Answer:
y becomes doubled.
Explanation:
If;
y = [tex]\frac{k}{x}[/tex]
what is the state of y when x is halved;
the given expression is an inverse relationship. When y increases, x is supposed to decrease and vice versa.
if x is halved; x = [tex]\frac{x}{2}[/tex]
[tex]\frac{k}{\frac{x}{2} }[/tex] = [tex]\frac{2k}{x}[/tex]
Now compare :
[tex]\frac{k}{x}[/tex] : [tex]\frac{2k}{x}[/tex]
we see that y becomes doubled
a (n) net is the overall force on a object
Answer:
net force
Explanation:
The net force is the vector sum of all the forces acting on an object.
An inventor claims to have invented a heat engine that receives 750kJ of heat from a source at 400K and produces 250kJ of net work while rejecting the waste heat to a sink at 300K. Is this a reasonable claim
Answer:
the claim is not valid or reasonable.
Explanation:
In order to test the claim we will find the maximum and actual efficiencies. maximum efficiency of a heat engine can be found as:
η(max) = 1 - T₁/T₂
where,
η(max) = maximum efficiency = ?
T₁ = Sink Temperature = 300 K
T₂ = Source Temperature = 400 K
Therefore,
η(max) = 1 - 300 K/400 K
η(max) = 0.25 = 25%
Now, we calculate the actual frequency of the engine:
η = W/Q
where,
W = Net Work = 250 KJ
Q = Heat Received = 750 KJ
Therefore,
η = 250 KJ/750 KJ
η = 0.333 = 33.3 %
η > η(max)
The actual efficiency of a heat engine can never be greater than its Carnot efficiency or the maximum efficiency.
Therefore, the claim is not valid or reasonable.
g A 320-g air track cart is traveling at 1.25 m/s and a 270-g cart traveling in the opposite direction at 1.33 m/s. What is the speed of the center of mass of the two carts
Answer:
1.287m/s
Explanation:
Using the law of conservation of mass expressed as;
m1u1+m2u2 = (m1+m2)v
m1 and m2 are the masses of the objects
u1 and u2 are the velocities
v is the speed of the center of mas of the two carts
Given
m1 = 320g = 0.32kg
u1 = 1.25m/s
m2 = 270g = 0.27kg
u2 = 1.33m/s
Substitute this value into the formula and get v;
0.32(1.25)+0.27(1.33) = (0.32+0.27)v
0.4+0.3591 = 0.59v
0.7591 = 0.59v
v = 0.7591/0.59
v = 1.287m/s
hence the speed of the center of mass of the two carts is 1.287m/s
How much thermal energy (in kcal) is required to change a 43 g ice cube from a solid at - 16.5 oC to steam at 11.5 oC above boiling
Answer:
The total thermal energy required is 8.93 Kcal
Explanation:
Given;
mass of the ice cube, m = 43 g
specific heat capacity of water, Cp = 4.18 J/gc
specific latent heat of fusion of ice, Cf = 334 J/g
First step, determine the heat needed to raise the temperature of the ice from -16.5 °C to 0° C
Q₁ = mCp[0 - (-16.5)]
Q₁ = 43 x 4.18(16.5)
Q₁ = 2965.71 J
Second step, determine the latent heat of fusion of ice at 0°C
Q₂ = mCf
Q₂ = 43 x 334
Q₂ = 14362 J
Third step, determine the quantity of heat required to raise the temperature of the water initially at 0°C to above 11.5 °C of boiling point of water.
The final temperature of the water = 11.5 °C + 100° C = 111.5 °C
Q₃ = mCp Δθ
Q₃ = 43 x 4.18 (111.5 - 0)
Q₃ = 20041 J
Total thermal energy required = Q₁ + Q₂ + Q₃
Total thermal energy required = 2965.71 J + 14362 J + 20041 J
Total thermal energy required = 37,368.71 J
Total thermal energy required = 8.93 Kcal
A 14000 kg tank moving at 9 m/s is brought to a halt in 2.5 s by a reinforced-steel tank barrier. What magnitude of the impulse was imparted to the tank
Answer
The value is [tex]I = 126000 \ kg \cdot m/s[/tex]
Explanation
From the question we are told that
The mass of the tank is [tex]m = 14000 \ kg[/tex]
The speed is [tex]u = 9 \ m/s[/tex]
The duration taken to bring it to a stop is [tex]\Delta t = 2.5 \ s[/tex]
Generally the impulse that was imparted on the tank is mathematically represented as
[tex]I = m (u - v )[/tex]
Generally the v is the final velocity of the tank which is v = 0 m/s , given that it was brought to rest
So
[tex]I = 14000 (9 - 0 )[/tex]
=> [tex]I = 126000 \ kg \cdot m/s[/tex]
Impulse is defined as the mass and change of velocity. The magnitude of the impulse was imparted to the tank 126000 Kg m/sec.
What is impulse?
The force which acts on the body for a short interval of time is known as the impulsive force. The impulsive force is defined as the product of force and the duration for the force is applied.
It is denoted by I. Its unit is kgm/sec.
m is the mass of the tank = 14000 kg
v is the final speed = 9 m/s
u is the initial speed =0
t is the time interval = 2.5 sec.
The formula for impulse is given as ;
[tex]\rm I=\frac{m(v-u)}{t} \times t \\\\ \rm I=m(v-u) \\\\ \rm I=14000(9-0)\\\\\rm I= 126000 \;kgm/sec[/tex]
Hence the magnitude of the impulse was imparted to the tank 126000 Kg m/sec.
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insulator allows the electric current to pass through it true or false please anyone please please please
how can we show the magnetic force of a magnet illustrate with an example
Answer:
take some sharp mixture of iron spread it from up the magnet you will see the magnetic field of magnet
Fast and safe heart rate for workouts is called muscular strength? True or false
Answer:
False
Explanation:
Answer:
false :3
hope this helps
Hurry please
The distance from wave to wave is called what
Answer:
Wavelength
Explanation:
Suppose an electric eel develops a potential difference of 450 V driving 0.80 A during a 1.0 ms pulse. What is the power output of the eel during this pulse
Answer:
The power output is [tex]P = 360 \ W[/tex]
Explanation:
From the question we are told that
The potential difference developed is [tex]V = 450 V[/tex]
The current is [tex]I = 0.80 \ A[/tex]
The duration of the pulse is [tex]\Delta t = 1.0 ms = 1,0 *10^{-3} \ s[/tex]
Generally the power output of the eel during the pulse is mathematically represented as
[tex]P = V * I[/tex]
=> [tex]P = 450 * 0.80[/tex]
=> [tex]P = 360 \ W[/tex]
what is the mass of an object that is accelerating at 15 m/s when a force of 2000N is exerted
Answer:
133.33 kgExplanation:
The mass of an object can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{2000}{15} = \frac{400}{3} \\ = 133.3333[/tex]
We have the final answer as
133.33 kgHope this helps you
Define SI system of measurement.
Answer:
SI system - a complete metric system of units of measurement for scientists; fundamental quantities are length (meter) and mass (kilogram) and time (second) and electric current (ampere) and temperature (kelvin) and amount of matter (mole) and luminous intensity (candela); "Today the United States is the only country
Explanation:
hope this helps u, sorry if it doesn't.
Answer:
International System of Units (SI), French Système International d'Unités, international decimal system of weights and measures derived from and extending the metric system of units. Adopted by the 11th General Conference on Weights and Measures (CGPM) in 1960, it is abbreviated SI in all languages
2 examples of where ground water comes from
Answer: Example of ground water
Explanation: Groundwater is part of the hydrologic cycle, originating when part of the precipitation that falls on the Earth's surface sinks (infiltrates) through the soil and percolates (seeps) downward to become groundwater.
PLS HURRY!!!! 15 PTS!!! The pictures represent three different states of matter.
Which order of pictures places molecules with the most
amount of motion to the least amount of motion?
O X Y Z
O ZYX
O Y Z
O Y - X - Z
I'll give brainliest if you give me a good awnser. :)
A football player kicks a ball with a force of 50 N. Find the impulse on the ball if his foot stays in contact with the football for 0.01 second.
Answer:
0.5
Explanation:
How is mass-energy equivalence demonstrated in the Sun?
Hydrogen nuclei fuse to form a larger nucleus, and a small amount of mass is converted into energy.
Hydrogen nuclei fuse to form a larger nucleus by absorbing a large amount of energy and converting it into a small amount of mass.
Hydrogen nuclei form from smaller nuclei, and a small amount of mass is converted into energy.
Hydrogen nuclei form from smaller nuclei by absorbing a large amount of energy and converting it into a small amount of mass.
Answer:
Explanation:
Hydrogen nuclei fuse to form a larger nucleus, and a small amount of mass is converted into energy.
The mass difference between a helium nucleus and four hydrogen nuclei is 0.7%; this mass difference is transformed into energy during the fusion process. Each mole of He42 created as a result of this reaction generates around 3.6 1011 kJ of energy. Thus, option A is correct.
What Hydrogen nuclei fuse to form a larger nucleus?Hydrogen is exhausted during the fusion of hydrogen nuclei, which creates helium and energy. The process's fuel is hydrogen. The star's core condenses and heats up further as the hydrogen is consumed.
For instance, 0.645% of the mass is lost during the fusion of two hydrogen atoms to create helium in the form of electromagnetic radiation or the kinetic energy of an alpha particle. Even those of the lightest element, hydrogen, require a significant amount of energy to get their nuclei to fuse.
Due to this, heavier and heavier elements are encouraged to fuse together, eventually creating all the elements up to iron.
Therefore, Hydrogen nuclei fuse to form a larger nucleus, and a small amount of mass is converted into energy.
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A boat can travel 2.30 m/s in still water. If the boat points its prow directly across a stream whose current is 1.80 m/s , what is the magnitude of the velocity of the boat relative to the shore?
Answer:
A boat can travel 2.30 m/s in still water. (a) If the boat points its prow directly across a stream whose current is. ... (a) What is the velocity (magnitude and direction) of the boat relative to the shore? ... The boat's velocity with respect to the shore, , is the sum of its velocity with respect to the water
Explanation:
What is the highest order dark fringe, , that is found in the diffraction pattern for light that has a wavelength of 575 nm and is incident on a single slit that is 1410 nm wide?
Answer:
The highest order dark fringe is 2
Explanation:
From the question we are told that
The wavelength is [tex]\lambda = 575 \ nm = 575 *10^{-9} \ m[/tex]
The width is of the slit is [tex]d = 1410 nm = 1410 *10^{-9} \ m[/tex]
Generally the highest order dark fringe is mathematically represented as
[tex]m = \frac{w}{\lambda }[/tex]
=> [tex]m = \frac{ 1410 *10^{-9}}{ 575 *10^{-9} }[/tex]
=> [tex]m =2[/tex]
An arrow in a bow has 357 J of elastic potential energy How much Winette enere
Will the arrow have after it has been shot assuming there is no sir restoran
Answer:
357 J
Explanation:
The elastic potential energy of arrow in the stretched bow is 357 J.
The kinetic energy of the arrow after it has been shot is given by half of the product of the arrow's mass and velocity of the arrow.
Here there are no other forms of energy at play here. Only potential and kinetic energy.
As we know that in any system the energy is conserved accordingly the elastic potential energy of the arrow will be equal to the kinetic energy of the bow after it is released i.e., 357 J.
A person who weighs 670 N steps onto a spring scale in the bath- room, and the spring compresses by 0.79 cm. (a) What is the spring con- stant
Answer:
The spring constant is 84,810.13 N/m
Explanation:
Given;
applied force on the spring scale, f = 670 N
extention of the spring, x = 0.79 cm = 0.0079 m
Apply Hook's law to determine the spring constant;
f = kx
where;
f is the applied force
k is the spring constant
x is the is the extension
k = f / x
k = 670 / 0.0079
k = 84,810.13 N/m
Therefore, the spring constant is 84,810.13 N/m
An archer shoots an arrow. Consider the action force to be the bowstring against the arrow. The reaction to this force is the:_____________
a. friction of the ground against the archer's feet.
b. grip of thhe archer's hand on the bow.
c. arrow's push against the bowstring.
d. combined weight of the arrow and bowstring
e. air resistance against the bow arrow.
Answer:
c. arrow's push against the bowstring.
Explanation:
Newtons third law of motion describe the relationship between action and reaction forces. Thus when the action force is applied by the bowstring against the arrow, a reaction to this force is supplied by the arrow's push against the bowstring.
If these two forces are not equal and opposite, the arrow would not move as expected. The elastic property of the bowstring propels the arrow at a rate which is due to the potential energy it has gained due to the stretching force.
A wheel accelerates with a constant angular acceleration of 4.5 rad/s2. If the initial angular velocity is 1.0 rad/s, what is the angle the wheel rotates through in 2.0 s?
Answer:
The angle which the wheel rotates through in 2 seconds is [tex]\theta =11 \ radians[/tex]
Explanation:
From the question we are told that
The constant angular acceleration of the wheel is [tex]\alpha = 4.5 rad/s^2[/tex]
The initial angular velocity of the wheel is [tex]w_1 = 1.0 \ rad/s[/tex]
The time duration considered is [tex]t = 2.0 \ s[/tex]
Generally from kinematic equation we have that
[tex]\theta = w_1 t +\frac{1}{2} \alpha t^2[/tex]
=> [tex]\theta = 1.0 * 2 +\frac{1}{2} * 4.5 * 2^2[/tex]
=> [tex]\theta =11 \ radians[/tex]
A block, whose mass is 0.500 kg, is attached to a spring with a force constant of 126 N/m. The block rests upon a frictionless, horizontal surface. A block labeled m is attached to the right end of a horizontal spring, and the left end of the spring is attached to a wall. The spring is stretched horizontally such that the block is displaced by a distance A to the right of its equilibrium position. The block is pulled to the right a distance A = 0.120 m from its equilibrium position (the vertical dashed line) and held motionless. The block is then released from rest. (a) At the instant of release, what is the magnitude of the spring force (in N) acting upon the block? N (b) At that very instant, what is the magnitude of the block's acceleration (in m/s2)? m/s2 (c) In what direction does the acceleration vector point at the instant of release?
Answer:
(a) F = 15.12 N
(b) a = 30.24 m/s²
(c) To Left
Explanation:
(a)
The magnitude of the spring force is given by Hooke's Law as follows:
F = kx
where,
F = Spring Force = ?
k = Spring Constant = 126 N/m
x = Displacement = A = 0.12 m
Therefore,
F = (126 N/m)(0.12 m)
F = 15.12 N
(b)
The magnitude of acceleration can be found by comparing the spring force with the unbalanced force formula of Newton's Second Law:
F = ma
where,
F = Spring Force = 15.12 N
m = mass of block = 0.5 kg
a = magnitude of acceleration = ?
15.12 N = 0.5 kg (a)
a = 15.12 N/0.5 kg
a = 30.24 m/s²
(c)
Since, the acceleration is always directed towards mean (equilibrium) position in periodic motion. Therefore, the direction of the acceleration at the time of release will be to left.
What part of the body acts as levelers
Answer: your feet are the foundation! Even though all your body parts are connected and affect one another, your feet are what we at Foot Levelers call, the "foundation".
Explanation:
where was the position of the singularity before the big bang ?
An elevator is pulled up by a cable with a force of 65,000 N. The upward acceleration of the elevator is 1.8 m/s/s. What is the mass of the elevator?
a. 1.8 kg.
b. 1700 kg.
c. 54880 kg.
d. 5600 kg.
e. 36111 kg.
Answer:
36111 kg
Explanation:
Given
Force = 65000N
Acceleration = 1.8m/s²
Required
Determine the mass of the elevator
This question will be answered using the following Force formula.
Force = Mass * Acceleration
Substitute values for Force and Acceleration
65000N = Mass * 1.8m/s²
Make Mass the subject
Mass = 65000N/1.8m/s²
Mass = 36111.11 kg
From the list of given options, option E answers the question.
Please help! ASAP. I'm going to have a panic attack.
Answer:
dont die bro
Explanation:
You are working out on a rowing machine. Each time you pull the rowing bar (which simulates the oars) toward you, it moves a distance of 1.1 m in a time of 1.3 s. The readout on the display indicates that the average power you are producing is 92 W. What is the magnitude of the force that you exert on the handle?
Answer:
The magnitude of force exerted on the handle is 108.73 N
Explanation:
To determine the magnitude of force exerted, we will use the formula relating Power and Force.
Power is the rate at which work is done. Power can be calculated from the formula
Power = Work / Time
But, Work = Force × Distance
Hence,
Power is given by the formula
[tex]P = \frac{F \times s}{t}[/tex]
Where P is the Power
F is the force
s is the distance
and t is the time
From [tex]P = \frac{F \times s}{t}[/tex],
Then we can write that
[tex]F = \frac{P \times t}{s}[/tex]
From the question,
Distance, s = 1.1 m
Time, t = 1.3 s
Power, P = 92 W
Putting these values into the formula, we get
[tex]F = \frac{92 \times 1.3}{1.1}[/tex]
[tex]F = \frac{119.6}{1.1}[/tex]
[tex]F = 108.73N[/tex]
Hence, the magnitude of force exerted on the handle is 108.73 N.
Select all that apply. The spectrum of Star Y is compared to a reference hydrogen spectrum. What can be concluded about Star Y? Reference (normal) Hydrogen Spectrum Star Y I 500 550 600 650 700 750 400 450 9200 OdyssepWare, Ing. Star Y is showing radial motion Star Y is moving away from the Earth Star Y is moving toward the Earth Star Y is showing transverse motion
Answer:
Star Y is showing radial motion
Star Y is moving toward the Earth
Explanation:
Just answered this question on a quiz and got it right.
Star Y is showing radial motion
Star Y is moving towards earth.
What is a spectrum ?Spectrum is defined as the arrangement of radiations emitted by atoms or molecules based on their characteristic wavelength and frequency.
Here,
The spectrum of the star Y is given and is compared to a reference hydrogen spectrum. The range of wavelengths of the star is given. The spectrum of the star shows that the wavelengths are shifted such that from longer wavelengths to shorter wavelength. This phenomenon of shift in wavelengths from higher to lower is known as blue shift. The star shows blue shift that means shifted to shorter wavelength or it can be said as shifted from lower frequency to higher frequency. As a result, it can be concluded that the star Y is moving towards the earth which implies Star Y is showing radial motion.
Hence,
The star Y is showing radial motion.
Star Y is moving towards the earth.
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When are zeros significant when found to the trailing (to the right) of the decimal point?
Answer:
Usually, zeroes are found to the right of a decimal point in significant numbers if you have something like [tex]7\frac{1}{100000000000000000000000000}[/tex] (exaggerated example of course), which is when you have a number that is very very close to the integer before it, but isn't that integer.
