Which statements are true for the functions g(x) = x2 and h(x) = –x2 ? Check all that apply.

For any value of x, g(x) will always be greater than h(x).
For any value of x, h(x) will always be greater than g(x).
g(x) > h(x) for x = -1.
g(x) < h(x) for x = 3.
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).

Answers

Answer 1

For the given function, any value of x, g(x) will always be greater than h(x). FALSE. For any value of x, h(x) will always be greater than g(x). FALSE. g(x) > h(x) for x = -1. TRUE. g(x) < h(x) for x = 3. TRUE. For positive values of x, g(x) > h(x). TRUE. For negative values of x, g(x) > h(x). FALSE

What is function?

In mathematics, a function is a rule that assigns a unique output value to each input value. It is a relationship between a set of inputs and a set of possible outputs, where each input has exactly one corresponding output.

According to given information:

The statements are related to the comparison between the functions [tex]g(x) = x^2\ and\ h(x) = -x^2.[/tex]

For any value of x, g(x) will always be greater than h(x). FALSE

This statement is false because for negative values of x, h(x) will be greater than g(x). For example, if x = -2, then g(x) = 4 and h(x) = -4.

For any value of x, h(x) will always be greater than g(x). FALSE

This statement is false for the same reason as statement 1.

g(x) > h(x) for x = -1. TRUE

This statement is true because g(-1) = 1 and h(-1) = -1, and 1 > -1.

g(x) < h(x) for x = 3. TRUE

This statement is true because g(3) = 9 and h(3) = -9, and 9 < -9.

For positive values of x, g(x) > h(x). TRUE

This statement is true because for any positive value of x, g(x) will always be positive and h(x) will always be negative, and any positive number is greater than any negative number.

For negative values of x, g(x) > h(x). FALSE

This statement is false because for negative values of x, h(x) will be greater than g(x), as explained in statement 1.

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Answer 2

Answer: C, E, F

Step-by-step explanation:


Related Questions

Evaluate the integral ∫∫ D (4x+2) dA where D is the region is bounded by the curves y=x^2 and y=2x. (7 marks, C3)

Answers

To evaluate the integral ∫∫ D (4x+2) dA over the region D bounded by the curves y=x^2 and y=2x, we can use a double integral in terms of x and y:

∫∫ D (4x+2) dA = ∫[0,2]∫[y/2,√y] (4x+2) dx dy

where the limits of integration for x come from the intersection of the two curves y=x^2 and y=2x.

First, we integrate with respect to x:

∫[y/2,√y] (4x+2) dx = 2x^2 + 2x |[y/2,√y]

= 2y + y√y

Then, we integrate with respect to y:

∫[0,2] (2y + y√y) dy

= (2/3)y^3 + (2/5)y^(5/2) |[0,2]

= (2/3)(2)^3 + (2/5)(2)^(5/2)

= 16/3 + 8/5√2

Therefore, the value of the integral is 16/3 + 8/5√2.

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URGENT!!! Will give brainliest :)

Which statement correctly compares the shapes of the distributions?

A. East Hills HS is negatively skewed, and Southview HS is symmetric.

B. East Hills HS is positively skewed, and Southview HS is symmetric.

C. East Hills HS is positively skewed, and Southview HS is negatively skewed.

D. East Hills HS is negatively skewed, and Southview HS is positively skewed.

Answers

The answer is D. East Hills HS is negatively skewed, and Southview HS is positively skewed.

How to determine the statement correctly compares the shapes of the distributions

In order to compare the shapes of the distributions, we need to look at the skewness of the distributions.

Skewness is a measure of the asymmetry of a probability distribution. A distribution is said to be negatively skewed if the tail on the left-hand side of the probability density function is longer or fatter than the right-hand side. Conversely, a distribution is said to be positively skewed if the tail on the right-hand side of the probability density function is longer or fatter than the left-hand side.

Based on the answer choices, we can eliminate options B and C, as they both indicate that one of the distributions is symmetric, which is not possible if the other is skewed.

Now, we need to determine which distribution is positively skewed and which is negatively skewed.

Option A indicates that East Hills HS is negatively skewed, and Southview HS is symmetric. This is not possible since a negatively skewed distribution cannot be symmetric.

Option D indicates that East Hills HS is negatively skewed, and Southview HS is positively skewed. This is a valid comparison since it is possible for one distribution to be negatively skewed while the other is positively skewed.

Therefore, the correct answer is D. East Hills HS is negatively skewed, and Southview HS is positively skewed.

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The symphony venue at a local community center has specialized acoustic tiles that eliminate any sounds greater than 16 kHz (16,000 hertz). During the next concert, a piece will be performed that features only French horns and piccolos. A single French horn produces 850 Hz, and a single piccolo produces 3,850 Hz. There are 4 French horns in the symphony.


A) Write an inequality expressing the possible number of piccolos that could perform allowing the audience to hear every note.B) Determine the maximum number of piccolos allowed to perform this piece. Assume the sound produced by the instruments is cumulative.

Answers

a) Note that the inequality  expressing the possible number of piccolos that could perform allowing the audience to hear every note  is given as: 3,850x ≤ 16,000

b) the maximum number of piccolos allowed to perform this piece is 4.16 or approximately 4.

How did we arrive at the above?

A) Where the above conditions are given, let us call the number of piccolos "x" as the number that can perform in a way that the audience will hear all the notes pplayed.

Recall that specialized acoustic tiles that eliminate any sounds greater than 16 kHz that means, all the frequencies put together must  nevr exced 16kHz. Thus,

the inequality will be 3,850x ≤ 16,000


B) To determine the maximum number of piccolos:

we must solve for x in the above equation:

3,850x ≤ 16,000

we divide both sides by 3850

3,850x/3850 ≤ 16,000/3850
x ≤ 4.15584415584

Hence, since x cannot be be decimal, that is the number of picollows, we must approximate x to 4

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6) What are vertical angles? What is
the sum of all the angles of a triangle?

Answers

Two angles that form two pairs of opposing rays are called vertical angles. A triangle's total angles are always equal to 180 degrees.

What is an opposite ray?

Two rays that originate from the same location and go in completely different directions are said to be opposing rays. As a result, the two rays combine to form a single straight line that passes through the shared terminal Q2.

Two angles that form two pairs of opposing rays are called vertical angles. These might be considered as the opposing angles of an X.

A triangle's total angles are always equal to 180 degrees. This indicates that the outcome will be as follows if we sum the measurements of all three angles of a triangle

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The formula e^2Ïiâ1=0 follows from Euler's formula.
a. true b. false

Answers

The answer is A: true

The time (in years) until the first critical-part failure for a certain car is exponentially distributed with a mean of 3.2 years. Find the probability that the time until the first critical-part failure is less than 1 year.

Answers

For an exponential distribution of time (in years) until part failure for a certain car, probability that the time until the first critical-part failure is less than 1 year is equals to the 0.2684.

The exponential distribution is a type of continuous probability distribution that is used to measure the expected time for an event to occur. Formula for it is

[tex]f(X) = \lambda e^{-\lambda x} ; X>0[/tex], where [tex]\lambda [/tex]--> rate parameter

x --> observed value

We have time ( in year) first critical-part failure for a certain car is exponentially distributed. Let X be the time until the first critical part failure for a certain car. Now, X follows Exponential distribution with mean 3.2 years. The probability density function of X is [tex]f(X) = \lambda e^{ - \lambda x} ; X>0 [/tex]

Here in this problem, [tex] \lambda =\frac{1}{3.2} [/tex] = 0.3125

Using the formula the probability of X less than 1 is P(X< 1) = [tex]1 - e^{ - 0.3125×1}[/tex]

P(X< 1 ) = 1 - 0.745189

P(X<1)= 0.2684

The required probability is 0.2684.

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A gardener buys a package of seeds. Seventy-nine percent of seeds of this type germinate. The gardener plants 110 seeds. Approximate the probability that 84 or more seeds germinate.

Answers

Answer:99% of 110 is 108.9

so your answer is 108.9

Step-by-step explanation:

Because I said so

HW 9 Chain Rule Tangent Planes: Problem 5 Previous Problem Problem List Next Problem (1 point) Find the equation of the tangent plane to the surface z = ly2 – 922 at the point (1, -3,0). Z= Note: Yo

Answers

The equation of the tangent plane to the surface z=ly2-922 at the point (1,-3,0) is z = -27 - 6ly(x-1).

To find the equation of the tangent plane to the surface z=ly2-922 at the point (1,-3,0), we need to first find the partial derivatives of z with respect to x and y.

∂z/∂x = 0

∂z/∂y = 2ly

Next, we need to evaluate these partial derivatives at the given point (1,-3,0), which gives us:

∂z/∂x(1,-3,0) = 0

∂z/∂y(1,-3,0) = -6l

Using these partial derivatives, we can now write the equation of the tangent plane:

z = f(a,b) + ∂f/∂x(a,b)(x-a) + ∂f/∂y(a,b)(y-b)

where f(a,b) is the value of the function at the point (a,b), and (x-a) and (y-b) are the differences between the given point and the point on the tangent plane.

Plugging in the values we found, we get:

z = -27 - 6ly(x-1)

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A lamina occupies the part of the disk z2 + y2 < 25 in the first quadrant and the density at each point is given by the function p(x,y) = 5(x2 + y²). A. What is the total mass? 3125pi/8 D. Where is the center of mass? 1/(2pi) 1/(2pi)

Answers

The total mass is 125π/6.

The Center of Mass is (625/4, 0)

We have a disk

x² + y² ≤25

let (x', y') be the center of Mass

So, x' = [tex](\int\limits_D {x. \rho(x,y)} \, dA[/tex]  / M

and, y' =  [tex](\int\limits_D {y. \rho(x,y)} \, dA[/tex]  / M

where M is the mass of the region

Also, p(x,y) = 5(x2 + y²)

x= r cos [tex]\theta[/tex] and y= r sin [tex]\theta[/tex]

Then, (r cos [tex]\theta[/tex] )² + (r sin [tex]\theta[/tex])² ≤25

r² < 25

r≤5

So, the total Mass is

= ∫ 5(x² + y²) dA

= [tex]\int\limits^{\pi/2}_0 \int\limits^5_ 0{ 5 (r^2 cos^2 \theta + r^2 sin^2 \theta)} \, dr d\theta[/tex]

= [tex]\int\limits^{\pi/2}_0 \int\limits^5_ 0{ 5 r^2 } \, dr d\theta[/tex]

= 5 x 125/3 [tex]\int\limits^ {\pi/2} _0{ d\theta[/tex]

= 5³/3. π/2

= 125π/6

Now, x' = [tex](\int\limits_D {x. \rho(x,y)} \, dA[/tex]  / M

x' = [tex]\int\limits^{\pi/2}_0 \int\limits^5_ 0{ r cos\theta 5 r^2 } \, dr d\theta[/tex]

x' = 5.5³/4

x' = 625/4

and, y' = [tex]\int\limits^{\pi/2}_0 \int\limits^5_ 0{ r sin\theta 5 r^2 } \, dr d\theta[/tex]

y' = 0

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Given f′(x)=12x^2+12x with f(2)=10. Find f(−1).

Answers

The value of f(-1) is 2

What is a function?

A function is defined as a relation between a set of inputs having one output each. In simple words, a function is a relationship between inputs where each input is related to exactly one output. Every function has a domain and codomain or range. A function is generally denoted by f(x) where x is the input. The general representation of a function is y = f(x).

The function is :

[tex]f'(x) = 12x^2+12x[/tex]

We integrate the above function, we get :

[tex]f(x) = 4x^3+6x^2+c[/tex] ....(1)

That's f(x) . so when x = 2 and y = 10 inside this function.

10 = [tex]4(2)^3+6(2)^2+c[/tex]

10 = 32 + 24 + c

10 = 56 + c

10 - 56 = c

c = - 46

Again, We have to find the f(-1)

And, Plug the value of x = -1 in equation (1)

f(-1) = [tex]4(-1)^3+6(-1)^2+c[/tex]

f(-1) = -4 + 6

f(-1) = 2

The original function is therefore [tex]f(x) = 4x^3+6x^2+c[/tex].

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A vector space cannot have more than one basis. true or false

Answers

A vector space can have multiple bases. So the given statement is false.

A vector space can have more than one basis. A basis is a set of linearly independent vectors that spans the entire vector space. A vector space can have infinitely many bases, and each basis may contain a different number of vectors. However, all bases of a vector space will have the same cardinality, which is called the dimension of the vector space.

Therefore, a vector space can have multiple bases.

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What is the least common factor of 4 and 10

Answers

Answer:

Step-by-step explanation:

Least Common Factors of 4 and 10: 1 and 2

Therefore, 1 is the least common factor.

(I am sure you meant Least Common Multiple and not Least Common Factor, as there is no term like that in mathematics. - The Lowest Common Factor would always be 1)

The LCM would be 20

solve for P(B | A). Write the answer as a percent rounded to the nearest tenth
A=16.9%
B=?
P(A & B) = 4.2%

Answers

The probability of B given A is approximately 24.9%.

The probability is typically defined as the proportion of positive outcomes to all outcomes in the sample space. Probability of an event P(E) = (Number of positive outcomes) (Sample space) is how it is written.

We can use the formula for conditional probability to solve for P(B | A):

P(B | A) = P(A & B) / P(A)

Substituting the given values, we get:

P(B | A) = 4.2% / 16.9%

        = 0.2485207100591716

To convert this to a percentage rounded to the nearest tenth, we can multiply by 100 and round to one decimal place:

P(B | A) ≈ 24.9%

Therefore, the probability of B given A is approximately 24.9%.

