Write the number one and three quarter million in figures.

Answers

Answer 1

Answer 1750000

Step-by-step explanation:

Answer 2

The number "one and three-quarter million" can be written in figures as 1,750,000.

Given the number one and three quarter million.

"One" represents the digit 1.

"Three-quarter" means three-fourths or 3/4.

In decimal form, this fraction is 0.75.

"Million" signifies a value of 1,000,000.

To represent this number in figures, we combine these components:

We start with the digit 1, representing "one."

Then we append the value 750,000, which corresponds to "three-quarter million."

Combining these two parts, we have 1,750,000.

Therefore, "one and three-quarter million" can be written in figures as 1,750,000.

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Related Questions

Assume that the probability of a driver getting into an accident is 7.1%, the
average cost of an accident is $14,886.05, and the overhead cost for an
insurance company per insured driver is $110. What should the driver's
insurance premium be?
O A. $1276.27
O B. $1242.93
O C. $1165.49
O D. $1156.43

Answers

Answer:

C - $1165.49

Step-by-step explanation:

We have that the probability of a driver getting into an accident = 7.1% i.e. 0.071.

Now, the average cost of an accident = $14,886.05

Then, the expected cost of an accident =  $14,886.05 × 0.071 = $1056.91

As, the overhead cost for insurance = $110

Therefore, the driver's insurance premium = $1056.91 + $110 = $1166.91

Since, the closest option to $1166.91 is option C.

Hence, the driver's insurance premium will be $1165.49.

the driver's insurance premium will then be,

⇒ $1166.91

What is mean by Percentage?

A number or ratio that can be expressed as a fraction of 100 or a relative value indicating hundredth part of any quantity is called percentage.

To Calculate the percent of a number , divide the number by whole number and multiply by 100.

Now, The following can be deduced from the question:

Average cost of an accident = $14,886.05

Probability of a driver getting into an accident = 7.1%

                                                                       = 7.1/100

                                                                       = 0.071.

Overhead cost for insurance = $110

Therefore, the expected cost of an accident will be calculated as:

= Average cost of an accident × Probability of a driver getting into an accident

= $14,886.05 × 0.071

= $1056.91

Therefore, the driver's insurance premium will then be:

= $1056.91 + $110

= $1166.91

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Help, please. I dont really understand

Answers

Answer:

We can eliminate the second and third options because marking something up doesn't result in a number less than the original. Since we are told to select 3 options and there are 3 answer choices left we select the first, fourth, and fifth statements.

8. A biotech company is looking for a user experience researcher to organize and report on some user experience data for a health and wellness app. They need to know the demographics of the users and the average time the app is open for each demographic. In the technical interview, you are asked to describe your approach to the initial analysis. When describing your analysis plan for the request, with what type of statistics would you tell the interviewer you would start your analysis

Answers

Answer:

Descriptive statistics

Step-by-step explanation:

Descriptive statistics describes and summarizes the basic features of a given dataset. It explains features from a collection of information, it is also said to be a form of summary statistics. Here data is characterized using its properties.

In this case, I was asked to describe my approach to the initial analysis. When describing the analysis plan for the request, I would tell the interviewer to start analysis using descriptive statistics.

I need help please HELP ME

Answers

Answer:

-3

Step-by-step explanation:

Because -3x-3=9 and 9+8= 17. 17 is greater than 14

Liam needs a guitar case. It must be 1.18 m long. Select the case that is suitable? 11.8mm,118cm,1.8m ,11.18mm

Answers

Answer:

118 cm

Step-by-step explanation:

1 m = 100 cm

1 m = 1000 mm

1.18 m = 118 cm = 1180 mm

11.8 mm   ----> too small

118 cm   ----> just right

1.8 m    ----> too big

11.18 mm    ----> too small

Where the above dimensions are given, the suitable guitar case for Liam would be the one that is 1.8 m long.

How is this so?

Since Liam's guitar case needs to be 1.18 m long, we need to select the option that is closest in length without exceeding it.

