Chemistry High School

What is the specific heat of ethanol if 4650 j are required to raise the temperature of 250.0g of ethanol from 22.0oc to 29.6 degrees Celsius

Answers

Answer 1

Answer:

[tex]C=2.45\frac{J}{g\°C}[/tex]

Explanation:

Hello there!

In this case, since the thermodynamic definition of heat in terms of mass, specific heat and temperatures is given by:

[tex]Q=mC(T_2-T_1)[/tex]

We are to calculate the specific heat of the ethanol as shown below:

[tex]C=\frac{Q}{m(T_2-T_1)}[/tex]

Thus, by plugging it the given data we can obtain:

[tex]C=\frac{4650J}{250.0g(29.6-22.00\°C)} \\\\C=2.45\frac{J}{g\°C}[/tex]

Regards!

Related Questions

Fill in the blank with the molar mass of calcium
nitrate. A link to the periodic table is provided for you.
g/mol

Answers

Answer: 61.98 is correct

Explanation:

Molar mass of calcium nitrate is 164 g/mole which is obtained by adding atomic weights of constituent elements.

What is molar mass?

Molar mass of a compound or a molecule is defined as the mass of the elements which are present in it.The molar mass is considered to be a bulk quantity not a molecular quantity. It is often an average of the of the masses at many instances.

The molecular mass and formula mass are used as synonym for the molar mass.It does not depend on the amount of substance which is present in the sample.It has units of gram/mole.

Molar masses of an element are given as relative atomic masses while that of compounds is the sum of relative atomic masses which are present in the compound.

Molar mass of calcium nitrate =40+[14+(16×3)]×2=164 g/mole.

Thus, the molar mass of calcium nitrate is 164 g/mole.

Learn more about molar mass,here:

https://brainly.com/question/12127540

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How many oxygen atoms are in 3.45 mol CaCO3

Answers

Answer:

The formula tells us that each mole of CaCO3 contains 3 moles of Oxygen. Then 3 moles of CaCO3 would contain 3 X 3 or 9 moles of Oxygen. I mole is define as avogadro’s number of units. Avogadro’s number is 6.02 X 10^23. so the answer is 3 X 3 X 6.02 X 10^23. = 5.42 X 10^24

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