What types of energy do lamps give off?
Include how was your day in you answer.
Explain why/if the lamp gives off heat energy.

Answer:

I would be if I do it your no learning anything but I would but I don't have insta yet

Explanation:

sorry

Answer:

k

Explanation:

Answer:

d. Although the hydrolysis of ATP is thermodynamically favorable, without a catalyst the reaction occurs at a very slow rate because it has a large activation energy.

Explanation:

Hello!

In this case, since negative Gibbs free energies of reaction stand for thermodynamically favored processes, we can immediately rule out choices a. and b.

Moreover, since the reaction is slow without the presence of a catalyst, which the context of biochemistry is an enzyme, we infer that correct choice is d. Although the hydrolysis of ATP is thermodynamically favorable, without a catalyst the reaction occurs at a very slow rate because it has a large activation energy because the higher the activation energy the slower the reaction according to the Arrhenius equation.

Best regards!

Answer:

C,A,B,D

Explanation:

That's the correct order, hope this helps

Answer:

The solution is 10^-2 or 0.01M in HCl.

Explanation:

meaning of pH is "power of hydrogen".

what is the molar concentration of a HCl solution with pH=2?

Let say pH=2

[H+]=10^-2M

HCL is a strong acid that dissociates completely:

[H+]=[HCL]

Therefore solution is 10^-2 or 0.01M in HCL.

Answer:

The composition of the objects because not all the planets have been explored

Answer:

55.025g of N2O

Explanation:

2 NH3 + 2 O2 → N2O + 3 H2O

moles of O2 = 80.0/32 = 2.5 moles O2

moles of N2O = 2.5 moles O2 * 1 mole N2O

= 1.25 moles N2O

moles = mass/Molar mass

mass = moles * Molar mass = 1.25 x 44.02 = 55.025 g

Carbon-14 is a radioisotope of carbon that decays following first-order kinetics. There are four values of interest in this problem: the "normal" (or original) amount of carbon-14 for a jawbone ([tex]\mathrm{N_0}[/tex]), the actual amount of carbon-14 in a jawbone ([tex]\mathrm{N}[/tex]), the half-life of carbon-14 ([tex]\mathrm{t_{1/2}}[/tex]), and the actual time elapsed ([tex]\mathrm{t}[/tex]) from the original time. There is an equation that ties all these values in together,

[tex]N= N_0 e^{-kt}[/tex]

where k is the rate constant, which, for first-order decay, is related to the half-life by

[tex]k = \dfrac{\ln 2}{ t_{1/2} }.[/tex]

What you want to find here is the time elapsed (t). So, you can substitute the latter equation for k into the k in the former equation to get

[tex]N= N_0 e^{\frac{-\ln 2 \;t}{t_{1/2}}.[/tex]

Rearranging to solve for t, the equation becomes

[tex]t = \left(\dfrac{\ln \dfrac{N_0}{N}}{\ln 2} \right) t_{1/2}.[/tex]

You are given all three of the values necessary to solve for t: The normal amount of carbon-14 is 200 mg; the actual amount of carbon-14 in the sample is 50 mg; and the half-life of carbon-14 is 5730 years. Plugging them into the above equation, we get

[tex]t = \left(\dfrac{\ln \dfrac{200 \text{ mg}}{50 \text{ mg}}}{\ln 2} \right) \left(5730 \text{ years} \right) = 11460 \text{ years}.[/tex]

So the jawbone found is 11460 years old (or 11000 if accounting for sig figs).

Answer:

These forces make objects change their motion or movement , the act of going from one place to another.

Explanation:

Answer:the answer is a c and e

Explanation:

Answer:

A

Explanation:

But I'm not sure just my instinct

The statement that described the movement of the medium via the transverse wave should be that it should be parallel to the wave.

It is the waves in which the motion considered all the points that should be on the wave oscillate along the paths at the right angles with respect to the wave of the direction. An example of this kind of wave should be electromagnetic, etc. Here, the movement should be parallel to the wave.

Hence, the correct option is b.

Learn more about transverse wave here: https://brainly.com/question/21890036

Answer:

487638640,7819

dndndnndndbxbdbdbdbdb

Answer:

7/16

Explanation:

The general formula for the combustion of alkanes is;

CnH2n+2 + 3n+1/2 O2  -------> nCO2 + (n+1)H2O

So, we have;

CnHn + nO2 ------> 7CO2 + 8H2O

So there are 7 carbon atoms and 16 hydrogen atoms in heptane according to the law of conservation of mass.

Therefore, heptane is; C7H16

The ratio of carbon to hydrogen is now; 7/16

Answer:

V2= 1.03L

Explanation:

Start off with what you are given.

V^1: 1.00L

T^1: 23°C

V^2?

T^2: 33°C

If you know your gas laws, you have to utilise a certain gas law called Charles' Law:

V^1/T^1 = V^2/T^2

Remember to convert Celsius values to Kelvin whenever you are dealing with gas problems. This can be done by adding 273 to whatever value in Celsius you have.

(23+273 = 296)     (33+273 = 306)

Multiply crisscross

1.00/296= V^2/306

296V^2 = 306

Dividing both sides by 296 to isolate V2, we get

306/296 = 1.0337837837837837837837837837838

V2= 1.03L

Answer:

Decomposition.

Explanation:

Decomposition Reactions T hose reactions in which a single substance (reactant) splits up into two or more simpler substances (products) are known as decomposition reactions. These reactions are carried out by supplying energy in form of heat, electricity or light which breaks that substance into simpler substances

Answer: [tex]3Mg(s)+2SnCl_3(aq)\rightarrow 3MgCl_2(aq)+2Sn(s)[/tex]

Explanation:

Single replacement reaction is a chemical reaction in which more reactive element displaces the less reactive element from its salt solution.

A more reactive element is one which can easily lose or gain electrons as compared to the other element.

As Magnesium is more reactive than tin, it can easily displace tin from its salt solution [tex](SnCl_3)[/tex] and form magnesium chloride and tin in elemental form.

The balanced chemical equation is:

[tex]3Mg(s)+2SnCl_3(aq)\rightarrow 3MgCl_2(aq)+2Sn(s)[/tex]

Answer:

There are 6 atoms of oxygen in 2Ca(NO3)2

Answer:

t = 1862 s

Explanation:

To do this, we need first to determine the theorical detention time, which can be determined with the following expression:

t₀ = ∀/Q  (1)

Where:

t₀: detention time

∀: Volume of the fluid in the reactor

Q: Flow rate in the reactor

With this time, we must use the following expression to determine the time that the workers will take to vent the tank:

C = C₀ e^(-t/t₀)   (2)

From here, we must solve for time t, and the expression will be:

t = ln(C₀/C) * t₀   (3)

Now that we know the expression to use, let's solve for t. Using (1) to determine the detention time, ∀ is 1900 m³, and Q is 2.35 m³/s so:

t₀ = 1900 / 2.35 = 808.51 s

Now, let's solve for the time t. C will be 0.0015 mg/L (or 1.5 mg/m³ cause in 1 m³ we have 1000 L) and C₀ 15 mg/m³:

t = ln(15/1.5) * 808.51

Hope this helps

Answer:

balancing the equation?

Answer:

48.27g Na

Explanation:

To start we need to balance the equation. The trick is to make sure both sides have equal amounts of each atom:

2Na + Cl2 --> 2NaCl

Now we can use sociometry

We have 75 g of Cl2, and for every 1 mole of Cl2, there are 70.9 grams:

[tex]75g Cl2 * \frac{1mole Cl2}{70.9g Cl2}= 1.05 mole Cl2[/tex]

Now we have moles of Cl2. To get to grams of Na, we need to first use mole to mole ratio:

[tex]1.05mole Cl2 *\frac{2 mole Na}{1 mole Cl2} =2.1 mole Na[/tex]

 From here we convert moles of Na into grams of Na

[tex]2.1mol Na*\frac{22.99g Na}{1 mole Na} = 48.27g Na[/tex]

It's usually easier to just make one singular equation with all of these smaller equations.

[tex]75gNa*\frac{1molCl2}{70.9gCl2} *\frac{2mol Na}{1 mol Cl2} *\frac{22.99g Na}{1 mol Na}=48.27 gNa[/tex]

The trick to sociometry is making sure your units cancel out until you only have the unit you want. If there are moles of Na in the numerator, there needs to be moles of Na in the denominator. If there are grams of Cl2 in the numerator, there needs to be grams of Cl2 in the denominator and so one and so on

Answer:

Bohr's model of the hydrogen atom is based on three postulates:

1) An electron moves around the nucleus in a circular orbit,

2) An electron's angular momentum in the orbit is quantised,

3) The change in an electron's energy as it makes a quantum jump from one orbit to another is always accompanied by the emission or absorption of a photon. Bohr's model is semi-classical because it combines the classical concept of electron orbit (postulate 1) with the new concept of quantisation ( postulates 2 and ).

Answer:

3.955*10^48

Explanation:

1 mole of a substance gives 6.02*10^23/6.57*10^24 will give x then cross multiply the answer. is 3.955*10^48

Answer:

Molecular formula: S4K8O16  empirical formula: SK2O4

Explanation:

First we find the moles of each by first finding grams (using the percent) and then using stoichiometry to convert into moles:

Sulfur: 696 *.18 = 125.28grams S* [tex]\frac{1 mole S}{32.065 g S} = 3.907 moles S[/tex]

Potassium: 696 *.4487 = 312.2952 *[tex]\frac{1 mole K}{39.08 g K}[/tex]= 7.99117 mole K

Oxygen: 696 * .367 = 255.432 * [tex]\frac{1 mol O}{16g O}[/tex] = 15.9654 mole O

Then we divide each value by the atom with the smallest number of moles to find the mole ratio:

3.907/3.907= 1

7.99117 mole K/ 3.907= 2.043

15.9654 mole O/ 3.907= 4.08

The empirical formula is SK2O4

To find the molecular formula, we divide the mass given (696) by the mass of the empirical formula (174.22) to get 4. We then divide each atom by 4.

Molecular formula: S4K8O16

Answer: a. 3.36 L

b. 33.2 g

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

Standard condition of temperature (STP)  is 273 K and atmospheric pressure is 1 atm respectively.

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

[tex]\text{Number of moles of} Fe_2O_3=\frac{16.0g}{159.69g/mol}=0.1mole[/tex]

[tex]3O_2(g)+4Fe(s)\rightarrow 2Fe_2O_3(s)[/tex]

a. 2 moles of [tex]Fe_2O_3[/tex] are produced by = [tex]3\times 22.4L=67.2L[/tex] of [tex]O_2[/tex]

Thus 0.1 moles of  [tex]Fe_2O_3[tex] are produced by =[tex]\frac{67.2}{2}\times 0.1=3.36L[/tex] of [tex]O_2[/tex]

b. [tex]3\times 22.4L=67.2L[/tex] of [tex]O_2[/tex] react with = [tex]4\times 55.8=223.2g[/tex] of iron

Thus 10.0 L of [tex]O_2[/tex] react with = [tex]\frac{223.2}{67.2}\times 10=33.2g[/tex] of iron

mass = mol no. x molar mass
         = 6.2 x 23
         = 142.6 g

Answer:

51.03g/mol is the molar mass of X

Explanation:

Based on the reaction:

2XI₃ + 3Cl₂X → 2XCl₃ + 3I₂

Where 2 moles of XI₃ reacts to produce 2 moles of XCl₃ -The ratio of reaction is 1:1-

To solve this question we must find the mass of X per mole (This is the atomic mass of X).

As the moles of both compounds are the same:

1.196g / 0.436g = Molar mass XI₃ / molar mass XCl₃ (1)

Also:

Molar mass XI₃ = Molar mass X + 380.71g/mol

Molar mass XCl₃ = Molar mass X + 106.36g/mol

Replacing in (1):

2.7431 = (Molar mass X + 380.71g/mol) / (Molar mass X + 106.36g/mol)

2.7431 Molar mass X + 291.76g/mol = Molar mass X + 380.71g/mol

1.7431 Molar mass X = 88.95g/mol

Molar mass X = 51.03g/mol

Answer:

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Explanation:

Answer:

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Explanation: