The type of solutions which are appearing cloudy are called colloids. Therefore, option a is correct.
What are colloids ?Colloids are mixtures in which particles of one substance are evenly dispersed throughout another substance, creating a stable mixture. The particles in a colloid are larger than those found in a solution, but smaller than those found in a suspension.
Colloids can be found in various states of matter, including solid, liquid, and gas, and they can be formed from a wide range of substances, such as polymers, metals, and biological molecules.
One important characteristic of colloids is their ability to scatter light. This phenomenon, known as the Tyndall effect, occurs when light passes through a colloid and is reflected by the particles, causing the mixture to appear cloudy or hazy.
Colloids also exhibit unique properties related to their size and shape, such as viscosity, surface tension, and Brownian motion. They appear cloudy in nature.
Find more on colloids:
https://brainly.com/question/25118068
#SPJ3
During electrophilic aromatic substitution, a resonance-stabilized cation intermediate is formed. Groups, already present on the benzene ring, that direct ortho/para further stabilize this intermediate by participating in the resonance delocalization of the positive charge. Assume that the following group is present on a benzene ring at position 1 and that you are brominating the ring at positon 4. In the box below draw the structure of the resonance contributor that shows this group actively participating in the charge delocalization. -OCH3 • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • Do not include lone pairs in your answer. They will not be considered in the grading.
Answer:
See explanation
Explanation:
In electrophillic aromatic substitution, an electrophile attacks the aromatic ring and resonance structures are created.
We know that the nature of the substituents already present in the ring determines the position to which the incoming substituent is directed.
-OCH3 is an ortho-para director. If the -OCH3 is present at position 1 and the ring is brominated at position 4, the resonance structures shown in the image attached are observed.
Are there any types of tissues that you think humans might have that are similar to plant’s vascular tissues? Help please
The types of tissues that you think humans might have that are similar to plant’s vascular tissues - is connective tissues of circulatory tissues.
A plant's vascular tissues transport nutrients throughout the plant, just as the circulatory system transports nutrients throughout the human body.
Vascular tissue is comprised of the xylem and the phloem, the main transport systems of plants.Xylem - transport of water and dissolved ions from the roots upwards through the plant.Phloem - transport of nutrients from leaves to other body parts.Connective tissue in the human :
is of four types mainly; blood, bones, cartilage, and connective tissue proper.Blood is the connective tissue that transports gases, nutrients.Blood also transports waste or toxic moleculesThus, the types of tissues that you think humans might have that are similar to plant’s vascular tissues - is connective tissues of circulatory tissues.
Learn more about the circulatory system:
https://brainly.com/question/22258254
how many electrons does chlorine need to gain to become an ion? will it become positively charged cation or negatively charged anion?
Which is mainly responsible for preventing erosion?
A) Mining
B) Farming
c) Rooting of Plants
D) Logging
Answer:
B. Farming
Explanation:
Plz help it over science stuff
The map shows the average high temperatures in July for two cities in Texas.
Average July High Temperatures
Texas
Del Rio
36°C
Galveston
32°C 12
Answer:
Highest temperature which was recorded in Texas was 40 degrees.
Explanation:
Texas has variating weather. In summer Texas city turns to be very hot and during winters the city of Texas experience fall in temperature. There is very few rainfall in Texas due the climatic conditions.
Find the molarity of the following solution:
734 grams of lithium sulfate (Li2SO4) is dissolved to make 2.5 liters of solution.
Answer:
2.67 M
Explanation:
Molarity, which is the molar concentration of a substance, can be calculated using the formula;
M = n/V
Where;
M = molarity (M)
n = number of moles (mol)
V = volume (Litres)
Based on the provided information in this question, mass of lithium sulfate (Li2SO4) = 734g, volume = 2.5L
Using mole = mass/molar mass
Molar mass of Li2SO4 = 7(2) + 32 + 16(4)
= 14 + 32 + 64
= 110g/mol
Mole = 734/110
Mole (n) = 6.67moles
Molarity = n/V
Molarity = 6.67/2.5
Molarity = 2.668
Molarity of Li2SO4 in the solution is 2.67 M
Answer:
The molarity of the solution is 2.672[tex]\frac{moles}{liter}[/tex]
Explanation:
Molarity (M) is a way of expressing the concentration of solutions. It is defined as the number of moles of solute per volume of solution. The Molarity of a solution is determined by the following expression:
[tex]Molarity=\frac{number of moles}{volume}[/tex]
Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].
