Answer:
Just put it into a calculator
0.97053528353
[tex]\text{Let's find the sine of -105 degrees}\\\text{Start by typing -105 into our calculator}\\\text{and click the sin button}\\\text{It gives us an irrational number, which is the sine of -105 degrees}[/tex]
[tex]\rule{300}{1.7}[/tex]
[tex]\text{The value is end less, it would take an eternity to type it here,}\\\text{ but I will round it to the nearest 100th}[/tex]
[tex]\rule{300}{1.7}[/tex]
[tex]\text{-0.97}[/tex]
Question 15 (06.01 LC)
Classify the expression: 5x³ - 4x²
Quadratic expression
Linear expression
Cubic expression
Constant expression
Answer:
Cubic expression
Step-by-step explanation:
Polynomials with a degree of 3 are known as cubics.
Answer:
cubic expression
Step-by-step explanation:
it is cubic when raised to the power of 3
Answer this! Thanks so much in advance (:
Answer:
ai) m = 17, applicable past x = 23/17; aii) m = 4; applicable past 3 dad jokes
Step-by-step explanation:
to calculate slope you use the (y2 - y1) / (x2 - x1) equation
so for the first one
(62 - 11) / (5 - 2)
51 / 3 = 17
the equation for this is y = 17x + b
plug in values to find b
11 = 34 + b
b is -23
y = 17x - 23
because distance cannot be negative we must find when x is exactly 0 to find where it is applicable
17x = 23
x = 23/17
for the second one we can subtract again
(10 - 2) / (5 - 3)
8 / 2
4 is the slope
like before we must find b and then find where y is 0
y = 4x + b
2 = 12 + b
b = -10
y = 4x - 10
4x = 10
x = 5/2
since you cannot have 1/2 a dad joke we round up from 2 1/2 to 3
find the volume of the rectangular prism WILL MARK BRAINLEST
Step-by-step explanation:
volume= l×w×h
1.1/3×1/2×2/3
=1/9
2. 3/4×1/8×13/16
=39/512
3. 1/12×7/8×1/4
=7/384
4. 3/2×1/7×7/8
=3/16
5. 1/5×9/10×2/3
=3/25
6.6/7×7/8×1/2
=3/8
Find dy/dx if y =x^3+5x+2/x²-1
How would I go about finding this? I would appreciate if you could be as detailed as possible!
Differentiate using the Quotient Rule –
[tex]\qquad[/tex][tex]\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\[/tex]
According to the given question, we have –
f(x) = x^3+5x+2 g(x) = x^2-1Let's solve it!
[tex]\qquad[/tex][tex]\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\[/tex]
[tex]\qquad[/tex][tex]\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2) \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\[/tex]
[tex]\qquad[/tex][tex]\twoheadrightarrow \sf \dfrac{(x^2-1)(3x^2+5) - ( x^3+5x+2) 2x}{(x^2-1)^2 }\\[/tex]
[tex]\qquad[/tex][tex] \pink{\sf \because \dfrac{d}{dx} x^n = nx^{n-1} }\\[/tex]
[tex]\qquad[/tex][tex]\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-(2x^4+10x^2+4x)}{(x^2-1)^2 }\\[/tex]
[tex]\qquad[/tex][tex]\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-2x^4-10x^2-4x}{(x^2-1)^2 }\\[/tex]
[tex]\qquad[/tex][tex]\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\[/tex]
[tex]\qquad[/tex][tex]\pink{\therefore \bf{\green{\underline{\underline{\dfrac{d}{dx} \dfrac{x^3+5x+2 }{x^2-1}} = \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}}}}\\\\[/tex]
Which of the following is the standard equation of the ellipse with vertices at (1, 0) and (11, 0) and an eccentricity of three fifths question mark
quantity x minus 6 end quantity squared over 100 plus y squared over 64 equals 1
quantity x plus 6 end quantity squared over 64 plus y squared over 100 equals 1
quantity x plus 6 end quantity squared over 16 plus y squared over 25 equals 1
quantity x minus 6 end quantity squared over 25 plus y squared over 16 equals 1
The equation fourth represents the ellipse that has vertices at (1, 0) and (11, 0), and an eccentricity of 3/5 option fourth is correct.
What is an ellipse?An ellipse is a locus of a point that moves in a plane such that the sum of its distances from the two points called focus adds up to a constant. It is taken from the cone by cutting it at an angle.
We have:
The vertices of the ellipse = (1, 0) and (11, 0)
Eccentricity of ellipse = 3/5
We have equations:
[tex]\rm \dfrac{\left(x-6\right)^{2}}{100}+\dfrac{y^{2}}{64}=1[/tex]
[tex]\rm \dfrac{\left(x+6\right)^{2}}{64}+\dfrac{y^{2}}{100}=1[/tex]
[tex]\rm \dfrac{\left(x+6\right)^{2}}{16}+\dfrac{y^{2}}{25}=1[/tex]
[tex]\rm \dfrac{\left(x-6\right)^{2}}{25}+\dfrac{y^{2}}{16}=1[/tex]
From the fourth equation:
The vertices of the ellipse:
(1, 0) and (11, 0)
The eccentricity:
c² = a² - b²
c² = 25-16
c = 3
e = c/a = 3/5
Thus, the equation fourth represents the ellipse that has vertices at (1, 0) and (11, 0), and an eccentricity of 3/5 option fourth is correct.
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A
Choose the correct statement about best-fit lines.
a.
A best-fit line is close to most of the data points.
b. A best-fit line describes the exact coordinates of each point in the data set.
C.
A best-fit line always has a positive slope.
d. A best-fit line must go through at least two of the data points.
Please select the best answer from the choices provided
Α
B
C
D
Answer:
Your answer would be A.
Step-by-step explanation:
okay so, with a best fit line, it needs to match up with your points. unless your points go up evenly. its not going to connect to all your points.
pls help me solve for x in this equation! + brainest
Answer:
x = -3
Explanation:
[tex]\rightarrow \sf \sqrt[3]{\sf 3x + 1} = -2[/tex]
[tex]\rightarrow \sf \sf 3x + 1 = (-2)^3[/tex]
[tex]\rightarrow \sf \sf 3x + 1 = -8[/tex]
[tex]\rightarrow \sf \sf 3x = -8-1[/tex]
[tex]\rightarrow \sf \sf 3x = -9[/tex]
[tex]\rightarrow \sf \sf x = -3[/tex]
Answer:
[tex]\sqrt[3]{3x+1} =-2\\(\sqrt[3]{3x+1})^{3} =(-2)^{3} \\3x+1=-8\\3x=-9\\x=-3[/tex]
Hope it helps!
The table shows ordered pairs of the function y=8-2x. What is the value of y when x = 8?
X
-3
-1
1
4
8
10
y
14
10
6
0
?
-12
Answer: -8
Step-by-step explanation:
[tex]y=8-2(8)=\boxed{-8}[/tex]
What is the main difference between confirmatory and exploratory factor analysis? (CFA vs EFA)
O a. In CFA, SPSS is required to build the model
O b. In CFA, the researcher does not define the model
O c. In CFA, the researcher defines the model
O d. In CFA, factor rotation is required
Oe In CFA, there is no model
Answer:
in exploratory factor analysis all the measures variables are related to every legend variable but in confirmatory factor analyse CFA research 10 specifically the number of factors required in the data in which measures variable is related with talent variable
Find the equation of the line using the given information.
(x, y) = (−3, 0)
and
(x, y) = (−3, 7)
are points on the line
HELP DUE SOON A farmer has decided to divide his land area in half in order to plant soy and corn. Calculate the area of the entire area so he knows how much soil is needed.
A parallelogram with a height of 6 yards and side length 9 yards. The height forms a triangle with the slanted side of the rhombus with a base of 2.5 yards. Rhombus is split into a soy half and a corn half.
Each bag of soil covers 20 square yards. How many bags should the farmer purchase?
The farmer should purchase 2 bags of soil for his farm.
What is Area of parallelogram?A parallelogram is a two-dimensional figure with four sides. It is a special case of the quadrilateral, where opposite sides are equal and parallel. The area of a parallelogram is the space enclosed within its four sides. Area is equal to the product of length and height of the parallelogram.
The shape of the farm, according to the picture is a parallelogram. Therefore, the total area can be calculated as follows:
Area = base X height
where
b = base
h = height
base = 6.5 + 2.5 = 9.0 yards
height = 6 yards
Area = 6 × 9 = 54 square yards.
40 square yards requires 1 bag of soil .
54 square yards will require ?
Bags required = 54 / 40 = 1.35 bag
Thus, the farmer will require 2 bags of soil for his farm.
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What is the present value of a cash inflow of 1250 four years from now if the required rate of
return is 8% (Rounded to 2 decimal places)?
Using simple interest, it is found that the present value of the cash inflow is of 947.
Simple InterestSimple interest is used when there is a single compounding per time period.
The amount of money after t years in is modeled by:
A(t) = A(0)(1 + rt)
In which:
A(0) is the initial amount.r is the interest rate, as a decimal.In this problem, the parameters are given as follows:
r = 0.08, t = 4, A(t) = 1250.
We have to solve for A(0) to find the present value, hence:
A(t) = A(0)(1 + rt)
1250 = A(0)(1 + 0.08 x 4)
A(0) = 1250/1.32
A(0) = 947.
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3x+6-2 = 6x-(7/2*9/0)
[tex]3x+6-2 = 6x-( \frac{7}{2} \times \frac{9}{0} ) \\ \\ 3x + 4 = 6x - \frac{63}{0} \\ \\ 3x + 4 = 6x - 0 \\ \\ 4 + 0 = 6x - 3x \\ \\ 3x = 4 \\ \\ x = \frac{4}{3} .[/tex]
The value of x is 4/3 .
Answer: No Solution
Why?
Any number divided by 0 is not defined, but we are given 9/0 in the question. Hence we cannot solve the equation for the value of ‘x’.
Solve x2 + 4x + 12 = 0 by completing the square.
x = –2 + 2i, x = –2 –2i
x = –2 + i, x = –2 – i
x = –2 + 2i, x = –2 – 2i
x = 0, –4
Answer:
See below
Step-by-step explanation:
x2 + 4x + 12 = 0 Complete the square ( take 1/2 of the 'x' coefficient, then square it and add it to both sides of the equation
x^2 + 4x + 2^2 + 12 = 2^2 Subtract 12 from both sides
x^2 + 4x + 4 = -8
(x+2)^2 = - 8 sqrt both sides
(x+2) =± sqrt (-8) simplify just a bit
x+2 = ±(2i sqrt2) subtract 2 from both sides
x = -2 ± 2i sqrt 2 <===== I do not see that answer listed
A car travels at 80 km an hour. How far will it travel in 2 1/2 hours?
Using approximations to 1 significant figure, estimate the value of:
[tex]\frac{0.482 * 61.2x^{2} }{\sqrt{98.01}}[/tex]
* = times by :D
Will pick Brainliest if right!
Answer:
3x²
Step-by-step explanation:
0.482 to 1sf is 0.5
61.2x² to one sf is 60x²
√98.01 to 1sf is √100
√100 = 10
0.5 x 60x² = 30x²
30x² / 10 = 3x²
On a certain day, the high temperature in city A was 93° F. On the same day, the high temperature in city B was -6° F. What was the difference in temperature between city A and city B?
Answer:
99°F
Step-by-step explanation:
The high temperature in city A was 93° F. On the same day, the high temperature in city B was -6° F.
The difference in temperature will be:
= 93 - (-6)
= 93 + 6
= 99
A bag contains 3 blue, 7 green and 1 purple counter. One counter is picked
at random. What is the probability that the counter is green or purple? Give
your answer as a fraction.
A bag contains 3 blue, 7 green and 1 purple counter. One counter is picked at random, the probability of selecting a green or purple counter is 8/11.
What is probability?Probability is a measure of the likelihood or chance of an event occurring. It is usually expressed as a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain to occur.
There are a total of 11 counters in the bag, 3 of which are blue, 7 are green, and 1 is purple.
The probability of selecting a green or purple counter is the sum of the probabilities of selecting a green counter and a purple counter, since the events are mutually exclusive (a counter cannot be both green and purple at the same time).
So the probability of selecting a green or purple counter is:
Probability = (Number of green counters + Number of purple counters) / Total number of counters
Probability = (7 + 1) / 11
Probability = 8/11
Therefore, the probability of selecting a green or purple counter is 8/11.
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find the area dimensions are in centimeters.
Answer:
[tex]9600cm^{2}[/tex]
Step-by-step explanation:
Get the area of the triangle and the rectangle, then subtract the triangle's area for the rectangle's
The USD appreciates 2% versus the JPY. The USD appreciates 4% versus the MXN. What is the approximate appreciation or depreciation we might see in the JPY/MXN cross exchange rate? Fill in the blanks: The JPY/MXN cross rate should ______________ about ______________ percent
The approximate appreciation or depreciation we might see in the MXN/JPY cross exchange rate is 3%.
What is Depriciation?
The term depreciation refers to an accounting method used to allocate the cost of a tangible or physical asset over its useful life. Depreciation represents how much of an asset's value has been used.
The approximate appreciation or depreciation we might see in the MXN/JPY cross exchange rate can be stated using the following 3 steps.
Step 1. State the initial exchange rates of the currency pairs.
Let first assume the initial exchange rates are as follows:
USD1 = JPY1
USD1 = MXN1
Therefore, we have the initial cross rate as follows:
MXN1 = USD1 = JPY1
MXN1 = JPY1
Step 2. Determine the new exchange rates
The new exchange rates can be determined as follows:
When the USD depreciates 2% versus the JPY, this implies that
USD1 X (100% + 2%) = USD1.02
has to be exchanged for JPY1.
Therefore, we now have:
USD1.02 = JPY1, or
USD1 = JPY1/1.02
USD1 = JPY0.98
Also, when The USD appreciates 1% versus the MXN, this implies that USD1 X (100% - 1%) = USD0.99
has to be exchanged for MXN1.
Therefore, we now have:
USD0.99 = MXN1, or
USD1 = MXN1/0.99
USD1 = MXN1.01
Therefore, we have the new cross rate as follows:
MXN1.01 = USD1 = JPY0.98
MXN1.01 = JPY0.98
MXN1.01 / 1.01 = JPY0.98/1.01
MXN1 = JPY0.97, or
MXN1/0.97 = JPY0.97/0.97
MXN1.03 = JPY1
Therefore, the new exchange rates are as follows:
USD1.02 = JPY1
USD0.99 = MXN1
MXN1.03 = JPY1
c. Determination of appreciation or depreciation we might see in the MXN/JPY
Percentage of depreciation of MXN against JPY = ((Initial MXN/JPY - New MXN/JPY) / Initial MXN/YPY) X 100 = ((1.03 - 1) / 1) * 100 = 3%
Since the percentage of depreciation of MXN against JPY is 3%, this also implies that the percentage of appreciation of JPY against MXN is 3%.
Thus, the approximate appreciation or depreciation we might see in the MXN/JPY cross exchange rate is 3%.
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Hello what is the next number in the sequence 7, 11, 2, 18, -7, ?
The next number in the sequence 7, 11, 2, 18, -7, would be -11.
What is the number pattern?A number pattern is a pattern in a series of numbers that represents the common relationship between the numbers.
Given sequence;
7, 11, 2, 18, -7,
We can see that the fifth term is similar to the first term, except for the negative.
So, we can conclude that the integers start from the fifth term and leads to the next term as a negative of the second one.
Therefore, The next number in the sequence 7, 11, 2, 18, -7, would be -11.
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ments
nts
ns
Mai says, "I know how to find the area of a sector or the length of an arc for central angles like 180
degrees or 90 degrees. But I don't know how to do it for central angles that make up more complicated
fractions of the circle."
1. In the diagram, the sector's central angle measures 8 degrees and the circle's radius is r units. Use
the diagram to tell Mai how to find the area of a sector and the length of an arc for any angle and
radius measure.
2. This image shows a circle with radius and central angle measurements. Find the area of the shaded
sector, and the length of the arc defined by the sector.
160%
5 in
The sector area and the arc length are 34.92 square inches and 13.97 inches, respectively
How to find a sector area, and arc length?For a sector that has a central angle of θ, and a radius of r;
The sector area, and the arc length are:
[tex]A = \frac{\theta}{360} * \pi r^2[/tex] --- sector area
[tex]L = \frac{\theta}{360} * 2\pi r[/tex] ---- arc length
How to find the given sector area, and arc length?Here, the given parameters are:
Central angle, θ = 160
Radius, r = 5 inches
The sector area is
[tex]A = \frac{\theta}{360} * \pi r^2[/tex]
So, we have:
[tex]A = \frac{160}{360} * \frac{22}{7} * 5^2[/tex]
Evaluate
A = 34.92
The arc length is:
[tex]L = \frac{\theta}{360} * 2\pi r[/tex]
So, we have:
[tex]L = \frac{160}{360} * 2 * \frac{22}{7} * 5[/tex]
L = 13.97
Hence, the sector area and the arc length are 34.92 square inches and 13.97 inches, respectively
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10 times the sum of certain numbers x and y
This can be represented by [tex]\boxed{10(x+y)}[/tex]
If y varies directly as the square of x and Y--54 when x-9, then -- when x-6.
True or false
Answer:
24.012
Step-by-step explanation:
y=kx^2
54=81k
k=54/81
k=0.667
y=kx^2
y=0.667×36
y=24.012
its false ik this because im one of the boyzz
Tim go to school.His age is a cube number.His age is double 1 square number and half a different square number.How old is Tim?
A rectangular prism and a cylinder both have a height of 8m, and their cross-sectional areas are equal at every level parallel to their respective bases.
Complete the steps to find the prism.
1) [tex]V=lwh=5(x)(8)=\boxed{40x}[/tex]
2) [tex]V=\pi r^{2}h=(\pi)(3^{2})(8)=\boxed{72}\pi[/tex]
3) [tex]40x=72\pi\\\\x=\frac{72\pi}{40} \approx \boxed{5.7}[/tex]
Integration by Parts Evaluate e-2x cos(2x) dx.
Let
[tex]I = \displaystyle \int e^{-2x} \cos(2x) \, dx[/]tex
Integrate by parts:
[tex]\displaystyle \int u \, dv = uv - \int v \, du[/tex]
with
[tex]u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \cos(2x) \, dx \implies v = \dfrac12 \sin(2x)[/tex]
Then
[tex]\displaystyle I = \frac12 e^{-2x} \sin(2x) + \int e^{-2x} \sin(2x) \, dx + C[/tex]
Integrate by parts again, this time with
[tex]u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \sin(2x) \, dx \implies v = -\dfrac12 \cos(2x)[/tex]
so that
[tex]\displaystyle I = \frac12 e^{-2x} \sin(2x) - \frac12 e^{-2x} \cos(2x) - \int e^{-2x} \cos(2x) \, dx + C\\\\ \implies I = \frac{\sin(2x)-\cos(2x)}{2e^{2x}} - I + C \\\\ \implies 2I = \frac{\sin(2x) - \cos(2x)}{2e^{2x}} + C \\\\ \implies I = \boxed{\frac{\sin(2x) - \cos(2x)}{4e^{2x}} + C}[/tex]
fy= 2x² + 2x + 1
y = 2x + 3
What is the solution to this system of equations?
o (-1, 3) and (0,4)
o (0, 1) and (1,5)
○ (0, 1) only
o (-1, 1) and (1, 5)
The answer is (-1,1) and (1,5)
A triangle has two sides of lengths 4 and 15. What value could the length of
the third side be? Check all that apply.
A. 19
B. 11
C. 4
OD. 15
OE. 12
F. 13
The value could the length of the third side will be 11,12,13,15. Options B, D, E, and F are the correct answers.
What is the triangle?A triangle is a three-sided polygon. It is one of the most fundamental geometric forms.
According to the triangle Inequality theorem, any two triangle sides must add up to more than the third side's length.
You may get the potential length of a triangle by multiplying the sum of two sides by the difference between two sides.
Therefore,
Let x is the possible length of the third side of a triangle.
14-4<x<15+4
10<x<19
The values of the third side is lies between the 10 and 19.The value could the length of the third side will be 11,12,13,15
Hence, options B, D, E, and F are the correct answers.
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find the lenght of (a) using the pytoagorean theorem.
Longest line is 8
shortest line is 6
Answer:
5.29
Step-by-step explanation:
8
[tex] \sqrt{8 { = }^{2} { - 6 {?}^{2} }^{2} } [/tex]
Answer: Missing side length (b) = 5.3 units
Step-by-step explanation:
Hii, I'd love to help you out! (:
We are provided with two sides, which are:
Longest side = 8Shortest side = 6Luckily, there's a formula to find the third side!
The Pythagorean TheoremThe Pythagorean Theorem ([tex]\pmb{a^2+b^2=c^2}[/tex]) is the formula that we will use to find the missing side. In this formula "a" and "b" denote the "legs" of the triangle (the two shorter sides) and "c" denotes the hypotenuse (the longest side which is opposite the right angle (the 90 degree angle)
NB: a and b are interchangeable, because a+b is the exact same thing as b+a; c is always the hypotenuse.
Now it's time for us to stick in the values.
[tex]\bigstar\underbrace{\boxed{\sf a=6;\;c=8}}[/tex]
This is what we obtain upon sticking in the values:
[tex]\tt 6^2+b^2=8^2[/tex]
Now we can solve for b.
[tex]\tt 36+b^2=64}\\b^2=64-36\\b^2=28\\b\approx5.3[/tex]
Thus, the value of "b" is 5.3. (Rounded to the nearest tenth, or one decimal place - one digit after the decimal point)
_____________
Hope I helped! Best wishes.
Reach far. Aim high. Dream big.
_____________
[tex]\underbrace[/tex]
