Answer:
299.83°K
Explanation:
So, kelvin is a means of measuring temperature, as the question implies. To convert Celsius, one form of measuring temperature, to Kelvin, another form of measuring temperature, we must know the conversion median. Our median is that 0°C = 273.15°K. So, now, as we know that 0°C = 273.15°K, 26.68°C = 273.15°K + 26.68°. Because 273.15K might as well be zero degrees celsius (according to our median 0°C = 273.15°K), we simply add 26.68° to 273.15K and get 299.83°K
Please help !!!
Suppose there are 29.9 g of butane gas in a barbecue lighter. How many moles of butane gas is that ?
Arrange the following elements in order of decreasing atomic radius: Ba , Sn , Cl , Pb , Se .
Rank elements from largest to smallest.
Answer:
Ba, Pb, Sn, Se, Cl
Explanation:
The atomic radius increases when going right to left and top to bottom on the periodic table and decreases going the opposite way so I put it in order based on that.
2. Grapes, when tested with Benedict's reagent, gave brick red colour, whereas the iodine test didn't show any colour change.
A. What does the test results indicate about grapes?
B. Rice contains complex carbohydrates. If grapes are substituted with rice, what would be the test result?
Rice would not show any negative test with Benedicts solution but will show blue black color with iodine.
What is the Benedicts solution?The Benedicts solution is used to test for the presence of reducing sugars in a solution. The brick red color is a positive test for reducing sugars such as glucose.
Owing to the fact that grape does not have starch, it shows a negative test for starch. Rice would not show any negative test with Benedicts solution but will show blue black color with iodine.
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10. How many grams of CoCl₂ in 0.5 liters would be used to make a 1.0 molar solution? I
a. Predict the outcome if 0.5 liters of water is added to 0.5 liters of 0.70M solution of CuSO4
b. Describe what could happen is there is evaporation in the original 0.5 liters of 0.70M
solution of CuSO4
The weight of CoCl₂ used to make 0.5 ltr 1 Molar solution is 49.5g.
How to Calculate weight of substance ?The weight of a substance can be calculated by multiplying the number of moles of the substance by its molar mass.
However,
the number of moles of CoCl₂ must be calculated using the following formula:
no of moles = 0.5L × 1M
no of moles = 0.5moles
Molar mass of CoCl₂ = 99g/mol
mass of CoCl₂ = 0.5 × 99
mass of CoCl₂ = 49.5g
Hence, the weight of CoCl₂ used to make 0.5 ltr 1 Molar solution is 49.5g.
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7. What produces more severe burns, boiling water or steam?
Answer:
boiling water
Explanation:
boiling water produces more severe burns
Which of the following is non polar covalent bond?
electronegativities:
C = 2.5, H = 2.1, P = 2.1, Cl = 3.0, N = 3.0, O = 3.5
N -O
N-Cl
P-O
H-Cl
Answer:
N-Cl
Explanation:
Look at the chart below. Since N-Cl bond has a electronegativity difference of (3.0-3.0) zero, they are non-polar.
Which of the following is not a type of covalent bond?
A. Quadruple
B. Double
C. Polar
D. Non-polar
Answer:
Quadruple
Explanation:
Answer:
A
Explanation:
Here: Describe the non metal elements .What group number are non metals
Answer:
A nonmetal is a chemical element that generally lacks a predominance of metallic properties. Non-metals are mostly found in groups 5, 6 and 7. These non-metals will have 5, 6 or 7 electrons in the outer shell.
The outer shell of a non-metal is, therefore, more than half full of electrons.
How is the Sun classified?
as a giant star
as a medium star
as a white dwarf
as a neutron star
Answer:
B.) As a medium star
Explanation:
A.) is incorrect. It is not a giant star because there a millions are stars which are much more massive.
B.) is correct. Our Sun has a radius of about 437,000 miles. Technically our Sun is classified as a G-type main-sequence star, aka. yellow dwarf star. The Sun is generally classified as this type of star.
C.) is incorrect. While the Sun's light is similar to the light of white dwarf, it is still most certainly classified as a yellow dwarf star.
D.) is incorrect. Neutrons stars are collapsed, incredibly dense stars. They are around the size of a city.
Answer:
b
Explanation:
took the test
Given the chemical formulas of the following compounds, name each compound and state the rules you used to determine each name. KI, Fe2O3, (NH4)3PO4
Answer:
1.) KI
-------> potassium iodide
Potassium (K⁺) is a metal and iodine (I⁻) is a nonmetal. Therefore, when naming, there are no prefixes denoting how many of each element is in the compound. Because potassium is listed first in the compound, it must be the cation. Because iodine is listed second, it must be the anion. Anions in naming have their endings dropped and have the suffix -ide added.
2.) Fe₂O₃
-------> iron(III) oxide
Iron (Fe³⁺) is a metal and oxygen (O²⁻) is a nonmetal. Therefore, when naming, there are no prefixes denoting how many of each element is in the compound. Because iron is listed first, it is the cation and oxygen is the anion. Both of the elements have charges that do not balance each other (denoted by the subscripts). Because iron can have multiple different charges, the charge of iron (+3) should be listed when naming.
3.) (NH₄)₃PO₄
-------> ammonium phosphate
Ammonium (NH₄⁺) and phosphate (PO₄³⁻) are both polyatomic ions. When these ions bond, they also don't have quantity prefixes. Ammonium is the cation and phosphate is the anion. No roman numerals are necessary because the polyatomic ions always have a particular charge.
determine how many grams of N2 are produced from the reaction of 8.73
g of H2O2 and 5.16
g of N2H4.
Taking into account the reaction stoichiometry, 4.515 grams of N₂ can be produced from 8.73 grams of H₂O₂ and 5.16 grams of N₂H₄.
Reaction stoichiometryIn first place, the balanced reaction is:
N₂H₄ + 2 H₂O₂ → N₂ + 4 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
N₂H₄: 1 mole H₂O₂: 2 molesN₂: 1 mole H₂O: 4 molesThe molar mass of the compounds is:
N₂H₄: 32 g/moleH₂O₂: 34 g/moleN₂: 28 g/moleH₂O: 18 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
N₂H₄: 1 mole ×32 g/mole= 32 gramsH₂O₂: 2 moles ×34 g/mole= 34 gramsN₂: 1 mole ×28 g/mole= 28 gramsH₂O: 4 moles ×18 g/mole= 18 gramsLimiting reagentThe limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
Limiting reagent in this caseTo determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 34 grams of H₂O₂ reacts with 32 grams of N₂H₄, 8.73 grams of H₂O₂ reacts with how much mass of N₂H₄?
[tex]mass of N_{2} H_{4} =\frac{8.73 grams of H_{2} O_{2}x 32 grams of N_{2} H_{4} }{34grams of H_{2} O_{2}}[/tex]
mass of N₂H₄= 8.22 grams
But 8.22 grams of N₂H₄ are not available, 5.16 grams are available. Since you have less mass than you need to react with 8.73 grams of H₂O₂, N₂H₄ will be the limiting reagent.
Mass of N₂ formedConsidering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 32 grams of N₂H₄ form 28 grams of N₂, 5.16 grams of N₂H₄ form how much mass of N₂?
[tex]mass of N_{2} =\frac{5.16 grams of N_{2} H_{4} x28 grams of N_{2}}{32 grams of N_{2} H_{4} }[/tex]
mass of N₂= 4.515 grams
Then, 4.515 grams of N₂ can be produced from 8.73 grams of H₂O₂ and 5.16 grams of N₂H₄.
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Which of the following tool components is unlikely to present a hazard
Gloves is the tool component which will unlikely present a hazard in this scenario.
What is Hazard?
This is referred to as potential source of harm when performing various types of activities.
Gloves will unlikely cause harm as it is used to prevent the risk of electric shock when handling electrical devices which is why it is the most appropriate choice.
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NH3 is produced by the reaction of 0.450 moles of N2 and 0.600 moles of H2 according to the following equation: 2N2 + 3H2 ⟶ 2NH3. (a) How many moles of NH3 are produced? (b) What is the percent yield if 5.52g of NH3 is produced?
The moles of nitrogen produced is 0.40 moles of ammonia.
The Percent yield of ammonia is 81.2%
What moles of ammonia is produced?The moles of ammonia produced is obtained from the mole ratio of the reaction.
The mole ratio of hydrogen to nitrogen is 3 : 2
Based on the mole ratio, the limiting reactant is hydrogen.
Moles of nitrogen produced = 0.600 * 2/3 = 0.40 moles of ammonia.
mass of ammonia expected = 0.4 * 17 g = 6.8 g
Percent yield = 5.52/6.8 * 100% = 81.2%
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An atom of elements x has one more shell of electrons than an atom of beryllium,but h are s one less valence electron then beryllium.which element is element X?
Element X is sodium.
If there is one more shell of electrons, then this means it is one period below.
Since there is one less valence electron, it is one group to the left.
▸ Exam Instructions
Question 15 of 20:
Select the best answer for the question.
15. Why can over-the-counter medications be sold to consumers without the need for a prescription?
A. They're found to give benefits to all people, regardless of whether a patient is ill or not.
B. They're all covered by insurance companies and therefore a prescription isn't necessary.
C. They're safe to use without the regulation of a physician, according to a regulatory agency.
D. They're considered the most important and consumers are encouraged to keep stock of certain types at home.
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Question 5 of 30
Which best describes a gamma ray that is given off during nuclear decay?
A. High-energy electromagnetic waves
B. A stream of small, positively charged particles
C. Low-energy electromagnetic waves
D. A stream of small, negatively charged particles
Gamma rays are high-energy electromagnetic waves given off during nuclear decay; option A.
What are electromagnetic waves?Electromagnetic waves are waves which are produced as a result of the interaction of the magnetic and electric fields.
Types of electromagnetic waves include gamma rays, radio waves, ultraviolet waves.
Gamma rays are high-energy electromagnetic waves given off during nuclear decay
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Pure water boils at 100°C.
What happens to the water particles when water
boils?
A They gain energy and move further apart.
B They gain energy and stay close together.
C They lose energy and move further apart.
D They lose energy and stay close together.
Answer:
A
Explanation:
A vessel with a volume of 25.1 L contains 2.80 g of nitrogen gas, 0.605 g of hydrogen gas, and 79.9 g of argon gas. At
25°C, what is the pressure in the vessel?
Select one:
a. 58.7 atm
b. 2.73 atm
c. 0.196 atm
d. 81.0 atm
e. 2.34 atm
2.73 atm is the pressure in the vessel. Hence, option B is correct.
What is an ideal gas equation?The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.
Given data:
P= ?
V= 25.1 L
[tex]n= \frac{m}{molar \;mass \;of \;nitrogen} + \frac{m}{molar \;mass \;of \;hydrogen } +\frac{m}{molar \;mass \;of \;argon}[/tex]
[tex]n= \frac{2.80 g}{14} + \frac{0.605 g}{1} +\frac{79.9 g}{40}[/tex]
n= 2.8025
R= [tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]
T=25°C + 273= 298 K
Putting value in the given equation:
[tex]\frac{PV}{RT}=n[/tex]
[tex]2.8025 = \frac{P\; X \;25.1 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}[/tex]
P = 2.73 atm
2.73 atm is the pressure in the vessel. Hence, option B is correct.
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The properties of an element depend on the electron structure within its atoms. The electrons are arranged in different
orbitals, at different energy levels and sublevels. Match each sublevel to the maximum number of electrons it can
accommodate?
The electrons are arranged in different orbitals, at different energy levels and sublevels.
What are Orbitals ?An atomic orbital is a function describing the location and wave-like behavior of an electron in an atom.
This function can be used to calculate the probability of finding any electron of an atom in any specific region around the atom's nucleus.
Following are the sublevel with the maximum number of electrons that can be accommodated by it ;
2 Electrons : S-SubshellTherefore, S-Subshell has 2 electrons, P-subshell has 3 electrons, d-subshell has 10 electrons and f-subshell has 14 electrons.
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PLEASE HELP ASAP!!!!!!!!!!!!
In the scientific sense the two examples of people doing work is: A and D
Meaning of WorkWork can be defined as a result of applying force to a particular object that changes its displacement in the direction of the applied force.
Work can only be done when their is a force that is being applied and a displacement that occurs.
In conclusion, In the scientific sense the two examples of people doing work is: A and D
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The heat of fusion of water is 79.9cal/g, the heat of vaporization of water is 540cal/g, and the specific heat of water is 1.00cal/deg/g. How much ice at 0 celsius could be converted to steam at 100 celsius by 9522cal of heat?
The amount of ice converted into steam is 13.23 gram.
What is Heat of Vaporisation ?Heat of Vaporisation is the amount of heat required to convert 1 gm to liquid at its boiling point to vapour.
Let x gram of ice is there
At first x gm of ice will melt
The heat required is x * Heat of fusion = x * 79.9 = 79.9x
Then the heat required to rise the temperature of x gm of water from 0 degree to 100 degree Celsius .
= mc ΔT
= x * 1 * 100 = 100x
The heat required to convert x gm of liquid into x gm of steam
= x * 540 = 540x
The total heat supplied is 9522 cal
79.9x + 100x + 540x = 9522
719.9 x = 9522
x = 13.23 gm
The amount of ice converted into steam is 13.23 gram.
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Calcular la normalidad de 1 Kg de sulfuro de aluminio en 5000 ml de solucion.
Calculate the normality of 1 Kg of aluminum sulfide in 5000 ml of solution.
Normality comes out to be 8.11
Given Mass of solute: 1000gVolume of solution (V): 5000 ml = 5 liters Equivalent mass of solute (E) = molar mass / n-factorn-factor for [tex]Al_{2}S_{3}[/tex] is 6 and molar mass is 148g
So, on calculating equivalent mass is equal to 24.66g
FORMULAE of Normality (N) = (Mass of the solute) / (Equivalent mass of the solute (E) × Volume of the solution (V)
N=[tex]\frac{1000}{24.66*5}[/tex]
N=8.11
Therefore, normality of 1 kg aluminum sulfide is 8.11
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Al + 0₂ → Al₂O3 help
Answer:
4Al +3O₂ → 2Al₂O₃
Explanation:
To balance the chemical equation, start by identifying the number of atoms of each element on both sides of the equation.
Al +O₂ → Al₂O₃
Reactants (right-hand side of the arrow)
Al➭ 1
O➭ 2
Products (left-hand side of the arrow)
Al➭ 2
O➭ 3
Balancing the equation means that we need to ensure the number of atoms of each element is the same on both sides of the equation.
Let's balance the number of O atoms.
Al +3O₂ → 2Al₂O₃
Reactants
Al➭ 1
O➭ 3(2)= 6
Products
Al➭ 2(2)= 4
O➭ 2(3)= 6
Balancing the number of Al atoms:
4Al +3O₂ → 2Al₂O₃
Reactants
Al➭ 4
O➭ 6
Products
Al➭ 4
O➭ 6
The equation is now balanced.
Additional:
For a similar question on balancing equations, do check out the following!
https://brainly.com/question/14072552A cup of water is warmed from 29 °C to 97 °C. What is the difference between these two temperatures, in kelvins
Answer:
I believe it is 68
Explanation:
to convert Celsius to kelvins you must add it to 273.15 for example 29 + 273.15 is 302.15
im so very sorry if im wrong.
5. In an oxyacetylene welding torch, acetylene (C2H2) burns in pure oxygen with a very hot flame. The reaction is: 2 C2H2 + 5 O2 → 4 CO2 + 2 H2O.
a. What is the mass of C2H2 that is consumed if 35.0 grams of oxygen is allowed to react?
b. How many milliliters of water will be produced when the 35.0 grams of oxygen from part a. above is allowed to react. The density of water is 1.0 gram
Answer:
[tex]a. \ \ \ \text{The mass of ethylene is 11.375 g}. \\ \\ b. \ \ \ \text{The volume of water produced is 7.875 ml}.[/tex]
Explanation:
a. According to the chemical equation for the combustion of ethylene, 5
moles of oxygen are required to react with 2 moles of ethylene, hence
[tex]m_{C_{2}H_{2}} \ = \ 35 \ \text{g} \ \times \ \displaystyle\frac{1 \ \text{mol}}{\left(2 \times 16 \right) \text{g}} \ \times \ \displaystyle\frac{2 \ \text{mol}}{5 \ \text{mol}} \ \times \ \displaystyle\frac{\left(12 \ \times \ 2 \ + \ 1 \ \times \ 2 \right) \ \text{g}}{1 \ \text{mol}} \\ \\ m_{C_{2}H_{2}} \ = \ 11.375 \ \text{g}[/tex]
b. Similarly, 5 moles of oxygen are required as a reactant to produce 2
moles of water, thus
[tex]m_{H_{2}O} \ = \ 35 \ \text{g} \ \times \ \displaystyle\frac{1 \ \text{mol}}{\left(2 \times 16 \right) \text{g}} \ \times \ \displaystyle\frac{2 \ \text{mol}}{5 \ \text{mol}} \ \times \ \displaystyle\frac{\left(1 \ \times \ 2 \ + \ 16 \right) \ \text{g}}{1 \ \text{mol}} \\ \\ m_{H_{2}O} \ = \ 7.875 \ \text{g}[/tex]
Given that the density of water is [tex]1.0 \ \text{g ml}^{-1}[/tex], therefore
[tex]\rho_{H_{2}O} \ = \ \displaystyle\frac{m_{H_{2}O}}{V_{H_{2}O}} \\ \\ V_{H_{2}O} \ = \ \displaystyle\frac{m_{H_{2}O}}{\rho_{H_{2}O}} \\ \\ V_{H_{2}O} \ = \ \displaystyle\frac{7.875 \ \text{g}}{1.0 \ \text{g ml}^{-1}} \\ \\ V_{H_{2}O} \ = \ 7.875 \ \text{ml}[/tex]
11.375 g ethylene is consumed if 35.0 grams of oxygen is allowed to react and 7.875 ml of water will be produced when the 35.0 grams of oxygen is allowed to react.
What are moles?A mole is defined as 6.02214076 ×[tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
According to the chemical equation for the combustion of ethylene, 5
moles of oxygen are required to react with 2 moles of ethylene, hence
[tex]m_{_C_2_H_2}[/tex] [tex]= 35gX \frac{1 mol}{(2 \;X\; 16)g } X \frac{2 mol}{(5\;mol )} X \frac{26g}{1 mol }[/tex]
[tex]m_{_C_2_H_2} = 11.375 g[/tex]
Similarly, 5 moles of oxygen are required as a reactant to produce 2 moles of water, thus
[tex]m_{_H_2_O} = 35gX \frac{1 mol}{(2 \;X\; 16)g } X \frac{2 mol}{(5\;mol )} X \frac{18g}{1 mol }[/tex]
[tex]m_{_H_2_O} = 7.875 g[/tex]
Given that the density of water is [tex]1.0g ml^{-1}[/tex], therefore
[tex]Density = \frac{Mass \;of \;water}{Volume \;of \;water}[/tex]
[tex]Volume \;of \;water = \frac{7.875}{1.0 g ml^{-1}}[/tex]
The volume of water = 7.875 ml
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Read the given equation.
2Na+ 2H₂O 2NaOH + H₂
During a laboratory experiment, a certain quantity of sodium metal reacted with water to produce sodium hydroxide and hydrogen gas. What was the initial quantity of
sodium metal used if 7.80 liters of H₂ gas were produced at STP?
07:29 grams
09.30 grams
12.2 grams
16.0 grams
equivalent weight of cacl2
Answer:
55 grams
Explanation:
55 grams of calcium chloride is the equivalent weigh because 55 grams of calcium chloride would supply one mole of positive or negative charges when dissolved in water.
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draw a diagram to show how you will separate the salt from sugar using the solvent ethanol
If 381 mL of 9.96 M LiCl is diluted with water to make 750 mL of solution calculate the molarity of the new solution.
Answer:
5.06 M LiCl
Explanation:
To find the new molarity of the solution, you need to (1) find the amount of moles LiCl (via the molarity equation using the original molarity and volume) and then (2) calculate the new molarity (via the molarity equation using the new volume and old moles). The final answer should have 3 sig figs to match the given values.
Molarity (M) = moles / volume (L)
Step (1)
381 mL / 1,000 = 0.381 L
Molarity = moles / volume
9.96 M = moles / 0.381 L
(9.96 M) x (0.381 L) = moles
3.79 = moles
Step (2)
750 mL / 1,000 = 0.750 L
Molarity = moles / volume
Molarity = 3.79 moles / 0.750 L
Molarity = 5.06 M
Which of the following sets of descriptors matches the molecule below?
Image of two hydrogen atoms bonded to one oxygen atom to form H2O, or water.
A. Simple structure, molecule, single bonds, two elements
B. One element, triple bond, molecule, diatomic
C. Giant structure, single bond, compound, one element
D. Compound, allotrope, double bond, giant structure
Answer: A. Simple structure, molecule, single bonds, two elements
