1. What happens to the current in a series circuit as it moves through each component? a. The current stays the same throughout the circuit.
b. The current will increase or decrease depending on the resistance.
c. The current decreases with each component it goes through.
d. The current increases with each component it goes through.

2. A 10-volt power supply is placed in series with two 5-ohm resistors. What is the current in the circuit after it passes through each of the two resistors?(1 point)
a. The current will stay the same at 1 amp after passing through both resistors.
b. The current will drop to 2 amps after the first resistor and then to 1 amp after the second resistor.
c. The current will stay the same at 2 amps after passing through both resistors.
d. The current will drop to 1 amp after the first resistor and then to 0 amps after the second resistor.

3. What is the voltage that passes through R1 and R2?
a. R1: 12 V, R2: 24 V
b. R1: 8 V, R2: 4 V
c. R1: 12 V, R2: 12 V
d. R1: 6 V, R2: 6 V

4. Which of the following correctly describes the magnitude of currents I1 and I2 ­?
a. I1 is equal to I2
b. I1 and I2 approach zero
c. I1 is greater than I2
d. I1 is less than I2

5. If the energy of an electric charge flowing in a circuit is conserved, which of the following obeys the Kirchhoff junction rule?
a. The sum of the current flowing in is greater than the sum of current flowing out.
b. The sum of the current flowing in is less than the sum of the current flowing out.
c. The sum of the current flowing in is equal to the sum of current flowing out.
d. The sum of the current flowing in is zero and the sum of the current flowing out is greater than zero.

Answer:

Diabetes

Explanation:

Insulin is an important hormone that helps the body convert sugar, starches, and other foods into energy.

Answer:

Pls ezplain your question more

Explanation:

Answer:

orbit is the answer

(a) The minimum speed required for the ball to clear the net is 26.3 m/s.

(b) The horizontal distance of the ball when it clears the net is 11.3 m

(c) The total time spent in the air by the ball is 1 s.

The time of motion of the tennis ball is calculated by using the following kinematic equation as shown below;

[tex]h = h_0 + v_0_yt - \frac{1}{2} gt^2\\\\0.9 = 2.5+ 0 - \frac{1}{2} (9.8) t^2\\\\0.9 = 2.5 - 4.9t^2\\\\4.9t^2 = 1.6\\\\t^2 = \frac{1.6}{4.9} \\\\t^2 = 0.327\\\\t = \sqrt{0.327} \\\\t = 0.57 \ s[/tex]

The minimum speed of the ball is calculated as follows;

[tex]v_x = \frac{X}{t} \\\\v_x = \frac{15}{0.57} \\\\v_x = 26.3 \ m/s[/tex]

The time of motion from top of the high net is calculated as follows;

[tex]t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 0.9}{9.8} } \\\\t = 0.43 \ s[/tex]

Horizontal range = 0.43 x 26.3 = 11.3 m

Total time in air = 0.57 s + 0.43 s = 1.0 s

Learn more about horizontal velocity here: https://brainly.com/question/24949996

Answer: Planet A is closer to the Sun and has much greater atmospheric pressure. This suggests that planet A has a thicker atmosphere. Planet A's atmosphere is also mostly made of carbon dioxide, which is a greenhouse gas. This gas retains heat, raising the surface temperature of planet A.

Explanation:

Planet A is closer to the Sun and has much greater atmospheric pressure. This suggests that planet A has a thicker atmosphere. Planet A’s atmosphere is also mostly made of carbon dioxide (CO2), which is a greenhouse gas. This gas retains heat, raising the surface temperature of planet A.

Hope this one help.

Answer:

Force=Mass*acceleration

on earth, acceleration=9.81 m/s^2

900 N=Mass*9.81 m/s^2

Mass=91.74 Kg

F=Mass*acceleration(Jupiter)

F=91.74Kg*25.9m/s

F=2376.066 N on Jupiter

Plz mark me as brainliest if u found it helpful

Answer:

v=u+gt , initially u=0 and g acting in the direction of movement of body.

v=0+9.8×2

v=19.6m/s

Explanation:

sorry i dont have exact answer but hope this above equation will help you ....♡

Answer:

Frame of reference

Answer: density decreases

Explanation:

Answer:

C

Explanation:

Answer:

that car got obliterated almost like the day my uncle said come with me

Explanation:

the outcome was not good

On a drive from your home to town, you wish

to average 33.6 mph. The distance from your

home to town is 90 miles. However, at 45 miles

(half way), you find you have averaged only

25.2 mph.

What average speed must you maintain in

the remaining distance in order to have an

overall average speed of 33.6 mph?

Answer in units of mph

let the speed be x

total average = 33.6

Answer:

Explanation:

To find the force acting on an object we use the formula

From the question

mass = 3.5 kg

acceleration = 0.80 m/s²

We have

Force = 3.5 × 0.8

We have the final answer as

Hope this helps you

Answer:

10,200 N

Explanation:

Given:

Mass of the car m = 1200 kg

Acceleration of the car a = 8.5 m/s^2

Force F=?

[tex]\because F = ma\\

\therefore F = 1200 \times 8.5\\

\therefore F = 10,200 N \\ [/tex]

Answer:

 N = 136.77 N

Explanation:

This is an exercise in Newton's second law, let's set a reference frame with the horizontal x-axis and the vertical y-axis. In the attachment we can see the applied forces.

Let's use trigonometry to decompose the force F1

           cos θ = F₁ₓ / F₁

           sin θ = F_{1y} / F₁

           F₁ₓ = F₁ cos θ

           F_{1y} = F₁ sin θ

now let's apply Newton's second law to each axis

X axis

        F₁ₓ - F4 = m a

Y axis

        N + F3 + F_{1y} -F₂ -W = 0

the acceleration can be calculated with kinematics

        v = v₀ + a t

since the object starts from rest, the initial velocity is zero v₀ = 0

        a = v / t

        a = 20/3

        a = 6.667 m / s²

we substitute in the equation

        F₁ₓ = F₄ + m a

        F₁ₓ = 42 + 15  6,667

        F₁ₓ = 142 N

        F₁ cos θ = 142

        cos θ = 142/206 = 0.6893

        θ = cos⁻¹ 0.6893

        θ = 46.42º

now let's work the y axis

        N = W + F₂ - F₃ - F_{1y}

        N  = 15 9.8 + 144 -5 - 206 sin 46.42

        N = 286 - 149.23

        N = 136.77 N

Answer:

25.88 N

Explanation:

Mass of the shopping cart,[tex]m=65 kg[/tex]

The coefficient of friction between the cart and the floor, [tex]\mu= 0.01[/tex]

Let, F be the required force to accelerate the cart at [tex]a=0.30 m/s^2[/tex].

Gravitational force, mg, acts downward which is being balanced by the normal reaction, N, on the cart by the floor.

As the motion of the cart in the vertical direction is zero. So, using the static equilibrium condition will be zero.

From free body diagram (FBD):

[tex]N-mg=0[/tex]

[tex]\Rightarrow N=mg.[/tex]

the net force action in this direction The frictional force, f, acts in the direction to opposes the motion of the cart as shown.

[tex]f=\muN=\mu mg[/tex]

Now, apply the dynamic equilibrium condition in the horizontal direction, i.e. net force acting on the body equals the rate of change of momentum of the body. From the FBD of the cart, we have

[tex]F-f-ma=0[/tex]

[tex]\Rightarrow F=f+ma[/tex]

[tex]\Rightarrow F=\mu mg+ma[/tex]

[tex]\Rightarrow F=m(\mu g +a)[/tex]

[tex]\Rightarrow F=65(0.01\times 9.81 + 0.3)[/tex]

[tex]\Rightarrow F=25.88 N.[/tex]

Hence, 25.88 N force required to accelerate the body with 0.03 [tex]m/s^2[/tex] .

Answer:

1.53 m/s toward the beach

Explanation:

1.53 m/s toward the beach

Explanation:

The magnitude of the velocity of the runner is given by:

where

d is the displacement of the runner

t is the time taken

In this case, d=110 m and t=72 s, so the velocity of the runner is

Velocity is a vector, so it consists of both magnitude and direction: we already calculate the magnitude, while the direction is given by the problem, toward the beach.

Answer:

66n

Explanation:

4376

Answer:

I think it's D

Explanation:

Most mobiles have touch screens

Answer:

The change in potential energy of the mass as it goes up the incline is 0.343 joules.

Explanation:

We must remember in this case that change in the potential energy is entirely represented by the change in the gravitational potential energy. From Work-Energy Theorem and definition of work we get that:

[tex]U_{g}= m\cdot g\cdot \Delta y[/tex]

Where:

[tex]U_{g}[/tex] - Gravitational potential energy, measured in Joules.

