Answer: your feet are the foundation! Even though all your body parts are connected and affect one another, your feet are what we at Foot Levelers call, the "foundation".
Explanation:
Two identical conducting spheres each have a charge of 2 C. They have a radius of 0.1 m and are separated by 0.5 meters. If you were to increase the radius of these spheres to 0.2 meters, the electrostatic force between them would
Answer:
The electrostatic force will remain the same
Explanation:
From the question we are told that
The charge on the each conducting sphere is [tex]q = 2 \ C[/tex]
The radius each sphere is [tex]r_1 = r_2 = r = 0. 1\ m[/tex]
Generally electrostatic force between the sphere is mathematically represented as
[tex]F = \frac{k * q_1 q_2 }{d^2}[/tex]
Here k is the coulomb constant ,
d is the distance between the two sphere which is measured from one center of the sphere to the other center of the sphere
Now from the question we are told that the radius of the spheres is doubled (i.e from 0.10 m to 0.2 m ) , this will not affect the distance between the sphere because their center are still in the same position
and given there is no change in the distance between the spheres , the electrostatic force will remain the same
How long had the Romans ruled those regions?
precisely which regions?
Answer:
Romans have ruled for 450 years
Explanation:
Cecelia dropped a ball from a height of 2 m. The ball fell in a straight path down to the ground.
According to Newton’s universal law of gravitation, which would change the path of the ball so it traces out the widest curved path possible?
tossing it horizontally at a slower speed
tossing it horizontally at a faster speed
dropping it from a shorter distance
dropping it from a greater distance
A rocket of mass m is to be launched fromplanet X, which has a mass M and a radius R. What is the minimum speed that the rocket must have for it to escape into space?
Answer:
The minimum speed = [tex]\sqrt{\frac{2GM}{R} }[/tex]
Explanation:
The minimum speed that the rocket must have for it to escape into space is called its escape velocity. If the speed is not attained, the gravitational pull of the planet would pull down the rocket back to its surface. Thus the launch would not be successful.
The minimum speed can be determined by;
Escape velocity = [tex]\sqrt{\frac{2GM}{R} }[/tex]
where: G is the universal gravitational constant, M is the mass of the planet X, and R is its radius.
If the appropriate values of the variables are substituted into the expression, the value of the minimum speed required can be determined.
The minimum speed that the rocket must have for it to escape into space is [tex]\sqrt{\frac{2GM}{R} }[/tex].
What is escape velocity?Escape velocity is the minimum speed that the rocket must have for it to escape into space.
The minimum speed (escape velocity) that the rocket must have for it to escape into space is given as;
[tex]V = \sqrt{\frac{2GM}{R} }[/tex]
where;
M is mass of the planetG is gravitational constantR is the radiusThus, the minimum speed that the rocket must have for it to escape into space is [tex]\sqrt{\frac{2GM}{R} }[/tex].
Learn more about escape velocity here: https://brainly.com/question/13726115
A boat can travel in still water at 56 m/s. If the boats sails directly across a river that flows at 126 m/s. What is the boats speed relative to the ground
Answer:
The answer is below
Explanation:
The speed of the boat in still water is perpendicular to the speed of the water flow. Therefore the speed relative to the ground (V), the speed of flow and the speed of the boat in still water form a right angled triangle. Hence the speed relative to the ground is given as:
V² = 56² + 126²
V² = 19012
V = 137.9 m/s
PLEASE PROVIDE AN EXPLANATION.
THANKS!!!
Answer:
(a) A = 0.0800 m, λ = 20.9 m, f = 11.9 Hz
(b) 250 m/s
(c) 1250 N
(d) Positive x-direction
(e) 6.00 m/s
(f) 0.0365 m
Explanation:
(a) The standard form of the wave is:
y = A cos ((2πf) t ± (2π/λ) x)
where A is the amplitude, f is the frequency, and λ is the wavelength.
If the x term has a positive coefficient, the wave moves to the left.
If the x term has a negative coefficient, the wave moves to the right.
Therefore:
A = 0.0800 m
2π/λ = 0.300 m⁻¹
λ = 20.9 m
2πf = 75.0 rad/s
f = 11.9 Hz
(b) Velocity is wavelength times frequency.
v = λf
v = (20.9 m) (11.9 Hz)
v = 250 m/s
(c) The tension is:
T = v²ρ
where ρ is the mass per unit length.
T = (250 m/s)² (0.0200 kg/m)
T = 1250 N
(d) The x term has a negative coefficient, so the wave moves to the right (positive x-direction).
(e) The maximum transverse speed is Aω.
(0.0800 m) (75.0 rad/s)
6.00 m/s
(f) Plug in the values and find y.
y = (0.0800 m) cos((75.0 rad/s) (2.00 s) − (0.300 m⁻¹) (1.00 m))
y = 0.0365 m
Doing specific exercises to improve a particular area of fitness is called flexibility? True or false
Answer:
True.
Explanation:
Exercises and yoga are important for the individual's health. The exercise makes the individual, fit, healthy and also reduces the chances of the deadly disease in human beings.
Different types of exercise can be performed by the individual. The aerobic exercises increase the amount of oxygen in the body. With the aerobic exercise, the exercise that can increase the strength, flexibility and total fitness must also be included.
The 2-mg Car Increases its
speed uniformly from rest to
28 m/s in 30s up the incline road
determine the maximum power
that must supplied by the engine
which operates with an efficiency
of e=0.8 Also find the
average power supplied by the
engine .
Answer:
0.35
Explanation:
Which of these types of land is included under special land use?
Answer:
Special land use basically include all land parcels that cannot be defined in terms of residential and commercial land uses.
Answer:
Applying pesticides
Explanation:
there is a limit on the use of pesticides and it is the only one that is truly applied water is naturally occuring same with rocks and trees and you are applying things to the soil not the other way around
Everyday activities do NOT produce significant muscle growth because:
A. Cytokines are released during everyday activities that inhibit (prevent) muscle regeneration.
B. Muscle growth requires going to the gym and lifting weights.
C. The nervous system cannot respond by recruiting more muscle fibers to generate hypertrophy.
D. The body adapts to the repeated demands so that those movements do not produce enough stress to cause hypertrophy (enlarging of the muscle).
Answer:
When elements bond together or when bonds of compounds are broken and form a new substance
Explanation:
Answer:
D
Explanation:
If a single circular loop of wire carries a current of 63 A and produces a magnetic field at its center with a magnitude of 1.70 10-4 T, determine the radius of the loop.
Answer:
The radius of the circular loop is 0.233 m
Explanation:
Given;
current on the circular loop, I = 63 A
magnitude of the magnetic field, B = 1.7 x 10⁻⁴ T
The magnetic field at the center of a circular loop is given by;
[tex]B = \frac{\mu I}{2R} \\\\[/tex]
Where;
R is the radius of the circular loop
μ is the permeability of free space = 4π x 10⁻⁷ T.m/A
Substitute the givens;
[tex]B = \frac{\mu I}{2R}\\\\R = \frac{\mu I}{2B}\\\\R = \frac{(4\pi*10^{-7})(63) }{2(1.7*10^{-4})}\\\\R = 0.233 \ m[/tex]
Therefore, the radius of the circular loop is 0.233 m
It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The radius of the circular loop is 0.233 m.
What is a magnetic field?It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.
The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength .it is denoted by B.
As we know that current is directly propotional to the induced magnetic field greater the current I, the greater the magnetic field B.
The given data in the problem is;
I is the value of current = 63 A
B is the megnetic field = 1.70 10⁻⁴ T
r is the radius of loop=?
μ is the permeability of free space = 4π x 10⁻⁷ T.m/A
The value of the megnetic field at the center is given by;
[tex]\rm B= \frac{\mu I}{2r} \\\\ \rm r= \frac{\mu I}{2B} \\\\ \rm r= \frac{4\pi \times 63}{2\times 1.7\times 10^{-4}} \\\\ \ \rm r=0.233 m[/tex]
Hence the radius of the circular loop is 0.233 m.
To learn more about the magnetic field refer to the link;
https://brainly.com/question/19542022
5. What is final temperature of the object with a heat capacity of 300 cal and a sp. Heat of
0.5 cal/g°C? The mass of the object is 200 g and the initial temperature is 0 degrees
Celsius.
Answer:
3°C
Explanation:
Given parameters:
Heat capacity = 300cal
Specific heat capacity = 0.5cal/g°C
Mass of the object = 200g
Initial temperature = 0°C
Unknown:
Final temperature = ?
Solution:
The heat capacity is the amount of heat required to raise the temperature of a substance by 1°C;
Mathematically ;
H = m c x (t₂ - t₁)
H is the heat capacity
m is the mass
c is the specific heat capacity
t is the temperature
Insert the parameters and solve;
300 = 200 x 0.5 x (t₂- 0 )
100 t₂ = 300
t₂ = 3°C
A car having a total mass of 2250 kg and traveling at 72.0 km/h smashes into a tree. The car is stopped in 0.250 s. The average force acting on the car during the collision is
A. 1.80, 105 N.
B. 80.0 N.
C. 1.80 102 N
D. zero. E. 2.20 104
Answer:
A. 1.8x10⁵
Explanation:
For this question we have
72km/h = speed
Total mass = 2250kg
Stopped at t = 0.2250s
To get average force acting on this car on collision:
72km/3.6 = 20m|s
Impulse = ∆p
This implies:
F∆t = m∆v
F = m∆v/∆t
= 2250x20/0.250
= 180000
= 1.8x10⁵
Therefore option A is correct.
A baseball player hits a ball with a bat. At one moment the force exerted by the bat on the ball is 18,000 N. At that same moment, how much force is exerted on the bat by the ball?
a) 18,000 N
b) less than 18,000 N
c) more than 18,000 N
Answer:
Less than 18000N
Explanation:
Given
[tex]Force\ Exerted = 18000N[/tex]
This question will be answered using Newton's third law.
Understanding this law, it implies that reaction force is equal and opposite to the force exerted.
This implies that;
If the force exerted on the ball is 18000N
the force exerted is -18000N
So, the option that answers the question is less than 18000N because -18000N < 18000N
The difference in a brass rod and steel rod is same as 12cm at all temperature .Find the length of the rod at 0°C.(Alpha b =18×10^-6k^-1 and alpha s =12×10^-6k^-1)
Answer:
length of brass=24cm and length of steel rod=36cm
what is Force and Preasure ??
Answer:
Definition: Pressure:- Force per unit area surface is called pressure. P = F/ A Pressure = Force /Area Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed. Gauge pressure is the pressure relative to the ambient pressure.
Answer:
A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects. When the interaction ceases, the two objects no longer experience the force.
Pressure is defined to be the amount of force exerted per area.
Formula of pressure = P = F÷A
Where, P = Pressure,
F = Force applied and,
A = Unit area.
Examples of Pressure is Air pressure.
A 55-kg woman is wearing high heels. If each heel has a circular cross-section 6.0 mm in diameter and she puts all her weight on one heel, how much pressure does that exert on the floor
Answer:
The pressure exerted by the woman on the floor is 1.9061 x 10⁷ N/m²
Explanation:
Given;
mass of the woman, m = 55 kg
diameter of the circular heel, d = 6.0 mm
radius of the heel, r = 3.0 mm = 0.003 m
Cross-sectional area of the heel is given by;
A = πr²
A = π(0.003)²
A = 2.8278 x 10⁻⁵ m²
The weight of the woman is given by;
W = mg
W = 55 x 9.8
W = 539 N
The pressure exerted by the woman on the floor is given by;
P = F / A
P = W / A
P = 539 / (2.8278 x 10⁻⁵ )
P = 1.9061 x 10⁷ N/m²
Therefore, the pressure exerted by the woman on the floor is 1.9061 x 10⁷ N/m²
A 4.5 kg block is pulled across a table by a horizontal force of 42 N. The frictional force
opposing the motion is 7.5 N. Calculate the acceleration of the object.
Answer:
7.67m/s²
Explanation:
The net force on the block is;
Net force = Force of pull - Frictional force
mass of block = 4.5kg
force of pull = 42N
Frictional force = 7.5N
Net force = 42 - 7.5
Force = mass x acceleration
ma = 34.5
4.5 x a = 34.5
a = [tex]\frac{34.5}{4.5}[/tex] = 7.67m/s²
Claudia stubs her toe on the coffee table with a force of 100.ON. A) What is the
acceleration of Claudia's 1.80kg foot? B) What is the acceleration of the table if it has a mass
of 20.0kg? (ignore any frictional effects) C) Why would Claudia's toe hurt less if the table had
less mass?
Answer:
A.) acceleration= 55.6m/s^2
B.) acceleration of table= 5.0m/s^2
C.) More acceleration
Explanation:
A.) 100N/1.8kg= -55.6
B.) 100N÷20kg= 5
C.) Because since the table would have less mass, it would have had to accelerate more
A stationary object is pushed with a force of 400N for 8s, resulting in its having a final velocity of 24m/s. What is its mass?
Answer:
The mass of the object is 133.33 kg
Explanation:
From Newton's second law of motion
F = ma
Where F is the force
m is the mass
and a is the acceleration
From the question,
A stationary object is pushed with a force of 400N, that is F = 400N. To determine the mass of the object,
First, we will determine the acceleration.
From one of the equations of kinematics for linear motion,
v = u + at
Where v is the final velocity
u is the initial velocity
a is the acceleration
and t is time
We can write that
v - u = at
Then, a = (v - u) / t
From the question,
t = 8s
v = 24m/s
u = 0 m/s (Since the object was stationary, that is, it was pushed from rest)
∴ a = (24m/s - 0m/s) / 8s
a = 24 / 8 = 3 m/s²
Therefore, acceleration is 3 m/s²
Now,
From F = ma
m = F / a
From the question
F = 400N
∴ m = 400N / 3m/s²
m = 133.33 kg
Hence, the mass of the object is 133.33 kg.
PLEASE PROVIDE AN EXPLANATION
THANK YOU!
Answer:
(a) 0.993 s
(b) 14.0 N/m
(c) -3.02 m/s
(d) -6.01 m/s²
Explanation:
(a) The block's position can be modeled as a cosine wave:
x(t) = A cos(ωt)
where A is the amplitude (in this case, 50 cm) and ω is the angular frequency.
At t = 0.200 s, x(t) = 15.0 cm.
15.0 cm = 50.0 cm cos((0.200 s) ω)
0.3 = cos((0.2 s) ω)
1.266 rad = (0.2 s) ω
ω = 6.33 rad/s
The period is:
T = (2π rad) (1 s / 6.33 rad)
T = 0.993
(b) For a spring-mass system, ω = √(k/m). The mass of the block is 0.350 kg, so:
ω = √(k/m)
6.33 rad/s = √(k / 0.350 kg)
6.33 rad/s = √(k / 0.350 kg)
40.1 rad/s² = k / 0.350 kg
k = 14.0 N/m
(c) Energy is conserved:
EE₀ = EE + KE
½ kx₀² = ½ kx² + ½ mv²
kx₀² = kx² + mv²
(14.0 N/m) (0.50 m)² = (14.0 N/m) (0.15 m)² + (0.35 kg) v²
v = -3.02 m/s
Alternatively, we can take the derivative of our position equation:
v(t) = -Aω sin(ωt)
v = -(0.50 m) (6.33 rad/s) sin((6.33 rad/s) (0.2 s))
v = -3.02 m/s
(d) Sum of forces on the block:
∑F = ma
-kx = ma
a = -kx / m
a = -(14.0 N/m) (0.15 m) / (0.350 kg)
a = -6.01 m/s²
Alternatively, we can take the derivative of our velocity equation:
a(t) = -Aω² cos(ωt)
a = -(0.50 m) (6.33 rad/s)² cos((6.33 rad/s) (0.2 s))
a = -6.01 m/s²
What are alkaline earth metals used for?
A. solar cells
B. jewelry
C. fireworks
D. insulation
Answer:
C firework
Explanation:
from Quizlet
The table shows the specific heat capacities of various substances. How much energy is required to raise the temperature of 5g of air by 10°C? Use the table below to help you.
Answer:
Q = 50.25 [J]
Explanation:
To solve this problem we must use the following equation that relates the temperature change with the mass and with the specific heat.
Q = m*Cp*(DT)
where:
Q = energy in form of heat [J]
m = mass = 5 [g] = 0.005 [kg]
Cp = specific heat = 1005 [J/kg*°C]
DT = temperature change = 10 [°C]
Now replacing:
Q = 0.005*1005*10
Q = 50.25 [J]
Unscramble heenagwirt
Answer:
weathering
Explanation:
Can someone please help me I don’t understand this please show work plus I got it wrong it’s not C
If you are riding your bike west to your friend’s house, and you ride the 1.25 miles in 5 minutes, what is your velocity, in miles per hour?
Answer:
velocity = 15 miles / hourExplanation:
distance = 1.25 mile
time traveled = 5 min.
find velocity in miles / hour
solution:
use the formula: velocity = distance / time
velocity = 1.25 mile x 60 min
5 min 1 hour
velocity = 15 miles / hour
The power rating of a 400-ΩΩ resistor is 0.800 W.
Required:
a. What is the maximum voltage that can be applied across this resistor without damaging it?
b. What is the maximum current it can draw?
Answer:
voltage= 17.88volts
current= 0.04 amps
Explanation:
Step one:
given data
resistance R=400 ohms
Power P= 0.8W
a. What is the maximum voltage that can be applied across this resistor without damaging it?
the expression relating power and voltage is
P=V^2/R
substituting we have
0.8=V^2/400
V^2=0.8*400
V^2=320
V=√320
V=17.88 volts
the maximum voltage is 17.88volts
b.What is the maximum current it can draw?
we know that from Ohm' law
V=IR
17.88=I*400
I=17.88/400
I=0.04amps
* WILL GIVE BRAINLIEST TO CORRECT ANSWER *
Name a product that people commonly purchase by mass and not by weight.
I would say food but like they take weight too
Use Newton’s first law to explain why a book on a desk does not move
Answer:
nothing moves if anything other doesn't move it.
natural position of things is the resting
Explanation:
yeah that's it
Answer:
The book does not move because all the forces acting on the book are in equilibrium, creating a net force of zero magnitude on the book. Since the net force on the book is zero, this means that the book will remain in its present state of motion (which is that the book is motionless).
Explanation:
Newton's first law states that all body will remain in their present state of motion unless acted upon by an external force. In order word, a moving body should continue moving forever, and a body at rest should remain like that forever, unless they are acted upon by a force to either cause them to stop stop or to start moving respectively.
In the Bohr model of the atom, atomic electrons approximatately 'orbit' the nucleus. The hydrogen atom consists of a proton of mass 1.67 × 10-27 kg and an orbiting electron of mass 9.11 × 10-31 kg. In one of its orbits, the electron is 5.3 × 10-11 m from the proton. What is the mutual attractive gravitational force between the electron and proton
Answer:
[tex]F=3.61\times 10^{-47}\ N[/tex]
Explanation:
Mass of a proton, [tex]m_p=1.67\times 10^{-27}\ kg[/tex]
Mass of an electron, [tex]m_e=9.11\times 10^{-31}\ kg[/tex]
The distance between the electron and the proton is, [tex]r=5.3\times 10^{-11}\ m[/tex]
We need to find the mutual attractive gravitational force between the electron and proton. The gravitational force is given by :
[tex]F=G\dfrac{m_em_p}{r^2}[/tex]
Where G is the universal Gravitational constant
[tex]F=6.67\times 10^{-11}\times \dfrac{9.11\times 10^{-31}\times 1.67\times 10^{-27}}{(5.3\times 10^{-11})^2}\\\\F=3.61\times 10^{-47}\ N[/tex]
So, the force between the electron and proton is [tex]3.61\times 10^{-47}\ N[/tex].