Being the molar mass of Li₂SO₄ 109.94 g/mol, then you can apply the following rule of three: if 109.94 grams are present in 1 mole, 734 grams will be present in how many moles?
[tex]amount of moles=\frac{734 grams*1 mole}{109.94 grams}[/tex]
amount of moles= 6.68 moles
Then:
number of moles= 6.68 molesvolume= 2.5 LReplacing in the definition of molarity:
[tex]Molarity=\frac{6.68 moles}{2.5 L}[/tex]
and solving you get:
Molarity= 2.672[tex]\frac{moles}{liter}[/tex]
The molarity of the solution is 2.672[tex]\frac{moles}{liter}[/tex]
By definition, a(n) _______acid is any species that can donate a proton. Ammonia has a proton bonded to nitrogen, so ammonia can be an base (although a very weak one). A(n)___________ base is a proton acceptor, that is, it must have a pair of electrons to share with a proton. In theory, any atom with an unshared electron pair can be a________ pair so ammonia is a_______ proton; instead, it acts as a base and pulls a proton from water to a small extent. base The nitrogen in ammonia has an unshared electron In water, ammonia is too weak an ______-to give up its
Answer:
A Brønsted-Lowry acid.
A Brønsted-Lowry base.
Ammonia is an acceptor of proton.
Explanation:
A Brønsted-Lowry acid is any atom that can donate a proton (H +) to another atom or molecule whereas Brønsted-Lowry base is any species that can accept a proton from another atom or molecule or in other words, a Brønsted-Lowry acid is a proton donor, while on the other hand, a Brønsted-Lowry base is a proton acceptor. The ammonia molecule accepts the hydrogen ion is considered as the Brønsted-Lowry base.
Find the molecular mass of
MgSO4 7H₂O.
Answer:
MgO +H2SO4
Explanation:
use photomath
What do atoms make up
Which of the following destroys the marine ecosystem?
A. fishpond C. dynamite fishing
B. reclamation D. constructing man-made sanctuaries
Answer:
The correct one is dynamite fishing
Read: https://kids.britannica.com/kids/article/DNA/390730 (Links to an external site.)
Answer the following questions:
1. What sort of things does DNA determine for a creature? (Think physical traits)
2. Sometimes there are mistakes in DNA, what are these mistakes called? what sort of things can these mistakes cause?
3. What makes up the sides of the DNA structure?
4. There are four different bases in DNA: adenine, thymine, guanine, and cytosine. About how many total pairs do humans have in their DNA?
Answer:
im not doing your whole homework. but ill give you one cent ;>, whats ur paypal
Explanation:
You need to produce a buffer solution that has a pH of 4.97. You already have a solution that contains 10. mmol (millimoles) of acetic acid. How many millimoles of acetate (the conjugate base of acetic acid) will you need to add to this solution?
Answer:
16.9 mmoles are needed to add to the solution
Explanation:
To solve this, we can apply the Henderson Hasselbach equation:
Acetic acid → CH₃COOH
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺ Ka
That is the acid base equilibrium, to determine the amount:
pKa of acetic acid is 4.74
Henderson Hasselbach formula is:
pH = pKa + log (base/acid)
We replace → 4.97 = 4.74 + log (B / 10mmoles)
Let's verify mmoles of B
4.97 - 4.74 = log (B/10)
0.23 = log (B/10)
10^(0.23) = 10^(log (B/10)
1.698 = B/10
B = 1.698 . 10 → 16.9 mmoles
HELPPPPPPPPPPPPPPPPPPPPPP PLZ
While cleaning my room, I use 5 Newtons of force to lift a board game from the floor to the shelf in my closet that's 2 meters high. How much work was done on the board game?
10 Joules
10 Watts
2.5 Watts
2.5 Joules
10 joules
hope that helps^^
Answer:
10 joules im not sure tho
The average adult heart pumps about 84./mLs of blood at 72 beats per minute. Suppose you need to calculate how long it would take the average heart to circulate 1700.mL of blood. Set the math up.
Answer:
1700 mL / 84 mLs
Explanation:
Given that:
Volume of blood pumped per minute = 84 /mLs
Time it takes to circulate 1700 mL of blood :
Time taken = Volume of blood circulate / Rate
Hence, to circulate 1700 mL of blood :
Time taken = 1700 mL / 84 mLs
how many grams of na2co3 would be needed to produce 1000g of nahco3
Answer:
630.95 grams of Na₂CO₃ would be needed to produce 1000g of NaHCO₃
Explanation:
The balanced reaction is:
Na₂CO₃ + CO₂+ H₂O → 2 NaHCO₃
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
Na₂CO₃: 1 moles CO₂: 1 moleH₂O: 1 mole NaHCO₃: 2 molesBeing the molar mass:
Na₂CO₃: 106 g/moleCO₂: 44 g/moleH₂O: 18 g/moleNaHCO₃: 84 g/moleThen by stoichiometry the following quantities of mass participate in the reaction:
Na₂CO₃: 1 mole* 106 g/mole= 106 gCO₂: 1 mole* 44 g/mole= 44 gH₂O: 1 mole* 18 g/mole= 18 gNaHCO₃: 2 moles* 84 g/mole= 168 gYou can apply the following rule of three: if 106 grams of Na₂CO₃ are needed to produce 168 grams of NaHCO₃, how much mass of Na₂CO₃ is necessary to produce 1000 grams of NaHCO₃?
[tex]mass of Na_{2} CO_{3}=\frac{1000grams ofNaHCO_{3} *106gramsofNa_{2} CO_{3} }{168grams ofNaHCO_{3}}[/tex]
mass of Na₂CO₃= 630.95 grams
630.95 grams of Na₂CO₃ would be needed to produce 1000g of NaHCO₃
Number of atoms in 2.56 moles of He
1.54 × 10²⁴ atoms He
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
MolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Stoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[Given] 2.56 moles He
[Solve] atoms He
Step 2: Identify Conversion
Avogadro's Number
Step 3: Convert
[DA] Set up: [tex]\displaystyle 2.56 \ mol \ He(\frac{6.022 \cdot 10^{23} \ atoms \ He}{1 \ mol \ He})[/tex][DA] Multiply/Divide [Cancel out units]: [tex]\displaystyle 1.54163 \cdot 10^{24} \ atoms \ He[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
1.54163 × 10²⁴ atoms He ≈ 1.54 × 10²⁴ atoms He
2H2(g)+O2(g)→2H2O(l)
What is the mass of water, H2O(l) , produced when 5.70 g of O2(g) reacts with excess H2(g)?
Answer:
6.4g
Explanation:
32g of O2 produce 36g of H2O/5.70g of O2 produce x the answer is 6.4g
I need help plz quick on my homework its due at 11 i will give branliest to correct answer its on limiting reagents.
Answer:4.2 6.4 6.7 9.5 5.5 3.8
Explanation:
The following conditions must be met before a standard calibration curve equation can be used to solve for the concentration of an unknown solution:
a. The same instrument must be used to measure the unknown solution as was used to measure the known (standard) solutions that were used to create the calibration curve.
b. The analyte in the unknown solution must be the same analyte (or type of analyte) that is present in the known (standard) solutions that were used to create the calibration curve.
c. The equation from the calibration curve can only be linear.
d. Domain and range restrictions must be observed.
Answer:
The same instrument must be used to measure the unknown solution as was used to measure the known (standard) solutions that were used to create the calibration curve.
The analyte in the unknown solution must be the same analyte (or type of analyte) that is present in the known (standard) solutions that were used to create the calibration curve.
Domain and range restrictions must be observed.
Explanation:
Calibration curves are tools necessary in understanding the instrumental response for any analyte.
A calibration curve is obtained by preparing a set of standard solutions with known concentrations of the analyte. The instrument response for each concentration is measured and plotted against the concentration of the standard solution. The linear portion of this plot may be used to determine the unknown concentration of a sample of the analyte.
The equation of the best-fit line is used to determine the concentration of the unknown sample.
Complete the following reaction: Li + S -->
Answer:
Li2S
Explanation:
Hope this helps.
Answer:
can u do an real answer pls so i can help u thanks
Calculate the volume in liters of a 0.72 M aluminum sulfate solution that contains 75.0 g of aluminum sulfate Al2SO43.
Answer:
0.30 L
Explanation:
First we convert 75.0 g of Al₂(SO₄)₃ into moles, using its molar mass:
75.0 g ÷ 342.15 g/mol = 0.219 mol Al₂(SO₄)₃Then we can calculate the volume of the solution, by using the definition of molarity:
Molarity = moles of solute / liters of solution0.72 M = 0.219 mol / VolumeWe solve for Volume:
Volume = 0.30 LExplain why fluorine and chlorine are in the same group of the periodic table.
