Answer: 2.3 x 10^-7
Explanation:
When you move the decimal to the right, you decrease the exponent. So lets count how many spots you have to move the decimal spot to get an answer between 1 and 10. I counted seven spots.
So:
[tex]2.3 *10^-^7[/tex]
2.3 * 10 °−7
The degree indicates that the number is that small thing that floats above
A pile of bricks of mass M is being raised to the tenth floor of a building of height H = 4y above the ground by a crane that is on top of the building. During the first part of the lift, the crane lifts the bricks a vertical distance h1=3y in a time t1=4T. During the second part of the lift, the crane lifts the bricks a vertical distance h2=y in t2=T. Which of the following correctly relates the power P1 generated by the crane during the first part of the lift to the power P2 generated by the crane during the second part of the lift?
A. P2=4P1
B. P2=43P1
C. P2=P1
D. P2=34P1
E. P2=13P1
Complete Question
A pile of bricks of mass M is being raised to the tenth floor of a building of height H = 4y above the ground by a crane that is on top of the building. During the first part of the lift, the crane lifts the bricks a vertical distance h1=3y in a time t1=4T. During the second part of the lift, the crane lifts the bricks a vertical distance h2=y in t2=T. Which of the following correctly relates the power P1 generated by the crane during the first part of the lift to the power P2 generated by the crane during the second part of the lift?
[tex]A.\ \ P_2=4P_1[/tex]
[tex]B.\ \ P_2=\frac{4}{3} P1[/tex]
[tex]C.\ \ P_2=P_1[/tex]
[tex]D. \ \ P_2=\frac{3}{4} P_1[/tex]
[tex]E. \ \ \ P_2=\frac{1}{3} P_1[/tex]
Answer:
The correct option is B
Explanation:
From the question we are told that
The mass of the brick is M
The height height of the 10th floor is H = 4y
The height attained during the first part of the lift is [tex]h_1 = 3y[/tex]
The time taken is [tex]t_1 = 4T[/tex]
The height attained during the second part of the lift is [tex]h_2 = y[/tex]
The time taken is [tex]t_2 = T[/tex]
Generally the velocity of the crane during the first lift is mathematically represented as
[tex]v_1 = \frac{h_1}{t_1}[/tex]
=> [tex]v_1 = \frac{3y}{4T}[/tex]
Generally the velocity of the crane during the first lift is mathematically represented as
[tex]v_1 = \frac{h_2}{t_2}[/tex]
=> [tex]v_1 = \frac{y}{T}[/tex]
Generally the power generated during the first lift is
[tex]P_1 = F_1 * v_1[/tex]
Here [tex]F_1[/tex] force applied during the first lift which is mathematically represented as
[tex]F_1 = M * g[/tex] here g is the acceleration due to gravity
So
[tex]P_1 = Mg * \frac{3y}{4T}[/tex]
Generally the power generated during the second lift is
[tex]P_2 = F_2 * v_2[/tex]
Here [tex]F_2[/tex] force applied during the second lift which is mathematically represented as
[tex]F_2 = M * g[/tex] here g is the acceleration due to gravity
So
[tex]P_2 = Mg * \frac{y}{T}[/tex]
So the ratio of the first power to the second power is
[tex]\frac{P_1}{P_2} = \frac{Mg * \frac{3y}{4T}[}{Mg * \frac{y}{T}}[/tex]
=> [tex]\frac{P_1}{P_2} = \frac{3}{4}[/tex]
=> [tex]P_2 = \frac{4}{3} P_1[/tex]
Chen is testing the friction of three surfaces. He pushes the same ball across three different surfaces with the same force and measures the distance the ball rolls over each surface. The ball moved ten inches across Surface 1, six inches across Surface 2, and fifteen inches across Surface 3. Which could most likely describe the three surfaces?
Answer:Surface 1 is blacktop, Surface 2 is gravel, and Surface 3 is ice.
Explanation:
Answer: its C
Explanation:
Which refers to the continuous release of nuclear energy caused when one fission reaction triggers more nuclear reactions?
-fusion reaction
-trigger effect
-energy effect
-chain reaction
Answer:d
Explanation:
Answer:
D is correct
hope it helps
Reset Answers
Practice Energy transformations (Ouestion 5 of 10)
Q5
A penny is dropped from the top of the Statue of Liberty. The Statue of Liberty is 93 m tall If a penny has about 3 Joules of gravitational potential energy at the top, how much
potential energy will have transformed into kinetic energy at the half way point (46.5m) ?
Explanation:
At a height of 93 m, the gravitational potential energy is given by :
P = mgh
Where, m is the mass of a penny
We can find its mass.
[tex]m=\dfrac{P}{gh}\\\\m=\dfrac{3}{9.8\times 93}\\\\m=0.00329\ kg[/tex]
We need to find how much potential energy will have transformed into kinetic energy at the half way point (46.5m). It can be calculated as :
[tex]E=mgh'\\\\E=0.00329\times 9.8\times 46.5\\\\E=1.499\ J[/tex]
Hence, a penny will have transferred 1.499 J of potential energy into kinetic energy.
HELP HURRY MULTIPLE CHOICE 100 POINTS!!!!!!!!
Answer Yes you answered correctly.
Explanation:
Gases, such as the air or helium inside a balloon, take the shape of the containers they're in. They spread out so that the space is filled up evenly with gas molecules. The gas molecules are not connected.
Answer:
Yea ur right
Explanation:
A spinning wheel on a fireworks display is initially rotating in a counterclockwise direction. The wheel has an angular acceleration of -4.46 rad/s2. Because of this acceleration, the angular velocity of the wheel changes from its initial value to a final value of -31.4 rad/s. While this change occurs, the angular displacement of the wheel is zero. (Note the similarity to that of a ball being thrown vertically upward, coming to a momentary halt, and then falling downward to its initial position.) Find the time required for the change in the angular velocity to occur.
Answer:
The time for the change in the angular velocity to occur is 14.08 secs
Explanation:
From the question,
the angular acceleration is - 4.46 rad/s²
Angular acceleration is given by the formula below
[tex]\alpha =\frac{\omega -\omega _{o} }{t - t_{o} }[/tex]
Where [tex]\alpha[/tex] is the angular acceleration
[tex]\omega[/tex] is the final angular velocity
[tex]\omega _{o}[/tex] is the initial angular velocity
[tex]t[/tex] is the final time
[tex]t_{o}[/tex] is the initial time
From the question
[tex]\alpha[/tex] = - 4.46 rad/s²
[tex]\omega _{o}[/tex] = 0 rad/s (starting from rest)
[tex]\omega[/tex] = -31.4 rad/s
[tex]t_{o}[/tex] = 0 s
Now, we will determine t
From [tex]\alpha =\frac{\omega -\omega _{o} }{t - t_{o} }[/tex], then
[tex]-4.46 = \frac{-31.4 - 0}{t - 0}[/tex]
[tex]-4.46 = \frac{-31.4}{t}[/tex]
[tex]t = \frac{-31.4}{-4.46}[/tex]
t = 7.04 secs
This is the time spent in one direction,
Since the angular displacement of the wheel is zero ( it returned to its initial position), then the time required for the change in the angular velocity will be twice this time, that is 2t
Hence,
The time is 2×7.04 secs = 14.08 secs
This is the time for the change in the angular velocity to occur.
An airplane flies with a constant speed of 540 miles per hour. How far can it travel in 1 1/4 hours?
Answer:
Hey!
Your answer is 675 MILES!
Explanation:
Using the S = D x T formula...
We first need to convert any values... 1 1/4 hours--75 mins (1.25hrs)
So now we substitute into the formula!
D (distance)= 540 x 1.25 = 675 (Distance = Speed x Time)
Distance Travelled= 675 MILES!
I HOPE THIS HELPED YOU!A man throws a ball straight up to his friend on a balcony who catches it at its highest point. The ball was thrown with an initial velocity of 17.9 m/s2. What height does the ball reach?
Answer:
The maximum height reached by the ball is 16.35 m.
Explanation:
Given;
initial velocity of the ball, u = 17.9 m/s
the final velocity of the ball at the maximum height, v = 0
The maximum height reached by the ball is given by;
v² = u² + 2gh
During upward motion, gravity is negative
v² = u² + 2(-g)h
v² = u² - 2gh
0 = u² - 2gh
2gh = u²
h = u² / 2g
h = (17.9)² / (2 x 9.8)
h = 16.35 m
Ttherefore, the maximum height reached by the ball is 16.35 m.
What is the elapsed time between the 0-m mark and the 40-m mark
Answer:
a) 4.0 s
b) 16 m/s
c) The distance covered between 4 - 5 s is four times the distance covered between 4 - 5 s
d) Equal distance are covered between 0 - 4 s and 4 -5 s
Note: The question is incomplete. The complete question is as follows;
Refer to the chart below that has data about a moving object to answer the following questions.
Time Elapsed 0.0s 1.0s 2.0s 3.0s 4.0s 5.0 s
Distance Traveled 0.0m 10.0m 20.0m 30.0m 40.0m 80.0 m
a. What is the elapsed time between the 0-m mark and the 40-m mark?
b. How large is the average velocity of the object for the interval from 0-5 s ?
c. How does the interval of 3-4 s compare with the interval from 4-5 s in terms of distance?
d. How does the interval of 0-4 s compare with the interval from 4-5 s in terms of distance?
Explanation:
a. From the data provide, time elapsed between the 0 m - 40 m mark is 4.0 s
b. Average velocity = total distance/ total time
average velocity = 80 m/ 5.0 s = 16.0 m/s
c. Distance covered between 3 - 4 s = 40 m - 30 m = 10 m
Distance covered between 4 - 5 s = 80 m - 40 m = 40 m
The distance covered between 4 - 5 s is four times the distance covered between 4 - 5 s
d. Distance covered between 0 - 4 s = 40 m - 0 m = 40 m
Distance covered between 4 - 5 s = 80 m - 40 m = 40 m
Equal distance are covered between 0 - 4 s and 4 -5 s
A solid nonconducting sphere of radius R carries a charge Q distributed uniformly throughout its volume. At a certain distance rl (r
(A) E/8
(B) E 78.
(C) E/2
(D) 2E
(E) 8E
Answer:
E ’= E / 8
therefore the correct answer is A
Explanation:
Let's calculate the electric field in an insulating sphere with a radius r <R, let's use Gauus's law, with a spherical Gaussian surface
Фi = ∫ E. dA = [tex]q_{int}[/tex] /ε₀
E (4πr²) = q_{int} / ε₀
density is
ρ = q_{int} / V
q_{int} = ρ V = ρ 4/3 π r³
we substitute
E (4π r²) = ρ 4/3 π r³ /ε₀
E = 1 /3ε₀ ρ r
let's change the density by
ρ = Q / V = Q / (4/3 π R³)
E = 1 / 4πε₀ Q r / R³
if we now distribute the same charge on a sphere of radius R' = 2R
E ’= 1 / 4pieo Q r / (2R)³
E ’= 1 / 4ft Qr / R³ ⅛
E ’= E / 8
therefore the correct answer is A
what are the answers to the question
Answer: the link isnt loading
Change in Energy Quick Check
1 of 5
Which change occurs as an object falls toward the surface of Earth? (1 point)
The force of gravity on the object decreases.
The potential energy of the object decreases.
The acceleration due to gravity decreases.
The kinetic energy of the object decreases
IF SOMEONE GETS THE ANSWERS TO 1-5 of quick check pls post them here
Answer:
The force of gravity on the object decreases. (FALSE)
The potential energy of the object decreases. (TRUE)
The acceleration due to gravity decreases. (FALSE)
The kinetic energy of the object decrease (FALSE)
Explanation:
FORCE OF GRAVITY:
Force of gravity on the object is the weight of object, which depends upon the mass and value of acceleration due to gravity (W = mg). Since, the value mass is constant on Earth and acceleration due to gravity is also constant on earth.
Therefore, force of gravity remains same on the object. The statement is false.
POTENTIAL ENERGY:
Potential energy of object depends upon the mass, value of acceleration due to gravity, and change in height of object (P.E = mgΔh). Since, the value mass is constant on Earth and acceleration due to gravity increases as the object moves towards the surface of earth. But, the height of object is decreasing.
Therefore, potential energy of object decreases. The statement is true.
ACCELERATION DUE TO GRAVITY:
Acceleration due to gravity depends upon the altitude (gh = g[1 - 2h/Re]). Since, the height of object is decreasing.
Therefore, acceleration due to gravity increases. The statement is false.
But, this change is not significant.
KINETIC ENERGY:
Kinetic Energy of object, which depends upon the mass and velocity of the object (K.E = mv²/2). Since, the value mass is constant on Earth and velocity increases as the object moves towards the surface of earth.
Therefore, kinetic energy of the object also increases. The statement is false.
As the object falls towards the surface of the earth, the potential energy of the object decreases.
The earth is a large gravitational field. The potential energy of an object is dependent on its height. As a body falls through a height, its mass remains constant but its height decreases therefore its potential energy decreases also.
Hence, the true statement is that as the object falls towards the surface of the earth, the potential energy of the object decreases.
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why bananas are curved
they are bananas and bananas are curved because they grow curved
A block of mass 12.2 kg is sliding at an initial velocity of 6.65 m/s in the positive x-direction. The surface has a coefficient of kinetic friction of 0.253. (Indicate the direction with the signs of your answers.)
a.) What is the force of kinetic friction (in N) acting on the block?
(b What is the block's acceleration (in m/s2)?
(c) How far will it slide (in m) before coming to rest?
Explanation:
Given that,
Mass of the block, m = 12.2 kg
Initial velocity of the block, u = 6.65 m/s
The coefficient of kinetic friction, [tex]\mu_k=0.253[/tex]
(a)The force of kinetic friction is given by :
[tex]f=\mu_k mg[/tex]
mg is the normal force
So,
[tex]f=0.253\times 12.2\times 9.8\\\\f=30.24\ N[/tex]
(b) Net force acting on the block in the horizontal direction,
f = ma
a is the acceleration of the block
[tex]a=\dfrac{f}{m}\\\\a=\dfrac{30.24}{12.2}\\\\a=2.47\ m/s^2[/tex]
(c) Let d is the distance covered by the block before coming to the rest. Using third equation of motion as follows :
[tex]v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{-(6.65)^2}{2\times 2.47}\\\\d=-8.95\ m[/tex]
Hence, this is the required solution.
This question involves the concepts of the frictional force, Newton's second law of motion, and the equations of motion.
a) The force of kinetic friction acting on the block is "-30.28 N".
b) The acceleration of the block is "-2.48 m/s²".
c) The block will slide "8.9 m" before coming to rest.
a)
The kinetic friction force is given by the following formula:
[tex]F=\mu_k mg[/tex]
where,
F = frictional force = ?
[tex]\mu_k[/tex] = coefficient of kinetic friction = 0.253
m = mass of block = 12.2 kg
g = acceleration dueto gravity = 9.81 m/s²
Therefore,
[tex]F=(0.253)(12.2\ kg)(9.81\ m/s^2)[/tex]
F = - 30.28 N (negative sign due to resistive force)
b)
According to Newton's Second Law of Motion:
F = ma
[tex]a=\frac{F}{m} = \frac{-30.28\ N}{12.2\ kg}\\\\[/tex]
a = -2.48 m/s² (negative sign due to deceleration)
c)
Using the third equation of motion to calculate the distance:
[tex]2as=v_f^2-v_i^2[/tex]
where,
s = distance = ?
vf = final speed = 0 m/s
vi = initial speed = 6.65 m/s
Therefore,
[tex]2(-2.48\ m/s^2)s=(0\ m/s)^2-(6.65\ m/s)^2\\\\s=\frac{-(6.65\ m/s)^2}{2(-2.48\ m/s^2)}[/tex]
s = 8.9 m
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The attached picture shows Newton's Second Law of Motion.
1. A tourist accidentally drops a camera from a 40.0 m high bridge and it falls for 2.85 seconds. If g = 9.81 m/s2 and air resistance are disregarded, what is the speed of the camera as it hits the water?
Answer:
28 m/s
Explanation:
v(final)^2=v(initial)^2+2a(delta y)
=sqrt(2*-9.8 m/s^2*-40)
28 m/s
The speed of the camera with which it hits the water is 27.93 meters per second.
What is the speed?
The speed of an object is the rate of change of position of an object in any of the directions. Speed can be measured as the ratio of distance covered by the object to the total time taken in which the distance was covered by the object. Speed is a scalar quantity because it has only magnitude and no direction.
v = gt
where, v is the velocity,
g is the acceleration due to gravity,
and t is the time taken by the object
v = (9.8 m/s²) (2.85s)
v = 27.93 m/s
Therefore, the speed of the camera as it hits the water is 27.93 meters per second.
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As the chief design engineer for a major toy company, you are in charge of designing a loop-the-loop toy for youngsters. The idea is that a ball of mass m and radius r will roll down an inclined track and around the loop without slipping. The ball starts from rest at a height h above the tabletop that supports the whole track. The loop radius is R. Determine the minimum height h, in terms of R and r, for which the ball will remain in contact with the track during the whole of its loop-the-loop journey
Answer: h = 2.7 R - 1.7 r
Explanation:
normally, force is 0 at the top ;
-N - mg = - m v^2 / ( R - r )
-0 - mg = (- mv^2) / ( R-r )
mg = (mv^2) / (R - r)
g = v^2 / ( R - r ) ; ----------------equation 1
conservation of energy ;
ΔK + ΔP = 0 ;
1/2 I ω^2 + 1/2 m v^2 + mg ( h2 - h1 ) = 0 ;
0.5 * ( 2/5 ) m r^2 * ( v / r )^2 + 0.5 m v^2 + mg ( ( 2R - r ) -h ) = 0 ;
0.5 * ( 2/5 ) m r^2 * ( v / r )^2 + 0.5 m v^2 = mg ( - 2R + r + h ) ;
0.5 * ( 2/5 )r^2 * ( v / r )^2 + 0.5 v^2 = g ( - 2R + r + h ) ;
0.5 * ( 2/5 ) v^2 + 0.5 v^2 = g ( - 2R + r + h ) ;
[ 0.5 * ( 2/5 ) + 0.5 ] v^2 = g ( - 2R + r + h ) ;-------------equation 2
from equation 1 , v^2 = g ( R - r ), input in equation 2
[ 0.5 * ( 2/5 ) + 0.5 ] [ g ( R - r ) ] = g ( - 2R + r + h )
[ 0.5 * ( 2/5 ) + 0.5 ] [ ( R - r ) ] = ( - 2R + r + h )
0.7 ( R - r ) = h - 2R + r
0.7R - 0.7r = h - 2R + r
solve for h
h = 0.7R + 2R - 0.7r - r
h = 2.7 R - 1.7 r
Without a battery , why would a circuit not work
Answer:
The cell will have no electromotive force in it.
Explanation:
The battery provides the chemical energy that produces the force needed to move electron around the circuit and to generate electrical energy.
electrochemical cells are devices in which chemical reactions produce electric current. The electromotive force inherent in a cell provides the driving force for the current to flow. Without this force, there would not be enough energy to move the electrons.A magnet is moved toward a coil or wire to induce an electric current. What will happen if the magnet is reversed and moved toward the coil of wire again? (Answer choices attached in photo)
Answer: the direction of the induced current will change :)
Explanation:
A 2.5 μF capacitor consists of 2 large, thin metal plates separated by a plexiglas sheet. The plexiglas sheet has a dielectric constant of 3.4. The capacitor is connected to a 60 V battery and fully charged. Then, whilst still connected to the battery, the plexiglas sheet is removed (assume that the spacing between the metal plates does not change). Calculate the amount of charge that flows to (or from) the capacitor plates when the sheet is removed. Additional charge flowing onto the plates is represented with a + sign and charge leaving the plates is represented with a - sign.
Answer:
Q / Q₀ = 3.4 , ΔQ = 31.14 10⁻⁶ C
Explanation:
For this exercise we will calculate the charge of the capacitor with and without dielectric
the capacitance is given by
C = Q /ΔV
we also use the ratio of capacitances
C = k C₀
Q /ΔV = kQ₀ /ΔV
Q = k Q₀
Q / Q₀ = k
Q / Q₀ = 3.4
If we want a numerical value
C = k Q / DV
Q = C ΔV / k
Q = 2.5 10⁻⁶ 60 / 3.4
Q = 44.12 10⁻⁶ C
whereby the charge without dielectric is
Q₀ = Q / 3.4
Q₀ = 44.12 / 3.4 10⁻⁶
Q₀ = 12.98 10⁻⁶ C
therefore the charge when removing the dielectric is reduced, the amount of charge that flows is
ΔQ = Q - Q₀
ΔQ = (44.12 - 12.98) 10⁻⁶
ΔQ = 31.14 10⁻⁶ C
The amount of charge should be Q / Q₀ = 3.4 , ΔQ = 31.14 10⁻⁶ C
Capacitor:For this given situation, we will determine the charge of the capacitor with and without dielectric
We know that
the capacitance is given by
C = Q /ΔV
Now here we can applied the ratio of capacitances
So,
C = k C₀
Q /ΔV = kQ₀ /ΔV
Q = k Q₀
Q / Q₀ = k
Q / Q₀ = 3.4
In case of numerical value
C = k Q / DV
Q = C ΔV / k
Q = 2.5 10⁻⁶ 60 / 3.4
Q = 44.12 10⁻⁶ C
whereby the charge without dielectric is
Q₀ = Q / 3.4
Q₀ = 44.12 / 3.4 10⁻⁶
Q₀ = 12.98 10⁻⁶ C
Thus the charge at the time when removing the dielectric is decreased , the amount of charge that flows is
ΔQ = Q - Q₀
ΔQ = (44.12 - 12.98) 10⁻⁶
ΔQ = 31.14 10⁻⁶ C
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how can you observe the law of conservation of energy in action at the skatepark?
Explanation:
When the skater is dropped onto the ramp from above, the potential energy decreases and the kinetic energy increases.
Every time the skater bounces from the impact, thermal energy is gained, and both potential and kinetic energy are lost.
The rate at which heat enters an air conditioned building is often roughly proportional to the difference in temperature between inside and outside.
(a) Under this assumption, show that the cost of operating an air con- ditioner is proportional to the square of the temperature difference.
(b) Give a numerical example for a typical house and discuss implications for your electric bill.
(c) Suppose instead that heat enters the building at a rate proportional to the square-root of the temperature difference between inside and outside. How would the operating cost now depend on the temperature difference?
Answer:
Considering first question
Generally the coefficient of performance of the air condition is mathematically represented as
[tex]COP = \frac{T_i}{T_o - T_i}[/tex]
Here [tex]T_i[/tex] is the inside temperature
while [tex]T_o[/tex] is the outside temperature
What this coefficient of performance represent is the amount of heat the air condition can remove with 1 unit of electricity
So it implies that the air condition removes [tex] \frac{T_i}{T_o - T_i}[/tex] heat with 1 unit of electricity
Now from the question we are told that the rate at which heat enters an air conditioned building is often roughly proportional to the difference in temperature between inside and outside. This can be mathematically represented as
[tex]Q \ \alpha \ (T_o - T_i)[/tex]
=> [tex]Q= k (T_o - T_i)[/tex]
Here k is the constant of proportionality
So
since 1 unit of electricity removes [tex] \frac{T_i}{T_o - T_i}[/tex] amount of heat
E unit of electricity will remove [tex]Q= k (T_o - T_i)[/tex]
So
[tex]E = \frac{k(T_o - T_i)}{\frac{T_i}{ T_h - T_i} }[/tex]
=> [tex]E = \frac{k}{T_i} (T_o - T_i)^2[/tex]
given that [tex]\frac{k}{T_i}[/tex] is constant
=> [tex]E \ \alpha \ (T_o - T_i)^2[/tex]
From this above equation we see that the electricity required(cost of powering and operating the air conditioner) is approximately proportional to the square of the temperature difference.
Considering the second question
Assuming that [tex]T_i = 30 ^oC[/tex]
and [tex]T_o = 40 ^oC[/tex]
Hence
[tex]E = K (T_o - T_i)^2[/tex]
Here K stand for a constant
So
[tex]E = K (40 - 30)^2[/tex]
=> [tex]E = 100K [/tex]
Now if the [tex]T_i = 20 ^oC[/tex]
Then
[tex]E = K (40 - 20)^2[/tex]
=> [tex]E = 400 \ K[/tex]
So from this see that the electricity require (cost of powering and operating the air conditioner)when the inside temperature is low is much higher than the electricity required when the inside temperature is higher
Considering the third question
Now in the case where the heat that enters the building is at a rate proportional to the square-root of the temperature difference between inside and outside
We have that
[tex]Q = k (T_o - T_i )^{\frac{1}{2} }[/tex]
So
[tex]E = \frac{k (T_o - T_i )^{\frac{1}{2} }}{\frac{T_i}{T_o - T_i} }[/tex]
=> [tex]E = \frac{k}{T_i} * (T_o - T_i) ^{\frac{3}{2} }[/tex]
Assuming [tex]\frac{k}{T_i}[/tex] is a constant
Then
[tex]E \ \alpha \ (T_o - T_i)^{\frac{3}{2} }[/tex]
From this above equation we see that the electricity required(cost of powering and operating the air conditioner) is approximately proportional to the square root of the cube of the temperature difference.
2. A carpenter tosses a shingle off a 9.4 m high roof, giving it an initial horizontal
velocity of 7.2 m/s.
(a) What is the final vertical velocity of the ball?
(b) How long does it take to reach the ground?
(c) How far does it move horizontally in this time?
Sounds like the shingle/ball is thrown from the roof horizontally, so that the distance it travels x after time t horizontally is
x = (7.2 m/s) t
The object's height y at time t is
y = 9.4 m - 1/2 gt²
where g = 9.80 m/s² is the magnitude of the acceleration due to gravity, and its vertical velocity is
v = -gt
(a) The object hits the ground when y = 0:
0 = 9.4 m - 1/2 gt²
t² = 2 * (9.4 m) / (9.80 m/s²)
t ≈ 1.92 s
at which time the object's vertical velocity is
v = -g (1.92 s) = -18.8 m/s ≈ -19 m/s
(b) See part (a); it takes the object about 1.9 s to reach the ground.
(c) The object travels a horizontal distance of
x = (7.2 m/s) * (1.92 s) ≈ 13.8 m ≈ 14 m
What were the quartering acts
Answer:
The quartering act of 1765 required the colonies to house British soldiers in barracks provided by the colonies.
2. What is the normal force acting a 800-kg car if there are two 55-kg people sitting inside the car?
describe three events you cannot explain about matter and energy
Answer:
describe three events you cannot explain about matter and energy
Explanation:
as anything that has mass and takes up space. Matter is found in 3 major states; solid, liquid and gas. ... Atoms are the smallest particle of matter. They are so small that you cannot see them with your eyes or even with a standard microscope.
Hope that helped.
Answer:
1. Different kinds of balls bounce to different heights when dropped on the same floor.
2. Sugar dissolves faster in hot milk than in cold milk.
3. Plants grow more slowly when they are not near a window.
Explanation:
PLATO/edmentum
what’s the best answer , a , b , c or d
Answer:
The Basic Concept
When we look at an object at rest, we say that it is in equilibrium since all the forces being applied on it, cancel out
now, if one of the force was slightly more than the other one in the same case. The object will start to move and NOT be in equilibrium
BUT
if an object is in a vacuum and moving on a frictionless surface, the object will attain equilibrium after some seconds since it will be moving with constant speed and all the forces acting on it will be equal
Hence, if the object is accelerating. we can say with surety that the object is not is equilibrium since from the second law of motion,
F = ma ; when a is a non-zero value, there is definitely some net force being applied on the object
Looking at the given case
in the question, we are given that the object is 'accelerating' upwards
we proved above that if an object is accelerating, there is some net force on that object and hence the object is NOT in equilibrium
Since the object is accelerating, from the second law of motion:
F = ma; m cannot be zero and if a is a non-zero value as given in the question, there is definitely some net force on the object
Since there is some force being applied on the object, the object is NOT in equilibrium
Conclusion
Since we found that the object is NOT in equilibrium and that there is some net force on the object,
The first option is correct
What is the product of 0.0322 cm x 6.5 cm rounded to the correct number of significant figures?
Answer:
2.093 × 10⁻³ cm²
Explanation:
Given:
0.0322 cm × 6.5 cm
Find:
Product
Computation:
⇒ 0.0322 cm × 6.5 cm
⇒ 0.2093 cm²
2.093 × 10⁻³ cm²
3 A stationary car accelerates uniformly
for 20 s. Its velocity reaches 80
km h-1. What is the acceleration of the
car during this period?-
A 1.11 ms-2
B 2.22 ms-2
C 4.00ms-2
D 22.2ms-2
What type of climate would be near cold ocean currents? PLEASE HELP QUICK!!
Answer:
hot humid with lots of rain.
Explanation:
ocean currents act as conveyer belts of warm and cold water sending heat to the polar regions and helping the tropical areas cool off, thus influencing both weather and climate. the tropics are particularly rainy because heat absorption , and thus ocean evaporation, is highest.
Mild with cooler weather than similar latitudes type of climate would be near cold ocean currents.
What is cold ocean currents?On the eastern side of ocean basins, lower latitudes or the tropics are where cold currents migrate in a direction toward the equator. They carry cold water into regions of the continent that have warm water, which are usually found on the west coastlines.
The Labrador Ocean Current and East Greenland Current flows are two noteworthy examples of cold currents.
From the perspectives of ecology and climate, ocean currents are also advantageous. For example, they are responsible for changing global temperatures.
Learn more about cold ocean currents here:
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what is 100+10000000000000000000
Answer:
200000000000000000000000
Explanation:
Answer:
10000000000000000100
Explanation:
