Magnitude of initial velocity
To calculate the magnitude of the velocity at any point in time, multiply the constant acceleration rate times the time difference and then add it to the initial velocity. As an example, if you dropped a rock off a cliff, its velocity increases by 32 feet per second, every second.
Hope this helps you a lot ...Good day :)
Answer:
magnitude of initial velocity
Explanation:
To calculate the magnitude of the velocity at any point in time, multiply the constant acceleration rate times the time difference and then add it to the initial velocity. As an example, if you dropped a rock off a cliff, its velocity increased by 32 feet per second, every second
A force of 30 Newtons is used to push a basket along the floor a total distance of 3 meters. How much work is done on the basket?
Answer:
the total work done is 90J
Explanation:
the reason why is because you are the force (30 newtons) and the metere (3) so you will be multiplying those two numbers together.
W= FD 30(3)= 90J
To obtain the number of meters from a distance measured In centimeters, you must ____ by the number _____
Answer:
Divide by the number 100
Explanation:
Since there are 100 centimeters in 1 meter, we can see that if you are given a number in centimeters, the number of meters is that number divided by 100. Hope this helps!
Answer:
Divide by 100
Explanation:
The ratio between the force of sliding friction and the normal force of an object is called
rolling friction
the drag
the coefficient of friction
the starting friction
(ILL GIVE BRAINLEST)
Watch the video linked here
Can you give me a summary of 3 sentences please it's for today at 6:00
Answer:
can you send the link i still want to help its better than watching netflix
Explanation:
What is the time interval in which the average velocity is Positive?
Answer:
between 0s and 0.5s
Explanation:
the objects position is moving away from the origin and the position-versus-time curve has a positive slope
Mendel wanted to find out if the pattern of inheritance for one trait affected the pattern of inheritance for anther. What experiment did he perform to test this idea?
Answer is given below :
Explanation:
He tested the seed color and shape. At the same time Gregor Mendel focused his search on seed size, flower color, seed coat color, pod size, immature pod color, flower position and pea plant height. To describe the results he drew, he coined the terms 'recessive' and 'dominant'.Answer:
The answer is that he tested seed color and shape that same time
Explanation:
if 8000cm3 of liquid drains off an hour glass in one hour, what is the flow rate of water from the clock
Answer:
8000cm³/hr
Explanation:
Given parameters:
Volume of the liquid draining off per hour = 8000cm³
Time taken to drain off = 1hr
Unknown:
Flow rate = ?
Solution:
Flow rate is the volume of fluid that passes per unit of time.
Flow rate = [tex]\frac{volume of fluid}{time taken}[/tex]
Flow rate = [tex]\frac{8000cm^{3} }{1hr}[/tex]
Flow rate = 8000cm³/hr
Someone answer these questions please???
Answer:
a. same
b. less
c. less
Explanation:
you can use the position, time, acceleration equation
xf=xi + vi*t+(at^2)/2
you can say the final distance will greater for X than Y
using acceleration for gravity a=9.81m/s^2
a. both X and Y will have the same acceleration due to gravity
b. to solve for final speed vf=vi+gt
since the initial velocity is 0 and X will take longer to fall, Y will hit the ground with less speed
c. as mentioned before, X will take longer to fall; therefore Y will have less time of descent.
A 4,350 kg truck traveling east has a momentum of 26,100kg m/s what's the trucks velocity
Answer:
6 m/s East
Explanation:
Momentum = Mass . Velocity
26100 = 4350. Velocity
Velocity = 6m/s East
The combined mass of a race car and its driver is 600 kg. Travelling at constant speed, the car completes one lap around a circular track of radius 160 m in total time of 36 s. What is the magnitude of the centripetal acceleration of the car?
Answer:
4.88m/s²
Explanation:
Given parameters:
Mass of the race car and driver = 600kg
Radius of path = 160m
time taken = 36s
Unknown:
Centripetal acceleration = ?
Solution:
The centripetal acceleration is the change in velocity of a body along a circular path with time.
It is mathematically expressed as;
a = [tex]\frac{v^{2} }{r}[/tex]
v is the velocity
r = radius of path
v = [tex]\frac{2\pi r}{t}[/tex]
t is the time;
Insert the parameters and solve for the velocity;
v = [tex]\frac{2 x \pi x 160}{36}[/tex] = 27.9m/s
Now,
acceleration = [tex]\frac{27.9^{2} }{160}[/tex] = 4.88m/s²
The magnitude of the centripetal acceleration of the car is [tex]4.87 \;\rm m/s^{2}[/tex].
Given data:
The combined mass of race car and its driver is, m = 600 kg.
The radius of the circular track is, r = 160 m.
The time taken to cover one lap is, t = 36 s.
The velocity of the car while covering one complete lap of circular track is given as,
[tex]v = \dfrac{2 \pi r}{t}\\\\v = \dfrac{2 \pi \times 160}{36}\\\\v = 27.92 \;\rm m/s[/tex]
And the expression for the magnitude of centripetal acceleration is given as,
[tex]a=\dfrac{v^{2}}{r}\\\\a=\dfrac{27.92^{2}}{160}\\\\a=4.87 \;\rm m/s^{2}[/tex]
Thus, we can conclude that the magnitude of the centripetal acceleration of the car is [tex]4.87 \;\rm m/s^{2}[/tex].
Learn more about the centripetal acceleration here:
https://brainly.com/question/6082363
What is the net force required to accelerate a 1.1 kg box at a rate of 2.8
m/s??
Answer:
Fnet = 13.86N
Explanation:
Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.
Mathematically, net force is given by the formula;
[tex] Fnet = Fapp + Fg[/tex]
Where;
Fnet is the net force Fapp is the applied forceFg is the force due to gravitationGiven the following data;
Mass = 1.1kg
Acceleration = 2.8m/s²
To find the applied force;
[tex] Fapp = ma[/tex]
Substituting into the equation, we have;
[tex] Fapp = 1.1 * 2.8[/tex]
Fapp = 3.08N
To find the gravitational force;
We know that acceleration due to gravity, g = 9.8m/s²
[tex] Fg = mg[/tex]
Substituting into the equation;
[tex] Fg = 1.1 * 9.8[/tex]
Fg = 10.78N
To find the net force;
[tex] Fnet = Fapp + Fg[/tex]
Substituting into the equation, we have;
[tex] Fnet = 3.08 + 10.78[/tex]
Fnet = 13.86N
Therefore, the net force required is 13.86N
Enter the number only - NO UNITS!
Calculate the speed of an object that travels 150 meters in 50 seconds.
Answer:
The answer is 3Explanation:
The speed of an object can be found by using the formula
[tex]s = \frac{d}{t} \\ [/tex]
d is the distance
t is the time taken
From the question we have
[tex]s = \frac{150}{50} = \frac{15}{5} \\ [/tex]
We have the final answer as
3 m/sHope this helps you
Answer:
110
Explanation:
i dont know
plz meeeeeeeeeeeeeeeee as brainliest❤❤❤❤❤✌✌✌✌p.s today is my birthday
Rohith has been jogging to the bus stop for 2.0 minutes at 3.5 m/s when he looks at
his watch and sees that he has plenty of time before the bus arrives. Over the next
10.0s, he slows his pace to a leisurely 0.75 m/s. What was his average acceleration
during this 10.0 s?
Dose the atoms in a solid move freely or remain in a fixed position ?
1-Find the gravitational force
between two objects the first
one is 25 kg and the seconed
one is 0.55 kg and the distance
between it is 35 m.
[tex]g = \frac{GMm}{r^2}[/tex]
where [tex]G[/tex] is the gravitational constant and is about [tex]6.67 * 10^{-11}[/tex]
[tex]g = \frac{6.67 * 10^{-11} * 25 * 0.55}{35^2}[/tex]
[tex]g = \frac{6.67 * 10^{-11} * 25 * 0.55}{1225} = 0.000000000000749 N[/tex] :D
Yol
An autographed baseball rolls off of a 1.2
m high desk and strikes the floor 0.28 m away
from the desk.
How fast was it rolling on the desk before
it fell off? The acceleration of gravity is
9.81 m/s2.
Answer in units of m/s.
Where is a good place to check your pulse?
A.
Wrist
B.
Face
C.
Stomach
D.
Ear
Answer:
a
a
a
a
a
a
a
a
a
a
a
a
a
a
a
a
a
a
a
a
a
a
Explanation:
Answer:
A. Wrist
Explanation:
Arteries run closely to the surface of the skin at the wrist and neck making the pulse particularly easy to find at these points.
where is the centripetal force directed on a banked curve?
Answer:
The net force on a car traveling around a curve is the centripetal force, Fc = m v2 / r, directed toward the center of the curve.
Explanation:LET ME KNOW IF ITS WRONG. HAVE A NICE DAY!!!!!!!!!!
Answer: The net force on a car traveling around a curve is the centripetal force, Fc = m v2 / r, directed toward the center of the curve. The centripetal force is directed at right angles to the motion and also along the radius towards the centre of the circular path. In order for a car to move around a circular track, something must provide a centipetal force. One source of the centripetal force is friction between the tires and the road. This means that the tires do not need to supply any friction at all to keep the car from slipping sideways. ...
Hope this helps... stay safe and have a great day!!! :D
How does Health & Physical Education relate to any other subject you now study in
school?
Answer:
Health relates to science because
in science you study, research, and knowledge in this case, health science, which helps you under stand more about how humans and animals function. And Physical education relates to science because , you study the way of human movement, think of push-ups as a example.
I hope I helped U ´꓃ ` U
helppppppppppppppppp
Answer:
Burning of paper
Explanation:
Because new substance is formed
What is Sound and state examples ?
In physics :
Sound is a vibration that propagates as an acoustic wave, through a transmission medium such as a gas, liquid or solid.
In human physiology and psychology ;
Sound is the reception of such waves and their perception by the brain. .
nd is the reception of such waves and their perception by the brain. .
In simple words ;
Sound is the vibration that travels through the air or another medium as an audible mechanical wave( It is produced from a vibrating body. The vibrating body causes the medium (water, air, etc.) around it to vibrate thus producing sound. An
It is produced from a vibrating body. The vibrating body causes the medium (water, air, etc.) around it to vibrate thus producing sound. AnAn air conditioning fan. It is produced from a vibrating body. The vibrating body causes the medium (water, air, etc.) around it to vibrate thus producing sound. AnAn air conditioning fan.An airplane taking off. It is produced from a vibrating body. The vibrating body causes the medium (water, air, etc.) around it to vibrate thus producing sound. AnAn air conditioning fan.An airplane taking off.A ballerina dancing in toe shoes. It is produced from a vibrating body. The vibrating body causes the medium (water, air, etc.) around it to vibrate thus producing sound. AnAn air conditioning fan.An airplane taking off.A ballerina dancing in toe shoes.A balloon popping. It is produced from a vibrating body. The vibrating body causes the medium (water, air, etc.) around it to vibrate thus producing sound. AnAn air conditioning fan.An airplane taking off.A ballerina dancing in toe shoes.A balloon popping.The bell dinging on a microwave. It is produced from a vibrating body. The vibrating body causes the medium (water, air, etc.) around it to vibrate thus producing sound. AnAn air conditioning fan.An airplane taking off.A ballerina dancing in toe shoes.A balloon popping.The bell dinging on a microwave.A boom box blaring. It is produced from a vibrating body. The vibrating body causes the medium (water, air, etc.) around it to vibrate thus producing sound. AnAn air conditioning fan.An airplane taking off.A ballerina dancing in toe shoes.A balloon popping.The bell dinging on a microwave.A boom box blaring.A broom swishing. It is produced from a vibrating body. The vibrating body causes the medium (water, air, etc.) around it to vibrate thus producing sound. AnAn air conditioning fan.An airplane taking off.A ballerina dancing in toe shoes.A balloon popping.The bell dinging on a microwave.A boom box blaring.A broom swishing.A buzzing bee.A skater of mass 60 kg has an initial velocity of 12 m/s. He slides on ice where the frictional force is 36 N. How far will the skater slide before he stops?
Answer:
d = 120 [m]
Explanation:
In order to solve this problem, we must use the theorem of work and energy conservation. Where the energy in the final state (when the skater stops) is equal to the sum of the mechanical energy in the initial state plus the work done on the skater in the initial state.
The mechanical energy is equal to the sum of the potential energy plus the kinetic energy. As the track is horizontal there is no unevenness, in this way, there is no potential energy.
E₁ + W₁₋₂ = E₂
where:
E₁ = mechanical energy in the initial state [J] (units of Joules)
W₁₋₂ = work done between the states 1 and 2 [J]
E₂ = mechanical energy in the final state = 0
E₁ = Ek = kinetic energy [J]
E₁ = 0.5*m*v²
where:
m = mass = 60 [kg]
v = initial velocity = 12 [m/s]
Now, the work done is given by the product of the friction force by the distance. In this case, the work is negative because the friction force is acting in opposite direction to the movement of the skater.
W₁₋₂ = -f*d
where:
f = friction force = 36 [N]
d = distance [m]
Now we have:
0.5*m*v² - (f*d) = 0
0.5*60*(12)² - (36*d) = 0
4320 = 36*d
d = 120 [m]
Convert 7.5 g/cm3 to kg/m3
Answer:
7500
Explanation:
multiply the mass / volume value by 1000
A group of students conduct an experiment with a block of wood sliding down an incline. They find that the final energy of the block is less than the initial energy of the block. Which statement best describes this situation?(1 point)
The students made an error in calculating the initial energy.
Some energy was transformed to other forms.
Some energy was destroyed or lost.
The students made an error in determining the final energy.
Answer:
1) 51 m
2) Some energy was transformed to other forms. (This question)
3) 3.24 J
4) 45 J
5) 1020 J
Explanation:
100%
If a feather takes 2.5 seconds to drop 200cm, what is the speed of this feather
Answer:
80cm per second
Explanation:
A 2.1W iPod is used for 30 minutes. How much energy does it use?
1.A Radio station broadcasts modern song on medium wave 350 Hz every day at ten o’clock in the morning. The velocity of radio wave is 3X108 ms-1. The wavelength of another wave created in water is one percent of the radio wave and the velocity of sound in water is 1450 ms-1.
How many times of the frequency of the radio wave that of the wave created in the water? Analyze mathematically.
Answer:
[tex]ans \: = \boxed{{4.8 \times 10}^{ - 4} Hz}[/tex]
Explanation:
[tex]given \to \\ f_{r} = 350 \: \\ v_{r} = {3 \times 10}^{8} \\ but \to \\ v = f \gamma \to \: \gamma = \frac{v}{f} : hence \to \\ \gamma _{r} = \frac{v_{r}}{f_{r}} = \frac{3 \times 10^{8} }{350} = \boxed{857,142.85714 \: m}\\ therefore \to \\ given \to \\ f_{w} = water \: frequency = \: \boxed{ ?}\: \\ v_{w} = 14 50 \\ but \to \\ v = f \gamma \to \: \gamma = \frac{v}{f} : hence \to \\ \gamma _{w} = \frac{v_{w}}{f_{w}} = \frac{1}{100} \times \gamma _{r} = \frac{1}{100} \times 857,142.85714 \\\gamma _{w} = \boxed{8,571.4285714 \: m} : hence \to \: \\ f_{w} = \frac{v_{w}}{ \gamma _{w}} = \frac{1450}{8,571.4285714} = \boxed{0.1691666667} \\ if \: the \: number \: of \: times = \boxed{ x} \\ f_{r} (x)=f_{w} \\ (x) = \frac{f_{w}}{f_{r}} = \frac{0.1691666667}{350} = 0.0004833333 \\ hence \to \\ the \: frequency \: of \: the \: radio \: wave \: is \to \: \boxed{{4.8 \times 10}^{ - 4} }\: \\ that \: of \: the \: wave \: created \: in \: the \: water.[/tex]
♨Rage♨
During a race, a sprinter increases from 5.0 m/s to 7.5 m/s over a period of 1.25s. What is the sprinter’s average acceleration during this period?
Answer:
[tex]\boxed {\boxed {\sf 2 \ m/s^2}}[/tex]
Explanation:
Acceleration can be found by dividing the change in velocity by the time.
[tex]a=\frac{\Delta v}{t}[/tex]
The time is 1.25 seconds. The change in velocity is the difference between the initial velocity and the final velocity.
[tex]\Delta v=v_f-v_i[/tex] The final velocity is 7.5 m/s and the initial velocity is 5.0 m/s[tex]\Delta v =7.5 \ m/s-5.0 \ m/s=2.5 \ m/s[/tex][tex]\Delta v= 2.5 \ m/s\\t=1.25 \ s[/tex]
Substitute the values into the formula.
[tex]a=\frac{2.5 \ m/s}{1.25 \ s}[/tex]
Divide.
[tex]a=2 \ m/s^2[/tex]
The sprinter's average acceleration is 2 meters per second squared.
Answer: 2 m/s^2
Explanation: Hope this helps :)
What Machines that help you go faster
Answer:
If you mean for exercising then, The Treadmill. Purists may claim that treadmill running isn't "real" running. ...
The Elliptical Trainer. ...
The Stair-Climber. ...
The Cross-Country Skiing Simulator. are all machines that help you practice agility
Explanation:
The kinetic energy of a golf ball is measured to be 140.5 J. If the golf ball has a mass of about 40g, what is its speed
Answer:
V= in square root 2KE/M=2(143.3J)/0.047kg=6097.8723 in square root around 78.1 approxmete
Explanation:
