Answer:
Yes because magnesium has a more negative reduction potential than aluminum.
Explanation:
The single factor that will determine whether a battery with magnesium as anode and aluminium as cathode will work or not is the respective electrode potentials of the two elements.
Recall that in a battery, oxidation occur at the anode and reduction occurs that the cathode. The reduction potential shows the ease with which a metal is reduced or oxidized. The substance with the most negative reduction potential will function as the anode while the substance with the less negative electrode potential will function as the anode.
The reduction potential of Magnesium is -2.37 V while that of aluminum is -1.66 V. This implies that magnesium must function as the anode and aluminum as the cathode in order to have a spontaneous electrochemical process in the cell.
fill in the blank
_______ is a gaseous state of matter that contains appreciable numbers of electrically charged particles.
Diamond is harder than graphite. This is a _______ observation.
Chemistry is defined as the study of _______.
Answer:
1. plasma; 2. qualitative; 3. matter;
Explanation:
PLASMA is a gaseous state of matter that contains appreciable numbers of electrically charged particles.
Diamond is harder than graphite. This is a QUALITATIVE observation.
Chemistry is defined as the study of MATTER.
Plasma is a gaseous state of matter that contains appreciable numbers of electrically charged particles.Diamond is harder than graphite. This is a qualitative observation.Chemistry is defined as the study of matter.
What is matter?Matter in chemistry, is defined as any kind of substance that has mass and occupies space that means it has volume .Matter is composed up of atoms which may or not be of same type.
Atoms are further made up of sub atomic particles which are the protons ,neutrons and the electrons .The matter can exist in various states such as solids, liquids and gases depending on the conditions of temperature and pressure.
The states of matter are inter convertible into each other by changing the parameters of temperature and pressure.Matter is always conserved according to law of conservation of matter.
Learn more about matter,here:
https://brainly.com/question/12972782
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explain how redox reactions are the source of electron flow in batteries. how can a dead battery be said to have attained equilibrium?
Answer:
can u help me whith one of my qutions
Explanation:
An independent country in which people share a common culture is called
an aristocracy.
an ethnic group.
a nation-state.
a polity.
PLease help
Question 1 of 23
The diagram below shows two mugs of coffee mug A and mug B). Both mugs have the same temperature, but mug A contains 30 ml, while mug B contains 5
thermal energy in both mugs?
B
30°C
30°C
.ll Lisa ko
30 ml
5 ml
O Mug A has more thermal energy than mug B
O Mug A has less thermal energy than mug B
O Mug A and B have the same thermal energy
Previous Question
Flag for re
Answer:
mug A has more thermal energy
Explanation:
what are two factors about particles that enable them to form solutions (SCIENCE)
Answer:
temperature and whether or not they are polar or non-polar.
Which of the following represents a 1.00 M (M = mol/dm3) aqueous solution of glucose (C6H12O6)?
A. 180 g glucose per 1000 cm3 solution
B. 10.0 g glucose per 10.0 cm3 water
C. 90.0 g glucose per 500 cm3 water
D. 0.100 g glucose per cm3 solution
Molybdenum metal requires a photon with a minimum frequency of 1.09x1015s-1before it can emit an electron via the photoelectric effect.
a) What is the minimum energy needed to eject an electron?
b)What wavelength of radiation (in nm) will provide a photon of this energy?
c)How many electrons can be freed by a burst of radiation whose total energy is 1.00 μJ, assuming one photon causes one electron to be freed? (μ= micro = 10-6)
d) If molybdenum is irradiated with light of 122nm, what is the maximum kinetic energy of the emitted electrons?
Answer:
a) 7.22 × 10⁻¹⁹ J; b) 275 nm; c) 1.38× 10¹² electrons; d) 9.1 × 10⁻¹⁹ J
Explanation:
a) Minimum energy to eject photon
E = hf = 6.626× 10⁻³⁴ J·s × 1.09 × 10¹⁵ s⁻¹ = 7.22 × 10⁻¹⁹ J
b) Wavelength required
fλ = c
[tex]\lambda = \dfrac{c}{f } = \dfrac{2.998 \times 10^{8}\text{ m/s}}{1.09 \times 10^{15}\text{/s}} = 2.75 \times 10^{-7} \text{ m} = \textbf{275 nm}[/tex]
c) Electrons required
[tex]\text{No. of electrons} = 1.00 \times 10^{-6}\text{ J} \times \dfrac{\text{1 electron}}{7.22 \times 10^{-19}\text{ J}} = 1.38 \times 10^{12}\text{ electrons}[/tex]
d) Kinetic energy of electrons
a) Energy of photon
[tex]E = hf = \dfrac{\text{hc}}{\lambda} = \dfrac{6.626 \times 10^{-34} \text{ J$\cdot$ s}\times 2.998 \times 10^{8} \text{ m/s}}{122 \times 10^{-9}\text{ m}}= 1.63 \times 10^{-18} \text{ J}[/tex]
b) Maximum kinetic energy
The equation for the photoelectric effect is
hf = φ + KE, where
φ = the work function of the metal — the minimum energy needed to eject an electron
KE = hf - φ = 1.63× 10⁻¹⁸ J - 7.22× 10⁻¹⁹ J = 9.1 × 10⁻¹⁹ J
a. The energy of molybdenum to eject electron has been [tex]\rm \bold{7.22\;\times\;10^{-19}}\;J[/tex].
b. The wavelength of the radiation has been 275 nm.
c. The number of electrons present in [tex]\rm 1\;\mu J[/tex] energy has been [tex]\rm \bold{1.38\;\times\;10^1^2}[/tex].
d. The kinetic energy of the emitted electrons as been [tex]\rm \bold{9.1\;\times\;10^-^1^9\;J}[/tex].
The metal emits the energy when it returns from the excited state to ground state.
a. The energy (E) to eject electron has been given by:
[tex]E=h\nu[/tex]
Where, the value of constant, [tex]h=6.626\;\times\;10^{-34}\;\rm J.s[/tex]
The value of frequency has been given, [tex]\nu=\rm 1.09\;\times\;10^{15}\;s^{-1}[/tex]
Substituting the values for energy:
[tex]E=6.626\;\times\;10^{-34}\;\times\;1.09\;\times\;10^{15} \rm J\\\textit E=7.22\;\times\;10^{-19}\;J[/tex]
The energy of molybdenum to eject electron has been [tex]\rm \bold{7.22\;\times\;10^{-19}}\;J[/tex].
b. The wavelength ([tex]\lambda[/tex]) of the radiation has been given by:
[tex]\lambda=\dfrac{c}{\nu}[/tex]
Where, the speed of light, [tex]c=3\;\times\;\rm m/s[/tex]
The frequency has been given as, [tex]\nu=1.09\;\times\;10^{15}\;\rm s^-^1[/tex].
Substituting the values for wavelength:
[tex]\lambda=\dfrac{3\;\times\;10^8}{1.09\;\times\;10^{15}}\;\rm m\\ \lambda=2.75\;\times\;10^-^7\;m\\\lambda=275\;nm[/tex]
The wavelength of the radiation has been 275 nm.
c. The electrons ([tex]e^-[/tex]) burst out can be given as:
[tex]e^-=\dfrac{E}{E'}[/tex]
Where, the energy of radiations, [tex]E=1\;\times\;10^{-6}\;\rm J[/tex]
The energy of each electron has been calculated as, [tex]E'=7.22\;\times\;10^{-19}\;\rm J[/tex]
Substituting the values for number of electrons:
[tex]e^-=\dfrac{1\;\times\;10^-^6}{7.22\;\times\;10^-^1^9} \\e^-=1.38\;\times\;10^1^2[/tex]
The number of electrons present in [tex]\rm 1\;\mu J[/tex] energy has been [tex]\rm \bold{1.38\;\times\;10^1^2}[/tex].
d. The maximum kinetic energy (K.E.) of the radiation has been given as:
[tex]K.E.=\dfrac{hc}{\lambda} -E^'[/tex]
Where, the value of constant, [tex]h=6.626\;\times\;10^{-34}\;\rm J.s[/tex]
The speed of light, [tex]c=3\;\times\;\rm m/s[/tex]
The wavelength of the radiation, [tex]\lambda=122\;\times\;10^-^9\;\rm m[/tex]
Energy of each electron, [tex]E'=7.22\;\times\;10^{-19}\;\rm J[/tex]
Substituting the values, for kinetic energy:
[tex]K.E.=\dfrac{6.626\;\times\;10^{-34}\;\times\;3.0\;\times\;10^8}{122\;\times\;10^-^9}\;-\;7.22\;\times\;10^-^1^9\;\rm J \\\textit {K.E.}=9.1\;\times\;10^{-19}\;J[/tex]
The kinetic energy of the emitted electrons as been [tex]\rm \bold{9.1\;\times\;10^-^1^9\;J}[/tex].
For more information about photoelectric effect, refer to the link:
https://brainly.com/question/9260704
Neutrons are in the nucleus of the atom. A neutron has
a) A positive charge
b) No charge
c) A negative charge
d) Twice as much positive charge as a proton
Answer: B. (No charge)
Explanation:
Protons have a positive charge, electrons have a negative charge.
Neutrons are neutral and therefore have no change.
What does the law of conservation of matter show?
A. That the total number of atoms in matter will never change.
B. That matter can never change form.
C. That atoms will combine in the simplest possible arrangement.
D. That atoms in matter can never be rearranged.
Answer: A) That the total number of atoms in matter will never change.
Explanation: Matter cannot be destroyed nor created. Matter is made up of atoms. The amount of atoms in an object will never change, even when changed into a different form.
Ex. When ice cubes melt there is still the same amount of water just in a different form.
Answer:
A
Explanation:
Which of the following is an example of a mixture?
A. NaCl
B. CO2 + H2 + O2
Ос. Са
D. C6H1206
Reset Selection
Answer:
B.
Explanation:
CO2 + H2 + O2 - are 3 individual substances.
A sample of octane undergoes combustion according to the equation 2 C8H18 + 25 O2 → 16 CO2 + 18 H2O ΔH°rxn = -11018 kJ. What mass of O2 (in grams) must react in order to generate 7280 kJ of energy?
Answer:
[tex]\large \boxed{\text{528.7 g} }[/tex]
Explanation:
It often helps to write the heat as if it were a reactant or a product in the thermochemical equation.
Then you can consider it to be 11018 "moles" of "kJ"
We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
M_r: 32.00
2C₈H₁₈ + 25O₂ ⟶ 16CO₂ + 8H₂O + 11 018 kJ
n/mol: 7280
1. Moles of O₂
The molar ratio is 25 mol O₂:11 018 kJ
[tex]\text{Moles of O}_{2} = \text{7280 kJ} \times \dfrac{\text{25 mol O}_{2}}{\text{11 018 kJ}} = \text{16.52 mol O}_{2}[/tex]
2. Mass of O₂
[tex]\text{Mass of C$_{8}$H}_{18} = \text{16.52 mol O}_{2} \times \dfrac{\text{32.00 g O}_{2}}{\text{1 mol O}_{2}} = \textbf{528.6 g O}_{2}\\\text{The reaction requires $\large \boxed{\textbf{528.67 g O}_{2}}$}[/tex]
If 11 moles of A are combined with 16 moles of B and the reaction occurs to the greatest extent possible, how many moles of C form?
PLEASE HELP ME OUTTTT
How many grams of Fe3O4 are required to react completely with 54.29 grams of H2?
Fe3O4 + H2 → Fe + H2O
Answer:
Balance the equation
Fe3O4 + 4H2---> 3Fe +4H2O
Molar mass H2=(2*1)=2g/mol
Mass of H2=54.29grams
mole of H2= 54.29/2=27.15mol
4 mol of H2 = 1 mol Fe3O4
27.15mol of H2= 6.79mol of Fe3O4
Moles of Fe3O4 =6.79mol
Molar mass of Fe3O4= (56×3)+(16×4)
=168+64=232g/mol
Grams of Fe3O4 required to react with 54.29 grams of H2 is 232g/mol× 6.79mol
=1575.28g
What is thought to be another cause of the large size of our brain compared to chimpanzees?
Answer:
Compared to early humans our brains seemed to have increased in size, and part of the cause may be because of things like Climage change, ecology and social competition
Explanation:
what are the steps to go from the names of compounds to the formulas
Answer:
Explanation:
write down the formulas, use the expressions and formulas to convert
The volume of a gas is 450 mL when its pressure is 1.00 atm. If the temperature of the gas does not change, what is the
pressure when its volume is changed to 2.00 L?
Use PV = P2V2.
0.225 atm
O 0.444 atm
O 2.25 atm
O 4.44 atm
Answer: 0.225 atm
Explanation:
For this problem, we have to use Boyle's Law.
Boyle's Law: P₁V₁=P₂V₂
Since we are asked to find P₂, let's manipulate the equation.
P₂=(P₁V₁)/V₂
[tex]P_{2} =\frac{(1.00atm)(0.45L)}{2.00L}[/tex]
With this equation, the liters cancel out and we will be left with atm.
P₂=0.225 atm
TRUE OR FALSE
As the human population increases, demand for natural resources will also increase.
What are some lessons from
past epidemics that we can
apply to our current coronavirus pandemic?
Answer:
The 1918 influenza pandemic and 2002-2003 SARS outbreak suggests social distancing measures, communication, and international cooperation are the most effective methods to slow down the coronavirus.
Explanation:
How many moles of zinch oxide can be produced from 275 of zinc?
Answer:
[tex]\large \boxed{\text{4.21 mol}}[/tex]
Explanation:
We must do the conversions :
mass of Zn ⟶ moles of Zn ⟶ moles of ZnO
We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
Mᵣ: 65.38
Zn + … ⟶ ZnO + …
m/g: 275
(a) Moles of Zn
[tex]\text{Moles of Zn} = \text{275 g Zn}\times \dfrac{\text{1 mol Zn}}{\text{65.38 g Zn}} = \text{4.206 mol Zn}[/tex]
(b) Moles of ZnO
The molar ratio is 1 mol ZnO:1 mol Zn
[tex]\text{Moles of ZnO} =\text{4.206 mol Zn} \times \dfrac{\text{1 mol ZnO}}{\text{1 mol Zn}} = \text{4.21 mol ZnO}\\\\\text{The reaction produces $\large \boxed{\textbf{4.21 mol}}$ of ZnO}[/tex]
Consider the unbalanced equation for the oxidation of butene. C4H8 + 6O2 CO2 + H2O For each molecule of C4H8 that reacts, how many molecules of carbon dioxide and water are produced?
two carbon dioxide molecules and two water molecules
four carbon dioxide molecules and four water molecules
two carbon dioxide molecules and four water molecules
four carbon dioxide molecules and two water molecules
Answer: Four carbon dioxide molecules and four water molecules
Explanation:
Answer:
D: four carbon dioxide molecules and two water molecules
Explanation:
There are four carbon dioxide molecules (CO₂) on the right side of chemical reaction, because there are four carbon atoms on the left side of balanced chemical reaction.
There are four water molecules (H₂O) on the right side of chemical reaction, because there are eight hydrogen atoms on the left side of balanced chemical reaction.
The use of nuclear energy can have both positive and negative consequences. Which of the following is a positive consequence of using nuclear energy? a. Nuclear energy uses nonrenewable resources. b. Nuclear energy produces little air pollution. c. Uranium ore used for nuclear power plants must be mined and processed. d. Nuclear energy has no environmental impact. Please select the best answer from the choices provided A B C D
Answer
its B
Explanation:
B.
Nuclear energy produces little air pollution.
A chemist prepares a solution of iron(III) bromide (FeBr3) by measuring out 41.1 mg of FeBr3 into a 50. mL volumetric flask and filling to the mark with
distilled water.
Calculate the molarity of Br- anions in the chemist's solution
Be sure your answer is rounded to 2 significant digits.
Answer: The molarity of [tex]Br^-[/tex] anions in the chemist's solution is 0.0084 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n = moles of solute
[tex]V_s[/tex] = volume of solution in ml
moles of [tex]FeBr_3[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{0.0411g}{295.6g/mol}=0.00014mol[/tex]
Now put all the given values in the formula of molality, we get
[tex]Molarity=\frac{0.00014\times 1000}{50}=0.0028[/tex]
As 1 mole of [tex]FeBr_3[/tex] gives = 3 moles of [tex]Br^-[/tex]
0.0028 moles of [tex]FeBr_3[/tex] gives = [tex]\frac{3}{1}\times 0.0028=0.0084 moles[/tex] of [tex]Br^-[/tex]
Thus the molarity of [tex]Br^-[/tex] anions in the chemist's solution is 0.0084 M
please help quick im on a test and i only got an few mins left
What Is the Reactivity Series? ...
How Do Glow Sticks Glow? ...
How Do You Get Different Coloured Fireworks? ...
What Is an Alloy? ...
Answer:
hey
Explanation:
Answer:
I'm really not sure
Explanation:
So there's the answer
calculate the amount of I - 125 that remains after 178.2 days if we started with 300 grams.
Answer:
38.3 g
Explanation:
The half life of a substance is the time taken for the substance to decay to about half of its amount.
Let us assume that I-125 have a half life of 60 days. It means that every 60 days, the amount of I - 125 would be halved.
The amount of I - 125 (A) that remains after t days is given by:
[tex]A=A_o*\frac{1}{2^n} \\[/tex]
Where Ao is the initial amount and n = t / half life
Given that:
Ao = 300 g, t = 178.2 days.
Therefore n = t / half life = 178.2 days / 60 days = 2.97
[tex]A=A_o*\frac{1}{2^n} \\A=300*\frac{1}{2^{2.97}}\\ A=38.3\ g[/tex]
Unscramble the following words to form a complete sentence about the cycles of nature:
limited is through environment Matter recycled the on Earth is and
Answer: idk I have that question too , sorry to get ur hopes up high thinking this was an answer. PERIOTTTT
Explanation:
Which of the following is the conjugate base of HPO 2?
O A. H2P04
B. PO 3
C. H3PO4
O D. HAP04
Answer:
A. H2P04
Explanation:
When potassium chromate (K2CrO4) is added to a solution containing 0.500 g silver nitrate (AgNO3), solid silver chromate (Ag2CrO4) is formed. a) Determine the theoretical yield.
Answer:
Theoretical Yield = 0.4882 grams
Explanation:
Potassium Chromate = K2CrO4 Molar mass: 194.1896 g/mol
Silver Nitrate = AgNO3 Molar mass: 169.87 g/mol
Silver(I) Chromate = Ag2CrO4 Molar mass: 331.73 g/mol
Potassium Nitrate = KNO3 Molar mass: 101.1032 g/mol
K2CrO4 + 2AgNO3 = Ag2CrO4 + 2KNO3
Potassium Chromate + Silver Nitrate = Silver(I) Chromate + Potassium Nitrate
Ratio 1:2 = 1:2
0.5g AgNO3
AgNO3 Molar mass: 169.87 g/mol
2AgNO3 = 339.74grams
0.5/339.74 = 0.0014717
Ag2CrO4 Molar mass: 331.73 g/mol
0.4882 grams
Theoretical Yield = 0.4882 grams
How many grams of LiNO2 are required to make 250 mL of 0.75 Molarity solution?
Answer:
159 g OF LiNO2 WILL BE USED TO MAKE 0.25 L OF 0.75 M SOLUTION.
Explanation:
How many grams of LiNO2 are required to make 250 mL of 0.75 M?
First calculate the molarity in mol per dm3
0.75 M of LiNO2 reacts in 250 mL = 250 /1000 L volume
0.75 M = 0.25 L
In 1 L, the molarity of LiNO2 will be:
= (0.75 * 1/ 0.25) M
= 3 mol/dm3 of LiNO2
Next is to calculate the molarity in g/dm3:
Molarity in mol/dm3 = molarity in g/dm3 / RMM.
RMM of LiNO2
(Li = 7 , N =14 , 0 = 16)
RMM = ( 7 + 14 + 16 * 2) = 53 g/mol
Molarity in mol/dm3 = Molarity in g/dm3 / RMM
Molarity in g/dm3 = Molarity in mol/dm3 * RMM
Molarity in g/dm3 = 3 * 53
Molarity in g/dm3 = 159 g/dm3.
So therefore, to make 250 mL of 0.75 M of LiNO2, we use 159 grams of LiO2.
Ava’s best friend has an indoor cat. Ava notices that she sneezes every time that she visits her friend. Ava suspects that she is allergic to cats but is unsure. What is the best thing for Ava to do next?
C) Test her suspicion by going to see an allergist to diagnose the allergy.
It's right
how many grams of H20 will be produced by 18g H2
Answer:
160.86 g to the nearest hundredth.
Explanation:
H2 + O ---> H2O
2.016 g H2 produces 18.016 g H2O
1g .. .. .. .. .. 18.016 / 2.016 g H2O
18g .. .. .. .. .. . . (18.016 * 18) / 2.016 g H2O.
= 160.86 g.
