Answer:
1000kg
Explanation:
F=MA
Rearrange the formula: M=F/A
plug in values for F (force), and A (acceleration).
M=4000/4
M=1000kg
i think.
not sure tho.
The mass of the jet that accelerates at 4 m/s^2 after a 4000 N force from the engines is 1000 kg.
What is Newton's second law of motion?Newton's second law of motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically, the law can be expressed as F = ma, where F is the net force acting on the object, m is its mass, and a is its acceleration. This law is fundamental to the understanding of the motion of objects under the influence of external forces.
Rearranging the formula to solve for mass, we get:
m = F / a
Substituting the given values, we get:
[tex]m = 4000 N / 4 m/s^2[/tex]
m = 1000 kg
Therefore, the mass of the jet that accelerates at 4 m/s^2 after a 4000 N force from the engines is 1000 kg.
Learn more about Newton's second law of motion, here:
https://brainly.com/question/13447525?referrer=searchRes
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Why do you think geologists were able to use these P and S seismic waves to confirm that the outer core is liquid?
Using waves of frequency and pich
Explanation:
There's always been water around us
Does gravity increase or decrease with greater mass???
Answer:
Increase
As the mass of either object increases, the force of gravitational attraction between them also increases.
Explanation:
The gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force.
As the mass of either object increases, the force of gravitational attraction between them also increases.
Answered by none other than the ONE & ONLY #QUEEN herself aka #DRIPPQUEENMO
HOPE THIS HELPED!!!
represent 11 by 9 on a number line
: A small block with mass 0.130 kg is attached to a string passing through a hole in a frictionless, horizontal surface. The block is originally revolving in a circle with a radius of 0.800 m about the hole with a tangential speed of 4.00 m/s. The string is then pulled slowly from below, shortening the radius of the circle in which the block revolves. The breaking strength of the string is 30.0 N. What is the radius of the circle when the string breaks
Answer:
r = 0.0173 m = 1.73 cm
Explanation:
Here, the centripetal force of the block will be providing the required breaking tension in the string:
[tex]Tension = Centripetal Force\\T = F_c\\\\T = \frac{mv^2}{r} \\\\r = \frac{mv^2}{T}\\[/tex]
where,
r = radius = ?
m = mass of block = 0.13 kg
v = tangential spee of block = 4 m/s
T = Breaking Strength = 30 N
Therefore,
[tex]r = \frac{(0.13\ kg)(4\ m/s)^2}{30\ N}[/tex]
r = 0.0173 m = 1.73 cm
When finding the radius of the string at the point it breaks, the tangential
velocity is assumed to be constant.
The radius when the string breaks is [tex]\underline{6.9 . \overline 3 \times 10^{-3}} \ m[/tex]Reasons:
The mass of the small block, m = 0.130 kg
Initial radius of the circle of rotation = 0.800 m
Tangential velocity, v = 4.00 m/s
The radius of the path of rotation is reduced as the string is pulled
Breaking strength of the string = 30.0 N
Required:
The radius of the circle when the string brakes
Solution:
[tex]Centripetal \ force = \dfrac{m \cdot v^2}{r}[/tex]
Where;
r = The radius of the circle of rotation
When the string brakes, w have;
Centripetal force = Breaking strength of the string = 30.0 N
Which gives;
[tex]\displaystyle r = \mathbf{\dfrac{m \cdot v^2}{Centrifugal \ force}} = \frac{0.130 \times 4^2}{30} =6.9\overline 3 \times 10^{-2}[/tex]
The radius of the circle when, the string breaks r = [tex]\underline{6.9\overline 3 \times 10^{-2}} \ m[/tex]
Learn more here:
https://brainly.com/question/20905151
sinat
Accelerationa
2 2.84
7 34
TABLE
in Elination
t2 t3 T2 2
1=0.04
2.29 1.25 1.28 1.271.61
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097 0.53
4. = 0.16 9.210.8
9.21 0.850.796. 82/0.67
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0.72 0.77 0.75 l 0-56/
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= 0.2 11.54
Answer:
so you have a question
Explanation:
either way,you have a nice day
There is a bottleneck in producing masses higher than4He, because there are no mass-5or mass-8 stable nuclides. For older stars with high densities and high temperatures (T>100 million K), three alpha particles can form12C. This occurs by two alpha particles firstforming8Be, and then8Be reacting with another alpha particle to form12C before8Be candecay back to two alpha particles.a) Explain why this can only happen in very hot stars and high density.b) Calculate how much energy is given up when three alpha particles form12C.
Answer:
Explanation:
a)
To pass the Coulomb barriers and undergo nuclear fusion, alpha particles must be burned at high temperatures. As a result, the ignition temperature needed for this reaction is 5.4168 × 10¹⁰ K. Helium must be burned at a high temperature and density. As a result, this must occur for hot stars with high densities.
b)
The amount of energy given up can be calculated as follows:
[tex]_2He^4 + _2He^4 \to _4Be^8 ---- (1) \\ \\ _4Be^8 + 2_He^4 \to _6C^{12} ---(2)[/tex]
where;
[tex]M(_2He^4) = 4.002603 \ u \\ \\ M(_4Be^8) = 8.005305 10 \ u[/tex]
Therefore, from the reaction (1);
[tex]Q = \Big ( M(_2He^4) + M(_2He^4) - M(_4Be^8) \Big ) ( 931.5 \ MeV) \\ \\ = \Big ( 2(4.002603 \ u) - (8.00530510 \ u) \Big) \Big ( 931.5 \ MeV/u \Big) \ \\ \mathbf{= -0.092 \ MeV}[/tex]
From the second reaction:
[tex]Q = \Big ( M(_4Be^8) + M(_2He^4) - M(_6C^{12}) \Big ) ( 931.5 \ MeV) \\ \\ = \Big ( 8.00530510 \ u +4.002603 \ u -12 \ u \Big) \Big ( 931.5 \ MeV/u \Big) \ \\ \mathbf{= 7.37 \ MeV}[/tex]
The drawing shows four sheets of polarizing material, each with its transmission axis oriented differently. Light that is polarized in the vertical direction is incident from the left and has an average intensity of 20 W/m2. Determine the average intensity of the light that emerges on the right in the drawing (a) when sheet A alone is removed, (b) when sheet B alone is removed, (c) when sheet C alone is removed, and (d) when sheet D alone is removed.
Answer:
Explanation:
At the point when light is vertically polarized is incident on the polarizer whose axes are situated at angle points [tex]\theta _1 , \theta _2 , \theta _3[/tex] the intensity power in the wake of going through all the polarisers is given by the Malus law, applied threefold for every one of the three axes.
[tex]I = I_o \ cos \theta _1 \ cos \theta _2 \ cos \theta _ 3[/tex]
The heading of the direction of the polarization is equivalent to the pivoted axes of the polarizer provided that light is an electromagnetic wave, its course of polarization is therefore controlled by the electric field part.
∴
a)
When sheet A is removed, the transmitted light goes through B, at 30°.
[tex]I = I_o \ cos ^2 \theta _1 \ cos ^2 \theta _2 \ cos^2 \theta _3[/tex]
[tex]I = 20 \ cos ^2 30 \ cos ^2 60 \ cos ^2 30[/tex]
[tex]I = 2.81 \ W/m^2[/tex]
b)
When B is removed, No light passes since the axis of A and the axis of C are perpendicular to each other.
c)
When C is removed, the intensity is indeed zero since the axes are aligned and adjusted at 90° to one another.
[tex]\mathbf{d) \ I - I_o cos^2 (0) cos^2 (30) \ cos^2 (60)}[/tex]
[tex]\mathbf{d = 3.75 \ W/m^2}[/tex]
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How did our Sun form? *
A cloud of stellar dust from part of a Nebula collapsed causing hydrogen atoms to
fuse together.
Many smaller stars became fused together by gravity
It broke off from a larger star in the universe.
Two gas giants from another solar system became fused together by gravity.
Answer: A cloud of stellar dust from part of a Nebula collapsed causing hydrogen atoms to fuse together
Explanation:
A baby was born on his due date, but doctors determined that a valve in his heart was too short to adequately pump blood to his body. The baby passed away after eight months. Which best describes the cause of his death?
He had a congenital condition.
He was premature.
He died in an accident.
He suffered SIDS.
Answer:
He had a cogenital condition
Explanation:
cogenital conditions are present before or at the time of birth and are considered birth defects
Answer:
The answer is C- He had a congential condition.
Explanation:
Edge
describe the human condition before Science and technology was practice.
WHY ARE ALL GIRLS THE SAME, don't even say their not cause if you say that then I guess you don't have a life!!!!!
two automobiles a and b are travelling in the same direction in adjacent lanes are stopped at a traffic signal. as the signal turns green, automobile a accelerates at a constant rate of 2 m/s2. two seconds later, automobile b starts and accelerates at a constant rate of 3.6 m/s2. determine (a) when b will overtake a, (b) the speed of each automobile at that time, and c) the location where b overtakes a relative to the traffic signal. -truck
Answer:
a.5.85 s b i. 15.7 m/s ii. 21.1m/s c. 61.62 m
Explanation:
(a) when b will overtake a,
Using s = ut + 1/2at² we express the distance moved by each automobile.
Since both automobiles start at rest, their initial speed, u = 0 m/s, a = acceleration of automobile and t = time of travel or overtaking
So s = 0 × t + 1/2at²
s = 0 + 1/2at²
s = 1/2at²
Let time, t be the time the automobile b start, and its acceleration a = 3.6 m/s²
So, s = 1/2 × 3.6 m/s² × t² = 1.8t²
Since automobile a starts 2 seconds earlier, its time of travel is (t + 2) s. Since its acceleration, a = 2 m/s²,
s = 1/2 × 2 m/s² × (t + 2)²
s = (t + 2)²
Since both distances are equal at overtaking
(t + 2)² = 1.8t²
t² + 4t + 4 = 1.8t²
1.8t²- t² - 4t - 4 = 0
0.8t² - 4t - 4 = 0
dividing through by 0.8, we have
0.8t²/0.8 - 4t/0.8 - 4/0.8 = 0
t² - 5t - 5 = 0
Using the quadratic formula to find t,
[tex]t = \frac{-(-5) +/-\sqrt{(-5)^{2} - 4 X 1 X (-5)} )}{2 X 1} \\t = \frac{5 +/-\sqrt{25 + 20} )}{2} \\t = \frac{5 +/-\sqrt{45} )}{2} \\t = \frac{5 +\sqrt{45} )}{2} or \frac{5 -\sqrt{45} )}{2}\\t = \frac{5 + 6.708 )}{2} or \frac{5 - 6.708)}{2}\\t = \frac{11.708 )}{2} or \frac{-1.708}{2}\\t = 5.854 sor -0.854 s[/tex]
t ≅ 5.85 or -0.85
We take the positive answer since t cannot be negative.
So, t = 5.85 s
So, b will overtake a 5.85 s later.
(b) the speed of each automobile at that time,
Using v = u + at for each automobile, where u =initial speed of automobile = 0 m/s (since they both start from rest), a = acceleration of automobile and t = time of travel of automobile
i. Speed of automobile a
For automobile a, its time of travel is (t + 2) s = 5.85 s + 2 s = 7.85 s and its acceleration is 2 m/s²
So, v = u + at
= 0 m/s + 2 m/s² × 7.85 s
= 0 m/s + 15.7 m/s
= 15.7 m/s
ii. Speed of automobile b
For automobile a, its time of travel is t s = 5.85 s and its acceleration is 3.6 m/s²
So, v = u + at
= 0 m/s + 3.6 m/s² × 5.85 s
= 0 m/s + 15.7 m/s
= 21.06 m/s
≅ 21.1 m/s
c) the location where b overtakes a relative to the traffic signal. -truck
The location where b overtakes a relative to the traffic signal is the distance each automobile moves before overtaking. In section (a), we foundthat distance s = 1/2at² = (t + 2)² = 1.8t²
Using s = (t + 2)²
= (5.85 + 2)²
= 7.85²
= 61.6225 m
≅ 61.62 m
explain why a diver at the bottom of the sea feels more pressure than one who is swimming on the surface of water
Answer:
the deeper into the ocean you go, the more pressure is exerted on you
Explanation:
A student pushes a 12 N book to the
right with a force of 10 N. The book
experiences a frictional force of 3 N.
Answer:
Explanation:
My name is Jeff
Which machine do you think will last longer, the traditional battery and motor, or the free energy machine?
Answer:
it will most likely be the free energy
What is the equivalent resistance of the circuit?
Answer:
(B) 80 ohms
Explanation:
Since the circuit is a series connection, simply add the two resistances together to get 80 ohms.
All objects have an electric charge, what are the options they could have select all that apply.
Positive
Negative
Neutral
Select the correct answer.
Which type of energy is thermal energy a form of
Will give brainliest!!
How much KClO3 is needed to make a saturated solution in 100 mL of water at 70⁰ C?
Answer:
iam not sure but I think its NaNO3
A 0.40 kg block can slide up and down a rough a 10-m-high, 30-m-long slope. At the bottom, a stiff spring with spring constant 800 N/m is compressed 0.50 m and used to launch the block up the slope. The friction force on the block from the slope is 1.2 N. What is the speed of the block when it reaches the top of the slope, in m/s
Answer:
[tex]v=11.135m/s[/tex]
Explanation:
From the question we are told that
Mass [tex]m=0.40kg[/tex]
Frictional friction [tex]f=1.2[/tex]
Spring constant [tex]k=800N/m[/tex]
Compressed [tex]x=0.50[/tex]
Generally the energy balance equation is mathematically given as
[tex]1/2kx^2=f*30+m*g*sin \theta*30+1/2m*v^2[/tex]
if [tex](sin=10/30-1/3)[/tex]
[tex]1/2(800)(0.5)^2=(1.2)*30+(0.4)*9.8*1/3*30+1/2(0.4)*v^2[/tex]
[tex]100=36+39.2+0.20v^2[/tex]
[tex]v^2=\frac{24.8}{0.20}[/tex]
[tex]v=\sqrt{124}[/tex]
[tex]v=11.135m/s[/tex]
An iron wire has a length of 1.50 m and a cross sectional area of 0.450 mm2. If the resistivity of iron is 10.0 ✕ 10−8 Ω · m and a potential difference of 0.800 V is maintained across its length, determine the current in the wire (in A)
Answer:
2400A
Explanation:
R=pL/A
R-Resistance
p-Resistivity=10.0 x 10^-8
L-1.5m
A-Cross sectional Area=0.00045
R=10.0 x 10^-8 x 1.5 ÷ 0.00045
and=0.000333333
I-current
V-potential difference
I=V/R
0.800÷0.000333333
Ans=2400A
an object has a velocity of 0.12 rad/s. how many revolutions will the object make after traveling for 30 seconds?
Answer:
We can write S = v * t where S is the distance traveled in time t
S = .12 rad/sec * 30 sec = 3.6 rad distance traveled
Also 2 * pi * N = S since there are 2 * pi rad / revolution
So 2 * pi * N = 3.6
N = 3.6 / (2 * pi) = .573 revolutions
Question 9 of 10
What happens to light as it moves at an angle into a medium that has a higher index of refraction?
A. It slows down, and the angle decreases.
B. It speeds up, and the angle increases.
C. It slows down, and the angle increases.
D. It speeds up, and the angle decreases.
Answer:
v = C / n light slows entering a medium of higher index of refraction
ni sin theta i = nr sin theta r Snell's Law where i refers to incidence and r refers to refraction
sin theta r = (ni / nr) sin theta i
So if the index of refraction is greater than the angle of incidence then the light ray would be refracted towards the normal
Answer:
A. It slows down, and the angle decreases.
Explanation:
got it right, trust
Two electrostatic point charges of +62.0 µC
and +43.0 µC exert a repulsive force on each
other of 189 N.
What is the distance between the two
charges? The value of the Coulomb constant
is 8.98755 × 109 N · m2
/C
2
.
Answer in units of m.
You need to design a spring that will launch a 1060 kg satellite with a speed of 3.35 m/s relative to an orbiting space station. The maximum safe acceleration of the satellite is 5.00g, (g being the usual gravitational field constant on the surface of the Earth). The spring's mass, the recoil kinetic energy of the space station, and changes in gravitational potential energy will all be negligible.What must the force constant of the spring be
Answer:
226.8 kN/m
Explanation:
The work done by the spring, W equals the kinetic energy of the satellite, K
W = K
work done by the spring, W = 1/2kx² where k = force constant and x = extension of spring
kinetic energy of the satellite, K = 1/2mv² where m = mass of satellite = 1060 kg and v = speed of satellite = 3.35 m/s
1/2kx² = 1/2mv²
k = mv²/x²
Also, the spring force F = kx where k = force constant and x = extension of spring.
k = F/x
equation both expressions for k, we have
mv²/x² = F/x
x = mv²/F since F = ma where m = mass of satellite and a = maximum acceleration of satellite = 5.00g and g = 9.8 m/s²
x = mv²/ma = mv²/5.00mg = v²/5.00g
Substituting the values of the variables into the equation, we have
x = v²/5.00g
= (3.35 m/s)²/(5.00 × 9.8 m/s²)
= 11.2225 m²/s²/49 m/s²
=0.229 m
Now k = F/x = 5.00mg/x
Substituting the values of the variables into the equation, we have
k = 5.00mg/x
k = 5.00 × 1060 kg × 9.8 m/s²/0.229 m
k = 51940 kgm/s²/0.229 m
k = 51940 N/0.229 m
k = 226812.23 N/m
k = 226.81223 kN/m
k ≅ 226.8 kN/m
A disk of a radius 50 cm rotates at a constant rate of 100 rpm. What distance in meters will a point on the outside rim travel during 30 seconds of rotation?
Answer:
The point will travel a distance of 15708 centimeters in 30 seconds of rotation.
Explanation:
In this case, we see a disk rotating at constant rate, the travelled distance of a point on the outside rim ([tex]s[/tex]), in centimeters, is determined by using this expression:
[tex]s = \omega \cdot r\cdot t[/tex] (1)
Where:
[tex]\omega[/tex] - Angular speed, in radians per second.
[tex]r[/tex] - Radius of the disk, in centimeters.
[tex]t[/tex] - Time, in seconds.
If we know that [tex]\omega \approx 10.472\,\frac{rad}{s}[/tex], [tex]r = 50\,cm[/tex] and [tex]t = 30\,s[/tex], then the travelled distance of the point is:
[tex]s = \omega \cdot r\cdot t[/tex]
[tex]s = 15708\,cm[/tex]
The point will travel a distance of 15708 centimeters in 30 seconds of rotation.
what is a black whole why does it exist
Answer:
A black hole is a region of spacetime where gravity is so strong that nothing—no particles or even electromagnetic radiation such as light—can escape from it. The theory of general relativity predicts that a sufficiently compact mass can deform spacetime to form a black hole.
Why do astronomers use frequencies other than the visible ones when they are
investigating the universe?
Which of these is an example of tertiary prevention?
A. Getting screened for skin cancer
B. Avoiding smoking and drinking alcohol
C. Dialysis for damaged kidneys
D. Washing hands
Explanation:
because a tertiary prevention is when the person is already infected with the disease