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Find the numerical value of each expression. (Round your answers to five decimal places.)
(a) sech(0)
(b) coshâ¹(1)

Answers

The numerical value of each expression,

a. sech(0) = 1

b. coshaA¹ = 0.

(a) The hyperbolic secant function, sech(x), is defined as sech(x) = 1/cosh(x). Therefore, sech(0) = 1/cosh(0) = 1/1 = 1.

(b) The inverse hyperbolic cosine function, coshaA¹(x), is defined as the value y such that cosh(y) = x. Therefore, we want to find y such that cosh(y) = 1. Using the definition of the hyperbolic cosine function, we get:

cosh(y) = ([tex]e^y[/tex] + [tex]e^{(-y)}[/tex])/2 = 1

Multiplying both sides by 2 and rearranging, we get:

[tex]e^y[/tex] + [tex]e^{(-y)}[/tex] = 2

Multiplying both sides by [tex]e^y[/tex], we get:

[tex]e^{(2y)}[/tex] - 2[tex]e^y[/tex] + 1 = 0

This is a quadratic equation in [tex]e^y[/tex]. Using the quadratic formula, we get:

[tex]e^y[/tex] = (2 ± √(4 - 4))/2 = 1

Therefore, y = coshaA¹(1) = 0.

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On a recent fishing trip, James caught 25 smallmouth bass (a type of fresh water fish). Suppose it is known the distribution of the weights of smallmouth bass is normal with a mean of 2.5 pounds and a standard deviation of 1.211 pounds. What is the probability that the average weight of the fish caught by James would be greater than 3 pounds?

The posted answer is 1.97% but there is no solution.

Answers

The probability that the z-score is greater than 2.064. Using a standard normal table or calculator, we find that the probability is approximately 1.97%. This means there is a 1.97% chance that the average weight of the fish caught by James would be greater than 3 pounds.

To solve this problem, we can use the central limit theorem, which states that the distribution of the sample means approaches a normal distribution as the sample size increases, regardless of the shape of the population distribution. We can also use the z-score formula to standardize the sample mean.

First, we need to calculate the standard error of the mean (SEM) using the formula:

SEM = standard deviation / square root of sample size
SEM = 1.211 / square root of 25
SEM = 0.2422

Next, we can calculate the z-score using the formula:

z = (sample mean - population mean) / SEM
z = (3 - 2.5) / 0.2422
z = 2.066

Finally, we can use a standard normal distribution table (or a calculator that has a normal distribution function) to find the probability of getting a z-score greater than 2.066. The probability is approximately 0.0197 or 1.97%.

Therefore, the probability that the average weight of the fish caught by James would be greater than 3 pounds is 1.97%.
To answer your question, we need to use the normal distribution and the given information to calculate the probability. Here are the terms you mentioned:

- Smallmouth bass: a type of freshwater fish
- Mean: 2.5 pounds
- Standard deviation: 1.211 pounds
- Number of fish caught by James: 25
- We need to find the probability that the average weight is greater than 3 pounds.

To solve this, we can use the z-score formula for the sample mean:

z = (X - μ) / (σ / √n)

Where:
- X is the sample mean (3 pounds)
- μ is the population mean (2.5 pounds)
- σ is the population standard deviation (1.211 pounds)
- n is the sample size (25 fish)

Calculating the z-score:

z = (3 - 2.5) / (1.211 / √25)
z = 0.5 / (1.211 / 5)
z = 0.5 / 0.2422
z ≈ 2.064

Now, we need to find the probability that the z-score is greater than 2.064. Using a standard normal table or calculator, we find that the probability is approximately 1.97%. This means there is a 1.97% chance that the average weight of the fish caught by James would be greater than 3 pounds.

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If the standard deviation for a Poisson distribution is known to be 3.60, the expected value of that Poisson distribution is:
a. 12.96
b. approximately 1.90
c. 7.2
d. 3.60
e. 8.28

Answers

The expected value of that Poisson distribution is 12.96. So, correct option is A.

The expected value of a Poisson distribution is given by lambda, where lambda is the mean or average number of occurrences in the given interval. In a Poisson distribution, the variance is equal to the mean, so the standard deviation is the square root of the mean.

Thus, if the standard deviation is known to be 3.60, we can find the mean as follows:

Standard deviation = √(mean)

Squaring both sides, we get:

Variance = mean

Substituting the given standard deviation, we have:

3.60 = √(mean)

Squaring both sides again, we get:

12.96 = mean

Therefore, correct option is A.

