Answers
Amplitude is the maximum vertical displacement of the seismic waves on the Seismogram. As evident from the graph, it is 60 mm.
What is the Time?1. Time at which P waves arrive- 0 sec
Time at which S waves arrive- 18 sec
S-P interval= Time at which S wave arrive- Time at which P wave arrive
S-P interval= 18-0= 18 sec
2. Amplitude is the maximum vertical displacement of the seismic waves on the Seismogram. As evident from the graph, it is 60 mm.
3. The distance is around 150 km and is evident on the Distance/S-P bar chart.
4. The magnitude is about 4 and can be found by joining S-P interval (18 sec) with the Amplitude i.e., 6 mm. The point of intersection of the line to the magnitude line gives the magnitude, i.e., 4.
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Related Questions
5. An elephant has weight of 48000N and exerts pressure of 60000 Pa on the ground. What is the area of the elephant's feet in contact with the ground?
a. 1.25 m^2
b. 0.8 m^2
c. 2.0 m^2
d. 8.0 m^2
Answers
Answer:
A 1.25 m²
Explanation:
1 Consider a ring, sphere and Solidey clinder all with the same mass. They are all held at the top of the inclined Plane which is at 20° to the horizontal. the top of the inclined Plane is 1m high. The shapes are released simultaneously and allowed to roll down the inclined plane. Assume the abjects roll with out slipping and that they are all made from the same material. Assume the coefficient of static friction bin the objects and the plane is 0-3-
A) workout what order
they would get to the bottom of the Slope!
B) How long will it take each shape to reach the bottom of the Slope ?
C) which shapes have the greater moment
of inertia ?
D ) determine the linear acceleration(a)
e) calculate the tangential (linear) Veloci ty of each shapes-
Answers
The ring will have the greater moment of inertia.
Acceleration of a body rolling down an inclined plane without slipping is given by,
α = gsinθ/(1 + K²/R²)
Acceleration of the ring,
α = gsinθ/(1 + R²/R²)
α = 1/2 gsinθ
Acceleration of the sphere,
α = gsinθ(1 + 5/2)
α = 2/7 gsinθ
Acceleration of the solid cylinder,
α = g sinθ(1 + 1/2)
α = 2/3 gsinθ
The ring has the highest acceleration. Therefore, the ring will reach the bottom of the slope first.
The ring will have the greater moment of inertia among the three.
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calculate the electric field at the centre of a square 60cm on a side if one corneris occupied by a +45uC charge and the other three corners are occupied by -31uC charge
Answers
E_total = 1.39 x 10^5 N/C
Explanation:
We can calculate the electric field at the center of the square using the principle of superposition. We will treat each charge as a point charge and calculate the electric field due to each charge, and then add them up vectorially.
Let's assume that the positive charge is located at the bottom-left corner of the square, and the negative charges are located at the other three corners. The distance from the charges to the center of the square is:
r = 60 cm / 2 = 30 cm
The electric field due to a point charge is given by Coulomb's law:
E = k*q / r^2
where k is the Coulomb constant, q is the charge, and r is the distance between the charge and the point where we want to calculate the electric field.
For the positive charge, we have:
E1 = k*q1 / r^2
E1 = (9 x 10^9 Nm^2/C^2)(45 x 10^-6 C) / (0.3 m)^2
E1 = 4.50 x 10^5 N/C
The electric field due to the negative charges is:
E2 = k*q2 / r^2
E2 = (9 x 10^9 Nm^2/C^2)(-31 x 10^-6 C) / (0.3 m)^2
E2 = -3.11 x 10^5 N/C
Since the negative charges are at opposite corners, the direction of the electric field due to each charge cancels out, so we only need to consider the magnitude of the electric field due to the negative charges.
The total electric field at the center of the square is:
E_total = E1 + E2
E_total = 4.50 x 10^5 N/C - 3.11 x 10^5 N/C
E_total = 1.39 x 10^5 N/C
The direction of the electric field at the center of the square is the direction of the net electric field due to the two charges, which is from the positive charge to the negative charges. This direction is along the diagonal of the square, at a 45 degree angle with respect to the sides of the square.
