Answer:
Asch's experiment showed that about 75% of people were "yielders" who conformed and 25% were "independent" who didn't conform. Asch concludes that people ignored reality and gave an incorrect answer in order to follow the rest of the group.
A particle of ink in a ink-jet printer carries a charge of -8x 10^-13 C and is deflected onto paper force of 3.2x10^-4. Find the strength of the electric field
what is liang most likely trying to do
Answer:
Who is liang
Explanation:
i need more info if i'm going to help you out
He is most likely trying to figure out how to upload the picture to Brainly.
He knows that his question cannot be answered as long as nobody can see the picture.
1. If a spring has a spring constant of 2 N/m and it is stretched 5 cm, what is the force of
the spring?
1.00 x 10^3 kg of clear liquid (specific heat
capacity = 5.11 x 10^2 J/kg-°C) at a temperature
of 15.0°C gains 3.33 x 10° J of heat. What is the
final temperature of the liquid? (Assume the
melting point is less than 15.0°C and the boiling
point is greater than 62.0°C.)
Answer:
15.00000652 °C
Explanation:
From the question,
Q = cm(t₂-t₁)................ Equation 1
Where Q = heat gained by the liquid, c = specific heat capacity of the liquid, m = mass of the liquid, t₁ = Initial Temperature of the liquid, t₂ = Final temperature of the liquid.
Given: Q = 3.33 J, c = 511 J/kg°C, m = 1000 kg, t₁ = 15°C
Substitute these values into equation 1 and solve for t₂
3.33 = 511×1000(t₂-15)
3.33 = 511000(t₂-15)
(t₂-15) = 3.33/511000
(t₂-15) = 0.0000065
t₂ = 15+ 0.0000065
t₂ = 15.00000652 °C
FOR FLVS STUDENTS ONLY///NO BIT LINKS, SCAM LINKS, OR GIBBERSH
**WILL BE MARKING BRAINLIEST AND 50pts (brainly if answer is correct)
I need help ASAPASAPASAPASAP!!!
I'm stuck and I am terrible at this...
Design a diagram, sketch, or other model to show changes in the nucleus of an atom during nuclear fission and fusion. Include a short description and a way to compare the amounts of energy released in each event.
Fusion:
Fission:
here's the definition if it helps!
"Nuclear fission, or radioactive decay, occurs when a heavy atomic nucleus splits into smaller nuclei. For example, atoms of uranium-235 can break down into smaller particles. Some of those particles are atoms of lighter elements. The rest are neutrons."
"Nuclear fusion are reactions that occur when two small nuclei combine to form one larger nucleus. Like nuclear fission reactions, fusion reactions release very large amounts of energy."
this does not belong to me to person it belongs to their name is on this but they had already answered this question but I hope their answer helps you.
Explanation:
archanamourya726
Inside the sun, fusion reactions take place at very high temperatures and enormous gravitational pressures
The foundation of nuclear energy is harnessing the power of atoms. Both fission and fusion are nuclear processes by which atoms are altered to create energy, but what is the difference between the two? Simply put, fission is the division of one atom into two, and fusion is the combination of two lighter atoms into a larger one. They are opposing processes, and therefore very different.
The word fission means "a splitting or breaking up into parts" (Merriam-Webster Online, www.m-w.com). Nuclear fission releases heat energy by splitting atoms. The surprising discovery that it was possible to make a nucleus divide was based on Albert Einstein’s prediction that mass could be changed into energy. In 1939, scientist began experiments, and one year later Enrico Fermi built the first nuclear reactor.
Answer:
i'm anwersing so that other person gets a brianiless
Explanation:
4
What happens because the Earth's orbit
is NOT a perfect circle?
Help Resources
A. We are always the exact same distance away from the
Sun throughout the entire year.
B. At certain timesh during the year, we are closer to the Sun
than at other times.
C. The shape of Earth's orbit does not affect the distance
from the Sun.
Which of the following is NOT a geological event caused by the movement of tectonic plates?
A) Sand Dunes
B) Mountain forming
C) Earthquakes
D) Volcanoes
The volumes of two bodies are measured to be
V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³. Calculate sum and difference in
volumes with error limits.
Answer:
sum of volumes = (16.6 ± 0.03) cm³
and difference of volumes = (3.8 ± 0.03) cm³
Explanation:
Here,
V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³.
