Which is the graph of f(x) = (2)* ?
a graph

Answer:

11

Step-by-step explanation:

(f + g)(x)

= f(x) + g(x)

= x² - 6x - 4 +5x + 3 ← collect like terms

= x² - x - 1

then

(f + g)(- 3) = (- 3)² - (- 3) - 1 = 9 + 3 - 1 = 11

Answer:

11

Step-by-step explanation:

F(–3)=(–3)²–6(–3)–4===> 9+18–4=23

g(–3)=5(–3)+3=‐15+3=–12

23–12=11

Let's see

Answer:

53 the correct answer off your question.

Answer:

jackson sold 27 pounds of bananas and 12 pounds of grapes :D

Step-by-step explanation:

Taking into account the definition of a system of linear equations, the number of pounds of bananas and grapes sold are 36 and 16 respectively.

A set of two or more first-degree equations with two or more connected unknowns is referred to as a system of linear equations.

Finding the value of each unknown in order to satisfy all of the system's equations constitutes the process of solving an system of equations. To put it another way, it is necessary to find the values of the unknowns, as they must be replaced with values that, when used to solve the equations, is the process of solving a system of equations

In this case, a system of linear equations must be proposed taking into account that:

You know:

The system of equations to be solved is

x +y= 52

x + 2.25y= 72

There are several methods to solve a system of equations, it is decided to solve it using the graphical method. The system's equations are graphically represented by graphs in the graphical method. The solution of the system is the point of intersection between the graphs, since the coordinates of said point satisfy both equations.

Graphically, it can be seen that the intersection point is (36; 16). That is, the value of x is 36 and the value of y is 16.

Finally, the number of pounds of bananas sold are 36 and the number of pounds of grapes sold are 16.

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Answer:

I believe you're trying to say 5+x= 3/4

Answer:

difference-of-squares

Step-by-step explanation:

£36

20+25=45          Take away 13 and it's 32.   32+4 (the shipping charge) is 36. So Ruth pays 36 pounds.

Step-by-step explanation:

rewrite the equation as follows

c2d = a - b

divide both sides by 2d

c = (a - b)/2d

Use the change-of-basis identity,

[tex]\log_x(y) = \dfrac{\ln(y)}{\ln(x)}[/tex]

to write

[tex]xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}[/tex]

Use the product-to-sum identity,

[tex]\log_x(yz) = \log_x(y) + \log_x(z)[/tex]

to write

[tex]xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}[/tex]

Redistribute the factors on the left side as

[tex]xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}[/tex]

and simplify to

[tex]xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)[/tex]

Now expand the right side:

[tex]xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}[/tex]

Simplify and rewrite using the logarithm properties mentioned earlier.

[tex]xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1[/tex]

[tex]xyz = 2 + \dfrac{\ln(c)+\ln(a)}{\ln(b)} + \dfrac{\ln(a)+\ln(b)}{\ln(c)} + \dfrac{\ln(b)+\ln(c)}{\ln(a)}[/tex]

[tex]xyz = 2 + \dfrac{\ln(ac)}{\ln(b)} + \dfrac{\ln(ab)}{\ln(c)} + \dfrac{\ln(bc)}{\ln(a)}[/tex]

[tex]xyz = 2 + \log_b(ac) + \log_c(ab) + \log_a(bc)[/tex]

[tex]\implies \boxed{xyz = x + y + z + 2}[/tex]

(C)

Answer:

g(4)= -2

g(-2)= 2

g(0)= 2

g(3)= -1

g(-4)= 0

Step-by-step explanation: See attachment, and don’t forget to check just in case ;)

Answer:

g(−4) = 0

g(−2) = 2

g(0) = 2

g(3) = -1

g(4) = -2

Step-by-step explanation:

Please Thank!

Answer:

[tex]x = -\frac{15}{2}[/tex]

Step-by-step explanation:

Hello!

The formula for the AOS is given to you, and you simply have to plug in the information given by the equation.

Equation of a Parabola (Standard): [tex]y = ax^2 + bx + c[/tex]

Comparing it to our equation:

Plug it in to the AOS formula:

You only have to input 15 in to the correct box since the negative sign is already placed for you.