Among the given options, 11.8 mm and 11.18 mm are too small, and 118 cm is equal to 1.18 m, which exceeds the required length.

Hence , the only suitable option is 1.8 m, which matches Liam's requirement of a guitar case with a length of 1.18 m.

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A rhombus is a quadrilateral with four congruent sides. The perimeter of rhombus WXYZ is less than 32 inches. Which inequality can be used to find all possible side lengths, s, for rhombus WXYZ? s squared greater-than 32 s squared less-than 32 4 s less-than 32 4 s greater-than 32

Answers

Answer:

4s< 32

Step-by-step explanation:

Congruent sides mean they are all the same length

Let the length be s

Perimeter means add the sides

s+s+s+s < 32

4s< 32

Answer:

4s>32

Step-by-step explanation:

your welcome dears

A sample of 899 Americans provides enough evidence to conclude that marketing campaign was effective. Provide a statement that should be put out by the marketing department. A. There is not sufficient evidence to conclude that the mean consumption of popcorn has risen. B. There is sufficient evidence to conclude that the mean consumption of popcorn has risen. C. There is sufficient evidence to conclude that the mean consumption of popcorn has stayed the same. D. There is not sufficient evidence to conclude that the mean consumption of popcorn has stayed the same.

Answers

Answer:

The correct answer to the following question will be Option A.

Step-by-step explanation:

Marketing Analyst seems to be responsible for information and evaluation that directs its marketing team and directs its marketing approach by defining the target clients as well as the competitiveness of the product.A survey of 899 American citizens requires appropriate evidence to demonstrate that perhaps the marketing strategy is working even though there was not considerable evidence to suggest that even the total demand for popcorn had increased.

Other given choices are not related to the given circumstances. So that option A seems to be the appropriate choice.

lucy buys 3 liters of apple juice. How many millilitres of apple juice does she buy?

*please help*​

Answers

Answer:

3000 milliliters

Step-by-step explanation:

1liter contains 1000militers

3liters contain (3*1000)militers

Answer:

3000 millilitres

Step-by-step explanation:

since 1 litre = 1000 millimetres

3 litres will be equal to 1000 x 3 = 3000 ml

Find the product. (4p – 6)(4p + 6) a. 16p2 + 36 b. 16p2 – 36 c. 16p2 – 48p – 36 d. 16p2 + 48p + 36

Answers

Answer:

Brainleist to me!

Step-by-step explanation:

(4p – 6)(4p + 6) =

B)  16 p^2  - 36

just use a online calculator

Answer:

16p²-36

Step-by-step explanation:

1(4p-6)(4p+6)

as we know that (a+b)(a-b)=a²-b²

=(4p)²-(6)²

=16p²-36

What is the quotient 5^-6 over 5^3

Answers

Answer:

1/ 5^9

Step-by-step explanation:

5^-6/5^3

5^(-6-3)

5^-9

Final Answer - 1/5^9

If f(x)=4arctan(7x), find f'(x). Find f'(4).

Answers

f'(x) = (4 arctan(7x))'

f'(x) = 4 (arctan(7x))'

By the chain rule,

f'(x) = 4/(1 + (7x)^2) * (7x)'

f'(x) = 28/(1 + 49x^2)

and hence

f'(4) = 28/(1 + 49*16) = 28/785

In case you're not sure about the derivative of arctan: If y = arctan(x), then x = tan(y). Differentiating both sides with respect to x gives

1 = sec^2y y' = (1 + tan^2y) y' = (1 + x^2) y'

==>  y' = 1/(1 + x^2)

Which of the following sequences is arithmetic? A 3, 9, 15, 21, 27, . . . B 3, 9, 17, 27, 39, . . . C 3, 9, 27, 81, 243, . . .

Answers

Answer:

A) 3, 9, 15, 21, 27, . . .

Step-by-step explanation:

EDGE 2020

Answer:

The second answer is 6.

Step-by-step explanation:

D=6

Can You please help me cause I'm gangsta Simplify (5^-2)^4 ​

Answers

Answer:

( 5 ^ -2)^4

= 5 ^ -8

= 1 /5^8

= 1 / 390,625

Find the value of the logarithm.
log 110
Round your answer to the nearest thousandth.

Answers

Answer:

Log 110 = 2.041

Step-by-step explanation:

Log 110 can be simplified and reduced to

Log 110 = log (10*11)

Log 110 = log10 + log11

But log10 = 1

Log 11= unknown = x

10^x= 11

X= 1.0413926

Log 110 = 1+1.0413926

Log110 = 2.0413926

Log 110 = 2.041

4x-y+ 2z=-1

Given the system -x+2y + 5z = 2, which is true?

|-x+y-3z= 1

Answers

Answer:

Y = 0

X= 1/2

Z = -1/2

Step-by-step explanation:

4x-y+ 2z=-1

-x+y-3z= 1

-x+2y + 5z = 2

Solving simultenously

Y= 4x + 2z -1

Y =1+ 3z+ x

Y =x/2 -( 5z/2) - 1

Equating y will give two equations

3x-z = 2

3x + 11z = -4

Subtracting the equations

-12z =6

Z= -1/2

Substituting z

3x +1/2 = 2

3x = 3/2

X= 1/2

Substituting x and z to find y in

-x+y-3z= 1

-1/2 + y +3/2 = 1

Y = 1-1

Y = 0

Answer: b) is answer

Step-by-step explanation:

The radius r of a sphere is increasing at a rate of 3 inches per minute. (a) Find the rate of change of the volume when r = 9 inches. in.3/min (b) Find the rate of change of the volume when r = 37 inches. in.3/min

Answers

Answer:

[tex]\frac{dV}{dt}[/tex]  = 1017.87 in³/min

[tex]\frac{dV}{dt}[/tex] = 17203.35 in³/min

Step-by-step explanation:

given data

radius r of a sphere is increasing at a rate = 3 inches per minute

[tex]\frac{dr}{dt}[/tex]  = 3

solution

we know volume of sphere is V = [tex]\frac{4}{3} \pi r^3[/tex]

so [tex]\frac{dV}{dt} = \frac{4}{3} \pi r^2 \frac{dr}{dt}[/tex]  

and when r = 9

so rate of change of the volume will be

rate of change of the volume [tex]\frac{dV}{dt} = \frac{4}{3} \pi (9)^2 (3)[/tex]

[tex]\frac{dV}{dt}[/tex]  = 1017.87 in³/min

and

when r = 37 inches

so rate of change of the volume will be

rate of change of the volume [tex]\frac{dV}{dt} = \frac{4}{3} \pi (37)^2 (3)[/tex]

[tex]\frac{dV}{dt}[/tex] = 17203.35 in³/min  

An engineering consulting firm wantedto evaluate a rivet process by measuring the formed diameter. The following data represent the diameters (in hundredths of an inch) for a random sample of 24 rivet heads:
6.81 - 6.79 - 6.69 - 6.59 - 6.65 - 6.60 - 6.74 - 6.70 - 6.76
6.84 - 6.81 - 6.71 - 6.66 - 6.76 - 6.76 - 6.77 - 6.72 - 6.68
7.71 - 6.79 - 6.72 - 6.72 - 6.72 - 6.79 - 6.83
a) Set up a 95% confidence interval estimate of the average diameter of rivet heads (in hundredths of an inch).
b) Set up a 95% confidence interval estimate of the standard deviation of the diameter of rivet heads (in hundredths of an inch)

Answers

Answer:

Step-by-step explanation:

6.81 - 6.79 - 6.69 - 6.59 - 6.65 - 6.60 - 6.74 - 6.70 - 6.76

6.84 - 6.81 - 6.71 - 6.66 - 6.76 - 6.76 - 6.77 - 6.72 - 6.68

7.71 - 6.79 - 6.72 - 6.72 - 6.72 - 6.79 - 6.83

[tex]\bar x =6.77[/tex]

