Which best explains how fiber-optic technology has improved communication?

It has eliminated the need to send audio data through telephones.
It has allowed for faster transmission of Internet signals.
It has increased the speed at which light travels through space.
It has reduced society’s reliance on devices such as computers and cell phones.

Answers

Answer 1

Answer:

B. It has allowed for faster transmission of Internet signals.

Explanation:

i took the test on engenuity

Answer 2

Fiber-optic technology has allowed for faster transmission of Internet signals.

What is meant by fiber-optics?

The term fiber optics, often known as optical fiber, describes the technique used to transport data via light pulses travelling along a glass or plastic fiber.

Here,

In fiber-optic communications, optical fibres are widely used to send light over longer distances and at higher bandwidths (data transfer rates) than electrical cables. They are most frequently used to convey light between the two ends of the fiber.

The concept of complete total internal reflection governs the operation of optical fibres. When a light beam strikes the interior surface of an optical fiber cable with an incidence angle greater than the critical angle, the incident light beam reflects in the same medium, and the occurrence is repeated.

Hence,

Fiber-optic technology has allowed for faster transmission of Internet signals.

To learn more about optical fiber, click:

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Related Questions

HELP ITS FOR SCIENCE
1. Explain why a wrecking ball can destroy a building, but a yo-yo can’t. Use the term kinetic energy in your explanation.

2. How is speed related to kinetic energy?

Answers

Answer:

A wrecking ball has the capability to destroy a building due to the greater mass and kinetic energy than the yo-yo.

Can someone help please

Answers

Answer:

The average blood speed is 0.39 m/s

Explanation:

According to Poiseuille’s law, the volume flow rate, Q (m³/s) of a fluid of

viscosity η through a tube or pipe of radius r and length L is:

Q = πr⁴ΔP/8ηL

where ΔP is the change in pressure or pressure difference of the fluid; L is length of the pipe

Also, the volume flow rate, Q, is related to the average velocity v, by the formula:

Q = Av

where A is the cross-sectional area of the pipe; A = πr²

Q = πr²v

Thus, the Poiseuille’s becomes: πr²v = πr⁴ΔP/8ηL

v = r²ΔP/8ηL

From the given values:

r = 2.5 mm = 0.0025 m

L = 15 cm = 0.15 m

ΔP = 380 Pa

η = 5 * 10⁻³ Pa.s

substituting the given values in the equation

v = {(0.0025)² * 380} / (8 * 5 * 10⁻³ * 0.15)

v = 0.39 m/s

Therefore, the average blood speed is 0.39 m/s

it is an organic compound and an essential micronutrient that the body needs in small amounts.​

Answers

Answer:

Nutrients the body needs in relatively small amounts are called micronutrients. They include vitamins and minerals. Vitamins are organic compounds that are needed by the body to function properly. ... Vitamins and minerals do not provide energy, but they are still essential for good health

Explanation:

Matter is made of small particles to small to be seen. Which of these best describe evidence of this statement? 1. Tara’s crayons melted when she left them under the sun. 2. Kerris glass of water overflowed when she added ice. 3. Sams basketball expands as he pumps air into it. 4. Stephanie dropped a vase and it broke into pieces.

Answers

Answer:

Explanation:

I think the answer is statement no 3.

Hope it helps.

Answer:

1 Tara's crayons melted when she left them under the sun

how is work and energy inter-related?? (in simple words)​

Answers

Answer:

The work and energy is inter- related because if we are energetic then only we are able to work.

People who are weak and not energetic cannot work continuously.

Explanation:

hope this helps you....

For a given substance, the molecules
move fastest when the substance is

Answers

Heat makes the molecules move faster

Answer:GAS

Explanation:

A radio transmitting station operating at a frequency of 125 MHz has two identical antennas that radiate in phase. Antenna B is 9.05 m to the right of antenna A. Consider point P between the antennas and along the line connecting them, a horizontal distance x to the right of antenna A. For what values of x will constructive interference occur at point P?

Answers

Answer:

Explanation:

The formula for frequency is:

[tex]f = \dfrac{c}{\lambda}[/tex]

If we make [tex]\lambda[/tex] the subject; we have:

[tex]\lambda = \dfrac{c}{f}[/tex]

[tex]\lambda = \dfrac{3\times 10^6 \ m/s}{125 \ MHz (\dfrac{10^6 \ Hz}{1 \ MHz})}[/tex]

[tex]\lambda = 2.4 \ m[/tex]

Let assume that there is a point P between antenna A  to B.

where;

A to B = 9.05

A to P = x  and

P to B = 9.05 - x

Then, the condition for the constructive inteference is:

Δx = nλ

x - (9.05 - x) = nλ

2x - 9.05 = n(2.4)

So, we need to start assigning values to n so that the value of x becomes less than or equal to 9.05 m

If n = -1

Then;

2x - 9.05 = (-1)(2.4)

x = 3.325 m

If n = -2

Then;

2x - 9.05 = (-2)(2.4)

x = 2.125 m

If n = -3

Then;

2x - 9.05 = (-3)(2.4)

x = 0.925 m

If n = 0

Then;

2x - 9.05 = (0)(2.4)

x = 4.525 m

If n = 1

2x - 9.05 = (1)(2.4)

x = 5.725 m

If n = 2

Then;

2x - 9.05 = (2)(2.4)

x = 6.925 m

Hence, there exist 7 points in which constructive interference occurs.

Which part of the water cycle is where vapor from plants leaves the plants as they breath?
condensation
Transpiration
evaporation

Answers

Answer:

I think it is transpiration

Answer:

transpiration is the right answer

Which statement accurately describes a relationship between parts of the
universe?
O A. There are millions of nebulae in a star.
O B. There are thousands of universes in a galaxy.
C. There are trillions of galaxies in the universe.
O D. There are billions of galaxies in a solar system.

Answers

Answer:

C. There are trillions of galaxies in the universe.

Explanation:

A. is wrong as nebulae are found inside galaxies and inside the universe, not inside stars.

B. is wrong because there are trillions of galaxies in the universe, not the latter.

D. The solar system consists of the eight planets, the Sun, comets, meteors, dwarf planets, and is inside the Milky Way galaxy and thus cannot have galaxies inside it.

Please give Brainliest

Answer:

C.

Explanation:

There are trillions of galaxies in the universe.

Work is a measurement of the transfer of which of the following?
A. Impulse
B. Power
C. Energy

Answers

Answer:Enegry

Explanation:Energy transfer is used to do work

Which of the following statements is true?
A. Friction primarily affects objects that contain iron.
B. Friction pulls objects toward the center of the Earth
C.
Friction does not affect objects in motion.
D.
Friction slows down or stops objects in motion.

Answers

Answer:

D. Friction slow down or stop objects in motion.

attraction is seen between the poles of two bar magnet in the case of​

Answers

Answer:

he magnetic field of a bar magnet is strongest at either pole of the magnet. It is equally strong at the north pole when compared with the south pole. The force is weaker in the middle of the magnet and halfway between the pole and the center

Explanation:

An astronaut named Sandra Bullock has drifted too far away from her spaceshuttle while attempting to repair the Hubble Space telescope. She realizes that theshuttle is moving away from her at 3 m/s. On her back is a 10 kg jetpack which consistsof an 8 kg holding tank filled with 2 kg of pressurized gas. Without the jetpack, sheand her space suit have a mass of 80 kg.

Required:
a. She is able to use the gas to propel herself in the same direction as the shuttle. The gas exits the tank at a uniform rate with a constant velocity of 100 m/s, relative to the tank (and her). After the gas in the tank has been released, what is her velocity?
b. After this, she throws her empty tank into space and relies on the conservation of momentum to increase her speed to match that of the shuttle. With what velocity (in her frame of reference!) will she have to throw the tank?

Answers

Answer:

a) v_f = 0.898 m / s, b)   v₂ = -6.286 m / s

Explanation:

a) For this exercise we use the conservation of momentum, we define a system formed by the astronaut, her equipment and the expelled gases. We must also define a stationary frame of reference, let's place the system on the platform, so the speed of the subject is v = -3 m / s

Initial instant. Before you start to pass gas

        p₀ = (M + Δm) v

M is the mass of the astronaut M  = 80Kg and Δm the masses of the gases

Final moment. When you expel the gases

        p_f = M (v + Δv) + Δm (v-v_e)

where v_e is the gas velocity v_e = 100 m / s

momentum is conserved

        p₀ = p_f

        M v + Δm v = Mv + M Δv + Δm v -Δm ve

          0 = M Δv - Δm v_e

         

if we make the very small quantities Δv → dv and Δm → dm, furthermore the quantity of output gas is equal to the decrease in the total mass dm = -dM

         M dv = -v_e dM

         ∫ dv = - v_e ∫ dM / M

We solve, between the lower limits v₀ = v with M = M₀   and the upper  limit v = v_f for M = M_f

 

         v_f - v₀ = - v_e (ln M_f - Ln M₀)

         v_f - v₀ = v_e ln ([tex]\frac{M_o}{M_f}[/tex])

         v_f = v₀ + v_e ln (\frac{M_o}{M_f})

let's calculate

         v_f = -1.3 + 100 ln (80 + 10 + 2/80 + 10)

          v_f = -1.3 +2.20

          v_f = 0.898 m / s

b) launch the jetpack to increase its speed up to the speed of the platform

  initial instant. Before launching the tanks

        p₀ = (M + m') v_f

final instnte. After launching the tanks

       p_f = M v₁ + m' v₂

indicate that the final velocity of the astronaut is the platform velocity v₁=0 m / s, since the reference system is fixed on it

       p₀ = p_f

       (M+ m) v_f = M v₁ + m v₂2

       v₂ = [tex]\frac{ M ( v_f - v_o) + m' v_f}{m'}[/tex]

        v₂ = [tex]\frac{M}{m}[/tex] (v_f -v₁) + v_f

let's calculate

        v₂ = 80/10 (0.898 - 0) + 0.898

        v₂ = -7.1874 + 0.898

        v₂ = -6.286 m / s

Please help I’m almost done with exam

Which phrase is the best description of what a telescope does?
O A. Causes objects to grow larger
B. Transports equipment to space
C. Converts solar energy to electricity
D. Detects electromagnethwaves

Answers

Answer:

D

Explanation:

Telescopes detect electromagnetic waves from space and it travels back to the telescope lens in order for you to see.

Answer:

D

Explanation:

Ap ex science exam lol

A motorcycle and rider have a total mass equal to 300 kg. The rider applies the brakes, causing the motorcycle to decelerate at a rate of -5 m/s^2. What is the net force on the motorcycle?

Answers

Answer:

Net force = - 1500 N

Explanation:

We calculate the net force acting using Newton's second Law:

[tex]F_{net}=m*a\\F_{net}=(300 \,kg)*(-5\,m/s^2)\\F_{net}=-1500\,N[/tex]

On Earth, the number flux of solar neutrinos from the p-p chain is:

f_neutrino = 2fo/2.62MeV

Other nuclear reactions in the Sun supplement this neutrino flux with a small additional flux of higher-energy neutrinos. A neutrino detector in Japan, named SuperKamiokande, consists of a tank of 50 kton of water, surrounded by photomultiplier tubes. The tubes detect the flash of Cerenkov radiation emitted by a recoiling electron when a high-energy neutrino scatters on it.

Required:
a. How many electrons are there in the water of the detector?
b. Calculate the detection rate for neutrino scattering, in events per day.

Answers

Answer:

Explanation:

The volume of the tank = 50 kton

50 kton = 5 × 10⁷ kg

Since 18 grams of water will contain: 10 electrons × 6.023 × 10²³

Then;

5× 10⁷ kg will contain [tex]( \dfrac{5 \times 10^7 \times 10^3}{18}) \times 10 \times 6.023 \times 10^{23}[/tex]

= 1.67 × 10³⁴ electrons

(b)

Suppose:

[tex]f_{neutrino} = \dfrac{2f_o}{26.2 MeV} = 6.7\times 10^{10} \ s^{-1} cm^{-2}[/tex]

Then;

10⁻⁶ of [tex]f_{neutrino} = 6.7 \times 10^{10} \times 10^{-6} \ s^{-1} cm^{-2}[/tex]

[tex]=6.7 \times 10^{4}\ s^{-1} cm^{-2}[/tex]

Thus, the number of high energy neutrinos which will interact with water is:

= [tex]6.7 \times 10^4 \times \sigma[/tex]

= [tex]6.7 \times 10^4 \times 10^{-43}[/tex]

= [tex]6.7 \times 10^{-39} s^{-1}[/tex]

For  1.67 × 10³⁴ electrons, the detection rate is:

[tex]6.7 \times 10^{-39} \times 1.67 \times 10^{34}[/tex]

[tex]= 11.19 \times 10^{-5} \ s^{-1}[/tex]

= 9.668 per day

For the questions below, include units if applicable. If necessary, use a separate sheet of paper for 1, 6c and 7c. Tire pressure is in part a function of the temperature of the tire.
1. Based on everyday experience, state (in words) the relationship between tire pressure and temperature. Look at the data below and see if the numbers support your statement.
2. Prepare a hand-drawn plot of the two variables on the reverse side of this worksheet. Include a title, axis labels (with units), and a trendline. Estimate the tire pressure when the temperature is 18.6°C: Estimate the temperature of the air in the tire when the pressure is 37.0 psi: 3.
a. Prepare a plot using graphing software. Include a title, axis labels (with units), the equation of the best-fit Line and the R? value on the graph.
b. Re-write the equation of the best-fit line substituting "Temperature" for x and "Pressure" for y directly on the graph.
c. Attach the fully labeled graph to this worksheet.
4. What is the value of the slope for the relationship between temperature and pressure?
5. Determine the percent error using the definition of percent error: Use 0.145 psi/" for the "Actual" value of the slope. %error = Actual-Experimental % Error Actual
6. Based on your computer-generated graph,
a. visually estimate the tire pressure when the temperature is 18.6°C:
b. calculate the tire pressure at this temperature using the equation of the best fit line: the graph to ensure that this value is reasonable.
c. compare the calculated pressure to the two visually interpolated values (Steps 2 and 6a). Comment on any discrepancies.
7. Based on your computer-generated graph,
a. visually estimate the temperature of the air in the tire when the pressure is 37.0 psi:
b. calculate the temperature of the air in the tire at this pressure: Use the graph to ensure that this value is reasonable.
c. compare the calculated temperature to the two visually interpolated values (Steps 2 and 7a). Comment on any discrepancies.
Data:
Temperature (x) Tire Pressure, psi (y)
12.9°C 3.39 x 10
15.4C 34.25
-2.10 F 2.68 x 10
19.5 °C 3.50 x 10
29.6 'F 36.53

Answers

Answer:

All answer are explained below in the explanation section.

Explanation:

1. The pressure varies proportionally with the change in temperature. It can also be observed in our daily lives.

As for example, a pressure cooker uses the same principal to cook food faster. With the increasing temperature, the pressure inside the cooker increases.

Thus after a while, the excess pressure inside is released through the top nozzle. The data shown below supports that pressure and temperature varies linearly.

2. Hand drawn plot is attached in the attachment please refer to the attachment for the hand drawn plot.

Tire pressure at temperature 18.6 degree C is ~ 35 psi.

Temperature at air pressure of 37 psi is ~26.1 degree C

3. a.) Necessary values are included in the stat box. It is attached in the attachment please refer to the attachment.

3. b) The equation becomes: Pressure = 0.176 x temperature + 32.32

3. c) It is already done in part a of this question.

4. The value of the slope estimated from the linear fit is 0.176 +/- 0.094.

5. % Error = [tex]\frac{Actual - Experiment}{Actual} x 100[/tex]

Plugging in the values, we get:

Actual = 0.145, Experimental = 0.176. Thus, percentage error is given by:

% Error = 21.33%

6. a.) Visual estimation of tire pressure at t = 18.6 degree C is ~ 35 psi

6.  b.) Estimation of pressure from the best fit line is given by 35.6 psi, which is consistent with the eye estimation value.

6. c.) The eye estimation and the estimation from the line fit are quite comparable. The discrepancy of +/-0.5 psi is within the percentage error calculated in 5.

7.  a.) Visual estimation of temperature of the air for a tire-pressure of 37 psi is ~ 26 degree C.

7.  b.) Estimation of temperature from best fit value of line is = 26.64 degree C

7 c) The values from eye estimation and evaluated from the fit are quite consistent within a random fluctuation of +/- 0.64 degree C.

alex often draws his dream house​

Answers

Answer:

hopefully alex quackity hahhaa

Explanation:

i hope this was free points and not an actual thing

Answer:

cool, cool for alex .....

Which of the following will be attracted toward a positively charged cloth?

Positively charged sock
Negatively charged pipe
Sound waves
Light energy

Answers

Postive and negatives attract, positive and positive repel. answer is negatively charged pipe.

sound waves and light energy are not "affected" by static electricity

What is the difference between the reflection and refraction of light

Answers

Answer:

Reflection can simply be defined as the reflection of light when it strikes the medium on a plane. Refraction can be defined as the process of the shift of light when it passes through a medium leading to the bending of light. The light entering the medium returns to the same direction.

Answer:

reflection is your image and refraction is light

3. Consider a large windmill 30m in diameter. On a windy day, suppose that the windmill entrains a stream of air at a speed of 40 mph. Downstream of the windmill, the entrained stream exits over a large diameter at a speed of 20 mph. The pressure is 2atm at the inlet and equals atmospheric pressure at the outlet. Find the power (in megawatts) generated by the windmill. Density of air is 1.2 kg/m3

Answers

Answer:

The power generated by the windmill is approximately 1.364 MW

Explanation:

The diameter of the windmill, d = 30 m

The inlet speed of the wind, [tex]V_e[/tex] = 40 mph = 17.88 m/s

The exit stream velocity, [tex]V_i[/tex] = 20 mph = 8.94 m/s

The pressure at the inlet, P₁ = 2 atm

The pressure at the outlet, P₂ = 1 atm

The density of air, ρ = 1.2 kg/m³

The power obtained from the windmill, 'P', is given as follows;

[tex]P =\dfrac{1}{4 \cdot g_c} \cdot \rho \cdot A \cdot (V_i + V_e)\cdot (V_i^2 - V_e^2)[/tex]

Where;

[tex]g_c[/tex] = 1.0 kg/(N·s²)

A = Cross-sectional rea of the the windmill =  π·D²/4 = π×(30 m)²/4 = 706.858347 m²

Plugging in the values, we get;

[tex]P =\dfrac{1}{4 \times 1.0} \times1.2 \times 706.858347 \times (17.88 + 8.94)\cdot (17.88^2 - 8.94^2) = 1363668.19438[/tex]

The power generated by the windmill, P ≈ 1363668.19438 W ≈ 1.364 MW.

3. Two cyclists that are 500 m apart start biking toward each other. They bike at speeds of 6 and

4 m/s.

How long does it take for them to reach each other?

a.

b. How far does the slower biker travel?

Answers

Answer:

A) 50 seconds

B) 200 m

Explanation:

They are 500 metres apart.

And one of the bike loves at 6 m/s while the other loves at 4 m/s.

A) Let distance of the 6 m/s bike before they meet be x.

Thus, time = x/6

Since time = distance/speed

For the second bike at 4 m/s, his distance covered before they meet will be 500 - x

Thus, time = (500 - x)/4

Now they will meet each other at the same time. Thus;

x/6 = (500 - x)/4

Cross multiply to get;

4x = 3000 - 6x

6x + 4x = 3000

10x = 3000

x = 3000/10

x = 300 m

Thus, time will be;

t = 300/6

t = 50 seconds

B) Distance covered by the slower bike is (500 - x)

Since from a above, x = 300

Thus; distance = 500 - 300 = 200 m

A 150.0 g baseball has a velocity of 28.5 m/s. What is its kinetic energy in J

Answers

Answer:

KE = 60.91875 J

Explanation:

First, convert the mass of the ball into kg, since we want the answer in J (SI system):

150 g = 0.15 kg

then use the kinetic energy formula

[tex]KE=\frac{1}{2} m*v^{2} \\KE=\frac{1}{2} (0.15)*(28.5)^{2}\\KE=60.91875 J[/tex]

A cyclist cover 6km in 20minutes. His speed is ​

Answers

Answer:

The speed of a cyclist is 0.3 km/min.

Explanation:

Given

The distance d = 6km Time t = 20 minutes

To determine

We need to determine the speed of a cyclist.

In order to determine the speed of a cyclist, all we need to do is to divide the distance covered by a cyclist by the time taken to cover the distance.

We know the formula involving speed, time, and distance

[tex]s=\frac{d}{t}[/tex]

where

s = speedd = distance coveredt = time taken

substitute d = 6, and t = 20 in the formula

[tex]s=\frac{d}{t}[/tex]

[tex]s=\frac{6}{20}[/tex]

Cancel the common factor 2

[tex]s=\frac{3}{10}[/tex]

[tex]s=0.3[/tex] km/min

Thus, the speed of a cyclist is 0.3 km/min.

0.3km/m
Trust the other guy he’s right and dont forget to give him BRAINLIEST

It has been suggested that rotating cylinders several miles in length and several miles in diameter be placed in space and used as colonies. Inhabitants of the space colonies would live on the inside surface of the cylinder. Inertial effects would resemble gravity's influence and keep them 'plastered to the surface.' Suppose that you are an inhabitant of a space colony which is 1070 miles in length and 4.86 miles in diameter. How many revolutions per hour must the cylinder have in order for the occupants to experience a centripetal acceleration equal to the acceleration of gravity

Answers

Answer:

the required revolution per hour is 28.6849

Explanation:

Given the data in the question;

we know that the expression for the linear acceleration in terms of angular velocity is;

[tex]a_{c}[/tex] = rω²

ω² = [tex]a_{c}[/tex] / r

ω = √( [tex]a_{c}[/tex] / r )

where r is the radius of the cylinder

ω is the angular velocity

given that; the centripetal acceleration equal to the acceleration of gravity a [tex]a_{c}[/tex]  = g = 9.8 m/s²

so, given that, diameter = 4.86 miles = 4.86 × 1609 = 7819.74 m

Radius r = Diameter / 2 = 7819.74 m / 2 = 3909.87 m

so we substitute

ω = √( 9.8 m/s² / 3909.87 m )

ω = √0.002506477 s²  

ω = 0.0500647 ≈ 0.05 rad/s  

we know that; 1 rad/s = 9.5493 revolution per minute

ω = 0.05 × 9.5493 RPM

ω = 0.478082 RPM  

1 rpm = 60 rph  

so  

ω = 0.478082 × 60

ω = 28.6849  revolutions per hour  

Therefore, the required revolution per hour is 28.6849

The required revolution per hour is 28.6849

Calculation of revolution per hour:

The expression for the linear acceleration with respect to the angular velocity is

= rω²

So,

ω² =  / r

ω = √(  / r )

Here r represent the radius of the cylinder

ω represent the angular velocity

Now

diameter = 4.86 miles = 4.86 × 1609 = 7819.74 m

And,

Radius r = Diameter / 2 = 7819.74 m / 2 = 3909.87 m

So,

ω = √( 9.8 m/s² / 3909.87 m )

ω = √0.002506477 s²  

ω = 0.0500647 ≈ 0.05 rad/s  

Now

1 rad/s = 9.5493 revolution per minute

So,

ω = 0.05 × 9.5493 RPM

ω = 0.478082 RPM  

Now

1 rpm = 60 rph  

so  

ω = 0.478082 × 60

ω = 28.6849  revolutions per hour  

Learn more about the cylinder here: https://brainly.com/question/17262276

QUESTION 9 / 10
What is the first step you should take when you want to open a savings account?
A. Present your photo ID to the bank representative,
B. Make your initial deposit.
C. Review the different savings account options that your
bank offers.
D. Go to the bank and fill out an application.

Answers

Answer:

A

Explanation:

AWNSER:

awnser:

C

explanation:

You are driving a car behind a truck. Both your car and the truck are moving at a speed of 80km/hr. If the driver of the truck suddenly slams on the brakes, what minimum distance betweenyour car and the truck is needed so that your car does not crash into the truck’s rear end? (This is called the "​minimum trailing distance​".) To simplify this problem, assume that the truck andthe car have the same braking acceleration.

a. In order to simplify the calculations for this problem, you are told to assume that the braking acceleration of the car and the truck are the same. What other reasonable assumptions do you need to make in order to solve this problem?
b. For both the truck and the car, draw an acceleration- and velocity-versus-time graph.
c. Find an expression for the minimum trailing distance. (Your expression should only contain symbols of physical quantities. No numbers are needed here.)
d. Find the numerical value for the minimum trailing distance (Plug the values of physical quantities into your expression from part A (do not forget units!))

Answers

Answer:

Explanation:

Let the velocity of car and truck be u and breaking acceleration be a .

We shall have to assume the reflex time of the driver of the car . By the time he applies brake , his car will cover some distance . There will be some time tag between the time the truck starts decelerating and the driver of the car responding to that . During this period the car will not start decelerating . It will keep on moving with uniform velocity of u .

Let this time lag be t .

b )

For answer see the attached file

c )

The minimum trailing distance will be the distance covered by car before it starts decelerating in response to truck's deceleration .

minimum trailing distance d = u x t

d )  u = 80 km / h = 22.22 m /s

reflex action time t = 0.1 s  ( assumed time )

d = 22.22 x .1

= 2.2 m

Four-wheel drive trucks do not stop better on icy
roads than a car. Is what law of motion (Newton's laws)

Answers

It would be Newton’s second law of motion

[BWS.02]If the same experiment is repeated in different parts of the world by different scientists,

the results will be the same
the results will become invalid
the outcome of the experiment will be non testable
the outcome of the experiment will be non observable

Answers

Answer:

the results will be the same.it may be

If the same experiment is repeated in different parts of the world by different scientists, the results will be the same.

What is scientific experiment?

An experiment is a procedure that is carried out to support or refute a hypothesis, or to determine the efficacy or likelihood of something that has never been tried before. Experiments shed light on cause-and-effect relationships by demonstrating what happens when a specific factor is changed.

Controls are typically included in experiments to minimise the effects of variables other than the single independent variable. This improves the reliability of the results, often by comparing control measurements to the other measurements. Scientific controls are an essential component of the scientific method.

Hence, If the same experiment is repeated in different parts of the world by different scientists, the results will be the same.

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What is the acceleration of a .3 kg mass when there is a net force of 25.9 N on it?

Answers

Answer:

86.33m/s^2

Explanation:

Acceleration = Force/Mass

= 25.9/0.3

= 86.33

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