The best answer for your question would be C. The total amount of all forms of energy stays the same.
First, let's eliminate the wrong choices. According to the Law of Conservation of Energy, you cannot create nor destroy energy, so you can eliminate choices A and B.
Also according to the Law of Conservation of Energy, the total amount of energy will always be the same. It may transform into different forms of energy.
To me, D doesn't sound very correct. For this one you can take an aducational guess, but I do not believe it would be D.
Hope this helps; have a great day!
The sum of the kinetic energy and the potential energy of a particle is its
Answer:
he total mechanical energy E of a particle is defined as the sum of the kinetic and potential energies
Explanation:
Answer:
thermal energy
Explanation:
The concentration of H3AsO3 in a solution is determined by titrating it with a 0.1741 M Ce4+ solution. The balanced net ionic equation for the reaction is: 2Ce4+(aq) + H3AsO3(aq) + 5H2O(l) 2Ce3+(aq) + H3AsO4(aq) + 2H3O+(aq) In one experiment, 18.68 mL of the 0.1741-M Ce4+ solution is required to react completely with 30.00 mL of the H3AsO3 solution.
Calculate the concentration of the H3AsO3 solution.
Answer:
0.0542 M
Explanation:
Let;
CA = concentration of Ce4+ solution = 0.1741 M
VA = volume of Ce4+ solution = 18.68 mL
CB = concentration of H3AsO3 = ?
VB = volume of H3AsO3 = 30.00 mL
NA = Number of moles of Ce4+ solution = 2
NB = Number of moles of H3AsO3 = 1
From;
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
CB = CAVANB/VBNA
CB = 0.1741 * 18.68 * 1/30.00 * 2
CB = 0.0542 M
The symbol for free energy is
a. DG.
b. DS.
c. DT.
d. DH.
Consider the following exothermic process at equilibrium:
CO(g)+H2O(g)⇌CO2(g)+H2(g)
Which of the following changes would increase the amount of H2(g) present in the equilibrium mixture?
Consider the following exothermic process at equilibrium:
Which of the following changes would increase the amount of present in the equilibrium mixture?
decrease the temperature
increase [CO2]
increase [CO]
increase the volume of the container in which the reaction occurs.
more than one of the above
(Answer is not increase [CO])
For the given exothermic process at equilibrium, an increase in the concentration of CO would increase the amount of H₂.
How is equilibrium affected by changes?When a perturbation is done on a system at equilibrium, it shifts its equilibrium position to counteract the perturbation.
Let's consider the following exothermic process at equilibrium.
CO(g) + H₂O(g) ⇌ CO₂(g) + H₂(g)
Which of the following changes would increase the amount of H₂(g) present in the equilibrium mixture?
decrease the temperature. NO. For an exothermic reaction, a decrease in the temperature will shift the equilibrium towards the reactants.increase [CO₂]. NO. This would shift the equilibrium towards the reactants.increase [CO]. YES. This would shift the equilibrium towards the products.increase the volume of the container in which the reaction occurs. NO. This wouldn't affect the equilibrium since the number of gaseous moles is the same on both sides.more than one of the above. NO.For the given exothermic process at equilibrium, an increase in the concentration of CO would increase the amount of H₂.
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The air bags in automobiles were once inflated by nitrogen gas generated by the rapid decomposition of
sodium azide, NaN3.
2 NaNz (s) 2 Na (s) + 3 N2 (g)
If an air bag has a volume of 53.4 L and is to be filled with nitrogen gas at a pressure of 1.07 atm and a
temperature of 23.7°C, how many moles of NaNz must decompose? You may assume the Ny behaves as
an ideal gas.
Answer:
1.57 mol NaN₃
Explanation:
2 NaN₃ (s) → 2 Na (s) + 3 N₂ (g)First we use PV=nRT to calculate the number of N₂ moles that need to be produced:
P = 1.07 atmV = 53.4 Ln = ?R = 0.082 atm·L·mol⁻¹·K⁻¹T = 23.7 °C ⇒ 23.7 + 273.16 = 296.86 KInputing the data:
1.07 atm * 53.4 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 296.86And solving for n:
n = 2.35 mol N₂Finally we convert N₂ moles into NaN₃ moles, using the stoichiometric coefficients of the balanced reaction:
2.35 mol N₂ * [tex]\frac{2molNaN_3}{3molN_2}[/tex] = 1.57 mol NaN₃A sample of hydrogen has an initial temperature of 122.0 °F. When the temperature is lowered to -23.0 °F, the volume of hydrogen becomes 212 cm3. What was the initial volume of the hydrogen?
Answer: The initial volume of gas was [tex]282cm^3[/tex]
Explanation:
Charles's Law: This law states that volume is directly proportional to temperature of the gas at constant pressure and number of moles.
[tex]V\propto T[/tex] (At constant pressure and number of moles)
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where,
[tex]V_1[/tex] = initial volume of gas =?
[tex]V_2[/tex] = final volume of gas = [tex]212cm^3[/tex]
[tex]T_1[/tex] = initial temperature of gas = [tex]122.0^0F=323.15K[/tex]
[tex](32^0C=273.15K)[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]-23.0^0F=242.59K[/tex]
[tex]\frac{V_1}{323.15}=\frac{212}{242.59}[/tex]
[tex]V_2=282cm^3[/tex]
Therefore, the initial volume of gas was [tex]282cm^3[/tex]
Why is Potassium called an alkali metal?
Answer:
Explanation: potassium (Na) has one electron in outer shell
And it donates it easily and can even reduce
Hydrogen gas from water. An alkaline solution containing
Hydroxide ions (OH-) is then formed
Answer:
Because
Explanation:
Potassium is called Alkali metal because Potassium forms oxides which dissolve in water to form Alkali
What is the formula of compound formed from a calcium ion and As? Express your answer as a chemical formula
Answer:
its chemical formula is Ca3N2
Explanation:
hope it will help
Arrange in terms of increasing atomic radius. From smallest to largest.
S, F, Sr, Na, Ga
Answer:
F<S<Na<Ga<Sr
Explanation:
Atomic radius increased from the right of the periodic table to left, and from the top to the down
When magma goes down into the lower part of the mantie where it is recycled and may come right back up the ocean ridge is called..
2Fe(s) +3H2SO4(aq) →Fe2(SO4)3(aq) +3H2(g)When 10.3 g of iron are reacted with 14.8 moles of sulfuric acid, what is the percent yield if 5.40 g of "hydrogen gas" are collected?
Answer:
1040%
Explanation:
To solve this question we must convert the mass of Iron to moles in order to find limiting reactant. With limiting reactant we can find the theoretical moles of hydrogen and theoretical mass:
Percent yield = Actual yield (5.40g) / Theoretical yield * 100
Moles Fe -Molar mass: 55.845g/mol-:
10.3g * (1mol / 55.845g) = 0.184 moles of Fe will react.
For a complete reaction of these moles there are necessaries:
0.184 moles Fe* ( 3 mol H2SO4 / 2 mol Fe) = 0.277 moles H2SO4.
As there are 14.8 moles of the acid, Fe is limiting reasctant.
The moles of H2 produced are:
0.184 moles Fe* ( 3 mol H2 / 2 mol Fe) = 0.277 moles H2
The mass is:
0.277 moles H2 * (2.016g/mol) = 0.558g H2
Percent yield is:
5.40g / 0.558g * 100 = 1040%
It is possible the experiment wasn't performed correctly
The equation for the formation of ammonia from nitrogen and hydrogen is shown below. What is the formula for the equilibrium constant, Kc? {Hint, I’m just looking for letters/symbols, not numbers.}
H2(g) + N2(g) ⇌ NH3(g)
First, make sure to balance your equation.
3H2(g) + N2(g) ⇄ 2NH3(g)
Now, you can write your Kc expression. Remember that Kc is products over reactants, and the exponent for each product or reactant is based on its coefficient.
Kc = [NH3]^2 / [H2]^3[N2]
The reaction between nitrogen and hydrogen is called the Haber process. Kc for the reaction is the ratio of the concentration of ammonia to nitrogen and hydrogen.
What is the equilibrium constant?An equilibrium constant, kc is the concentration proportion of the products to the concentration of the reactants raised by their respective coefficients.
The balanced chemical Haber process is given as:
[tex]\rm 3H_{2}(g) + N_{2}(g) \leftrightharpoons 2NH_{3}(g)[/tex]
Now, the equilibrium constant for the reaction can be given as:
[tex]\rm Kc = \rm \dfrac{[NH_{3}]^{2}}{[H_{2}]^{3}[N_{2}]}[/tex]
Therefore, the ratio of the concentration of ammonia to hydrogen and nitrogen gives the equilibrium constant.
Learn more about the equilibrium constant here:
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The gas phase decomposition of nitrogen dioxide at 383 °C
NO2(g)NO(g) + ½ O2(g)
is second order in NO2 with a rate constant of 0.540 M-1 s-1.
If the initial concentration of NO2 is 0.477 M, the concentration of NO2 will be
M after 12.4 seconds have passed.
Answer:
[tex][NO_2]=0.112M[/tex]
Explanation:
Hello there!
In this case, since the second-order integrated law is given by the following equation:
[tex]\frac{1}{[NO_2]} =\frac{1}{[NO_2]_0}+kt[/tex]
Thus, given the initial concentration of the nitrogen dioxide gas, the rate constant and the elapsed time, we obtain:
[tex]\frac{1}{[NO_2]}= \frac{1}{0.477M} +0.54M^{-1}s^{-1}\\\\\frac{1}{[NO_2]}=8.933M^{-1}[/tex]
[tex][NO_2]=\frac{1}{8.933M^{-1}} =0.112M[/tex]
Best regards!
pls help i will mark as brainliest
Answer:
ano po ito?? isa po ba itong story
How are a tundra and a desert different?
A desert has a low level of precipitation and a tundra has a high level of precipitation.
A desert is wet year-round and a tundra is dry.
A tundra has a lower levels of humidity.
A tundra has lower average temperatures year-round.
i am giving brainlyest!!!!!!!
Answer:
A tundra has a lower average temperatures year-round.
Which of the following statements about C3 carbon fixation is true? a. C3 carbon fixation is an adaptation for plants exposed to high light intensity. b. C3 carbon fixation occurs in more plants than C4 carbon fixation. c. C3 carbon fixation is more common in areas of high temperatures than C4 carbon fixation. d. C3 carbon fixation occurs in the inner cells of a leaf rather than the entire leaf.
Answer: The answer is B
Explanation:
RiP BoZo. shout out to faze gabi staright up bopped potato girl.
Answer:
B
:D
Explanation:
How many moles of solute are present in 2 L of a 25M potassium nitrate (KNO3) solution?
0.5 moles
50 moles
25 moles
2 moles
50 moles
The formula used in this question is-
Mole= Molarity*Volume(in Litre)
So after putting the value
= (25)*(2)
=50 moles
What is molarity?
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution.
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gloves worn when working with liquid oxygen must be able to resist.
Answer:
What is your question?
Explanation:
Can you give more context to ur question?
Which process takes place in the conversion of iron into steel?
Iron is changed into steel by blowing oxygen through the molten metal from the Blast Furnace. This oxidises the impurities in the molten metal. Carbon is a major impurity in Blast Furnace metal.
How many moles of C2H2 are required to produce 0.60 mol of H2O?
Express your answer to two significant figures and include the appropriate units.
Answer:
0.60 moles
Explanation:
From the reaction:
[tex]2C_2H_2 + 5O_2 \to 4CO_2+2H_2O[/tex]
From above, Only 2 moles of CH2CH2 are required to produce 2 moles of water (H_2O).
As such, 0.6 moles of H2O will require:
x (CH2CH2) × 2 moles of (H_2O) = 0.6 moles (CH2CH2) × 2 mole of (H_2O)
x mole of (CH2CH2) = 0.60 moles
∴
0.6 moles of H2O will require 0.60 moles of CH2CH2
How many grams of Mg(NO3), are necessary to
make 1500 mL of a 0.50 M solution?
Answer:
1.1 × 10² g
Explanation:
Step 1: Given data
Concentration of the solution (C): 0.50 M (0.50 mol/L)Volume of solution (V): 1500 mL (1.500 L)Step 2: Calculate the moles of Mg(NO₃)₂ (solute)
Molarity is equal to the moles of solute (n) divided by the liters of solution.
C = n/V
n = C × V
n = 0.50 mol/L × 1.500 L = 0.75 mol
Step 3: Calculate the mass corresponding to 0.75 moles of Mg(NO₃)₂
The molar mass of Mg(NO₃)₂ is 148.3 g/mol.
0.75 mol × 148.3 g/mol = 1.1 × 10² g
How tightly particles are packed determines what state it takes.
True or False
Answer:
True
Explanation:
tighter the molecules the slower it moves and the harder it gets
solid has very tight particles packed together
gas has its particles spread out
What's the wavelength in meters of an electron traveling at 9.5 x 10^7 m/s? The mass of an electron is 9.11 x 10^-28 g.
Select one:
a. 7.66 x 10-15 m
b.7.66 x 10-12 m
c. 3.47 x 1027 m
d. 3.47 x 1030 m
Answer:
where:
• A is the wavelength in m.
• h = 6.626 x 10-34Js is Planck's
constant.
• m is the mass of the particle, such as the electron, in kg. The particle must have a mass for this relation to work.
• v is the forward velocity of the particle, in m/s.
Hence, the wavelength is:
6.626 x 10-34J.s
(9.1094 × 10 −³¹kg) (5 × 10³m/s)
We know that 1 J 1 kg. m²/s². So:
6.626 × 10-³4 g · m² / ø
9.1094 x 10 - 31) (5 x 105 m/s)
= 1.455 x 10-9 m
=
= 1.455 nm
Observe the map what do the grey scar like represent?
Answer:
mid ocean ridge
Explanation:
Human blood contains a buffer of carbonic acid (H_2 CO_3) and bicarbonate anion (HC〖O_3〗^-) in order to maintain blood pH between 7.35 and 7.45, as a value higher than 7.8 or lower than 6.8 can lead to death. In this buffer, hydronium and bicarbonate anion are in equilibrium with carbonic acid. Furthermore, the carbonic acid in the first equilibrium can decompose into CO_2 gas and water, resulting in a second equilibrium system between carbonic acid and water. Because CO_2 is an important component of the blood buffer, its regulation in the body, as well as that of O_2 , is extremely important. The effect of this can be important when the human body is subjected to strenuous condition.
Carbonic acid buffer:
H_2 CO_3 (aq)+ H_2 O(l) ↔H_3 O^+ (aq)+HC〖O_3〗^- (aq)
1. Write the equilibrium constant expression K_c for the carbonic acid buffer in the blood.
Kc = [H3O+][HCO3-] / [H2CO3]
Remember that Kc is products over reactants. Also, you do not include liquid water in a Kc expression, since liquid water has no concentration.
As an FDA physiologist, you need 0.625 L of phosphoric acid acid / dihydrogen phosphate (H3PO4 (aq) / H2PO4 - (aq) ) buffer with a pH of 2.75. How do you prepare this solution from stock solutions of 1.0 M H3PO4 (formic acid) and 1.5 M NaOH
Answer:
0.4058L of 1.0M H3PO4
0.2192L of 1.5M NaOH
Explanation:
The pKa of the H3PO4 / H2PO4- buffer is 2.12
To solve this question we must use H-H equation for this system:
pH = pKa + log [H2PO4-] / [H3PO4]
2.75 = 2.12 + log [H2PO4-] / [H3PO4]
0.63 = log [H2PO4-] / [H3PO4]
4.2658 = [H2PO4-] / [H3PO4] (1)
Where [] could be taken as the moles of each reactant
As you have H3PO4 solution, the reaction with NaOH is:
H3PO4 + NaOH → H2PO4- + Na+ + H2O
As you can see, both H3PO4 and H2PO4- comes from the same 1.0M H3PO4 solution
The moles of H3PO4 are:
[H3PO4] = Moles H3PO4 - Moles NaOH
And for H2PO4-:
[H2PO4-] = Moles NaOH added
Replacing in (1):
4.2658 = [Moles NaOH] / [Moles H3PO4 - Moles NaOH]
4.2658 Moles H3PO4 - 4.2658 moles NaOH = Moles NaOH
4.2658 Moles H3PO4 = 5.2658 moles NaOH (1)
In volume:
0.625L = Moles H3PO4 / 1.0M + Moles NaOH / 1.5M
0.625 = Mol H3PO4 + 0.6667 Moles NaOH (2)
Replacing (2) in (1):
4.2658 Moles H3PO4 = 5.2658 (0.625 - Mol H3PO4 / 0.6667)
4.2658 Moles H3PO4 = 5.2658 (0.625 - Mol H3PO4) / 0.6667
4.2658 Moles H3PO4 = 5.2658*(0.9375 - 1.5 mol H3PO4)
4.2658 Moles H3PO4 = 4.9367 -7.8983 mol H3PO4
12.1641 mol H3PO4 = 4.9367
Mol H3PO4 = 0.4058moles * (1L / 1.0moles) =
0.4058L of 1.0M H3PO4
And:
0.625L - 0.4058L =
0.2192L of 1.5M NaOH
How many milliliters of 0.2560 M KCl solution will contain 20.00 g of KCl?
Answer is 1048 mL solution but how do I get to the answer?
Answer:
1048 mL
Explanation:
Step 1: Given data
Concentration of the solution: 0.2560 MMass of KCl (solute): 20.00 gStep 2: Calculate the moles corresponding to 20.00 g of KCl
The molar mass of KCl is 74.55 g/mol.
20.00 g × 1 mol/74.55 g = 0.2683 mol
Step 3: Calculate the volume of the solution
Molarity is equal to moles of solute divided by liters of solution.
M = moles of solute / volume of solution
volume of solution = moles of solute / M
volume of solution = 0.2683 mol / (0.2560 mol/L)
volume of solution = 1.048 L = 1048 mL
Answer the following question by studying the given
structure of the stoma
1)Name the atoms of element
2)In which group of the periodic table do these element lie?
Answer:
1) A. carbon B. oxygen
2) A. semi metal. B. Non- metal( gas)
C. 2.86 g
D. 1.22 g
13. At what Kelvin temperature will 25.2 mol of Xe occupy a volume of 645 L at a pressure of 732 torr?
A. 361 K
B. 291 K
C. 402 K
D. 300 K
22.4 L is the volume of any gas regardless of atmospheric conditions.
O True
O False
