Which of the following statements about CASE is not true?CASE tools provide automated graphics facilities for producing charts.CASE tools reduce the need for end user participation in systems development.CASE tools have capabilities for validating design diagrams and specifications.CASE tools support collaboration among team members.CASE tools facilitate the creation of clear documentation

Answer:

From the given address:  7d2b:00a9:a0c4:0000:a772:00fd:a523:0358

We can see that:

In general, Internet Protocol version 6 (IPv6) is the Internet Protocol (IP) which was developed to deal with the expected anticipation of IPv4 address exhaustion.

The IPv6 addresses are in the format of a 128-bit alphanumeric string which is divided into 8 groups of four hexadecimal digits. Each group represents 16 bits.

Since the size of an IPv6 address is 128 bits, the address space has [tex]2^{128}[/tex] addresses.

Answer:

b. Try to convince the owner of the computer to give you to decryption key/password.

Explanation:

Encrypted hard drives have maximum security and high data protection. to access them you need to enter a password to unlock them.

The image filtering technique is a method that serves to selectively highlight information contained in an image, for which it does not work.

The encryption algorithm is a component used for the security of electronic data transport, not to access data on an encrypted hard drive.

The encryption key is used in encryption algorithms to transform a message and cannot be exposed by disconnecting the hard drive from its power source.

Answer:

Here is the function unzip:

def unzip(lst):

   result= zip(*lst)

   return list(result)

The complete program in Python is given below:

def unzip(lst):

   result= zip(*lst)

   return list(result)

lst =[(1, "one"), (2, "two"), (3, "three")]

tup= unzip(lst)

print(tup)

Explanation:

Here zip() function is used in the unzip function. The return type of zip() function is a zip object. This means the function returns the iterator of tuples. This function can be used as its own inverse by using the * operator.

If you do not want to use zip() function then the above program can also be implemented as following which uses a for loop for elements in the given list (lst). This can make a pair of lists (2 tuple) instead of list of tuples:

def unzip(lst):

   output = ([ a for a,b in lst ], [ b for a,b in lst ])

   return output

lst =[(1, "one"), (2, "two"), (3, "three")]  

tup= unzip(lst)  

print(tup)

The programs along with their output are attached.

Answer: Provided in the explanation section

Explanation:

(a). BIND is a type of DNS server used on the internet, actually it is reported to be most widely used DNS server on the internet. Also BIND is the de-facto standard on Unix like operating systems and Linux. Thus it can be used to locate computers on a network using domain names instead of their IP addresses. BIND was originally programmed at the University of California, Berkeley in the 1980s, this was made possible by a grant from US based DARPA program.

Originally, BIND stood for Berkeley Internet name daemon, but nowadays it is called Berkeley Internet name domain.

(b). In some of the clients in windows and Windows servers we will install LDP. By the LDP.exe we can test tDNS, Active directory woking , even we can add or modify. LDP is used to test and verify the Active Directory objects. We will install in windows machine then open the software, then from the menu we will select connect and type the IP adress of the Active Directory then we will select or type the objects of Active directory. For Linux system we have to openldap and can search the AD.

From Linux or Unix we can use the nmap tool which can test the network connectivity between all the computers whether it is windows or Linux. By nmap we can test by ICMP protocol to verify the network connectivity. By nmap we can scan all the port which are required to open from client to the server. We can also use nslookup to test DNS server from the client. By nslookup we can check that client can connect the server.

Answer:

The pseudocode is as given below while the flowchart is attached.

Explanation:

The pseudocode is as follows

input customer name, number of texts  

Set Basic bill=5 $;

if the number of texts is less than or equal to 60

Extra Charge=0;

If the number of texts is greater than 60 and less than 200

number of texts b/w 60 and 200 =number of texts-60;

Extra Charge=0.1*(number of texts b/w 60 and 200);

else If the number of texts is greater than 200

number of texts beyond 200 =number of texts-200;

Extra Charge=0.25*(number of texts beyond 200)+0.1*(200-60);

Display Customer Name

Total Bill=Basic bill+Extra Charge;

Total Bill after Tax=Total Bill*1.12;

Answer:

w = ["Algorithm", "Logic", "Filter", "Software", "Network", "Parameters", "Analyze", "Algorithm", "Functionality", "Viruses"]

for i in range (len(w)):

   print(w[i].upper())

Explanation:

every element needs to be upper cased

A loop that prints the words in uppercase letters is written below with the help of Python.

Simply said, a function is a "chunk" of code that you may reuse repeatedly so instead of having to write it out several times. Software developers can divide an issue into smaller, more manageable parts, which can each carry out a specific task, using functions.

A function, according to a technical definition, is a relationship between an amount of parameters and a set of potential outputs, where every other input is connected to precisely one output.

All the functions are to be written in uppercase:

w = ["Algorithm", "Logic", "Filter", "Software", "Network", "Parameters", "Analyze", "Algorithm", "Functionality", "Viruses"]

for i in range (len(w)):

  print(w[i].upper())

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Answer:

Explanation:

The objective of this question is to  compute a program  that involve using  a  C++ code for  designing and implementing  a Bank Account Management Simulator with integrated file storage for saving details to secondary storage.

When writing this code I notice the words are more than 5000 maximum number of characters the text editor can contain, so i created a word document for it. The attached file  to the word document can be found below.

Answer:

automated

Explanation:

Basically a Business Impact Analysis (BIA) estimates and determines the effects of a business activity and process disturbances. These disruptions can be natural or electronic disasters. It also collects information which is used to establish recovery plan. It identifies the business vulnerabilities and works on the strategies in order to reduce such potential hazards. The BIA involves both manual and automated processes. BIA involves automated processes which include the automated software tools that enables the protection of the confidential information of the users and also generates automated reports about the critical business processes.

Answer:

Numeric Addition

Explanation:

Literally, the + sign is an arithmetic operator used to perform addition operation between numeric datatypes (integer, float, decimal, double, long integer, etc...)

Its default built in function of the plus is sign is to add variables, constants and/or expressions.

The plus sign is used as follows;

a = 5;

b = 3;

c = a + b

-------------

a + b = 5 + 3 = 8

8 will be saved in variable c. This is only possible using the plus sign.

The plus sign also has other function such as string concatenation but this function is language dependent (i.e. some programming languages do not use + for string concatenation).

Conclusively, the built in function of the plus sign is for numeric addition

external hard drive

external hard drive

Answer:

Amswer would be D

Explanation:

Answer:

The algorithm takes 346 ms to run on an input array with 1500 rows and 4096 columns.

Explanation:

For an input array with 1000 rows and 512 columns, the algorithm takes 173 ms.

We want to find out how long will the algorithm take to run on an input array with 1500 rows and 4096 columns?

Let the algorithm take x ms to run 1500 rows and 4096 columns.

For an input of n rows and m columns, it takes

[tex]n \: log_{2} \:m[/tex]

So,

[tex]1000 \: log_{2} \:512 = 173 \\\\1000 \: log_{2} \:2^{9} = 173 \:\:\: ( 2^{9} = 512) \\\\1000 \times 9 = 173 \:\:\:\:\: \: \: eg. 1[/tex]

and

[tex]1500 \: log_{2} \:4096 = x \\\\1500 \: log_{2} \:2^{12} = x \:\:\: ( 2^{12} = 4096) \\\\1500 \times 12 = x \:\:\:\:\: \: \: eg. 2[/tex]

Now divide the eq. 2 by eq. 1 to find the value of x

[tex]\frac{1500 \times 12}{1000 \times 9} = \frac{x}{173} \\\\\frac{18000 }{9000} = \frac{x}{173} \\\\2 = \frac{x}{173} \\\\x = 2 \times 173 \\\\x = 346 \: ms[/tex]

Therefore, the algorithm takes 346 ms to run on an input array with 1500 rows and 4096 columns.

