You have decided that the complexity of the corporate network facility and satellite offices warrants the hiring of a dedicated physical security and facilities protection manager. You are preparing to write the job requisition to get this critical function addressed and have solicited some ideas from the PCS working group members regarding physical and environmental security risks. Discuss the operational security functions that the physical security and facilities protection manager would be responsible for. Discuss how these functions would inform the development and implementation of system related incident response plans. Further discuss how these incident response plans fit into business continuity planning. Include at least one research reference and associated in-text citation using APA standards. In yourreplies to your peers further discuss how the concepts improve the security posture of PCS.

Answer:

to keep count of how many users there are in total.

Explanation:

all i had to do was read the question twice to understand the answer is pretty

much in the question.

The director of the computer lab tasks with creating a data warehouse to manage lab utilization data. The major needs for this database are to keep count of how many users there are in total.

The tactical measures used by a corporation to create a financial plan are the budgeting processes. Budgeting for a future time entails more than simply allocating spending; it also entails figuring out how much income is required to achieve organizational objectives.

These procedures are used by accounting departments to regulate corporate activities, particularly expenditure. A person may use budgeting process to record how much money a business makes and spends over a specific time period.

Therefore, With the aid of budgeting, it may establish financial objectives for the team and the entire organization.

Learn more about the budgeting process, refer to:

https://brainly.com/question/21411418

#SPJ2

Answer:

B

Explanation:

all url's begin with https://

Answer:

15 minutes

Explanation:

this meeting is normally timeboxed to a maximum duration of 15 minutes.

Answer:

A.  15 minutes

B.  45 minutes

C.  10 minutes

D.  30 minutes

The Answer is A): 15 minutes

explanation:

PLZ Mark Me As Brainliest

Answer:

Output device

Explanation:

Im pretty sure that correct

Answer:

33600

Explanation:

Let M = ABE16

and N = DF416

In hexadecimal representation: 10 = A, 11 = B, 12 = C, 13 = D, 14 = E, 15 = F

Step 1: Find the 15's complement of N

 F  F  F  F  F

- D  F  4  1  6

2  0  B  E  9

Step 2: Add 15's complement of N to M

  A  B  E  1  6

+ 2  0  B  E  9  

  C  C  9  F  F

Step 3: Find the 15's complement of CC9FF

 F  F   F  F  F

- C  C  9  F  F

 3   3  6  0  0

Therefore, ABE16 - DF416 using 15's complement is 33600

Answer:

Following are the code to this question:

import java.util.*; //importing package for user input

public class Main //defining class

{

public static void main(String []ar) //defining main method

{

double investment_amount,interest_rate,future_investment_value; //defining double variables

int years; //defining integer variable

Scanner obx=new Scanner(System.in); //creating Scanner class Object

System.out.print("Enter invest value: "); //print message

investment_amount=obx.nextDouble(); //input value

System.out.print("Enter interest rate: ");//print message

interest_rate=obx.nextDouble();//input value

System.out.print("Enter number of years: ");//print message

years=obx.nextInt();//input value

future_investment_value=investment_amount*Math.pow((1+interest_rate/1200.),years*12); //calculating value by apply formula

System.out.println("you enter amount: $"+investment_amount); //print calculated value

System.out.println("annual interest rate:"+interest_rate+"%");//print calculated value

System.out.printf("Number of years: "+years+" the future investment value is :$%.2f\n",future_investment_value);//print calculated value

}

}

output:

please find the attachment.

Explanation:

Program Description:

Answer: Provided in the explanation section

Explanation:

The Question says;

Identify a logical operation (along

with a corresponding mask) that, when

applied to an input string of 8 bits,

produces an output string of all 0s if and

only if the input string is 10000001.​

The Answer (Explanation):

XOR, exclusive OR only gives 1 when both the bits are different.

So, if we want to have all 0s, and the for input only 10000001, then we have only one operation which satisfies this condition - XOR 10000001. AND

with 00000000 would also give 0,

but it would give 0 with all the inputs, not just 10000001.

Cheers i hope this helped !!

