When magma goes down into the lower part of the mantie where it is recycled and may come right back up the ocean ridge is called..

Answer:

A. The reaction proceeds in the forward and reverse directions at the same rate.

B. Both the forward and the reverse reactions are achievable.

D. There is no net change in concentrations of reactants and products.

Explanation:

Chemical equilibrium can be defined as the state of a reversible reaction in which the concentration (rate) of the forward reaction is equal to the concentration (rate) of the backward or reverse reaction. Thus, both the reactants and products of the chemical equation don't have the tendency to change with respect to time.

Hence, the options that are true of chemical equilibria include the following;

I. The reaction moves in both forward and reverse directions simultaneously i.e at the same rate.

II. The chemical equation can attain both forward and reverse reactions.

III. The concentrations of both reactants and products are the same i.e there's no net change.

Answer:

A B D knewton

Explanation:

Answer:

relating to or denoting the business of entertaining clients, conference delegates, or other official visitors.

Answer:

This is because .It doesn't reacts with dilute acid .It is a coinage metal.

C

Tarnishing of silver is caused by hydrogen sulfide and other sulfur containing compounds in the air reacting to the silver and resulting in a fine layer of silver sulfide. The other answers don't make sense

Answer:

1. The balanced chemical reaction is:

[tex]HNO_3(aq)+NaOH(aq)\rightarrow NaNO_3(aq)+H_2O(l)[/tex]

2. The balanced chemical reaction is:

[tex]2HI(aq)+Sr(OH)_2(aq)\rightarrow SrI_2(aq)+2H_2O(l)[/tex]

Explanation:

Hello there!

In this case, according to the given chemical reactions, it is necessary to keep in mind the cations and anions are switched around as a result of the bonds rearrangement in these neutralization reactions; therefore, we can proceed as follows:

1. The balanced chemical reaction is:

[tex]HNO_3(aq)+NaOH(aq)\rightarrow NaNO_3(aq)+H_2O(l)[/tex]

Because all atoms are in the same amount at each side of the equation and the resulting salt is soluble.

2. The balanced chemical reaction is:

[tex]2HI(aq)+Sr(OH)_2(aq)\rightarrow SrI_2(aq)+2H_2O(l)[/tex]

Because all atoms are in the same amount at each side of the equation and the resulting salt is soluble.

Best regards!

Answer:

1.25×10²⁵ molecules of ethane contains 124.56 moles of Hydrogen atoms.

Answer:

A reduction potential measures the tendency of a molecule to be reduced by taking up new electrons. ... Standard reduction potentials can be useful in determining the directionality of a reaction. The reduction potential of a given species can be considered to be the negative of the oxidation potential.

Explanation:

Answer:

D

Explanation:

Answer:

Velocity

Explanation:

Synonyms are words/phrases that mean the exact or nearly exact same in meaning. Velocity, pace, and speed all mean close to the same thing as far as the rate in which something is moving.

Answer:

1.00 moles of CO2 is the final yield.

Explanation:

Based on the reaction:

2C2H2(g)+ 5O2(g) → 4CO2(g) + 2H2O(g)

When 2 moles of acetylene (C2H2) completely reacts with oxygen, 4 moles of CO2 are produced.

To solve this question we must use the chemical equation knowing: 2 moles C2H2 = 4 mol CO2

When 0.500 moles of acetylene react:

0.500 moles C2H2 * (4mol CO2 / 2mol C2H2) =

There is an increase in entropy because the energetically equivalent ways to arrange the components of the  system increased. Option A and C.

The term entropy refers to the degree of disorder in a system. Thus we know that any change that leads to an increase in the number of particles will lead to an increase in entropy.

Hence, we can see from the diagram that the energetically equivalent ways to arrange the components of the  system increased hence there is a positive increase in entropy. The correct options are therefore A and C.

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Answer:

2.75 × 10⁻⁶ M/s

1.69 × 10⁻⁶ M/s

9.23 × 10⁻⁻⁷ M/s

4.43 × 10⁻⁻⁷ M/s

2.1 × 10⁻⁻⁷ M/s

Explanation:

We have the following information for the isomerization of methyl isonitrile

Time (s)      [CH₃NC] (M)

  0              0.0165

2000          0.0110

5000          0.00591

8000          0.00314

12000         0.00137

15000         0.00074

To calculate the average rate of reaction (r) for each interval, we need to use the following expression:

r = -Δ[CH₃NC]/Δt

Interval 0-2000 s

r = - (0.0110 M-0.0165 M)/2000 s - 0 s = 2.75 × 10⁻⁶ M/s

Interval 2000-5000 s

r = - (0.00591 M-0.0110 M)/5000 s - 2000 s = 1.69 × 10⁻⁶ M/s

Interval 5000-8000 s

r = - (0.00314 M-0.00591 M)/8000 s - 5000 s = 9.23 × 10⁻⁻⁷ M/s

Interval 8000-12000 s

r = - (0.00137 M - 0.00314 M)/12000 s - 8000 s = 4.43 × 10⁻⁻⁷ M/s

Interval 12000-15000 s

r = - (0.00074 M - 0.00137 M)/15000 s - 12000 s = 2.1 × 10⁻⁻⁷ M/s

The average rates of reactions for the time interval between each measurement are

2.75×10⁻⁶ M/s

1.70×10⁻⁶ M/s

9.23×10⁻⁷ M/s

4.43×10⁻⁷ M/s

2.10×10⁻⁷ M/s

From the question,

We are to calculate the average rate of reaction for each of the measurement.

First, we will create a proper table for the data

Time (s)       [CH3NC] (M)

0                    0.0165    

2,000            0.0110

5,000            0.00591      

8,000            0.00314      

12,000          0.00137

15,000          0.00074

The average rate of reaction is given by the formula

[tex]Average\ rate\ of\ reaction = \frac{Final\ concentration - Initial\ concentration}{Final\ time - Initial\ time}[/tex]

1.

[tex]Average\ rate\ of\ reaction = \frac{0.0110-0.0165}{2000 -0 }[/tex]

Average rate of reaction = 2.75×10⁻⁶ M/s

2.

[tex]Average\ rate\ of\ reaction = \frac{0.00591-0.0110}{5000 -2000 }[/tex]

Average rate of reaction = 1.70×10⁻⁶ M/s

3.

[tex]Average\ rate\ of\ reaction = \frac{0.00314-0.00591}{8000 -5000 }[/tex]

Average rate of reaction = 9.23×10⁻⁷ M/s

4.

[tex]Average\ rate\ of\ reaction = \frac{0.00137-0.00314}{12000 -8000 }[/tex]

Average rate of reaction = 4.43×10⁻⁷ M/s

5.

[tex]Average\ rate\ of\ reaction = \frac{0.00074-0.00137}{15000 -12000 }[/tex]

Average rate of reaction = 2.10×10⁻⁷ M/s

Hence, the average rates of reactions for the time interval between each measurement are

2.75×10⁻⁶ M/s

1.70×10⁻⁶ M/s

9.23×10⁻⁷ M/s

4.43×10⁻⁷ M/s

2.10×10⁻⁷ M/s

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Answer:

The ratio of the mass of a substance to its volume is called...density.

Explanation:

T=?

Given

n=3.33×10³

V=478mL=4.78L

P=750torr= 0.987 Atm

simply use the formula

PV =nRT

where R is universal gas constant

0.987×4.78= 3.33×10³×8.314×T

T = 0.000170°c

T= 273.15 K!

The absolute temperature of the gas at which 3.33x10³ mol occupies 478 mL at 750 torr is 1.726 × 10-³K

HOW TO CALCULATE TEMPERATURE:

PV = nRT

Where;

According to this question,

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Explanation:

The two main categories of energy are potential energy (stored

energy) and kinetic energy (energy presently doing

work or causing change)...I hope this helps.

The molarity of a solution containing 20moles of NaCl dissolved in 10 liters of water is 2 mol/L.

Molarity of any solution will be calculated by using the below formula:
M = n/V, where

n = moles of solute = 20 mol

V = volume of solution or solvent = 10 L

On putting values on above equation, we get

M = 20 / 10 = 2M

Hence required molarity of NaCl is 2 M.

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Answer:

3.089 L

Explanation:

From the given information, provided that the no of moles and the temperature remains constant;

[tex]P_1[/tex] = 15.6 psi

[tex]V_1[/tex] = ???

[tex]P_2[/tex] = 25.43 psi

[tex]V_2[/tex] = 1.895 L

Using Boyle's law:

[tex]P_1V_1 =P_2V_2 \\ \\ V_1 = \dfrac{P_2V_2}{P_1} \\ \\ V_1 = \dfrac{25.43 \times 1.895}{15.6} \\ \\ \mathbf{ V_1 = 3.089 \ L}[/tex]

Answer:D

Explanation:

I think the answer is C. (Increasing the number of variables in the experiment)

Answer:

ITS B

Explanation:

THE OTHER GUY WAS WRONG

Answer: a

Explanation:

this is common sense

Answer:

C'est fini sous la lettre A. Ice crystals from forming inside it's body

Answer:

0.559 L

Explanation:

Step 1: Given data

Moles of sodium iodide (n): 0.405 mol

Molar concentration of sodium iodide (M): 0.724 M (0.724 mol/L)

Step 2: Calculate the volume of solution (V)

The molarity is equal to the moles of solute divided by the liters of solution.

M = n/V  

V = n/M  

V = 0.405 mol/(0.724 mol/L) = 0.559 L

(hope this helps can i plz have brainlist :D hehe)

The mass of the kool aid needed to prepare the solution is 81.2 g.

The term concentration has to do with the amount of substance present in solution. We are told to make calculations regarding the preparation of a 237.5 ml kool-aid solution with a concentration of 1M.

Litres of water needed = 237.5/1000 = 0.2375 L

Molarity of kool-aid needed = 1 M

number of moles = 1 M *  0.2375 L = 0.2375 moles

0.2375 moles = mass of kool aid/molar mass

0.2375 moles = mass/ 342 g/mol

mass = 0.2375 moles * 342 g/mol

mass = 81.2 g

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Answer:

water pollution is a process in which water gets polluted due to discharge of city sewage and industrial waste. I was suffering through the water born disease when I drank the contaminated water. The sources of water becomes dirty. It makes environment unbalanced. People suffer from different water born disease when they drink polluted water.

Answer:

Universal indicator can show us how strongly acidic or alkaline a solution is, not just that the solution is acidic or alkaline. This is measured using the pH scale , which runs from pH 0 to pH 14.

Explanation:

~Hope this helps

Answer:

during interphase the cells start to grow

cells grow, store up energy, and take in nutrients

hope it helped :)

Answer:

No, alloys are independent of the amount of it's constituents.

Alloys depend on the number of it's constituents.

Only strength of alloys depends on the specific amount of ingredients/constituents/elements.

Answer:

see calculations below

Explanation:

Given:     HOAc     ⇄    [H⁺]     +    [OAc⁻]            

C(i)          0.12M             0M           0.15M

mix  => 5.55ml(0.092M NaOH) / (50ml + 5.55ml)

            = 0.00555(0.092)mole NaOH / 0.0555 L Soln

            = 0.0092M in NaOH is added into the initial buffer solution

            = 0.0092M in OH⁻ (NaOH is a strong base => 100% ionized)

Rxn => Addition of 0.0092M OH⁻ will react with 0.0092M H⁺ shifting buffer            .           equilibrium to the right decreasing [HOAc] and increasing [OAc⁻] by    .           0.0092M each.

Therfore ...

Given:           HOAc      ⇄    [H⁺]     +       [OAc⁻]            

C(i)                0.12M             0M               0.15M

ΔC           - 0.0092M           +x            +0.0092M

C(f)             0.1108M             x                0.1592M  =>  New Concentrations            .                                                                                     after adding 0.0092M             .                                                                                     NaOH

Substituting new acid and ion concentrations into Ka expression ...

Ka = [H⁺][OAc⁻]/[HOAc] = (x)(0.1592M)/(0.1108M) = 1.75 x 10⁻⁵M

=> x = [H⁺](new) = (1.75 x 10⁻⁵M*)(0.1108M)/(0.1592M) = 1.22 x 10⁻⁵M in H⁺ ions

*units of Ka are Molar

FYI => Adding a strong base to a buffer solution will shift pH to more basic.

          Adding a strong acid   to a buffer solution will shift pH to more acidic.

=> (such is a good way to check that your buffer calculations are correct.)

NOTE => Question asks for moles of HOAc, Na⁺OAc⁻ & NaOH after adding base. Giving answers in terms of Molarity (moles/Liter) is same as moles. Therefore ...

[HOAc] = 0.1108M

[NaOAc] = 0.1592M

[NaOH] = ∅M (from rxn of H⁺ + OH⁻ => H₂O, all NaOH was consumed in acid/base reaction.  Remaining are only Na⁺ as a spectator ion and OH⁻ as a function of the new concentration of H⁺ => [OH⁻] = Kw/[H⁺] = 1 x 10⁻¹⁴/1.22 x 10⁻⁵ = 8.2 x 10⁻¹⁰M.

Hope this helps. :-)

Answer:

1.32 moles.

Explanation:

From the question given above, the following data were obtained:

Density of Al = 2.70 g/cm³

Volume of Al = 13.2 cm³

Number of mole of Al =.?

Next, we shall determine the mass of Al.

This can be obtained as follow:

Density of Al = 2.70 g/cm³

Volume of Al = 13.2 cm³

Mass of Al =?

Density = mass / volume

2.7 = mass of Al / 13.2

Cross multiply

Mass of Al = 2.7 × 13.2

Mass of Al = 35.64 g

Finally, we shall determine the number of mole of Al. This can be obtained as follow:

Mass of Al = 35.64 g

Molar mass of Al = 27 g/mol

Number of mole of Al =?

Mole = mass / molar mass

Number of mole of Al = 35.64 / 27

Number of mole of Al = 1.32 moles

Thus, 1.32 moles of aluminum are present in the block of the metal.

Answer:

acceleration

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