Answer:

The java program is as follows.

import java.lang.*;

public class Numbers

{

   //variables to hold two numbers

   static int num1=-8, num2=-2;

   //method to return integer with higher magnitude

   public static int maxMagnitude(int userVal1, int userVal2)

   {

       if(Math.abs(userVal1) > Math.abs(userVal2))

           return userVal1;

       else    

           return userVal2;

   }

public static void main(String[] args) {

    int max = maxMagnitude(num1, num2);

 System.out.println("The number with higher magnitude among "+num1+ " and "+num2+ " is "+max);

}

}

OUTPUT

The number with higher magnitude among -8 and -2 is -8

Explanation:

1. Two integer variables are declared to hold the two numbers. The variables are declared at class level (outside main()) and declared static.

2. The variables are initialized with any random value.

3. The method, maxMagnitude(), takes the two integer parameters and returns the number with higher magnitude. Hence, return type of the method is int.

public static int maxMagnitude(int userVal1, int userVal2)

4. This method finds the number with higher magnitude using the Math.abs() method inside if-else statement.

               if(Math.abs(userVal1) > Math.abs(userVal2))

                   return userVal1;

        else    

                   return userVal2;

5. Inside main(), the method, maxMagnitude(), is called. This method takes the two variables as input parameters.

6. The integer returned by the method, maxMagnitude() is assigned to a local integer variable, max, as shown.

      int max = maxMagnitude(num1, num2);

7. The result is displayed to the user as shown.

System.out.println("The number with higher magnitude among "+num1+ " and "+num2+ " is "+max);

8. The class variables and the method, maxMagnitude(), are declared static so that they can be used and called inside main().

9. The variable, max, is called local variable since it can be used only within the main() where it is declared. It is not declared static.

10. The class is declared public since it has the main() method and execution begins with main().

11. The program is saved with the same name as the name of the public class having main(). In this case, the program is saved as Numbers.java.

12. No user input is taken for the two input parameter values. The static variables can be assigned any integer value and the program can be tested accordingly.

Answer:

the part of an engine that supplies the fuel/air mixture to the cylinders

Explanation:

There is also an exhaust manifold that collects the exhaust gases from multiple cylinders into a smaller number of pipes

Answer:

def output_ints_less_than_or_equal_to_threshold(user_values, upper_threshold):

  for value in user_values:

      if value < upper_threshold:

          print(value)  

def get_user_values():

  n = int(input())

  lst = []

  for i in range(n):

      lst.append(int(input()))

  return lst  

if __name__ == '__main__':

  userValues = get_user_values()

  upperThreshold = int(input())

  output_ints_less_than_or_equal_to_threshold(userValues, upperThreshold)

Explanation:

Answer:

#Declare variable to get the input

#list from the user

input_list = input()

#split the list into words by space

list = input_list.split()

#Begin for-loop to iterate each word

#to get the word frequency

for word in list:

#get the frequency for each word

frequency=list.count(word)

#print word and frequency

print(word,frequency)

Explanation:

This program that we are told to write will be done by using python programming language/ High-level programming language.

The question wants us to write a program in which the output will be as below;

hey 1

hi 2

Mark 1

hi 2

mark 1

Just by imputing hey hi mark hi mark.

Just copy and run the code below.

#Declare variable to get the input

#list from the user

input_list = input()

#split the list into words by space

list = input_list.split()

#Begin for-loop to iterate each word

#to get the word frequency

for word in list:

#get the frequency for each word

frequency=list.count(word)

#print word and frequency

print(word,frequency)

In this exercise we have to use the knowledge in computational language in python to write the following code:

We have the code can be found in the attached image.

So in an easier way we have that the code is

input_list = input()

list = input_list.split()

for word in list:

frequency=list.count(word)

print(word,frequency)

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Answer:

import java.util.*;

public class Grade {

   public static void main(String[] args) {

       Scanner input = new Scanner(System.in);

       double[] grades =  new double[4];

       for (int i=0; i<4; i++){

           System.out.print("Enter a grade: ");

           grades[i] = input.nextDouble();

       }

       double lowest = grades[0];

       double highest = grades[0];

       double total = 0;

       for (int i=0; i<4; i++){

           System.out.println("Grade " + (i+1) + " is: "  + grades[i]);

           if(grades[i] >= highest)

               highest = grades[i];

           if(grades[i] <= lowest)

               lowest = grades[i];

           total += grades[i];

       }

       double average = total/4;

       System.out.println("The highest grade is: " + highest);

       System.out.println("The lowest grade is: " + lowest);

       System.out.println("The average is: " + average);

  }

}

Explanation:

Ask the user for the grades and put them in the grades array using a for loop

Create another for loop. Inside the loop, print the grades. Find highest and lowest grades in the grades array using if-structure. Also, add each grade to the total.

When the loop is done, calculate the average, divide the total by 4.

Print the highest grade, lowest grade and average.

Answer:

A. Make Laws

Explanation:

Montesquieu believed the ways to go about limiting the power of a monarch would be to split up power among 3 groups, Judicial, Legislative and Executive. The American Presidential system and Constitution used Montesquieu's writings as a foundation for their principles.

Answer:

I think that they should ban ads for all four products.  These products, e-cigarettes, abortion clinics, ice cream, and sugared soft drinks, are all discreet adult products that should not be advertised because of their health hazards.  Since the "large online company provides a widely used search engine, social network, and/or news service, which are mainly patronized by younger people, such ads that promote products injurious to individual health should be banned.  Those who really need or want these products know where they could get them.  Therefore, the products should not be made easily accessible to all people.  Nor, should ads promote their patronage among the general population.

Explanation:

Advertisements create lasting and powerful images which glamourize some products, thereby causing the general population, especially children, to want to consume them without any discrimination of their health implications.  If online banning is then contemplated, there should not be any distinguishing among the four products: e-cigarettes, abortion clinics, ice cream, and sugared soft drinks.

Answer:

I would say cclrearner

Explanation:

This is what helped me with my computer so it may help you but try which one works for you

The bitmap is 1110 0000 0001 0000 after some use. The system always looks for free blocks beginning using a contiguous allocation technique.

After some use, the new bitmap is 1110 0000 0001 0000. The system employs a contiguous allocation mechanism and starts searching for free blocks at the position.

(a) File B is made up of five blocks, 1111 1111 1111 0000.

b) The batch number 1000 0001 1111 0000 deletes File A.

c) Eight blocks are used for writing in file C.

1111 1111 1111 1100

File B is deleted (d). 1111 1110 0000 1100

Free-space bitmaps are one method used by some file systems to keep track of allocated sectors. Even though the most fundamental implementation of free-space bitmaps is incredibly wasteful, some modern file systems use complex or hybrid versions of them.

Therefore, after some use, the bitmap is 1110 0000 0001 0000. The contiguous allocation strategy is always used by the system to look for free blocks to start with.

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Answer:

Explanation:

(a) The recurrence relation for the given problem is :

T(n) = T(n-1) + T(n-4) + 1

(b) The O(n) time recursive algorithm with memoization for the above recurrence is given below :

Create a 1-d array 'memo' of size, n (1-based indexing) and initialize its elements with -1.

func : a recursive function that accepts the cost array and startingJobNo and returns the minimum cost for doing the jobs from startingJobNo to n.

Algorithm :

func(costArr[], startingJobNo){

if(startingJobNo>n)

then return 0

END if

if(memo[startingJobNo] != -1)

then return memo[startingJobNo];

END if

int ans1 = func(costArr, startingJobNo+1) + costArr[startingJobNo]

int ans2 = func(costArr, startingJobNo+4) + h

memo[startingJobNo] = min(ans1,ans2);

return memo[startingJobNo];

}

(c)

First, Create a 1-d array 'dp' of size, N+1.

dp[0] = 0

bottomUp(int c[]){

for  i=1 till i = n

DO

dp[i] = min(dp[i-1] + c[i], dp[max(0,i-4)] + h);

END FOR

return dp[n];

}

(d)

Modifying the algorithm given in part (b) as follows to know which job to do yourself and in which jobs we need to hire a handyman.

