Answer:
Honestly, you should have a firm resolve not to go into drug peddling.
Politely tell him you are not interested in the business, that you are most concerned about your future and the career path you have chosen for yourself already.
He will definitely feel bad, but you can go on to advise him.
You can also advise him to stop and highlight the dangers of doing drugs.
Explanation:
There are a whole lot of disadvantages involved in the drug business,
in fact, the disadvantages out weights the advantages in the long run.
say if one is caught and sent to a life long sentence, or if one is caught up with the effect of the use of hard drugs and the health implication, to the extent that one looses his/her sanity, you see it won't make any sense anymore doing drugs in the long run. so friend you can advise you cousin to stop and thinker of good businesses that cold fetch him cool money, without the law chasing him, with that he can be a contributor to economic growth by paying his taxes too
Experiments need to be repeated by the scientist and also replicated by other scientists.
true
false
Answer:
false
Explanation: because the other scientists could've missed something in there experiment
Which of the following is a scientific law?
A. No one is allowed to operate a motor vehicle unless that person is over the age of 16 and passes a driving exam.
B. For a gas in a closed container at a constant temperature, the product of the pressure and the volume remains constant.
C. No one is allowed to take the property of anyone else without their permission.
D. All cars must stop at red lights and move through an intersection when the light is green.
Answer:
B. For a gas in a closed container at a constant temperature, the product of the pressure and the volume remains constant.
Explanation:
The rest are societal laws, as they are telling you something you should avoid or follow.
Hope this helps :)
Newton
10. Your mass on Earth is 50kg. Planet Xenon has half the gravitational force of Earth. What
are your weight and mass on Planet Xenon?
Given parameters:
Mass on earth = 50kg
Unknown:
Mass on planet Xenon = ?
Weight on planet Xenon = ?
Mass is the amount of matter contained in a particular substance.
Weight is the force on a body and it is derived from the product of mass and acceleration due to gravity.
Weight = mass x acceleration due to gravity
Planet Xenon has half the gravitational force of Earth.
This translated gives [tex]\frac{9.8}{2}[/tex] = 4.9m/s²
Now, mass is always the same every where if the amount of matter in a substance does not change.
In this problem, mass = 50kg on planet xenon.
Weight = mass x acceleration due to gravity = 50 x 4.9 = 245N
The weight on Xenon is 245N and the mass is 50kg
A hiker starts at point P and walks 2.0 km due east and then walks at an angle of 30 degrees north of east for 1.4 km.
Use the Pythagorean theorem to determine the resultant of the 2 vectors. This is the magnitude of the hiker’s displacement.
Answer:
The magnitude of the hiker’s displacement is 2.96 km
Explanation:
Let the initial displacement of the hiker, = x = 2km
the final displacement of the hiker, = y = 1.4 km
The resultant of the two vectors, According to Pythagorean theorem is the vector sum of the two vectors.
R' = x' + y'
Check the image uploaded for solution;
An airplane travels directly from Washington, D.C., to Atlanta, Georgia, a distance of 850 km at a velocity of 425 km/h southwest
How long does the trip take in hours?
1.0 h
2.0 h
0.5 h
4.0 h
Answer:
obviously 2 hours cuz 850/425
Explanation:
What is the magnitude of the momentum of a 11kg object moving at 2.2 m/s?
Answer:
The answer is 24.2 kgm/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocityFrom the question
mass = 11 kg
velocity = 2.2 m/s
We have
momentum = 11 × 2.2
We have the final answer as
24.2 kgm/sHope this helps you
what is the net force?
URGENT! thank you
A torch is dropped down a large chasm. It takes 10 seconds to hit the ground. How deep is the chasm?
490m
49m
98m
980m
Answer: 490m
Explanation: 1/2 * 9.8m/s/s * 10s
7. An auto's velocity increases uniformly from 3m/s to 25m/s while
covering 90m. Calculate the acceleration. *
Answer:
3.422 m/s^2
Explanation:
A useful relation is ...
v2^2 -v1^2 = 2ad
(25 m/s)^2 -(3 m/s)^2 = 2a(90 m)
(616 m^2/s^2)/(180 m) = a ≈ 3.422 m/s^2
The acceleration is about 3.422 m/s^2.
PLEASE HELP!! Salmon often jump waterfalls to reach their
breeding grounds.
Starting downstream, 3.41 m away from a
waterfall 0.397 m in height, at what minimum
speed must a salmon jumping at an angle of
28.4° leave the water to continue upstream?
The acceleration due to gravity is 9.81 m/s2
Answer in units of m/s.
Answer:
7.13781 m/s
Explanation:
X-direction | Y-direction
[tex]x=v_{xo}t+\frac{1}{2}a_{x}t^2[/tex] | [tex]y=v_{yo}t+\frac{1}{2}a_{y}t^2[/tex]
[tex]3.41=v_{o}cos(28.4)t[/tex] | [tex]0.397=v_{yo}sin(28.4)t+\frac{1}{2} (-9.81)t^2[/tex]
[tex]3.41=v_{o}(0.87964)t[/tex] | [tex]0.397=v_{yo}sin(28.4)(\frac{3.87658}{v_{o} })+\frac{1}{2} (-9.81)(\frac{3.87658}{v_{o} })^2[/tex]
[tex]\frac{3.41}{0.87964}=v_{o}t[/tex] | [tex]0.397=1.84379-\frac{73.71171}{v^2}[/tex]
[tex]\frac{3.87658}{v_{o} } =t[/tex] | [tex]7.13781=v[/tex]
3 Points
The half-value layer for lead for g rays from 60Co is 12.8 mm. An electrometer gave a count rate of 35 pulses per second when at a
certain distance from a source, with no lead between source and detector. If 6 mm of lead were then inserted between source and
detector, the count rate (in pulses per second) would be nearest to:
A. 16
OB. 8
OC. 20
D. 25
OE. 75
Answer:
D. 25
Explanation:
The number of pulses per second (p) for x mm of lead can be modeled by the exponential equation ...
p = 35(0.5^(x/12.8))
Then for x=6, the value of p is ...
p = 35·0.5^(6/12.8) ≈ 25.29
The expected count rate would be nearest 25 pps.
I
An arrow fired horizontally at 41 m/s travels 23 m horizontally before it hits
the ground. From what height was it fired?
Answer:
Height = 1.54 m
Explanation:
Given:
Velocity = 41 m/s
Distance = 23 m
Find:
Height
Computation:
We know that
a = 9.8 m/s²
Time = Distance / Velocity
Time = 23 / 41
Time = 0.56 second
Height = (1/2)(9.8)(0.56)²
Height = 1.54 m
A net force of 20 N acting on a wooden block produces an
acceleration of 4.0 m/s2 for the block. What is the mass of
the block?
Answer:
From the second law of motion:
F = ma
we are given that the force applied on the block is 20N and the block accelerates at an acceleration of 4 m/s/s
So, F= 20N and a = 4 m/s/s
Replacing the variables in the equation:
20 = 4* m
m = 20 / 4
m = 5 kg
Three vectors, one of 74 km at 30°, the second of 54 km at 135°, and the final of 62 km due South. What is the sum of the three vectors?
- will give brainliest -
Answer:
The sum of the three vectors are 63.18 km.
Explanation:
Given that,
One vector = 74 km at 30°
Second vector = 54 km at 135°
Third vector = 62 km
We need to calculate the sum of the three vectors
Using given data
[tex]R=\vec{A}\sin\theta+\vec{B}\sin\theta+\vec{C}[/tex]
Put the value into the formula
[tex]R=-74\sin30+54\sin135+62[/tex]
[tex]R=63.18\ km[/tex]
Hence, The sum of the three vectors are 63.18 km.
An object starts from rest and accelerates at a rate of 4 m/s2 for 3 seconds. What is it's displacement from the start position?
Answer:
36m
Explanation:
a = 4 m/s^2
u = 0 ( it's starting from rest )
t = 3
a=v-u/t ....... 4=(v-0)/3, v = 12m/s
Using s=d/t,
12=d/3,
d= 36m
If an object starts from rest and accelerates at a rate of 4 m/s2 for 3 seconds, then its displacement from the start position would be 44.1 meters.
What are the three equations of motion?There are three equations of motion given by Newton
v = u + at
S = ut + 1/2 × a × t²
v² - u² = 2 × a × s
As given in the problem If an object starts from rest and accelerates at a rate of 4 m/s² for 3 seconds,
S = ut + 1/2 × a × t²
S = 0 + 0.5 × 9.8 × 3²
S = 44.1 meters
Thus, If an object starts from rest and accelerates at a rate of 4 m/s2 for 3 seconds, then its displacement from the start position would be 44.1 meters.,
To learn more about equations of motion here, refer to the link given below ;
brainly.com/question/5955789
#SPJ2
D.
(S. 15
10. The average velocity of a car is 54km/h. What is
the distance covered if the time taken is 10s
A. 200m B. 150m C. 100m D. 50m E.
Answer:
Option B 150 Metre
Hope this helps youAnswer:
B. 150 m
Explanation:
In order to answer the question, it is important to know the formula for "velocity."
velocity = [tex]\frac{distance}{time}[/tex]
What is being asked? The distance covered if the time taken is 10 sec.
So this means: velocity x time = distance
Step 1: Convert 10 sec. to hour.
10 sec. x [tex]\frac{1 hour}{3,600 sec.}[/tex] = 0.00278 hr.
Step 2: Plug in the values to the formula.
distance = 54 [tex]\frac{km}{hr}[/tex] x 0.00278 hr.
distance = 0.150 km
Step 3: The choices are in meters (m), so let's convert 0.150 km to meter.
0.150 km x [tex]\frac{1,000 m}{1 km}[/tex] = 150 meters
The answer is: 150 m
Layer with partially melted material that can flow easily is
Answer:
the mantle.
Explanation:
The mantle is the mostly-solid bulk of Earth's interior. The mantle lies between Earth's dense, super-heated core and its thin outer layer, the crust. It's practically hot lava (Magma) Flowing and causing earthquakes and what not.
Hope this helps :)
What magnification is best for the observation of most tissue slides? Explain why this has proved to be true?
Answer:
The 10X objective is use for the identification of actual size of histology tissues and 4X magnification is best for observation of most tissues slides
Explanation:
4X magnification is best for observation of most tissues slides because it has an objective lens that have lower power and have great high field overview which make it very easier to locate specimens on the slide. It is use to get the overview of histology slides. It is use to showcase more detailed observations about histology.
The 40X objective is use majorly to identify tissue , to observe the finer details and study tissue organization on the histology slide.
The equation for water is H2 +O2 - H2O. To balance the equation, which coefficient should be placed in front of H2 and H2O?
1
2
3
4
Answer:
Question: The equation for water is H2 +O2 → H2O. To balance the equation, which coefficient should be placed in front of H2 and H2O?
Answer: B.)2
Explanation:
The coefficient that would need to be placed in front of the H2, to balance the equation would be 2. After doing this all of the atoms for their respective elements will be balanced.
To balance the equation, coefficient 2 should be placed in front of H2 and H2O.
BALANCING EQUATION:
A chemical equation is said to be balanced if the number of atoms of each element on both sides of the equation are the same. According to this question, an equation that combines hydrogen and oxygen gases to form water was given as follows:H2 + O2 → H2OTo balance the above equation, we make use of coefficient 2 to ensure that the number of atoms (4) of hydrogen are the same on both sides. The balanced equation is as follows:2H2 + O2 → 2H2OLearn more at: https://brainly.com/question/21049751?referrer=searchResults
which theory says dreaming is an unimportant by-product of neural firing during sleep
Answer:activation-synthesis
Explanation:
What is the difference between a rule and a law?
a car with a mass of 100 kg is stopped on the side of the road after getting a flat tire. the two people that were riding in the car get out and begin to push the car from rest to a nearby gas station. The car travels 50 meters in 40 seconds. Determine the speed of the car in these 40 seconds.
Answer:
Please mark me brainliest and thank me and rate me
Researchers have measured the acceleration of racing greyhounds as a function of their speed; a simplified version of their results is shown in (Figure 1). The acceleration at low speeds is constant and is limited by the fact that any greater acceleration would result in the dog pitching forward because of the force acting on its hind legs during its power stroke. At higher speeds, the dog's acceleration is limited by the maximum power its muscles can provide.
How far does the dog run until its speed reaches 4.0 m/s?
[tex]\Huge\boxed{\boxed{\dfrac{4}{5}\ \text{meters}}}[/tex]
Let's start by finding the time it takes for the dog to reach a velocity of [tex]4[/tex] m/s.
We can use the following equation, where [tex]v_i[/tex] is initial velocity, [tex]v_f[/tex] is final velocity, [tex]t[/tex] is time, and [tex]a[/tex] is acceleration.
[tex]v_f-v_i=at[/tex]
We're trying to solve for [tex]t[/tex] first, so divide both sides by [tex]a[/tex].
[tex]\dfrac{v_f-v_i}{a}=t[/tex]
Substitute in the known values.
[tex]\dfrac{4-0}{10}=t[/tex]
[tex]\dfrac{4}{10}=t[/tex]
[tex]\dfrac{2}{5}=t[/tex]
Now, we can use the following formula to find the distance.
[tex]s=v_it+\dfrac{1}{2}at^2[/tex]
Substitute in the known values.
[tex]s=0*\dfrac{2}{5}+\dfrac{1}{2}*10*(\frac{2}{5})^2[/tex]
Anything multiplied by [tex]0[/tex] is
[tex]s=\dfrac{1}{2}*10*(\frac{2}{5})^2[/tex]
Just simplify from there.
