What is the denominator of the simplified expression? (startfraction 2 n over 6 n 4 endfraction) (startfraction 3 n 2 over 3 n minus 2 endfraction)

Step-by-step explanation:

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Step-by-step explanation:

[tex] = \frac{1}{5} + \frac{1}{10} \\ [/tex]

Now make the denominator same...

[tex] = \frac{1}{5} \times \frac{2}{2} + \frac{1}{10} \\ [/tex]

[tex] = \frac{2}{10} + \frac{1}{10} \\ [/tex]

[tex] = \frac{3}{10} \\ [/tex]

:)

..

Answer:

its right there.

Step-by-step explanation:

Answer:

x = 37

Step-by-step explanation:

Answer:

[tex]\cfrac{-4}{3} [/tex] and [tex]\cfrac{1}{2} [/tex].

Step-by-step explanation:

Equation:

[tex] \rm \: \: (2x - 1)(3x + 4) = 0[/tex]

Solution:

Set factors equal to zero,that is:

[tex](2x - 1) = 0 \: \: \: \: \: \: \: \: \: \: \: ...(1)[/tex]

[tex](3x + 4) = 0 \: \: \: \: \: \: \: \: \: \: \: \: ...(2)[/tex]

Solving for equation 1:

Solving for equation 2:

Hence,the solutions to the quadratic equation in factored form is [tex]\cfrac{-4}{3} [/tex] and [tex]\cfrac{1}{2} [/tex].

[tex]\rule{225pt}{2pt}[/tex]

Good luck on your assignment!

x=1/2 and x=-4/3 are the solutions of the equation (2x - 1)(3x + 4) = 0

A quadratic equation is a second-order polynomial equation in a single variable x , ax²+bx+c=0. with a ≠ 0 .

The given equation is (2x - 1)(3x + 4) = 0

We have to find the solutions of the equation

As the equation is in factored form

We take each factor and solve for solution

2x-1=0

2x=1

Divide both sides by 2

x=1/2

Now 3x+4=0

3x=-4

Divide both sides by 3

x=-4/3

Hence, x=1/2 and x=-4/3 are the solutions of the equation (2x - 1)(3x + 4) = 0

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Answer:

C

Step-by-step explanation:

calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (0, 2) and (x₂, y₂ ) = (4, 0) ← 2 points on the line

m = [tex]\frac{0-2}{4-0}[/tex] = [tex]\frac{-2}{4}[/tex] = - [tex]\frac{1}{2}[/tex]

the y- intercept is the value of y where the line crosses the y- axis , then

y- intercept = 2

The word in the problem that indicates that a negative sign should be used is "descend"

We know that he stops for water breaks four times, and between each water break, he descends 15 meters.

The written equation is:

4*(-15)m = -60m

Why the negative sign is used?

The negative sign is used because the hiker is descending, so its height is decreasing. The word in the problem that indicates that a negative sign should be used is "descend"

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Surface area of old cube

Side of new cube

Surface area

Difference

Answer:

A)  6(x + y)² = 6x² + 12xy +6y²

B)  12xy +6y²

Step-by-step explanation:

Surface area of a cube = 6s²  (where s is the side length)

Part A

Given:

⇒ Surface area of the original cube = 6x²

If the side length of the cube is increased by y, then:

⇒ Surface area of the new cube = 6(x + y)²

Expand and simplify:

⇒ 6(x + y)²

⇒ 6(x + y)(x + y)

⇒ 6(x² + xy + xy + y²)

⇒ 6x² + 12xy +6y²

Part B

To find the difference between the surface areas of the new and original cubes, subtract the surface area of the original cube from the surface area of the new cube:

⇒ SA of new cube - SA of original cube

⇒ 6x² + 12xy +6y² - 6x²

⇒ 12xy +6y²

Answer:

57 square units

Step-by-step explanation:

Area is = Length x Width

Given:

f(x)= 4x + 3    Length

g(x)=2x-5      Width

x = 4

============

Width

g(x)=2x-5

g(4)=2(4)-5

g(4)= 3

Length

f(x)= 4x + 3

f(4) = (4)(4) + 3

f(4) = 19

Area = (length)*(width)

Area = f(x)*g(x) for x = 4

Area = (f(4))*(g(4))

Area = (19)*(3)

Area = 57 square units

Answer:

1, 17, 33, 49

Step-by-step explanation:

given the first term is 1 then the next 3 terms are

1 + d, 1 + 2d, 1 + 3d ( d is the common difference )

the sum of the first 4 terms is 100 , then

1 + 1 + d + 1 + 2d + 1 + 3d = 100 , that is

4 + 6d = 100 ( subtract 4 from both sides )

6d = 96 ( divide both sides by 6 )

d = 16

1 + d = 1 + 16 = 17

1 + 2d = 1 + 2(16) = 1 + 32 = 33

1 + 3d = 1 + 3(16) = 1 + 48 = 49

the first 4 terms are

1, 17, 33, 49

Answer:

see the file attached!!!!