First, Create a 1-d array 'memo' of size, n (1-based indexing) and initialize its elements with -1.

Next, Create another 1-d array 'worker' of size,n (1-based indexing) and initialize its elements with character 'y' representing yourself.

Algorithm :

func(costArr[], startingJobNo){

if(startingJobNo>n)

then return 0

END if

if(memo[startingJobNo] != -1)

then return memo[startingJobNo];

END if

int ans1 = func(costArr, startingJobNo+1) + costArr[startingJobNo]

int ans2 = func(costArr, startingJobNo+4) + h

if(ans2 < ans1)

THEN

for (i = startingJobNo; i<startingJobNo+4 and i<=n; i++)

DO

// mark worker[i] with 'h' representing that we need to hire a mechanic for that job

worker[i] = 'h';

END for

END if

memo[startingJobNo] = min(ans1,ans2);

return memo[startingJobNo];

}

//the worker array will contain 'y' or 'h' representing whether the ith job is to be done 'yourself' or by 'hired man' respectively.

2 4 9

Explanation:

Basically what I thought was the way was, since 2 is first, then its 1, then since 4 is second, it's added second, lastly to get the last oneI added them all and got 9 so that's third.

Answer:

Does not exist.

Explanation:

The answer is not in the option:

Let's analyse the code:

random.randint(2,4)

This means take in random integer numbers starting with 2 and ending with 4.

Meaning numbers : 2, 3 and 4

Next math.pow(a,2) means a× a = a2

So when we input 2 the function;

math.pow(a,2) returns an integer 4

You do same for input 3 , it returns 9.

For input 4 it returns 16.

And the result is encapsulated in the function string(). Meaning display the result as a string:

4 9 16

Answer:

The cpp program for the given scenario is as follows.

#include <iostream>

#include <iterator>

using namespace std;

int main()

{

   //boolean variable declared and initialized  

   bool sorted=true;

   //integer array declared and initialized

   int arr[] = {1, 2, 3, 4, 5};

   //integer variables declared and initialized to length of the array, arr

   int len = std::end(arr) - std::begin(arr);

       //array tested for being sorted

    for(int idx=0; idx<len-1; idx++)

    {

        if(arr[idx] < arr[idx+1])

           {

               sorted=false;

            break;

           }

    }

    //message displayed  

    if(sorted == false)

     cout<< "UNSORTED" <<endl;

 else

    cout<< "UNSORTED" <<endl;

return 0;

}

OUTPUT

UNSORTED

Explanation:

1. An integer array, arr, is declared and initialized as shown.

int arr[] = {1, 2, 3, 4, 5};

2. An integer variable, len, is declared and initialized to the size of the array created above.

int len = std::end(arr) - std::begin(arr);

3. A Boolean variable, sorted, is declared and initialized to true.

bool sorted=true;  

4. All the variables and array are declared inside main().

5. Inside for loop, the array, arr, is tested for being sorted or unsorted.  The for loop executes over an integer variable, idx, which ranges from 0 till the length of the array, arr.

6. The array is assumed to be sorted if all the elements of the array are in descending order.

7. If the elements of the array are in ascending order, the Boolean variable, sorted, is assigned the value false and for loop is exited using break keyword. The testing is done using if statement.

8. Based on the value of the Boolean variable, sorted, a message is displayed to the user.

9. The program can be tested for any size of the array and for any order of the elements, ascending or descending. The program can also be tested for array of other numeric data type including float and double.

10. All the code is written inside the main().

11. The length of the array is found using begin() and end() methods as shown previously. For this, the iterator header file is included in the program.

Answer:

Explanation:

The objective of this task is to compute a program that involves the usage of Python code to save the data to MongoDB and to query  the database.

