The second-order dark fringe in a single-slit diffraction pattern is 1.40 mm from the center of the central maximum. Assuming the screen is 89.0 cm from a slit of width 0.710 mm and assuming monochromatic incident light, calculate the wavelength of the incident light.
We know, for single slit :
[tex]y =\dfrac{ n\lambda L}{a}\\\\\lambda = \dfrac{ya}{nL}[/tex] ...1)
[tex]y = 1.4\ mm = 1.4 \times 10^{-3}\ m[/tex]
n = 2
L = 89 cm = 0.89 m
[tex]a=7.1\times 10^{-4}\ m[/tex]
Putting all these in equation 1), we get :
[tex]\lambda = \dfrac{ya}{nL}\\\\\lambda = \dfrac{1.4\times 10^{-3}\times 7.1\times 10^{-4}}{2\times 0.89 }\\\\\lambda = 5.584 \times 10^{-7}\ m[/tex]
Therefore, wavelength of the incident light is [tex]5.584 \times 10^{-7}\ m[/tex] or 558.4 nm.
Hence, this is the required solution.
20 points - Help me please with explanation of (A) and (B)
(a)to find voltage of battery we use the wire containg 4 ohm resistor and 3 ohm resistor
the voltage of 4ohm = Ri=4x1.5=6V
the voltage of 3 ohm = Ri=3x1.5=4.5v
since voltage is additive in series then Voltage of batteries = 4.5+6=10.5V
(b) the currrent flowing in 20 ohm resistor is the same as 8 ohm resistor so
Voltage of 8 ohm + voltage of 20 ohm= 10.5
8i+20i=10.5
28i=10.5
i=0.375 A
For a given centrifugal pump, if the speed of rotation of the impeller is cut in half, how does the power required to drive the pump change
Answer:
The power required to drive the pump is reduced in [tex]\frac{1}{8}[/tex].
Explanation:
From Turbomachinery, we find that power required to drive the pump ([tex]\dot W[/tex]) is directly proportional to the cube of the speed of rotation of the impeller ([tex]\dot n[/tex]). That is:
[tex]\dot W \propto \dot n^{3}[/tex]
[tex]\dot W = k\cdot \dot n ^{3}[/tex] (Eq. 1)
Where [tex]k[/tex] is the proportionality constant.
And now we eliminate the proportionality constant by constructing the following relationship:
[tex]\frac{\dot W_{B}}{\dot W_{A}} = \left(\frac{\dot n_{B}}{\dot n_{A}}\right)^{3}[/tex] (Eq. 2)
If we know that [tex]\frac{\dot n_{B}}{\dot n_{A}} = \frac{1}{2}[/tex], then:
[tex]\frac{\dot W_{B}}{\dot W_{A}} = \frac{1}{8}[/tex]
The power required to drive the pump is reduced in [tex]\frac{1}{8}[/tex].
A Spring is pulled to 10cm and held in place with a force of 500N .what is the spring constant
We are given:
extension of the spring (x) = 10 cm OR 0.1 m
Force applied to keep it in position (F) = 500 N
Solving for the spring constant:
We know that F = kx (when the spring is extended)
replacing the variables with the given values
500 = k * 0.1
k = 5000 N/m
This means that to extend the spring by 1 m, we have to apply a force of 5000 N
An amateur golfer swings a golf club, striking a golf ball that has a mass of 55.0 g. The club is in contact with the ball for only 0.00360 s. After the collision, the ball leaves the club at a speed of 34.0 m/s. What is the magnitude of the average force (in N) exerted on the ball by the club?
Answer:
The average force ≅ 519.44 N.
Explanation:
Impulse = change in momentum of a body
i.e Ft = m(v - u)
where F is the force, t is the time, m is the mass of the body, v is the final velocity and u is the initial velocity.
m = 55.0 g (0.055 Kg), t = 0.00360 s, v = 34.0 m/s, since the ball was initially at rest; u = 0 m/s
So that,
F x 0.00360 = 0.055(34 - 0)
F x 0.00360 = 0.055 x 34
= 1.87
F = [tex]\frac{1.87}{0.0036}[/tex]
= 519.4444
The average force exerted on the ball by the club is approximately 519.44 N.
Next 100 points if u answer this
Answer: When frequency increases more wave crests pass a fixed point each second. That means the wavelength shortens. So, as frequency increases, wavelength decreases. The opposite is also true—as frequency decreases, wavelength increases.
The frequency and wavelength of a wave are related. When frequency increases more wave crests pass a fixed point each second. ... So, as frequency increases, wavelength decreases. The opposite is also true—as frequency decreases, wavelength increases.
uncountable the number of times that something happens during a period of time. frequency of: Changes in sea temperature will increase the frequency of hurricanes. with increasing frequency (=more often): Accidents occur here with increasing frequency.
Explanation:
If the_____of a wave increases, its frequency must decrease.
a. period
b. energy
c. amplitude
d. velocity
Answer:wrong. Jts not velocity. Its period.
Explanation:
Took the test
A large bottle contains number medical tablets each having a mass of 250
mg.The mass of all tablets is 1kg.Calculate the number of tablets in the
bottle.
First of all, this isn't physics. But, here's the answer:
1 gram is a 1000 milligram and 250 milligram is 250 * 0.001 g which is 0.25 gram.
Since 1 kg is 1000 g, we divide 1000 by 0.25 and we get 1000 * 4 which is 4000.
There are [tex]4000[/tex] tablets inside the bottle.
a plank rests on two supports that exert upward forces of 14N and 18N. find the weight of the plank.
Answer:
32
Explanation:
Up forces and Down forces must be equal if the object is balanced
For this question
down force is weight of the plank
up forces is 14 and 18
14+18=Weight of plank
Form hypothesis: Compare the floating objects, then do the same for the sinking objects. A. What do the floating objects have in common
Answer:
Explanation:
This question is incomplete. However, it should be noted that for an object to float in a liquid, the density of the object must be less dense than the liquid. This causes the weight force of the object to be balanced by the upthrust force of the liquid. Thus, when the object is more dense than the liquid, the object sinks.
One thing the floating objects will have in common is that they are less dense than the liquid in which they are floating.
NOTE that the floating of an object can be dependent on size and shape (which affects the upthrust force) also.
HELP ASAP!!
The table below lists protected constitutional rights and how they may be limited.
Protected Rights Limitations
Property rights ?
Unwarranted search and seizure Crime suspects may be searched
Which phrase completes the table? (3 points)
Group of answer choices
Poll taxes
Eminent domain
Jury trial
Background checks
Answer:
jury trial
Explanation:
rights to a fair trial by jury, or the whole innocent until proven guilty ya know
Sustained exercise that increases heart and lung fitness; may also alleviate depression and anxiety is called anaerobic exercise? True or false
Answer:
False
Explanation:
the y-axis of a position-time graph represents__________.
Answer:position relative to the starting point
Explanation:
What is the force per meter of length on a straight wire carrying a 8.05 A current when perpendicular to a 0.82 T uniform magnetic field?
Answer:
6.601 N/m.
Explanation:
Generally, the force on a wire carrying current in a magnetic field can be determined by:
F = BIL Sinθ
where: F is the force, B is the value of the magnetic field, I is the value of current in the wire and θ is the angle between the direction of current and magnetic field.
For force per meter of length, we have;
[tex]\frac{F}{L}[/tex] = BI Sinθ
Given: I = 8.05 A, B = 0.82 T and θ = [tex]90^{o}[/tex](since they are perpendicular).
Then;
[tex]\frac{F}{L}[/tex] = 0.82 x 8.05 x Sin [tex]90^{o}[/tex]
= 6.601
= 6.601 N/m
the force per meter length is 6.601 N/m.
The required magnitude of force per meter of wire is of 6.601 N/m.
Given data:
The magnitude of current in a wire is, I = 8.05 A.
The strength of magnetic field is, B = 0.82 T.
We known that, in a magnetic field there is always a force acting on a wire kept in the region. This force is known as magnetic force, and the expression for the magnetic force is given as,
[tex]F = B \times I \times L \times sin \theta[/tex]
Now,
For the force per unit length, and current being perpendicular to magnetic field,
[tex]\dfrac{F}{L} = B \times I \times sin90\\\\\dfrac{F}{L} = 0.82 \times 8.05 \times sin90\\\\\dfrac{F}{L} = 6.601 \;\rm N/m[/tex]
Thus, we can conclude that the required magnitude of force per meter of wire is of 6.601 N/m.
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A heavy storm leaves 1 cm of rain on a city 5 km wide and 8 km long on a 2 hour period. How many cm3 of water fell on the city?
Answer: wow that’s hard
Explanation:
Running with an initial velocity of 13 m/s , a horse has an average acceleration of -1.88 m/s2 . How long does it take for the horse to decrease its velocity to 6.3 m/s
pls :/
Answer:
3.56s
Explanation:
Ya that's the right answer.
What is the deBroglie wavelength of an electron moving at 1.37 x 106 m/s if the mass of the electron is 9.11 x 10-28 g
Answer:
The value is [tex]\lambda = 5.30 *10^{-10 } \ m[/tex]
Explanation:
From the question we are told that
The velocity of the electron is [tex]v = 1.37 *10^{6} \ m/s[/tex]
The mass of the electron is [tex]m = 9.11 *10^{-28} \ g = 9.11 *10^{-31} \ kg[/tex]
Generally the deBroglie wavelength is mathematically represented as
[tex]\lambda = \frac{h}{mv}[/tex]
Here h is the Planck'c constant with value [tex]h = 6.62607015 * 10^{-34} J \cdot s[/tex]
So
[tex]\lambda = \frac{6.62607015 * 10^{-34} }{9.11 *10^{-31} * 1.37 *10^{6}}[/tex]
=> [tex]\lambda = 5.30 *10^{-10 } \ m[/tex]
significance of practicals in the discipline of geography
uses of atmospheric pressure
А)
An automobile traveling along a straight road
increases its speed from 48 ft/s to 66 ft/s in
180 ft.
If the acceleration is constant, how much
time elapses while the auto moves the 180 ft?
Answer in units of s.
Answer:
4.5s
Explanation:
u=30m/s
v=50m/s
s=180m
a=constant(given)
By third equation of motion, v
2
=u
2
+2as
(50)
2
=(30)
2
+2a(180)
a=
3
40
m/s
2
By first equation of motion, v=u+at
50=30+(
9
40
)t
t=
2
9
=4.5sec
A force F = (2xî + 4yĵ), where F is in newtons and x and y are in meters, acts on an object as the object moves in the x-direction from the origin to x = 4.99 m. Find the work W = ∫ F · dr done by the force on the object (in J).
Answer:
Work done, W = 24.9001 J
Explanation:
Given that,
Force, F = (2xî + 4yĵ) Where x and y are in meters
This force acts on an object as the object moves in the x-direction from the origin to x = 4.99 m.
We need to find the work done by the force on the object. It is given by :
[tex]W=\int\limits^a_b {F dr} \\\\W=\int\limits^{4.99}_0 {(2xi+4yj)dx} \\\\W=\int\limits^{4.99}_0 {2xi\ dx} \\\\W=x^2|_0^{4.99}\\\\\text{Applying limits}\\\\W=(4.99)^2-0^2\\\\W=24.9001\ J[/tex]
So, the work done is 24.9001 J.
HELP!!! An object accelerates from rest to 85 m/s over a distance of 36 m. What acceleration did it
experience?
Answer:
Explanation:
Given:-
Initial velocity (u) = 0m/s
Final velocity (v) = 85m/s
Distance covered (s) = 36m
To Find:-
Acceleration of the object (a)
Solution:-
By using 3rd equation of motion
→ v² = u² +2as
Substitute the value we get
→ 85² = 0² +2×a×36
→ 7225 = 0 + 72 ×a
→ a = 7225/72
→ a = 100.34m/s²
∴ The acceleration of the object is 100.34m/s²
Additional Information!!
The rate of change of velocity at per unit time is called acceleration .
✧ SI unit of acceleration is m/s²
✧ It is vector Quantity ( both magnitude and directio
If the velocity of Homer the astronaut (mass =200 kg) is 5 m/s and he runs into and grabs his stationary pal Larry (mass = 150 kg), what is the new velocity of the astronauts after the collision?
We are given:
Homer the Astronaut:
Mass of Homer the astronaut(m1) = 200 kg
initial velocity of Homer the astronaut(u1) = 5 m/s
Larry the Pal:
Mass of Larry the Pal (m2) = 150 kg
initial velocity of Larry the Pal (u2) = 0 m/s
Since they will move together after the collision, they will have the same velocity:
v1 = v2 = V
Solving for the Final velocity:
from the law of conservation of momentum:
m1u1 + m2u2 = m1v1 + m2v2
since v1 = v2 = V:
m1u1 + m2u2 = V(m1 + m2)
replacing the variables with the given values
200 * 5 + 150 * 0 = V(200 + 150)
1000 = 350V
V = 1000 / 350
V = 2.86 m/s
At what speed does a 1500 kg compact car have the same kinetic energy as a 18000 kgkg truck going 21 km/hr km/hr
Answer:
speed = 72.75km/hr
Explanation:
Let us first determine the Kinetic energy (KE) of the 18000kg truck
[tex]KE = \frac{1}{2} mv^2\\where:\\m = mass = 18000\\v = velocity = 21km/hr\\\therefore KE = \frac{1}{2} \times 18000 \times (21)^2\\= 9000 \times 441\\KE = 3,969,000\ Joules\\= 3,969\ KJ[/tex]
Next we will substitute this value of kinetic energy into the KE equation for the 1500kg compact car
[tex]KE = \frac{1}{2} mv^2\\3969000 = \frac{1}{2} \times 1500 \times v^2\\3969000 = 750 \times v^2\\v^2 = \frac{3969000}{750} = 5292\\v = \sqrt{5292} \\v = 72.75km/hr[/tex]
The speed at which the 1500 kg compact car have the same kinetic energy as the truck is 73 km/h
The kinetic energy of an object is known to be the energy at work and in motion. It is usually expressed as;
[tex]\mathbf{K.E = \dfrac{1}{2}mv^2}[/tex]
To determine the speed at which the car will have the same kinetic energy as the truck, we can say that:
[tex]\mathbf{\implies \dfrac{1}{2}m_c v_c^2= \dfrac{1}{2}m_t v_t^2}[/tex]
[tex]\mathbf{m_c}[/tex] = mass of the car[tex]\mathbf{v_c}[/tex] = speed of the car[tex]\mathbf{m_t}[/tex] = mass of the truck[tex]\mathbf{v_t}[/tex] = speed of the truck∴
[tex]\mathbf{\implies \dfrac{1}{2}\times 1500\times v_c^2= \dfrac{1}{2}\times 18000 \times 21^2}[/tex]
[tex]\mathbf{v_c^2= \dfrac{3969000}{ 750}}[/tex]
[tex]\mathbf{v_c^2=5292}[/tex]
[tex]\mathbf{v_c=\sqrt{5292}}[/tex]
[tex]\mathbf{v_c\simeq 73 km/h}[/tex]
Therefore, we can conclude that the speed at which the 1500 kg compact car have the same kinetic energy as the truck is 73 km/h
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Which accurately completes the statement? Conduction involves the transfer of electric charge or due to the movement of particles. O thermal energy Olight waves O protons o neutrons
Answer:
A: thermal energy
Conduction involves the transfer of electric charge or thermal energy due to the movement of particles. So, the correct option is 1.
What is meant by heat transfer ?Heat transfer is defined as the process of transferring heat from one body to another based on the temperature difference between them.
Here,
There are several mechanisms of heat transfer such as conduction, convection, radiation, etc.
Conduction or thermal conduction is a commonly used mechanism for heat transfer.
Conduction is defined as the process by which heat is transferred from one body to other in contact with each other. In conduction, the heat flows from the hotter body to the surface of the colder body which is in contact with it.
This property or ability of the body to conduct heat or thermal energy is known as its thermal conductivity.
Conductions requires a temperature gradient to transfer the heat. The temperature difference between the bodies leads to the heat flow between them.
Conduction occurs mostly in solids and liquids, in where the intermolecular distance between the particles is higher than that in gases.
Hence,
Conduction involves the transfer of electric charge or thermal energy due to the movement of particles.
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AKS 8a - Phenomena-Based Question: Use the data and the graph to make a claim as to which person represents each letter on the graph. In your discussion, be sure to:
explain how the data matches each line on the graph
describe, compare, and contrast the rates of speed and change in position for each person based on the documents
explain what the slope of each line helps determine
Person
Action
Distance Travelled
Time
Dad
Drives home from the grocery store
1 mile
10 minutes
Aiden
Rides his bike to a friend’s house
0.75 miles
10 minutes
Mom
Waits at the doctor’s office
0 miles
10 minutes
Alexis
Walks to her mailbox down the long driveway
0.25 miles
10 minutes
Answer: what’s the answer
Explanation:
What is the largest planet in our galaxy
who plays adopt me on rob.lox!! plz answer people only if you play though tell me your best pet and your user name so we can play!!
Answer: I don't do adopt me but I do have a Ro.blox username its Nvm i cant but my user name
Explanation:
Answer:
adopt me sucks but my best pet was an albino monkey I think or a king monkey
Explanation:
A 2.0 cm thick brass plate (k_r = 105 W/K-m) is sealed to a glass sheet (kg = 0.80 W/K m), and both have the same area. The exposed face of the brass plate is at 80°C, while the exposed face of the glass is at 20 °C. How thick is the glass if the glass brass interface is at 65 C? Ans. 0.46 mm
True or False: In a p-n junction diode, the absolute value of the electric field is the largest at the metallurgical junction (exactly where p-type and n-type semiconductors meet).
Answer:
false
Explanation:
In a p-n junction diode, the absolute value of the electric field is the largest at the metallurgical junction is false statement.
What is electric field?An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. It can also refer to a system of charged particles' physical field.
In a p-n junction diode, the absolute value of the electric field is the not largest at the metallurgical junction field is maximum at the depletion region.
In a p-n junction diode, the absolute value of the electric field is the largest at the metallurgical junction is false statement.
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