Which 5 are examples of locomotor movements? Select all that apply.
Question 1 options:

Hopping

Galloping

Sitting

Sleeping

Walking

Running

Skipping

Eating

Answer:

c.holding a sign in the air

Explanation:

because b is kinetic energy and a is also kinetic energy

Answer:

Left

Explanation:

Answer:

Your Left hand is negatively charged, and receives energy. It emits the energy that "allows things to happen''.

Explanation:

did some research

Answer:

Please find attached pdf

Explanation:

Answer:

   F₁> F₂

Explanation:

For this exercise Newton's second law is used, in the adjoint we can see the unapplied forces in this exercise.

Y axis y

        N- W = 0

in this axis there is no movement

X axis

          F -fr = m a

as they indicate that the velocity is consonant the acceleration is worth zero

          F - fr = 0

friction force has the expression

           fr = μ N

           fr = μ mg

we substitute

           F = μ m g

by the time the block is stopped the deferred force is

           F₁ = μ_s m g

when it begins to move the force should decrease to

           F₂ = μ_k k m g

as the static coefficient is greater than the dynamic coefficient

             F₁> F₂

The free body diagram consists of applied force (F) and kinetic frictional force acting in opposite direction.

The net force on the block will result constant speed of the block which is zero acceleration.

[tex]\Sigma F= 0\\\\F - F_f = 0\\\\F - \mu_k F_n= 0\\\\F - \mu_k mg = 0\\\\F - \mu k W = 0\\\\F = F_f\ \ \ or \ \ F = \mu_k W[/tex]

The free body diagram consists of applied force (F) and kinetic frictional force acting in opposite direction.

                        F →  Ф ← Ff

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Answer:

difference between the field  = 1.56 N/C

as; 1.56 N/C is greater than 0.77 N/C;

Hence, Honeybees can detected the difference

Explanation:

Given the data in the question;

distance r = 24 cm = 0.24 m

charge 1 Q1 = +30 pC = 30×10⁻¹² C

charge 2 Q2 = +40 pC = 40×10⁻¹² C

Now, electric field due to +30 pC charge

E1 = kQ1/r²

where coulomb constant k is 9 × 10⁹ N.m²/C²

so we substitute

E1 = [( 9 × 10⁹ ) × (30×10⁻¹²)] / (0.24)²

E1 = 0.27 / 0.0576

E1 = 4.69 N/C

electric field due to +40 pC charge

E2 = kQ1/r²

E2 = [( 9 × 10⁹ ) × (40×10⁻¹²)] / (0.24)²

E2 = [( 9 × 10⁹ ) × (40×10⁻¹²)] / (0.24)²

E2 = 0.36 / 0.0576

E2 = 6.25 N/C

Now,

E2 = E1 =  6.25 N/C - 4.69 N/C = 1.56 N/C

difference between the field  = 1.56 N/C

as; 1.56 N/C is greater than 0.77 N/C;

Hence, Honeybees can detected the difference

Answer:

RThe answer is Reflection....

Answer:

The magnitude of the potential difference is 900 V.

Explanation:

Given;

mass of the bead, m = 4.0 g = 0.004 kg

charge of the bead, Q = 20 μC = 20 x 10⁻⁶ C

final velocity of the bead, v = 3 m/s

What is the magnitude of the potential difference V?

Apply the principle of conservation of energy;

The electric potential energy at the beginning is equal to kinetic energy of the bead  at the end of the journey.

qV = ¹/₂mv²

[tex]V = \frac{mv^2}{2q} \\\\V = \frac{0.004 \ \times \ (3)^2}{2(20 \times 10^{-6})}\\\\V = 900 \ V[/tex]

Therefore, the magnitude of the potential difference is 900 V.

The magnitude of the potential difference (V) is equal to 900 Volts.

Given the following data:

To determine the magnitude of the potential difference (V):

We would apply the law of conservation of energy, which states that the electric potential energy possessed by the bead at the beginning is equal to the kinetic energy possessed by the bead at the end of the journey:

[tex]qV = \frac{1}{2} mv^2\\\\V = \frac{\frac{1}{2} mv^2}{q} \\\\V = \frac{\frac{1}{2} \times 0.004 \times 3.0^2}{20 \times 10^{-6}} \\\\V = \frac{ 0.002 \times 9}{20 \times 10^{-6}}[/tex]

V = 900 V.

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Answer:

O exothermic, because energy is released into the surrounding

Explanation:

From the diagram the energy of the reactant is higher than the energy of the product, thereby making it exothermic. If you study diagram well, exothermic reaction means that the reactions releases energy into the surroundings.

Answer:

750 J

Explanation:

We have a student that pushes a 50N block  across the floor for a distance of 15m. The question is asking how much work was done to move the block.

To solve this, we must know that we are looking for a certain thing called joules. And to get the answer, we must follow the formula of W = FS

F being the force and S being the distance.

W = FS

W = (50)(15)

W = 750

Therefore, 750 joules is our answer.

Answer:

6. A

7. C

8. B

9. The average speed is the distance (a scalar quantity) per time ratio. Speed is ignorant of direction. The average velocity is the displacement or position change (a vector quantity) per time ratio.

Answer:

m = 30, g = 9.8, coefficient = 0.2, so force due to friction = 30 x 9.8 x 0.2 = 58.8 N, so work done by friction = 58.8 x 1.2 = 70.56 J

Explanation:

Answer:

The correct answer is option D.

Explanation:

It is stated in the question that constriction of the vocal tract at a place where the standing wave of a formant exhibits minimum-amplitude pressure oscillations generally causes the formant to drop in frequency so to increase formant frequency, the vocal should expand where the standing wave of a formant exhibits minimum-amplitude pressure oscillations. The answer is D.

I hope this helps.

Answer:

ok i think the answer would be C. or B. hope im right

Answer:

They become oppositely charged, which causes them to be attracted to each other.

Answer: number A

Explanation:

If a positive charge and a negative charge interact, their forces act in the same direction, from the positive to the negative charge. As a result opposite charges attract each other: The electric field and resulting forces produced by two electrical charges of opposite polarity. Have a nice day <3

Answer:

the answer is B: 35,136

Explanation:

force = mass × acceleration

force = 9760 × 3.6

35,136 = 9760 × 3.6

Answer:

0.339 kgm²

Explanation:

We know the period of this pendulum, T = 2π√(I/mgh) where I = moment of inertia of the object about the pivot axis, m = mass of object = 2.15 kg, g = acceleration due to gravity = 9.8 m/s² and h = distance of center of mass of object from pivot point = 0.163 m.

Since T = 2π√(I/mgh), making I subject of the formula, we have

I = mghT²/4π²

Now since it takes 241 s to complete 113 cycles, then it takes 241 s/113 cycles to complete one cycle.

So, T = 241 s/113 = 2.133 s

So, Substituting the values of the variables into I, we have

I = mghT²/4π²

I = 2.15 kg × 9.8 m/s² × 0.163 m × (2.133 s)²/4π²

I = 15.63/4π² kgm²

I = 0.396 kgm²

Now from the parallel axis theorem, I = I' + mh² where I' = moment of inertia of object with respect to its center of mass about an axis parallel to the pivot axis

I' = I - mh²

I' = 0.396 kgm² - 2.15 kg × (0.163 m)²

I' = 0.396 kgm² - 0.057 kgm²

I' = 0.339 kgm²

Answer:

178.6 m

Explanation:

Since the car moves in a circular path, it experiences a centripetal force, F = mv²/r where m = mass of car, v = speed of car = 35 m/s and r = radius of curvature of path.

Now, for the car not to skid, this centripetal force must be equal to the frictional force, F' acting in the opposite direction.

So, F' = μN where μ = coefficient of static friction(since the car does not move in this direction) and N = normal force = mg where m = mass of car and g = acceleration due to gravity = 9.8m/s²

F' = μmg

Since F = F'

mv²/r = μmg

dividing both sides by m, we have

v²/r = μg

multiplying both sides by r, we have

v² = μgr

dividing both sides by μg, we have

r = v²/μg

Here we use μ = coefficient of static friction(since the car does not move in this direction) = 0.70. Substituting the other variables into the equation, we have

r = v²/μg

r = (35 m/s)²/(0.70 × 9.8m/s²)  

r = 1225 m²/s²/6.86m/s²)  

r = 178.6 m

So, the minimum radius of curvature of the corner is 178.6 m

Answer:

0.13 m/s

Explanation:

Unfortunately, I don't have an explanation but I guessed the correct answer.

Answer:

the change in kinetic energy of the system is 0.577 J

Explanation:

Given;

mass of the bullet, m₁ = 6.25 g = 0.00625 kg

initial velocity of the bullet, u₁ = 365 m/s

mass of the crate, m₂ = 4.5 kg

initial velocity of the crate, u₂ = 0

distance moved by the system after collision, d = 0.15 m

Determine the final velocity of the system after collision;

m₁u₁ + m₂u₂ = v (m₁ + m₂)

0.00625 x 365 + 4.5 x 0 = v(0.00625 + 4.5)

2.2813 + 0 = v(4.5063)

2.2813 =  v(4.5063)

v = 2.2813 / 4.5063

v = 0.506 m/s

The change in kinetic energy of the system after collision is calculated as;

ΔK.E = ¹/₂ (m₁ + m₂)v²

ΔK.E =  ¹/₂ (4.506) x 0.506²

ΔK.E = 0.577 J

Therefore, the change in kinetic energy of the system is 0.577 J

Answer:

5m/s^2 is the acceleration.

Answer:

[tex]\boxed {\boxed {\sf a= 5 \ m/s^2}}[/tex]

Explanation:

Acceleration is the change in speed over time.

[tex]a=\frac{ v_f-v_i}{t}[/tex]

The object accelerates from 0 meters per second to 25 meters per second in 5 seconds.

[tex]v_f= 25 \ m/s\\v_i= 0 \ m/s \\t= 5 \ s[/tex]

Substitute the values into the formula.

[tex]a=\frac{ 25 \ m/s -0 m/s }{ 5 \ s}[/tex]

Solve the numerator.

[tex]a=\frac{25 \ m/s}{5 \ s}[/tex]

Divide

[tex]a= 5 \ m/s/s= 5 \ m/s^2[/tex]

The object's acceleration is 5 meters per square second.

Answer:

a)  x = 660 m, b)  λ = 0.330 m, c) Δλ = 0.1 cm, d)    Δf = 104

Explanation:

a) the distance in which the train of waves extends can be obtained from the uniform movement

             v = x / t

             x = v t

             x = 330 2

             x = 660 m

b) the speed of sound is related to the wavelength and frequency

             v = λ f

              λ = v / f

              λ = 330/1000

              λ = 0.330 m

c) The precision in the measurement of the wavelength refers to the error or uncertainty in the measurement, if the measurement is direct with a tape measure the precision is the appreciation of the tape measure, in general it is 0.1 cm

d) the accuracy of the frequency in general the frequency is calculated from the measurements of period T

                f = 1 / T

The precision of the period is data by the chronometer used, in general time a press of 0.01s, by the response time of the people

               Δf = df / dT    ΔT

               Δf = 1 / T² ΔT

                Δf = 1 / (0.001)² 0.01

                 Δf = 104

As we can see, a much more precise system is needed to reduce the error

Answer:

Canopus is more than 300 light years away from earth. This means it takes the light we see more than 300 years to reach us.

Answer:

Explanation:

Speed of electrical nerve signal = 33 m /s

Distance travelled = 1.3 m

time taken = distance / speed

= 1.3 / 33  

= .039 s

= 39 ms ( millisecond )  .

Answer:

land becomes unfit for food production

I think you need Graph to figure it out

Using Newton's second law and kinematic projectile motion we can find the proton deflection y = 5.43 10⁻⁷ m, in the opposite direction to the electron deflection.

given parameters

to find

For this exercise we will use Newton's second law where the force is electric

            F = ma

            F = q E

where F is the force, q the charge, E the electric field, m the mass and the acceleration of the particle

           q E = m a

           a = q / m E

This acceleration is the direction of the electric field that is perpendicular to the initial velocity (v_i)

Having the acceleration we can use the kinematics relations

If we make the direction of the initial velocity coincide with the x-axis

             v_i = cte

             v_i = x / t

             t = x/ v_i

on the y-axis is in the direction of the electric field

            y = v_{iy}  t + ½ a t²

on this axis the initial velocity is zero

            y = [tex]\frac{1}{2} (\frac{q}{m} E) \ t^2[/tex]

subtitute

            y =            (1)

Electron motion.

Let us propose the expression for the electron situation, the length of the displacement must be the same for electron and proton, suppose that it is x = L

In this case the charge q = -e and the mass m = m_e

its substitute in  equation 1

            y₁ = [tex]\frac{1}{2} \ ( \frac{-e}{m_e} E) \ \frac{x^2}{v_i^2}[/tex]  

where y₁, is the lectron deflection.

Proton motion

Between the proton and the electron we have some relationships

          q_p = -e

          m_ = 1840 m_e

we substitute in the equation  1

         y₂ = ½ e / 1840 me E x² / vi²

         y₂ =

         y₂ = - y₁ / 1840

         y₂ = - 0.001 / 1840

         y₂ = - 5.43 10⁻⁷ m

The negative sign indicates that the deflection of the proton is in the opposite direction to the deflection of the electron.

In conclusion they use Newton's second law and kinematics we can find the proton deflection is y = 5.43 10⁻⁷ m

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Answer:

It's A

Explanation:

sound waves are longitudinal they need a medium to travel through

Answer:

[tex]q_1=9.9998\mu C[/tex] and [tex]q_2=0.0002\mu C[/tex]

Or

[tex]q_1=0.00016\mu C[/tex] and [tex]q_2=9.99984\mu C[/tex]

Explanation:

We are given that

Force between two charges=0.036 N=[tex]36\times 10^{-3}N[/tex]

Distance between two charges, r=2cm=[tex]2\times 10^{-2}[/tex]m

1m=100cm

Sum of two charges=[tex]10\mu C[/tex]

Let one charge=[tex]q_1=q\mu C=q\times 10^{-6}C[/tex]

[tex]q_2=(10-q)\times 10^{-6} C[/tex]

We know that

Electric force between two charges

[tex]F=\frac{kq_1q_2}{r^2}[/tex]

Where [tex]k=\frac{1}{4\pi \epsilon_0}=9\times 10^{9}[/tex]

Using the formula

[tex]36\times 10^{-3}=9\times 10^{9}\times \frac{q\times 10^{-6}\times(10-q)\times 10^{-6}}{(2\times 10^{-2})^2}[/tex]

[tex]\frac{144\times 10^{-7}}{9\times 10^{9}\times 10^{-12}}=q(10-q)[/tex]

[tex]0.0016=10q-q^2[/tex]

[tex]q^2-10q+0.0016=0[/tex]

[tex]10000q^2-100000q+16=0[/tex]

[tex]q=\frac{100000\pm\sqrt{(100000)^2-4\times 10000\times 16}}{2\times 10000}[/tex]

Using the formula

[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

[tex]q=9.999[/tex] and [tex]q=0.00016[/tex]

[tex]q_2=10-9.9998=0.0002[/tex]

[tex]q_2=10-0.00016=9.99984[/tex]

Hence, two charges are

[tex]q_1=9.9998\mu C[/tex] and [tex]q_2=0.0002\mu C[/tex]

Or

[tex]q_1=0.00016\mu C[/tex] and [tex]q_2=9.99984\mu C[/tex]

Answer:B

Explanation:

C and O

Atoms of C and O pair of elements will form covalent bonds in a compound.Therefore the correct option is B.

The chemical compound is a combination of two or more  either similar or dissimilar chemical elements

for example, H₂O is a chemical compound made up of two oxygen atoms and a single hydrogen atom.

These chemical compounds are formed because of different types of bonds between the constituents elements ,the chemical bonds are mainly ionic bonds, covalent bonds,s, and hydrogen bonds.

Ionic bonds are formed due to the transfer of electrons between two bond forming pairs differentiated by their electronegativity.

Covalent bonds are formed by the sharing of electrons.Generally organic compound are formed as the reason of covalent bonds.

The carbon and oxygen atoms share their valence electrons to form a covalent bond, therefore the correct option is B.

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