Answer: the answer is b

Step-by-step explanation:

The graph of the greatest integer function is graph A.

A graph is a diagram or a pictorial representation of data or values that show the relationship between quantities or objects.

Given are graphs we need to find the graph of the greatest integer function,

The graph of the greatest integer function is graph A because since it is a greatest integer function, it includes the highest integer, but excludes the lowest since it is the highest integer when x is less than or equal to an integer but greater than x-1.

Hence the graph of the greatest integer function is graph A.

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Answer:

This point is not on the line, NOT TRUE

Step-by-step explanation:

The equation of the line is written in the slope-intercept form,

y = mx + b

where m represents the slope

          b represents the y-intercept

where the format of a point is (x, y)

Given: y = 3x - 5.1, (-1.2, -3.1)

we can plug in the point (-1.2, -3.1)

-3.1 = 3(-1.2) - 5.1

-3.1 = -3.6 - 5.1

-3.1 = -8.7

-3.1 does not equal -8.7 so this point is not on the line

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Answer:

√2.236

Step-by-step explanation:

(2,0) (5,-2). 2 - 5 = -3. 0 - -2 = 2. -3 squared = -9. 2 squared = 4. -9 + 4 = -5. Square root of -5 = 2.236, so the distance would be √2.236

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\texttt {D. Symmetry about the polar axis Theta = 0} [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

The given graph is symmetric along Theta = 0

[ polar axis ]

Because it's a horizontal line that divides the features on the graph into two equal halves. and there's no other suitable symmetric relation.

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

6x²

Step-by-step explanation:

[tex]-\frac{3}{4} x\times \left( -8x\right) =\frac{3}{4} x\times 8x[/tex]

                     [tex]=\frac{3}{4} \times 8\times x\times x[/tex]          

                     [tex]=\frac{24}{4} \times x^{2}[/tex]

                     [tex]=6x^2[/tex]

The value of a is 1/64.

The rules of the exponent are

(a) [tex]a^m*a^n=a^{m+n[/tex]

(b)[tex]a^m/a^n=a^{m-n[/tex]

(c)[tex](a^b)^c=a^{bc}[/tex]

(d) [tex]\sqrt[n]{a}=a^{1/n[/tex]

(e) a⁻ⁿ=1/aⁿ

From the table it is clear that

By the rule of the exponent a⁻ⁿ=1/aⁿ

where a=2

2⁻¹ = 1/2¹ = 1/2

2⁻² =1/2² =1/4

2⁻³ =1/2³ =1/8

2⁻⁴ =1/2⁴ =1/16

2⁻⁵ =1/2⁵ =1/32

So we have to calculate the left one where it is given that we have to estimate the value for 2⁻⁶ which is a.

From the above, it is clear that 2⁻ⁿ =1/2ⁿ

using the above formula

2⁻⁶= 1/2⁶ =1/64= a

Therefore the value of a is 1/64.

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Answer:

Polygon 3 and polygon 4 are similar to polygon 1.

Step-by-step explanation:

I believe this is the answer from the looks of it. If it's not 3, then try 2. I know one of them is definitely 4 though. I hope this helps!!

The equation of the given sine graph is gotten as; y = 4 sin [(0.4(x + 2.5)] - 1

We know that the  general formula for equation of a sine graph is;

y = A sin [(B(x - D)] + C

where;

A is Amplitude

Period = 2π/B.

Phase Shift = -C/B.

Vertical Shift = D.

From the graph;

A = 4

B = 2π/5π = 2/5

C = -1

D = -5/2

Thus;

y = 4 sin [(0.4(x + 2.5)] - 1

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Answer:

the two angles equal 180 degree

so 2x+2+5x+3=180

2x+5x+3+2=180

7x=180-5

7x/7=175/7

x=25

Step-by-step explanation:

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Answer:

(x - 9)(x^2 + 18x + 81).

Step-by-step explanation:

Use the difference of cubes factorization, which claims that a^3 - b^3 = (a - b)(a^2 + ab + b^2)

x^3 - 729 = (x - 9)(x^2 + 18x + 81)

Answer:[tex](x-9) (x^{2} +9x + 81)[/tex]

Step-by-step explanation:

The only option that meets the root theorem is option b.

The polynomial function is:

[tex]f(x) = 2x^2 - 4x + 9[/tex]

The rational root theorem says that if a root is a rational number, then the leading coefficient must be divisible by the denominator of the rational number and the constant term must be divisible by the numerator.

In this case, the constant is 9, and the only option such that the constant is divisible by the numerator is option b: 3

Where 3 is a rational number:

3 = 3/1

The numerator is 3 (which divides 9) and the denominator is 1 (which divides the leading coefficient 9. (notice that it meets the theorem, but it is not an actual root).

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Answer:

[tex]24\sqrt{5}[/tex]

Step-by-step explanation:

So for this problem you can use the law of sines which states

[tex]\frac{a}{sin A} = \frac{b}{sin B}\\[/tex]

Since the angle is a right triangle we can find the hypotenuse by plugging in the values.

[tex]\frac{4\sqrt{15}}{sin 60} = \frac{hypotenuse}{sin 90}\\\\\frac{4\sqrt{15}}{sin 60} = hypotenuse\\hypotenuse = \frac{4\sqrt{15}}{\frac{\sqrt{3}}{2}} = \frac{8\sqrt{15}}{\sqrt{3}}\\hypotenuse = \frac{8\sqrt{45}}{3} = \frac{24\sqrt{5}}{3}\\[/tex]

we now just multiply that side by 3since all the sides should be equal since all the angles are equal and we get the length of 24sqrt(5)

Answer:

Step-by-step explanation:

Answer:

(-2, 11) and (2, 3)

Step-by-step explanation:

Given system of equations:

1) f(x) = x² - 2x + 3 ⇒ y = x² - 2x + 3

2) f(x) = -2x + 7 ⇒ y = -2x + 7

Solve Using the Substitution Method:

Step 1: Substitute the the first equation into the second.

⇒ x² - 2x + 3 = -2x + 7

Step 2: Solve for x.

x² - 2x + 3 = -2x + 7 [ Add 2x to both sides. ]

x² - 2x + 2x + 3 = -2x + 2x + 7

⇒ x² + 3 = 7 [ Subtract 3 from both sides. ]

x² + 3 - 3 = 7 - 3

⇒ x² = 4 [ Take the square root of both sides. ]

√x² = √4

x = ± 2

⇒ x = -2, x = 2

Step 3: Solve for y.

Substitute the found x-values into one of the given equations.

y = -2x + 7 ⇒ y = -2(-2) + 7 ⇒ y = 4 + 7 ⇒ y = 11

y = -2x + 7 ⇒ y = -2(2) + 7 ⇒ y = -4 + 7 ⇒ y = 3

The solutions to the system of equations are: (-2, 11) and (2, 3).

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The distance that edgar runs in a 5-day week will be 4.45 miles.

Distance is defined as the length between the two points it can be represented in mm,cm, meters,km, and miles.

Given that:-

Edgar runs 8/9 of a mile each day. what is the total distance that Edgar runs in a 5-day week?

The total distance will be calculated as:-

D = [tex]\dfrac{8}{9}[/tex] x 5

D = 4.45 miles

Therefore the distance that edgar runs in a 5-day week will be 4.45 miles.

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Answer:

cost of old motor bike =$5675

he spent on repair =$453

cost that he sold =$7265

profit he made=$7265-$5675+$453

=$7265-$6128

=$1137

Step-by-step explanation:

STEP 1 : Rearrange this Absolute Value Inequality

Absolute value inequalitiy entered

|2x-1| < 11

STEP 2 : Clear the Absolute Value Bars

Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.

The Absolute Value term is |2x-1|

For the Negative case we'll use -(2x-1)

For the Positive case we'll use (2x-1)

STEP 3 : Solve the Negative Case

-(2x-1) < 11

Multiply

-2x+1 < 11

Rearrange and Add up

-2x < 10

Divide both sides by 2

-x < 5

Multiply both sides by (-1)

Remember to flip the inequality sign

x > -5

Which is the solution for the Negative Case

STEP 4 : Solve the Positive Case

(2x-1) < 11

Rearrange and Add up

2x < 12

Divide both sides by 2

x < 6

Which is the solution for the Positive Case

STEP 5 : Wrap up the solution

-5 < x < 6

Solution in Interval Notation

(-5,6) .

Semiperimeter is used to find the area of various shapes including the equilateral triangle (False).

Semiperimeter is a term used in geometry to refer to half the perimeter of a polygon. It is generally used in formulas for triangles.

However, it is also part of calculations related to other geometric shapes. According to the above, it can be inferred that the semiperimeter can be used to find the area of various geometric figures.

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The proof will be given as:- [tex]\dfrac{tanx+Cotx}{Coscx Cosx} = Sec^2x[/tex].

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

The proof will be given as:-

[tex]\dfrac{tanx+Cotx}{Coscx Cosx} = \dfrac{tanx}{coscxCosx}+\dfrac{Cosx}{CoscxCosx}\\\\[/tex]

[tex]\dfrac{tanx+Cotx}{Coscx Cosx} =\dfrac{\dfrac{Sinx}{Cosx}}{\dfrac{Cosx}{Sinx}}+\dfrac{\dfrac{Cosx}{Sinx}}{\dfrac{Cosx}{Sinx}}[/tex]

[tex]\dfrac{tanx+Cotx}{Coscx Cosx} = \dfrac{Sin^2x}{Cos^2x}+1[/tex]

[tex]\dfrac{tanx+Cotx}{Coscx Cosx} = tan^2x+1}[/tex]

[tex]\dfrac{tanx+Cotx}{Coscx Cosx} =Sec^2x[/tex]

Therefore the proof will be given as:- [tex]\dfrac{tanx+Cotx}{Coscx Cosx} = Sec^2x[/tex].

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