CH₃CHCl₂COOH is 2,2-dichloropropanoic acid, with the least pH, option (c) is correct.
pH is a measure of the acidity or basicity of a solution. A lower pH indicates a higher acidity. Acidity is due to the presence of hydrogen ions (H⁺) in a solution. The more the concentration of H⁺, the lower the pH. CH₃CH₂COOH is propanoic acid, which has a pH of around 4.9.
CH₂ClCH₂COOH is 2-chloropropanoic acid, which has a pH of around 2.8 due to the electron-withdrawing effect of the chlorine atom. CH₃CH₂CH₂COOH is butanoic acid, which has a pH of around 4.8. Thus, CH₃CHCl₂COOH is 2,2-dichloropropanoic acid, which has the least pH among the given options, around 1.5 due to the presence of two electron-withdrawing chlorine atoms, option (c) is correct.
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Gaseous butane (CH3(CH2)2CH3) will react with gaseous oxygen (02) to produce carbon dioxide (CO2) and gaseous water (H2O). Suppose 34.g of butane s mixed with 200. g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.
The maximum mass of water that can be produced by the reaction is 43.3 g, rounded to three significant figures.
Determining the maximum mass of water producedThe balanced chemical equation for the reaction between butane and oxygen is:
C4H10 + 13/2 O2 → 4 CO2 + 5 H2O
From the equation, we can see that 1 mole of butane reacts with 13/2 moles of oxygen to produce 5 moles of water.
moles of butane = 34. g / 58.12 g/mol = 0.585 mol
moles of oxygen = 200. g / 32.00 g/mol = 6.25 mol
Determining the limiting reactant.
butane : oxygen = 0.585 mol : 6.25 mol
= 0.0936 : 1.00
stoichiometric ratio = 1 : 13/2
= 0.7692 : 1.00
Since the actual ratio is lower than the stoichiometric ratio for oxygen, it is the limiting reactant.
The maximum amount of water that can be produced is determined by the amount of limiting reactant (oxygen).
moles of water = 5/13 * 6.25 mol
= 2.403 mol
Finally, we can convert the moles of water to grams:
mass of water = 2.403 mol * 18.015 g/mol
= 43.3 g
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17. An artist took two photographs of the Moon that were several days apart. Images that look like his photographs are shown above. The light part of the Moon appeared to get smaller over time. Why did this happen?
According to the information, we can infer that the difference between photographs 1 and 2 originate from the translation of the Moon around the earth (option C).
How do we explain the differences between the two images?To explain the difference between both images we must take into account the movement patterns of the earth and the moon. In the case of the earth, it has 2 main movements, which are rotation on its own axis and translation around the sun.
On the other hand, the moon has a translational movement around the earth, which is what causes the different lunar phases. This motion causes the moon to appear partially shadowed from the earth because the earth blocks the sunlight.
Based on the above, we can infer that the correct answer is option C because this phenomenon is caused by the translation of the moon.
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What is the main reason plants grow fruit?
A
to provide delicious food for humans and other animals
B
to stop animals from spreading seeds
C
to encourage bees to pollinate
D
to keep seeds safe and make them easier to spread
Answer:
D
Explanation:
to keep seeds safe and make them easier to spread
Answer:
D. to keep seeds safe and make them easier to spread
Explanation:
The main reason plants grow fruit is to aid in the protection and spreading of seeds. The fruit protects the seeds and also helps to spread them. Many fruits are good to eat and attract small animals, such as birds and squirrels, who like to feed on them. The seeds pass through them unharmed and then get spread through their droppings. So, the correct answer would be D.
Please help me with this chemistry investigation I need answers as soon as possible please
B. To plot the data on a bar chart, draw a horizontal axis for metals and a vertical axis for time to complete the reaction. Then, draw bars for each metal that represent the amount of time required to complete the reaction. The height of the bars must match the time values in the table.
C. No, Emilia was not correct in her forecast. According to the data, aluminum reacted 100 seconds faster than magnesium, which reacted in 50 seconds. Thus aluminum reacts more rapidly with hydrochloric acid than magnesium.
