Explanation:
search engine because it helps to search find what you are expecting to search in the google.
5. Write a C++ program that can display the output as shown below. Your
program will calculate the price after discount. User will input the
price and the discount is 20%
Answer:
#include<iostream>
using namespace std;
int main()
{
float price;
float discount;
cout<<"enter price : ";
cin>>price;
discount=price - (price * 20 / 100);
cout<<"discount rate is :"<<discount;
}
Explanation:
Translate each statement into a logical expression. Then negate the expression by adding a negation operation to the beginning of the expression. Apply De Morgan's law until each negation operation applies directly to a predicate and then translate the logical expression back into English.
Sample question: Some patient was given the placebo and the medication. ∃x (P(x) ∧ D(x)) Negation: ¬∃x (P(x) ∧ D(x)) Applying De Morgan's law: ∀x (¬P(x) ∨ ¬D(x)) English: Every patient was either not given the placebo or not given the medication (or both).(a) Every patient was given the medication.(b) Every patient was given the medication or the placebo or both.(c) There is a patient who took the medication and had migraines.(d) Every patient who took the placebo had migraines. (Hint: you will need to apply the conditional identity, p → q ≡ ¬p ∨ q.)
Answer:
Explanation:
To begin, i will like to break this down to its simplest form to make this as simple as possible.
Let us begin !
Here statement can be translated as: ∃x (P(x) ∧ M(x))
we require the Negation: ¬∃x (P(x) ∧ M(x))
De morgan's law can be stated as:
1) ¬(a ∧ b) = (¬a ∨ ¬b)
2) ¬(a v b) = (¬a ∧ ¬b)
Also, quantifiers are swapped.
Applying De Morgan's law, we have: ∀x (¬P(x) ∨ ¬M(x)) (∃ i swapped with ∀ and intersecion is replaced with union.)
This is the translation of above
English: Every patient was either not given the placebo or did not have migrane(or both).
cheers i hope this helped !!
In this assignment you'll write a program that encrypts the alphabetic letters in a file using the Hill cipher where the Hill matrix can be any size from 2 x 2 up to 9 x 9. The program can be written using one of the following: C, C++, or Java. Your program will take two command line parameters containing the names of the file storing the encryption key and the file to be encrypted. The program must generate output to the console (terminal) screen as specified below.Command Line Parameters1. Your program compile and run from the command line.2. The program executable must be named "hillcipher" (all lowercase, no spaces or file extension).3. Input the required file names as command line parameters. Your program may NOT prompt the user to enter the file names. The first parameter must be the name of the encryption key file, as described below. The second parameter must be the name of the file to be encrypted, as also described below. The sample run command near the end of this document contains an example of how the parameters will be entered.4. Your program should open the two files, echo the input to the screen, make the necessary calculations, and then output the ciphertext to the console (terminal) screen in the format described below.Note: If the plaintext file to be encrypted doesn't have the proper number of alphabetic characters, pad the last block as necessary with the letter 'X'. It is necessary for us to do this so we can know what outputs to expect for our test inputs.
Answer: Provided in the explanation section
Explanation:
C++ Code
#include<iostream>
#include<fstream>
#include<string>
using namespace std;
// read plain text from file
void readPlaneText(char *file,char *txt,int &size){
ifstream inp;
inp.open(file);
// index initialize to 0 for first character
int index=0;
char ch;
if(!inp.fail()){
// read each character from file
while(!inp.eof()){
inp.get(ch);
txt[index++]=ch;
}
}
// size of message
size=index-1;
}
// read key
int **readKey(char *file,int **key,int &size){
ifstream ink;
//
ink.open(file);
if(!ink.fail()){
// read first line as size
ink>>size;
// create 2 d arry
key=new int*[size];
for(int i=0;i<size;i++){
key[i]=new int[size];
}
// read data in 2d matrix
for(int i=0;i<size;i++){
for(int j=0;j<size;j++){
ink>>key[i][j];
}
}
}
return key;
}
// print message
void printText(string txt,char *msg,int size){
cout<<txt<<":\n\n";
for(int i=0;i<size;i++){
cout<<msg[i];
}
}
// print key
void printKey(int **key,int size){
cout<<"\n\nKey matrix:\n\n";
for(int i=0;i<size;i++){
for(int j=0;j<size;j++){
cout<<key[i][j]<<" ";
}
cout<<endl;
}
}
void encrypt(char *txt,int size,int **key,int kSize,char *ctxt){
int *data=new int[kSize];
for(int i=0;i<size;i=i+kSize){
// read key size concecutive data
for(int a=0;a<kSize;a++){
data[a]=txt[i+a]-'a';
}
// cipher operation
for(int a=0;a<kSize;a++){
int total=0;
for(int b=0;b<kSize;b++){
total+=key[a][b]*data[b];
}
total=total%26;
ctxt[i+a]=(char)('a'+total);
}
}
}
int main(int argc,char **argv){
char text[10000];
char ctext[10000];
int **key;
int keySize;
int size;
// input
key=readKey(argv[1],key,keySize);
readPlaneText(argv[2],text,size);
encrypt(text,size,key,keySize,ctext);
// output
printKey(key,keySize);
cout<<endl<<endl;
printText("Plaintext",text,size);
cout<<endl<<endl;
printText("Ciphertext",ctext,size);
return 0;
}
cheers i hope this helped !!!
(Find the number of days in a month) Write a program that prompts the user to enter the month and year and displays the number of days in the month. For example, If the user entered month 2 and year 2012, the program should display that February 2012 has 29 days. If the user entered month 3 and year 2015, the program should display that March 2015 has 31 days.
An introduction to object-oriented programming.
Write a GUI program named EggsInteractiveGUI that allows a user to input the number of eggs produced in a month by each of five chickens. Sum the eggs, then display the total in dozens and eggs. For example, a total of 127 eggs is 10 dozen and 7 eggs.
Answer:
The csharp program is given below.
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
namespace WindowsFormsApplication1
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void button6_Click(object sender, EventArgs e)
{
int total = (Convert.ToInt32(textBox1.Text) + Convert.ToInt32(textBox2.Text) + Convert.ToInt32(textBox3.Text) + Convert.ToInt32(textBox4.Text) + Convert.ToInt32(textBox5.Text));
int dozen = total / 12;
int eggs = total % 12;
textBox6.Text = dozen.ToString();
textBox7.Text = eggs.ToString();
}
private void button7_Click(object sender, EventArgs e)
{
textBox1.Text = "";
textBox2.Text = "";
textBox3.Text = "";
textBox4.Text = "";
textBox5.Text = "";
textBox6.Text = "";
textBox7.Text = "";
}
private void button8_Click(object sender, EventArgs e)
{
Close();
}
}
}
Explanation:
1. The integer variables are declared for total eggs, number of dozens and number of eggs.
2. The input of each text box is converted into integer by using the Convert.ToInt32() method on the value of that particular text box.
3. All the inputs are added and the sum is assigned to variable, total.
4. The number of dozens are obtained by dividing total by 12 and assigning the value to the variable, dozen.
5. The number of extra eggs are obtained by taking the modulus of total and 12 and the value is assigned to the variable, eggs.
6. The integer values in the variables, dozen and eggs, are converted into string using the ToString() function with that particular value.
dozen.ToString();
eggs.ToString();
7. The text boxes are assigned the respective values of dozens and number of eggs.
textBox6.Text = dozen.ToString();
textBox7.Text = eggs.ToString();
8. Two additional buttons, clear and exit, are also added.
9. The clear button erases the contents of all the text boxes. The Text property of each textbox is set to “” thereby clearing all the text fields.
10. The exit button closes the application using Close() function.
11. The program is made in visual studio and the output is attached.
Suppose that the following two classes have been declared public class Car f public void m1) System.out.println("car 1"; public void m2) System.out.println("car 2"); public String toString) f return "vroom"; public class Truck extends Car public void m1) t System.out.println("truck 1"); public void m2) t super.m1); public String toString) t return super.toString) super.toString ); Write a class MonsterTruck whose methods have the behavior below. Don't just print/return the output; whenever possible, use inheritance to reuse behavior from the superclass Methog Output/Return monster 1 truck1 car 1 m2 toString "monster vroomvroom'" Type your solution here:
Answer: provided in the explanation section
Explanation:
// code to copy
Car.java
public class Car {
public void m1()
{
System.out.println("car 1");
}
public void m2() {
System.out.println("car 2");
}
public String toString()
{
return "vroom";
}
}
Truck.java
public class Truck extends Car{
public void m1()
{
System.out.println("truck 1");
}
public void m2()
{
super.m1();
}
public String toString()
{
return super.toString() + super.toString();
}
}
MonsterTruck.java
public class MonsterTruck extends Truck
{
public void m1() {
System.out.println("monster 1");
}
public void m2() {
super.m1();
super.m2();
}
public String toString() {
return "monster " + super.toString();
}
public static void main(String[] args) {
MonsterTruck mt=new MonsterTruck();
mt.m1();
mt.m2();
System.out.println(mt);
}
}
cheers i hope this helped !!!
