Answer:
Archimedes
Step-by-step explanation:
Archimedes is known as the Father Of Mathematics.
Answer:
Archimedes
Archimedes is known as the Father Of Mathematics
Step-by-step explanation:
Graph the rational function
f(x) = 2x+3
———
X-4
Answer:
Step-by-step explanation:
Without using mathematical tables or calculator, find, in surd form(radicals) the value of tan22.5
Answer:
Step-by-step explanation:
tan 45=1
[tex]tan 2\alpha =\frac{2tan\alpha}{1-tan^2\alpha } \\put~\alpha =22.5\\2\alpha =2 \times 22.5=45\\tan~2\alpha =tan~45=1\\1=\frac{2tan \alpha }{1-tan^2\alpha} \\1-tan^2\alpha =2 tan\alpha \\ tan^2\alpha +2tan \alpha -1=0\\tan\alpha =\frac{-2 \pm\sqrt{4+4} }{2} \\=-1\pm\sqrt{2} \\\alpha =22.5\\so ~tan~\alpha ~is~positive.\\so ~tan~\alpha =\sqrt{2} -1[/tex]
A car travels ¹/4 mile in ³ minutes, what 4 is its speed in terms of miles per minutes? A car travels ¹ / 4 mile in ³ minutes , what 4 is its speed in terms of miles per minutes ?
Answer:
1/12 mile per minute
Step-by-step explanation:
1/4 mile in 3 minutes
then miles per minute is 1/4 mile / 3 min = 1/12 mile/min
Solve for w.
−16w-3 = 5w²
Answer:
w = -1/5
OR
w = -3
Step-by-step explanation:
Given equation:
−16w-3 = 5w²
Solution:
Subtracting 5w^2 from both sides,we get
-16w-3-5w² = 5w² - 5w²-5w²-16w-3=0Factor the LHS of this equation using middle term factor:
(-5w²-1)(w-3)Now,
[tex]( - 5w - 1) = 0 \: \: \: \: \: \: \: \: ...(1)[/tex][tex](w - 3) = 0 \: \: \: \: \: \: \: \: \: \: ... (2)[/tex]Solving for equation 1:
[tex] - 5w = 0 + 1[/tex][tex] - 5w = 1[/tex][tex] \boxed{w = - \cfrac{1}{5} }[/tex]Solving for equation 2:
[tex]w - 3 = 0[/tex][tex]w = 0 - 3[/tex][tex] \boxed{w = - 3}[/tex][tex] - 16w - 3 = 5 {w}^{2} \\ \\ 0 = 5 {w}^{2} + 16w + 3 \\ \\ 5 {w}^{2} + 16w + 3 = 0 \\ \\ 5 {w}^{2} + w + 15w + 3 = 0 \\ \\ (5 {w}^{2} + w) + (15w + 3) = 0 \\ \\ w(5w + 1) + 3(5w + 1) = 0 \\ \\ (w + 3)(5w + 1) = 0. [/tex]
The value of w is -3 and -1/5 .
If lies in the quadrant IV what can be the value of cos
When Ф lies in quadrant IV the value of cos Ф lies in [0, 1].
What is quadrant?One fourth of the part of a circle is said to be the quadrant of the circle.
Given the angle Ф lies in quadrant IV.
As we know, cos Ф is positive only in first and fourth quadrant i.e when Ф lies in 0<Ф<90 and 270<Ф<360.
cosФ range from [-1,1]
So, cos Ф is positive when Ф lies in 1st and 4th quadrant.
& cos Ф is negative when Ф lies in 2nd and 3rd quadrant.
If cos ∅ lies in the quadrant IV, anything between [0, 1] can be the value of cos ∅.
Hence, when Ф lies in quadrant IV the value of cos Ф lies in [0, 1].
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ap:3, 2, 1....
what is its coomon difference
Answer:
-1
Step-by-step explanation:
3-1=2
2-1=1
What is the principal, if a person paid an amount of $432 after 1 year at 8% rate of interest per annum
Answer:
principal = $400
Step-by-step explanation:
amount(a)=principal(p) + interest(y).........(1)
Interest(y)=principal(p) x rate(r) x time(t)....(2)
In (1), p= a - y...........(3)
putting (3) in (2),
y = (a - y) x r% x t
y = (432 - y) x 8% x 1
y = 3456%-8y%
y + 0.08y = 3456%
1.08y = 34.56
y = 32
but a - y = p
432 - 32 = p
p = 400
principal = $400
If the set U = {all positive integers} and set A = {x|x ∈ U and x is an odd positive integer}, which describes the complement of set A, Ac?
Ac = {x|x ∈ U and is a negative integer}
Ac = {x|x ∈ U and is zero}
Ac = {x|x ∈ U and is not an integer}
Ac = {x|x ∈ U and is an even positive integer}
Answer: Choice D) set of even integers
=======================================================
Explanation:
U = universal set = {all positive integers} = {1, 2, 3, 4, 5, ...}
A = {stuff in set U that is odd} = {1, 3, 5, 7, 9, ...}
[tex]A^c[/tex] = {stuff in set U but NOT from set A} = {2, 4, 6, 8, ...}
[tex]A^c[/tex] = {set of even numbers from set U}
In set theory, the complement is simply the complete opposite. If the number 7 is found in set A for instance, then 7 is not going to live in the complement [tex]A^c[/tex]
The opposite of the odd numbers is the set of even numbers.
Therefore, we go for choice D as our final answer.
Side note: if we union set A with its complement [tex]A^c[/tex] then we get the universal set as a result. [tex]A \cup A^c = \text{universal set} = \text{set of all positive integers}[/tex]
The solution is Option D.
Ac = {x|x ∈ U and is an even positive integer} where Ac represents the complement of set A
What is union and intersection of sets?
The union of two sets A and B is the set of all those elements which are either in A or in B, i.e. A ∪ B, whereas the intersection of two sets A and B is the set of all elements which are common. The intersection of these two sets is denoted by A ∩ B
The union of two sets is a new set that contains all of the elements that are in at least one of the two sets
The intersection of two sets is a new set that contains all of the elements that are in both sets
Given data ,
Let the set U be = {all positive integers}
So , the values of set U = { 1 , 2 , 3 , 4 , 5 .. }
And , let the set A = {x|x ∈ U and x is an odd positive integer}
So , the value of set A = { 1 , 3 , 5 , 7 , ... }
And , the complement of set A is Ac
The value of set Ac is all the even positive odd integers
So , the value of set Ac = { 2 , 4 , 6 , 8 .. }
Therefore , the value of set Ac = { 2 , 4 , 6 , 8 .. }
Hence , the set Ac = {x|x ∈ U and is an even positive integer}
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1. At which point do Line CF and Line GF intersect? They intersect at point?
2. Look at Line AD and Like BE. Do these lines intersect?
(a) yes they will intersect at Point F?
(b) no they will never intersect?
(c) yes they will point at Point G
(d) yes they will intersect at Point F?
3. Look at Line BG and Line AC. Where do they intersect? They intersect at Point?
(Please hurry giving 50 points!)
Answer: i think no?
Step-by-step explanation:
AD and BE are both parallel lines (they are parallel to eachother), so they will never intersect
CF and GF intersect at point F (i think)
Bg and Ac intersect at point B (i think)
i dont want to give a definite answer in the event im wrong bc I just learned this like a few weeks ago-
How many dogs were in the sample?
each number under the leaves section would be a dog
answer: 11
Answer:
11
Step-by-step explanation:
PLEASE HELP ASAP!!!!!!!1
Consider the series 1/4+3/2+11/4+4+21/4+....
Does the series converge or diverge?
Select answers from the drop-down menus to correctly complete the statements.
The series _____ (diverges or converges). You Consider conclude this because the series is _________ (Arithmetic, Geometric and the absolute value of the common ratio is greater than 1, Geometric and the absolute value of the common ratio is less than 1, neither arithmetic nor geometric)
The series diverges. You Consider concluding this because the series is in arithmetic progression.
What is an arithmetic sequence?An arithmetic sequence is a sequence of integers with its adjacent terms differing with one common difference.
The explicit formula for any arithmetic series is given by the formula,
[tex]a_n = a_1 + (n-1)d[/tex]
where d is the difference and a₁ is the first term of the sequence.
The given series of numbers 1/4+3/2+11/4+4+21/4+.... is an arithmetic series because the difference between any two consecutive terms is 5/4. Therefore, the blanks can be filled as,
The series diverges. You Consider conclude this because the series is in arithmetic progression.
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could i get help with this equation?
Answer:
10
Step-by-step explanation:
use PEMDAS
PEMDAS order is Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).
2[32 — (4 − 1)³] =
2[32 — (3)³] =
2[32 — 27] =
2[5] =
10
khanacademy
Let a population consist of the values cigarettes, cigarettes, and cigarettes smoked in a day. Show that when samples of size 2 are randomly selected with replacement, the samples have mean absolute deviations that do not center about the value of the mean absolute deviation of the population. What does this indicate about a sample mean absolute deviation being used as an estimator of the mean absolute deviation of a population?.
Based on the given mean absolute deviations, the sample mean absolute deviation will be 2 and the population mean absolute deviation will be 3.8.
What is the sample mean absolute deviation?= Sum of sample mean absolute deviation / Number
= (0 + 0.5 + 4.5 + 0.5 + 0 + 4 + 4.5 + 4 + 0) / 9
= 2
What is the population mean absolute deviation:First find the population mean:
= (10 + 11 + 19) / 3
= 13.3
Population mean absolute deviation:
= 1/3 x ( (10 - 13.67) + (11 - 13.3) + (19 - 13.3))
= 3.8
We can therefore see that the sample mean deviations is a biased estimate of the population mean absolute deviation.
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which of the following is a Monomail
Reason:
sorry but here is no options so I am giving you a example so that you can understand by your own!
Answer;
5r+3
2x-6
X4+10
4y-1
Step by step answer;
So the method of identifying the Monomail is if you see a variable in a constant so it is a Monomail !
Mark as brainlest answerWhich of the following sets of data will have the smallest Standard Deviation?
1, 6, 2, 100, 4, 0, 0, 0, 0, 1
3, 33, 103, 4, 122, 1, 0, 245, 7, 99
1, 2, 3, 4, 5, 6, 7, 8, 8, 9
79, 79, 79, 79, 79, 79, 79, 79, 79, 79
Answer:
Step-by-step explanation:
The last one: 79, 79, 79, 79, 79, 79, 79, 79, 79, 79 because there isn't any difference in the numbers.
S.D.: 0
The probability distribution for a random variable x is given in the table. Probability Find the probability that x=-10
Answer:.20
Step-by-step explanation:
According to what are written in the table the probability for x=-10 is .20
If f(x) = 2x^2+3 and g(x)= 5x, evaluate the following: a. f(g(x)) b. g(g(3)) c. g(f(-2))
Answer:
A = 50x^2+3
B = 75
C = 55
Step-by-step explanation:
[tex]f(x)=2x^2+3\\g(x)=5x[/tex]
A. f(g(x))
[tex]2(5x)^2+3\\2(25x^2)+3\\=50x^2+3[/tex]
B. g(g(3))
[tex]5(5(3))\\5(15)\\=75[/tex]
C. g(f(-2))
[tex]g(2(-2)^2+3)\\g(8+3)\\g(11)\\5(11)\\=55[/tex]
How do you write an effective explanation to explain this problem?
The error happens in the last line.
The relevant log rule is ln(A) - ln(B) = ln(A/B)
The issue is that the 0 isn't ln(0), so that 0 cannot be thrown into the natural log like that.
What we can do is this set of steps
ln(3x) - 0
ln(3x) - ln(1)
ln(3x/1) ... applying the log rule mentioned
ln(3x)
But these steps are a needlessly overcomplicating things. We can simply go from ln(3x)-0 to ln(3x) in one step. Subtracting off zero doesn't change ln(3x) at all.
--------------------------
Let's continue the steps to solve for x.
ln(x^2) = ln(3x)
x^2 = 3x
x^2-3x = 0
x(x-3) = 0
x = 0 or x-3 = 0
x = 0 or x = 3
Those are the two possible solutions.
However, x = 0 isn't valid because it's not in the domain of ln(x^2). In other words, ln(0) isn't defined. The domain of y = ln(x) is x > 0
This means that x = 3 is the only solution.
Evaluate the definite integral from pi/2 to put of cos theta/sqrt 1+ sin theta.
Answer:
[tex]\textsf{B.}\quad -2(\sqrt{2}-1)[/tex]
Step-by-step explanation:
Given integral:
[tex]\displaystyle \int^{\pi}_{\frac{\pi}{2}}\dfrac{\cos \theta}{\sqrt{1+ \sin \theta}}\:\:d\theta[/tex]
Solve by using Integration by Substitution
Substitute u for one of the functions of [tex]\theta[/tex] to give a function that's easier to integrate.
[tex]\textsf{Let }u=1+\sin \theta[/tex]
Find the derivative of u and rewrite it so that [tex]d \theta[/tex] is on its own:
[tex]\implies \dfrac{du}{d \theta}=\cos \theta[/tex]
[tex]\implies d \theta=\dfrac{1}{\cos \theta}\:du[/tex]
Use the substitution to change the limits of the integral from [tex]\theta[/tex]-values to u-values:
[tex]\textsf{When }\theta=\pi \implies u=1[/tex]
[tex]\textsf{When }\theta=\dfrac{\pi}{2} \implies u=2[/tex]
Substitute everything into the original integral and solve:
[tex]\begin{aligned}\displaystyle \int^{\pi}_{\frac{\pi}{2}}\dfrac{\cos \theta}{\sqrt{1+ \sin \theta}}\:\:d\theta & =\int^{1}_2}\dfrac{\cos \theta}{\sqrt{u}}\:\cdot \dfrac{1}{\cos \theta}\:\:du\\\\& =\int^{1}_{2}\dfrac{1}{\sqrt{u}} \:\:du \\\\& =\int^{1}_{2} u^{-\frac{1}{2}}\:\:du \\\\& = \left[ 2u^{\frac{1}{2}} \right]^{1}_{2}\\\\& = \left(2(1)^{\frac{1}{2}}\right)-\left(2(2)^{\frac{1}{2}}\right)\\\\& = 2-2\sqrt{2}\\\\& = -2(\sqrt{2}-1)\end{aligned}[/tex]
2. analyze the data you gathered about the number of births in the united states in 2011.
a. what do you observe about michigan and florida? justify your conclusion by using the cartogram. (5points)
b. there were 4,008,000 births in the united states during 2011. what proportion of all national births are accounted for by michigan? what proportion of all national births are accounted for by florida? (5 points)
c. suppose a person born during 2011 in the united states is chosen randomly. is the person more likely to have been born in florida or michigan? explain. (5 points)
d. the population of the united states was 308,745,538 in 2011. there were 18,801,310 people in florida and 9,883,640 people in michigan. compute the probability that a randomly selected us resident in 2011 was living in florida. do the same for michigan. which is greater? (5 points)
e. the number of births in a region depends mostly on population size. there are also random fluctuations and regional differences. consider your answers about populations and birth rates. are your answers consistent with this fact? (5 points)
The figures show that the number of births for Florida and Michigan reduced
How to compute the probability?From the data sourced, the number of births in Florida in 2010 was 214519 while in 2011, it was 213237. For Michigan, there was decrease from 114717 to 114159.
When a person born during 2011 in the United States is chosen randomly, the person is more likely to have been born in Florida.
The probability that a randomly selected us resident in 2011 was living in Florida will be:
= 18,801,310/308,745,538
= 0.061
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3. Error Analysis A classmate began an indirect
proof as shown below. Explain and correct
your classmate's error.
Given: AABC
Prove: LA is obtuse.
Assume temporarily that LA is acute.
The diagonals of a rhombus are: A. are the same length and intersect at different angles B. bisect each other at right angles C. bisect each other and intersect at different angles D. are the same length and intersect at a right angle
Answer:
Step-by-step explanation:
Comment
Either you know the answer to this or you don't. There is no point in eliminating the wrong answers until you get to the right one. It is better to get to the right one immediately.
A rhombus and its diagonals have many interesting properties. This one is one of those properties. The diagonals are not the same length. The diagonals bisect each other at right angles.
Answer: B
Solve the equation for x by graphing.
-2x − 3 = 3x + 2
If f(x)=7^x and g(x)=15x/x+9, find a simplified formula for: g(f(x))=
Answer:
[tex]\frac{15*7^{x} }{7^{x} +9}[/tex]
Step-by-step explanation:
→ Substitute f(x) into g(x)
[tex]\frac{15*7^{x} }{7^{x} +9}[/tex]
The enrollment for a new program is 1,500 students. the program is expected to grow at a rate of 0.03. what is the expected enrollment in 7 years? round to the nearest whole number.
The expected enrolment in 7 years is 1845.
What is the expected enrolment?The formula for calculating future value of the number of students is an exponential equation with this form:
FV = P (1 + r) ^n
FV = Future populationP = Present populationR = rate of growth of the populationN = number of years1500 x (1.03)^7 = 1845
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Nadine had 20 minutes to do a three-problem quiz. She spent 10 7/10 minutes on question A and 6 2/5 minutes on question B. How much time did she have left for question C?