Give the electronic structures of fluorine and chlorine in your explanation.
Answer:
They both have 7 electrons in their outer shell
Consider the following chemical equilibrium:
2H2(g) + O2 ⇌ 2H2O(l)
Now write an equation below that shows how to calculate Kc from Kp for this reaction at an absolute temperature . You can assume is comfortably above room temperature.
Answer:
hmm i dont know but i can try mate!
How many moles of N2 is 25.92g of N2?
Explanation:
number of moles = mass /relative molecular mass
n = 25,92/mr(N2)
n=25,92/14×2
n=25,92/28
n=0.93moles
Each polysaccharide tested gives different color results with the iodine test
How many atoms are in phosgene
Answer:
3 atoms
Explanation:
there is one calcium and two chlorine
Suppose you perform a calorimeter experiment to determine the molar heat of neutralization of an unknown acid, H A HA, with sodium hydroxide, N a O H NaOH. You mix 37.2 mL of 0.50 M H A HA with 56.8 mL of 0.75 M N a O H NaOH and calculate the heat of reaction as -1.6 kJ. What is the molar heat of neutralization (in kJ/mol) for the unknown acid
Answer:
-86.02 kJ/ mole
Explanation:
The moles of the acid used = Molarity × Volume (L) =
= 0.50 (0.0372 L)
= 0.0186 moles
The heat released = -1.6 kJ
∴ 0.0186 moles neutralization of HA heat is: -1.6 kJ
The molar heat of neutralization due to one mole of the unknown acid = -1.6/0.0186
= -86.02 kJ/ mole
The molar heat of neutralization for the unknown acid is -86.02 kJ/ mole.
How to calculate Moles?The moles of the acid used = Molarity × Volume (L) =
= 0.50 (0.0372 L)
= 0.0186 moles
Thus, the moles of the acid used is 0.0186.
The heat released = -1.6 kJ
Thus, 0.0186 moles neutralization of HA heat is: -1.6 kJ
Molar heat of Neutralization: It is the amount of heat each mole of base added to the acid (or vice versa) causes the reaction to give off.
The molar heat of neutralization due to one mole of the unknown acid = [tex]\frac{-1.6}{0.0186}=-86.02kJ/mole[/tex]
So, the molar heat of neutralization is -86.02kJ/mole.
Find more information about Moles here:
brainly.com/question/13314627
A chemistry student is given 700. mL of a clear aqueous solution at 26.° C. He is told an unknown amount of a certain compound X is dissolved in the solution. The student allows the solution to cool to 26.° C. The solution remains clear. He then evaporates all of the water under vacuum. A precipitate remains. The student washes, dries and weighs the precipitate. It weighs 0.032 kg.
Required:
Using only the information above, can you calculate the solubility of X in water at 22.0°C ? If you said yes, calculate it. Be sure your answer has a unit symbol and 2 significant digits.
Answer:
The correct answer is - yes, 4.57 g of solute per 100 ml of solution
Explanation:
The correct answer is yes we can calculate the solubility of X in the water at 22.0°C. The salt will remain after the evaporate from the dissolved and cooled down at 26°C.
Then, the amount of solute dissolved in the 700 ml solution at 26°C is the weighed precipitate: 0.032 kg = 32 g.
Then solublity will be :
32. g solute / 700 ml solution = y / 100 ml solution
⇒ y = 32. g solute × 100 ml solution / 700 ml solution = 4.57 g.
Thus, the answer is 4.57 g of solute per 100 ml of solution.
Ethical Behavior Worksheet Situation 1. You are taking a very difficult chemistry course, which you must pass to maintain your scholarship and to avoid damaging your application for graduate school. Chemistry is not your strong suit, and, because of a just-below-failing average in the course, you will have to receive a grade of 90 or better on the final exam, which is two days away. A janitor, who is aware of your plight, informs you that he found the master for the chemistry final in a trash barrel and has saved it. He will make it available to you for a price, which is high but which you could afford. What would you do?
Answer:
I would not accept it.
Explanation:
Although it is tempting to accept the janitor's offer and save the scholarship, which is not easy to get, I would not accept his offer, as I do not believe in victories based on dishonesty and would be heavy on conscience if I did the opposite. Obviously, I would not like to lose my scholarship and for that reason, I would look for other ways that would be honest and help me improve my grade. If I could not improve and lose the scholarship, I would be extremely sad, but I would be at peace with my conscience.