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a club with 20 women and 17 men needs to choose three different members to be president, vice president, and treasurer. (a) in how many ways is this possible?

Answers

There are 46,620 number of ways to choose three different members to be president, vice president, and treasurer from a club with 20 women and 17 men.

In order to determine the number of ways three different members can be choose for given position are as follows:

1: Calculate the total number of members in the club.

Total members = Women + Men = 20 + 17 = 37

2: Determine the number of ways to choose the president.

Since there are 37 members, there are 37 options for president.

3: Determine the number of ways to choose the vice president.

After the president has been chosen, there are 36 remaining members to choose from for vice president.

4: Determine the number of ways to choose the treasurer.

After choosing both the president and vice president, there are 35 remaining members to choose from for treasurer.

Step 5: Calculate the total number of ways to choose the three different members.

Total ways = Ways to choose president × Ways to choose vice president × Ways to choose treasurer = 37 × 36 × 35 = 46,620

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The Taylor series expansion of some polynomial function g(x,y) about the point (1,2) can be written as follows, 1 - (x - 1) +(y-2) + 2(x - 1)+ 3(0 - 1)(y-2) - (y-2). i) Write down all second order partial derivatives of g at the point (1,2). ii) Write down the gradient of g at the point (1, 2) and find the tangent plane to the surface defined by the equation z = g(x, y) at the point (1,2,1).

Answers

a.In the Taylor series expansion the second-order partial derivatives of g at the point (1,2) are gxx = 2, gyy = -2, and gxy = 3.

b. The gradient of g at the point (1,2) is z = 2x - 2y + 1.

a. To find the second-order partial derivatives of g at (1,2), we take the partial derivatives of each term of the given polynomial expansion. The resulting second-order partial derivatives are d²g/dx²=2, d²g/dy²=-2, and d²g/dxdy=3.

b. To find the gradient of g at (1,2), we take the partial derivatives of g with respect to x and y and evaluate them at (1,2). The resulting gradient is ∇g(1,2) = <1, -1>.

To find the equation of the tangent plane to the surface defined by z=g(x,y) at (1,2,1), we use the point-normal form of a plane equation. The normal vector is the gradient of g at (1,2), so the equation of the tangent plane is (x-1) - (y-2) + z-1 = 0.

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If there are 6 red scrubs and 7 green scrubs, what is the probability that a red scrub is chosen and then another red scrub?

Answers

The probability of choosing a red scrub and then another red scrub is 0.14423 or 14.42%.

To calculate the probability of choosing a red scrub, we first need to know how many red scrubs are in the set. In this case, there are 6 red scrubs out of a total of 13 scrubs. Therefore, the probability of choosing a red scrub is:

Probability of choosing a red scrub = Number of red scrubs / Total number of scrubs

Probability of choosing a red scrub = 6 / 13

Now, we need to calculate the probability of choosing another red scrub after the first one has been chosen. Since one red scrub has already been chosen, there are now only 5 red scrubs left out of a total of 12 scrubs. Therefore, the probability of choosing another red scrub is:

Probability of choosing another red scrub = Number of remaining red scrubs / Total number of remaining scrubs

Probability of choosing another red scrub = 5 / 12

To calculate the probability of both events happening (choosing a red scrub and then another red scrub), we need to multiply the probabilities together. This is known as the multiplication rule of probability.

Probability of both events happening = Probability of the first event x Probability of the second event

Probability of both events happening = (6/13) x (5/12)

Probability of both events happening = 0.14423 or 14.42%

This means that out of all the possible outcomes, there is a 14.42% chance of choosing two red scrubs in a row from a set of 13 scrubs.

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A study was conducted in a school on how students travel to school. Following are the data collected for three methods students use to travel to school: Methods Number of People Carpool 35 Drive 14 Public transport 47 a. Construct a relative frequency table for the provided data. b. What is the probability that a student is not driving to school? c. What is the probability that a student either carpools or drives to school?

Answers

a. relative frequency table can be made by calculating the percentage of students who use each mode of transportation. We may get the answer by dividing the number of people using each technique by the total number of students

Methods          Number of People                 Relative Frequency

Carpool                         35                                              35/96

Drive                         14                                              14/96

Public transport         47                                              47/96

Total                         96                                                1

b. The likelihood that a student takes public transportation or a carpool to get to school is equal to the likelihood that they do not drive.

P(not driving) = P(carpooling) + P(public transport)

P(not driving) = 35/96 + 47/96

P(not driving) = 82/96

P(not driving) = 0.8542 or 85.42%

c. The likelihood that a student will either drive or participate in a carpool to get to school is equal to the likelihoods of both options.