A rectangular prism has a length of 8 in., a width of 4 in., and a height of 2 1/4 in.
The prism is filled with cubes that have edge lengths of 14 in.
How many cubes are needed to fill the rectangular prism?
Enter your answer in the box.
To fill the rectangular prism,
cubes are needed.
The number of cubes needed to fill the rectangular prism 4608 cubes.
How to find volume of rectangular prism and cube?volume of rectangular prism = lwh
where
l =lengthw = widthh = heightTherefore,
volume of the rectangular prism = 8 × 4 × 9 / 4 = 72 inches³
volume of the cube = l³
where
l = lengthTherefore,
volume = (1 / 4)³
volume of the cube = 1 / 64 inches³
Therefore,
The number of cubes needed to fill the rectangular prism = 72 ÷ 1 / 64
The number of cubes needed to fill the rectangular prism = 72 × 64 = 4608
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The presence of a midpoint will result in what type of segments?
Answer: two congruent segments.
Step-by-step explanation:
idlk im not smart
Hi, could you help me with this substitution question?
I'd really appreciate if you added workings out as I'm terribly confused.
Thanks,
Answer:
[tex]-\dfrac{69}{14}[/tex]
Step-by-step explanation:
Substitute the given values of the variables into the given expression:
[tex]\implies \dfrac{60 \left(\dfrac{1}{3}\right)\left(-\dfrac{1}{5}\right)\left(\dfrac{1}{4}\right)\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{4}\right)}{\left(\dfrac{1}{3}-\dfrac{1}{5}\right)\left(\dfrac{1}{3}+\dfrac{1}{4}\right)}[/tex]
When multiplying fractions, simply multiply the numerators and the denominators:
[tex]\implies \dfrac{60 \left(\dfrac{1 \cdot -1 \cdot 1}{3\cdot 5 \cdot 4}\right)\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{4}\right)}{\left(\dfrac{1}{3}-\dfrac{1}{5}\right)\left(\dfrac{1}{3}+\dfrac{1}{4}\right)}[/tex]
[tex]\implies \dfrac{60 \left(-\dfrac{1}{60}\right)\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{4}\right)}{\left(\dfrac{1}{3}-\dfrac{1}{5}\right)\left(\dfrac{1}{3}+\dfrac{1}{4}\right)}[/tex]
[tex]\implies \dfrac{\left(-1\right)\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{4}\right)}{\left(\dfrac{1}{3}-\dfrac{1}{5}\right)\left(\dfrac{1}{3}+\dfrac{1}{4}\right)}[/tex]
When adding or subtracting fractions, make the denominators the same:
[tex]\implies \dfrac{\left(-1\right)\left(\dfrac{20}{60}-\dfrac{12}{60}+\dfrac{15}{60}\right)}{\left(\dfrac{5}{15}-\dfrac{3}{15}\right)\left(\dfrac{4}{12}+\dfrac{3}{12}\right)}[/tex]
Now add the numerators and put that over the denominator:
[tex]\implies \dfrac{\left(-1\right)\left(\dfrac{20-12+15}{60}\right)}{\left(\dfrac{5-3}{15}\right)\left(\dfrac{4+3}{12}\right)}[/tex]
[tex]\implies \dfrac{\left(-1\right)\left(\dfrac{23}{60}\right)}{\left(\dfrac{2}{15}\right)\left(\dfrac{7}{12}\right)}[/tex]
Again, multiply the fractions:
[tex]\implies \dfrac{\left(-1 \cdot \dfrac{23}{60}\right)}{\left(\dfrac{2 \cdot 7}{15 \cdot 12}\right)}[/tex]
[tex]\implies \dfrac{-\dfrac{23}{60}}{\dfrac{14}{180}}[/tex]
To divide the fractions, turn the second fraction upside down, then multiply it by the first fraction:
[tex]\implies -\dfrac{23}{60} \cdot \dfrac{180}{14}[/tex]
[tex]\implies -\dfrac{4140}{840}[/tex]
Finally, simplify:
[tex]\implies -\dfrac{4140 \div 60}{840 \div 60}[/tex]
[tex]\implies -\dfrac{69}{14}[/tex]
Identify angles with terminology
I need help I’ve been stuck for hours
