which of the following is a condition in order for a setting to be considered binomial: group of answer choices the probability of success is the same for each trial. each observation/trial has 3 possible outcomes. the number of outcomes varies on the first success. the trials are dependent on one another.

To obtain the solution of the wave equation, we need to use the given initial conditions and apply them to the general solution of the wave equation. The wave equation is: ∂²y/∂x² = 1/v² * ∂²y/∂t² where v is the velocity of the wave.

The general solution to this equation is:

y(x,t) = f(x + vt) + g(x - vt)

where f and g are arbitrary functions that depend on the initial conditions.

Using the given initial conditions, we can determine the values of f and g. When x = 1, we have:

y(1,t) = f(1 + vt) + g(1 - vt) = P cos(pr)

Similarly, when x = 0, we have:

y(0,t) = f(vt) + g(-vt) = 0

To solve for f and g, we can use the method of separation of variables. Let:

f(1 + vt) = F(vt) and g(1 - vt) = G(-vt)

Substituting these expressions into the first initial condition, we have:

F(vt) + G(-vt) = P cos(pr)

Differentiating both sides with respect to t, we get:

v[F'(vt) - G'(-vt)] = -P pr sin(pr)

Dividing both sides by v and substituting v = √(T/ρ), where T is the tension and ρ is the mass density, we get:

[F'(vt) - G'(-vt)] = -P pr sin(pr) / √(Tρ)

Integrating both sides with respect to t, we get:

F(vt) - G(-vt) = -P cos(pr) / √(Tρ)

Using the second initial condition, we have:

F(0) + G(0) = 0

Substituting F(vt) = f(1 + vt) and G(-vt) = g(1 - vt), we get:

f(1) + g(1) = 0

Solving these two equations for f and g, we get:

f(x) = (P/2) cos(pr - 2πx/λ)

g(x) = -(P/2) cos(pr + 2πx/λ)

where λ = v/f is the wavelength.

Therefore, the solution to the wave equation is:

y(x,t) = (P/2) cos(pr - 2π(x - vt)/λ) - (P/2) cos(pr + 2π(x + vt)/λ)

which satisfies the initial conditions y(1,t) = P cos(pr) and y(0,t) = 0.

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The value of C is calculated to be -6.

If F(x) = x + 9x + C and F(1) = 4, we can use the given information to solve for C by using Green's theorem;

F(1) = 1 + 9(1) + C = 4

Simplifying, we get:

C = 4 - 1 - 9 = -6

Therefore, the value of C is -6.

If F(x) = x + 9x + C and F(1) = 4, we can still use the given information to solve for C:

F(1) = 1 + 9(1) + C = 4

Simplifying, we get:

C = 4 - 1 - 9 = -6

Now, we can use the value of C to simplify the expression for F(x):

F(x) = x + 9x - 6x^2

Simplifying further, we get:

F(x) = -6x^2 + 10x

Therefore, FC(x) = x² FC = -6x² + 10x² = 4x².

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Using Kepler's Third Law, we can find the distance of the exo-planet from its star. The formula is P^2 = a^3, where P is the orbital period in years and a is the average distance from the planet to the star in astronomical units (AU).

the average distance of Le Grosse Homme from its star is approximately 2 AU, which is answer choice b).

To determine the distance of the exo-planet Le Grosse Homme to the star, we will use Kepler's Third Law, which states that the square of the orbital period (P) of a planet is proportional to the cube of the semi-major axis (a) of its orbit. The formula is given as:

P² = a³

In this case, the orbital period P is 2.8284 years. We can now solve for the semi-major axis (a), which represents the distance from the planet to the star in astronomical units (AU).

Step 1: Square the orbital period
(2.8284)² = 7.99968336

Step 2: Find the cube root of the squared orbital period to get the distance (a)
a = ∛(7.99968336) ≈ 2.0 AU

So, the distance of the exo-planet Le Grosse Homme to the star is approximately 2.0 AU. The correct answer is option (b) ~2.0 AU.

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The equation is written as ; <SVT = 90/2

The measure of the angle SVT = 45 degrees

To determine the value of the angle, we need to take into considerations the properties of a right-angled triangle.

These properties are;

From the information given, we have that;

RVT is a right -angled triangle

Since the diagonal SV bisects the angle 90 degrees into two equal halves, then,

<SVT = 90/2

Divide the angle

<SVT = 45 degrees

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Answer:

2($3.95 + $4.75)(1.05) = $18.27

There is about a 33.7% probability that a case of 48 cans will contain at least two cans with a defective ball.