Now,
∆V = ± (∆V₁ + ∆V₂)
= ± (0.02 + 0.01) cm³
= ± 0.03 cm³
V₁ + V₂ = (10.2 + 6.4) cm³ = 16.6 cm³ and
V₁ - V₂ = (10.2 - 6.4) cm³ = 3.8 cm³
Thus, sum of volumes = (16.6 ± 0.03) cm³
and difference of volumes = (3.8 ± 0.03) cm³
-TheUnknownScientist
Answer:
I hope it's helpful .............
3. At an early age, what happened to Cesar’s home?
Answer: He died later in 78 BC and was accorded a state funeral. Hearing of Sulla's death, Caesar felt safe enough to return to Rome. Lacking means since his inheritance was confiscated, he acquired a modest house in the Subura, a lower-class neighbourhood of Rome. hope this helps. Can u give me brainliest
Explanation:
The impact wrench consists of a slender 1-kg rod AB which is 580 mm long, and cylindrical end weights at A and B that each have a diameter of 20 mm and a mass of 1 kg. This assembly is free to turn about the handle and socket, which are attached to the lug nut on the wheel of a car. If the rod AB is given an angular velocity of 4 rad/s and it strikes the bracket C on the handle without rebounding, determine the angular impulse imparted to the lug nut.
Answer:
0.8324 kgm^2/s
Explanation:
Attached below is the detailed solution to the given problem
First step :
Calculate mass moment of Inertia of the section about the axle
I axle = 0.20813 kgm^2
next : apply the principle of Angular impulse and momentum to determine the angular impulse imparted to the lug nut
Angular impulse imparted to lug nut = 0.8324 kgm^2/s
A bicycle rider pushes a 13kg bicycle up a steep hill. the incline is 24 degree and the road is 275m long. the rider pushes the bike parallel to the road with a force of 25N.
A. How much work does the rider do on the bike?
B. How much work is done by the force of gravity on the bike?
Answer:
A. W = 6875.0 J.
B. W = -14264.6 J.
Explanation:
A. The work done by the rider can be calculated by using the following equation:
[tex] W_{r} = |F_{r}|*|d|*cos(\theta_{1}) [/tex]
Where:
[tex]F_{r}[/tex]: is the force done by the rider = 25 N
d: is the distance = 275 m
θ: is the angle between the applied force and the distance
Since the applied force is in the same direction of the motion, the angle is zero.
[tex] W_{r} = |F_{r}|*|d|*cos(0) = 25 N*275 m = 6875.0 J [/tex]
Hence, the rider does a work of 6875.0 J on the bike.
B. The work done by the force of gravity on the bike is the following:
[tex] W_{g} = |F_{g}|*|d|*cos(\theta_{2}) [/tex]
The force of gravity is given by the weight of the bike.
[tex] F_{g} = -mgsin(24) [/tex]
And the angle between the force of gravity and the direction of motion is 180°.
[tex] W_{g} = |mgsin(24)|*|d|*cos(\theta_{2}) [/tex]
[tex] W_{g} = 13 kg*9.81 m/s^{2}*sin(24)*275 m*cos(180) = -14264.6 J [/tex]
The minus sign is because the force of gravity is in the opposite direction to the motion direction.
Therefore, the magnitude of the work done by the force of gravity on the bike is 14264.6 J.
I hope it helps you!
How does a battery generate electrical energy?
What efforts are made to conserve wildlife in Nepal ?
large roll of fabric
Costume Rendering
Scissors
Pattern
Bolt
Answer:
Do we have to choose out of those three?
Explanation:
You set a tuning fork into vibration at a frequency of 683 Hz and then drop it off the roof of the Physics building where the acceleration due to gravity is 9.80 m/s2. Determine how far the tuning fork has fallen when waves of frequency 657 Hz reach the release point
Answer:
The distance traveled by the tuning fork is 9.37 m
Explanation:
Given;
source frequency, [tex]f_s[/tex] = 683 Hz
observed frequency, [tex]f_o[/tex] = 657 Hz
The speed at which the tuning fork fell is calculated by applying Doppler effect formula;
[tex]f_o = f_s [\frac{v}{v + v_s} ][/tex]
where;
[tex]v[/tex] is speed of sound in air = 343 m/s
[tex]v_s[/tex] is the speed of the falling tuning fork
[tex]657 = 683[\frac{343}{343 + v_s} ]\\\\\frac{657}{683} = \frac{343}{343 + v_s}\\\\0.962 = \frac{343}{343 + v_s}\\\\0.962(343 + v_s) = 343\\\\343 + v_s = \frac{343}{0.962} \\\\343 + v_s = 356.55\\\\v_s = 356.55 - 343\\\\v_s = 13.55 \ m/s[/tex]
The distance traveled by the tuning fork is calculated by applying kinematic equation as follows;
[tex]v_s^2 = v_o^2 + 2gh[/tex]
where;
[tex]v_o[/tex] is the initial speed of the tuning fork = 0
g is acceleration due to gravity = 9.80 m/s²
[tex]v_s^2 = 0 + 2gh\\\\h = \frac{v_s^2}{2g} \\\\h = \frac{13.55^2 }{2\times 9.8} \\\\h = 9.37 \ m[/tex]
Therefore, the distance traveled by the tuning fork is 9.37 m
PLEASE HELP ME IN THE QUESTION ALSO!
Answer:
467
Explanation:
if the dissipated power between a and b equal 210 watt then VB equal
Answer:
correct answer is A
Explanation:
The diagram shows a series circuit with three resistors and two power sources.
In a series circuit the current through the entire circuit is constant and the resistance is the sum of the resistances in the circuit.
When the power sources are placed in opposite position the voltage between them is subtracted.
V_b - 30 = I (10 + 4 + 6)
V_b = I (20) - 30
V_b = 30 - 2 20
V_b = 10 V
the correct answer is A
In Milgram's experiment:
A. Yale University would not allow the experiment to be done.
B. participants overwhelmingly did not go all the way to 450 volts.
C. the "learner" was working with Milgram.
D. the "teacher" was working with Milgram.
Answer:
B. The "Learner" was working with Milgram.
Explanation:
just took the test
give brainliest, please. :)
Electron spin: Radio astronomers can detect clouds of hydrogen too cool to radiate optical wavelengths of light by means of the 21 cm spectral line corresponding with the flipping of the electron in a hydrogen atom from having its spin parallel to the proton spin to having it antiparallel. From this wavelength, and thus E between states, find the magnetic field experienced by the electron in a hydrogen atom
Answer:
the magnetic field experienced by the electron is 0.0511 T
Explanation:
Given the data in the question;
Wavelength λ = 21 cm = 0.21 m
we know that Bohr magneton μ[tex]_B[/tex] is 9.27 × 10⁻²⁴ J/T
Plank's constant h is 6.626 × 10⁻³⁴ J.s
speed of light c = 3 × 10⁸ m/s
protein spin causes magnetic field in hydrogen atom.
so
Initial potential energy = -μ[tex]_B[/tex]B × cos0°
= -μ[tex]_B[/tex]B × 1
= -μ[tex]_B[/tex]B
Final potential energy = -μ[tex]_B[/tex]B × cos180°
= -μ[tex]_B[/tex]B × -1
= μ[tex]_B[/tex]B
so change in energy will be;
ΔE = μ[tex]_B[/tex]B - ( -μ[tex]_B[/tex]B )
ΔE = 2μ[tex]_B[/tex]B
now, difference in energy levels will be;
ΔE = hc/λ
2μ[tex]_B[/tex]B = hc/λ
2μ[tex]_B[/tex]Bλ = hc
B = hc / 2μ[tex]_B[/tex]λ
so we substitute
B = [(6.626 × 10⁻³⁴) × (3 × 10⁸)] / [2(9.27 × 10⁻²⁴) × 0.21 ]
B = [ 1.9878 × 10⁻²⁵ ] / [ 3.8934 × 10⁻²⁴ ]
B = 510556326.09
B = 0.0511 T
Therefore, the magnetic field experienced by the electron is 0.0511 T
A car, initially at rest, travels from 0 m/s to 17.7 m/s in 21.7 s. What is the car's acceleration?
balance Al +N₂ --> AIN
Answer:
[tex]2Al + N_{2} ==> 2AlN[/tex]
Explanation:
What does the outer part of the disk turn into?
1) Planets and Moons
2) Interstellar Cloud
3) Planetary Nebula
4) It gets sucked into the star
Answer:
what does the outer part of the disk turn into
Explanation:
4) it gets sucked into the star
State the collective name given to protons, neutrons in the nucleus of an atom.
2 Define the mass number.
3 An atom has atomic number of 28 and mass number of 64.
Find
1, Neutron number.
2, Proton number.
Answer: See explanation
Explanation:
1. The collective name given to protons, neutrons in the nucleus of an atom is referred to as the nucleon.
2. The mass number simply means the total number of both the protons and the neutrons that we have in a nucleus.
3. Atomic number = Protons = 28
Mass number = 64.
Neutron = Mass Number - Protons
Neutron = 64 - 28 = 36
4. The number of Protons is also the number of atomic number which is 28.
A 1.4-cm-tall object is 22 cm to the left of a lens with a focal length of 11 cm . A second lens with a focal length of -5 cm is 37 cm to the right of the first lens.
Calculate the distance between the final image and the second lens.
Calculate the image height.
Answer:
can you explain yourself more please
Explanation:
d. What is the net force on the bowling ball rolling lane
Answer:
Friction.
Explanation:
A wheelbarrow full of bricks is lifted to the top of a wall. If the mass of the loaded wheelbarrow is 3000.0 g and the height of the wall is 0.45 meters, what is its GPE?
Answer:
the Gravitational potential energy is 13.23 J
Explanation:
The computation of the GPE is shown below:
GPE stands for Gravitational potential energy
The following formula should be used for the same
= mass × gravity × height
= 3000 g × 9.8m/sec^2 × 0.45 m
= 13.23 J
Hence, the Gravitational potential energy is 13.23 J
We simply applied the above formula so that we can easily determine the GPE
What would be a good reason to increase friction between surfaces? to allow objects to slide past each other easily to reduce wear and tear to provide traction so that slipping does not occur to avoid contact that results in increased temperature and overheating
Answer:
B to provide traction so that slipping does not occur
Explanation:
To increase friction between two surfaces, allow the objects to slide past each other thereby force that is called friction.
What is friction?Friction is a type of force acting on an object to hinder its motion . It is negative by direction, since this force, hinder the motion of the object. Friction is also known as an opposing force because it always acts in the opposite direction of a moving or attempting to move body.
The virtue of friction causes a moving body to slow down. Friction is useful at times because it prevents car tires from skidding on the road and also allows us to walk on the pavement without slipping.
To increase friction , make an uneven, rugged, or sticky point of contact. When two or more bodies slide or rub against each other, three things can happen: small irregularities, nooks and crannies on the surfaces can catch on each other.
To find more on friction, refer here:
https://brainly.com/question/13000653
#SPJ2
Answer pls quick or dont i dk what to say
Answer:
C!
Explanation:
Cold fronts generally advance at average speeds of 20 to 25 mph. toward the east — faster in the winter than summer — and are usually oriented along a northeast to southwest line.
Answer:
I think not sure B sorry if this is wrong yay if im right
Explanation:
HELP ME PLEASE <333, NUMBER 3 ONLY!
Answer:
b
Explanation:
is correct .....................
i think
A wheel rotating with a constant angular acceleration turns through 19 revolutions during a 3 s time interval. Its angular velocity at the end of this interval is 18 rad/s. What is the angular acceleration of the wheel? Note that the initial angular velocity is not zero. Answer in units of rad/s 2 .
Answer:
The magnitude of the angular acceleration of the wheel is 14.53 rad/s².
Explanation:
The angular acceleration can be found by using the following equation:
[tex] \omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \Delta \theta [/tex] (1)
Where:
[tex] \omega_{f}[/tex]: is the final angular velocity = 18 rad/s
[tex]\omega_{0}[/tex]: is the initial angular velocity
α: is the angular acceleration =?
Δθ = 19 rev*(2π/1 rev) = 119.4 rad
The initial angular velocity can be found knowing that the wheel turns through 19 revolutions during a 3 s time interval:
[tex] \omega_{f} = \omega_{0} + \alpha t [/tex]
Where:
t: is the time = 3 s
By solving the above equation for ω₀ we have:
[tex] \omega_{0} = \omega_{f} - \alpha t [/tex] (2)
Now, by entering equation (2) into (1) we have:
[tex] \omega_{f}^{2} = (\omega_{f} - \alpha t)^{2} + 2\alpha \Delta \theta [/tex]
[tex] \omega_{f}^{2} = \omega_{f}^{2} - 2\omega_{f} \alpha t + (\alpha t)^{2} + 2\alpha \Delta \theta [/tex]
[tex](9\alpha)^{2} + 130.8 \alpha = 0[/tex]
By solving the above equation for "α" we have:
α = -14.53
The minus sign means that the wheel is decelerating.
Hence, the angular acceleration of the wheel is -14.53 rad/s².
I hope it helps you!