A force acts on a particle that has a mass of 1.5 kg. The force is related to the position x
of the particle by the formula = 0.503 where if x is in meters and F is in newtons. (a)
What are the SI units of C? (b) Find the work done by this force as the particle moves from
= 3.0 to = 1.5 (c) At = 3.0, the force points opposite the direction of the
particle’s velocity (speed is 12.0m/s). What is its speed at = 1.5? (d) Can you tell its
direction of motion at using only the work–kinetic energy theorem? Explain your
calculations.
Answers
(a) F(x) = 0.503 x, where x is in meters and F is in newtons, is the formula given for the force. We can see that this equation's proportionality constant, C, must be expressed in newtons per meter. C is therefore measured in N/m in the SI.
The work done and direction(b) The work done by the force as the particle moves from x = 3.0 m to x = 1.5 m can be calculated using the formula for work, which is W = ∫ F(x) dx, where the integral is taken over the distance moved. Therefore, we have:
W = ∫ 0.503 x dx from x = 3.0 to x = 1.5
W = [0.503/2 x^2] from x = 3.0 to x = 1.5
W = [0.503/2 (1.5^2 - 3.0^2)]
W = -1.129 J
The work done by the force is -1.129 joules.
(c) At x = 3.0, the force is given to be in the opposite direction to the particle's velocity. Therefore, the force is opposing the motion of the particle. We can use the work–kinetic energy theorem to determine the change in kinetic energy of the particle between x = 3.0 and x = 1.5, and hence its speed at x = 1.5. The work–kinetic energy theorem states that the net work done on an object is equal to its change in kinetic energy. Therefore, we have:
W_net = ΔK
In this case, the only force acting on the particle is the given force, and we have already calculated the work done by this force as -1.129 J. Therefore, we have:
W_net = -1.129 J
ΔK = 1.129 J (since the work done is negative, indicating a decrease in kinetic energy)
We can use the formula for kinetic energy, K = (1/2)mv^2, to find the particle's speed at x = 1.5. Therefore, we have:
ΔK = (1/2)m(v^2 - v_0^2)
1.129 = (1/2)(1.5)(v^2 - 12^2)
v^2 = 12^2 - (2/1.5)(1.129)
v^2 = 56.49
v = 7.52 m/s
The particle's speed at x = 1.5 is 7.52 m/s.
(d) kinetic energy theorem states that the net work done on an object is equal to its change in kinetic energy. In this case, the net work done by the given force Is -1.129 J, the initial kinetic energy of the particle (since we are told its speed at x = 3.0).
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From a sack of fruit containing 3 Apples ,2 Bananas , and 3 oranges , a random sample of 4 pieces of fruit is selected. Suppose X is the number of apples and Y is the number of bananas in the sample.
(a) Find the joint probability distribution of X and Y.
(b) Find P[(X,Y)A], where A is the region that is given
Answers
The joint probability distribution of X and Y is 2/70 and 3/70.
The value of P[(X,Y)A], where A is the region that is given is 1/2.
How to calculate the probabilityProbability simply means the chance that a particular thing or event will happen. It is the occurence of likely events. It is simply the area of mathematics that deals with the numerical estimates of the chance that an event will occur or that a particular statement is true.
The value of P[(X,Y)A], where A is the region that is given is:
= 0 + 2/70 + 3/70 + 3/70 + 18/70 + 9/70
= 35 / 70
= 1/2.
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Why did Izzy fall when playing tug of war? Responses he tripped he tripped balanced forces balanced forces he was pushed he was pushed unbalanced forces
Answers
Answer:
he tripped ballanced forces ballanced forces
Use the heating curve (Figure 1) to answer the question.
Temperature (°C)
200
150
100
50
0
-50
-100
-150
200 400 600 800 1000 1200
Energy (J)
What is the boiling point of the substance represented?
0
-100 °C
150 °C
-50 °C
50 °C
Answers
Answer:
Melting Point = -50 °C
Boiling Point = 50 °C
Explanation:
A heating curve displays a substance in its 3 states.
On the graph, each region where the slope is positive represents the substance as a solid, liquid, or gas.
When the slope is 0, this is the temperature point at which the substance's state of matter has changed (i.e., melting or boiling/vaporization point) – also known as a phase transition. Essentially, the 0 slope regions are where the substance is changing from one state of matter to the next.
(When the substance is being heated, it's absorbing energy, but when it reaches a phase transition point, the substance begins to consume energy to change its matter state. That's why the temperature doesn't go up while the substance's internal Energy increases.)
In (Figure 1), where 'x' is Energy (J) and 'y' is Temperature (°C):
Region A (0 J ≤ x ≤ 200 J):
The slope is positive, so the substance is in a constant matter state. Because it's the first sloped region, the substance is in its solid state from -100 °C to -50 °C.
Region B (200 J ≤ x 600 J):
The slope is 0, so the substance has reached a phase transition point. Because the previous region was when the substance was solid, that means that the temperature throughout Region B is the melting point at -50 °C.
Region C (600 J ≤ x ≤ 800 J):
The slope is positive so the substance is in a constant matter state. We've already identified when the substance was solid and when it melted, so now the substance is in its liquid state from -50 °C to 50 °C.
Region D (800 J ≤ x ≤ 900 J):
The slope is 0, and since the previous region was when the substance was a liquid, it's now reached its boiling point at 50 °C.
Region E (900 J ≤ x ≤ 1000 J):
The slope is positive, and we've previously identified all of the transition points and matter states except for one, so the substance is now in its gaseous state after reaching 100°C.
(Once a substance reaches its gaseous state, the Temperature/Energy ratio is constant.)
Which definition describes a scientific theory?
OA. A claim, assumption, or method that is commonly thought to be
based on science but is not scientific
B. The pursuit of knowledge about the natural world and the
application of that knowledge
C. An explanation for a natural phenomenon that is based on facts
and is supported by the results of many experiments
D. A method of carefully examining an idea, using a variety of
thought processes to construct and evaluate knowledge
Answers
OA: A. A claim, assumption, or method that is commonly thought to be based on science but is not scientific.
Science is a systematic enterprise that builds and organizes knowledge in the form of testable explanations and predictions about the universe.
A claim, assumption, or method that is commonly thought to be based on science but is not scientific is called pseudoscience. Pseudoscience is often presented as being scientific, but it does not meet the criteria of science. For example, pseudoscience may be based on speculation or personal opinion, rather than on evidence. It may also be based on experiments that are not properly controlled or that are not reproducible.
Pseudoscience can be harmful because it can lead people to make decisions that are not based on evidence. For example, people who believe in pseudoscience may be more likely to avoid proven medical treatments or to use unproven treatments that could actually be harmful.
It is important to be able to identify pseudoscience so that you can make informed decisions about your health and your life. If you are unsure whether something is pseudoscience, you can ask a scientist or do some research to find out more.
4.
The "force" that moves electric charge carriers through an electric circuit is
a superconductor
resistance
An
10
a
MacBook Air
s
8
current
voltage
DII
8
A
EMA
4
F11
F12
Answers
Answer: Voltage
Explanation: Not really sure what all that other stuff is after your question...
The "force" that moves electric charge carriers through an electric circuit is ________.
An electric charge carrier moving through a circuit is a charged particle (usually electrons). The force that pushes it is called an electromagnetic force, commonly known as EMF.
Between atoms, EMFs are what attract electrons from one atom to another to form bonds. Likewise, In a circuit, the EMF is the driving force, which is known as voltage.
Superconductivity refers to a state in which these charge carriers travel at a specific voltage with no resistance, meaning no energy is lost. However, this isn't an independent force, so it's incorrect.
Resistance affects the circuit by slightly dampening the flow of charge carriers. Resistance commonly comes in the form of temperature or simply a characteristic of the material through which the circuit flows, so this is incorrect.
Current merely refers to the flow of charge carriers through a circuit in a given time window.
(Think of a circuit as a water pipe. Current is like the speed of a specific amount of water and Voltage (or EMF) is the pressure in the pipe. The higher the pressure, the faster the water flows. Resistance is anything in the pipe that impedes the water flow)
Four point masses 2kg, 4kg, 6kg and 8kg are placed at the corners of Square ABCD of 2cm long respectively. Find the Position of centre of mass of the system from the corner A.
Answers
The position of the center of mass of the system from corner A is 4.3692cm.
To find the position of the center of mass of the system, we need to use the formula:
C.M. = (m1r1 + m2r2 + m3r3 + m4r4)/(m1 + m2 + m3 + m4)
where m1, m2, m3, and m4 are the masses of the four-point masses, and r1, r2, r3, and r4 are the distances of the point masses from the reference point (in this case, corner A).
Let's first find the distances of the four-point masses from corner A. We can see that the distance of the 2kg mass from corner A is 2 cm. The distance of the 4kg mass from corner A is the diagonal of a square of side 2 cm, which is sqrt(22 + 22) = 2.828 cm. Similarly, the distances of the 6kg and 8kg masses from corner A are also 2.828 cm.
Now, let's substitute the values in the formula:
C.M. = (2kg2cm + 4kg2.828cm + 6kg2.828cm + 8kg2.828cm)/(2kg + 4kg + 6kg + 8kg)
C.M. = (4cm + 11.312cm + 16.968cm + 22.624cm)/20kg
C.M. = 1.824cm + 0.5656cm + 0.8484cm + 1.1312cm
C.M. = 4.3692cm
Therefore, the position of the center of mass of the system from corner A is 4.3692cm.
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A rifle with a weight of 30 N fires a 5.0-g bullet with a speed of 300 m/s. (a) Find
the recoil speed of the rifle. (b) If a 700-N man holds the rifle firmly against his
shoulder, find the recoil speed of man and rifle.
Answers
_______________________________
Notes:
1grain = 64.8mg
1newton = 100g
= 300 m/s (speed)
= 30 × 100
= 3,000g (rifle mass)
= 5-g × 64.8
= 324mg (bullet mass)
= 700 × 100
= 70,000g (human mass)
= 70,000g + 3,000g
= 70,300g (human + rifle mass)
A) Newton's 2nd Law of MotionM1 V1 = - m2 v2Vr = - mb ÷ mrVb = - (324 ÷ 3,000) 300= 32.4 m/sB) Newton's 2nd Law of MotionM1 V1 = - m2 v2Vr = - mb ÷ mr Vb = - (324 ÷ 70,300) 300= 1.39 m/s_______________________________
What is amplitude and phase in electrical and electronics circuit?
Answers
In electrical and electronics circuits, amplitude is the maximum value of a signal. This is known as the strength or intensity of the signal. Phase, can be seen as the timing relationship between two signals or waveforms. It tell the time it takes betwen the peaks or zero crossings of two waveforms
What more should you know about phase in electrical and electronics circuits?In electrical and electronics circuits, phase tell us about the the relationship between currents in different parts of the circuit, For example in AC circuits with multiple components.
We the amplitude and phase of signals in electrical and electronics circuits is understood, it becomes easier to design and analyz circuits, and can even be used for troubleshooting and maintaining them.
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A blue train of mass 50 kg moves at 4 m/s toward a green train of 30 kg initially at rest. What is the initial momentum of the blue train?
A. 20 kgm/s
B. 200 kgm/s
C. 50 kgm/s
D. 0 kgm/s
Answers
Answer:
B. 200 kgm/s
Explanation:
The initial momentum of the blue train can be calculated using the formula:
p = mv
where p is the momentum, m is the mass, and v is the velocity.
The mass of the blue train is 50 kg and its velocity is 4 m/s. Therefore, the initial momentum of the blue train is:
p = 50 kg x 4 m/s = 200 kgm/s
Therefore, the initial momentum of the blue train is 200 kgm/s, which is option B.
What is the difference between analog signal and digital signal. Explained in essay form.
Answers
A continuous signal that changes in frequency and amplitude over time is referred to as an analogue signal. A digital signal one can only take on a small number of values and is commonly represented by 0s and 1s.
Being able to take on any value within a continuous range of values makes it the perfect choice for simulating physical phenomena like temperature, sound, and light. Analogue signals include things like radio waves, vinyl records, and conventional telephone networks. Modern communication and computing systems use digital signals instead of analogue ones because they can be transferred and processed more effectively and are less prone to noise. Computer networks and digital cameras are few examples of digital signals.
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Why might earthquakes be much more intense closer to the initial disturbance than they are further away
Answers
Earthquakes are typically more intense closer to the initial disturbance because the seismic waves generated by the earthquake lose energy as they travel through the Earth's crust. The energy of the seismic waves is dissipated as they encounter different layers of rock and other materials, causing the waves to become weaker and less intense.
Closer to the initial disturbance, the seismic waves encounter less material to pass through, and therefore experience less energy loss. As a result, the waves are more intense and can cause more damage to structures and the surrounding environment.
In addition to this, the type of rock and soil that the seismic waves pass through can also affect their intensity. Softer materials like sand and clay amplify the seismic waves, which can cause more damage in the nearby areas.
Therefore, the distance from the initial disturbance and the geological features of the region can both affect the intensity of an earthquake. Typically, the closer an area is to the epicenter of an earthquake, the more intense the shaking will be, and the further away an area is, the weaker the shaking will be.
[Rotational motion] Calculate the length L between the 40N weight and the pivot needed to balance the beam shown in Figure 10.9. (solution says it's 7 m but it's unclear how it was obtained)
Answers
Answer:
L = 7m
Explanation:
The beam is balanced (not moving), so the moments about the pivot have to sum to 0.
Let x = dist. from pivot to the 10N ↓ force
CCW rotation is +
CW rotation is -
(100 N)(3 m) - (10 N)(x) - (40 N)(L) = 0
300 N·m - (10 N)(x) - (40 N)(L) = 0 divide by 10 on both sides
30 - x - 4L = 0
x + 4L = 30
10N is the Weight of the beam, so it is at the midpoint of the beam.
x = 5 - 3 = 2 m substitute into the equation above:
2 + 4L = 30
4L = 30 - 2 = 28
L = 28/4 = 7 m
A tourist, who weighs 705 N, is walking through the woods and crosses a small horizontal bridge. The bridge rests on two concrete supports, one at each end. He stops on the bridge. Assume that the board of the bridge has negligible weight. Where is he standing if the magnitude of the vertical force that a concrete support exerts on the bridge at the near end is 470 N?
а)one-fifth of the way along the bridge b)one-fourth of the way along the bridge c)one-third of the way along the bridge d)one-half of the way along the bridge f)one-sixth of the way along the bridge
Answers
The tourist is standing one-third of the way along the bridge (option c).
How to solveLet's denote the distance from the near end of the bridge to the point where the tourist is standing as x and the total length of the bridge as L.
According to the equilibrium condition, the sum of the forces exerted on the bridge is zero.
So, the vertical forces exerted by the two concrete supports should be equal to the weight of the tourist:
F_near + F_far = 705 N
Given that the magnitude of the vertical force exerted by the near end support is 470 N, we can calculate the force exerted by the far end support:
F_far = 705 N - 470 N = 235 N
Now, we can use the moment equilibrium condition, considering moments around the near end support:
Moment = Force × Distance
For the tourist:
Moment_tourist = 705 N × x
For the far end support:
Moment_far = 235 N × L
For equilibrium, the sum of the moments should be zero:
Moment_tourist - Moment_far = 0
Substituting the moments:
705 N × x - 235 N × L = 0
Now, we can solve for x/L, which represents the fraction of the way along the bridge where the tourist is standing:
x/L = (235 N × L) / 705 N
x/L = 235/705 = 47/141 ≈ 1/3
So, the tourist is standing one-third of the way along the bridge (option c).
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Two vectors with a magnitude of 5 and 12 have a dot product equal to -6. Find the angle between the vectors to the
nearest degree.
Answers
the angle between vectors is 1
let, vector A,B and |A| =5 , |B| =12
According to dot product,
A.B = |A| |B| cos∝
-6 = 5x12cos∝
cos∝ = 0.99
nearly equal to 1
hence the angle between A and B is 1
Four point masses 2kg, 4kg, 6kg and sky are placed at the corners of Square ABCD of 2cm long respectively. Find the position of centre of mass of the system from the corner A.
Answers
The position of center of mass is, 1 cm right, and 1.4 cm above the corner A, of the square ABCD.
The respective coordinates of masses, on corner ABCD, are:
Corner A: 2kg (0,0)Corner B: 4kg (2,0)Corner C: 6kg (2,2)Corner D: 8kg (0,2) ... (assuming the not given data as 8kg)Let the coordinates of COM(center of mass), be, Xcom and Ycom.
Therefore,
Xcom = [ ∑([tex]M_{i}[/tex] x [tex]X_{i}[/tex]) / ∑([tex]M_{i}[/tex]) ] , and
Ycom = [ ∑([tex]M_{i}[/tex] x [tex]Y_{i}[/tex]) / ∑([tex]M_{i}[/tex]) ]
That is,
Xcom = [ {(2x0)+(4x2)+(6x2)+(8x0)} / (2+4+6+8) ]
Xcom = (20/20) cm
Xcom = 1cm
Similarly,
Ycom = [ {(2x0)+(4x0)+(6x2)+(8x2)} / (2+4+6+8) ]
Ycom = (28/20) cm
Ycom = 1.4 cm
So, the position of center of mass is, 1 cm right, and 1.4 cm above the corner A, of the square ABCD.
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Researchers want to assess your intelligence. To do so, they have you
complete a short survey on which you indicate your favorite color. They ask
you to complete this survey multiple times, and you always answer the same
color. Unfortunately, one's favorite color has nothing to do with one's
intelligence. This research survey is best defined as:
Answers
This research survey is an example of a flawed or invalid measure of intelligence.
The research survey that is shown in this question can be defined as a poor measurement tool for assessing intelligence. One can easily identify that the researchers are measuring intelligence by asking about the favorite color of the personnel, which has nothing to do with the intelligence of the person. This survey lack validity which is essential to measure the intelligence of any personnel through a survey.
The survey also lacks reliability as it can't provide consistent results. If the intelligence of any personnel is somehow related to the intelligence of the person, answering the survey multiple times must give the same answer. This doesn't provide consistent result and lack reliability and realism.
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Which of the following is the dimension of moment of inertia? (a) ML2 (b) MLT-1 (c) L2T 2 (d) L T-1
Answers
The dimension of the moment of inertia is [tex]ML^2[/tex]. Option A.
What is the moment of inertia?The moment of inertia represents the resistance of a body to rotational motion. It depends on the body's mass and the distribution of that mass around the axis of rotation.
The formula for the moment of inertia involves mass and distance and is expressed as:
I = mr^2
where
m is the mass of the bodyr is the distance from the axis of rotation.The dimension of mass is represented by M, and the dimension of distance is represented by L. Therefore, the dimension of moment of inertia is:
Moment of inertia = mass x distance^2 = M x L^2 = [tex]ML^2[/tex].
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_______, ________, and ________ are renewable resources.
biomass energy, hydropower, and coal energy
hydropower, coal energy, and wind energy
biomass energy, hydropower, and wind energy
biomass energy, coal energy, and wind energy
✎help its an exam✎ ☕︎if any links I WILL REPORT☕︎
Answers
Answer:
biomass energy, hydropower and wind energy
what are the two major types of mechanical energy and how do you calculate each equations with variables identified?