P(carpooling or driving) = P(carpooling) + P(driving)

P(carpooling or driving) = 35/96 + 14/96

P(carpooling or driving) = 49/96

P(carpooling or driving) = 0.5104 or 51.04%

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The measure of an angle is 80°. What is the measure of its supplementary angle?

Answers

Answer:

The answer is 100°

Step-by-step explanation:

supplementary angles are angles that sum up to 180°

x+80=180

x=180-80

x=100°

Answer:

100

Step-by-step explanation:

A supplementary angle have 180°

[tex]x + 80 = 180\\[/tex]

then

[tex]x = 100[/tex]

so the answer is

[tex]100[/tex]

Hope this helps :)

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A journalist created a table of the political affiliation of voters in Ontario (NDP, Conservative, or Other) and whether they favoured or opposed raising taxes.
Raising Taxes
Favour Oppose
NDP 0.09 0.28
Conservative 0.23 0.12
Other 0.14 0.14
Find the probability that a Conservative voter opposed raising taxes.
A. 0.350
B. 0.222
C. 0.540
D. 0.343
E. 0.120

Answers

Rounding to three decimal places, we get 0.343 or approximately 0.222 when expressed as a percentage.

The probability that a Conservative voter opposed raising taxes, we need to look at the second row of the table, which shows the proportions of Conservative voters who favoured or opposed raising taxes.

The proportion who opposed raising taxes is 0.12.
Therefore, the answer is B. 0.222.
To calculate this probability, we simply divide the number of Conservative voters who opposed raising taxes by the total number of Conservative voters:
0.12 / (0.23 + 0.12) = 0.12 / 0.35 = 0.342857
Rounding to three decimal places, we get 0.343 or approximately 0.222 when expressed as a percentage.

This means that there is a 22.2% chance that a Conservative voter opposed raising taxes.

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helpFind the area of the region included between the parabolas y2 = 4(p+1)(x + p + 1), and y2 = 4(p2 + 1)(p2 + 1 - x)

Answers

The area of the region included between the parabolas:  [tex]A = 4 [(2/3)p^2\sqrt{p } + (2/3)\sqrt{p } - (2/5)p^2\sqrt{p}[/tex]

To find the area of the region between the parabolas [tex]y^2 = 4(p+1)(x + p+ 1)[/tex] and [tex]y^2 = 4(p^2 + 1)(p^2 + 1 - x),[/tex]  we need to first graph the two parabolas and determine the intersection points.

Then, we can integrate the difference between the y-coordinates of the two parabolas over the range of x where they intersect.

Let's start by graphing the two parabolas:

[tex]y^2 = 4(p+1)(x + p + 1)[/tex] is a parabola that opens to the right and has its vertex at the point (-p-1, 0).

The distance between the vertex and the focus is p+1, and the distance between the vertex and the directrix is also p+1.

[tex]y^2 = 4(p^2 + 1)(p^2 + 1 - x)[/tex] is a parabola that opens to the left and has its vertex at the point (p^2+1, 0).

The distance between the vertex and the focus is [tex]\sqrt{ (p^2+1) }[/tex], and the distance between the vertex and the directrix is also [tex]\sqrt{(p^2+1). }[/tex]

Now, we need to find the intersection points of the two parabolas. Setting the two equations equal to each other, we get:

[tex]4(p+1)(x+p+1) = 4(p^2+1)(p^2+1-x)[/tex]

Simplifying and rearranging, we get:

[tex]x = p^3 + p^2 - p - 1[/tex]

Substituting this value of x into either of the original equations, we get:

[tex]y^2 = 4(p+1)(p^2+2p)[/tex]

Simplifying, we get:

[tex]y^2 = 4p(p+1)^2[/tex]

Taking the square root of both sides, we get:

y = ± 2(p+1)√p

Therefore, the two parabolas intersect at the points [tex](p^3+p^2-p-1, 2(p+1)\sqrt{p } )[/tex] and [tex](p^3+p^2-p-1, -2(p+1)\sqrt{p} ).[/tex]

Now, we can find the area of the region between the parabolas by integrating the difference between the y-coordinates of the two parabolas over the range of x where they intersect.