[tex]s=\dfrac{1}{2}*10*\dfrac{4}{25}[/tex]
[tex]s=5*\dfrac{4}{25}[/tex]
[tex]s=\dfrac{20}{25}[/tex]
[tex]s=\boxed{\dfrac{4}{5}}[/tex]
Hey there!
The hind legs of the dog create it to accelerate.
We know the mass of the dog is 36km (m).
We know that the acceleration of the dog it 10m/s² (a).
Find the average force with the formula [ f = ma ] where m = mass and a = acceleration.
f = 36*10
f = 360 newtons
We don't know the traveled distance but we do know that the starting speed of the dog was 0m/s and the ending speed was 4m/s.
We can use the formula [ vf² = vo² + 2ad ] where vf = final speed, vo = starting speed, a = acceleration, and d = distance.
We know all the variables except the distance, so we are going to solve for d.
(4)² = (0)² + 2(10)(d)
16 = 0 + 20d
16 = 20d
16/20 = 20d/20
0.8 = d
Therefore, the dog runs 0.8 meters until it reaches 4m/s.
Best of Luck!
show that the motion of Bob of simple pendelum is simple harmonic. find it's time period.
Answer:
a) = 11.29°
b) = 1.93 m/s²
Explanation:
θ = θ(m) sin(w(n).t + Φ)
w(n) = 2π / t
w(n) = 6.284 / 1.3
w(n) = 4.834 rad/s
θ• = θ(m).w(n).cos (w(n).t + Φ)
θ•(m) = θ(m).w(n)
v(m) = L.θ•(m)
v(m) = L.θ(m).w(n)
θ(m) = v(m) / L.w(n)
For a simple pendulum,
w(n) = √(g / l)
l = g / w(n)²
l = 9.8 / 4.834²
l = 9.8 / 23.368
l = 0.42 m
Remember, θ(m) = v(m) / l.w(n)
θ(m) = 0.4 / (0.42 * 4.834)
θ(m) = 0.4 / 2.03
θ(m) = 0.197 rad
Converting to °, we have
0.197 * 360 * 1/2π
0.197 rad = 11.29°
Thus, the amplitude of the motion is 11.29°
a(t) = l.θ(t)
Tangential acceleration occurs when θ(t) is maximum, so
θ(t) = -θ(m).w(n)².sin(w(n)t + Φ)
θ(t max) = θ(m).w(n)²
a(t max) = l.θ(m).w(n)²
a(t max) = 0.42 * 0.197 * 4.834²
a(t max) = 1.93 m/s²
Explanation:
wheel and axle is also called a continuous lever
Explanation:
When load is connected to axle and effort is on the wheel it acts as first class lever with in fulcrum in the middle ..So wheel and axle is continuous lever
Determine the beginning and end of the solar maximum or minimum.
Please help will give brainliest
Answer:
5 billion years ago...ends 4.9 billion years later
Answer:
That's correct... you can mark them brainliest now. You have to have both slots answered before you can mark them. So, you're welcome :)
Explanation:
Amass oscillates in simple harmonic motion with amplitude A , if the mas is halved , but the amplitude is not changed , what will happen to the total mechanical energy of the system
A- It will increase
B-it will decrease
c-It will stay at the same
D-None of these
list of energy changes when hydroelectricity city is made
Answer:
A turbine and generator produce the electricity
Explanation:
"A hydraulic turbine converts the energy of flowing water into mechanical energy. A hydroelectric generator converts this mechanical energy into electricity.
1. Three kids in a parking lot launch a rocket that rises
into the air along a 380-m long arc in 40s.
Determine its average speed.
Answer:
Average speed equals distance / time
380 / 40 = 9.5 m/s.
Explanation:
5 13. If a train going 60 m/s hits the brakes, and it takes the train 2 minute 25 seconds to stop, what is the train's acceleration?
Answer:
Acceleration = -12/17 m/s ^2
Explanation:
Name the variables
V = final velocity( velocity after the train stops) u= intial velocity(velocity when the train was moving at constant speed, before brakes are applied)
A = acceleration( in this case, it is deceleration)
T = time ( time taken to fully stop)
Second Step: What equation should we use?
The 3 Big Motion in One Dimension Formulas are:
V = u+at
v^2 = u^2 + 2as
S = ut+ (1/2) at^2
For this question, we will be using the first one.
Third Step: Solve
V = 0 (the final velocity is 0, because the train stopped)
U = 60 (the train was going at 60 mps)
T = 85 seconds( 1 min and 25 sec)
0 = 60+ 85a