S.D = 0.21

[tex]I=6.77\pmt\times\frac{s}{\sqrt{n} }[/tex]

df = 24

α = 0.05

t = 2.064

[tex]I=6.77\pm2.064\times\frac{0.21}{\sqrt{25} } \\\\=6.77\pm0.087\\\\=[6.683,6.857][/tex]

b)

[tex]\sqrt{\frac{(1-n)s^2}{X^2_{\alpha /2} } < \mu <\sqrt{\frac{(1-n)s^2}{X^2_{1-\alpha/2} } }[/tex]

[tex]\sqrt{\frac{24 \times 0.21^2}{39.364} } < \mu <\sqrt{\frac{24 \times 0.21^2}{12.401} } \\\\=0.1640<\mu<0.2921[/tex]

Can someone plz help me solved this problem I need help ASAP plz help me! Will mark you as brainiest!

Answers

Answer:

x²- 5²

(x+5)(x-5)

Step-by-step explanation:

Area of shaded region: area of square with side x - area of square with side 5

A= x²- 5²

A= (x+5)(x-5)

Solve 5(2x-3a)+2b=3ax-4, for x

Answers

Answer:

10x-15a

Step-by-step explanation:

so im gna write smthn so jejjxhejxheidjieh uruxueudueususus

Based on aâ poll, among adults who regret gettingâ tattoos, 18â% say that they were too young when they got their tattoos. Assume that eight adults who regret getting tattoos are randomlyâ selected, and find the indicated probability. Complete partsâ (a) throughâ (d) below.

a. Find the probability that none of the selected adults say that they were too young to get tattoos.
b. Find the probability that exactly one of the selected adults says that he or she was too young to get tattoos.
c. Find the probability that the number of selected adults saying they were too young is 0 or 1.
d. It we randomly select 9 adults. Is 1 a significantly low number who day that they were too young to get tattoos?

Answers

Answer:

a) 20.44% probability that none of the selected adults say that they were too young to get tattoos.

b) 35.90% probability that exactly one of the selected adults says that he or she was too young to get tattoos.

c) 56.34% probability that the number of selected adults saying they were too young is 0 or 1.

d) No

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they say they were too young when they got their tattoos, or they don't say that. Each adult is independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

18% say that they were too young when they got their tattoos.

This means that [tex]p = 0.18[/tex]

Eight adults who regret getting tattoos are randomly selected

This means that [tex]n = 8[/tex]

a. Find the probability that none of the selected adults say that they were too young to get tattoos.

This is P(X = 0).

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{8,0}.(0.18)^{0}.(0.82)^{8} = 0.2044[/tex]

20.44% probability that none of the selected adults say that they were too young to get tattoos.

b. Find the probability that exactly one of the selected adults says that he or she was too young to get tattoos.

This is P(X = 1).

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 1) = C_{8,1}.(0.18)^{1}.(0.82)^{7} = 0.3590[/tex]

35.90% probability that exactly one of the selected adults says that he or she was too young to get tattoos.

c. Find the probability that the number of selected adults saying they were too young is 0 or 1.

Either a. or b.

20.44 + 35.90 = 56.34

56.34% probability that the number of selected adults saying they were too young is 0 or 1.

d. It we randomly select 9 adults. Is 1 a significantly low number who day that they were too young to get tattoos?

Now [tex]n = 9[/tex]

It is significantly low if it is more than 2.5 standard deviations below the mean.

The mean is [tex]E(X) = np = 9*0.18 = 1.62[/tex]

The standard deviation is [tex]\sqrt{V(X)} = \sqrt{n*p*(1-p)} = \sqrt{9*0.18*0.82} = 1.15[/tex]

1 > (1.62 - 2.5*1.15)

So the answer is no.

Suppose 44% of a large sample of a population favor a tax increase. If there
are 95,000 people in the population about how many people in the population
favor a tax increase?
A. 13,300
B. 22,800
C. 41,800
D. 32,300

Answers

Answer:

C. 41,800

Step-by-step explanation:

Multiply 0.44 by 95,000.

0.44 x 95,000 = 41,800

If P(A)=0.4, P(A and B)=0.2,and P(A or B)=0.5, What is P(B)

Answers

Answer:

[tex]\boxed{\ P(B)=0.3 \ }[/tex]

Step-by-step explanation:

Hi,

We know that

P(A or B)=P(A)+P(B)-P(A and B)

so P(B)= P(A or B) - P(A) + P(A and B)

so

P(B) = 0.5 - 0.4 + 0.2 = 0.3

thanks

Please help me with this problem

Answers

Answer:

I think it is -2

Step-by-step explanation:

I think but I do not know

The mean percent of childhood asthma prevalence in 43 cities is 2.32​%. A random sample of 32 of these cities is selected. What is the probability that the mean childhood asthma prevalence for the sample is greater than 2.8​%? Interpret this probability. Assume that sigmaequals1.24​%. The probability is nothing.

Answers

Answer:

[tex] P(\bar X>2.8)[/tex]

We can use the z score formula given by:

[tex] z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

And replacing we got:

[tex] z=\frac{2.8 -2.32}{\frac{1.24}{\sqrt{32}}}=2.190 [/tex]

And using the normal standard distribution and the complement rule we got:

[tex] P(z>2.190 )= 1-P(z<2.190) = 1-0.986=0.014[/tex]

Step-by-step explanation:

For this case w eknow the following parameters:

[tex] \mu = 2.32[/tex] represent the mean

[tex]\sigma =1.24[/tex] represent the deviation

n= 32 represent the sample sze selected

We want to find the following probability:

[tex] P(\bar X>2.8)[/tex]

We can use the z score formula given by:

[tex] z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

And replacing we got:

[tex] z=\frac{2.8 -2.32}{\frac{1.24}{\sqrt{32}}}=2.190 [/tex]

And using the normal standard distribution and the complement rule we got:

[tex] P(z>2.190 )= 1-P(z<2.190) = 1-0.986=0.014[/tex]

Answer:

0.55% probability that the mean childhood asthma prevalence for the sample is greater than 2.8​%. This means that a sample having an asthma prevalence of greater than 2.8% is unusual event, that is, unlikely.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If X is more than two standard deviations from the mean, it is considered an unusual outcome.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

[tex]\mu = 2.32, \sigma = 1.24, n = 43, s = \frac{1.24}{\sqrt{43}} = 0.189[/tex]

What is the probability that the mean childhood asthma prevalence for the sample is greater than 2.8​%?

This is 1 subtracted by the pvalue of Z when X = 2.8. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{2.8 - 2.32}{0.189}[/tex]

[tex]Z = 2.54[/tex]

[tex]Z = 2.54[/tex] has a pvalue of 0.9945

1 - 0.9945 = 0.0055

0.55% probability that the mean childhood asthma prevalence for the sample is greater than 2.8​%. This means that a sample having an asthma prevalence of greater than 2.8% is unusual event, that is, unlikely.

In a random sample of six cell​ phones, the mean full retail price was ​$538.00 and the standard deviation was ​$184.00. Assume the population is normally distributed and use the​ t-distribution to find the margin of error and construct a 90​% confidence interval for the population mean mu. Interpret the results. Identify the margin of error. Construct a 90​% confidence interval for the population mean. Interpret the results. Select the correct choice below and fill in the answer box to complete your choice.

Answers

Answer:

The margin of error is 370.8.

The 90​% confidence interval for the population mean is between $167.2 and $908.8

The correct interpretation is that we are 90% sure that the true mean price for all cellphones in within the interval end-points, so option B.

Step-by-step explanation:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.9}{2} = 0.95[/tex]. So we have T = 2.0150

The margin of error is:

M = T*s = 2.0150*184 = 370.8.

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 538 - 370.8 = $167.2

The upper end of the interval is the sample mean added to M. So it is 538 + 370.8 = $908.8

The 90​% confidence interval for the population mean is between $167.2 and $908.8

The correct interpretation is that we are 90% sure that the true mean price for all cellphones in within the interval end-points, so option B.

Please answer this correctly

Answers

Answer:

  698 cm²

Step-by-step explanation:

The volume is given by ...

  V = LWH

Filling in the given values, we have ...

  1020 = (17)(5)y . . . . . . . using L=17, W=5, H=y

  y = 1020/(17·5) = 12

The surface area is given by ...

  A = 2(LW +H(L+W))

  A = 2(17·5 +12(17+5)) = 2(85 +264) . . . . . . . using L=17, W=5, H=y=12

  A = 698 . . . . square centimeters



A box on a 20 degree incline is shown with vectors radiating from a point in the center of the box. The first vector points up and parallel to the surface of the incline, labeled F Subscript f s Baseline. A second vector points toward the center of the earth, labeled F Subscript g Baseline = 735 N. A third vector is perpendicular to and away from the surface of the incline from the point, labeled F Subscript N Baseline. A fourth vector is broken into 2 components, one parallel to the surface and down the incline, labeled F Subscript g x Baseline, and one perpendicular to the surface and into the surface, labeled F Subscript g y Baseline.

A box at rest on a ramp is in equilibrium, as shown.

What is the force of static friction acting on the box? Round your answer to the nearest whole number. N

What is the normal force acting on the box? Round your answer to the nearest whole number.

Answers

The images to solve this problem is in the attachment.

Answer: [tex]F_{fs}[/tex] = 671.0 N; [tex]F_{N}[/tex] = 300 N

Step-by-step explanation: From the image in the attachment and knowing that the box is in equilibrium, i.e., the "sum" of all the forces is 0, it is possible to conclude that:

[tex]F_{fs}[/tex]  = [tex]F_{gx}[/tex] and [tex]F_{N}[/tex] = [tex]F_{gy}[/tex]

Using trigonometry, shown in the second attachment, the values for each force are:

Force of Static Friction

sin 20° = [tex]\frac{F_{gx} }{F_{g} }[/tex]

[tex]F_{gx}[/tex] = [tex]F_{g}[/tex]. sin(20)

[tex]F_{gx}[/tex] = 735.0.913

[tex]F_{gx}[/tex] = 671.0

Normal Force

cos 20° = [tex]\frac{F_{gy} }{F_{g} }[/tex]

[tex]F_{gy}[/tex] = [tex]F_{g}[/tex]. cos (20)

[tex]F_{gy}[/tex] = 735.0.408

[tex]F_{gy}[/tex] = 300

The force of static friction is 671N and normal force is 300N

Answer:

Static force is 251 and the Normal force is 691.

Step-by-step explanation:

Hope this helps!! Have a great day!!    :)

I don’t know if it’s g(2(5)(3(5)^2-5-5

Answers

Answer:

  B.  135

Step-by-step explanation:

For ...

f(x) = 3x^2 -xg(x) = 2x -5

f(5) = 3·5^2 -5

   = 3·25 -5 = 75 -5 = 70

Then g(f(5)) is ...

  g(f(5)) = g(70) = 2·70 -5 = 140 -5

  g(f(5)) = 135 . . . . . matches choice B

Which graph show the line y-4=3(x+1)

Answers

Answer:

x or slope: 3

y-intercept: 7

x      y

0     7

1      10

Explanation:

Which chart is good for showing the following? For each part, choose the most appropriate chart from the charts listed. - trends over time - cross tabulation - the relationship among 3 quantitative variables - the relationship between 2 quantitative variables - frequency distribution of quantitative data - show differences in numbers across categories A. column or bar chart B. line chart C. heat map D. clustered column or bar chart E. bubble chart F. scatter chart G. histogram

Answers

Answer:

Step-by-step explanation:

Trends over time - Line charts

Cross tabulation - column or bar chart

The relationship among 3 quantitative variables - Bubble charts or clusteréd column or bar chart

The relationship between 2 quantitative variables - scatter plot

Frequency distribution of quantitative data - Histogram

Show differences in numbers across categories - Bar chart or column charts.

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