When a spring is compressed, the energy changes from kinetic to potential. Which best describes what is causing this change?

•work
•power
•gravitational energy
•chemical energy​

Answers

Answer 1

Answer:

work

Explanation:

Answer 2

Answer:

A

Explanation:


Related Questions

A 2.0 cm thick brass plate (k_r = 105 W/K-m) is sealed to a glass sheet (kg = 0.80 W/K m), and both have the same area. The exposed face of the brass plate is at 80°C, while the exposed face of the glass is at 20 °C. How thick is the glass if the glass brass interface is at 65 C? Ans. 0.46 mm​

Answers

I need a good phisics teacher for one day online please123


A large bottle contains number medical tablets each having a mass of 250
mg.The mass of all tablets is 1kg.Calculate the number of tablets in the
bottle.​

Answers

First of all, this isn't physics. But, here's the answer:

1 gram is a 1000 milligram and 250 milligram is 250 * 0.001 g which is 0.25 gram.

Since 1 kg is 1000 g, we divide 1000 by 0.25 and we get 1000 * 4 which is 4000.

There are [tex]4000[/tex] tablets inside the bottle.

What famous equation describes the energy of stars?

Answers

Answer:

E=mc2

Explanation:

It explains that in their interiors, atoms fuse together, creating energy.

To solve this we must be knowing each and every concept related to energy and its different types. Therefore, the famous equation that describes the energy of stars is E=mc².

What is energy?

In physics, energy is the capacity to accomplish work. It can be potential, kinetic, thermal, electric, chemical, radioactive, or in other forms.

There is also heat and work—energy inside the process of being transferred by one body to the other. Energy is always classified according to its type once it has been transmitted. As a result, heat transported could become thermal energy, whereas labor done may emerge as mechanical energy. The famous equation that describes the energy of stars is E=mc²

Therefore, the famous equation that describes the energy of stars is E=mc².

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What is the deBroglie wavelength of an electron moving at 1.37 x 106 m/s if the mass of the electron is 9.11 x 10-28 g

Answers

Answer:

The value  is  [tex]\lambda = 5.30 *10^{-10 } \ m[/tex]

Explanation:

From the question we are told that

    The velocity of the electron is  [tex]v = 1.37 *10^{6} \ m/s[/tex]

    The mass of the electron is  [tex]m = 9.11 *10^{-28} \ g = 9.11 *10^{-31} \ kg[/tex]

Generally the  deBroglie wavelength  is mathematically represented as

       [tex]\lambda = \frac{h}{mv}[/tex]

Here h is the Planck'c constant with value  [tex]h = 6.62607015 * 10^{-34} J \cdot s[/tex]

So

      [tex]\lambda = \frac{6.62607015 * 10^{-34} }{9.11 *10^{-31} * 1.37 *10^{6}}[/tex]

=>   [tex]\lambda = 5.30 *10^{-10 } \ m[/tex]

who plays adopt me on rob.lox!! plz answer people only if you play though tell me your best pet and your user name so we can play!!

Answers

Answer: I don't  do   adopt me   but I do have a Ro.blox username its  Nvm i cant but my user name

Explanation:

Answer:

adopt me sucks but my best pet was an albino monkey I think or a king monkey

Explanation:

uses of atmospheric pressure​

Answers

Atmospheric pressure is an indicator of weather. When a low-pressure system moves into an area, it usually leads to cloudiness, wind, and precipitation.

a plank rests on two supports that exert upward forces of 14N and 18N. find the weight of the plank.

Answers

Answer:

32

Explanation:

Up forces and Down forces must be equal if the object is balanced

For this question

down force is weight of the plank

up forces is 14 and 18

14+18=Weight of plank

A heavy storm leaves 1 cm of rain on a city 5 km wide and 8 km long on a 2 hour period. How many cm3 of water fell on the city?

Answers

Answer: wow that’s hard

Explanation:

Running with an initial velocity of 13 m/s , a horse has an average acceleration of -1.88 m/s2 . How long does it take for the horse to decrease its velocity to 6.3 m/s

pls :/

Answers

Answer:

3.56s

Explanation:

Ya that's the right answer.

An amateur golfer swings a golf club, striking a golf ball that has a mass of 55.0 g. The club is in contact with the ball for only 0.00360 s. After the collision, the ball leaves the club at a speed of 34.0 m/s. What is the magnitude of the average force (in N) exerted on the ball by the club?

Answers

Answer:

The average force ≅ 519.44 N.

Explanation:

Impulse = change in momentum of a body

i.e Ft = m(v - u)

where F is the force, t is the time, m is the mass of the body, v is the final velocity and u is the initial velocity.

m = 55.0 g (0.055 Kg), t = 0.00360 s, v = 34.0 m/s, since the ball was initially at rest; u = 0 m/s

So that,

F x 0.00360 = 0.055(34 - 0)

F x 0.00360 = 0.055 x 34

                    = 1.87

F = [tex]\frac{1.87}{0.0036}[/tex]

 = 519.4444

The average force exerted on the ball by the club is approximately 519.44 N.

Next 100 points if u answer this

Answers

Answer: When frequency increases more wave crests pass a fixed point each second. That means the wavelength shortens. So, as frequency increases, wavelength decreases. The opposite is also true—as frequency decreases, wavelength increases.

The frequency and wavelength of a wave are related. When frequency increases more wave crests pass a fixed point each second. ... So, as frequency increases, wavelength decreases. The opposite is also true—as frequency decreases, wavelength increases.

uncountable the number of times that something happens during a period of time. frequency of: Changes in sea temperature will increase the frequency of hurricanes. with increasing frequency (=more often): Accidents occur here with increasing frequency.

Explanation:

HELP ASAP!!
The table below lists protected constitutional rights and how they may be limited.

Protected Rights Limitations
Property rights ?
Unwarranted search and seizure Crime suspects may be searched
Which phrase completes the table? (3 points)

Group of answer choices

Poll taxes

Eminent domain

Jury trial

Background checks

Answers

Answer:

jury trial

Explanation:

rights to a fair trial by jury, or the whole innocent until proven guilty ya know

Please help me with this question guys.

Answers

Answer:

The average speed is 22.2 km/h

Explanation:

Average Speed

Given an object travels a total distance d and took a total time t, then the average speed is:

[tex]\displaystyle \bar v=\frac{d}{t}[/tex]

The mailman first drives d1=7 km at v1=15 km/h. The time taken to drive is:

[tex]\displaystyle t1=\frac{d1}{v1}=\frac{7}{15}=0.467\ h[/tex]

Then he drives d2=7 km at v2=43 km/h taking a time of:

[tex]\displaystyle t2=\frac{d2}{v2}=\frac{7}{43}=0.163\ h[/tex]

The total time is

t=0.467 h + 0.163 h = 0.63 h

The total distance is

d = 7 km + 7 km = 14 km

The average speed is:

[tex]\displaystyle \bar v=\frac{14}{0.63}=22.2\ km/h[/tex]

The average speed is 22.2 km/h

The second-order dark fringe in a single-slit diffraction pattern is 1.40 mm from the center of the central maximum. Assuming the screen is 89.0 cm from a slit of width 0.710 mm and assuming monochromatic incident light, calculate the wavelength of the incident light.

Answers

We know, for single slit :

[tex]y =\dfrac{ n\lambda L}{a}\\\\\lambda = \dfrac{ya}{nL}[/tex]       ...1)

[tex]y = 1.4\ mm = 1.4 \times 10^{-3}\ m[/tex]

n = 2

L = 89 cm = 0.89 m

[tex]a=7.1\times 10^{-4}\ m[/tex]

Putting all these in equation 1), we get :

[tex]\lambda = \dfrac{ya}{nL}\\\\\lambda = \dfrac{1.4\times 10^{-3}\times 7.1\times 10^{-4}}{2\times 0.89 }\\\\\lambda = 5.584 \times 10^{-7}\ m[/tex]

Therefore, wavelength of the incident light is [tex]5.584 \times 10^{-7}\ m[/tex] or 558.4 nm.

Hence, this is the required solution.

Form hypothesis: Compare the floating objects, then do the same for the sinking objects. A. What do the floating objects have in common

Answers

Answer:

Explanation:

This question is incomplete. However, it should be noted that for an object to float in a liquid, the density of the object must be less dense than the liquid. This causes the weight force of the object to be balanced by the upthrust force of the liquid. Thus, when the object is more dense than the liquid, the object sinks.

One thing the floating objects will have in common is that they are less dense than the liquid in which they are floating.

NOTE that the floating of an object can be dependent on size and shape (which affects the upthrust force) also.

HELP!!! An object accelerates from rest to 85 m/s over a distance of 36 m. What acceleration did it
experience?

Answers

Answer:

Explanation:

Given:-

Initial velocity (u) = 0m/s

Final velocity (v) = 85m/s

Distance covered (s) = 36m

To Find:-

Acceleration of the object (a)

Solution:-

By using 3rd equation of motion

→ v² = u² +2as

Substitute the value we get

→ 85² = 0² +2×a×36

→ 7225 = 0 + 72 ×a

→ a = 7225/72

→ a = 100.34m/s²

∴ The acceleration of the object is 100.34m/s²

Additional Information!!

The rate of change of velocity at per unit time is called acceleration .

✧ SI unit of acceleration is m/s²

✧ It is vector Quantity ( both magnitude and directio

AKS 8a - Phenomena-Based Question: Use the data and the graph to make a claim as to which person represents each letter on the graph. In your discussion, be sure to:



explain how the data matches each line on the graph

describe, compare, and contrast the rates of speed and change in position for each person based on the documents

explain what the slope of each line helps determine



Person

Action

Distance Travelled

Time

Dad

Drives home from the grocery store

1 mile

10 minutes

Aiden

Rides his bike to a friend’s house

0.75 miles

10 minutes

Mom

Waits at the doctor’s office

0 miles

10 minutes

Alexis

Walks to her mailbox down the long driveway

0.25 miles

10 minutes

Answers

Answer: what’s the answer

Explanation:

At what speed does a 1500 kg compact car have the same kinetic energy as a 18000 kgkg truck going 21 km/hr km/hr

Answers

Answer:

speed = 72.75km/hr

Explanation:

Let us first determine the Kinetic energy (KE) of the 18000kg truck

[tex]KE = \frac{1}{2} mv^2\\where:\\m = mass = 18000\\v = velocity = 21km/hr\\\therefore KE = \frac{1}{2} \times 18000 \times (21)^2\\= 9000 \times 441\\KE = 3,969,000\ Joules\\= 3,969\ KJ[/tex]

Next we will substitute this value of kinetic energy into the KE equation for the 1500kg compact car

[tex]KE = \frac{1}{2} mv^2\\3969000 = \frac{1}{2} \times 1500 \times v^2\\3969000 = 750 \times v^2\\v^2 = \frac{3969000}{750} = 5292\\v = \sqrt{5292} \\v = 72.75km/hr[/tex]

The speed at which the 1500 kg compact car have the same kinetic energy as the truck is 73 km/h

The kinetic energy of an object is known to be the energy at work and in motion. It is usually expressed as;

[tex]\mathbf{K.E = \dfrac{1}{2}mv^2}[/tex]

To determine the speed at which the car will have the same kinetic energy as the truck, we can say that:

[tex]\mathbf{\implies \dfrac{1}{2}m_c v_c^2= \dfrac{1}{2}m_t v_t^2}[/tex]

[tex]\mathbf{m_c}[/tex] = mass of the car[tex]\mathbf{v_c}[/tex] = speed of the car[tex]\mathbf{m_t}[/tex] = mass of the truck[tex]\mathbf{v_t}[/tex] = speed of the truck

[tex]\mathbf{\implies \dfrac{1}{2}\times 1500\times v_c^2= \dfrac{1}{2}\times 18000 \times 21^2}[/tex]

[tex]\mathbf{v_c^2= \dfrac{3969000}{ 750}}[/tex]

[tex]\mathbf{v_c^2=5292}[/tex]

[tex]\mathbf{v_c=\sqrt{5292}}[/tex]

[tex]\mathbf{v_c\simeq 73 km/h}[/tex]

Therefore, we can conclude that the speed at which the 1500 kg compact car have the same kinetic energy as the truck is 73 km/h

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What is the force per meter of length on a straight wire carrying a 8.05 A current when perpendicular to a 0.82 T uniform magnetic field?

Answers

Answer:

6.601 N/m.

Explanation:

Generally, the force on a wire carrying current in a magnetic field can be determined by:

F = BIL Sinθ

where: F is the force, B is the value of the magnetic field, I is the value of current in the wire and θ is the angle between the direction of current and magnetic field.

For force per meter of length, we have;

[tex]\frac{F}{L}[/tex] = BI Sinθ

Given: I = 8.05 A, B = 0.82 T and θ = [tex]90^{o}[/tex](since they are perpendicular).

Then;

[tex]\frac{F}{L}[/tex] = 0.82 x 8.05 x Sin [tex]90^{o}[/tex]

  = 6.601

  = 6.601 N/m

the force per meter length is 6.601 N/m.

The required magnitude of force per meter of wire is of 6.601 N/m.

Given data:

The magnitude of current in a wire is, I = 8.05 A.

The strength of magnetic field is, B = 0.82 T.

We known that, in a magnetic field there is always a force acting on a wire kept in the region. This force is known as magnetic force, and the expression for the magnetic force is given as,

[tex]F = B \times I \times L \times sin \theta[/tex]

Now,

For the force per unit length, and current being perpendicular to magnetic field,

[tex]\dfrac{F}{L} = B \times I \times sin90\\\\\dfrac{F}{L} = 0.82 \times 8.05 \times sin90\\\\\dfrac{F}{L} = 6.601 \;\rm N/m[/tex]

Thus, we can conclude that the required magnitude of force per meter of wire is of 6.601 N/m.

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А)
An automobile traveling along a straight road
increases its speed from 48 ft/s to 66 ft/s in
180 ft.
If the acceleration is constant, how much
time elapses while the auto moves the 180 ft?
Answer in units of s.

Answers

Answer:

4.5s

Explanation:

u=30m/s

v=50m/s

s=180m

a=constant(given)

By third equation of motion,    v  

2

=u  

2

+2as

(50)  

2

=(30)  

2

+2a(180)

a=  

3

40

​  

m/s  

2

 

By first equation of motion,    v=u+at

50=30+(  

9

40

​  

)t

t=  

2

9

​  

=4.5sec

Objects are lighter on the moon than they are on earth. if an object A weighs 25lbs on the Moon and another object B weighs 25 Newtons on earth, which has more mass?

a. Object a
b. Object b
c. Same mass
d. Other

Answers

Answer:

a. Object A

Explanation:

The mass of an object implies the quantity of matter in it, while the weight is the amount of gravitational force applied on an object.

The object A has a mass of 25 lbs, but object B on the earth has a weight, W, of 25 N.

So that,

For object A on the moon, mass = 25 lbs

For object B on the earth, W = 25 N,

W = m x g

25 = m x 10                (g = 10 m/[tex]s^{2}[/tex])

m = [tex]\frac{25}{10}[/tex]

   = 2.5 lbs

Mass of object B is 2.5 lbs.

Therefore, the mass of the object A is more than that of B.

If the velocity of Homer the astronaut (mass =200 kg) is 5 m/s and he runs into and grabs his stationary pal Larry (mass = 150 kg), what is the new velocity of the astronauts after the collision?

Answers

We are given:

Homer the Astronaut:

Mass of Homer the astronaut(m1) = 200 kg

initial velocity of Homer the astronaut(u1) = 5 m/s

Larry the Pal:

Mass of Larry the Pal (m2) = 150 kg

initial velocity of Larry the Pal (u2) = 0 m/s

Since they will move together after the collision, they will have the same velocity:

v1 = v2 = V

Solving for the Final velocity:

from the law of conservation of momentum:

m1u1 + m2u2 = m1v1 + m2v2

since v1 = v2 = V:

m1u1 + m2u2 = V(m1 + m2)

replacing the variables with the given values

200 * 5 + 150 * 0 = V(200 + 150)

1000 = 350V

V  = 1000 / 350

V = 2.86 m/s

For a given centrifugal pump, if the speed of rotation of the impeller is cut in half, how does the power required to drive the pump change

Answers

Answer:

The power required to drive the pump is reduced in [tex]\frac{1}{8}[/tex].

Explanation:

From Turbomachinery, we find that power required to drive the pump ([tex]\dot W[/tex]) is directly proportional to the cube of the speed of rotation of the impeller ([tex]\dot n[/tex]). That is:

[tex]\dot W \propto \dot n^{3}[/tex]

[tex]\dot W = k\cdot \dot n ^{3}[/tex] (Eq. 1)

Where [tex]k[/tex] is the proportionality constant.

And now we eliminate the proportionality constant by constructing the following relationship:

[tex]\frac{\dot W_{B}}{\dot W_{A}} = \left(\frac{\dot n_{B}}{\dot n_{A}}\right)^{3}[/tex] (Eq. 2)

If we know that [tex]\frac{\dot n_{B}}{\dot n_{A}} = \frac{1}{2}[/tex], then:

[tex]\frac{\dot W_{B}}{\dot W_{A}} = \frac{1}{8}[/tex]

The power required to drive the pump is reduced in [tex]\frac{1}{8}[/tex].

True or False: In a p-n junction diode, the absolute value of the electric field is the largest at the metallurgical junction (exactly where p-type and n-type semiconductors meet).

Answers

Answer:

false

Explanation:

In a p-n junction diode, the absolute value of the electric field is the largest at the metallurgical junction is false statement.

What is electric field?

An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. It can also refer to a system of charged particles' physical field.

In a p-n junction diode, the absolute value of the electric field is the not largest at the metallurgical junction field is maximum at the depletion region.

In a p-n junction diode, the absolute value of the electric field is the largest at the metallurgical junction is false statement.

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Which is the function of a nucleus within a eukaryotic cell?
O A) Transport materials within the cell.
O B) Control what materials move into and out of the cell.
OC) Provide the cell with energy to perform its other functions.
OD) Store genetic information that provides instructions for the cell.

Answers

ANSWER
D) store genetic information that provides instructions for the cell

A piston has an external pressure of 15.0 atmatm. How much work has been done in joules if the cylinder goes from a volume of 0.120 liters to 0.450 liters

Answers

Answer: Work done is  - 501.56 J

Explanation:

Given that;

External pressure P = 15.0 atm

Volume V1 = 0.120 liters

Volume V2 = 0.450 liters

Work done = ?

we know that; Work = -Pdv

where P is pressure and dv is change in volume

so we substitute our values into the equation

Work = -15.0 × ( 0.450 - 0.120)

= -15 × 0.33

= - 4.95 atm/L

we know that;

1 atm.L = 101.325 J

so

- 4.95 atm/L = 101.325 J × -4.95 atm/L ÷

= - 501.56 J

Therefore Work done is  - 501.56 J

the y-axis of a position-time graph represents__________.

Answers

Answer:position relative to the starting point

Explanation:

What is the largest planet in our galaxy

Answers

In our Solar System, Jupiter is the largest planet we have. it has the surface area of 23.71 billion mi^2. it beats all the other planets in both mass and volume.

Which accurately completes the statement? Conduction involves the transfer of electric charge or due to the movement of particles. O thermal energy Olight waves O protons o neutrons​

Answers

Answer:

A: thermal energy

Conduction involves the transfer of electric charge or thermal energy due to the movement of particles. So, the correct option is 1.

What is meant by heat transfer ?

Heat transfer is defined as the process of transferring heat from one body to another based on the temperature difference between them.

Here,

There are several mechanisms of heat transfer such as conduction, convection, radiation, etc.

Conduction or thermal conduction is a commonly used mechanism for heat transfer.

Conduction is defined as the process by which heat is transferred from one body to other in contact with each other. In conduction, the heat flows from the hotter body to the surface of the colder body which is in contact with it.

This property or ability of the body to conduct heat or thermal energy is known as its thermal conductivity.

Conductions requires a temperature gradient to transfer the heat. The temperature difference between the bodies leads to the heat flow between them.

Conduction occurs mostly in solids and liquids, in where the intermolecular distance between the particles is higher than that in gases.

Hence,

Conduction involves the transfer of electric charge or thermal energy due to the movement of particles.

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A force F = (2xî + 4yĵ), where F is in newtons and x and y are in meters, acts on an object as the object moves in the x-direction from the origin to x = 4.99 m. Find the work W = ∫ F · dr done by the force on the object (in J).

Answers

Answer:

Work done, W = 24.9001 J

Explanation:

Given that,

Force, F = (2xî + 4yĵ) Where x and y are in meters

This force acts on an object as the object moves in the x-direction from the origin to x = 4.99 m.

We need to find the work done by the force on the object. It is given by :

[tex]W=\int\limits^a_b {F dr} \\\\W=\int\limits^{4.99}_0 {(2xi+4yj)dx} \\\\W=\int\limits^{4.99}_0 {2xi\ dx} \\\\W=x^2|_0^{4.99}\\\\\text{Applying limits}\\\\W=(4.99)^2-0^2\\\\W=24.9001\ J[/tex]

So, the work done is 24.9001 J.

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