Answer:

In HTML file

<body style="background-color:orange;">

Or

In CSS file

body {

background-color: orange;

}

Answer:

Explanation:

PROGRAM

main.c

#include <fcntl.h>

#include <stdio.h>

#include <stdlib.h>

#include <sys/stat.h>

#include <sys/types.h>

#include <unistd.h>

#include "myio.h"

int checkInt(char *arg);

int main(int argc, char *argv[]) {

  int doubles, i, ints, lines;

  char newline;

  FILE *out;

  int x, y, z;

  newline = '\n';

  if (argc != 5) {

     printf("Usage is x y z output_filename\n");

     return 0;

  }

  if (checkInt(argv[1]) != 0)

     return 0;

  ints = atoi(argv[1]);

  if (checkInt(argv[2]) != 0)

     return 0;

  doubles = atoi(argv[2]);

  if (checkInt(argv[3]) != 0)

     return 0;

  lines = atoi(argv[3]);

  out = fopen(argv[4], "a");

  if (out == NULL) {

     perror("File could not be opened");

     return 0;

  }

  for (x = 0; x < ints; x++) {

     int n = ReadInteger();

     printf("%d\n", n);

     fprintf(out, "%d\n", n);

  }

  for (y = 0; y < doubles; y++) {

     double d = ReadDouble();

     printf("%lf\n", d);

     fprintf(out, "%lf\n", d);

  }

  for (z = 0; z < lines; z++) {

     char *l = ReadLine();

     printf("%s\n", l);

     fprintf(out, "%s\n", l);

     free(l);

  }

  fclose(out);

  return 0;

}

int checkInt(char *arg) {

  int x;

  x = 0;

  while (arg[x] != '\0') {

     if (arg[x] > '9' || arg[x] < '0') {

        printf("Improper input. x, y, and z must be ints.\n");

        return -1;

     }

     x++;

  }

  return 0;

}

myio.c

#include <limits.h>

#include <stdio.h>

#include <stdlib.h>

#include <unistd.h>

char *ReadInput(int fd) {

  char buf[BUFSIZ];

  int i;

  char *input;

  int r, ret, x;

  i = 1;

  r = 0;

  ret = 1;

  input = calloc(BUFSIZ, sizeof(char));

  while (ret > 0) {

     ret = read(fd, &buf, BUFSIZ);

     for (x = 0; x < BUFSIZ; x++) {

        if (buf[x] == '\n' || buf[x] == EOF) {

           ret = -1;

           break;

        }

        input[x*i] = buf[x];

        r++;

     }

     i++;

     if (ret != -1)

        input = realloc(input, BUFSIZ*i);

  }

  if (r == 0)

     return NULL;

  input[r] = '\0';

  input = realloc(input, r+1);

  return(input);

}

int ReadInteger() {

  char *input;

  int go, num, x;

  go = 0;

  do {

     go = 0;

     printf("Input an integer\n");

     input = ReadInput(STDIN_FILENO);

     for (x = 0; x < INT_MAX; x++) {

        if (x == 0&& input[x] == '-')

           continue;

        if (input[x] == 0)

           break;

        else if (input[x]> '9' || input[x] < '0') {

           go = 1;

           printf("Improper input\n");

           break;

        }

    }

  } while (go == 1);

  num = atoi(input);

  free(input);

  return num;

}

double ReadDouble(void) {

  int dec, exp;

  char *input;

  int go;

  double num;

  int x;

  do {

     go = 0;

     dec = 0;

     exp = 0;

     printf("Input a double\n");

     input = ReadInput(STDIN_FILENO);

     for (x = 0; x < INT_MAX; x++) {

        if (x == 0&& input[x] == '-')

           continue;

        if (input[x] == 0)

           break;

        else if (input[x] == '.' && dec == 0)

           dec = 1;

        else if (x != 0&& (input[x] == 'e' || input[x] == 'E') && exp == 0) {

           dec = 1;

           exp = 1;

        }

        else if (input[x]> '9' || input[x] < '0') {

           go = 1;

           printf("Improper input\n");

           break;

        }

     }

  } while (go == 1);

  num = strtod(input, NULL);

  free(input);

  return num;

}

char *ReadLine(void) {

  printf("Input a line\n");

  return(ReadInput(STDIN_FILENO));

}

char *ReadLineFile(FILE *infile) {

  int fd;

  fd = fileno(infile);

  return(ReadInput(fd));

}

myio.h

#ifndef _myio_h

#define _myio_h

/*

* Function: ReadInteger

* Usage: i = ReadInteger();

* ------------------------

* ReadInteger reads a line of text from standard input and scans

* it as an integer. The integer value is returned. If an

* integer cannot be scanned or if more characters follow the

* number, the user is given a chance to retry.

*/

int ReadInteger(void);

/*

* Function: ReadDouble

* Usage: x = ReadDouble();

* ---------------------

* ReadDouble reads a line of text from standard input and scans

* it as a double. If the number cannot be scanned or if extra

* characters follow after the number ends, the user is given

* a chance to reenter the value.

*/

double ReadDouble(void);

/*

* Function: ReadLine

* Usage: s = ReadLine();

* ---------------------

* ReadLine reads a line of text from standard input and returns

* the line as a string. The newline character that terminates

* the input is not stored as part of the string.

*/

char *ReadLine(void);

/*

* Function: ReadLine

* Usage: s = ReadLine(infile);

* ----------------------------

* ReadLineFile reads a line of text from the input file and

* returns the line as a string. The newline character

* that terminates the input is not stored as part of the

* string. The ReadLine function returns NULL if infile

* is at the end-of-file position. Actually, above ReadLine();

* can simply be implemented as return(ReadLineFile(stdin)); */

char *ReadLineFile(FILE *infile);

Explanation:

1. I grew up in a small community and my family owned a small business which involved manual labor. Although, having little income, my Dad sought to give us the best education he could afford from his little savings. With the small family savings I went to college where I studied Information Technology, after graduating I worked for a startup firm for two years before I decided to proceed with post graduate studies and I attained my Masters in UA. I met a friend who recommended I study in University of Cumberlands, I hesitated initially but was convinced after I researched the institution.

2. I'm particularly interested in the applications of information technology in labor intensive businesses and work because of my family background.

3. I have my own startup firm that designs work communication software for companies, however I intend to broaden my knowledge through this program into Information Technology based systems using machine learning algorithm.

4. I am committed to work and study, as some have called me a curious mind because of my passion towards learning.

5. I view obtaining a doctorate as not just a personal achievement but of lasting benefits to society as I use knowledge derived to improve the work experience of society.

I am confident that after my program I would be one the renowned contributors to the applications of information technology in labor intensive businesses.

Answer:

Please follow the code indentation for the python program.

Explanation:

Answer:

Explanation:

I mean I would copy and paste it. I hope thats right

Answer:

Explanation:

The objective of this question and what we are meant to do is to compute a short program in C++ that will display the information given in the question.

Let get started!.

C ++ Program Code.

#include <iostream>

#include<string>

using namespace std;

int main()

{

string name,email,hometown,highschool,previousColleges,mathOrCSCource,lastMathOrCSCource,CompType,ExtraCur,FavBook

,planAfterGrad,phone;

//Reading Data

cout<<"Name:";

getline(cin,name);

cout<<"Phone:";

getline(cin,phone);

cout<<"Email:";

getline(cin,email);

cout<<"HomeTown:";

getline(cin,hometown);

cout<<"High School(s):";

getline(cin,highschool);

cout<<"Previous Colleges:";

getline(cin,previousColleges);

cout<<"List of math/CS Cources:";

getline(cin,mathOrCSCource);

cout<<"When,Where and what was your last math or CS course:";

getline(cin,lastMathOrCSCource);

cout<<"Type(s) of computer you are confident working with:";

getline(cin,CompType);

cout<<"ExtraCurricular Activities (job,club,sports,etc.):";

getline(cin,ExtraCur);

cout<<"Favourite books,movies,music:";

getline(cin,FavBook);

cout<<"What you plan to do after Graduation:";

getline(cin,planAfterGrad);

//Printing data

cout<<"--------------------Printing Data---------------------------"<<endl;

cout<<"Name:"<<name<<endl;

cout<<"Phone:"<<phone<<endl;

cout<<"Email:"<<email<<endl;

cout<<"HomeTown:"<<hometown<<endl;

cout<<"High School(s):"<<highschool<<endl;

cout<<"Previous Colleges:"<<previousColleges<<endl;

cout<<"List of math/CS Cources:"<<mathOrCSCource<<endl;

cout<<"When,Where and what was your last math or CS course:"<<lastMathOrCSCource<<endl;

cout<<"Type(s) of computer you are confident working with:"<<CompType<<endl;

cout<<"ExtraCurricular Activities (job,club,sports,etc.):"<<ExtraCur<<endl;

cout<<"Favourite books,movies,music:"<<FavBook<<endl;

cout<<"What you plan to do after Graduation:"<<planAfterGrad<<endl;

return 0;

}

Answer:

When you sign into a website, you have to enter a password and username most of the time, which will allow the website to know that you have checked in and it is you, who is using your account.

Answer:

(a)The CPU B should be  selected for the new computer as it has a low clock cycle time which implies that it will implement the process or quicker when compared to the CPU A.

(b) The CPU B is faster because it executes the same number of instruction in a lesser time than the CPU A .

Explanation:

Solution

(a)With regards to  the MIPS performance metric the CPU B should be chosen for the new computer as it low clock cycle time which implies that it will implement the process or quicker when compared to the CPU A and when we look at the amount of process done by the system , the CPU B is faster when compared to other CPU and carries out same number of instruction in time.

The metric of response time for CPU B is lower than the CPU A and it has advantage over the other CPU and it has better amount as compared to CPU A, as CPU B is carrying out more execution is particular amount of time.

(b) The execution can be computed as follows:

Clock cycles taken for a program to finish * increased by the clock cycle time = the Clock cycles for a program * Clock cycle time

Thus

CPU A= 5*10^6 * 60*10^-9 →300*10^-3 →0.3 second (1 nano seconds =10^-9 second)

CPU B= 3 *10^6 * 75*10^-9 → 225*10^-3 → 0.225 second

Therefore,The CPU B is faster as it is executing the same number of instruction in a lesser time than the CPU A

Answer:

yooooooooooooooooooooo

Explanation:

Answer:

Insertion query for first row :

INSERT into Invoice_Line_Items (invoice_sequence, account_number, line_item_amount, line_item_description) Values (1, 160, '$180.23', "Hard drive Exchange");

Insertion query for second row :

INSERT into Invoice_Line_Items (invoice_sequence, account_number, line_item_amount, line_item_description) Values (2, 527, '$254.35', "Server update");

Explanation:

* In SQL for insertion query, we use INSERT keyword which comes under DML (Data manipulation Language).

* Statement is given below -

INSERT into Table_name  (column1, column2, ....column N) Values (value1, value2, .....value N);

* With the use of INSERT query we can insert value in multiple rows at a same time in a table which reduces our work load.

Answer:

There are a total of 8 page faults.

Explanation:

In FIFO page replacement, the requests are executed as they are received. The solution is provided in the attached figure. The steps are as follows

Look for the digit in the pages. if they are available, there is no page fault. If the digit does not exist in the page frames it will result in an error.

Answer:

Explanation:

I have written the Python program based on your requirements.

Just give the path of the input file and the path for the output file correctly where you want to place the output file.

In, my code - I have given my computer's path to the input and output file.

You just change the path correctly

My code works perfectly and I have tested the code with your inputs.

It gives the exact output that you need.

I have attached the Output that I got by running the below program.

Code:

month_list={ "january":"1","february":"2", "march":"3","april":"4", "may":"5", "june":"6","july":"7", "august":"8", "september":"9","october":"10", "november":"11", "december":"12"} input_file=open('C:\\Users\\Desktop\\inputDates.txt', 'r') output_file=open('C:\\Users\\Desktop\\parsedDates.txt','w') for each in input_file: if each!="-1": lis=each.split() if len (lis) >=3: month=lis [0] day=lis[1] year=lis [2] if month.lower() in month_list: comma=day[-1] if comma==',': day=day[:len (day)-1] month_number=month_list[month.lower()] ans-month_number+"/"+day+"/"+year output_file.write (ans) output_file.write("\n") output_file.close() input_file.close()

- O X parsedDates - Notepad File Edit Format View Help 3/1/1990 12/13/2003

- X inputDates - Notepad File Edit Format View Help March 1, 1990 April 2 1995 7/15/20 December 13, 2003 -1

cheers i hope this helped !!

In this exercise we have to use the knowledge in computer language to write a code in python, like this:

the code can be found in the attached image

to make it simpler we have that the code will be given by:

month_list ={"january": "1", "february": "2", "march": "3", "april": "4", "may": "5", "june": "6", "july": "7", "august": "8", "september": "9", "october": "10", "november": "11", "december":"12"}

input_file = open ('C:\\Users\\Desktop\\inputDates.txt', 'r') output_file =

open ('C:\\Users\\Desktop\\parsedDates.txt', 'w') for each

in input_file:if each

 !="-1":lis = each.split ()if len

   (lis) >= 3:month = lis[0] day = lis[1] year = lis[2] if month

    .lower ()in month_list:comma = day[-1] if comma

    == ',': day = day[:len (day) - 1] month_number =

 month_list[month.lower ()]ans - month_number + "/" + day + "/" +

 year output_file.write (ans) output_file.write ("\n") output_file.

 close ()input_file.close ()

See more about python at brainly.com/question/26104476

Answer: Provided in the explanation section

Explanation:

import java.util.Scanner;

public class commission

{

   public static void main(String[] args) {

      Scanner input = new Scanner(System.in);

        int totals[]={0,0,0,0,0,0,0,0,0};          

      int n,sales,i,index;

       double salary;

        System.out.print("how many salesmen do you have? ");                          

      n=input.nextInt();

        for(i=1;i<=n;i++)

           {System.out.print("Salesman "+i+" enter sales: ");

            sales=input.nextInt();

            salary=200+(int)(.09*sales);

               System.out.printf("Salary=$%.2f\n",salary);

            index=(int)salary/100-2;

            if(index>8)

                index=8;

            totals[index]++;

            }

        System.out.println("SUMMARY\nSALES\t\tCOUNT");

        for(i=0;i<8;i++)

           System.out.println("$"+(i*100+200)+"-"+(i*100+299)+"\t"+totals[i]);

        System.out.println("$1000 and over\t"+totals[i]);

       }                                

   }

cheers i  hope this helped !!      

Answer:

The following assumption will be made for this assignment;

The program is written in Java and it uses comments to explain difficult lines. The program is as follows

import java.util.*;

public class Tests

{

public static void main(String [] args)

{

 //Declare variables

 Scanner input = new Scanner(System.in);

 String firstname, lastname;

 //Prompt user for name

 System.out.print("Enter Lastname: ");

 lastname = input.next();

 System.out.print("Enter Firstname: ");

 firstname = input.next();

 char grade;

 //Declare Array

 int[] Scores = new int[5];

 //Initialize total scores to 0

 int total = 0;  

  //Decalare Average

  double   average;

 //Prompt user for scores

 for(int i =0;i<5;i++)

 {

  System.out.print("Enter Score "+(i+1)+": ");

  Scores[i] = input.nextInt();

  //Calculate Total Scores

  total+=Scores[i];

 }

 //Calculate Average

 average = total/5.0;

 //Get Letter Grade

 if(average>75)

 {

 grade = 'A';

 }

 else if(average>65)

 {

 grade = 'B';

 }

 else if(average>55)

 {

 grade = 'C';

 }

 else if(average>45)

 {

 grade = 'D';

 }

 else if(average>40)

 {

 grade = 'E';

 }

 else

 {

 grade = 'F';

 }

 //Print Student Results

 System.out.print("Fullname: "+lastname+", "+firstname);

 System.out.print('\n');

 System.out.print("Total Scores: "+total);

 System.out.print('\n');

 System.out.print("Average Scores: "+average);

 System.out.print('\n');

 System.out.print("Grade: "+grade);

}

}

See Attachment for .java file

Answer:

a) tie the exception condition to a processing step

Explanation:

Numbering exception conditions, in a fully developed use case description is helpful to tie the exception condition to a processing step

The fully developed use case description is useful for the documentation of the context, purpose, description, conditions, and workflow of each use case. Activity diagrams give a graphical image of the use case workflow and serve the purpose of illustrating the alternative paths through a business process.