Answer:

-x+4, 4+-x

Step-by-step explanation:

Obtain these answers by moving the X and 4 around and multiplying the equation by -1

In the diagram, the value of the last angle will be 158°.

It should be noted that the total angle is a quadrilateral is 360°.

In this case, the value of the last angle will be:

= 360° - (76° + 110° + 116°)

= 360° - 302°

= 158°

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Answer: 14

Step-by-step explanation:

because 8 +4 is 14

Answer:

1/3

Step-by-step explanation:

We multiply 33(Figure A side) by 1 /3 to get 11(Figure B side).

Answer:

Range: (-10 , 14)

Step-by-step explanation:

Given information:

Range: (x , y)?

Plug in domain of x = -4 and x = 4 into equation to find range.

f(-4) = 3 * -4 + 2 = -10

f(4) = 12 + 2 = 14

Range: (-10 , 14)

The statement is given as the distance between points (x₁, y₁) and (4, 8) is the square root of (x₁ - 8)² + (₁-4)². Hence, the given statement is false, it is  √[(x₁-4)² + (y₁-8)²].

The shortest distance (length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:

D = √[(x-p)² + (y-q)²]  

WE have been given two points.

So,

The distance between points (x₁, y₁) and (4, 8)

D = √[(x-p)² + (y-q)²]  

D = √[(x₁-4)² + (y₁-8)²]  

But the statement is given as the distance between points (x₁, y₁) and (4, 8) is the square root of (x₁ - 8)² + (₁-4)².

Hence, the given statement is false, it is  √[(x₁-4)² + (y₁-8)²].

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Answer:

This point is not on the line, NOT TRUE

Step-by-step explanation:

The equation of the line is written in the slope-intercept form,

y = mx + b

where m represents the slope

           b represents the y-intercept

where the format of a point is (x, y)

Given: y = 7x (6/7, -1/4)

we can plug in the point (6/7, -1/4)

-1/4 = 7(6/7)

-1/4 = 6

-1/4 does not equal 6 so this point is not on the line

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Answer:

what?????????????????

Subdivide the interval [0, 3] into 6 subintervals of equal length, ∆x = (3 - 0)/6 = 1/2. Then the partition is

[tex]\left[0,\dfrac12\right] \cup \left[\dfrac12,1\right] \cup \left[1,\dfrac32\right] \cup \cdots \cup \left[\dfrac52,3\right][/tex]

The right endpoint of the [tex]i[/tex]-th subinterval is

[tex]r_i = \dfrac12 + (i-1)\times\dfrac12 = \dfrac i2[/tex]

with [tex]i\in\{1,2,3,\ldots,6\}[/tex].

Then the area under the [tex]y=x^2[/tex] on the interval [0, 3] is approximately

[tex]\displaystyle \int_0^3 x^2 \, dx \approx \sum_{i=1}^6 (r_i)^2 \Delta x = \frac18 \sum_{i=1}^6 i^2[/tex]

Recall that

[tex]\displaystyle \sum_{n=1}^N n^2 = \frac{N(N+1)(2N+1)}6[/tex]

Then the approximate value of the area is

[tex]\displaystyle \int_0^3 x^2 \, dx \approx \frac{6\times7\times13}{48} = \boxed{\frac{91}8}[/tex]

The actual value of the area is 9, so this approximation is an overestimation, as is always the case when using a right endpoint sum for an increasing function.

Answer: 1

Step-by-step explanation:

[tex]2x-\sqrt{5}=2x^{1}-\sqrt{5}[/tex], and thus the highest exponent of x is 1

Answer:

Bricks for 1 wall= 405

If there are 5 rooms with 4 walls,

Walls= 5 x 4= 20

Bricks= 405 x 20

= 8100

Mark me the brainliest pleeeeeaseee :)

Answer:

81

Step-by-step explanation:

27 people will tell 3 people each. 3x27=81

Answer:

81

Step-by-step explanation:

Answer:

y=-2/3x-13/3

Step-by-step explanation:

parralel line have the same gradient

y=mx+c is the general straight line equation

m represents the gradient

if the equation is y=-2/3x+3/2

m=-2/3

the coordinates (4,-7)

x=4

y=-7

substitute into equation

-7=-2/3×4+c

-7=-8/3+c

c=-7+8/3

c=-13/3

so the equation is :

y=-2/3x-13/3

Answer:

(5,18)  & (-5 , 38)

Step-by-step explanation:

  A linear equation represented by a line in a graph intersect the quadratic equation represented by a parabola zero, one or two times.

f(x) = x² - 2x + 3   -------------------(I)  

f(x) = -2x + 28   ---------------------(II)

x² - 2x + 3 = -2x + 28

x² - 2x + 2x + 3 - 28 = 0

x² - 25 = 0

x²         = 25

         x = √25 = √5*5

        x = ± 5

Plugin x = 5 in equation (II),

                    f(5) = -2*5 + 28

                          = -10 + 28

                          = 18

(5 , 18)

Plugin x = -5 in equation (II),

 f(-5) = -2*(-5) + 28

         = 10 + 28

         = 38

(-5, 38)

Answer:

(5, 18) and (-5, 38)

Step-by-step explanation:

Given system of equations:

1) f(x) = x² - 2x + 3 ⇒ y = x² - 2x + 3

2) f(x) = -2x + 28 ⇒ y = -2x + 28

Solve using the Substitution Method:

Step 1: Substitute the the first equation into the second equation.

⇒ x² - 2x + 3 = -2x + 28

Step 2: Solve for x.

x² - 2x + 3 = -2x + 28 [ Add 2x to both sides. ]

x² - 2x + 2x + 3 = -2x + 2x + 28

⇒ x² + 3 = 28 [ Subtract 28 from both sides. ]

x² + 3 - 28 = 28 - 28

⇒ x² - 25 = 0 [ Factor using the following rule: a² - b² = (a - b)(a + b). ]  

(x - 5)(x + 5) = 0

⇒ x - 5 = 0, x + 5 = 0 [ Solve for the values of x. ]

x - 5 + 5 = 0 + 5, x + 5 - 5 = 0 - 5

⇒ x = 5, x = -5

Step 3: Solve for y.

Substitute the found x-values into one of the given equations.

y = x² - 2x + 3 ⇒ y = (5)² - 2(5) + 3 ⇒ y = 25 - 10 + 3 ⇒ y = 18

y = x² - 2x + 3 ⇒ y = (-5)² - 2(-5) + 3 ⇒ y = 25 + 10 + 3 ⇒ y = 38

The solutions to the system of equations are:

⟹ x₁ = 5, y₁ = 18 ⇒ (5, 18)

⟹ x₂ = -5, y₂ = 38 ⇒ (-5, 38)

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ANSWERS ARE AT THE BOTTOM

To solve this question, we need to write the questions algebraically. Let's look at the problem first: The sum of a number 8, and twice the number x is equal to 28.

Algebraic form:

8 + 2x = 28

Lets solve this!

8 + 2x = 28            (Algebraic Form)

2x = 28 - 8             (Subtract 8 from both sides)

2x = 20                  (Divide by 2)

x = 10                     (Answer)

ANSWER:

x = 10

The equation representing the value of the collection after 7 years is  value of collection = 430 + (0.04 * 430 )* 7 or value of collection = $550.4

An equation is a mathematical statement , where the algebraic expression is equated to another algebraic expression.

It is given that

Ella has a collection of vintage action figures that is worth $430.

collection

appreciates at a rate of 4% per year

equation representing the value of the collection after 7 years is

value of collection = 430 + (0.04 * 430 )* t

value of collection = 430 + (0.04 * 430 )* 7

= $550.4

Therefore the equation representing the value of the collection after 7 years is  value of collection = 430 + (0.04 * 430 )* 7 or value of collection = $550.4

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2x² + 2x + ? = x

⇒ ? = x - 2x² - 2x

⇒ ? = -2x² - x

Your answer is incorrect because 2x² - x² would mean x² is part of the answer, which is clearly incorrect.