(04.03 MC)

Alex is planning to surround his pool ABCD with a single line of tiles. How many units of tile will he need to surround his pool? Round your answer to the nearest hundredth.

A coordinate plane with quadrilateral ABCD at A 0 comma 3, B 2 comma 4, C 4 comma 0, and D 2 comma negative 1. Angles A and C are right angles, the length of segment AB is 2 and 24 hundredths units, and the length of diagonal BD is 5 units.

8.96
10.48
13.42
20.42

Answers

Answer 1

The units of tile will he need to surround his pool is 13.42

The given parameters are:

[tex]AB =2.24[/tex]

[tex]BD =5[/tex]

Start by calculating the distance BC using the following Pythagoras theorem

[tex]BD^2 = AB^2 + BC^2[/tex]

So, we have:

[tex]5^2 = 2.24^2 + BC^2[/tex]

[tex]25 = 5 + BC^2[/tex]

Collect like terms

[tex]BC^2 = 25 - 5[/tex]

[tex]BC^2 = 20[/tex]

Take the square roots of both sides

[tex]BC = 4.47[/tex]

The unit of tiles is then calculated using the following perimeter formula

[tex]Tiles = 2 \times (AB + BC)[/tex]

So, we have:

[tex]Tiles = 2 \times (2.24 + 4.47)[/tex]

[tex]Tiles = 13.42[/tex]

Hence, the units of tile will he need to surround his pool is 13.42

Read more about perimeters at:

https://brainly.com/question/17297081


Related Questions

Simplify the following:

(4x^3+2x) + (8x^3 -5x + 4)

Answers

Answer:

12x^3 - 3x + 4

Im 100% percent sure and if you  are kind enough, I’d love a BRAINLIEST :)

Please answer this correctly

Answers

Answer:

The answer is 2.5ft².

Step-by-step explanation:

Given that the area of trapezoid formula is A = 1/2×(a+b)×h where a and b is the length and h is the height. Then substitute the following values into the formula :

[tex]area = \frac{1}{2} \times (a + b) \times h[/tex]

Let a = 1.2,

Let b = 0.8,

Let c = 2.5,

[tex]area = \frac{1}{2} \times (1.2 + 0.8) \times 2.5[/tex]

[tex]area = \frac{1}{2} \times 2 \times 2.5[/tex]

[tex]area = 2.5 {feet}^{2} [/tex]

The students in Mrs. Willow's reading class are all reading the same novel independently. Four students create a graph of their reading rates, in words per minute, as shown below. Which student reads the fastest? A. Mason B. RIley C. Sarah D. Charlie

Answers

Answer:

Mason reads the fastest

Answer:

c

Step-by-step explanation:

try to see how much every person reads every one or two minutes.

Charlie: 350 in two min

Mason :400 in two min

Sarah: 450 in two min (the middle of 300-600 is 450)

so between the three Sarah wins.

now Reilly is a bit more difficult but you can see that she read 4000 in 20 min. so if we divide it by 10 we can see she reads 400 in 2 min. and therefore Sarah os the winner.

How do I explain this answer

Answers

Answer:

199

Step-by-step explanation:

i dont know

what is the volume of a cylinder with diameter of the base 4 inches and the height of the cylinder 6 inches ?​

Answers

Answer:

24π

Step-by-step explanation:

If the diameter is 4, the radius is 2

V = [tex]\pi r^2 *h[/tex]

r = 2

h = 6

24π

Answer:

24 brainliest appreciatEd

Step-by-step explanation:

diameter: 4 inch (Radius is 2)

V

If the diameter is 4, the radius is 2

V is  r^2*h

the radius is 6

so it’s 24

I’ll give the bralyist to the first correct answer

Let f be defined as shown.
What is f1 (-7)?

Answers

Answer:

The answer is 2

From the function when the input is 2 the output is -7. The inverse reverses the order so the input will be -7 and the output will be 2.

Which one of the following is always true?a. The coefficient of variation measures variability in a positively skewed data set relative to the size of the median.b. None of the suggested answers are correctc. The coefficient of variation is a measure of relative dispersion that expresses the standard deviation as a percentage of the mean, for any data on a ratio scale and an interval scale.d. The interquartile range is very unique in the sense that it is a measure of central tendency as well as a measure of dispersion.e. The coefficient of variation should only be used to compare positive data on an interval scale.

Answers

Answer:

C. The coefficient of variation is a measure of relative dispersion that expresses the standard deviation as a percentage of the mean, for any data on a ratio scale and an interval scale

Step-by-step explanation:

Th Coefficient of Variance is a measure of dispersion that can be calculated using the formula:

[tex]CV = \frac{\sigma_{x} }{\mu_{x} } * 100%[/tex]

Where [tex]\sigma{x}[/tex] is the Standard Deviation

and [tex]\mu_{x}[/tex] is the sample mean

From the formula written above, it is shown that the Coefficient of Variation expresses the Standard Deviation as a percentage of the mean.

Coefficient of variation can be used to compare positive as well as negative data on the ratio and interval scale, it is not only used for positive data.

The Interquartile Range is not a measure of central tendency, it is a measure of dispersion.

An appliance repairman charges $25 plus $40 per hour for house calls. Write the rule as an equation that relates hours worked x and his fee y.

Answers

To get the total fee, you need to multiply the hourly rate by number of hours worked and add that to the flat fee of $25.

The equation would be y = 40x + 25

Simplify
20x over 70x

Answers

Answer:

The answer is 2/7.

Step-by-step explanation:

You have to cut out the common terms :

[tex] \frac{20x}{70x} [/tex]

[tex] \frac{20}{70} [/tex]

[tex] \frac{2}{7} [/tex]

The answer is 2/7
hope that helps!!

Please answer this correctly

Answers

Answer:

See below.

Step-by-step explanation:

The total is 20 friends. This means that we need to make each frequency into a fraction, then simplify to percentage.

1. 10/20 = 50%

2. 3/20 15%

3. 2/20 = 10%

4. 5/20 = 25%

Hope this helps! (Please consider giving brainliest)

Answer:

Bus: 50%

Walk: 15%

Bike: 10%

Car: 25%

Step-by-step explanation:

The total amount of friends is 20.

10 out of 20 is equal to 1/2, which is equal to 50%.

3 out of 20 is equal to 15%.

2 out of 20 is equal to 10%.

And 5 out of 20 is equal to 1/4, which is equal to 25%.

Please mark Brainliest if correct

A bank is investigating ways to entice customers to charge more on their credit cards. (Banks earn a fee from the merchant on each purchase, and hope to collect interest from the customers, as well.) A bank selects a random group of customers who are told their "cash back" will increase from 1% to 2% for all charges above a certain dollar amount each month. Of the 500 customers who were told the increase applied to charges above $1000 each month, the average increase in spending was $527 with a standard deviation of $225. Of the 500 customers who were told the increase applied to charges above $2000 each month, the average increase in spending was $439 with a standard deviation of $189. A level C = 95% confidence interval for \mu_1\:-\:\mu_2μ 1 − μ 2 is approximated by Group of answer choices (62.2, 113.8) (86.2, 120.5) (10.3, 23.8) (55.6, 67.8)

Answers

Answer:

[tex]CI = (\bar{x_{1} } - \bar{x_{2}} ) \pm MoE\\\\[/tex]

[tex]CI = (527 - 439) \pm 25.75\\\\CI = 88 \pm 25.75\\\\CI = 88 - 25.75 \:\: and \:\: 88 + 25.75\\\\CI = (62.2 \: ,\: 113.8 )[/tex]

The correct answer choice is a. (62.2, 113.8)

Step-by-step explanation:

Of the 500 customers who were told the increase applied to charges above $1000 each month, the average increase in spending was $527 with a standard deviation of $225.

Sample size = n₁ = 500

Sample mean = x₁ = $527

Standard deviation = s₁ = $225

Of the 500 customers who were told the increase applied to charges above $2000 each month, the average increase in spending was $439 with a standard deviation of $189

Sample size = n₂ = 500

Sample mean = x₂ = $439

Standard deviation = s₂ = $189

We are asked to find the 95% confidence interval for the difference between two means.

The given group of answer choices are

a. (62.2, 113.8)

b. (86.2, 120.5)

c. (10.3, 23.8)

d. (55.6, 67.8)

The confidence interval for the difference between two means is given by

[tex]CI = (\bar{x_{1} } - \bar{x_{2}} ) \pm MoE\\\\[/tex]

Where [tex]\bar{x_{1} }[/tex] and [tex]\bar{x_{2} }[/tex] are the given sample means and margin of error is given by

[tex]$ MoE = z_{\alpha/2} \cdot \sqrt{\frac{s_{1}^2}{n_1} + \frac{s_{2}^2}{n_2}} $[/tex]

The z-score corresponding to 95% confidence level is given by

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

From the z-table at α = 0.025 the z-score is 1.96

[tex]$ MoE = 1.96 \cdot \sqrt{\frac{225^2}{500} + \frac{189^2}{500}} $[/tex]

[tex]MoE = 1.96 \cdot 13.14[/tex]

[tex]MoE = 25.75[/tex]

Finally,

[tex]CI = (\bar{x_{1} } - \bar{x_{2}} ) \pm MoE\\\\[/tex]

[tex]CI = (527 - 439) \pm 25.75\\\\CI = 88 \pm 25.75\\\\CI = 88 - 25.75 \:\: and \:\: 88 + 25.75\\\\CI = (62.2 \: ,\: 113.8 )[/tex]

Therefore, the correct answer choice is a. (62.2, 113.8)

How to use z-table?

In the z-table find the probability of 0.025

Note down the value of that row, it would be 1.9.

Note down the value of that column, it would be 0.06.

Add the two numbers together.

The z-score is 1.9 + 0.06 = 1.96

PLEASE HELP QUICKLY AS POSSIBLE THANK YOU :)​

Answers

Answer:

Option (B).

Step-by-step explanation:

From the table shown in the figure attached,

There is a common difference of 5 in every successive and previous term, so the relation is a linear relation.

Let the equation representing the relation is,

y - y' = m(x - x')

where m = slope of the line

Now we choose two ordered pairs from the table,

Let the points are (10, 54) and (11, 59)

Slope = [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

      m = [tex]\frac{59-54}{11-10}[/tex]

      m = 5

Now the equation of of the line passing through (10, 54) and slope = 5

y - 54 = 5(x - 10)

y - 54 = 5x - 50

y = 5x - 50 + 54

y = 5x + 4

By substituting the values of x and y from the ordered pairs given in the options we find option B satisfies the equation.

For (2, 14),

14 = 5×2 + 4

14 =  14 [True]

For (3, 19),

19 = 5×3 + 4

19 = 19 [True]

Therefore, option (B) will be the answer.

Find the range of the set of numbers shown by the box-and-whisker plot.
6
6
7
8
9
10
11
12
13
14
16
16
17
18
19
20
21
22

Answers

I’m confused on what you are asking in this I think it would be 6

Answer:

16

Step-by-step explanation:

The range is the difference between the highest and lowest number of a data set. 22-6=16

Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a left-tailed test is z = -1.63.
a. 0.1032; fail to reject the null hypothesis
b. 0.0516; reject the null hypothesis
c. 0.9484; fail to reject the null hypothesis
d. 0.0516; fail to reject the null hypothesis

Answers

Answer:

Option d

Step-by-step explanation:

The p-value is 0.0516 which is not statistically significant to reject the null hypothesis. Thus we will fail to reject the null hypothesis.

The amount of pollutants that are found in waterways near large cities is normally distributed with mean 9 ppm and standard deviation 1.5 ppm. 38 randomly selected large cities are studied. Round all answers to 4 decimal places where possible.
1. What is the distribution of XX? XX ~ N(,)
2. What is the distribution of ¯xx¯? ¯xx¯ ~ N(,)
3. What is the probability that one randomly selected city's waterway will have more than 9.6 ppm pollutants?
4. For the 37 cities, find the probability that the average amount of pollutants is more than 9.6 ppm.
5. For part d), is the assumption that the distribution is normal necessary? YesNo
6. Find the IQR for the average of 37 cities.
Q1 = ppm
Q3 = ppm
IQR: ppm

Answers

Answer:

Step-by-step explanation:

Hello!

There are two values of n in the text, I'll use the one that appears in all the questions.

The variable of interest is

X: pollutants found in waterways near large cities. (ppm)

This variable has a normal distribution with parameters μ= 9ppm and σ= 1.5ppm

1) X~N(μ;σ²)

X~N(9;2.25)

2) The distribution of the sample mean is X~N(μ;σ²/n)

σ²/n= 2.25/37= 0.06

X~N(9;0.06)

3) P(X>9.6)

To calculate this probability you have to use the standard normal distribution. Using the population parameters, you can calculate the corresponding Z value:

Z= (X-μ)/σ= (9.6-9)/1.5= 0.4

P(Z>0.4)= 1-P(Z≤0.4)= 1 - 0.65542= 0.34458

The probability of selecting a city at random and finding 9.6ppm pollutants.

4) In this item, instead of calculating the probability of one value of the variable you have to calculate the probability of the sample average taking a determined value. Because of this, you have to work using the distribution of the sample mean, instead of the distribution of the variable.

P(X[bar]>9.6)

Z= (X[bar]-μ)/(σ/√n)= (9.6-9)/√0.06= 2.45

P(Z>2.45)= 1 - P(Z≤2.45)= 1 - 0.99286= 0.00714

5) The assumption of a normal distribution is not necessary for item 4. Since the sample size is large enough (greater than 30) you can apply the central limit theorem and approximate the distribution of the sample mean to normal, regarding the distribution of the original variable.

6)

In this case, you have to work starting with the standard normal distribution and then "translate" the Z values into values of the average amount of pollutants.

The first quartile divides the bottom 25% of the distribution from the top 75%, symbolically:

P(Z≤z₁)= 0.25

z₁= -0.674

z₁= (X[bar]-μ)/(σ/√n)

z₁*(√n/σ)=X[bar]-μ

X[bar]=z₁*(√n/σ)+μ

X[bar]=(-0.674)*(√37/1.5)+9= 6.27ppm

The third quartile divides the bottom 75% of the distribution from the top 25%, symbolically:

P(Z≤z₂)= 0.75

z₂= 0.674

z₂= (X[bar]-μ)/(σ/√n)

z₂*(√n/σ)=X[bar]-μ

X[bar]=z₂*(√n/σ)+μ

X[bar]=(0.674)*(√37/1.5)+9= 11.7.3ppm

IQR= Q₃-Q₁= 11.73-6.27= 5.46ppm

I hope this helps!

Help! Please do a,b,c and d with explanation

Answers

Answer:

  a.  235°

  b. 146.03 km

  c. 105 km

  d. 193 km

Step-by-step explanation:

a. The bearing of E from A is given as 55°. The bearing in the opposite direction, from E to A, is this angle with 180° added:

  bearing of A from E = 55° +180° = 235°

__

b. The internal angle at E is the difference between the external angle at C and the internal angle at A:

  ∠E = 134° -55° = 79°

The law of sines tells you ...

  CE/sin(∠A) = CA/sin(∠E)

  CE = CA(sin(∠A)/sin(∠E)) = (175 km)·sin(55°)/sin(79°) ≈ 146.03 km

  CE ≈ 146 km

__

c. The internal angle at C is the supplement of the external angle, so is ...

  ∠C = 180° -134° = 46°

The distance PE is opposite that angle, and CE is the hypotenuse of the right triangle CPE. The sine trig relation is helpful here:

  Sin = Opposite/Hypotenuse

  sin(46°) = PE/CE

  PE = CE·sin(46°) = 146.03 km·sin(46°) ≈ 105.05 km

  PE ≈ 105 km

__

d. DE can be found from the law of cosines:

  DE² = DC² +CE² -2·DC·CE·cos(134°)

  DE² = 60² +146.03² -2(60)(146.03)cos(134°) ≈ 37099.43

  DE = √37099.43 ≈ 192.6 . . . km

  DE is about 193 km

What is the area of the obtuse triangle below?
A. 90 sq units
B. 23 sq units
C. 18 sq units
D. 45 sq units

Answers

Answer:

A. 90 sq. units

Step-by-step explanation:

5(18) = 90

Which point is an x-intercept of the quadratic function f(x) = (x + 6)(x – 3)? (0,6) (0,–6) (6,0) (–6,0)

Answers

Answer: (-6, 0)

Step-by-step explanation:

X-intercepts of equations are any points on the equation that lie on the x-axis, or the horizontal line "y = 0".

In order to find the x-intercept of an equation, find the points that will satisfy the equation "y = 0":

y = (x + 6)(x - 3)

y = 0

(x + 6)(x - 3) = 0

With this equation, you can find which points lie on the x-axis.

When x = -6, the equation is: 0 * -9 = 0, which is correct.

When x = 3, the equation is 9 * 0 = 0, which is correct.

Make sure you're picking the correct coordinate out of the answer choices.

The x-coordinates are -6 and 3, and the y-coordinates are 0, because the points lie on the x-axis.

The correct answer is (-6, 0).

(3, 0) is also correct, but the question does not require it.

Answer:

D

Step-by-step explanation:

I need this question today. Pls help

Answers

B why is it B because I did it

[tex]answer \\ = 2 , 4 , 5 \\ additional \: information \\ let \: r \: be \: a \: relation \: a \: to \: b. \: then \: the \: set \\ of \: first \: components \: or \: the \: set \: of \: \\ elements \: of \: a \: are \: called \: domain \\ and \: the \: set \: of \: second \: components \\ or \: the \: set \: of \: elements \: of \: b \: are \: called \: the \: range. \\ hope \: it \: helps[/tex]

solve for x

x/9=3

whats x

Answers

Answer:

x = 27

Step-by-step explanation:

x/9 = 3

Multiply each side by 9

x/9 * 9 = 3*9

x = 27

Answer:

27

Step-by-step explanation:

x/9= 3

Carry over the 9 and make x the subject.

x= 3*9

x= 27

Therefore x is 27.

To check if the answer is correct, replace the x with the value of what it is in brackets. The value of x is 27.

(27)/9= 3

= 27/9

= 3

We got back the 3 so that means the answer is correct

What is true about this system of equations {2x-y=5 , x=4

Answers

Answer: The systems of equations have only one solution because if x 4 then y is equal to 3 which  proves it that is a one solution graph.

Step-by-step explanation:

2(4)- y = 5

8 - y= 5

-8      -8

-1y= -3

y= 3

You have 10 shirts 2 of them are black what is the probability of not choosing a black shirt.

Answers

80% or 4/5
Since there are 2 blacks shirts and 10 in total the probability is of not poking a black shirt is 8/10 which when reduced is 4/5

Answer:

80% or 4/5

Step-by-step explanation:

the probability of not choosing a black shirt

P = number of shirts that are not black ÷ total number of shirts

Total number of shirts = 10

Number of black shirts = 2

Number of shirts that are not black = 10-2 = 8

P = 8/10 = 4/5 or 80%

The amount of coffee that people drink per day is normally distributed with a mean of 17 ounces and a standard deviation of 4 ounces. 15 randomly selected people are surveyed. Round all answers to 4 decimal places where possible.
a) What is the distribution of XX? XX ~ N(,)
b) What is the distribution of ¯xx¯? ¯xx¯ ~ N(,)
c) What is the probability that one randomly selected person drinks between 15.5 and 18 ounces of coffee per day?
d) For the 15 people, find the probability that the average coffee consumption is between 15.5 and 18 ounces of coffee per day.
e) For part d), is the assumption that the distribution is normal necessary? YesNo
f) Find the IQR for the average of 15 coffee drinkers.
Q1 = ounces
Q3 = ounces
IQR: ounces

Answers

Answer:

Step-by-step explanation:

(a)

The distribution of X is Normal Distribution with mean [tex]= \mu =17[/tex] and Variance [tex]= \sigma^{2} = 16 \ i.e., X \sim N (17, 16),[/tex]

(b)

The distribution of [tex]\bar{x}[/tex] is Normal Distribution with mean [tex]= \mu =17[/tex] and Variance = [tex]\sigma^{2}/n = 16/15= 1.0667[/tex].i.e., [tex]\bar{x}\sim N(17,1.0667)[/tex]

c)

To find P(15.5 < X < 18):

Case 1: For X from 15.5 to mid value:

Z = (15.5 - 17)/4 = - 0.375

Table of Area Under Standard Normal Curve gives area = 0.1480

Case 2: For X from mid value to 18:

Z = (18 - 17)/4 = 0.25

Table of Area Under Standard Normal Curve gives area = 0.0987

So,

P(15.5 < X< 18) = 0.1480 +0.0987 = 0.2467

So,

Answer is:

0.2467

(d)

[tex]SE = \sigma/\sqrt{n}\\\\= 4/\sqrt{15}[/tex]

= 1.0328

To find [tex]P(15.5 < \bar{x}< 18):[/tex]

Case 1: For [tex]\bar{x}[/tex] from 15.5 to mid value:

Z = (15.5 - 17)/1.0328 = - 1.4524

Table of Area Under Standard Normal Curve gives area = 0.4265

Case 2: For X from mid value to 18:

Z = (18 - 17)/1.0328 = 0.9682

Table of Area Under Standard Normal Curve gives area = 0.3340

So,

[tex]P(15.5 < \bar{x}< 18) = 0.4265 + 0.3340 = 0.7605[/tex]

So,

Answer is:

0.7605

(e)

Correct option:

No

because Population SD is provided.

(f)

(i)

Q1 is given by:

[tex]- 0.6745 = (\bar{x} - 17)/1.0328[/tex]

So,

X = 17 - (0.6745 * 1.0328) = 17 - 0.6966 = 16.3034

So,

Q1 = 16.3034

(ii)

Q3 is given by:

[tex]0.6745 = (\bar{x} - 17)/1.0328[/tex]

So,

X = 17 + (0.6745 * 1.0328) = 17 + 0.6966 = 17.6966

So,

Q3= 17.6966

(iii)

IQR = Q3 - Q1 = 17.6966 - 16.3034 = 1.3932

So

Answers are:

Q1 = 16.3034 ounces

Q3 = 17.6966 Ounces

IQR = 1.3932 Ounces

A local store developed a multiplicative time-series model to forecast its revenues in future quarters, using quarterly data on its revenues during the 5-year period from 2008 to 2012. The following is the resulting regression equation: log10 = 6.102 + 0.012 X - 0.129 Q1 - 0.054 Q2 + 0.098 Q3 where is the estimated number of contracts in a quarter X is the coded quarterly value with X = 0 in the first quarter of 2008 Q1 is a dummy variable equal to 1 in the first quarter of a year and 0 otherwise Q2 is a dummy variable equal to 1 in the second quarter of a year and 0 otherwise Q3 is a dummy variable equal to 1 in the third quarter of a year and 0 otherwise To obtain a fitted value for the fourth quarter of 2009 using the model, which of the following sets of values should be used in the regression equation?1. In testing the significance of the coefficient of X in the regression equation (0.012) which has a p-value of 0.02. Which of the following is the best interpretation of this result? a. The quarterly growth rate in revenues is significantly different from 0%. b. The quarterly growth rate in revenues is not significantly different from 0%. c. The quarterly growth rate in revenues is significantly different from 1.2%. d. The quarterly growth rate in revenues is not significantly different from 1.2%. e. The quarterly growth rate in revenues is significantly different from 1.2% 2. using the regression equation, the forecast for the revenues in the fourth quarter of 2004 is:______ a. 6,426 b. 2,666,858 c. 6,638 d. 2,741,574 e. 6,414

Answers

Answer:

The quarterly growth rate in revenues is significantly different from 1.2%.

b. 2,666,858

Step-by-step explanation:

Given that:

The regression equation can be represented as :

[tex]log_{10} \hat Y= 6.102+0.012 X - 0.129 Q_1 - 0.054 Q_2 + 0.098 Q_3[/tex]

In testing the significance of the coefficient of X in the regression equation (0.012) which has a p-value of 0.02.