From most reactive to least reactive, the metals are as follows:
aluminummagnesiumZincIronThis order is consistent with the reactivity series, which is:
PotassiumSodiumCalciumMagnesiumAluminiumZincIronCopperSilverGoldWe are unable to estimate the reactivity of potassium, sodium, calcium, copper, silver, or gold from this experiment because those variables are not present in the data.
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If you mix 30 mL of cold water with 70 mL of hot water in a calorimeter, then calculate that the cold water gained 142 J of heat and the hot water lost 181 J of heat, and the temperature change of the cold water (and calorimeter) was an increase in 1.93°C, then what is the heat capacity of the calorimeter in J/°C (only enter the number, not units, and assume that no heat was lost to the environment around the calorimeter, assume the density of water to be 1.00g/mL and specific heat capacity of water to be 4.184 J/g-°C)?
First, we need to calculate the heat gained by the cold water and the heat lost by the hot water:
Qcold = mcΔT = (30 g)(4.184 J/g-°C)(1.93°C) = 242.06 J
Qhot = mcΔT = (70 g)(4.184 J/g-°C)(-1.93°C) = -546.53 J
Since energy is conserved, we can assume that the heat gained by the cold water and calorimeter is equal to the heat lost by the hot water:
Qcold + Qcalorimeter = Qhot
Qcalorimeter = Qhot - Qcold
Qcalorimeter = -546.53 J - 242.06 J = -788.59 J
Therefore, the heat capacity of the calorimeter can be calculated as:
Ccalorimeter = Qcalorimeter / ΔT
Ccalorimeter = (-788.59 J) / (1.93°C)
Ccalorimeter ≈ -408.4 J/°C
Note that the negative sign indicates that the calorimeter loses heat when the system gains heat, which is expected since the calorimeter is absorbing some of the heat from the hot water.
Nitrogen dioxide gas and liquid water react to form aqueous nitric acid and nitrogen monoxide gas. Suppose you have 5.0 mol of NO2 and 11.0 mol of H2O in a reactor.
Calculate the largest amount of HNO3 that could be produced. Round your answer to the nearest 0.1 mol
First, we need to write the balanced chemical equation for the reaction:
2 NO2(g) + H2O(l) → HNO3(aq) + NO(g)
From the equation, we can see that 2 moles of NO2 react with 1 mole of H2O to produce 1 mole of HNO3 and 1 mole of NO. Therefore, we need to determine which reactant is limiting and calculate the amount of HNO3 that can be produced based on that.
To do this, we can use the mole ratio of NO2 to H2O:
5.0 mol NO2 × (1 mol H2O / 2 mol NO2) = 2.5 mol H2O
Since we have 11.0 mol of H2O, it is not limiting and we will use up all of the NO2.
Therefore, we can calculate the amount of HNO3 that can be produced from 5.0 mol of NO2:
5.0 mol NO2 × (1 mol HNO3 / 2 mol NO2) = 2.5 mol HNO3
Therefore, the largest amount of HNO3 that could be produced is 2.5 mol, rounded to the nearest 0.1 mol.
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Help me please I need the answer as soon as possible
Answer:
see in your book properly
Please ASAP!! :'(
Which of the following graphs repMagnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial.
· Trial 1:
· Trial 2:
Determine the percent yield of MgO for your experiment for each trial.
· Trial 1:
· Trial 2:
Determine the average percent yield of MgO for the two trials.
resents the function g (x) = x2(x + 1)(x – 2)?
The theoretical yield of MgO for Trial 1 is 0.348 g, and for Trial 2 is 0.307 g. The percent yield of MgO for Trial 1 is 58.0% and for Trial 2 is 159.2%. The average percent yield of MgO for the two trials is 108.6%.
To calculate the theoretical yield of MgO, we need to use the balanced chemical equation for the reaction between magnesium (Mg) and oxygen (O2) to form magnesium oxide (MgO):
2Mg + O₂ → 2MgO
According to the stoichiometry of this equation, 2 moles of Mg react with 1 mole of O2 to produce 2 moles of MgO. Therefore, we need to determine the number of moles of Mg in each trial and use the mole ratio to find the theoretical yield of MgO.
