hz is known as infrasonic. Volcanoes, earthquakes, and thunder all emit sound in the infrasonic range. Human ears cannot hear this sound, but elephants and whales can. Ultrasonic frequencies are those that are above 20,000 Hz.

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The correct statement explaining how a megaphone amplifies sound is: "A megaphone amplifies sound by focusing sound energy into one specific direction."

By increasing the acoustic impedance perceived by the vocal chords and bringing them into closer proximity to the air, the loudhailer amplifies the sound and increases the amount of sound power that is emitted.

Many people are familiar with the distinctively distorted sound of a human voice amplified by a loudhailer thanks to its use in train and bus stations and sporting venues. It produces the sound of a vintage acoustic phonograph record player when used with music.

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Answer: boiling point is when the object of a liquid is hot enough to start to boil and create bubbles, and even start to evaporate into gas.

Explanation:

The true statements regarding VDGS Systems are you must power on and check the system before arrival and a qualified agent must man the Emergency stop.

VDGS stands for Visual Docking Guidance System. It is a technology used in airports to assist pilots in parking their aircraft at the gate by providing visual cues and guidance through the use of lights and/or displays.

The following statements regarding VDGS Systems are true:

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Sonography uses infrasonic waves to create images of objects found inside other objects.-False

Sonography, commonly known as ultrasound imaging, creates pictures of structures and organs inside the body using high-frequency sound waves (rather than infrared rays). These sound waves are emitted by a transducer, a portable device put on the skin and deliver sound waves through the body. The waves reverberate off internal organs and structures and are picked up by the transducer, which generates a visual representation on a computer screen. Ultrasonic imaging is widely used in obstetrics to monitor fetal development and in other medical specialties to diagnose and treat various disorders.

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To determine the elemental composition of the faraway galaxy, would use spectroscopy to analyze the light that is emitted or absorbed by the galaxy. This technique enables me to determine the types of atoms and molecules that are present in the galaxy, providing insights into its elemental composition.

To determine the galaxy's motion relative to the Milky Way, would use the Doppler effect to measure the galaxy's redshift or blueshift. This would enable me to determine whether the galaxy is moving away from or towards us, and at what speed, providing information about its motion relative to our galaxy.

It could also look for any gravitational lensing effects, which could indicate the presence of massive objects that are influencing the galaxy's motion.

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The best description of the image is (B) upright, smaller, and virtual is correct option.

To determine the characteristics of the image, we can use the thin lens equation:

1/f = 1/do + 1/di

where f is the focal length of the lens, do is the object distance (distance of the object from the lens), and di is the image distance (distance of the image from the lens).

We can also use the magnification equation:

m = -di/do

where m is the magnification.

First, we need to determine the focal length of the lens. We can use the fact that the lens is centered over the 14 cm ruler at the 7 cm mark, which means the lens is 7 cm from both the left and right sides of the ruler. Since the ruler has a total length of 14 cm, the lens must be in the middle, and the distance from the lens to the ruler is 7 cm. Therefore, the lens has a focal length of 7 cm.

Next, we can use the thin lens equation to find the image distance for the arrow located at the 6 cm mark:

1/7 = 1/(6 - 7) + 1/di

di = -7 cm

The negative sign indicates that the image is inverted.

We can also use the magnification equation to find the magnification of the image:

m = -di/do = -(-7)/(-6) = 7/6

The positive magnification indicates that the image is upright.

Finally, we can use the image distance and magnification to determine the characteristics of the image. Since the image distance is negative, the image is virtual. Since the magnification is less than 1, the image is smaller.

Therefore, the best description of the image is upright, smaller, and virtual.

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Answer:

upright, smaller virtual

Explanation:

Answer:

Explanation:

que ricos puntitos

In the 1600s, a scientist by the name of Robert Boyle made the first known demonstration of the fact that a sound cannot pass through void space. Boyle placed the clock in a glass jar with a tight lid.

Pump out the air from the sealed bell jar while putting an electrical bell inside. Set the electric bell to ringing. We cannot hear the sound that the bell makes with our ears. This indicates that sound waves require a material environment for propagation because they cannot move through a vacuum.

Since sound waves are carried from one location to another by the molecules of solids, liquids, and gases, sound requires a physical medium for propagation, such as a solid, liquid, or gas. Since there are no molecules in the vacuum that can vibrate and convey sound waves, sound cannot travel through it.

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The recoil speed of the rifle is 0.5 m/s.

Weight of the rifle, W = 30 N

Mass of the rifle, M = W/g = 30/10 = 3 kg

Mass of the bullet, m = 5 g = 5 x 10⁻³kg

Speed of the bullet, v = 300 m/s

a) The expression for the recoil speed of the rifle is given by,

v(r) = mv/M

v(r) = 5 x 10⁻³ x 300/3

v(r) = 0.5 m/s

b) Weight of the man, W' = 700 N

Mass of the man, M' = W'/g = 700/10 = 70 kg

So, the combined mass of the man and the rifle,

M₁ = M + M'

M₁ = 3 + 70

M₁ = 73 kg

Therefore, the recoil speed of man and rifle,

v(r)' = mv/M₁

v(r)' = 5 x 10⁻³ x 300/73

v(r)' = 0.0205 m/s

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Answer:

a = 0.724 m/s2

Explanation:

Known:

m = 650 kg

F = 897 N

a = ?

Use this formula:

F = ma

a = F/m

a = 650/897

a = 0.724 m/s2

The section that shows the largest acceleration on the graph would be section B, as it has the steepest slope.

This indicates that the car is increasing in speed at a faster rate during this section compared to the other sections.

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complete question not found in search engine.

Answer:60 seconds

Explanation: Since we have the boy's initial location si (0m), final location sf (600m) and his velocity v, we can have our position equation like so:

sf = si + vt
600 = 0 + 10t

Solve for t by dividing 600 by 10 and your time t = 60s

Answer:

Explanation:

To find the relative velocity of two cars moving in different directions, we need to subtract their velocities. In this case, one car is moving with a velocity of 70 km/hr and the other car is moving with a velocity in the west direction.

Let's assume that the velocity of the second car is also 70 km/hr. Since the car is moving in the west direction, we can represent its velocity as -70 km/hr (negative sign indicates motion in the opposite direction).

Now, we can find the relative velocity of the second car with respect to the first car by subtracting the velocity of the first car from the velocity of the second car:

Relative velocity = Velocity of the second car - Velocity of the first car

= (-70 km/hr) - (70 km/hr)

= -140 km/hr

Therefore, the relative velocity of the second car with respect to the first car is -140 km/hr, which means that the two cars are moving away from each other at a speed of 140 km/hr.

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The time taken to get up and out of the way before you and the child collide is 2.82 s.

The time taken to get up and out of the way before you and the child collide is calculated as follows;

s = v + ¹/₂at²

s = v + ¹/₂(g sin (31)t²

where;

The time taken to get up is calculated as;

20 = 0 +  ¹/₂(9.8 sin (31)t²

20 = 2.524t²

t² = 20/2.524

t² = 7.925

t = 2.82 s

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