What's the difference between speed and velocity

Answer:

baby yoda

Explanation:

Answer:

ice (solid), water (liquid) and vapor (gas)

Explanation:

Answer:

E=mc2

Explanation:

It explains that in their interiors, atoms fuse together, creating energy.

To solve this we must be knowing each and every concept related to energy and its different types. Therefore, the famous equation that describes the energy of stars is E=mc².

In physics, energy is the capacity to accomplish work. It can be potential, kinetic, thermal, electric, chemical, radioactive, or in other forms.

There is also heat and work—energy inside the process of being transferred by one body to the other. Energy is always classified according to its type once it has been transmitted. As a result, heat transported could become thermal energy, whereas labor done may emerge as mechanical energy. The famous equation that describes the energy of stars is E=mc²

Therefore, the famous equation that describes the energy of stars is E=mc².

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Answer:

The time taken before the phone hits the ground is 1.4 s.

Explanation:

Given;

height of the rock wall, h = 10 m

speed of the climber, v = 0.25 m/s

The time taken before the phone hits the ground is given;

h = ut + ¹/₂gt²

10 = 0.25t + ¹/₂(9.8)t²

20 = 0.5t + 9.8t²

9.8t² + 0.5t - 20 = 0

solving this quadratic equation;

t = 1.4 s

Therefore, the time taken before the phone hits the ground is 1.4 s.

Answer: Work done is  - 501.56 J

Explanation:

Given that;

External pressure P = 15.0 atm

Volume V1 = 0.120 liters

Volume V2 = 0.450 liters

Work done = ?

we know that; Work = -Pdv

where P is pressure and dv is change in volume

so we substitute our values into the equation

Work = -15.0 × ( 0.450 - 0.120)

= -15 × 0.33

= - 4.95 atm/L

we know that;

1 atm.L = 101.325 J

so

- 4.95 atm/L = 101.325 J × -4.95 atm/L ÷

= - 501.56 J

Therefore Work done is  - 501.56 J

Answer:

A: thermal energy

Conduction involves the transfer of electric charge or thermal energy due to the movement of particles. So, the correct option is 1.

Heat transfer is defined as the process of transferring heat from one body to another based on the temperature difference between them.

Here,

There are several mechanisms of heat transfer such as conduction, convection, radiation, etc.

Conduction or thermal conduction is a commonly used mechanism for heat transfer.

Conduction is defined as the process by which heat is transferred from one body to other in contact with each other. In conduction, the heat flows from the hotter body to the surface of the colder body which is in contact with it.

This property or ability of the body to conduct heat or thermal energy is known as its thermal conductivity.

Conductions requires a temperature gradient to transfer the heat. The temperature difference between the bodies leads to the heat flow between them.

Conduction occurs mostly in solids and liquids, in where the intermolecular distance between the particles is higher than that in gases.

Hence,

Conduction involves the transfer of electric charge or thermal energy due to the movement of particles.

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Answer:

The average speed is 22.2 km/h

Explanation:

Average Speed

Given an object travels a total distance d and took a total time t, then the average speed is:

[tex]\displaystyle \bar v=\frac{d}{t}[/tex]

The mailman first drives d1=7 km at v1=15 km/h. The time taken to drive is:

[tex]\displaystyle t1=\frac{d1}{v1}=\frac{7}{15}=0.467\ h[/tex]

Then he drives d2=7 km at v2=43 km/h taking a time of:

[tex]\displaystyle t2=\frac{d2}{v2}=\frac{7}{43}=0.163\ h[/tex]

The total time is

t=0.467 h + 0.163 h = 0.63 h

The total distance is

d = 7 km + 7 km = 14 km

The average speed is:

[tex]\displaystyle \bar v=\frac{14}{0.63}=22.2\ km/h[/tex]

The average speed is 22.2 km/h

Answer:

Explanation:

This question is incomplete. However, it should be noted that for an object to float in a liquid, the density of the object must be less dense than the liquid. This causes the weight force of the object to be balanced by the upthrust force of the liquid. Thus, when the object is more dense than the liquid, the object sinks.

One thing the floating objects will have in common is that they are less dense than the liquid in which they are floating.

NOTE that the floating of an object can be dependent on size and shape (which affects the upthrust force) also.

Answer:

The value  is  [tex]\lambda = 5.30 *10^{-10 } \ m[/tex]

Explanation:

From the question we are told that

    The velocity of the electron is  [tex]v = 1.37 *10^{6} \ m/s[/tex]

    The mass of the electron is  [tex]m = 9.11 *10^{-28} \ g = 9.11 *10^{-31} \ kg[/tex]

Generally the  deBroglie wavelength  is mathematically represented as

       [tex]\lambda = \frac{h}{mv}[/tex]

Here h is the Planck'c constant with value  [tex]h = 6.62607015 * 10^{-34} J \cdot s[/tex]

So

      [tex]\lambda = \frac{6.62607015 * 10^{-34} }{9.11 *10^{-31} * 1.37 *10^{6}}[/tex]

=>   [tex]\lambda = 5.30 *10^{-10 } \ m[/tex]

Answer: wow that’s hard

Explanation:

Answer:

6.601 N/m.

Explanation:

Generally, the force on a wire carrying current in a magnetic field can be determined by:

F = BIL Sinθ

where: F is the force, B is the value of the magnetic field, I is the value of current in the wire and θ is the angle between the direction of current and magnetic field.

For force per meter of length, we have;

[tex]\frac{F}{L}[/tex] = BI Sinθ

Given: I = 8.05 A, B = 0.82 T and θ = [tex]90^{o}[/tex](since they are perpendicular).

Then;

[tex]\frac{F}{L}[/tex] = 0.82 x 8.05 x Sin [tex]90^{o}[/tex]

  = 6.601

  = 6.601 N/m

the force per meter length is 6.601 N/m.

The required magnitude of force per meter of wire is of 6.601 N/m.

Given data:

The magnitude of current in a wire is, I = 8.05 A.

The strength of magnetic field is, B = 0.82 T.

We known that, in a magnetic field there is always a force acting on a wire kept in the region. This force is known as magnetic force, and the expression for the magnetic force is given as,

[tex]F = B \times I \times L \times sin \theta[/tex]

Now,

For the force per unit length, and current being perpendicular to magnetic field,

[tex]\dfrac{F}{L} = B \times I \times sin90\\\\\dfrac{F}{L} = 0.82 \times 8.05 \times sin90\\\\\dfrac{F}{L} = 6.601 \;\rm N/m[/tex]

Thus, we can conclude that the required magnitude of force per meter of wire is of 6.601 N/m.

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Answer:

The average force ≅ 519.44 N.

Explanation:

Impulse = change in momentum of a body

i.e Ft = m(v - u)

where F is the force, t is the time, m is the mass of the body, v is the final velocity and u is the initial velocity.

m = 55.0 g (0.055 Kg), t = 0.00360 s, v = 34.0 m/s, since the ball was initially at rest; u = 0 m/s

So that,

F x 0.00360 = 0.055(34 - 0)

F x 0.00360 = 0.055 x 34

                    = 1.87

F = [tex]\frac{1.87}{0.0036}[/tex]

 = 519.4444

The average force exerted on the ball by the club is approximately 519.44 N.

Answer:

3.56s

Explanation:

Ya that's the right answer.

Explanation:

so sorry

don't know but please mark me as brainliest please

Answer:

a. Object A

Explanation:

The mass of an object implies the quantity of matter in it, while the weight is the amount of gravitational force applied on an object.

The object A has a mass of 25 lbs, but object B on the earth has a weight, W, of 25 N.

So that,

For object A on the moon, mass = 25 lbs

For object B on the earth, W = 25 N,

W = m x g

25 = m x 10                (g = 10 m/[tex]s^{2}[/tex])

m = [tex]\frac{25}{10}[/tex]

   = 2.5 lbs

Mass of object B is 2.5 lbs.

Therefore, the mass of the object A is more than that of B.

Answer:

Work done, W = 24.9001 J

Explanation:

Given that,

Force, F = (2xî + 4yĵ) Where x and y are in meters

This force acts on an object as the object moves in the x-direction from the origin to x = 4.99 m.

We need to find the work done by the force on the object. It is given by :

[tex]W=\int\limits^a_b {F dr} \\\\W=\int\limits^{4.99}_0 {(2xi+4yj)dx} \\\\W=\int\limits^{4.99}_0 {2xi\ dx} \\\\W=x^2|_0^{4.99}\\\\\text{Applying limits}\\\\W=(4.99)^2-0^2\\\\W=24.9001\ J[/tex]

So, the work done is 24.9001 J.

Answer:

Explanation:

To get the focal length, we will use the lens formula;

1/f = 1/u + 1/v

f is the focal length

u is the object distance

v is the image distance

Given

since the physicist's left eye is myopic, it will be corrected using concave lens and the image distance is negative.

u = 35cm

v = -2.0

1/f = 1/35-1/2

1/f = 2-35/70

1/f = -33/70

f = -70/33

f = -2.12 cm

f = -0.0212m

Power of a lend is the reciprocal of its focal length

Power of the lens = 1/f

P = 1/-0.0212

P = -47.17dioptres

The power of the lens is -47.17D

Answer:position relative to the starting point

Explanation:

Answer:

speed = 72.75km/hr

Explanation:

Let us first determine the Kinetic energy (KE) of the 18000kg truck

[tex]KE = \frac{1}{2} mv^2\\where:\\m = mass = 18000\\v = velocity = 21km/hr\\\therefore KE = \frac{1}{2} \times 18000 \times (21)^2\\= 9000 \times 441\\KE = 3,969,000\ Joules\\= 3,969\ KJ[/tex]

Next we will substitute this value of kinetic energy into the KE equation for the 1500kg compact car

[tex]KE = \frac{1}{2} mv^2\\3969000 = \frac{1}{2} \times 1500 \times v^2\\3969000 = 750 \times v^2\\v^2 = \frac{3969000}{750} = 5292\\v = \sqrt{5292} \\v = 72.75km/hr[/tex]

The speed at which the 1500 kg compact car have the same kinetic energy as the truck is 73 km/h

The kinetic energy of an object is known to be the energy at work and in motion. It is usually expressed as;

[tex]\mathbf{K.E = \dfrac{1}{2}mv^2}[/tex]

To determine the speed at which the car will have the same kinetic energy as the truck, we can say that:

[tex]\mathbf{\implies \dfrac{1}{2}m_c v_c^2= \dfrac{1}{2}m_t v_t^2}[/tex]

∴

[tex]\mathbf{\implies \dfrac{1}{2}\times 1500\times v_c^2= \dfrac{1}{2}\times 18000 \times 21^2}[/tex]

[tex]\mathbf{v_c^2= \dfrac{3969000}{ 750}}[/tex]

[tex]\mathbf{v_c^2=5292}[/tex]

[tex]\mathbf{v_c=\sqrt{5292}}[/tex]

[tex]\mathbf{v_c\simeq 73 km/h}[/tex]

Therefore, we can conclude that the speed at which the 1500 kg compact car have the same kinetic energy as the truck is 73 km/h

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Answer:

Lunar and solar eclipses occur with about equal frequency. Lunar eclipses are more widely visible because Earth casts a much larger shadow on the Moon during a lunar eclipse than the Moon casts on Earth during a solar eclipse. As a result, you are more likely to see a lunar eclipse than a solar eclipse.

For a total eclipse to take place, the sun, moon and Earth must be in a direct line. The second type of solar eclipse is a partial solar eclipse. This happens when the sun, moon and Earth are not exactly lined up. The sun appears to have a dark shadow on only a small part of its surface.

For a lunar eclipse to occur, the Sun, Earth, and Moon must be roughly aligned in a line

The force required to hold it completely submerged under water is 0.252 N

As a result of the low density (ρ1 = 0.0839 g/cm3 = 83.9 kg/m3)of the ball compared to that of water (ρ2 =1000 kg/m3), the buoyant force that is acting on the ball is greater than its weight.

Therefore, the minimum force required to hold the ball submerged under water can be calculated using the relation

Radius = 3.77/2 cm = 0.0377/2 m = 0.01885 m

Volume of sphere = 4/3 π r³ = 4/3 * 3.142 * 0.01885³ = 2.805 e-5 m³

Mass of sphere = 4/3 π r³ ρ1 = 4/3 * 3.142 * 0.01885³ * 83.9 = 0.0023 kg

Weight of sphere = 4/3 π r³ ρ1 g = 4/3 * 3.142 * 0.01885³ * 83.9 * 9.8 = 0.023 N

Volume of water displaced = 4/3 π r³ = 2.805 e-5

Buoyant force = weight of water displaced = 4/3 π r³ ρ2 g = 4/3 π r³ = 4/3 * 3.142 * 0.01885³ * 1000 * 9.8 = 0.275 N

F = 0.275 - 0.023 = 0.252 N

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The force required to hold it completely submerged under water is 0.25 N

The density of the ball ([tex]\rho_b[/tex]) = 0.0839 g/cm³ = 83.9 kg/m³

The density of water [tex]\rho_w[/tex] = 1000 kg/m³

Diameter = 3.77 cm = 0.0377 m

radius of ball = 0.0377/2 = 0.01885 m

The volume (V) = [tex]\frac{4}{3} \pi r^3=\frac{4}{3}*\pi*0.01885^3=2.8*10^{-5}\ m^3[/tex]

Let us assume the acceleration due to gravity (g) = 9.8 m/s², Hence:

The force is required to hold it completely submerged under water (F) is:

[tex]F=\rho_w Vg-\rho_b Vg=1000*(2.8*10^{-5})*9.81-83.9*(2.8*10^{-5})*9.81\\\\[/tex]

F = 0.25 N

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Answer: what’s the answer

Explanation:

Answer:

4.5s

Explanation:

u=30m/s

v=50m/s

s=180m

a=constant(given)

By third equation of motion,    v  

2

=u  

2

+2as

(50)  

2

=(30)  

2

+2a(180)

a=  

3

40

​  

m/s  

2

By first equation of motion,    v=u+at

50=30+(  

9

40

​  

)t

t=  

2

9

​  

=4.5sec

Answer:

[tex]5\sqrt{2} \ N[/tex]

Explanation:

It is given that,

A 5-newton force directed east and a 5-newton force directed  north.

We need to find the resultant of the two forces.

As the two forces are acting in perpendicular to each other. The resultant of two such forces is given by :

[tex]F=\sqrt{5^2+5^2} \\\\=5\sqrt{2} \ N[/tex]

So, the resulatnt force is [tex]5\sqrt{2} \ N[/tex]

Answer: I don't  do   adopt me   but I do have a Ro.blox username its  Nvm i cant but my user name

Explanation:

Answer:

adopt me sucks but my best pet was an albino monkey I think or a king monkey

Explanation:

Answer:

B. symbolic

Explanation:

The mental image formed in Terell's mind is a symbolic mental image.

A symbolic mental image helps to bring perception to imagery formed on the mind.

Answer:

Terell lives in Washington, D.C., where he can see the Potomac River from his bedroom window. When he sees this river, Terell thinks of swimming, boating, fun, and friends. What type of mental image is this?

symbolic

Explanation:

Answer:

32

Explanation:

Up forces and Down forces must be equal if the object is balanced

For this question

down force is weight of the plank

up forces is 14 and 18

14+18=Weight of plank

Answer:

manual

Explanation:

A manual distraction is when a driver takes their hand(s) off the wheel for any reason, for any amount of time. Without both hands on the wheel, your reaction time suffers, and so does your ability to steer.