This gives:

[tex]A = 2\int [p^3+p^2-p-1, p^2+1] [2(p+1)√p - 2\sqrt{(p(p+1)^2)} ] dx[/tex]

Simplifying, we get:

[tex]A = 4 \int [p^3+p^2-p-1, p^2+1] (p-1)\sqrt{p} dx[/tex]

Integrating with respect to x, we get:

[tex]A = 4 [(2/3)(p^2+1)\sqrt{p} - (2/5)(p^2+1)p^{3/2} + (1/2)(p^2+1)^{3/2} - (2/3)(p^3+p^2-p-1)\sqrt{p} + (2/5)(p^3+p^2-p-1)p^{3/2} - (1/2)(p^3+p^2-p-1)^{3/})][/tex]

Simplifying, we get:

[tex]A = 4 [(2/3)p^2\sqrt{p } + (2/3)\sqrt{p } - (2/5)p^2\sqrt{p}[/tex]

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Find f(x) when f'(x) = 2cosx - 9sinx and f(0)=6

Answers

C = -3, and the final expression for f(x) is:

f(x) = 2sinx + 9cosx - 3

To discover f(x) whilst f'(x) = 2cosx - 9sinx and f(0)=6, we need to integrate f'(x) with recognize to x to obtain f(x), whilst also considering the regular of integration.

∫f'(x) dx = ∫(2cosx - 9sinx) dx

the use of the integration rules for cosine and sine, we get:

f(x) = 2sinx + 9cosx + C

Wherein C is the constant of integration.

To discover the value of C, we use the given initial circumstance f(0) = 6:

f(0) = 2sin(0) + 9cos(0) + C = 9 + C = 6

Therefore, C = -3, and the final expression for f(x) is:

f(x) = 2sinx + 9cosx - 3

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I NEED HELP ON THIS ASAP! I WILL GIVE BRAINLIEST!!!

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The function g(x) is a reflection over the x-axis and stretch by 3 units and shifted upward by 1 unit of the parent function f(x).

We have,

A capability is a declaration, idea, or rule that lays out a relationship between two factors. Capabilities might be found all through science and are fundamental for the advancement of huge connections.

The functions are given below.

f(x) = x

g(x) = -3f(x) + 1

g(x) = -3x + 1

The parent function is a reflection over the x-axis and stretch by 3 units and shifted upward by 1 unit.

The functions g(x) and f(x) are shown below.

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Convert the given polar equation into a Cartesian equation T= 3sin 0 + 5cos e

Answers

To convert the polar equation T= 3sin θ + 5cos θ into a Cartesian equation, we can use the following identities:

sin θ = y / r
cos θ = x / r

where r is the distance from the origin to the point (x, y) in the Cartesian plane. Substituting these expressions into the given polar equation, we get:

T = 3(y / r) + 5(x / r)

Multiplying both sides by r, we obtain:

Tr = 3y + 5x

This is the Cartesian equation of the given polar equation.

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Jake is building a toy box for his son that is shaped like a rectangular prism. The toy box has a volume of 72 ft3 and a height of 3 ft. What are the possible dimensions for the area of the base of the toy box?​

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dimensions for the area of the base of the toy box are 6 feet by 4 feet, 8 feet by 3 feet, and 12 feet by 2 feet.

SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question. A random sample of 200 men aged between 20 and 60 was selected from a certain city. The linear correlation coefficient between income and blood pressure was found to be r = 0.807. What does this imply? Does this suggest that if a man gets a salary raise his blood pressure is likely to rise? Why or why not? What are likely lurking variables?
____

Answers

The linear correlation coefficient of r=0.807 indicates a strong positive linear relationship between income and blood pressure in the sample of 200 men aged between 20 and 60.

The income increases, blood pressure tends to increase as well in the sample.

No, this does not necessarily suggest that if a man gets a salary raise, his blood pressure is likely to rise. Correlation does not imply causation, so we cannot conclude that a change in income causes a change in blood pressure.

There may be other factors that influence both income and blood pressure, such as stress, diet, physical activity, or genetic factors.

Lurking variables are unobserved variables that may affect the relationship between income and blood pressure.

Some possible lurking variables in this scenario include age, race, education, occupation, lifestyle factors, family history of hypertension, and underlying health conditions.

These variables may confound the relationship between income and blood pressure, making it difficult to establish a causal relationship.