Answer:

A. 20 30

Explanation:

Given

Linked list: 10, 20, 30, 40, 50, 60

Required

The output of the following code segment

pCur = head->next;

cout << pCur->data << " ";

cout << pCur->next->data << endl;

A linked list operates by the use of nodes which begins from the head to the next node, to the next, till it reaches the last;

The first line of the code segment; "pCur = head->next; " shifts the node from the head to the next node

The head node is the node at index 0 and that is 10;

This means that the focus has been shifted to the next at index 1 and that is 20;

So, pCur = 20

The next line of the code segment; cout << pCur->data << " "; prints pCur and a blank space

i.e. "20 " [Take note of the blank space after 20]

The last line "cout << pCur->next->data << endl; " contains two instructions which are

1. pCur = next->data;

2. cout<<pCur->data;

(1) shifts focus to the next node after 20 ; This gives pCur = 30

(2) prints the value of pCur

Hence, the output of the code segment is 20 30

Answer:

Given

The above lines of code

Required

Rearrange.

The code is re-arrange d as follows;.

#include<iostream>

int main()

{

int userNum;

scanf("%d", &userNum);

if (userNum > 0)

{

printf("Positive.\n");

}

else

{

printf("Non-positive, converting to 1.\n");

userNum = 1;

printf("Final: %d\n", userNum);

}

return 0;

}

When rearranging lines of codes. one has to be mindful of the programming language, the syntax of the language and control structures in the code;

One should take note of the variable declarations and usage

See attachment for .cpp file

Answer:

a. social engineering attack

Explanation:

Two-factor authentication requires that the user/owner of the account enter a second verification code alongside their password in order to access the account. This code is usually sent to a personal phone number or email address. Therefore in order to breach such a security measure the best options is a social engineering attack. These are attacks that are accomplished through human interactions, using psychological manipulation in order to trick the victim into making a mistake or giving away that private information such as the verification code or access to the private email.

Answer:

Video or Teleconferencing.

Explanation:

Solution

The method in which you will inform the IT director about this opportunity is through video conferencing or tele conferencing.

Video conferencing : refers to a method whereby it enables people at two or more locations or places to hear and see each other simultaneously through computers and communication technology.

what is exchanged between them are information such as visual web cameras and online streaming videos.

Teleconferencing: It is a method of sharing or discussion information and news among a large group of people or team at different places at the same time.

Answer:

Following are the algorithm to this question:

Find_Heavier_Coins(Coin[9]):

   i) Let Coin[] Array represent all Coins.  

   ii) Divide coin[] into 3 parallel bundles and each has three coins, example 0-2, 3-5, 6-8 indicate a1 a2 a3

   iii) Randomly select any two bundles and place them in balance [say a1 and a2]

   iv) If Weigh of a1 and a2 has same:

           // checking that if a3 has heavier coin

           Choose any two 6-8 coins and place them onto balance [say 6 and 8]

           If those who weigh has the same weight:

               Third coin is coin heavier [say 7]

           else:  

               The coin [6 or 8] is the one which is heavier on the balance

       else:

           //The coin has the package which would be heavier on the balance [say a1]

           Select any two coins on balance from of the heavier package [say 0 and 1]

   If they weigh the same weight:

       Third coin is coin heavier [say 2]

   else:

       The coin that is heavier on the balance is the [or 0]

Explanation:

In the above-given algorithm code, a method Find_Heavier_Coins is declared which passes a coin[] array variable in its parameters. In the next step, if conditional block is used that checks the values which can be described as follows: