Which of the following linear equations has the steepest slope?
A. Y = -2x +11
B. y=+x+4
C. y - x +7
D. y - 7+2

Answer:

(a) A cross sectional study (b) The parameter can be computed as follows: Non-drinkers who agree exposed to obesity, Drinkers who are exposed or vulnerable to obesity (c) A postie relationship is established from the experiment between drinkers who are exposed to obesity and non drinkers who are exposed to obesity

Step-by-step explanation:

(a) The type of design is refereed to as a cross sectional study

(b) Now, because 50 men are beer drinkers out of 891 men.

Hence we can deduce form this that  500/891 gives us 0.56%.

This suggest that 0.56% men are beer drinkers out of which 325 have obesity, lets take for example 235/500 = 0.65% are exposed to obesity in which 80/ (89-500) = 80/491 = 0.16%

The non drinkers are 0.16% and are not exposed to obesity

Thus,

The parameters to be calculated is stated below:

(c) The next step is to determine and explain the results.

In this case we can say there is a positive relationship between drinkers and non drinkers, since from the experiment 0.65% are exposed to obesity and 0.16$ non drinkers are exposed to obesity.

Answer:

The test statistic to test the null hypothesis equals 1.059

Step-by-step explanation:

From the given information; we have:

Treatment               Observations

A                                20        30         25       33

B                                22         26        20       28

C                               40         30         28       22

The objective is to find the  test statistic to test the null hypothesis; in order to do that;we must first run through a series of some activities.

Let first compute the sum of the square;

Total sum of squares (TSS) = Treatment sum of squares [tex](T_r SS)[/tex]  +    Error sum of squares   (ESS)

where:

(TSS) = [tex]\sum \limits ^v_{i=1} \sum \limits ^{n_i}_{j-1}(yij- \overline {y}oo)^2[/tex]  with (n-1)   df

[tex](T_r SS)[/tex]   [tex]= \sum \limits ^v_{i=1} n_i( \overline yio- \overline {y}oo)^2[/tex]   with (v-1)  df

[tex](ESS) = \sum \limits ^v_{i=1} \sum \limits ^{n_i}_{j-1}(yij- \overline {y}io)^2[/tex]   with (n-v) df

where;

v= 3

[tex]n_i=[/tex]4

i = 1,2,3

n =12

[tex]y_{ij}[/tex] is the [tex]j^{th[/tex] observation for the [tex]i^{th[/tex] treatment

[tex]\overline{y}io[/tex] is the mean of the  [tex]i^{th[/tex] treatment  i = 1,2,3 ;  j = 1,2,3,4

[tex]\overline y oo[/tex]   is the overall mean

From the given data

[tex]\overline y oo = \dfrac{1}{12} \sum \limits ^3_{i=1} \sum \limits ^{4}_{j=1}(yij)^2= 27[/tex]

[tex]TSS = \dfrac{1}{12} \sum \limits ^3_{i=1} \sum \limits ^{4}_{j=1}(yij- 27)^2 = 378[/tex]

[tex]T_r SS= \sum \limits^3_{i=1}4 (\overline y io - \overline yoo)^2[/tex]

[tex]=4(27-27)^2+4(24-27)^2+4(30-27)^2 = 72[/tex]

Total sum of squares (TSS) = Treatment sum of squares [tex](T_r SS)[/tex]  +    Error sum of squares   (ESS)

(TSS) =  378 - 72

(TSS) =  306

Now; to the mean square between treatments (MSTR); we use the formula:

MSTR = TrSS/df(TrSS)

MSTR = 72/(3 - 1)

MSTR = 72/2

MSTR = 36

The mean square within treatments  (MSE) is:

MSE = ESS/df(ESS)

MSE = 306/(12-3)

MSE = 306/(9)

MSE = 34

The test statistic to test the null hypothesis is :

[tex]T = \dfrac{ \dfrac{TrSS}{\sigma^2}/(v-1) }{ \dfrac{ESS}{\sigma^2}/(n-v) } = \dfrac{MSTR}{MSE} \ \ \ \approx \ \ T(\overline {v-1}, \overline {n-v})[/tex]

[tex]T = \dfrac{36}{34}[/tex]

T = 1.059

Answer: 360ᴼ

Step-by-step explanation:

If a figure goes 360ᴼ around the graph, it will be mapped onto itself.

360ᴼ is full circle (number of degrees in a circle), so the figure just went around in a circle, back into the same location before it rotated.

Answer:

360

Step-by-step explanation:

i took the text

Answer: m is 13

m is 6

you find m by calculating!

Step-by-step explanation:

Answer: -8

Step-by-step explanation:

Answer:

Step-by-step explanation:

According to the condition, your terms are arranged as

5, 7 , -7 ,-5, 5, 7, -7, 5, -5,...................

So one loop will have 4 terms: 5, 7, -7. -5

Hence after 63 loops, the new loop has only 3 terms. That means the last loop will be 5, 7 ,-7. In other words, the 255th term will  be -7

Answer: 525

Step-by-step explanation:

3 km =30 hm

35hm*15=525

Answer:

Step-by-step explanation:

a. Null hypothesis: P = p

Alternatives hypothesis: P =/ p

Where P is the hypothesized population proportion and p is the sample proportion

b. Performing a test of proportions

Randomization: the sample was randomly selected in the study

The population size is at least 20 times as big as the sample size.

The sample includes both successes and failures with 29 success and 171 failures.

c. To perform the hypothesis test: we have to find the standard deviation first

Sd = sqrt[ P * ( 1 - P ) / n ]

where P is the hypothesized value of population proportion, n is the sample size.

Sd = √[0.12*(1-0.12)/200]

Sd = √[0.12*(0.88/200]

Sd = √[0.12*(0.0044)]

Sd = √0.000528

Sd = 0.023

Then we can find the z score

z = (p - P) / σ where p = 29/200 = 0.145

z = (0.145-0.12)/ 0.023

z = 0.025/0.023

z = 1.09

Calculation the p value using 0.05 level of significance and a two waited test (p value calculator),

A p-value of 0.2757 which is greater than 0.05, thus we will fail to reject the null stating that there is not enough strong evidence that the left-handed rate in the state of Maine is higher than the national average.

Answer:

A. d= 45t

Step-by-step explanation:

(assuming that you meant 67.5 in the last 1.5 hours)

67.5 miles = distance

1.5 hours = time

therefore:

[tex]\frac{d}{t\\}[/tex] = 67.5/1.5

making your answer 45

leaving a as your correct answer:

d= 45t

The proportion relationship between the distance d, and the time t, that the train has travelled is, d = 45t. So the correct option is A).

Proportional relationships are relationships between two variables where their ratios are equivalent. Another way to think about them is that, in a proportional relationship, one variable is always a constant value times the other.

Given that, A train travels at a constant speed and has travelled 67.5 miles in the last 1.5 hours. (assuming that you meant 67.5 in the last 1.5 hours)

67.5 miles = distance

1.5 hours = time

We know that, speed = distance / time

s = 67.5/1.5

s = 45 mph

Now, distance = speed × time

d = 45t

Hence, the proportion relationship between the distance d, and the time t, that the train has travelled is, d = 45t. So the correct option is A).

For more references on proportion relationship, click;

https://brainly.com/question/29765554

#SPJ5

Answer:

9.222222222

Step-by-step explanation:

7+21+2+17+3+13+7+4+9 = 83

7+21+2+17+3+13+7+4+9 = 83 83÷9 = 9.222222222

_____________________________

Hey!!

Solution,

Given data=7,21,2,17,3,13,7,4,9

summation FX= 83

N(total no. of items)=9

Now,

Mean=summation FX/N

= 83/9

=9.23

So the answer is 9.23

__________________________

Answer: the answer is linear pair

Step-by-step explanation:

Answer:

Linear pair postulate

Step-by-step explanation:

Answer:

So since the formula for a square is w*h

That means that the area is 1*1 or 1 unit^2

I knew it was a joke question.

:))))

Step-by-step explanation:

Answer:

Step-by-step explanation:

Consider the calculations in the table below with the respective columns being: Name | Laps | Time | Time(in hours) |Total Distance | Unit Rate

[tex]\left|\begin{array}{c|c|c|c|c|c}---&---&---&----&----&---\\Amber&3&40&\frac{40}{60}&3*\frac{3}{4}=2.25&2.25 \div \frac{40}{60}= 3\frac{3}{8} \\\\Bruno&4&54&\frac{54}{60}&4*\frac{3}{4}=3&3 \div \frac{54}{60}= 3\frac{1}{3}\\\\Cady&5&75&\frac{75}{60}&5*\frac{3}{4}=3.75&3.75 \div \frac{75}{60}= 3 \\\\Drake&6&72&\frac{72}{60}&6*\frac{3}{4}=4.5&4.5 \div \frac{72}{60}= 3\frac{3}{4} \end{array}\right|[/tex]

We can then match each walker to their respective unit rates in miles per hour.

Answer:

9.72% probability that among the next 7 theft cases reported in this district, exactly 3 of them resulted from the need to buy drugs.

Step-by-step explanation:

For each theft, there are only two possible outcomes. Either the need to buy drugs is the reason of the theft, or it is not. Each theft is independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

In a certain city district the need for money to buy drugs is stated as the reason for 70% of all thefts.

This means that [tex]p = 0.7[/tex]

Find the probability that among the next 7 theft cases reported in this district, exactly 3 of them resulted from the need to buy drugs.

This is P(X = 3) when n = 7. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 3) = C_{7,3}.(0.7)^{3}.(0.3)^{4} = 0.0972[/tex]

9.72% probability that among the next 7 theft cases reported in this district, exactly 3 of them resulted from the need to buy drugs.

Answer:

Step-by-step explanation:

On the y-axis, graph the point on (0,4). Then from there, go up one, and to the right 4.

Answer:

  8

Step-by-step explanation:

We can start by making the table below to show the given numbers (red) and to assign a variable (x) to the number we want to find: female PhDs.

By subtracting the female numbers from the totals, we can find the corresponding numbers of male PhDs and non-PhDs.

The number of male non-PhDs is twice the number of male PhDs, so we have ...

  2(14 -x) = 20 -x

  28 -2x = 20 -x . . . . eliminate parentheses

  8 = x . . . . . . . . . . . .add 2x-20

The number of female faculty with PhDs is 8.

Answer:

1. 100[tex]\pi[/tex]

2. 27 [tex]cm^{3}[/tex]

3. 30

Step-by-step explanation:

Area = [tex]\pi[/tex][tex]r^{2}[/tex]

       = [tex]\pi[/tex] x [tex]10x^{2}[/tex]

       = 100[tex]\pi[/tex]

Volume = l x w x h

             = 3 x 3 x 3

             = 27

Answer:

Option (3)

Step-by-step explanation:

Given functions are f(x) = 4 - x² and g(x) = 6x

We gave to find the expression for (g - f)(3).

(g - f)(x) = g(x) - f(x)

            = 6x - (4 - x²)

            = 6x - 4 + x²

By substituting x = 3 in this expression,

(g - f)(x) = 6(3) - 4 + (3)²

Therefore, option (3) will be the answer.

Answer:

Step-by-step explanation:

a) Number of variables in the data set : 5

b) A quantitative variable is the one which can be quantitatively measured. i.e. it is a numerical value.

A categorical variable is the one that can take one value from a limited number of fixed values.

Exchange is a Categorical Variable. Price/Earnings Ratio is a Quantitative Variable. Gross Profit Margin (%) is a Quantitative Variable.

c. Out of the 25 stocks, AMEX is the exchange for 5 stocks. So percent frequency is 5/25 = 0.2 = 20%.

NYSE is the exchange for 3 stocks. So percent frequency is 3/25 = 0.12 = 12%.

OTC is the exchange for 17 stocks. So percent frequency is 17/25 = 0.68 = 68%.

These percentages are correctly shown in graph a. So the answer is a.

d) The frequency distribution is

Gross Profit Margin                Frequency

0-14.9                                        2

15-29.9                                      6

30-44.9                                     8

45.59.9                                    6

60.74.9                                    3

As we come across the Gross Profit Margin values in the table, we add a | next to its respective interval and build the above table. E.g. the first value in the table under Gross Profit Margin is 36.7 which lies in the interval 30–44.9. So we add one | in fromt of that interval and so on until we cover the entire table. The number of | shows the frequency distribution of the values.

The correct histogram is A.

e. The average price/earnings ratio is found by adding all the 25 values in the table and dividing the answer by 25.

= 505.40/25

Answer:

A) MP(q) = -3q² + 440q - 13

B) 146.64 units.

Step-by-step explanation:

The profit function is given by the revenue minus the cost function:

[tex]P(q) = R(q) - C(q)\\P(q) = -q^3+220q^2-500-13q[/tex]

A) The Marginal profit function is the derivate of the profit function as a function of the quantity sold:

[tex]P(q) = -q^3+220q^2-500-13q\\MP(q) = \frac{dP(q)}{dq} \\MP(q)=-3q^2+440q-13[/tex]

B) The value of "q" for which the marginal profit function is zero is the number of items (in hundreds) that maximizes profit:

[tex]MP(q)=0=-3q^2+440q-13\\q=\frac{-440\pm \sqrt{440^2-(4*(-3)*(-13))} }{-6}\\q'=146.64\\q'' = - 0.03[/tex]

Therefore, the only reasonable answer is that 146.64 hundred units must be sold in order to maximize profit.

Answer:

Step-by-step explanation:

Hello!

The table shows the daily sales (in $1000) of shopping mall for some randomly selected  days

Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5

Days 18 27 31 40 56 55 23

Use it to answer questions 13 and 14.

13. What is the approximate value for the modal daily sales?

To determine the Mode of a data set arranged in a frequency table you have to identify the modal interval first, this is, the class interval in which the Mode is included. Remember, the Mode is the value with most observed frequency, so logically, the modal interval will be the one that has more absolute frequency. (in this example it will be the sales values that were observed for most days)

The modal interval is [3.1-3.5]

Now using the following formula you can calculate the Mode:

[tex]Md= Li + c[\frac{(f_{max}-f_{prev})}{(f_{max}-f_{prev})(f_{max}-f_{post})} ][/tex]

Li= Lower limit of the modal interval.

c= amplitude of modal interval.

fmax: absolute frequency of modal interval.

fprev: absolute frequency of the previous interval to the modal interval.

fpost: absolute frequency of the posterior interval to the modal interval.

[tex]Md= 3,100 + 400[\frac{(56-40)}{(56-40)+(56-55)} ]= 3,476.47[/tex]

A. $3,129.41 B. $2,629.41 C. $3,079.41 D. $3,123.53

Of all options the closest one to the estimated mode is A.

14. The approximate median daily sales is …

To calculate the median you have to identify its position first:

For even samples: PosMe= n/2= 250/2= 125

Now, by looking at the cumulative absolute frequencies of the intervals you identify which one contains the observation 125.

F(1)= 18

F(2)= 18+27= 45

F(3)= 45 + 31= 76

F(4)= 76 + 40= 116

F(5)= 116 + 56= 172 ⇒ The 125th observation is in the fifth interval [3.1-3.5]

[tex]Me= Li + c[\frac{PosMe-F_{i-1}}{f_i} ][/tex]

Li: Lower limit of the median interval.

c: Amplitude of the interval

PosMe: position of the median

F(i-1)= accumulated absolute frequency until the previous interval

fi= simple absolute frequency of the median interval.

[tex]Me= 3,100+400[\frac{125-116}{56} ]= 3164.29[/tex]

A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664

Of all options the closest one to the estimated mode is C.

Answer:

  [tex]f^{-1}(x)=4x+48[/tex]

Step-by-step explanation:

To find the inverse, solve for y:

  x = f(y)

  x = (1/4)y -12

  x +12 = (1/4)y . . . . add 12

  4(x +12) = y . . . . . multiply by 4

  y = 4x +48 . . . . . . simplify

The inverse function is ...

  [tex]\boxed{f^{-1}(x)=4x+48}[/tex]

Answer:

x = 1/9

Step-by-step explanation:

3^ (x+1) = 9 ^ (5x)

Replace 9 with 3^2

3^ (x+1) = 3^2 ^ (5x)

We know that a^b^c = a ^(b*c)

3^ (x+1) = 3^(2 * (5x))

3^ (x+1) = 3^(10x)

The bases are the same so the exponents are the same

x+1 = 10x

Subtract x from each side

x+1-x = 10x-x

1 = 9x

Divide each side by 9

1/9 = 9x/9

1/9 =x

Step-by-step explanation:

Total gum balls = 22 + 18 + 10 + 23 = 73

Probability of red gum = 22/73

Answer:

he will be 25

Step-by-step explanation:

36 monthly payments left/12 payments a year = 3 years. 22 + 3 = 25

Answer:

So C doesn't have symmetry so that rules out a

b does though

J doesn't work so that rules out c

F doesn't work so that rules out d

B is answer

Answer:

B. is the rotational symmetry

Step-by-step explanation:

Answer:

Graph D

Step-by-step explanation:

First, look at the x-intercepts (where the graph touches the x-axis): x= -1 and x= 3

This rules out Graph B and C which have x-intercepts at x= -3 and x= -1

Next, look at the y-intercept (where the graph touches the y-axis): y= -3

This rules out Graph A which has a y-intercept at y= 3

Answer:

a) N(33,15).

b) 37.33% probability that a randomly selected LA worker has a commute that is longer than 38 minutes

c) 45.6 minutes.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 33, \sigma = 15[/tex]

a. What is the distribution of X?

Normal with mean 33 and standard deviaton 15. So

N(33,15).

b. Find the probability that a randomly selected LA worker has a commute that is longer than 38 minutes

This is 1 subtracted by the pvalue of Z when X = 38. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{38 - 33}{15}[/tex]

[tex]Z = 0.333[/tex]

[tex]Z = 0.333[/tex]  has a pvalue of 0.6267.

1 - 0.6267 = 0.3733

37.33% probability that a randomly selected LA worker has a commute that is longer than 38 minutes

c. Find the 80th percentile for the commute time of LA workers.

This is X when Z has a pvalue of 0.8. So it is X when Z = 0.84.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.84 = \frac{X - 33}{15}[/tex]

[tex]X - 33 = 0.84*15[/tex]

[tex]X = 45.6[/tex]

45.6 minutes.

Answer:

The slope of AB is

different than the

slope of BC.

Step-by-step explanation:

Answer:

b = -18

Step-by-step explanation:

(3 + 4i) (-3-2i)

When we foil:

-9 + -6i + -12i + -8i^2

-8i^2 = +8

Combine like terms:

-1 + -18i