Due to the error that occur which makes me to be unable to submit this answer, I've created a word document instead and the attached file can be found below.

Thanks!

Using the knowledge in computational language in C++ it is possible to write a code that complete main() to read dates from input, one date per line

#include <iostream>

#include <string>

using namespace std;

int DateParser(string month) {

  int monthInt = 0;

  if (month == "January")

      monthInt = 1;

  else if (month == "February")

      monthInt = 2;

  else if (month == "March")

      monthInt = 3;

  else if (month == "April")

      monthInt = 4;

  else if (month == "May")

      monthInt = 5;

  else if (month == "June")

      monthInt = 6;

  else if (month == "July")

      monthInt = 7;

  else if (month == "August")

      monthInt = 8;

  else if (month == "September")

      monthInt = 9;

  else if (month == "October")

      monthInt = 10;

  else if (month == "November")

      monthInt = 11;

  else if (month == "December")

      monthInt = 12;

  return monthInt;

}

int main ()

{

  // TODO: Read dates from input, parse the dates to find the one

  // in the correct format, and output in m/d/yyyy format

  while(1)

  {

   //declaring the required variables

  int monthInt,dayInt,yearInt;string input;

  //receive the input string frim the user

  getline(cin,input);

  //if the input is -1 then quit

  if(input=="-1")

    break;

  //else try to process the input

  try

  {

  //find and extract the month name and parse it to monthInt

  monthInt=DateParser(input.substr(0,input.find(' ')));

  //find and extract the day and parse it to dayInt

  dayInt=stoi(input.substr(input.find(' '),input.find(", ")));

  //find and extract the year and parse it to yearInt

  yearInt=stoi(input.substr(input.find(", ")+1,input.length()));

  //display the output

  cout<<monthInt<<"/"<<dayInt<<"/"<<yearInt<<endl;

  }

  //catch if any of the exceptions happens

  catch(exception& e){}

  }

}

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Answer:

Many-to-one (multiple inputs, single output)

Explanation:

Solution

In the case of a recurrent neural network that listens to a audio speech sample, and classifies it according to whose voice it is, the RNN will listen to the audio and will give result by doing classification.

There will be a single output, for the classified or say identified person.

The RNN will take a stream of input as the input is a audio speech sample.

Therefore, there will be multiple inputs to the RNN and a single output, making the best fit Architecture to be of type Many-to-one(multiple inputs, single output).

Answer:

cs

Explanation:

Answer:

3) Academic journal articles are always unbiased in their analysis.

Explanation:

The Academic journals are not always unbiased. There can be some authors which may write in some situation and bias the articles. It is important to analyse source and reliability of the article before relying on it. An unbiased author will try to capture picture fairly. The unbiased author presents the facts as it is and does not manipulates the truth.

Answer:

Hello your question lacks the required options which is : True or False

answer : TRUE

Explanation:

If a large organization wants to develop a software that will benefit the entire organization such software will be known as an enterprise application software and such application software must be developed in such a way that it meets the required purpose for which the organization is designed it for.

An enterprise application software is a computer software developed specially to satisfy the specific needs of an entire  organization inside of the individual needs of the people working in the organization.

Answer:

1  

def dict_intersect(d1,d2): #create dictionary

  d3={} #dictionaries

  for key1,value1 in d1.items():       #iterate through the loop  

      if key1 in d2:   #checking condition

          d3[key1]=(d1[key1],d2[key1])   #add the items into the dictionary  

  return d 3

print(dict_intersect({'a': 'apple', 'b': 'banana'}, {'b': 'bee', 'c': 'cat'})) #display

2

def consolidate(*l1):  #create consolidate

  d3={} # create dictionary

  for k in l1:       #iterate through the loop

      for number in k:   #iterate through  the loop                               d3[number]=d3.get(number,0)+1   #increment the value

             return d 3 #return

print(consolidate([1,2,3], [1,1,1], [2,4], [1])) #display

Explanation:

1

Following are  the description of program

2

Following are  the description of program