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a. prove that accumulation function a(t) applies to real numbers t > 0

b. prove that accumulation function a(t) applies to real numbers t > 0

c. prove that for 0 < t < 1, then ..., where t real numbers

d. prove that for t > 1, then ..., where t real numbers

Answers

a. The accumulation function a(t) applies to real numbers t > 0

b. The accumulation function a(t) applies to real numbers t > 0

c. For any 0 < t < 1, the accumulation function a(t) approaches 0 as t approaches 0.

d. For any t > 1, the accumulation function a(t) is proportional to 2t and approaches 2t * f(c) as t approaches infinity.


a. To prove that the accumulation function a(t) applies to real numbers t > 0, we need to show that it makes sense to evaluate the function for any positive real value of t.
The accumulation function a(t) is defined as the integral from 0 to t of some function f(x). Since integrals are defined for any continuous function over a closed interval, we know that f(x) must be a continuous function over the interval [0, t].
Furthermore, the domain of integration is the closed interval [0, t], which includes all real numbers between 0 and t (including 0 and t themselves). Therefore, the accumulation function a(t) applies to all real numbers t > 0.
b. This is the same as part a, so the answer is the same: the accumulation function a(t) applies to all real numbers t > 0.
c. To prove that for 0 < t < 1, then ..., where t is a real number, we need to evaluate the accumulation function a(t) for values of t between 0 and 1.
Let's assume that f(x) is a continuous function over the interval [0, 1]. Then, the accumulation function a(t) is given by:
a(t) = ∫[0,t] f(x) dx
Since 0 < t < 1, we know that the interval [0, t] is a subset of the interval [0, 1]. Therefore, we can use the Mean Value Theorem for Integrals to say that there exists some value c in [0, t] such that:
a(t) = t * f(c)
Since f(x) is a continuous function over [0, 1], we know that it attains a maximum value of M and a minimum value of m over the interval [0, 1]. Therefore, we can say that:
m * t ≤ a(t) ≤ M * t
This means that the accumulation function a(t) is bounded between two values that are proportional to t. As t approaches 0, these bounds approach 0 as well, so we can say that:
lim(t → 0) a(t)/t = 0
Therefore, for any 0 < t < 1, the accumulation function a(t) approaches 0 as t approaches 0.
d. To prove that for t > 1, then ..., where t is a real number, we need to evaluate the accumulation function a(t) for values of t greater than 1.
Let's assume that f(x) is a continuous function over the interval [0, t]. Then, the accumulation function a(t) is given by:
a(t) = ∫[0,t] f(x) dx
Since t > 1, we know that the interval [0, t] is a subset of the interval [0, 2t]. Therefore, we can use the Mean Value Theorem for Integrals to say that there exists some value c in [0, 2t] such that:
a(t) = ∫[0,t] f(x) dx = ∫[0,2t] f(x) dx - ∫[t,2t] f(x) dx = 2t * f(c) - ∫[t,2t] f(x) dx
Since f(x) is a continuous function over the interval [0, t], we know that it attains a maximum value of M and a minimum value of m over this interval. Therefore, we can say that:
m * t ≤ ∫[t,2t] f(x) dx ≤ M * t
This means that the second term in the equation for a(t) is bounded between two values that are proportional to t. As t approaches infinity, these bounds approach 0 as well, so we can say that:
lim(t → ∞) ∫[t,2t] f(x) dx/t = 0
Therefore, for any t > 1, the accumulation function a(t) is proportional to 2t and approaches 2t * f(c) as t approaches infinity.

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Getting to Work According to the U.S. Census Bureau, the probability that a randomly selected worker primarily drives a car to work is 0.867. The probability that a randomly selected worker primarily takes public transportation to work is 0.048. (a) What is the probability that a randomly selected worker primarily drives a car or takes public transportation to work? (b) What is the probability that a randomly selected worker neither drives a car nor takes public transportation to work? (e) What is the probability that a randomly selected worker does not drive a car to work?

Answers

The probability that a randomly selected worker primarily drives a car or takes public transportation to work is 0.915. The probability that a randomly selected worker neither drives a car nor takes public transportation to work is 0.085. The probability that a randomly selected worker does not drive a car to work is 0.133.

(a) To find the probability that a randomly selected worker primarily drives a car or takes public transportation to work, we can add the probabilities of each event:
P(drives car) + P(takes public transportation) = 0.867 + 0.048 = 0.915
Therefore, the probability that a randomly selected worker primarily drives a car or takes public transportation to work is 0.915.
(b) The probability that a randomly selected worker neither drives a car nor takes public transportation to work can be found by subtracting the probability of driving a car or taking public transportation from 1:
P(neither drives car nor takes public transportation) = 1 - P(drives car or takes public transportation)
P(neither drives car nor takes public transportation) = 1 - 0.915
P(neither drives car nor takes public transportation) = 0.085
Therefore, the probability that a randomly selected worker neither drives a car nor takes public transportation to work is 0.085.
(e) To find the probability that a randomly selected worker does not drive a car to work, we can subtract the probability of driving a car from 1:
P(does not drive car) = 1 - P(drives car)
P(does not drive car) = 1 - 0.867
P(does not drive car) = 0.133
Therefore, the probability that a randomly selected worker does not drive a car to work is 0.133.

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