To solve this problem, we can use the binomial distribution. Let's define "success" as getting a can with no defective ball and "failure" as getting a can with at least one defective ball.

The probability of success in one can is:

P(success) = 1 - P(failure) = 1 - 0.025 = 0.975

The probability of failure in one can is:

P(failure) = 0.025

Now, let's define X as the number of cans in a case of 48 that have at least one defective ball. We want to find the probability that X is greater than or equal to 2.

We can use the binomial distribution formula to calculate this probability:

P(X ≥ 2) = 1 - P(X < 2) = 1 - P(X = 0) - P(X = 1)

P(X = 0) = (0.975)^48 ≈ 0.223

P(X = 1) = 48C1 (0.975)^47 (0.025)^1 ≈ 0.44

where 48C1 is the number of ways to choose one can out of 48.

Therefore, the probability that a case of 48 cans will contain at least two cans with a defective ball is:

P(X ≥ 2) ≈ 1 - 0.223 - 0.44 ≈ 0.337

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The average velocity of an object dropped off a building between 2 seconds and 3 seconds is less than the average velocity of the object between 2 seconds and 3.5 seconds.

This is because the velocity of a freely falling object due to gravity increases at a constant rate of 9.8 m/s² (assuming negligible air resistance). Therefore, the object's velocity at 3.5 seconds will be greater than its velocity at 3 seconds, resulting in a higher average velocity over the longer time interval.

In other words, the object falls faster as time passes, which means that its instantaneous velocity increases over time. Therefore, the average velocity over a longer time interval will be higher than the average velocity over a shorter time interval, assuming the object continues to fall freely with no additional forces acting upon it.

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The mean, also known as the average, is calculated by adding up all the values in a dataset and dividing by the total number of values in the dataset. The correct answer is b. mean.

The mean, also known as the average, is calculated by adding up all the values in a dataset and dividing by the total number of values in the dataset. It is the sum of all the values divided by the count of values in the dataset. The mean is a measure of central tendency and is commonly used to represent the "typical" or "average" value in a dataset.

Therefore, the mean is calculated by adding up all the values in a dataset and dividing by the total number of values in the dataset.

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The equation of the plane is -x - 20y + 4z + 1 = 0

The plane that contains the line r = (-4,-3,3) + f(4,1,0) and is parallel to the vector u = (0,1,5) must also be perpendicular to the vector u.

Let's find the normal vector of the plane first.

The direction vector of the line is d = (4,1,0).

Since the plane is parallel to u, its normal vector must be perpendicular to u.

Therefore, the normal vector of the plane is the cross product of d and u:

n = d × u = (4,1,0) × (0,1,5) = (-1,-20,4)

We can use the point-normal form of the equation of a plane:

n · (r - p) = 0

We can choose any point on the line as the point on the plane, so let's choose (-4,-3,3):

(-1,-20,4) · (r - (-4,-3,3)) = 0

Expanding the dot product, we get:

-x - 20y + 4z + 1 = 0

Hence,  the equation of the plane is -x - 20y + 4z + 1 = 0

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To find the curvature of the curve r(t), first compute its first and second derivatives, then use the curvature formula: κ(t) = (18t) / (9 + 9t^4)^(3/2), where r(t) = (3t + 9)i - 9j + (6 - 3/2t^2)k.

To find the curvature of the curve r(t), we need to compute the first and second derivatives of r(t), and then use the curvature formula. Given r(t) = (3t + 9)i - 9j + (6 - 3/2t^2)k:

First, find the first derivative r'(t):
r'(t) = (3)i - (3t^2)k

Next, find the second derivative r''(t):
r''(t) = (-6t)k

Now, we use the curvature formula:
κ(t) = |r'(t) × r''(t)| / |r'(t)|^3

Compute the cross product r'(t) × r''(t):
(3)i × (-6t)k = -18tj

Compute the magnitudes |r'(t) × r''(t)| and |r'(t)|^3:
|r'(t) × r''(t)| = |-18t| = 18t
|r'(t)| = √(3^2 + 0^2 + (-3t^2)^2) = √(9 + 9t^4)
|r'(t)|^3 = (9 + 9t^4)^(3/2)

Finally, find the curvature κ(t):
κ(t) = (18t) / (9 + 9t^4)^(3/2)

This is the curvature of the curve r(t) at any point t.

