What is the slope of a line that is parallel to the line y = 3/4x + 2?

Answer:

D.) x - 4

Step-by-step explanation:

This is a graph of an exponential/quadratic function. There general structure looks like this:

ax² + bx + c

Generally, when finding the zeros these functions, you are told to factor the equation. Once you have factored the equation, you can set the factors equal to zero to find the points where the function touches the x-intercept.

That being said, you can determine the factors without having the entire equation by identifying the zeros on the function. On this graph, there is a zero at (4,0). This means that one of the factors must have been "x - 4". You can check your work by setting the factor equal to zero.

x - 4 = 0

x = 4

Answer:

72  sq cm

Step-by-step explanation:

For any rectangle, the diagonal is the hypotenuse of the right triangle formed by the base of the rectangle(b) and the height (h) of the rectangle

By the Pythogorean formula

[tex]d^{2} = b^{2} + h^{2}[/tex]

where d is the diagonal

For a square, all sides are equal so b = h = a and we get the formula

[tex]d^{2} = a^{2} + a^{2} = 2a^{2}[/tex]

[tex]a^{2} = d^{2} /2[/tex]

In this case we have d =12 so

[tex]a^{2} = 12^{2} /2 = 144/2 = 72[/tex]

But for a square of side a, the area is [tex]a^{2}[/tex] so 72 is the area

Answer:

72 square cm

Step-by-step explanation:

       [tex]\sf \boxed{\bf Area = \dfrac{d^{2}}{2}}[/tex]  , here d is the length of the diagonal

                  [tex]\sf =\dfrac{12* 12 }{2}\\\\ = 6*2\\\\= 72 \ cm^2[/tex]

Answer:

[tex]\frac{3x^{4} }{2y^{4} }[/tex]

Step-by-step explanation:

Factor out 7 from top and bottom :

[tex]\frac{7(3x^6y^5)}{7(2x^2y^9)}[/tex]

Divide top and bottom by 7 :

[tex]\frac{3x^6y^5}{2x^2y^9}[/tex]

Simplify :  

[tex]\frac{x^6}{x^4}=x^{2}[/tex]

Simplify :

[tex]\frac{y^5}{y^9} = y^{-4} = \frac{1}{y^{4} }[/tex]

Collect everything together :

[tex]\frac{3x^{4} }{2y^{4} }[/tex]

Hope this helped and have a good day

Answer: (6, -31)

Explanation: See attachment

Answer:

its D. 2 and 3

Step-by-step explanation: supplementary angles are angles that add up to 180 (or that make a straight line) the angle pairs that make a straight line are 1 and 2, 2 and 3, 3 and 4, and 4 and 1.
So D would be correct

The statement that must be true about square WXYZ are as follows;

Therefore, the statement that must be true about square WXYZ are as follows;

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Given the egg has hatched, the egg was kept warmer than room temperature.

                      Cool      Room temperature        Warm             Total

Hatched           5              16                                21                  42

Unhatched        18           10                                 4                   32

Total                 23            26                                25                    74

To fill the blank we need to analyse the temperature carefully if see the table then cool hatched eggs are 5 , unhatched cool eggs are 18, eggs on room temperature and hatched are 16, eggs on room temperature and unhatched are 10, warm hatched eggs are 21 and warm unhatched eggs

So we can notice that hatched eggs are more in room temperature.

Hence hatched eggs are more in room temperature.

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Answer:

Given the egg has hatched the egg was kept warmer than room temperature.

Hope this helped!

Now out of these points, steps 5 and 6 are the main steps that ensure that the copied line segment is exactly the same as the original segment.

The steps to copy a line segment are given below:

1. Let's start with a line segment AB that we have to copy.

2. Now mark a point C. Below or above AB, which will be one endpoint of the new line segment.

3. Now, put the compass tip on point A of the line segment AB.

4. Spread the compass up to point B, so that the compass width is equal to the length of AB.

5. Without changing the compass width, now place the compass tip on point C that you made in step 2.

6. Now, draw an arc roughly without changing the compass settings. Mark that point D. This will form the new line segment.

7. Draw a line from C to D.

Now out of these points, steps 5 and 6 are the main steps that ensure that the copied line segment is exactly the same as the original segment.

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Answer:

8ax - 8bx + 4a - 4b

Step-by-step explanation:

(a - b)(2x - 3) + (6x + 7)(a - b)

2ax -3a -2bx +3b + 6ax - 6bx + 7a -7b

8ax + 4a - 8bx - 4b

Jeff should purchase 25 , 2 ounce box and it will cost him $27.5 .

Ounce is defined as 1/16 part of a pound.

It is given that

price of a 2-ounce box is $1.10,

a 16-ounce box is $8.98

a 32-ounce box is $17.98.

As Jeff wants to purchase total 48 ounce chocolates , the box which is more cheaper has to be determined  

The price of 1 ounce in a 2 ounce box is $1.1 /2 = $ 0.55

The price of 1 ounce in a 16 ounce box is $8.98 /16 = $ 0.56

The price of 1 ounce in a 32 ounce box is $17.98 /32 = $ 0.56

Therefore Jeff should purchase 25 , 2 ounce box and it will cost him $27.5 .

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Answer:

$42.95

Step-by-step explanation:

If Chris lost $8.59 playing poker in one week, in five weeks he would lose $42.95.

$8.59 lost per week.

5 weeks.

$8.59 x 5 = $42.95.

Hope this helps!

If not, I am sorry.

Answer:

0,5                    b

Step-by-step explanation:

Answer:

max weight truck can hold = 1200 pounds

your weight. 165 pounds

1200 - 165

1035 pounds left

3 pounds --- 1 brick

1035 --- ?

1035 / 3

You can haul 345 bricks in the truck.

An inequality is a relationship that makes a non-equal comparison between two numbers or other mathematical expressions e.g. 2x > 4.

From the given information, we have:

The amount of weight a truck can hold is limited to 1200 pounds.

You weigh 165 pounds and each brick weighs 3 pounds.

Number of bricks you can haul, b.

Thus, we can say:

Your weight + (Weight of each brick * Number of bricks)  ≤ Total weight capacity of the truck

165 + (3 * b) ≤ 1200

3b ≤ 1200 - 165

3b ≤ 1035

b ≤ 1035/3

b ≤ 345

Therefore, you can haul 345 bricks in the truck.

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The measure of the other side of a quadrilateral is [tex]3\sqrt{13}[/tex] cm.

In the given quadrilateral one side is unknown we need to find the unknown side.

By dividing the given quadrilateral into a rectangle and a triangle we can find the other side.

The Pythagoras theorem states that if a triangle is right-angled, then the square of the hypotenuse is equal to the sum of the squares of the other two sides. That is, [tex]c^{2}=a^{2}+b^{2}[/tex].

Now, [tex]x^{2} =9^{2}+6^{2}=81+36=17[/tex]

⇒[tex]x=\sqrt{13 \times 9} =3\sqrt{13}[/tex]

Therefore, the measure of the other side of a quadrilateral is [tex]3\sqrt{13}[/tex] cm.

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True. All natural numbers N are integers Z, but not all integers are natural numbers.

Natural numbers:

Integers:

Since natural numbers are all positive, N is positive integers but not all integers are natural numbers.

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The value of the angles x,y, and z is 73 degrees,88 degrees, and 55 degrees.

We have given that,

Two overlapping triangles

Here we have the angle Z and 52

The sum of the all angle in a triangle is 180 degrees.

Therefore we have

The Z+43+52+40=180

Z+125=180

Z=55

Therefore in a triangle degree 52 degrees and 40 degree

y+52+40=180

y+92=180

y=180-92

y=88 degrees

For the angle x, we have

x+15+40+52=180

x+107=180

x=180-107

x=73

The value of the angles x,y, and z is 73 degrees,88 degrees, and 55 degrees.

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The probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one trial is 9% will be 0.000343311 %

Probability is synonymous with possibility. It is concerned with the occurrence of a random event.

Probability can only have a value between 0 and 1. Its simple notion is that something is very likely to occur. It is the proportion of favorable events to the total number of events.

No of failure,n = 7

No of trials,x≥6

A binomial probability is represented as;

[tex]\rm P(x) = nC_x p^z(1-p)^{n-r}[/tex]

Substitute the given data;

[tex]P(x \geq 6) = 7C_6 \times 9^6 \times 91-9)^{7-6} +7C_7 (9)^7+(1-9)^{(7-7)}[/tex]

[tex]\rm P(x \geq 6) = 0.000000343311 \\\\ P(x \geq6)=0.000343311 \%[/tex]

Hence,the probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one trial is 9% will be 0.000343311 %

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The decimal: 0.4545...

Can be written in fraction form as 45/99.

Here we have the number:

N = 0.4545...

Notice that the repeating digits are two, 4 and 5.

Then we can multiply our number by 100 (same number of zeros as repeating digits) so we get:

100*0.4545... = 45.4545...

Now if we subtract the original number, we get:

45.4545... - 0.4545... = 45

This means that:

(100 - 1)*0.4545... = 99*0.4545... = 45

Then we can multiply and divide our number by 99, so we get:

[tex]0.4545... = 0.4545...\frac{99}{99} = \frac{45}{99}[/tex]

So the fraction is 45/99

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Answer:

Step-by-step explanation:

0P=OA+AP

    =OA+2/5(AB)
    =(4,-5)+2/5(0,10)

    =(4,-5)+(0,4)

    =(4,-1)

therefore P(4,-1)

We happen to have

[tex]\dfrac17 = \dfrac18 + \dfrac1{8^2} + \dfrac1{8^3} + \cdots[/tex]

which is to say, the base-8 representation of 1/7 is

[tex]\dfrac17 \equiv 0.111\ldots_8[/tex]

This follows from the well-known result on geometric series,

[tex]\displaystyle \sum_{n=1}^\infty ar^{n-1} = \frac a{1-r}[/tex]

if [tex]|r|<1[/tex]. With [tex]a=1[/tex] and [tex]r=\frac18[/tex], we have

[tex]\displaystyle \sum_{n=1}^\infty \frac1{8^{n-1}} = 1 + \frac18 + \frac1{8^2} + \frac1{8^3} + \cdots \\\\ \implies \frac1{1-\frac18} = 1 + \frac18 + \frac1{8^2} + \frac1{8^3} + \cdots \\\\ \implies \frac87 = 1 + \frac18 + \frac1{8^2} + \frac1{8^3} + \cdots \\\\ \implies \frac17 = \frac18 + \frac1{8^2} + \frac1{8^3} + \cdots[/tex]

Uniformly multiplying each term on the right by an appropriate power of 2, we have

[tex]\dfrac17 = \dfrac2{16} + \dfrac{2^2}{16^2} + \dfrac{2^3}{16^3} + \dfrac{2^4}{16^4} + \dfrac{2^5}{16^5} + \dfrac{2^6}{16^6} + \cdots[/tex]

Now observe that for [tex]n\ge4[/tex], each numerator on the right side side will contain a factor of 16 that can be eliminated.

[tex]\dfrac{2^n}{16^n} = \dfrac{2^4\times2^{n-4}}{16^n} = \dfrac{2^{n-4}}{16^{n-1}}[/tex]

That is,

[tex]\dfrac{2^4}{16^4} = \dfrac1{16^3}[/tex]

[tex]\dfrac{2^5}{16^5} = \dfrac2{16^4}[/tex]

[tex]\dfrac{2^6}{16^6} = \dfrac4{16^5}[/tex]

etc. so that

[tex]\dfrac17 = \dfrac2{16} + \dfrac4{16^2} + \dfrac9{16^3} + \dfrac2{16^4} + \dfrac4{16^5} + \dfrac9{16^6} + \cdots[/tex]

and thus the base-16 representation of 1/7 is

[tex]\dfrac17 \equiv 0.249249249\ldots_{16}[/tex]

and the first 10 digits after the (hexa)decimal point are {2, 4, 9, 2, 4, 9, 2, 4, 9, 2}.

Answer:

09

Step-by-step explanation:

34

[tex]3(8 - 4x) < 6(x - 5) \\ 24 - 12x < 6x - 30 \\ 24 + 30 < 6x + 12x \\ 54 < 18x \\ \frac{54}{18} < \frac{18x}{18} \\ x > 3[/tex]

Solution : ] 3 , + ♾️ [

PLEASE GIVE BRAINLIEST

Answer:

12 is the answer

Step-by-step explanation:

FIRST do 23 - 11 and you will find your answer

Answer:

27/4

Step-by-step explanation:

added in the picture

Answer:

You are right...........

Answer:

a. y-intercept:(0,  -6), x-intercepts: (3, 0) and (-2, 0). vertex: (0.5, -6.25)

b. y-intercept: (0, 6), x-intercepts(3, 0) and (-2, 0). vertex: (0.5, 6.25)

Step-by-step explanation:

a:

 So finding the y-intercept is really easy and is simply when x=0. If you plug in 0 as x it makes [tex]y=(0)^2-0-6[/tex] which simplifies to -6, which is the y-intercept. As for the x-intercepts you can calculate that by using the quadratic equation [tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\[/tex]. In this case a=1, b=-1, c=-6. So plugging those values in you get [tex]x=\frac{-(-1)\pm\sqrt{(-1)^2-4(1)(-6)}}{2(1)}[/tex], which simplifies to [tex]x=\frac{1\pm5}{2}[/tex]. This gives you the x-intercepts 6/2 and -4/2 which are 3 and -2. The vertex can be calculated by manipulating the equation so it's in the form of [tex]y=(x-h)^2+k[/tex] where (h, k) is the vertex of the parabola. This is done by moving c to the other side and then completing the square and the isolating y. So the first step will be

Move c to the other side

[tex]y+6=x^2-x[/tex]

Complete the square by adding (b/2)^2

[tex]y+6+0.25 = x^2-x+0.25[/tex]

Rewrite as square binomial

[tex]y+6.25 = (x-0.5)^2[/tex]

Isolate y

[tex]y=(x-0.50)^2-6.25[/tex]

(h, k) = 0.50, -6.25 which is the vertex

b: To identify the y-intercept you plug in 0 as x which will only leave c which in this case is 6 which is the y-intercept. (0, 6). To identify the x-intercepts you can simplify plug in the values a, b, c into the quadratic equation which was stated in the previous answer. In this case a, b, c = -1, 1, 6. Plugging these values in gives the equation [tex]y=\frac{-(1)\pm\sqrt{1^2-4(-1)(6)}}{2(-1)}[/tex]. which simplifies to [tex]x=\frac{-1\pm5}{-2}[/tex] which gives the values -2 and 3. To find the vertex it's the same process as before

Factor out -1

[tex]y=-(x^2-x-6)[/tex]

Add 6 to both sides (on the left side add -6 since -1 was factored out).

[tex]y-6=-(x^2-x)[/tex]

Complete the square by adding (b/2)^2 to both sides (add -(b/2)^2 to left side since -1 was factored out)

[tex]y-6-0.25 = -(x^2-x+0.25)[/tex]

Rewrite as square binomial

[tex]y-6.25=-(x-0.5)^2[/tex]

Add 6.25 to both sides

[tex]y=(x-0.50)^2+6.25[/tex]

(h, k) = (0.50, 6.25)

When you graph the parabolas you'll notice there just flipped relative to the x-axis. This can be deduced by simply looking at the two equations, since the two equations have the same absolute value coefficients, the signs are just different, and more specifically they're all opposite. If you took the first equation and multiplied the entire right side by -1 you would get the same equation. And since that equation really represents the value of y (since it's equal to y) you're reflecting it across the x-axis.

Answer:

a) y-intercept (0,  -6); x-intercepts (3, 0) and (-2, 0); vertex (0.5, -6.25)

b) y-intercept (0, 6); x-intercepts (3, 0) and (-2, 0); vertex (0.5, 6.25)

Step-by-step explanation:

The polynomial f(x) in expanded form is [tex]f(x) = x^3 - 3x^2 - 25x - 21[/tex]

The polynomial zeros are given as:

x = 7, x = -1 and x = -3

Rewrite as:

x - 7 = 0, x + 1 = 0 and x + 3 = 0

Multiply the zeros

f(x) = (x - 7)(x + 1)(x + 3)

Expand

[tex]f(x) = (x - 7)(x^2 + 4x + 3)[/tex]

Further, expand

[tex]f(x) = x^3 + 4x^2 - 7x^2 + 3x - 28x - 21[/tex]

Evaluate

[tex]f(x) = x^3 - 3x^2 - 25x - 21[/tex]

Hence, the polynomial f(x) in expanded form is [tex]f(x) = x^3 - 3x^2 - 25x - 21[/tex]

We have:

[tex]g(x) = \frac{f(x)}{x^2 - x- 2}[/tex]

This gives

[tex]g(x) = \frac{x^3 - 3x^2 - 25x - 21}{x^2 - x- 2}[/tex]

Expand the numerator

[tex]g(x) = \frac{x^3 - x^2 - 2x^2 - 2x + 2x - 25x + 4 - 25}{x^2 - x - 2}[/tex]

Rewrite as:

[tex]g(x) = \frac{x^3 - x^2 - 2x - 2x^2 + 2x + 4 - 25x - 25}{x^2 - x - 2}[/tex]

Factorize

[tex]g(x) = \frac{(x - 2)(x^2 - x- 2) - 25x - 25}{x^2 - x- 2}[/tex]

Evaluate the quotient

[tex]g(x) = x - 2 - \frac{25x + 25}{x^2 - x- 2}[/tex]

The slant asymptote is the quotient i.e. x - 2

Hence, the slant asymptote of the function g(x) is x - 2

In (b), we have:

[tex]g(x) = \frac{x^3 - 3x^2 - 25x - 21}{x^2 - x- 2}[/tex]

Set the denominator to 0

[tex]x^2 - x - 2 = 0[/tex]

Expand

[tex]x^2 + x - 2x - 2 = 0[/tex]

Factorize

x(x + 1) - 2(x + 1) = 0

Factor our x + 1

(x - 2)(x + 1) = 0

Solve for x

x = 2 or x = -1

2 is greater than -1.

So, the discontinuities and their types are:

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At  150 minutes the length of the first candle is 3 times that of the other.

The complete question is

There are two candles of same length and same size. Both of them burn at uniform rate. The first one burns in 5 hours and the second one burns in 2 hours. Both the candles are lit together. After how many minutes the length of the first candle is 3 times that of the other?

When two algebraic expression are equated using an equal sign an equation is formed.

First candle burns for 5 hours

Second candle burns for 2 hours

Let the length of candle be l.

After t time (in minutes), length of first candle =l−(lt/300)

Length of second candle =l− (lt/120)

From the data given

l -  (lt/120) = 3 * (l−(lt/300))

On simplifying

4t = 600

t = 150 minutes

Therefore after 150 minutes the length of the first candle is 3 times that of the other.

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