Answer:
This program is written in C++
Note that the average is calculated without the highest and the least value.
Comments are used for explanatory purpose
See attachment for .cpp file.
Program starts here
#include<iostream>
using namespace std;
int main()
{
int num;
cout<<"Enter Number of Test [0-10]: ";
//cin>>num;
while(!(cin>>num) || num > 10|| num<0)
{
cout << "That was invalid. Enter a valid digit: "<<endl;
cin.clear(); // reset the failed input
cin.ignore(123,'\n');//Discard previous input
}
//Declare scores
int scores[num];
//Accept Input
for(int i =0;i<num;i++)
{
cout<<"Enter Test Score "<<(i+1)<<": ";
cin>>scores[i];
}
//Determine highest
int max = scores[0];
for (int i = 1; i < num; i++)
{
if (scores[i] > max)
{
max = scores[i];
}
}
//Determine Lowest
int least = scores[0];
for (int i = 1; i < num; i++)
{
if (scores[i] < least)
{
least = scores[i];
}
}
int sum = 0;
//Calculate total
for(int i =0; i< num;i++)
{
sum += scores[i];
}
//Subtract highest and least values
sum = sum - least - max;
//Calculate average
double average = sum / (num - 2);
//Print Average
cout<<"Average = "<<average<<endl;
//Print Highest
cout<<"Highest = "<<max<<endl;
//Print Lowest
cout<<"Lowest = "<<least;
return 0;
}
Which of the following statements about CASE is not true?CASE tools provide automated graphics facilities for producing charts.CASE tools reduce the need for end user participation in systems development.CASE tools have capabilities for validating design diagrams and specifications.CASE tools support collaboration among team members.CASE tools facilitate the creation of clear documentation
Answer:
CASE tools reduce the need for end user participation in systems development.
Explanation:
CASE is an acronym for Computer-aided Software Engineering and it comprises of software application tools that provide users with automated assistance for Software Development Life Cycle (planning, analysing, designing, testing, implementation and maintenance). The CASE tools helps software developers in reducing or cutting down of the cost and time of software development, as well as the enhancement of the software quality.
Some other benefits of using the CASE tools are;
- CASE tools provide automated graphics facilities for producing charts.
- CASE tools have capabilities for validating design diagrams and specifications.
- CASE tools support collaboration among team members.
- CASE tools facilitate the creation of clear documentation.
- CASE tools checks for consistency, syntax errors and completeness.
The CASE tools can be grouped as, requirement and structure analysis, software design, test-case and code generation, reverse engineering, and document production tools.
Examples of CASE tools are flowchart maker, visible analyst (VA), dreamweaver, net-beans, microsoft visio, adobe illustrator and photoshop etc.
Paul has opened a bespoke tailoring shop. He wants to work online to keep a database of all his customers, send emails when garments are ready, create designs, and maintain financial records using software. Which productivity suite should he consider?
a. Prezi, G suite
b. G suite, Zoho
c. OpenOffice, G suite
d. Zoho, Apple iWork
Answer:
c. OpenOffice, G suite
Explanation:
The main advantage of OpenOffice is that it is free and obviously keeps your costs down. It has a lot of features that can help Paul (and really anyone else). It offers decent word processing, spreadsheets, databases and graphics, which can cover most, if not all, of Paul's needs.
Google's G Suite also offers cheap plan's that can satisfy Paul's needs regarding emails, CRM features and cloud storage. Even though it is not free, Paul would probably need only the most basic plan at just $6 per month.
The productivity suite Paul should consider is OpenOffice. Therefore, the correct answer is option C.
The primary benefit of OpenOffice is that it is cost free, which obviously lowers your expenses. Paul can benefit mostly from its many features. The majority if not all of Paul's demand may be met by its decent word processing, spreadsheets, databases, and graphical features.
Therefore, the correct answer is option C.
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Write a class called Triangle that can be used to represent a triangle. It should include the following methods that return boolean values indicating if the particular property holds: a. isRight (a right triangle) b. isScalene (no two sides are the same length) c. isIsosceles (exactly two sides are the same length) d. isEquilateral (all three sides are the same length).
Answer:
Explanation:
import java.io.*;
class Triangle
{
private double side1, side2, side3; // the length of the sides of
// the triangle.