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For fx=ln(x^4x): f(x) = ln(x^4x) = 5ln(x), f'(x) = 5/x, f''(x) = -5/x^2. For fx=2e^-x^2: f(x) = 2e^-x^2, f'(x) = -4xe^-x^2, f''(x) = (8x^2 - 4)e^-x^2. Using chain rule and product rule, we can find the solutions.

To find the second derivative f''(x) for the given functions, we'll first find the first derivative f'(x) and then derive it again.

For the first function, f(x) = ln(x^4/x):
1. Simplify: f(x) = ln(x^3)
2. Find f'(x) using the chain rule: f'(x) = (1/x^3) * 3x^2 = 3/x
3. Find f''(x): f''(x) = -3/x^2

For the second function, f(x) = 2e^(-x^2):
1. Find f'(x) using the chain rule: f'(x) = 2(-2x)e^(-x^2) = -4xe^(-x^2)
2. Find f''(x) using the product rule: f''(x) = -4e^(-x^2) - 4x(-2x)e^(-x^2) = -4e^(-x^2) + 8x^2e^(-x^2)

So, the second derivatives are f''(x) = -3/x^2 for the first function and f''(x) = -4e^(-x^2) + 8x^2e^(-x^2) for the second function.

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Percentage and angles.

The derivative of f(x) = -4x with respect to x, or dy/dx, is -4.

To find the derivative of f(x) = -4x using first principles.
First, let's recall the definition of the derivative using first principles:
f'(x) = lim (h → 0) [(f(x + h) - f(x))/h]
Now, substitute f(x) = -4x into the definition:
f'(x) = lim (h → 0) [(-4(x + h) - (-4x))/h]
Next, distribute -4 to both x and h in the numerator:
f'(x) = lim (h → 0) [(-4x - 4h + 4x)/h]
Simplify the expression by canceling out -4x and +4x:
f'(x) = lim (h → 0) [(-4h)/h]
Cancel out h in the numerator and denominator:
f'(x) = lim (h → 0) [-4]

Since -4 is a constant and doesn't depend on h, the limit is simply:
f'(x) = -4.

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The sign of a z-score tells us whether the data point is above or below the mean.

A positive z-score indicates that the data point is above the mean, while a negative z-score indicates that the data point is below the mean. The further away the z-score is from zero, the more extreme the data point is relative to the mean.
A z-score is a numerical value that represents how far a data point is from the mean in terms of standard deviations. The sign of a z-score, either positive (+) or negative (-), indicates the direction of the deviation from the mean.

A positive z-score (+) indicates that the data point is above the mean, or it is higher than the average value in the distribution. On the other hand, a negative z-score (-) indicates that the data point is below the mean, or it is lower than the average value in the distribution.

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The best integration technique to use for the given integral ∫2x(x^2+1)^5 dx is D) The substitution rule.

This is because you can substitute u = x^2 + 1, making the integral easier to solve. The other rules mentioned are differentiation rules, not integration techniques.

The substitution rule, also known as u-substitution, is a fundamental technique in integration that involves replacing a function inside the integral with a new variable, making it easier to solve. This is the reason why it is also known as the "inside-out" method.

In the given integral, we have the term (x^2+1)^5, which is a composite function. By letting u = x^2+1, we can simplify the integrand and express the integral in terms of u as follows:

∫2x(x^2+1)^5 dx = ∫(x^2+1)^5 d(x^2+1) [Substitute u = x^2+1]

= (1/2) ∫u^5 du [Integrate with respect to u]

= (1/12) u^6 + C [Replace u with x^2+1 and add the constant of integration]

Therefore, the solution to the integral is:

∫2x(x^2+1)^5 dx = (1/12) (x^2+1)^6 + C

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The local minimum of the function f(x, y) is (-1.957, 0.391) with a value of -241.427.

To find the local maxima, minima and saddle points of the function f(x, y), we need to follow these steps:

Find the partial derivatives of f(x, y) with respect to x and y.

Set these partial derivatives equal to zero and solve for x and y to find the critical points.

Find the second partial derivatives of f(x, y) with respect to x and y.

Evaluate these second partial derivatives at each critical point.

Use the second partial derivatives to determine the nature of each critical point (whether it is a local maximum, minimum, or saddle point).

Let's follow these steps:

Find the partial derivatives of f(x, y) with respect to x and y.

[tex]f_x = 26x + 5y + 99[/tex]

[tex]f_y = 10y + 5x + 4[/tex]

Set these partial derivatives equal to zero and solve for x and y to find the critical points.

26x + 5y + 99 = 0

10y + 5x + 4 = 0

Solving these equations simultaneously, we get:

x = -1.957

y = 0.391

Find the second partial derivatives of f(x, y) with respect to x and y.

[tex]f_xx = 26[/tex]

[tex]f_xy = 5[/tex]

[tex]f_yy = 10[/tex]

Evaluate these second partial derivatives at each critical point.

At (-1.957, 0.391), we have:

[tex]f_xx = 26[/tex]

[tex]f_xy = 5[/tex]

[tex]f_yy = 10[/tex]

Use the second partial derivatives to determine the nature of each critical point.

Let's compute the discriminant[tex]D = f_xx * f_yy - (f_xy)^2[/tex] at the critical point:

[tex]D = (26 * 10) - (5^2) = 255[/tex]

Since D > 0 and[tex]f_xx[/tex]  > 0 at the critical point, we conclude that (-1.957, 0.391) is a local minimum of f(x, y).

Therefore, the function f(x, y) has only one critical point which is a local minimum at (-1.957, 0.391), and there are no saddle points.

The value of the function at the critical point is:

[tex]f(-1.957, 0.391) = 13(-1.957)^2 + 5(-1.957)(0.391) + 8(0.391)^2 + 99(-1.957) + 4(0.391) + 17 = -241.427[/tex]

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The function  sin x + cos y = 2y does not have critical points and there are there are no relative maxima or minima.

To find the critical points, we need to find the values of x and y such that the partial derivatives are equal to zero:

∂/∂x(sin x + cos y) = cos x = 0

∂/∂y(sin x + cos y) = -sin y = 2

From the first equation, we get cos x = 0, which means x = π/2 + nπ, where n is an integer.

From the second equation, we get -sin y = 2, which has no real solutions. Therefore, there are no critical points.

Since there are no critical points, there are no relative maxima or minima.

Hence, the function  sin x + cos y = 2y does not have critical points and there are there are no relative maxima or minima.

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As Schmuller emphasizes (p106-110), and as noted in class, R's sd function (sd(x) -- in the Basic R package), assumes n-1 in the denominator. The n-1 term would be used if the distribution of scores represented a sample of values on the variable.

This is because in a sample, there is inherent variability due to chance, and using n-1 instead of n in the denominator of the formula for standard deviation accounts for this variability. Therefore, the correct answer is c. a sample of values on the variable. As Schmuller emphasizes (p106-110), the R's sd function (sd(x) -- in the Basic R package) uses n-1 in the denominator. The n-1 term is applied when the distribution of scores represents:
c. a sample of values on the variable. This is because using n-1, known as Bessel's correction, provides an unbiased estimate of the population variance when working with a sample rather than the entire population.

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Mark has left with 44 inches. The correct option is C.

An object or event's attributes are quantified through measurement so that they can be compared to those of other things or occurrences.

To solve this problem, we need to first convert the measurements to a common unit. Let's convert everything to inches:

To find out how much rope Mark had left after cutting off 4 feet 6 inches, we need to subtract 54 inches from 98 inches:

98 inches - 54 inches = 44 inches

Therefore, the answer is C. 44 inches.

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As sample size decreases, the degrees of freedom decrease.

This affects both the group and error degrees of freedom. Specifically:

The group degrees of freedom (df between) decrease as the number of groups decreases. This is because there are fewer groups to estimate the population means from, resulting in fewer degrees of freedom for group differences.

The error degrees of freedom (df within) decrease as the sample size within each group decreases. This is because there is less information available to estimate the variation within each group, resulting in fewer degrees of freedom for residual variation.

The total degrees of freedom (df total) also decrease as the number of observations decreases, since the total degrees of freedom is equal to the number of observations minus 1.

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This information could help healthcare providers tailor their treatment plans and interventions for patients diagnosed with that disease at the hospital.

As an AI language model, I don't have an intended future career. However, I can provide an example from the nursing profession. Let's say a nurse wants to do a hypothesis test to determine if the population mean age of patients diagnosed with a specific disease at a hospital is significantly different from the national population mean age for that disease. The target population for this hypothesis test would be all patients diagnosed with that disease at the hospital. The nurse could collect a sample of patient data from the hospital and use statistical analysis to determine if the hospital's population mean age for the disease is significantly different from the national population means age. This information could help healthcare providers tailor their treatment plans and interventions for patients diagnosed with that disease at the hospital.

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False.

A scatter plot can help distinguish between a curvilinear and a linear relationship by visually displaying the data points, whereas the correlation coefficient primarily measures the strength and direction of a linear relationship between two variables, but does not account for curvilinear relationships.

On the other hand, the correlation coefficient measures the strength and direction of a linear relationship between two variables. It ranges from -1 to +1, with values closer to -1 indicating a strong negative linear relationship, values closer to +1 indicating a strong positive linear relationship, and values close to 0 indicating little or no linear relationship.

However, the correlation coefficient does not account for curvilinear relationships, which means that even if the correlation coefficient is close to 0, there could still be a curvilinear relationship between the two variables.

Therefore, while a scatter plot can help distinguish between a curvilinear and a linear relationship by visually displaying the data points, the correlation coefficient primarily measures the strength and direction of a linear relationship between two variables, but does not account for curvilinear relationships.

It is important to use both tools in conjunction to fully understand the relationship between two variables.

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The probability that a random sample of 100 bulbs will have an average life of more than 1,825 hours is approximately 0.1056, or 10.56%.

To find the probability that a random sample of 100 bulbs will have an average life of more than 1,825 hours, we need to use the central limit theorem.

First, we need to calculate the standard error of the mean, which is the standard deviation of the population (200 hours) divided by the square root of the sample size (100):

standard error of the mean = 200 / √(100) = 20

Next, we need to standardize the sample mean using the formula:

z = (x - mu) / SE

where x is the sample mean (1,825 hours), mu is the population mean (1,800 hours), and SE is the standard error of the mean (20 hours).

z = (1825 - 1800) / 20 = 1.25

Finally, we need to find the probability that a standard normal distribution is greater than 1.25. We can use a standard normal distribution table or calculator to find this probability, which is approximately 0.1056.

Therefore, the probability that a random sample of 100 bulbs will have an average life of more than 1,825 hours is approximately 0.1056, or 10.56%.

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a.) What fraction of the buildings are bigger than 150 meters high is 0.0038.

b.) The median height and the 95th percentile of the height distribution is 135.675 meters.

c.) In a random sample of 25 buildings, the approximate probability that fewer than 10 buildings exceed the median height is 0.1587. 

a) To discover the division of buildings that are taller than 150 meters, ready to utilize the standard normal distribution table or a calculator. To begin with, we have to standardize the esteem of 150 meters utilizing the equation:

z = (x - μ) / σ

where x = 150, μ = 110, and σ = 15

z = (150 - 110) / 15 = 2.67

Employing a standard typical dispersion table, we discover that the range to the correct of 2.67 is around 0.0038. This implies that as it were 0.38% of the buildings are taller than 150 meters.

b) The middle tallness of the building can be found utilizing the equation:

middle = μ = 110 meters

To discover the 95th percentile of the stature dispersion, we are able to utilize the standard ordinary dispersion table or a calculator. We ought to discover the z-score that compares to the 95th percentile, which is 1.645. Utilizing the equation for standardizing esteem, we get:

1.645 = (x - 110) / 15

Tackling for x, we get:

x = 135.675

Subsequently, the 95th percentile of the tallness dispersion is roughly 135.675 meters.

c) The number of buildings that surpass the middle tallness in a test of 25 buildings takes after binomial dissemination with parameters n = 25 and p = 0.5, since the likelihood of a building being taller or shorter than the middle is rise to 0.5.

We can utilize the ordinary guess to the binomial dissemination to inexact the probability that less than 10 buildings surpass the middle tallness. The cruel of the binomial conveyance is

μ = np = 25 x 0.5 = 12.5,

and the standard deviation is

σ = √(np(1-p)) = √(25 x 0.5 x 0.5) = 2.5.

To utilize the ordinary estimation, we ought to standardize the esteem of 10 utilizing the formula:

z = (x - μ) / σ

z = (10 - 12.5) / 2.5 = -1

Employing a standard typical conveyance table or a calculator, we discover that the region to the cleared out of -1 is roughly 0.1587.

Hence, the surmised likelihood that less than 10 buildings exceed the middle tallness is 0.1587. 

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Answer:

5

Step-by-step explanation:

becaus the x is more diferent like 4×15 is a representation of the algebar so is 5

(a) The conditions for testing the hypothesis are:

1. Random sample 2. Normality:

(b) The box plot also shows that there are no outliers and the data is evenly spread, supporting the normality assumption. Therefore, the conditions for testing the hypothesis are satisfied.

1. Random sample: The sample of 10 orders is stated to be randomly selected, so this condition is met.
2. Normality: The manager must verify that the wait time is normally distributed. The normal probability plot shows that the data points are roughly linear, indicating that the data is normally distributed. Therefore, this condition is met.
3. Independence: The sample does not contain any others, so this condition is met.

(b) The box plot also shows that there are no outliers and the data is evenly spread, supporting the normality assumption. Therefore, the conditions for testing the hypothesis are satisfied.

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Answer:

pootis

Step-by-step explanation:

this is pootis, he is very lovable.

The statement that is true about the triangles is: "The triangles must be similar." When two triangles have two pairs of corresponding congruent angles, they are called similar triangles. The corresponding sides of similar triangles are proportional to each other, but their lengths may differ. However, since two angles in each triangle are congruent, the third angle must also be congruent. Therefore, the triangles have the same shape, but possibly different sizes.

~~~Harsha~~~

The positive difference between the two solutions of the quadratic equation [tex]2x^{2}[/tex] + 5x + 12 = 19 -7x is [tex]\frac{\sqrt{200} }{4}[/tex].

We are required to determine the positive difference between the two solutions of the given quadratic equation: [tex]2x^{2}[/tex] + 5x + 12 = 19 -7x

1. Move all terms to the left side of the equation to form a standard quadratic equation:

[tex]2x^{2}[/tex] + 5x + 12 + 7x - 19 = 0

2. Simplify the equation: [tex]2x^{2}[/tex] + 12x - 7=0.

3. Use the quadratic formula to find the solutions for x:

[tex]x = \frac{-b \pm \sqrt{b^{2} -4ac}}{2a}[/tex]

where a=2, b=12, and c=-7.

4. Substitute the values:

[tex]x = \frac{-12 \pm \sqrt{12^{2} -4(2)(-7)}}{2(2)}[/tex]

5. Simplify the expression:

[tex]x = \frac{-12 \pm \sqrt{144 + 56}}{4}[/tex]

6. Calculate the value under the square root:

[tex]x = \frac{-12 \pm \sqrt{200}}{4}[/tex]

7. Now, we have two solutions:

[tex]x_{1} = \frac{-12 + \sqrt{200}}{4}x_{2} = \frac{-12 - \sqrt{200}}{4}[/tex]

8. Find the difference between the solutions:

[tex]x_{1} - x_{2}[/tex] = [tex]\frac{\sqrt{200} }{4}[/tex]

The positive difference between the two solutions is[tex]\frac{\sqrt{200} }{4}[/tex].

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The derivative of the expression y = ln ((15x² + 4x)⁵ (4x² – 2x)) is (120x - 10)/(3x + 1) (15x² + 4x)⁴.

To find the derivative of this expression, we'll need to use the chain rule and product rule. The chain rule allows us to find the derivative of a function inside another function, while the product rule allows us to find the derivative of two functions multiplied together.

Let's start by using the product rule to differentiate the expression inside the natural logarithm:

(15x² + 4x)⁵ (4x² – 2x) = f(x)g(x)

f(x) = (15x² + 4x)⁵ g(x) = (4x² – 2x)

f'(x) = 5(15x² + 4x)⁴ (30x + 4)

Now, we can use the product rule:

y = ln(f(x)g(x))

y' = 1/(f(x)g(x)) (f(x)g'(x) + g(x)f'(x))

y' = 1/((15x² + 4x)⁵ (4x² – 2x)) ((15x² + 4x)⁵(8x-2) + (4x² - 2x)5(15x² + 4x)⁴ (30x + 4))

Simplifying, we get:

y' = (120x - 10)/(3x + 1) (15x² + 4x)⁴

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Answer:

The length and breadth giving the lowest perimeter is 6 and 10.

Step-by-step explanation:

Area= Length* Breadth
Therefore, we divide 60 into pairs of 2 factors.
(30,2), (20,3), (12,5), (60,1), (15,4), (10,6).
These are the possible values of length and breadth which can give us the area 60.

Perimeter=2*(Length+Breadth)
Now, to minimise perimeter, we take the pair with the lowest sum.

The pair comes out to be 6 and 10 with the sum of 16.