For Trial 1:
The mass of Mg used is: 26.682 g - 27.012 g = 0.330 g
The molar mass of Mg is 24.31 g/mol, so the number of moles of Mg is:
0.330 g / 24.31 g/mol = 0.0136 mol Mg
According to the balanced equation, 2 moles of Mg produce 2 moles of MgO, so the theoretical yield of MgO is:
0.0136 mol Mg x (2 mol MgO / 2 mol Mg) x (40.31 g MgO/mol) = 0.348 g MgO
For Trial 2:
The mass of Mg used is: 26.987 g - 26.695 g = 0.292 g
The number of moles of Mg is:
0.292 g / 24.31 g/mol = 0.0120 mol Mg
The theoretical yield of MgO is:
0.0120 mol Mg x (2 mol MgO / 2 mol Mg) x (40.31 g MgO/mol) = 0.307 g MgO
To calculate the percent yield of MgO, we need to use the following formula:
Percent yield = (actual yield / theoretical yield) x 100%
For Trial 1:
The actual yield of MgO is: 27.214 g - 27.012 g = 0.202 g MgO
The percent yield of MgO is:
(0.202 g / 0.348 g) x 100% = 58.0%
For Trial 2:
The actual yield of MgO is: 27.183 g - 26.695 g = 0.488 g MgO
The percent yield of MgO is:
(0.488 g / 0.307 g) x 100% = 159.2%
To calculate the average percent yield of MgO for the two trials, we add the percent yields and divide by 2:
Average percent yield = (58.0% + 159.2%) / 2 = 108.6%
Therefore, the theoretical yield of MgO for Trial 1 is 0.348 g, and for Trial 2 is 0.307 g. The percent yield of MgO for Trial 1 is 58.0% and for Trial 2 is 159.2%. The average percent yield of MgO for the two trials is 108.6%.
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Describe the intermolecular forces that must be overcome to convert each of the following from a liquid or solid to a gas.
P2O5 and HI
For P₂O₅ the intermolecular forces such as van der Waals forces, dipole-dipole interactions, and hydrogen bonding must be overcome.
For HI the intermolecular forces that must be overcome are as van der Waals forces, dipole-dipole interactions, and hydrogen bonding.
What are the intermolecular forces that must be overcome?P₂O₅ is a covalent compound and it is solid. To convert P₂O₅ from a solid to a gas, intermolecular forces such as van der Waals forces, dipole-dipole interactions, and hydrogen bonding must be overcome.
HI is a covalent compound that is a gas at room temperature and pressure. To convert HI from a liquid to a gas, intermolecular forces such as van der Waals forces, dipole-dipole interactions, and hydrogen bonding must be overcome.
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If 80 grams of KBr were dissolved in 100 grams of water at 35 degrees Celsius, which of these terms would best describe the solution
The term that would best describe the solution formed if 80g KBr dissolved in 100g water is unsaturated solution.
What is a saturated solution?A saturated solution is a solution with solute that dissolves until it is unable to dissolve anymore, leaving the undissolved substances at the bottom.
On the other hand, an unsaturated solution is that solution that is capable of dissolving more of a solute at the same temperature.
According to this question, 80 grams of KBr were dissolved in 100 grams of water at 35 degrees Celsius. This means that the solution is unsaturated because it can still dissolve more KBr.
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The value of H for the following reaction is +128.1kJ: CH3OH(I) —> CO(g)+2H2(g) . Calculate the value of H (in kJ) when 5.10g of H2(g) is formed.
A) 653 B)326 C)-162.0 D)128 E)162
The value of H (in kJ) when 5.10 g of H2(g) is formed is 326 kJ (option B).
The given reaction is: CH3OH(I) —> CO(g)+2H2(g)
From the given value of H, we know that when one mole of CH3OH reacts, 128.1 kJ of heat energy is absorbed.
The molar mass of H2 is 2 g/mol. So, 5.10 g of H2 is equivalent to 5.10/2 = 2.55 moles of H2.
From the balanced equation, we can see that two moles of H2 are produced for each mole of CH3OH that reacts.
So, 2.55 moles of H2 are produced by 1.275 moles of CH3OH reacting (2.55/2).
Therefore, the amount of heat energy absorbed when 1.275 moles of CH3OH reacts can be calculated as:
Q = n x ΔH = 1.275 mol x 128.1 kJ/mol = 163.28 kJ
Since this amount of heat energy is absorbed when 1.275 moles of CH3OH reacts, to find the amount of heat energy absorbed when 2.55 moles of H2 is formed, we can simply double the value of Q:
Q = 2 x 163.28 kJ = 326.56 kJ
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How many grams of oxygen would be produced by electrolysis of 83.7 grams of water?
H2O --> O2 + H2
The balanced chemical equation for the electrolysis of water is:
2H2O → 2H2 + O2
This equation shows that for every two moles of water that are electrolyzed, one mole of oxygen gas is produced. To solve this problem, we need to first convert the given mass of water (83.7 grams) to moles of water.
The molar mass of water (H2O) is:
2(1.008 g/mol H) + 15.999 g/mol O = 18.015 g/mol
So, 83.7 grams of water is equal to:
83.7 g / 18.015 g/mol = 4.646 mol H2O
Next, we need to determine how many moles of oxygen gas will be produced when 4.646 moles of water are electrolyzed. Since the mole ratio of water to oxygen is 2:1, we can use the following proportion:
2 mol H2O : 1 mol O2 = 4.646 mol H2O : x mol O2
Solving for x, we get:
x mol O2 = (1 mol O2 / 2 mol H2O) * 4.646 mol H2O = 2.323 mol O2
Finally, we can convert the moles of oxygen gas produced to grams using the molar mass of oxygen:
2.323 mol O2 * 32.00 g/mol O2 = 74.3 g O2
Therefore, 83.7 grams of water will produce 74.3 grams of oxygen gas by electrolysis.
diagram of reaction of water,oxygen,acids
When water and oxygen react in the presence of an acid, the oxygen can oxidize the acid to produce a compound and release hydrogen ions.
Reaction:
The reaction is as follows and it's diagram mentioned below.
Acid + Oxygen + Water → Compound + Hydrogen ions
if we take the acid hydrochloric acid (HCl), the reaction with oxygen and water can produce the compound chlorine dioxide ([tex]ClO_{2}[/tex]) and hydrogen ions ([tex]H^{+}[/tex]):
2 HCl + [tex]O_{2}[/tex] + [tex]H_{2}O[/tex] → 2 [tex]ClO_{2}[/tex] + 4 [tex]H^{+}[/tex]
This type of reaction is known as an oxidation-reduction reaction or a redox reaction, where one species is oxidized (loses electrons) while the other is reduced (gains electrons).
What is redox reaction?
A redox reaction, also known as an oxidation-reduction reaction, is a type of chemical reaction in which there is a transfer of electrons between two species. One species undergoes oxidation, meaning it loses electrons, while the other species undergoes reduction, meaning it gains electrons.
Redox reactions are fundamental to many processes in nature and technology, including photosynthesis, respiration, corrosion, and energy production in batteries and fuel cells. They are also important in many industrial processes, such as the production of metals, chemicals, and pharmaceuticals.
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VITAMIN C IN FRUIT JUICE
Why might it be difficult to use this method to determine the amount of Vitamin C in other fruit juices such as cranberry, blackcurrant, or pomegranate juice?
The method for determining the sum of Vitamin C in fruit juice ordinarily includes adding an indicator (such as DCPIP) to the juice test and titrating the test with a standard arrangement of ascorbic corrosive until the marker changes colour.
In any case, there are a few variables that seem to make this strategy troublesome to utilize for other natural product juices such as cranberry, blackcurrant, or pomegranate juice:
Interference with the indicator: A few natural product juices may contain compounds that are meddled with the marker and anticipate it from changing colour indeed when all the Vitamin C has been titrated. This may lead to wrong comes about.Presence of other reducing agents: Natural product juices may contain other diminishing operators other than Vitamin C, such as fructose or glucose, which can moreover respond with the marker and create wrong positive comes about.Differences in Vitamin C substance: Diverse natural products contain distinctive sums of Vitamin C, and the sum of Vitamin C in a specific juice can change depending on variables such as the readiness of the fruit and the handling strategy utilized. This will make it troublesome to compare the Vitamin C substance of diverse natural product juices utilizing the same strategy.Differences in pH: The pH of natural product juices can moreover change, and this could influence the solidness of Vitamin C and the precision of the titration strategy.In this manner, whereas the strategy for deciding the sum of Vitamin C in natural product juice can be a valuable apparatus, it may not be appropriate for all sorts of natural product juices and may have to be be adjusted or adjusted to account for these variables.
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A 7.95 L
container holds a mixture of two gases at 25 °C.
The partial pressures of gas A and gas B, respectively, are 0.352 atm
and 0.715 atm.
If 0.240 mol
of a third gas is added with no change in volume or temperature, what will the total pressure become?
Question 6 (5 points)
Label each situation as metals, nonmetals, or metalloids. Label each with numbers.
Usually conducts electricity
& heat well
at room temperature these
are gases or liquids
Will lose valance electrons
to form compounds.
can be used as
semiconductors
Will gain valance electrons
to form compounds.
1. a metal
2. a nonmetal
3. a metalloid
Answer:
Explanation:
Here are the labels for each situation:
1.Usually conducts electricity & heat well - Metal (1)
2.At room temperature these are gases or liquids - Nonmetal (2)
3.Will lose valance electrons to form compounds - Metal (1)
4.Can be used as semiconductors - Metalloid (3)
5.Will gain valance electrons to form compounds - Nonmetal (2)
What’s the oxidation number of copper in CuO?
the oxidation number of copper in copper oxide is 2...
Answer: +2
Explanation: Copper has a +2 oxidation number in CuO.
This is due to the fact that oxygen has an oxidation number of 2, and the entire chemical has a neutral charge. Consequently, the following equation can be used to determine copper's oxidation number:
(+2) + (-2) = 0
In order to counteract the -2 oxidation number of oxygen in CuO, copper must have an oxidation number of +2.
What is the difference between collecting and analysing data
Answer:
Data collection is the act of obtaining information from diverse sources, and data analytics is the process of processing that information to derive practical insights.
Explanation:
Which of the following is the most basic level of organization that can perform functions like converting food into energy?
The most basic level of organization that can perform functions like converting food into energy is the cell.
The most basic level of organization that can perform functions like converting food into energy is the cell. Cells are the fundamental units of life and are capable of various functions, including metabolism, which involves converting food into energy through processes such as cellular respiration.
Cells can be found in all living organisms, from single-celled bacteria to complex multicellular organisms like plants and animals. Within a cell, various organelles such as mitochondria, which are responsible for energy production, carry out specialized functions to support the overall cellular function. Therefore, the cell is the smallest and most basic level of organization that is capable of performing functions like converting food into energy.
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How many mL of a 0.75 N KOH solution
should be added to a 500 mL flask to make
500 mL of a 0.300 M KOH solution?
The amount of volume of KOH solution that should be added to make 500mL of a 0.300M solution is 200mL.
How to calculate volume?The volume of a solution given the concentration can be calculated using the following expression;
CaVa = CbVb
Where;
Ca = initial concentrationVa = initial volumeCb = final concentrationVb = final volumeAccording to this question, we are to calculate how many mL of a 0.75 M OH solution that should be added to a 500 mL flask to make 500 mL of a 0.300 M KOH solution.
0.75 × Va = 500 × 0.3
0.75Va = 150
Va = 150/0.75
Va = 200mL
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Using the equations
N₂ (g) + O₂ (g) → 2 NO (g) ∆H° = 180.6 kJ/mol
N₂ (g) + 3 H₂ (g) → 2 NH₃ (g) ∆H° = -91.8 kJ/mol
2 H₂ (g) + O₂ (g) → 2 H₂O (g) ∆H° = -483.7 kJ/mol
Determine the molar enthalpy (in kJ/mol) for the reaction
4 NH₃ (g) + 5 O₂ (g) → 4 NO (g) + 6 H₂O (g).
The molar enthalpy for the reaction 4 NH₃ (g) + 5 O₂ (g) → 4 NO (g) + 6 H₂O (g) is 266.4 kJ/mol.
What is the molar enthalpy for the reaction?The molar enthalpy is determined from Hess's law as follows:
Equation 1 x2:
2 N₂ (g) + 2 O₂ (g) → 4 NO (g) ∆H° = 361.2 kJ/mol
Equation 3 x3, :
6 H₂ (g) + 3 O₂ (g) → 6 H₂O (g) ∆H° = -1451.1 kJ/mol
Equation 2 x -4:
-8 N₂ (g) - 12 H₂ (g) → -8 NH₃ (g) ∆H° = 367.2 kJ/mol
Adding the equations together:
-6 N₂ (g) - 6 H₂ (g) + 5 O₂ (g) → 4 NO (g) + 6 H₂O (g) - 8 NH₃ (g) ∆H° = 266.3 kJ/mol
Multiplying the equation above by -1/2:
3 N₂ (g) + 3 H₂ (g) - 5/2 O₂ (g) → -2 NO (g) - 3 H₂O (g) + 4 NH₃ (g) ∆H° = -133.2 kJ/mol
Multiplying the above equation by -2:
4 NH₃ (g) + 5 O₂ (g) → 4 NO (g) + 6 H₂O (g) ∆H° = 266.4 kJ/mol
This is the molar enthalpy of the given reaction
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How many grams of air are in a 2.35 L balloon when its density is 1.4 g/L?
Answer:
3.29 grams
Explanation:
This is found by multiply 2.35 L by 1.4 g/L that is because the liters will cancel each other out leaving just grams. [tex]\frac{g}{L} * \frac{L}{1}[/tex]
How many grams in 5 moles of water?
Answer:
90g
Explanation:
Ans. 90 gram
we know that,
n = wt/m.wt
where, n= moles
wt.= weight
m.wt = molecular weight
putting values we get
5 = wt./18 ( molecular weight of water is 18
wt.= 90
hence ans.= 90 gram
bromsted-lowry acids and bases
find out the acids and bases
Johannes Brsted and Thomas M. Lowry, two chemists, identified the Bromsted-Lowry acids and bases as a particular kind of acid-base reaction in 1923.
Acids are substances that give a base a proton (H+), whereas bases are substances that take a proton from an acid. In a Bromsted-Lowry acid-base reaction, the acid gives the base a proton in order to create the conjugate base and the conjugate acid, two new compounds.
Nitric acid (HNO3), sulfuric acid (H2SO4), and hydrochloric acid (HCl) are a few examples of acids. Sodium hydroxide (NaOH), ammonium hydroxide (NH4OH), and potassium hydroxide (KOH) are a few examples of bases.
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A sphere has a diameter of 16 m. What is the volume of the sphere?
Answer:
V ≈ 2144.66 m³
Explanation:
Volume of sphere formula is:
V = 4/3 πr³
Radius is half the diameter so we divide the given diameter, 16 by 2 to get 8, the radius. Now we can solve
V = 4/3 π (8)³
V = 4/3 (512π)
V = 2048/3 π
V ≈ 2144.66 m³
Answer:
4/3 x π
Explanation:
HELP ASAP!! 50 POINT AND A BRAINLIEST FOR THE CORRECT ANSWER
FeO (s) + Fe (s) + O2(g) →
Fe2O3 (s)
Given the following table of thermodynamic data at 298 K:
Substance ΔHf° (kJ/mol) S° (J/K⋅mol)
FeO (s) -271.9 60.75
Fe (s) 0 27.15
O2 (g) 0 205.0
Fe2O3 (s) -822.16 89.96
The value K for the reaction at 25 °C is ________.
Consider the reaction:
FeO (s) + Fe (s) + O2(g) Fe2O3 (s)
Given the following table of thermodynamic data at 298 K:
Substance ΔHf° (kJ/mol) S° (J/K⋅mol)
FeO (s) -271.9 60.75
Fe (s) 0 27.15
O2 (g) 0 205.0
Fe2O3 (s) -822.16 89.96
The value K for the reaction at 25 °C is ________.
8.1 *10^19
5.9 *10^4
3.8 ⋅*10^-14
370
7.1 *10^85
Answer:
3.8 ⋅*10^-14
Explanation:
The standard free energy change (ΔG°) for the reaction at 298 K can be calculated using the following equation:
ΔG° = ΣnΔGf°(products) - ΣnΔGf°(reactants)
where ΔGf° is the standard molar free energy of formation of the species and n is the stoichiometric coefficient.