//---------------------------------------------------------------
// constructor
//
// input : the length of the three sides of the triangle.
//---------------------------------------------------------------
public Triangle(double side1, double side2, double side3)
{
this.side1 = side1;
this.side2 = side2;
this.side3 = side3;
}
//---------------------------------------------------------------
// isRight
//
// returns : true if and only if this triangle is a right triangle.
//---------------------------------------------------------------
boolean isRight()
{
double square1 = side1*side1;
double square2 = side2*side2;
double square3 = side3*side3;
if ((square1 == square2 + square3) ||
(square2 == square1 + square3) ||
(square3 == square1 + square2))
return true;
else
return false;
}
// isValid
// returns : true if and only if this triangle is a valid triangle.
boolean isValid()
{
if ((side1 + side2 < side3) ||
(side1 + side3 < side2) ||
(side2 + side3 < side1))
return false;
else
return true;
}
// isEquilateral
//
// returns : true if and only if all three sides of this triangle
// are of the same length.
boolean isEquilateral()
{
if (side1 == side2 && side2 == side3)
return true;
else
return false;
}
// isIsosceles
//
// returns : true if and only if exactly two sides of this triangle
// has the same length.
boolean isIsosceles()
{
if ((side1 == side2 && side2 != side3) ||
(side1 == side3 && side2 != side3) ||
(side2 == side3 && side1 != side3))
return true;
else
return false;
}
// isIsosceles
// returns : true if and only if exactly no two sides of this
// triangle has the same length.
boolean isScalene()
{
if (side1 == side2 || side2 == side3 || side1 == side3)
return false;
else
return true;
}
}
//-------------------------------------------------------------------
// class Application
//
// This class is the main class of this application. It prompts
// the user for input to construct a triangle, then prints out
// the special properties of the triangle.
//-------------------------------------------------------------------
public class Application
{
//---------------------------------------------------------------
// getInput
//
// input : stdin - BufferedReader to read input from
// msg - message to prompt the user with
// returns : a double value input by user, guranteed to be
// greater than zero.
//---------------------------------------------------------------
private static double getInput(BufferedReader stdin, String msg)
throws IOException
{
System.out.print(msg);
double input = Double.valueOf(stdin.readLine()).doubleValue();
while (input <= 0) {
System.out.println("ERROR : length of the side of triangle must " +
"be a positive number.");
System.out.print(msg);
input = Double.valueOf(stdin.readLine()).doubleValue();
}
return input;
}
//---------------------------------------------------------------
// printProperties
//
// input : triangle - a Triangle object
// print out the properties of this triangle.
//---------------------------------------------------------------
private static void printProperties(Triangle triangle)
{
// We first check if this is a valid triangle. If not
// we simply returns.
if (!triangle.isValid()) {
System.out.println("This is not a valid triangle.");
return;
}
// Check for right/equilateral/isosceles/scalene triangles
// Note that a triangle can be both right triangle and isosceles
// or both right triangle and scalene.
if (triangle.isRight())
System.out.println("This is a right triangle.");
if (triangle.isEquilateral())
System.out.println("This is an equilateral triangle.");
else if (triangle.isIsosceles())
System.out.println("This is an isosceles triangle.");
else
// we do not need to call isScalene here because a triangle
// is either equilateral/isosceles or scalene.
System.out.println("This is an scalene triangle.");
}
// main
// Get the length of the sides of a triangle from user, then
// print out the properties of the triangle.
public static void main(String args[]) throws IOException
{
BufferedReader stdin = new BufferedReader
(new InputStreamReader(System.in));
double side1 = getInput(stdin,
"What is the length of the first side of your triangle? ");
double side2 = getInput(stdin,
"What is the length of the second side of your triangle? ");
double side3 = getInput(stdin,
"What is the length of the third side of your triangle? ");
System.out.print("Pondering...\n");
printProperties(new Triangle(side1, side2, side3));
}
}
For this project, you have to write 3 functions. C++
1. remove_adjacent_digits. This takes in 2 arguments, a std::vector, and a std::vector of the same size. You need to return a std::vector, where each of the strings no longer has any digits that are equal to, one more, or one less, than the corresponding integer in the 2nd vector.
2. sort_by_internal_numbers. This takes in a single argument, a std::vector, and you need to return a std::vector, which is sorted as if only the digits of each string is used to make a number.
3. sort_by_length_2nd_last_digit. This takes in a std::vector>. It returns a vector of the same type as the input, which is sorted, first by the length of the string in the pair, and if they are the same length, then the second last digit of the int.
See the test cases for examples of each of the above functions.
You need to submit a single file called main.cpp that contains all these functions. You can (and should) write additional functions as well. There is no need for a main function.
No loops (for, while, etc) are allowed. You must use only STL algorithms for this project.
Find the given attachments
Wireshark capture files, like the DemoCapturepcap file found in this lab, have a __________ extension, which stands for packet capture, next generation.
(a) .packcng
(b) .paccapnextg
(c) .pcnextgen
(d) .pcapng
Answer:
Option (d) is correct
Explanation:
Previously saved capture files can be read using Wireshark. For this, select the File then open the menu. Then Wireshark will pop up the “File Open” dialog box.
Wireshark capture files, like the DemoCapturepcap file found in this lab, have a .pcapng extension, which stands for packet capture, next generation.
Write a program that takes in an integer in the range 10 to 100 as input. Your program should countdown from that number to 0, printing
the count each of each iteration After ten numbers have been printed to the screen, you should start a newline. The program should stop
looping at 0 and not output that value
I would suggest using a counter to cổunt how many items have been printed out and then after 10 items, print a new line character and
then reset the counter.
important: Your output should use %3d" for exact spacing and a space before and after each number that is output with newlines in order
to test correctly. In C please
Answer:
The program written in C language is as follows
#include<stdio.h>
int main()
{
//Declare digit
int digit;
//Prompt user for input
printf("Enter any integer: [10 - 100]: ");
scanf("%d", &digit);
//Check if digit is within range 10 to 100
while(digit<10 || digit >100)
{
printf("Enter any integer: [10 - 100]: ");
scanf("%d", &digit);
}
//Initialize counter to 0
int counter = 0;
for(int i=digit;i>0;i--)
{
printf("%3d", i); //Print individual digit
counter++;
if(counter == 10) //Check if printed digit is up to 10
{
printf("\n"); //If yes, print a new line
counter=0; //And reset counter to 0
}
}
}
Explanation:
int digit; ->This line declares digit as type int
printf("Enter any integer: [10 - 100]: "); -> This line prompts user for input
scanf("%d", &digit);-> The input us saved in digit
while(digit<10 || digit >100) {
printf("Enter any integer: [10 - 100]: ");
scanf("%d", &digit); }
->The above lines checks if input number is between 10 and 100
int counter = 0; -> Declare and set a counter variable to 0
for(int i=digit;i>0;i--){ -> Iterate from user input to 0
printf("%3d", i); -> This line prints individual digits with 3 line spacing
counter++; -> This line increments counter by 1
if(counter == 10){-> This line checks if printed digit is up to 10
printf("\n"); -> If yes, a new line is printed
counter=0;} -> Reset counter to 0
} - > End of iteration
Computers in a LAN are configured to use a symmetric key cipher within the LAN to avoid hardware address spoofing. This means that each computer share a different key with every other computer in the LAN. If there are 100 computers in this LAN, each computer must have at least:
a. 100 cipher keys
b. 99 cipher keys
c. 4950 cipher keys
d. 100000 cipher keys
Answer:
The correct answer is option (c) 4950 cipher keys
Explanation:
Solution
Given that:
From the given question we have that if there are 100 computers in a LAN, then each computer should have how many keys.
Now,
The number of computers available = 100
The number of keys used in symmetric key cipher for N parties is given as follows:
= N(N-1)/2
= 100 * (100 -1)/2
= 50 * 99
= 4950 cipher keys
is brainly down? Cant search anything
A number of LC-3 instructions have an "evaluate address" step in the instruction cycle, in which a 16-bit address is constructed and written to the Memory Address Register via the MARMUX. List all LC-3 instructions that write to the MAR during the evaluate address phase of the instruction cycle, with the Register Transfer description of each.
Answer: you want to list all LC structers
Explanation:
a. A programmer wrote a software delay loop that counts the variable (unsigned int counter) from 0 up to 40,000 to create a small delay. If the user wishes to double the delay, can they simply increase the upperbound to 80,000?
b. If the code contains a delay loop and we noticed that no delay is being created at run-time. What should we suspect during debugging?
Answer:
Explanation:
The objective here is to determine if the programmer can simply increase the upperbound to 80,000.
Of course Yes, The programmer can simply increase the delay by doubling the upperbound by 80000. The representation can be illustrated as:
( int : i = 0; i < 40,000; i ++ )
{
// delay code
}
Which can be modified as:
( int : i = 0; i < 80,000; i ++ )
{
// delay code
}
b) If the code contains a delay loop and we noticed that no delay is being created at run-time. What should we suspect during debugging?
Assuming there is no delay being created at the run-time,
The code is illustrated as:
For ( int : i = 0 ; i < 0 ; i ++ )
{
// delay code which wont
//execute since code delay is zero
}
we ought to check whether the loop is being satisfied or not. At the Initial value of loop variable, is there any break or exit statement is being executed in between loop. Thus, the aforementioned delay loop wont be executed since the loop wont be executed for any value of i.
Given main(), define the Team class (in file Team.java). For class method getWinPercentage(), the formula is:teamWins / (teamWins + teamLosses)Note: Use casting to prevent integer division.Ex: If the input is:Ravens133 where Ravens is the team's name, 13 is number of team wins, and 3 is the number of team losses, the output is:Congratulations, Team Ravens has a winning average!If the input is Angels 80 82, the output is:Team Angels has a losing average.Here is class WinningTeam:import java.util.Scanner;public class WinningTeam {public static void main(String[] args) {Scanner scnr = new Scanner(System.in);Team team = new Team();String name = scnr.next();int wins = scnr.nextInt();int losses = scnr.nextInt();team.setTeamName(name);team.setTeamWins(wins);team.setTeamLosses(losses);if (team.getWinPercentage() >= 0.5) {System.out.println("Congratulations, Team " + team.getTeamName() +" has a winning average!");}else {System.out.println("Team " + team.getTeamName() +" has a losing average.");}}}
Answer:
Explanation:
public class Team {
private String teamName;
private int teamWins;
private int teamLosses;
public String getTeamName() {
return teamName;
}
public void setTeamName(String teamName) {
this.teamName = teamName;
}
public int getTeamWins() {
return teamWins;
}
public void setTeamWins(int teamWins) {
this.teamWins = teamWins;
}
public int getTeamLosses() {
return teamLosses;
}
public void setTeamLosses(int teamLosses) {
this.teamLosses = teamLosses;
}
public double getWinPercentage() {
return teamWins / (double) (teamWins + teamLosses);
}
}
Following are the Java program to define the Team class and calculate its value:
Class Definition:class Team //defining the class Team
{
private String teamName;//defining String variable
private int teamWins, teamLosses;//defining integer variable
//defining the set method to set value the input value
public void setTeamName(String teamName)//defining setTeamName method that takes one String parameter
{
this.teamName = teamName;//using this keyword that sets value in teamName
}
public void setTeamWins(int teamWins) //defining setTeamWins method that takes one integer parameter
{
this.teamWins = teamWins;//using this keyword that sets value in teamWins
}
public void setTeamLosses(int teamLosses)//defining setTeamLosses method that takes one integer parameter
{
this.teamLosses = teamLosses;//using this keyword that sets value in teamLosses
}
//defining the get method that returns the input value
public String getTeamName() //defining getTeamName method
{
return teamName;//return teamName value
}
public int getTeamWins() //defining getTeamWins method
{
return teamWins;//return teamWins value
}
public int getTeamLosses() //defining getTeamLosses method
{
return teamLosses;//return teamLosses value
}
public double getWinPercentage()//defining getWinPercentage method
{
return ((teamWins * 1.0) / (teamWins + teamLosses));//using the return keyword that returns percentage value
}
}
Please find the complete code in the attached file and its output file in the attached file.
Class definition:
Defining the class "Team".Inside the class two integer variable "teamWins, teamLosses" and one string variable "teamName" is declared.In the next step, the get and set method is defined, in which the set method is used to set the value, and the get method is used to return the value.Find out more about the Class here:
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Write a calling statement for the following code segment in Java: public static int sum(int num1, int num2, String name) { int result = num1 + num2; System.out.println("Hi " + name + ", the two numbers you gave me are: " + num1 + " " + num2); return result; } Function Integer sum(Integer num1, Integer num2, String name) Integer result = num1 + num2 Display "Hi " + name + ", the two numbers you gave me are: ", num1, " ", num2 Return result End Function Write a calling statement to the function in Java or Pseudocode. You may use any value of appropriate data samples to demonstrate your understanding.
Answer:
Following are the calling of the given question
public static void main(String[] args) // main function
{
int store; // variable declaration
store = sum(32,15,"san"); // Calling of sum()
System.out.println(" TheValue returned by sum() : "+store); // display
}
Explanation:
Following are the description of the above statement
Here is the name of function is sum() In the sum() function definition there are 3 parameter in there signature i.e two "int" type and 1 is "string" type .In the main function we declared the variable store i,e is used for storing the result of sum() it means it storing the result of value that is returning from the definition of sum() function .After that calling the function by there name and passing three parameter under it sum(32,15,"san"); and store in the "store" variable.Finally print the value by using system.out.println ().What is a digital security risks?
Answer:
A digital security risk is an action that could result in damage to a computer or similar device's hardware, software, data etc.
Look at these examples:- • Men are not emotional. • Women are too emotional. • Jewish people are good business people. • The French are great lovers. • Old people are useless. • Young people are sex mad. • Black people are poor. • Thin people are self-disciplined. • Fat people are clumsy. • Rock stars are drug addicts. To what extent do you agree with these statements? Make a note of which ones you agree with
Answer:
None
Explanation:
These are all stereotypes. Sure, there are definitely some people who fit their stereotypes, but not all. It's just a generalization at the end of the day. I can't really agree with any of them due to the fact that it's all stereotyping.
Perhaps you feel differently, and believe that some of these example are true. I can't though, sorry. Hope this take helps.
In which contingency plan testing strategy do individuals follow each and every IR/DR/BC procedure, including the interruption of service, restoration of data from backups, and notification of appropriate individuals?
a. Full-interruption
b. Desk check
c. Simulation
d. Structured walk-through
Answer:Full-interruption--A
Explanation: The Full-interruption is one of the major steps for a Disaster Recovery Plan, DRP which ensures businesses are not disrupted by saving valuable resources during a disaster like a data breach from fire or flood.
Although expensive and very risky especially in its simulation of a disruption, this thorough plan ensures that when a disaster occurs, the operations are shut down at the primary site and are transferred to the recovery site allowing Individuals follow every procedure, ranging from the interruption of service to the restoration of data from backups, also with the notification of appropriate individuals.
Let K(x, y) denote the statement "x knows y" and D denote the domain of all people. Express the following English sentences as a quantified proposition using the definitions above:
1. Everybody knows somebody.
2. There is somebody that no one knows.
3. There is no one who knows everybody
Answer:
Given: K(x,y) denotes statement:
"x knows y"
D denote domain of all people.
Explanation:
1. Everybody knows somebody.
Solution:
∀x∈D ∃y∈D : K(x, y)
∀ means for all. Here it is used for Everybody.
∃ means there exists some. Here it represents Somebody.
∈ means belongs to . Both x and y belongs to the domain D of all people.
2. There is somebody that no one knows.
Solution:
∀x∈D ∃y∈D : ¬K(x, y)
∀ means for all. ∃ means there exists some. ∈ means belongs to both x and y belongs to the domain D of all people.¬ this is negation sign which means not K(x,y). So the negation of everybody knows somebody can be expressed as there is somebody that no one knows.
3. There is no one who knows everybody
Solution:
This can be represented in both the ways below.
∀ y∈D ∃ x∈D : K(x, y)
∀ means for all. ∃ means there exists some. ∈ means belongs to both x and y belongs to the domain D of all people.
∀x∈D ∀y∈D : ¬K(x, y)
∀ means for all. The negation shows that there is no one who knows everybody.
In the lab, you defined the information systems security responsibility for each of the seven domains of a typical IT infrastructure. In which domain are you most likely to find service provider service level agreements (SLAs), managed security services, monitoring, and reporting?
Answer:
LAN/WAN domain
Explanation:
This is the boundary between trusted adn untrusted zones. All SLA's, managed security services, their monitoring and reporting is done by this domain.
Pretend that your mother is a real estate agent and that she has decided to automate her daily tasks by using a laptop computer. Consider her potential hardware and software needs and create a hardware and software specification that describes them. The specification should be developed to help your mother buy her hardware and software on her own.
The specification should be developed to help your mother buy her hardware and software on her own is hardware.
Which is hardware?Hardware refers back to the computer's tangible additives or shipping structures that shop and run the written commands furnished through the software program. The software program is the intangible a part of the tool that shall we the consumer have interaction with the hardware and command it to carry out unique tasks.
A few automatic software programs could ship messages, alert and notifications to the customer in addition to the owner.The pc need to be of respectable potential and processing pace three. Video calling software program to have interaction with the clients. Softwares like Excel to keep the information and all An running gadget of right here convenience 4.320 to 500 GB difficult drive three.2.2 GHz of processor. Long battery life Software: three GB RAM.Read more about the hardware :
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Bill downloaded an antivirus software from the Internet. Under the Uniform Commercial Code (UCC), the software is a: Select one: a. good. b. service. c. good-faith warranty. d. mixture of goods and services.
Answer:
a. good
Explanation:
According to the Uniform Commercial Code (UCC), It deals with all the contracts that also involves the sale of the goods,
Here goods include those things or items that are movable in a nature and also consist of manufactured goods that are specialized in nature
Therefore, as per the given situation, the bill downloaded an antivirus software so here the software is treated as a good
Managers can use __ software to discuss financial performance with the help of slides and charts
Answer:
presentation
Explanation:
Software like Google Slides and Microsoft Powerpoint can be utilized to present financial performances through the use of slides and charts.
Array A is not a heap. Clearly explain why does above tree not a heap? b) Using build heap procedure discussed in the class, construct the heap data structure from the array A above. Represent your heap in the array A as well as using a binary tree. Clearly show all the steps c) Show how heap sort work in the heap you have constructed in part (b) above. Clearly show all the step in the heap sort
Answer:
Sorted Array A { } = { 1, 4, 23, 32, 34, 34, 67, 78, 89, 100 }
Explanation:
Binary tree is drawn given that the binary tree do not follow both minimum heap and maximum heap property, therefore, it is not a heap.
See attached picture.
Alejandra is using a flash drive that a friend gave to her to copy some financial records from the company database so she can complete a department presentation at home. She does not realize that the flash drive is infected with a virus that enables a malicious hacker to take control of her computer. This is a potential __________ to the confidentiality of the data in the files
Answer:
maybe threat?
Explanation:
Consider the following skeletal C-like program:
void fun1(void); /* prototype */
void fun2(void); /* prototype */
void fun3(void); /* prototype */
void main() {
int a, b, c;
. . .
}
void fun1(void) {
int b, c, d;
. . .
}
void fun2(void) {
int c, d, e;
. . .
}
void fun3(void) {
int d, e, f;
. . .
}
Given the following calling sequences and assuming that dynamic scoping is used, what variables are visible during execution of the last function called? Include with each visible variable the name of the function in which it was defined
a. main calls funl; funl calls fun2; fun2 calls fun3
b. main calls fun1; fun1 calls fun3
c. main calls fun2; fun2 calls fun3; fun3 calls funl
d. main calls fun1; funl calls fun3; fun3 calls fun2.
Answer:
In dynamic scoping the current block is searched by the compiler and then all calling functions consecutively e.g. if a function a() calls a separately defined function b() then b() does have access to the local variables of a(). The visible variables with the name of the function in which it was defined are given below.
Explanation:
a. main calls fun1; fun1 calls fun2; fun2 calls fun3
Solution:
Visible Variable: d, e, f Defined in: fun3Visible Variable: c Defined in: fun2 ( the variables d and e of fun2 are not visible)Visible Variable: b Defined in: fun1 ( c and d of func1 are hidden)Visible Variable: a Defined in: main (b,c are hidden)b. main calls fun1; fun1 calls fun3
Solution:
Visible Variable: d, e, f Defined in: fun3 Visible Variable: b, c Defined in: fun1 (d not visible)Visible Variable: a Defined in: main ( b and c not visible)c. main calls fun2; fun2 calls fun3; fun3 calls fun1
Solution:
Visible Variable: b, c, d Defined in: fun1 Visible Variable: e, f Defined in: fun3 ( d not visible)Visible Variable: a Defined in: main ( b and c not visible)Here variables c, d and e of fun2 are not visible .
d. main calls fun1; fun1 calls fun3; fun3 calls fun2
Solution:
Visible Variable: c, d, e Defined in: fun2Visible Variable: f Defined in: fun3 ( d and e not visible)Visible Variable: b Defined in: fun1 ( c and d not visible)Visible Variable: a Defined in: main ( b and c not visible)For this assignment, you will create flowchart using Flowgorithm and Pseudocode for the following program example:
Hunter Cell Phone Company charges customer's a basic rate of $5 per month to send text messages. Additional rates apply as such:
The first 60 messages per month are included in the basic bill
An additional 10 cents is charged for each text message after the 60th message and up to 200 messages.
An additional 25 cents is charged for each text after the 200th message
Federal, state, and local taxes add a total of 12% to each billThe company wants a program that will accept customer's name and the number of text messages sent. The program should display the customer's name and the total end of the month bill before and after taxes are added.
Answer:
The pseudocode is as given below in the explanation while the flow diagram is attached herewith
Explanation:
The pseudocode is as follows
input cust_name, num_texts
Set Main_bill=5 $;
if the num_texts is less than or equal to 60
Excess_Charge=0;
If the num_texts is greater than 60 and less than or equal to 200
num_text60200 =num_texts-60;
Excess_Charge=0.1*(num_text60200);
else If the num_texts is greater than 60
num_texts200 =num_texts-200;
Excess_Charge=0.25*(num_texts200)+0.1*(200-60);
Display cust_Name
Total_Bill=Main_bill+Excess_Charge;
Total_Bill_after_Tax=Total_Bill*1.12;
It's inventiveness, uncertainty futuristic ideas typically deal with science and technology.what is it?
Answer:
Engineering and Science
Explanation:
Suppose that class OrderList has a private attribute double cost[100] which hold the cost of all ordered items, and a private attributes int num_of_items which hold the number of items ordered. For example, if num_of_items is 5, then cost[0], cost[1], ..., cost[4] hold the cost of these 5 items. Implement the member function named total_cost which returns the total cost of this OrderList.
Answer:
OrderList.java
public class OrderList { private double cost[]; private int num_of_items; public OrderList(){ cost = new double[100]; } public double total_cost(){ double total = 0; for(int i=0; i < num_of_items; i++){ total += cost[i]; } return total; } }Main.java
public class Main { public static void main(String[] args) { OrderList sample = new OrderList(); double totalCost = sample.total_cost(); } }Explanation:
Firstly, define a class OrderList with two private attributes, cost and num_of_items (Line 1-3). In the constructor, initialize the cost attribute with a double type array with size 100. Next, create another method total_cost() to calculate the total cost of items (Line 9-15). To implement the total_cost member function, create an OrderList instance and use that instance to call the total_cost() and assign it to totalCost variable.
Assume passwords are selected from four character combinations of 26 lower case alphabetic characters. Assume an adversary is able to attempt passwords at a rate of 1 per second. Assuming feedback to the adversary flagging an error as each incorrect character is entered, what is the expected time to discover the correct password
Answer:
Given:
Passwords are selected from 4 characters.
Character combinations are 26 lower case alphabetic characters.
Passwords attempts by adversary is at rate of 1 second.
To find:
Expected time to discover the correct password
Explanation:
Solution:
4 character combinations of 26 alphabetic characters at the rate of one attempt at every 1 second = 26 * 4 = 104
So 104 seconds is the time to discover the correct password. However this is the worst case scenario when adversary has to go through every possible combination. An average time or expected time to discover the correct password is:
13 * 4 = 52
You can also write it as 104 / 2 = 52 to discover the correct password. This is when at least half of the password attempts seem to be correct.
Describe and list advantages and disadvantages of each of the following backup types:
full, differential, incremental, selective, CPD, and cloud.
Answer:
Full back up
It creates complete copy of the source of data. This feature made it to the best back up with good speed of recovery of the data and simplicity.However, because it is needed for backing up of a lot of data, it is time consuming process,Besides it also disturbs the routine application of the technologist infrastructure. In addition large capacity storage is needed for the storage of the large volume of back up with each new creation.
Incremental back up: back up work at high speed thus saves time, Little storage capacity is needed. This type of back up can be run as many time as wished.
However, the restoration of data takes time, due to the time spent for restoration of initial back up and the incremental.
Differential Back up has very fast back up operation, because it only requires two pieces of back up.This is however slower compare to the Incremental.
The selective back up enable selection of certain type of file or folders for back up.
it can only be used to back up folders only when important data are needed only.Thus the storage capacity is low.
CPD eliminates back up window and reduces the recovery point objective.However, it has issue of compatibility with the resources to back up.,it is also expensive because its solutions are disk based.
Cloud based is affordable and save cost,It is easier to access. it is efficient,it can be access remotely for convenience.
However, Internet sources and some bandwidth must be available for access., always depends on third party providers,There is also problems encountered when switching providers.
Explanation:
Chapter 15 Problem 6 PREVENTIVE CONTROLS Listed here are five scenarios. For each scenario, discuss the possible damages that can occur. Suggest a pre-ventive control. a. An intruder taps into a telecommunications device and retrieves the identifying codes and personal identification numbers for ATM cardholders. ( The user subsequently codes this information onto a magnetic coding device and places this strip on a piece of cardboard.) b. Because of occasional noise on a transmission line, electronic messages received are extremely garbled. c. Because of occasional noise on a transmission line, data being transferred is lost or garbled. d. An intruder is temporarily delaying important strategic messages over the telecommunications lines. e. An intruder is altering electronic messages before the user receives them.
Answer: seen below
Explanation:
There are various solution or ways to go about this actually. In the end, curtailing this is what matters in the end.
Below i have briefly highlighted a few precise way some of this problems can be solved, other options are open for deliberation.
A. Digital encoding of information with the calculation being changed occasionally, particularly after the frameworks advisors have finished their employments, and the framework is being used.
Which can also mean; The money could be withdrawn form the ATM. preventive Control is password to be changed periodically and regularly.
B. Noise on the line might be causing line blunders, which can bring about information misfortune. Reverberation checks and equality checks can assist with recognizing and right such mistakes.
C. If information is being lost, reverberation checks and equality checks ought to likewise help; notwithstanding, the issue might be that an intruder is blocking messages and altering them. Message arrangement numbering will assist with deciding whether messages are being lost, and in the event that they are maybe a solicitation reaction strategy ought to be executed that makes it hard for gatecrashers to dodge.
D. In the event that messages are being postponed, a significant client request or other data could be missed. As in thing c, message arrangement numbering and solicitation reaction methods ought to be utilized.
E. Messages modified by intruders can have an extremely negative effect on client provider relations if orders are being changed. For this situation, information encryption is important to keep the gatecrasher from perusing and changing the information. Additionally, a message succession numbering strategy is important to ensure the message isn't erased.
cheers i hope this was helpful !!
Write a short assembly language program in either our 8088 SCO DOSBox or 80386+ MASM Visual Studio 2017 environment that demonstrates data storage and retrieval from memory. As an example consider some value which is either 16 or 32 bits, after instantiating as an immediate value transfer to and retrieve from memory using assembly language instructions.
Answer: provided in the explanation section
Explanation:
The question says:
Write a short assembly language program in either our 8088 SCO DOSBox or 80386+ MASM Visual Studio 2017 environment that demonstrates data storage and retrieval from memory. As an example consider some value which is either 16 or 32 bits, after instantiating as an immediate value transfer to and retrieve from memory using assembly language instructions.
The Answer:
multi-segment executable file template. data segment ; add your data here! pkey db "press any key...$" ends stack segment dw 128 dup(0) ends code segment start: ; set segment registers: mov ax, data mov ds, ax mov es, ax ; add your code here mov cx,4 input: mov ah,1 int 21h push ax loop input mov dx,13d mov ah,2 int 21h mov dx,10d mov ah,2 int 21h mov cx,4 output: pop bx mov dl,bl mov ah,2 int 21h loop output exit: lea dx, pkey mov ah, 9 int 21h ; output string at ds:dx ; wait for any key....
mov ah, 1 int 21h mov ax, 4c00h ; exit to operating system. int 21h ends end start ;
set entry point and stop the assembler.
Cheers I hope this helps!!!
