what kind of growth model (pattern) is showen in the table x 1, 2, 3, 4, 5 y 5, 25, 125 ,635 ,3,125

Answer:

Step-by-step explanation:

The subject in a statistical research work usually refer to the participants involved in the experiment which is usually a quantitative research.

The subjects in this study are all the overweight cats including those in the control and treatment groups.

Answer:

c. 2.2%

Step-by-step explanation:

The total number of all students in all fields, male and female is 4663.

There are 103 female research scientists.

p(female scientist) = 103/4663 = 0.022 = 2.2%

Answer:

A

Step-by-step explanation:

Answer:

[tex]\huge\boxed{\text{Domain:}\ D=\mathbb{R}=(-\infty;\ \infty)}\\\boxed{\text{Range:}\ R=\mathbb{R}=(-\infty;\ \infty)}[/tex]

Step-by-step explanation:

y = 4x - 5 + 3 = 4x - 2

It's an equation of a line in the slope-intercept form.

y = 4x - 2 → f(x) = 4x - 2 - it's a lienar function.

The domain of a linear function is the set of all real numbers.

If a slope of linear function is different than 0, then the range is the set of all real numbers.

Answer: negative infinity to infinity and 3 to infinity

Step-by-step explanation:

edge 2023

Answer:

8 miles OR 8.0 miles

Answer:

Step-by-step explanation:

[tex](\sqrt{2}+3)^2=(\sqrt{2})^2 + 6\sqrt{2}+9 = 6\sqrt{2} +9+2=6\sqrt{2}+11[/tex]

hope this helps

Answer:

97

Step-by-step explanation:

y=mx+b

m= slope

y=97x+1

Answer:

x= -1

Step-by-step explanation:

Solving through linear equation,

-0.1x + 3/10= 4/10

Bring 3/10 to the other side making it minus

-0.1x = 4/10 - 3/10

-0.1x = (4-3)/10

-0.1x= 1/10

Bring -0.1 to the other side n divide

x= 1/10 ÷ -0.1

( Note that -0.1 is the same as -1/10)

x = 1/10 ÷ -1/10

= 1/10*-10/1

= -10/10

= -1

Answer:

D. 71.61 ft

Step-by-step explanation:

A=pi*r^2

408.3=pi*r^2

solve for r

r=11.4 ft

C=2*pi*r

C=2*pi*11.4=71.61 ft

Answer:

Perimeter: 2l+2w

Area: lw

Step-by-step explanation:

Let l=length, and w=width

Answer:

For Perimeter its  2times length + 2times width

and for Area its: length times width

Hope this helps :)

Answer: 5/8

Step-by-step explanation:

Answer:

k = [tex]\frac{5}{8}[/tex]

Step-by-step explanation:

The standard form of an equation representing proportion is

y = kx ← k is the constant of proportionality

y = [tex]\frac{5}{8}[/tex] x ← is in this form

with k = [tex]\frac{5}{8}[/tex]

Answer:

x=29

Step-by-step explanation:

isolate x, and multiply the 29 by -1

Answer:

previous speed of the aeroplane is 500 km/hr

Step-by-step explanation:

Given: Distance covered by  aeroplane = 1500 km

It covers the same distance in a time which is half an hour less than the previous time if the speed is increased by 100 km/hr

To find: previous speed of the aeroplane

Solution:

Let x denotes the previous speed of the aeroplane.

Time taken by an aeroplane if speed is x km/hr = distance/speed = [tex]\frac{1500}{x}[/tex] hours

If speed is increased by 100 km/hr, new speed = (x + 100) km/hr

Time taken by an aeroplane if speed is (x + 100) km/hr = [tex]\frac{1500}{x+100}[/tex] hours

According to question,

[tex]\frac{1500}{x+100}=\frac{1500}{x}-\frac{1}{2}\\ \frac{1500}{x}-\frac{1500}{x+100}=\frac{1}{2} \\\frac{1}{x}-\frac{1}{x+100}=\frac{1}{3000}\\ \frac{x+100-x}{x(x+100)}=\frac{1}{3000}\\ x^2+100x=300000\\x^2+100x-300000=0\\[/tex]

[tex]x^2+600x-500x-300000=0\\x(x+600)-500(x+600)=0\\(x-500)(x+600)=0\\x=500\,,\,-600[/tex]

As speed can not be negative, [tex]x=-600[/tex] is rejected.

So,

previous speed of the aeroplane is 500 km/hr

Answer:

(a). Range is 6 (b). Mode is 5.75

Step-by-step explanation:

Finding range: Subtract the smallest value (2) from the largest value (8).

Finding mode: Add all the values (for each "x" you add the value that it corresponds to) and then divide them by the number of x's.

Answer:

x = 11

Step-by-step explanation:

Answer:

x = 11

Step-by-step explanation:

3x11 = 33

4+3 = 7

33 + 7 = 40

Answer: B

Negative a squared b and 5 a squared b

Step-by-step explanation:

Given that:

Negative a squared b + 6 a b minus 8 + 5 a squared b minus 6 a minus b. That is,

- a^2b + 6ab - 8 + 5a^b - 6a - b

Collecting the like term by rearranging the expression

5a^2b - a^2b + 6ab - 6a - b

The like terms in the expression above are

5a^2b - a^2b.

The correct option is B:

Negative a squared b and 5 a squared b or (-a^2b and 5a^b)

Answer:

B

Step-by-step explanation:

Negative a squared b and 5 a squared b

Step-by-step explanation:

Given that:

Negative a squared b + 6 a b minus 8 + 5 a squared b minus 6 a minus b. That is,

- a^2b + 6ab - 8 + 5a^b - 6a - b

Collecting the like term by rearranging the expression

5a^2b - a^2b + 6ab - 6a - b

The like terms in the expression above are

5a^2b - a^2b.

The correct option is B:

Negative a squared b and 5 a squared b or (-a^2b and 5a^b)

Answer:

30 and 32

Step-by-step explanation:

Answer:

[tex]=x^2+12x+35[/tex]

Step-by-step explanation:

[tex]\left(x+7\right)\left(x+5\right)[/tex]

[tex]\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd[/tex]

[tex]a=x,\:b=7,\:c=x,\:d=5\\=xx+x\cdot \:5+7x+7\cdot \:5\\=xx+5x+7x+7\cdot \:5\\=x^2+12x+35[/tex]

Answer:

" Expected Payoff " ⇒ $ 0.830

Step-by-step explanation:

Consider the probability of entering 1 ticket out of the 1000 entered;

[tex]Total Tickets Entered - 1000 Tickets,\\Prize Won - 830 Dollars,\\Number of Tickets One Can Enter - 1 Ticket,\\\\Probability of Winning - 1 / 1000,\\Proportionality - 1 / 1000 = x / 830, If x = " Expected Payoff ",\\\\1 / 1000 = x / 830 - Cross Multiplication ,\\1000 * x = 830,\\x = 830 / 1000 = 0.830\\\\Conclusion ; x = 0.83[/tex]

Solution ; " Expected Payoff " ⇒ $ 0.830 ( might or might not include 0 at end )

Answer:

I guess the answer is c.... I guess it must be c

Answer: The equation is 45-10=x the answer is 35

Step-by-step explanation: To make the equation you need to have and = sign so, we can do what he has (45) and subtract what he gives away (10) which would equal what he has left (x)

Answer:

45 (initial amount) - 10 (given to brother) = x (number of cd's left)

Equation:

    45 - 10 = x

Answer:

    35 CDs

Answer:D

Step-by-step explanation:

Answer:

[tex]x=log_{1.5}(\frac{y}{20})[/tex]

Step-by-step explanation:

Considering the function:

[tex]f(x) = 20\, (1.5)^x[/tex]

The independent variable is "x" and we are asked to model it in terms of the variable "y":

[tex]f(x) = 20\, (1.5)^x\\y=20\, (1.5)^x[/tex]

Then, in order to solve for x (which resides in the exponent), we need to use the logarithm function.

Since the base of the exponent is 1.5, we need to use the logarithm base 1.5, to lower that exponent "x":

[tex]y=20\, (1.5)^x\\\frac{y}{20} =(1.5)^x\\log_{1.5}(\frac{y}{20}) =x\\x=log_{1.5}(\frac{y}{20})[/tex]

Step-by-step explanation:

4/9x-10>x/3-12

3 4/9x-3 10>x/3-12

4/3x-10>x-12

3 4/3x-3(10>x)-3(12)

4x-30x<-36

26x<-36

Answer:

  a) 50π cm^2

  b) π/8

Step-by-step explanation:

a) The formula for the area of a semicircle is ...

  A = (1/2)πr^2 = (1/2)π(d/2)^2 = (π/8)d^2

For a diameter of 20 cm, the area is ...

  A = (π/8)(20 cm)^2 = 50π cm^2 . . . . . the area of the semicircle

__

The formula for the area of a quarter circle is ...

  A = (1/4)πr^2

For a radius of 20 cm, the area is ...

  A = (π/4)(20 cm)^2 = 100π cm^2 . . . . . the area of the quarter circle

__

The shaded area is the difference of the areas of the quarter circle and semicircle:

  shaded area = (100π cm^2) -(50π cm^2)

  shaded area = 50π cm^2

__

b) The ratio of the shaded area to the square area is ...

  shaded area / square area = (50π cm^2)/(20 cm)^2 = π/8

Answer:

- 1 4/5

Step-by-step explanation:

-1 1/5 + - 3/5

Since the signs are the same, we add and take the sign

1 1/5 + 3/5

1 4/5

The sign is negative

- 1 4/5

On the number line start at - 1 1/5 and go to the left 3/5( since the sign is negative)  you will end up at - 1 4/5

_______________________________

Hey!!!

Solution,

2x+2x+3x=77

or,7x=77

or,X=77/7

X=11

Replacing value,

2x=2*11

=22

3x=3*11

=33

So, Brian gets £ 22.

Kritika gets £ 22

Peter gets £ 33

Hope it helps...

Good luck on your assignment

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