The null and alternative hypothesis can be stated as;

[tex]H_0:[/tex]    The quarterly growth rate in revenues is not significantly different from 1.2%.

[tex]H_a:[/tex]   The quarterly growth rate in revenues is significantly different from 1.2%.

The decision rule is to reject the null hypothesis if the p-value is less than 0.05.

From above ; the p-value = 0.02 which is less than 0.05.

Conclusion:

Thus; we reject the null hypothesis and accept the alternative hypothesis. i.e

The quarterly growth rate in revenues is significantly different from 1.2%.

b.

Since [tex]Q_1=Q_2=Q_3 = 0[/tex] ; X = 27

Thus ;

[tex]log_{10} \hat Y= 6.102+0.012 X - 0.129 Q_1 - 0.054 Q_2 + 0.098 Q_3[/tex]

[tex]log_{10} \hat Y= 6.102+0.012 (27)[/tex]

[tex]\hat Y=10^{ 6.102+0.012 (27) }[/tex]

[tex]\hat Y =[/tex] 2666858.665

[tex]\hat Y =[/tex]  2,666,858



Are You Ready for More?: Two raised to the 12th power is equal to 4,096. How many other

whole numbers can you raise to a power and get 4,096? Explain or show your reasoning.

(1 Point)

2^12 = 4096

Answers

Answer:

4, 8, 16,64 and 4096.

Step-by-step explanation:

We are already given: [tex]4096=2^{12}[/tex]

To determine other whole numbers that can be raised to a power to obtain 4096, we apply the product rule of indices.

Product Rule of Indices: [tex]a^{xy}=(a^x)^y[/tex]

Now 12 can be factored in the following ways where one of the terms must be a perfect square:

12=2 X 612 =6 X 212 =3 X 412 =4 X 312=1 X 12

[tex]2^{12}=(2^2)^6=4^6\\\\2^{12}=(2^6)^2=64^2\\\\2^{12}=(2^4)^3=16^3\\\\2^{12}=(2^3)^4=(8^2)^2=8^{2*2}=8^4\\\\2^{12}=(2^{12})^1=4096^1 $(This is the trivial case)[/tex]

Therefore, the other whole numbers that can be raised tp a power to obtain 4096 are: 4, 8, 16, 64 and 4096.

What is a word problem for 15-28?

Answers

Answer:

valarie had 28 pencils , she gave 15 pencils away to people. How many pencils will she have left?

Step-by-step explanation:

hope this helps:)

Please help ASAP thank you

Answers

Answer:

q

Step-by-step explanation:

Since AB is a transversal of the two parallel lines, the angle with measure 135 degrees and angle q are vertical angles. Therefore, their measure must be equal.

Hope this helps!

Rectangle WXYZ was dilated to create W'X'Y'Z'. Point G is the center of dilation. Rectangle W X Y Z was dilated to create smaller rectangle W prime X prime Y prime Z prime. The length of G Z prime is 1.5. The length of Z prime Z is 7.5. Side W X is 3 units and side X Y is 6 units. What is W'X'? 0.5 units 1.2 units 1.5 units 1.8 units

Answers

Answer:

  0.5 units

Step-by-step explanation:

The dilation factor is ...

  (GZ')/(GZ) = (GZ')/(GZ' +Z'Z) = 1.5/(1.5 +7.5) = 1/6

Side WX is 3 units, so side W'X' is (1/6)(3 units) = 1/2 units

W'X' is 0.5 units.

Answer:

It is .5 on edge

Step-by-step explanation:

I took the test

Can anyone help???????

Answers

Answer:

80

Step-by-step explanation:

For every additional 10 hrs, you get 200 more dollars.

Use any method to multiply (-14ab)(a + 3b - 4c).

Answers

Answer:

-14a^2b-42ab^2+56abc

Step-by-step explanation:

You can use the FOIL method

multiply the first numbers

then inner

then outer

then last

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