Answers
The equation to calculate both of them are:
KE = 1/2 * m * v^2
PE = m * g * h
What is Kinetic energy?Kinetic energy is described as the energy an object possesses due to its motion. The equation to calculate kinetic energy is:
KE = 1/2 * m * v^2
Where:
KE = Kinetic energy
m = Mass of the object
v = Velocity of the object
Potential energy is described as the energy an object possesses due to its position or configuration.
. The equation to calculate gravitational potential energy is:
PE = m * g * h
Where:
PE = Gravitational potential energy
m = Mass of the object
g = Acceleration due to gravity (9.81 m/s^2 on Earth)
h = Height or elevation of the object relative to a reference point
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11 When you stand on scales you see your mass in kg. Explain whether
it is your mass or your weight that makes the scales work.
Answers
When yоu stаnd оn а scаle, thе reаding thаt yоu sее is аctuаlly а meаsurement оf thе forсe thаt yоur bоdy is еxеrting оn thе scаle.
What makes the scale workThis forсe rеsults frоm thе grаvitаtiоnаl аttrаctiоn between yоur bоdy аnd thе eаrt. Тhe scаle meаsures thе forсe with а sрring or а string gаuge, cоnverts thе reаding tо а morе рrecise meаsurement in kilogrаms, аnd finаlly reсords thе rеsult.
Thus, thе scаles operаte bаsed оn thе forсe еxеrtеd by yоur bоdy, whiсh is dirеctly proportiоnаl tо yоur wеight. Тhe forсe оf grаvity аcting оn аn оbject is cаlled wеight, аnd it vаries bаsed оn thе mаss оf thе оbject аnd thе strength оf thе grаvitаtiоnаl field. On thе othеr hаnd, mаss is а meаsurement оf thе quаntity оf mаtter present in аn оbject аnd is cоnstаnt аcross time.
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Will the placement of the continents on Earth look different in 100 million years than today?
Answers
Answer:
Yes
Explanation:
Continents is constantly moving, but at very slow rate.
This is due to the movement of the tectonic plate underneath the earth surface.
On average they move about 10 cm per year.
So in 100 million, they will move 10,000 km.
Of course, how the continents looks 100 million years from now will be very different than today.
Two whistles emit sounds of wavelength 3.2 m and 2.9 m which produce a beat frequency of about? a) 2 hertz b) 3 hertz c) 4 hertz d) 7 hertz e) 11 hertz
Answers
Two whistles emitting sound of wavelength 3.2 m and 2.9 m would produce a beat of frequency 11 Hertz, hence option e.
The beat frequency (f_beat) is given by the difference in frequency (f) between the two whistles,
f_beat = |f₁ - f₂ |, frequencies of the two whistles are f₁ and f₂ . The frequencies can be calculated from the wavelengths (λ) using the formula,
f = c/λ, speed of sound in air is c, which is approximately 343 m/s at room temperature and atmospheric pressure. For the first whistle with a wavelength of 3.2 m,
f₁ = c/λ₁
= 343/3.2
= 107.1875 Hz
For the second whistle with a wavelength of 2.9 m,
f₂ = c/λ₂
= 343/2.9
= 118.2759 Hz
The difference in frequency is,
f_beat = |f_1 - f_2|
= |107.1875 - 118.2759| ≈ 11.1 Hz
Therefore, the beat frequency is approximately 11 hertz.
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1 Consider a ring, sphere and Solidey clinder all with the same mass. They are all held at the top of the inclined Plane which is at 20° to the horizontal. the top of the inclined Plane is 1m high. The shapes are released simultaneously and allowed to roll down the inclined plane. Assume the abjects roll with out slipping and that they are all made from the same material. Assume the coefficient of static friction bin the objects and the plane is 0.3.
A) which shapes have the greater moment of inertia ?
B) workout what order they would get to the bottom of the Slope!
C ) determine the linear acceleration(a)
D) calculate the tangential (linear) Veloci ty of each shapes
E) How long will it take each shape to reach the bottom of the Slope ?
I give you 100 coin please help me
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Answers
B) The solid cylinder will reach the bottom of the slope first, followed by the sphere, and then the ring.
C) The linear acceleration of the objects can be calculated using the following formula:
a = g * sin(θ) / (1 + I / mr^2)
where g is the acceleration due to gravity, θ is the angle of the incline, I is the moment of inertia, m is the mass, and r is the radius of the object.
Plugging in the numbers, we get:
a_ring = 9.8 m/s^2 * sin(20°) / (1 + 0.5 / 1^2) = 1.09 m/s^2
a_sphere = 9.8 m/s^2 * sin(20°) / (1 + 2 / 1^2) = 0.84 m/s^2
a_cylinder = 9.8 m/s^2 * sin(20°) / (1 + 0.5 / 0.5^2) = 1.47 m/s^2
Therefore, the linear accelerations are a_ring = 1.09 m/s^2, a_sphere = 0.84 m/s^2, and a_cylinder = 1.47 m/s^2.
D) The tangential velocity of each object can be calculated using the following formula:
v = a * r
where a is the linear acceleration, and r is the radius of the object.
Plugging in the numbers, we get:
v_ring = 1.09 m/s^2 * 0.5 m = 0.55 m/s
v_sphere = 0.84 m/s^2 * 1 m = 0.84 m/s
v_cylinder = 1.47 m/s^2 * 0.5 m = 0.74 m/s
Therefore, the tangential velocities are v_ring = 0.55 m/s, v_sphere = 0.84 m/s, and v_cylinder = 0.74 m/s.
E) The time it takes for each object to reach the bottom of the slope can be calculated using the following formula:
t = sqrt(2 * d / a)
where d is the distance traveled, and a is the linear acceleration.
Plugging in the numbers
A) The solid cylinder has the greatest moment of inertia.
B) The order in which the objects would reach the bottom of the slope is: sphere, cylinder, and ring.
C) The linear acceleration of each object is the same and is equal to 0.98 m/s^2.
D) The tangential velocity of the sphere, cylinder, and ring are 2.78 m/s, 3.53 m/s, and 4.24 m/s, respectively.
E) The time it takes for each object to reach the bottom of the slope can be calculated using the following formula:
time = square root(2h / g)
where h is the height of the slope (1m) and g is the acceleration due to gravity (9.8 m/s^2).
Plugging in the numbers, we get:
time for sphere = 0.45 s
time for cylinder = 0.51 s
time for ring = 0.57 s
Therefore, the sphere would reach the bottom first, followed by the cylinder, and then the ring.
What is the magnitude of the force in coulomb's law when one of the charge is double
Answers
Answer: Doubled
Explanation:
A mass of 10kg suspended on a steel rod of length 2m and radius 1mm what is the elongation of the rod beyond it's original length (Take E = 200*10^9 Newton per metre square
Answers
The elongation of the rod beyond its original length would be 2.5 mm.
Elongation calculationTo elongation of the rod can be deduced using the formula:
ΔL = FL / AE
where:
ΔL is the elongationF is the force appliedL is the original length of the rodA is the cross-sectional area of the rodE is Young's modulus of elasticity of the material.The cross-sectional area of the steel rod is given by:
A = π[tex]r^2[/tex]A = π[tex](0.001 m)^2[/tex] = 7.85 x [tex]10^{-7} m^2[/tex]The force applied to the rod:
F = mgF = 10 x 9.81 = 98.1 NThus:
ΔL = (98.1 x 2) / ((7.85 x [tex]10^{-7[/tex]) x (200 x [tex]10^9[/tex] ))
ΔL = 0.0025 m = 2.5 mm
In other words, the elongation of the steel rod beyond its original length is 2.5 mm.
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What is the definition of physical activity?
A.
a movement that stimulates your respiratory system
B.
a movement that causes perspiration
C.
a movement that results in the body’s use of energy
D.
a movement that requires little effort
Answers
Answer: The answer is C
Explanation: because I got it correct
C. A movement that results in the body's use of energy.
WHO has defined physical activity as any bodily movement that requires expenditure of energy.
Physical activity includes both exercise as well as integrated activities of one's daily routine.
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