I would say food but like they take weight too
an object traveling at 15m/s if it has a mass of 2.8kg find the momentum
Answer:
42
Explanation:
p=mv
momentum=mass*velocity
x=2.8*15
x=42
if 6.24×10¹⁸ electron pass through a wire in 1s how many pass through it during a time interval of 2hr, 47min and 10s
During a time interval of 2hr, 47min and 10s, 6.25× [tex]10^{28[/tex] electrons pas through the wire.
What is electron?A negatively charged subatomic particle known as an electron can either be free or attached to an atom (not bound). One of the three main types of particles within an atom is an electron that is bonded to it; the other two are protons and neutrons.
Given parameter:
The electron pass through a wire in 1s = 6.24 × [tex]10^{18}[/tex].
The time interval = 2 hour 47 minute 10 second.
= (2×60×60 + 47×60 +10) second = 1030 second.
Total number of electrons pass through the wire during the time interval = number of electrons pass per second × time interval in second.
= 6.24×[tex]10^{24[/tex]×1030
= 6.25× [tex]10^{28[/tex].
Hence, total number of electrons pass during a time interval of 2hr, 47min and 10s is 6.25× [tex]10^{28[/tex].
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Some vitamins can not be stored in the body and so they must be replenished by intake on a regular basis. Which of the following is not true about these vitamins?
1 they are water-soluble
2 they need to be taken daily
3 they are fat-soluble
4 They include vitamin C and the B complex vitamins.
Answer:
Explanation:
3
PLEASE PROVIDE AN EXPLANATION
THANK YOU!
Answer:
(a) 0.993 s
(b) 14.0 N/m
(c) -3.02 m/s
(d) -6.01 m/s²
Explanation:
(a) The block's position can be modeled as a cosine wave:
x(t) = A cos(ωt)
where A is the amplitude (in this case, 50 cm) and ω is the angular frequency.
At t = 0.200 s, x(t) = 15.0 cm.
15.0 cm = 50.0 cm cos((0.200 s) ω)
0.3 = cos((0.2 s) ω)
1.266 rad = (0.2 s) ω
ω = 6.33 rad/s
The period is:
T = (2π rad) (1 s / 6.33 rad)
T = 0.993
(b) For a spring-mass system, ω = √(k/m). The mass of the block is 0.350 kg, so:
ω = √(k/m)
6.33 rad/s = √(k / 0.350 kg)
6.33 rad/s = √(k / 0.350 kg)
40.1 rad/s² = k / 0.350 kg
k = 14.0 N/m
(c) Energy is conserved:
EE₀ = EE + KE
½ kx₀² = ½ kx² + ½ mv²
kx₀² = kx² + mv²
(14.0 N/m) (0.50 m)² = (14.0 N/m) (0.15 m)² + (0.35 kg) v²
v = -3.02 m/s
Alternatively, we can take the derivative of our position equation:
v(t) = -Aω sin(ωt)
v = -(0.50 m) (6.33 rad/s) sin((6.33 rad/s) (0.2 s))
v = -3.02 m/s
(d) Sum of forces on the block:
∑F = ma
-kx = ma
a = -kx / m
a = -(14.0 N/m) (0.15 m) / (0.350 kg)
a = -6.01 m/s²
Alternatively, we can take the derivative of our velocity equation:
a(t) = -Aω² cos(ωt)
a = -(0.50 m) (6.33 rad/s)² cos((6.33 rad/s) (0.2 s))
a = -6.01 m/s²
What destructive feature is created by photons?
Answer:
...........................
A child cart is given an initial velocity of 8 m/s and undergoes a constant acceleration of 4 m/s2. Calculate the distance moved.
please hellppppp 30points
Answer: This is Yazan From 10-C
Explanation
if the ice on the polar of earth melts , how will it affect the duration of the day ? explain
Answer:
When ice of polar caps of earth melts, mass concentrated near the axis of rotation spreads out. Therefore, the moment of inertia I increases. With increase of I,T will increase i.e length of the day will increase.
months
a. How long will it take to pay off the debt?
years
b. How much is the total interest paid on the $1,000 debt? $
Answer:
Explanation:
A. Determines on how much dept you got your self into,and if you have a job to help to pay off the credit card dept
B.It could take awhile
A snow age is a period of time when much of the Earth’s land is covered in glaciers.
A: True
B: False
A ____________________ is a thick ice mass that moves slowly over the land surface.
The glacial budget is the balance or lack of balance between accumulation at the head of a glacier and loss, or wastage, at the foot
A: True
B: False
Although chemical weathering occurs in deserts, _____________________ is far more dominant in shaping desert landscapes.
An alluvial fan is a fan-shaped deposits of sediments formed when a stream’s slop[e is abruptly reduced
A: True
B: False
A __________________ is a flat area on the floor of an undrained desert basin that fills and becomes a lake after heavy rain.
Wind erodes land surfaces in two ways. Name them!
WIndblown silt can be build up, forming thick deposits called what ?
Which of the following isn’t a real sand dune?
A: barchan dunes
B: latitudinal dunes
C: transversal dunes
D: parabolic dunes
What is known as the vibration of the earth produced by the rapid release of energy within the lithosphere?
A: blizzard
B: mudflow
C: earthquake
The point within earth where an earthquake starts is called the focus
A: True
B: False
_______________ are fractures in earth where movement has occurred
A(n) ________________________ is an earthquake that occurs sometimes soon after the major earthquake.
Foreshocks can happen days, weeks or even months before the major quake
A: True
B: False
Earthquakes produce 2 main types of seismic waves. Name them!
There are 2 types of body waves. Name them!
17. The Greek word “seismo” means what?
18. A seismogram is an instrument that records seismic waves
A: True
B: False
19. A seismograph is the record made by a moment magnitude
A: True
B: False
20. The ____________________ ______________ and the moment magnitude scale
measure earthquake magnitude.
21. If Los Angeles had a moment magnitude reading of 2.5, the results would be?
A: generally not felt
B: rarely felt
C: destructive in built-up areas
22. If New York City had a moment magnitude reading of 5.5, the results would be?
A: generally not felt
B: potentially perceptible
C: can be damaging shocks
23. If E. St. Louis, Illinois had a moment magnitude reading of 6.4, the results would be?
A: generally not felt
B: rarely felt
C: destructive in built-up areas
24. Earthquake -related hazards include seismic shaking, liquefaction. Landslides,
__________________ and tsunamis
25. Define the term, “liquefaction”!
26. A _______________________ is a wave formed when the ocean floor shifts suddenly during an earthquake.
27. The earth’s interior consists of 3 major layers defined by their chemical composition. Name them!
28. Out of these 3 layers of the earth, which is the highest in volume?
29. Which of the following isn’t a real layer of the earth, based on physical properties?
A: lithosphere
B: middle core
C: inner core
30. The outer core is a solid layer of the earth.
A: True
B: False
Answer:
1.true
2.true
3.true
4.d
17to30.
a
d
a
d
a
d
a
d
a
d
a
d
The table shows the specific heat capacities of various substances. How much energy is required to raise the temperature of 5g of air by 10°C? Use the table below to help you.
Answer:
Q = 50.25 [J]
Explanation:
To solve this problem we must use the following equation that relates the temperature change with the mass and with the specific heat.
Q = m*Cp*(DT)
where:
Q = energy in form of heat [J]
m = mass = 5 [g] = 0.005 [kg]
Cp = specific heat = 1005 [J/kg*°C]
DT = temperature change = 10 [°C]
Now replacing:
Q = 0.005*1005*10
Q = 50.25 [J]
A scale reads 184 N when a piece of copper is hanging from it. What does it read (in N) when it is lowered so that the copper is submerged in water?
Answer:
163 N
Explanation:
The density of copper is about 8.96. The ratio of the weight in water to the weight in air is about 1-1/ρ, so is about 0.8884.
0.8884 × 184 N ≈ 163 N
The submerged weight is about 163 N.
Building contractors often install double-glazed windows to prevent thermal energy (heat) from entering or exiting a building. In addition to being effective insulators, such windows present interesting optical effects.
In the figure, a double-glazed window consists of two identical panes of glass ( g=1.50 ), each g=42.0 mm thick, separated by an air gap of a=33.6 mm . If light incident on the glass makes an angle of =40.00∘ with respect to the glass, find the shift in path Δ as the light enters the room. Use a=1.00 for the index of refraction of air.
Two parallel, horizontal rectangular regions representing glass panes, separated by an open rectangular region representing the air gap between the glass. The thickness of each glass pane is y subscript g. The thickness of the air gap is y subscript a. A light ray is incident upon the upper glass pane, and makes an angle phi with respect to the glass surface. The ray bends downward toward the normal at the air-glass boundary. The ray passes through the glass and strikes the bottom glass-air boundary, where it bends away from the normal and enters the air gap. The beam continues to the second glass sheet, where it once again bends toward the normal at the air-glass boundary. The ray passes through the second sheet and again bends away from the normal at the glass-air boundary. The ray that emerges from the second sheet propagates parallel to a straight line extending the trajectory of the ray incident on the first glass sheet, and is a perpendicular distance delta x away from it.
Δ=
mm
Answer:
x_total = 0.46 cm
Explanation:
Let's analyze this exercise we can calculate the lateral displacement formed by the displacement of the glass plate plus the displacement in the part of air between the glasses.
x_total = d₁ - d₂ + d₃
The sign of displacement in the air is because it reduces lateral displacement.
Let's use the law of refraction to find the angle refracted in the glass, which will determine the displacement
n₁ sin θ₁ = n₂ sin θ₂
where subscript 1 is for the indicating part and subscript 2 for the refracted part (glass)
sin θ₂ = n₁ /n₂ sin θ₁
sin θ₂ = 1 /n_g sin θ₁
for the specific case
sin θ₂ = 1 /1.5 sin 40
θ₂ = sin⁻¹ (0.4285)
θ₂ = 25.37º
so the lateral displacement when exiting the plate is
tan θ₂ = d₁ / y_g
d₁ = y_g tan 25.37
d₁ = 4.20 so 25.37
d₁ = 1.99 cm
when the ray leaves glass and enters the air, it will recover its initial direction, therefore the angle is θ = 40º, the displacement for this part is
tan θ = d₂ / y_a
d₂ = y_a sin θ
suppose that the width is equal to the thickness of the glass y_a = 4.20 cm
d₂ = 4.20 tan 40
d₂ = 3.52 cm
At this time it enters the second glass plate, we see that it is identical to the analysis of the first plate. So the displacement is
d₃ = y_g tan 25.37
d₃ = 4.2 tan 2537
d₃ = 1.99 cm
consequently the total displacement is
general fromula
x_total = 2 y_g tan 25.37 - y_a tan 40
The offset for the given values is
x_total = 1.99 - 3.52 + 1.99
x_total = 0.46 cm
The perpendicular distance delta x away from it will be 0.46 cm.
What is the law of refraction?The incident ray refracted ray, and normal to the interface of two media at the moment of incidence all lie on the same plane,
According to refraction laws. A constant is the ratio of the sine of the angle of incidence to the sine of the angle of refraction. Snell's law of refraction is another name for this.
Let's look at this activity in more detail. We can compute the lateral displacement created by the displacement of the glass plate plus the displacement of the air between the glasses.
[tex]\rm x_{total} = d_1 - d_2 + d_3[/tex]
Because it lowers lateral displacement, displacement in the air is an indication. To compute the displacement, we'll utilize the law of refraction to determine the angle refracted in the glass.
[tex]\rm n_1 sin \theta_1 = n_2 sin \theta_2[/tex]
[tex]sin \theta_2 = \frac{n_1}{n_2} sin \theta_1[/tex]
[tex]\rm sin \theta_2 = \frac{1}{15} sin 40^0 \\\\ \theta_2 = sin^{-1}(0.4285) \\\\\ sin \theta_2 =25.37 ^0[/tex]
As a result, while departing the plate, the lateral displacement is;
[tex]tan \theta_2 = \frac{d_1}{y_g} \\\\\ d_1 = y_g tan 25.37^0 \\\\\ d_1 = 4.20 cos 25.37^0 \\\\ d_1= 1.99 cm[/tex]
The ray will revert to its original orientation when it exits the glass and enters the air, therefore the angle is = 40° and the displacement for this section is
[tex]\rm tan = \frac{d_s}{y_a} \\\\\ d_s = y_a sin \theta \\\\[/tex]
Assume that the breadth of the glass is equal to its thickness, y a = 4.20 cm.
[tex]\rm d_2 = 4.20 tan 40^0\\\\ d_2 = 3.52 cm[/tex]
When it reaches the second glass plate, we notice that the analysis is identical to the first plate's. As a result, the displacement
[tex]\rm d_3 = y_g tan 25.37^0\\\\ d_3 = 4.2 tan 2537 \\\\\ d_3 = 1.99 cm[/tex]
Consequently, the total displacement will be;
[tex]\rm x_{total} = 2 y_g tan 25.37^0 - y_a tan 40^0[/tex]
[tex]x_{total} = 1.99 - 3.52 + 1.99\\\\ x_{tota}l = 0.46 \ cm[/tex]
Hence the perpendicular distance delta x away from it will be 0.46 cm.
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In the Bohr model of the atom, atomic electrons approximatately 'orbit' the nucleus. The hydrogen atom consists of a proton of mass 1.67 × 10-27 kg and an orbiting electron of mass 9.11 × 10-31 kg. In one of its orbits, the electron is 5.3 × 10-11 m from the proton. What is the mutual attractive gravitational force between the electron and proton
Answer:
[tex]F=3.61\times 10^{-47}\ N[/tex]
Explanation:
Mass of a proton, [tex]m_p=1.67\times 10^{-27}\ kg[/tex]
Mass of an electron, [tex]m_e=9.11\times 10^{-31}\ kg[/tex]
The distance between the electron and the proton is, [tex]r=5.3\times 10^{-11}\ m[/tex]
We need to find the mutual attractive gravitational force between the electron and proton. The gravitational force is given by :
[tex]F=G\dfrac{m_em_p}{r^2}[/tex]
Where G is the universal Gravitational constant
[tex]F=6.67\times 10^{-11}\times \dfrac{9.11\times 10^{-31}\times 1.67\times 10^{-27}}{(5.3\times 10^{-11})^2}\\\\F=3.61\times 10^{-47}\ N[/tex]
So, the force between the electron and proton is [tex]3.61\times 10^{-47}\ N[/tex].
Calculate the average induced voltage between the tips of the wings of a Boeing 747 flying at 970 km/hr above East Lansing. The downward component of the earth's magnetic field at this place is
This question is incomplete, the complete question is;
Calculate the average induced voltage between the tips of the wings of a Boeing 747 flying at 970 km/hr above East Lansing. The downward component of the earth's magnetic field at this place is 0.7 × 10⁻⁴ T. (DATA: Assume that the wingspan is 60 meters.)
Answer:
the average induced voltage between the tips of the wings of a Boeing 747 flying is 1.132 Volts
Explanation:
Given that;
Speed S = 970 KM/hr
downward component of the earth's magnetic field B = 0.7 × 10⁻⁴
wingspan 1 = 60min
Velocity V = (970 × 10³) / 3600 = 269.44 m/s
So Average Induced Voltage E = VBI
we substitute
E = 269.44 × (0.7 × 10⁻⁴) × 60
E = 1.132 Volts
Therefore the average induced voltage between the tips of the wings of a Boeing 747 flying is 1.132 Volts
The 2-mg Car Increases its
speed uniformly from rest to
28 m/s in 30s up the incline road
determine the maximum power
that must supplied by the engine
which operates with an efficiency
of e=0.8 Also find the
average power supplied by the
engine .
Answer:
0.35
Explanation:
5. What is final temperature of the object with a heat capacity of 300 cal and a sp. Heat of
0.5 cal/g°C? The mass of the object is 200 g and the initial temperature is 0 degrees
Celsius.
Answer:
3°C
Explanation:
Given parameters:
Heat capacity = 300cal
Specific heat capacity = 0.5cal/g°C
Mass of the object = 200g
Initial temperature = 0°C
Unknown:
Final temperature = ?
Solution:
The heat capacity is the amount of heat required to raise the temperature of a substance by 1°C;
Mathematically ;
H = m c x (t₂ - t₁)
H is the heat capacity
m is the mass
c is the specific heat capacity
t is the temperature
Insert the parameters and solve;
300 = 200 x 0.5 x (t₂- 0 )
100 t₂ = 300
t₂ = 3°C
11. How can you determine if there is net force acting
on an
object?
Answer:
Explanation:
Sum all the forces that are acting on the object and what ever the sum is, is what the net force is.
For example if there is a piece of wood sitting on a table the net force would be the sum of the forces that are acting on it, so the force of gravity (which is negative) + the normal force which would equal zero because they are the same value.
If the forces acting on an object are balanced, what must be true about the motion of this object?
A. It must be moving
B. It must be accelerating
C. It must be changing direction
D. It must have a constant velocity
Answer:
D Constant velocity
Explanation:
if it has forces moving on it it has constant velocity
In football we see unbalanced forces. When 1 player exerts an unbalanced force on another player and causes a player to
Answer:
Fall
Explanation:
The gravitational field at the Moon in N/kg due to the Earth is approximately (G = 6.67 × 10-11 N m2/kg2, the mass of the Earth is 5.98 × 1024 kg, and the distance to the Moon is 3.85 × 108 m)
Answer:
F = 2.69 10⁻³ m [ N]
Explanation:
This exercise asks to calculate the gravitational field of the Earth on the lunar surface, let's use the universal gravitation law
F = G m M / r²
where m is the mass of the body, M the mass of the Earth and r the distance between the Earth and the Moon
F = (G M / r²) m
F = (6.67 10⁻¹¹ 5.98 10²⁴ / (3.85 10⁸)² ) m
F = 2.69 10⁻³ m [ N]
This force is directed from the Moon towards the Earth, therefore it reduces the weight of the body
4.
Vectors P and Q are drawn to scale.
P
Which diagram represents the vector (P +Q)?
A
B
с
D
plz help I will fail.
can anyone plz help me.
plz
Answer:
hindi ko gets
Explanation:
ang gulo naman nyan
1. explain how the concept of atomic number led to the synthesis of new elements in the laboratory;
Answer:
Because from the atomic number of an element we can predict some of its properties; the properties of elements are a periodic function of their atomic numbers. That is the periodic law which is basically used to synthesize new and understand existing and undiscovered elements
Explanation:
New elements can be formed by bombarding atoms of different chemical elements with ions.
The atomic number also called proton number, refers to the number of protons (positive charge) present in the nucleus of an atom. Each chemical element contains one different atomic number (AN).In the laboratory, chemical elements can be generated by bombarding atoms with ions in order to produce new elements.In conclusion, new elements can be formed by bombarding atoms of different chemical elements with ions.
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A stone is thrown horizontally from a cliff 30m high with an initial speed of 20m/s. How long was the stone in the air before hitting the ground? How far did the rock land from the edge of the cliff?
Answer:
Substitute the numbers for YOUR problem this is NOT the answer.
Explanation:
Which diagram models the position of a soccer ball when it has the greatest amount of gravitational potential energy?
Answer:
C
Explanation:
Diagram C is the correct answer, because the ball is at the point with the highest height relative to the ground, in this way all the kinetic energy has been transformed into potential energy.
We must remember that potential energy is defined as the product of mass by gravity by height
Ep = m*g*h
where:
m = mass [kg]
g = gravity acceleration [m/s²]
h = elevation [m]
So when we have a great value for h in the above equation, we will have a big value for potential energy.
Which cell structure is the fluid that fills a eukaryotic or prokaryotic cell?
O A) nucleus
OB) cytoplasm
OC) mitochondrion
OD) cell membrane
pleaseeee answer quick
Answer:
the answer would be be B cytoplasm
what is environment
Answer:
Explanation:
all biotic and abiotic factors around a living organism is its environment
Answer: An environment is the surroundings or conditions in which a person, animal, or plant lives or operates. the natural world, as a whole or in a particular geographical area, especially as affected by human activity. The best synonym for environment would be nature.
Explanation: Environment is a place where different things are such as a swampy or hot environment. They constantly interact with it and adapt themselves to conditions in their environment. In the environment there are different interactions between animals, plants, soil, water, and other living and non-living things. Environment plays an important role in healthy living and the existence of life on planet earth. Earth is a home for different living species and we all are dependent on the environment for food, air, water, and other needs. Therefore, it is important for every individual to save and protect our environment. To divide environments' sorts we can mention 3 kinds of environments Natural, industrial, and social environment. Natural environment: Include water, light, land, air and all organisms that live in nature.
Draw a graph of these results
Answer:
Actually I know but I can't cause it will take time
If a single circular loop of wire carries a current of 63 A and produces a magnetic field at its center with a magnitude of 1.70 10-4 T, determine the radius of the loop.
Answer:
The radius of the circular loop is 0.233 m
Explanation:
Given;
current on the circular loop, I = 63 A
magnitude of the magnetic field, B = 1.7 x 10⁻⁴ T
The magnetic field at the center of a circular loop is given by;
[tex]B = \frac{\mu I}{2R} \\\\[/tex]
Where;
R is the radius of the circular loop
μ is the permeability of free space = 4π x 10⁻⁷ T.m/A
Substitute the givens;
[tex]B = \frac{\mu I}{2R}\\\\R = \frac{\mu I}{2B}\\\\R = \frac{(4\pi*10^{-7})(63) }{2(1.7*10^{-4})}\\\\R = 0.233 \ m[/tex]
Therefore, the radius of the circular loop is 0.233 m
It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The radius of the circular loop is 0.233 m.
What is a magnetic field?It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.
The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength .it is denoted by B.
As we know that current is directly propotional to the induced magnetic field greater the current I, the greater the magnetic field B.
The given data in the problem is;
I is the value of current = 63 A
B is the megnetic field = 1.70 10⁻⁴ T
r is the radius of loop=?
μ is the permeability of free space = 4π x 10⁻⁷ T.m/A
The value of the megnetic field at the center is given by;
[tex]\rm B= \frac{\mu I}{2r} \\\\ \rm r= \frac{\mu I}{2B} \\\\ \rm r= \frac{4\pi \times 63}{2\times 1.7\times 10^{-4}} \\\\ \ \rm r=0.233 m[/tex]
Hence the radius of the circular loop is 0.233 m.
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Claudia stubs her toe on the coffee table with a force of 100.ON. A) What is the
acceleration of Claudia's 1.80kg foot? B) What is the acceleration of the table if it has a mass
of 20.0kg? (ignore any frictional effects) C) Why would Claudia's toe hurt less if the table had
less mass?
Answer:
A.) acceleration= 55.6m/s^2
B.) acceleration of table= 5.0m/s^2
C.) More acceleration
Explanation:
A.) 100N/1.8kg= -55.6
B.) 100N÷20kg= 5
C.) Because since the table would have less mass, it would have had to accelerate more
How does the abundance of hydrogen and helium support the Big Bang Theory?
It is the proportion predicted to be present in the early universe.
The hydrogen and helium abundance helps us to model the expansion rate of the early universe.
In the abundance of hydrogen and helium, we can say that they account for nearly all the nuclear matter in today's universe.
In big Bang model, the universe is mostly light or protons.
This abundance of hydrogen and helium is consistent with this big bang model. The process of forming this hydrogen and helium is often called big bang nucleosynthesis.The Schramm's model for relative abundances indicate that helium is about 25% by mass and hydrogen about 73% with all other elements constituting less than 2%.
Several proponents of big Bang theory has proposed similar relative abundance for hydrogen and helium. In all it is clear that hydrogen and helium constitute of more than 98% of the ordinary matter in the universe.
Finally, the hydrogen and helium abundance helps us to model the expansion rate of the early universe.
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