[tex]m[/tex] - Mass, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]\Delta y[/tex] - Change in vertical height, measured in meters.

This work is the energy needed to counteract effects of gravity at given vertical displacement.

If we know that [tex]m = 0.5\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\Delta y = 0.07\,m[/tex], the change in the potential energy of the mass as it goes up the incline is:

[tex]U_{g} = (0.5\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.07\,m)[/tex]

[tex]U_{g} = 0.343\,J[/tex]

The change in potential energy of the mass as it goes up the incline is 0.343 joules.

The change in the potential energy (in Joules) of the mass as it goes up the incline is 0.343 J.

We know that

Potential energy = m*g*h

Here m means the mass = 0.5 kg

g means the gravity = 9.8

And, the h means the height  = 7cm = 0.07m

So, the change in the potential energy should be

=0.5*9.8*0.07

=0.343 J

hence, we can conclude that the  change in the potential energy (in Joules) of the mass as it goes up the incline is 0.343 J.

Learn more about energy here: https://brainly.com/question/13203990

Answer:

The thermal conductivity  [tex]k  = 1.4094   W/ m\cdot K[/tex]

Explanation:

From the question we are told that

  The  depth of the thermocouple from the surface is  x =  10 mm  = 0.01 m

   The  temperature is  [tex]T_f  =  100 ^o C[/tex]

   The  initial temperature is   [tex]T_i  =  30 ^o C[/tex]

    The  temperature of the thermocouple after t =  2 minutes( 2 * 60 =  120 \ seconds)  is   [tex]T_t  =  65 ^o C[/tex]

    The  density of the material  is  [tex]\rho =  2200 kg/m^3[/tex]

     The specific heat of the solid [tex]c_s  =  700 J/kg \cdot K[/tex]

Generally  the  equation for  semi -infinite medium  is mathematically as  

    [tex]\frac{T_s - T }{T_i - T} =  erf [\frac{x}{2 \sqrt{\alpha  * t} } ][/tex]

     [tex]\frac{65 - 100 }{30 - 100} =  erf [\frac{x}{2 \sqrt{\alpha  * t} } ][/tex]

        [tex]0.5 =  erf [\frac{0.01}{2 \sqrt{\alpha  * 120} } ][/tex]

Here [tex]\alpha[/tex] is a constant with unit [tex]m^2 /s[/tex]

  [tex]\frac{0.01}{ 2 (\sqrt{\alpha  *  120 } )}[/tex]   this is from the Gaussian function table  

    [tex]0.0 1 =  0.954 * (\sqrt{\alpha * 120  } )[/tex]

=>   [tex]\sqrt{\alpha  * 120  } =  \frac{0.01 }{0.954 }[/tex]

=>   [tex]\alpha =  9.1525 *10^{-7} \  m^2 /s[/tex]

Generally the thermal  conductivity is mathematically represented as

     [tex]k  =  \alpha  *  \rho * c_s[/tex]

      [tex]k  = 9.1525 *10^{-7}   *  2200 * 700[/tex]

     [tex]k  = 1.4094   W/ m\cdot K[/tex]

Answer:

m₁ = 1720

m₂ = 413.46

m₃ = 586.54

mr = 720

Explanation:

Draw a diagram.  Sea water (1000 lb/h, 3.1% salt) is mixed with the recycled brine (mr, 5.25% salt) to create the inlet stream (m₁, 4.0% salt).  This inlet stream is fed into the osmosis cell.  The osmosis cell produces desalinated water (m₂, 500 ppm) and brine tailings.  Part of the tailings is recycled (mr, 5.25% salt), and the rest is removed (m₃, 5.25%).

The mass of water is conserved, so:

1000 + mr = m₁

m₁ = mr + m₂ + m₃

The mass of salt is conserved, so:

0.031 (1000) + 0.0525 mr = 0.040 m₁

0.040 m₁ = 0.0525 mr + 0.0005 m₂ + 0.0525 m₃

Four unknown variables, and four equations.  We can use the first and third to find mr and m₁.

0.031 (1000) + 0.0525 mr = 0.040 (1000 + mr)

31 + 0.0525 mr = 40 + 0.040 mr

0.0125 mr = 9

mr = 720

m₁ = 1720

Now we can use these values and the second and fourth equations to solve for the remaining variables.

1720 = 720 + m₂ + m₃

0.040 (1720) = 0.0525 (720) + 0.0005 m₂ + 0.0525 m₃

1000 = m₂ + m₃

68.8 = 37.8 + 0.0005 m₂ + 0.0525 m₃

68.8 = 37.8 + 0.0005 m₂ + 0.0525 (1000 − m₂)

68.8 = 37.8 + 0.0005 m₂ + 52.5 − 0.0525 m₂

0.052 m₂ = 21.5

m₂ = 413.46

m₃ = 586.54

Answer:

The unit energy losses due to nonconservative forces is 881.40 joules per kilogram.

Explanation:

We can estimate the unit energy losses of gas eruption by Principle of Energy Conservation and Work-Energy Theorem:

[tex]U_{g,1} + K_{1} = U_{g,2}+K_{2}+W_{loss}[/tex] (Eq. 1)

Where:

[tex]U_{g,1}[/tex] - Gravitational potential energy of gas eruptions at surface, measured in joules.

[tex]U_{g,2}[/tex] - Gravitational potential energy of gas eruptions at highest height, measured in joules.

[tex]K_{1}[/tex] - Translational kinetic energy of gas eruptions at surface, measured in joules.

[tex]K_{2}[/tex] - Translational kinetic energy of gas eruptions at highest height, measured in joules.

[tex]W_{loss}[/tex] - Energy losses due to nonconservative forces, measured in joules.

We clear the component associated with energy losses in (Eq. 1):

[tex]W_{loss} = U_{g,1}-U_{g,2}+ K_{1}-K_{2}[/tex]

And we expand it afterwards:

[tex]W_{loss} = m\cdot g\cdot (z_{1}-z_{2}) + \frac{1}{2}\cdot m \cdot (v_{1}^{2}-v_{2}^{2})[/tex] (Eq. 2a)

[tex]w_{loss} = g\cdot (z_{1}-z_{2})+\frac{1}{2}\cdot (v_{1}^{2}-v_{2}^{2})[/tex] (Eq. 2b)

Where:

[tex]W_{loss}[/tex] - Energy losses due to nonconservative forces, measured in joules.

[tex]w_{loss}[/tex] - Unit energy losses due to nonconservative forces, measured in joules per kilogram.

[tex]g[/tex] - Gravitational acceleration, measured in meters per second.

[tex]z_{1}[/tex], [tex]z_{2}[/tex] - Bottom and top height, measured in meters.

[tex]v_{1}[/tex], [tex]v_{2}[/tex] - Gas eruption speeds at surface and highest heights, measured in meters per second.

If we know that [tex]g = 3.7\,\frac{m}{s^{2}}[/tex], [tex]z_{1} = 0\,m[/tex]. [tex]z_{2} =62\,m[/tex]. [tex]v_{1} = 36.111\,\frac{m}{s}[/tex] and [tex]v_{2} = 0\,\frac{m}{s}[/tex], the unit energy losses are:

[tex]w_{loss} = \left(3.7\,\frac{m}{s^{2}} \right)\cdot (62\,m-0\,m)+\frac{1}{2} \cdot \left[\left(36.11\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right][/tex]

[tex]w_{loss} = 881.40\,\frac{J}{kg}[/tex]

The unit energy losses due to nonconservative forces is 881.40 joules per kilogram.

Answer:

]

Explanation:

Answer:

As the earth rotates, it tries to drag/bring the tidal bulges with it. When a large amount of friction is applied, the earth spin will gradually and slow down but not all the way down.

Answer:

If the Earth spun slower the rate of tides will be higher because the moon will start revolving faster tan the Earth, creating more tides as the moon will revolve more around the Earth in a month.

If my answer helped, kindly mark me as the brainliest !!

Thank You!!

Answer:

Energy storage plays an important role in this balancing act and helps to create a more flexible and reliable grid system. For example, when there is more supply than demand, such as during the night when low-cost power plants continue to operate, the excess electricity generation can be used to power storage devices.

Explanation:

I hope this helps you out and if your feeling generous plz mark brainliest it helps me a lot thank you:)

It important for scientists to find better ways to store solar and wind energy because solar and wind energy have variable outputs.

Lately, the world have begun to gradually gravitate away from non renewable energy sources such as fossil fuels and research efforts have been concentrated on renewable energy sources such as solar and wind energy.

However, the energy output from these sources are variable. Therefore, it is necessary to device ways to store energy from these sources in order to improve overall energy supply.

Learn more: https://brainly.com/question/17319210