ΔG° = [1×ΔGf°(Fe2O3)] - [1×ΔGf°(FeO) + 1×ΔGf°(Fe) + 1×ΔGf°(O2)]
ΔG° = [1×(-822.16 kJ/mol)] - [1×(-271.9 kJ/mol) + 1×(0 kJ/mol) + 1×(0 kJ/mol)]
ΔG° = -550.26 kJ/mol
The standard enthalpy change (ΔH°) and standard entropy change (ΔS°) can be used to calculate the standard free energy change (ΔG°) at any temperature using the following equation:
ΔG° = ΔH° - TΔS°
where T is the temperature in Kelvin.
ΔG° = ΔH° - TΔS° = (-550.26 kJ/mol) - (298 K)(-0.08996 kJ/K/mol) = -524.05 kJ/mol
Now, we can calculate the equilibrium constant (K) for the reaction at 298 K using the following equation:
ΔG° = -RTlnK
where R is the gas constant (8.314 J/K/mol) and T is the temperature in Kelvin.
-524.05 kJ/mol = -(8.314 J/K/mol)(298 K)lnK
lnK = -200.16
K = e^(-200.16) = 3.89×10^(-87)
Therefore, the value of K for the reaction at 25 °C is 3.89×10^(-87). Answer: 3.8 ⋅*10^-14.
What mass of sulfur must be used to produce 25.7 L of gaseous sulfur dioxide at STP
according to the following equation?
S8 (s) + 8 O2 (g) −→ 8 SO2 (g)
Answer in units of g.
A mass of 37.0 g of sulfur must be used to produce 25.7 L of gaseous sulfur dioxide at STP.
What is the reactant mass of the sulfur?The molar ratio of S₈ to SO₂ is 1:8.
At STP, one mole of gas occupies 22.4 L. Therefore, 25.7 L of SO₂ gas will contain;
25.7 L / 22.4 L/mol = 1.15 mol of SO₂.
The number of moles of S₈ needed is calculated as;
= 1.15 mol SO₂ / 8 mol S₈ per 1 mol SO₂
= 0.144 mol S₈.
The mass of S₈ needed is calculated as;
0.144 mol S₈ × 256.6 g/mol = 37.0 g of S₈.
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If 50 joules of energy is added to sample of water, the temperature will?
Explanation:
The temperature change of a substance when it absorbs or loses energy can be calculated using the specific heat capacity of the substance. The specific heat capacity of water is approximately 4.18 J/(g°C), which means that it takes 4.18 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
To calculate the temperature change of the water sample when 50 joules of energy is added, we need to use the following equation:
q = m * c * ΔT
where q is the amount of energy absorbed by the water, m is the mass of the water sample, c is the specific heat capacity of water, and ΔT is the resulting temperature change.
Rearranging the equation to solve for ΔT, we get:
ΔT = q / (m * c)
Plugging in the values, we get:
ΔT = 50 J / (m * 4.18 J/(g°C))
We need to know the mass of the water sample to calculate the temperature change. Let's assume a mass of 10 grams:
ΔT = 50 J / (10 g * 4.18 J/(g°C))
ΔT = 1.2°C
Therefore, if 50 joules of energy is added to a 10-gram sample of water, the resulting temperature change will be approximately 1.2 degrees Celsius.
Classify each into the concepts of HEAT and TEMPERATURE
Answer:
Heat HeatHeatTemperatureTemperatureHeatChromium, Cr, has the following isotopic masses and fractional abundances:
Mass Number Isotopic Mass (amu) Fractional Abundance
50 49.9461 0.0435
52 51.9405 0.8379
53 52.9407 0.0950
54 53.9389 0.0236
What is the atomic mass of chromium
The average mass of chromium is 52.1. Isotopic mass is defined as the average mass of all the isotopes of a specific element.
The average atomic mass of an element is referred to as the sum of the masses of its isotopes, each multiplied by its natural abundance which can be also explained as the decimal associated with the percent of atoms of that element that are of a given isotope. Average atomic mass is equal to f1M1 + f2M2 and so on. Hydrogen, chromium, lithium, cobalt, oxygen, boron, plutonium, and carbon are some examples.
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